Answer: s = 3.7 (rounded 3.67 to the nearest tenth)
Step-by-step explanation:
Surface Area = 81 cm^2
Surface Area of the cube = 6s^2
A = 6s^2
81 = 6s^2
S^2 = 81/6
S = 3.67
Find the area
O 60 square meters
O 120 square meters
O None of these
O 156 square meters
Answer:
120 m²
Step-by-step explanation:
We khow that the area of a triangle is the product of the lenght and the wight
let x be the width
the pythagorian theorem : x²+8²= 17² x² = 17²-8² x²= 225 x= 15so the lenght is 15
A= 15*8 = 120 m²Answer:
120 square meters
Step-by-step explanation:
The missing leg of the right triangle is found from the Pythagorean theorem:
diagonal² = length² + width²
length² = diagonal² -width²
length = √(17² -8²) = √(289 -64) = √225 = 15
So, the rectangle is 8 m by 15 m and has an area that is ...
A = LW = (15 m)(8 m) = 120 m²
Write the comparison below as a ratio in simplest form using a fraction, a colon, and the word to. 11 oz to 5 oz
Identifico el nombre de la propiedad a la que hacen referencia las siguientes expresiones:
Hacen falta las expresiones para poder responder a tu pregunta, estuve investigando y adjuntaré una imagen que hace referencia a tus preguntas, espero no equivocarme.
Si este es el caso, son 9 expresiones y el nombre de cada propiedad es:
1. Inverso aditivo (Sumar un número por su opuesto el resultado es 0)
2. Ley conmutativa (El orden de los factores no altera el producto)
3. Ley asociativa (Agrupar los términos sin alterar el resultado)
4. Ley de la identidad, (Sumar un número con 0 se obtiene el mismo número)
5. Ley distributiva (La misma respuesta cuando multiplicas un conjunto de números por otro número que cuando se hace cada multiplicación por separado)
6. Ley distributiva
7. Ley distributiva
8. Ley asociativa
9. Ley conmutativa
If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
Answer:
25%
Step-by-step explanation:
George is 33[tex]\frac{1}{3}[/tex]% ([tex]\frac{100}{3}[/tex]%) richer than Pete. Let Pete's percentage of wealth be 100%.
Thus George percentage of wealth = 100% + [tex]\frac{100}{3}[/tex]%
= [tex]\frac{400}{3}[/tex]%
= 133[tex]\frac{1}{3}[/tex]%
Pete's percent poorer than George can be determined by;
= [tex](\frac{100}{3})[/tex] ÷ [tex](\frac{400}{3} )[/tex] × 100
= [tex](\frac{100}{3})[/tex] × [tex]\frac{3}{400}[/tex] ×100
= 0.25 × 100
= 25%
Pete is 25% poorer than George.
Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200 ft. Use the fact that the weight-density of water is 62.4 lb/ft3
Answer:
work done is equal to 384279168 lb-ft
Step-by-step explanation:
The cylinder has a circular base of 7 ft.
The height of the cylinder is 200 ft
The weight density of water in the cylinder is 62.4 lb/ft^3
First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.
The volume of a cylinder is given as [tex]\pi r^{2} h[/tex]
where, r is the radius,
and h is the height of the cylinder.
the volume of the cylinder = [tex]3.142* 7^{2}*200[/tex] = 30791.6 ft^3
Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...
weight of water = 62.4 x 30791.6 = 1921395.84 lb
We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...
The work done in pumping the water out of the container will be
==> (weight of water) x (height of cylinder) = 1921395.84 x 200
==> work done is equal to 384279168 lb-ft
The required work done will be "384279168 lb-ft".
Work done:Whenever a force pushes anything across distances, work is performed. This same energy transmitted, as well as work done, maybe determined by calculating the force through the kilometers moved throughout the direction of the applied force.
According to the question,
Circular base of cylinder = 7 ft
Height of cylinder = 200 ft
Weight density of water = 62.4 lb/ft³
The Volume of cylinder be:
= πr²h
By substituting the values,
= [tex]3.142\times (7)^2\times 200[/tex]
= [tex]3.142\times 49\times 200[/tex]
= [tex]30791.6[/tex] ft³
Now,
The weight of water be:
= [tex]62.4\times 30791.6[/tex]
= [tex]1921395.84[/tex] lb
hence,
The work done be:
= Water's weight × Cylinder's height
= [tex]1921395.84\times 200[/tex]
= [tex]384279168[/tex] lb-ft
Thus the above answer is right.
Find out more information about work done here:
https://brainly.com/question/25573309
For the triangle show, what are the values of x and y (urgent help needed)
we just have to use the Pythagoras theorem and then calculate the value of x and y.
Tommy has "n" friends and he wants to give each friend 5 pencils. Write an expression to show how many pencils pencils Tommy will share.
Answer:
5n
Step-by-step explanation:
Think about it:
If Tommy has 4 friends (n = 4), then he will have to give 5 pencils to each person. The total number of pencils is 5 * n or 5 * 4 = 20.
Similarly, if Tommy has 0 friends (I can relate), then he will have to give 5 pencils to each of his imaginary friends. The total number of pencils he has to give out to his real friends is 5 * n or 5 * 0 = 0.
acccording to this diagram what is cos 28
Answer:
[tex] \frac{15}{17} [/tex]Option B is the correct option.
Here,
Adjacent=15
Hypotenuse=17
Now,
[tex]cos \: theta = \frac{adjacent}{hypotenuse} \\ cos \: 28 = \frac{15}{17} [/tex]
Hope this helps..
Good luck on your assignment..
Answer:
B. 15/17
Step-by-step explanation:
(see attached graphic for reference)
Because we have a right triangle (i.e one of the internal angles is 90 degrees), we can use trigonometry to solve
from the diagram, we can see that
cos 28° = adjacent length / hypotenuse
we can also see that the length adjacent to 28° = 15 units and the hypotenuse is 17 units,
hence, substituting these values into the equation:
cos 28° = 15 / 17 (answer)
edit: typo
The domain and range of T
Answer:
Step-by-step explanation:
The domain is {-1, 2} (the domain has only two values).
The range is {-4, -3, 2} (the range contains three values)
graph y=8 sec1/5 Ø the answers are graphs I am just unsure of how to answer
Answer:
Use a graphing calc.
Step-by-step explanation:
Betty tabulated the miles-per-gallon values for her car as 26.5, 28, 30.2, 29.6, 32.3, and 24.7. She wants to construct the 95% two-sided confidence interval. Which value should Betty use for the value of t* to construct the confidence interval?
Answer:
Betty should use T = 2.571 to construct the confidence interval
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.571
Betty should use T = 2.571 to construct the confidence interval
Determine what type of study is described. Explain. Researchers wanted to determine whether there was an association between high blood pressure and the suppression of emotions. The researchers looked at 1800 adults enrolled in a Health Initiative Observational Study. Each person was interviewed and asked about their response to emotions. In particular they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10. Each person's blood pressure was also measured. The researchers analyzed the results to determine whether there was an association between high blood pressure and the suppression of emotions.
Answer:
Experimental Study
Step-by-step explanation:
In an experimental study, the researchers involve always produce and intervention (in this case they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10) and study the effects taking measurements.
These studies are usually randomized ie subjects are group by chance.
As opposed to observation studies, where the researchers only measures what was observed, seen or hear without any intervention on their parts.
Find the value of x and the value of y. A.x = 15, y = 10 B.x = 20, y = 50 C.x = 50, y = 10 D.x = 50, y = 20
Answer:
X = 50
Step-by-step explanation:
(5x - 100) + (x - 20) = 180 (sum of angle on a straight line is = 180)
5x + x -100 -120 = 180
6x - 120 = 180
6x = 180 + 120
6x = 300
x = 300/6
x = 50
For y
3y + y + 140 = 180
4y = 180 -140
4y = 40
y = 40/4
y = 10
Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145 a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145
a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)
c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)
Answer:
a. Cumulative Probability Distribution
Grade P(X ≤ x)
F 0.145
D 0.310
C 0.670
B 0.910
A 1
b. P(at least B) = 0.330
c. P(pass) = 0.855
Step-by-step explanation:
Professor Sanchez has been teaching Principles of Economics for over 25 years.
He uses the following scale for grading.
Grade Numerical Score Probability
A 4 0.090
B 3 0.240
C 2 0.360
D 1 0.165
F 0 0.145
a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
The cumulative probability distribution is given by
Grade = F
P(X ≤ x) = 0.145
Grade = D
P(X ≤ x) = 0.145 + 0.165 = 0.310
Grade = C
P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670
Grade = B
P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910
Grade = A
P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1
Cumulative Probability Distribution
Grade P(X ≤ x)
F 0.145
D 0.310
C 0.670
B 0.910
A 1
b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)
At least B means equal to B or greater than B grade.
P(at least B) = P(B) + P(A)
P(at least B) = 0.240 + 0.090
P(at least B) = 0.330
c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)
Passing the course means getting a grade of A, B, C or D
P(pass) = P(A) + P(B) + P(C) + P(D)
P(pass) = 0.090 + 0.240 + 0.360 + 0.165
P(pass) = 0.855
Alternatively,
P(pass) = 1 - P(F)
P(pass) = 1 - 0.145
P(pass) = 0.855
PLSSS PEOPLE I NEED HELP
Answer:C
Step-by-step explanation:
The vertical line test
The number of degrees of freedom for the appropriate chi-square distribution in a test of independence is a. k – 1. b. A chi-square distribution is not used. c. number of rows minus 1 times number of columns minus 1. d. n – 1.
Answer:
Option C
Step-by-step explanation:
The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.
It tests the claim that the row and column variables are independent of each other.
The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.
I need help plz someone help me solved this problem I need help ASAP! I will mark you as brainiest!
Answer: k = -9
Step-by-step explanation:
kx² - 12x - 4 = 0
In order to have exactly one solution, it must be a perfect square.
Assume k is negative and factor out a negative 1.
-1(kx² + 12x + 4) = 0
[tex]\bigg(\sqrt{kx^2}+\sqrt4\bigg)^2=0\\\\[/tex]
The middle term = 12x [tex]= 2(\sqrt{kx^2})(\sqrt4)[/tex]
12x = 4x√k
3 = √k
9 = k
-1(9x² + 12x + 4) = 0
-9x² - 12x - 4 = 0
k=-9
Evaluate. Write your answer as a fraction or whole number without exponents. 7^–1 =
Answer:
1/7 = 0.142857... repeating
Step-by-step explanation:
7^(-1) = 1/(7^1) =1/7 = 0.142857... repeating
Answer:
[tex] \frac{1}{7} [/tex]Solution,
[tex] {7}^{ - 1} \\ = \frac{1}{ {7}^{1} } \\ = \frac{1}{7} [/tex]
Laws of indices:Law of zero index:[tex] {x}^{0} = 1[/tex]
Product law of indices:[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
( powers are added in multiplication of same base)
Power law of indices:[tex] {( {x}^{m} )}^{n} = {x}^{m \times n} [/tex]
law of negative index:[tex] {x}^{ - m} = \frac{1}{ {x}^{m} } [/tex]
Root law of indices:[tex] {x}^{ \frac{p}{q} } = \sqrt[q]{ {x}^{p} } [/tex]
[tex]( \frac{x}{y} ) ^{n} = \frac{ {x}^{n} }{ {y}^{n} } [/tex] [tex] {(xy)}^{m} = {x}^{m} {y}^{m} [/tex][tex] \sqrt[n]{x} = x \frac{1}{n} [/tex]Hope this helps ....
Good luck on your assignment...
Suppose that g(x) = f(x) - 2. Which statement best compares the graph of
g(x) with the graph of f(x)?
A. The graph of g(x) is shifted 2 units to the left.
B. The graph of g(x) is vertically stretched by a factor of 2.
C. The graph of g(x) is shifted 2 units up.
D. The graph of g(x) is shifted 2 units down.
Answer:
D. The graph of g(x) is shifted 2 units down
Step-by-step explanation:
Since we are modifying b in f(x) = mx + b, we are dealing with vertical movement up and down. Since it is -2, we are moving down 2.
A Bureau of Labor Statistics (BLS) economist conducts a statistical study to test his hunch that in households with a minimum-wage worker, mean household debt increases (spending increases more than income) following a hike in the minimum wage.
Formulate the null and alternative hypotheses for the test conducted by the economist, For each statement below indicate whether the statement is the null hypothesis, the alternative hypothesis, or neither,
a. In households with a minimum-wage worker, mean household debt decreases following a hike in the minimum wage.
b. In households with a minimum-wage worker, mean household debt decreases or stays the same following a hike in the minimum wage.
c. In households with a minimum-wage worker, mean household debt is unaffected by a hike in the minimum wage.
d. In households with a minimum-wage worker, mean household debt increases following a hike in the minimum wage.
Answer:
a. Neither
b. Null hypothesis
c. Neither
d. Alternative hypothesis
Step-by-step explanation:
This hypothesis test wants to test the claim that, in households with a minimum-wage worker, mean household debt increases following a hike in the minimum wage.
Then, the alternative hypothesis, that reflects the claim, will state that the mean household debt significantly increases (under the previous descriptions).
The null hypothesis will state the opposite: that mean household debt does not signficantly increases in that conditions (it stays the same or decreases).
a. In households with a minimum-wage worker, mean household debt decreases following a hike in the minimum wage. NEITHER.
b. In households with a minimum-wage worker, mean household debt decreases or stays the same following a hike in the minimum wage. NULL HYPOTHESIS.
c. In households with a minimum-wage worker, mean household debt is unaffected by a hike in the minimum wage. NEITHER.
d. In households with a minimum-wage worker, mean household debt increases following a hike in the minimum wage. ALTERNATIVE HYPOTHESIS.
Estimate the area under the graph of f(x)=2x^2-12x+22 over the interval [0,2] using four approximating rectangles and right endpoints.
Answer:
The right Riemann sum is 21.5.
The left Riemann sum is 29.5.
Step-by-step explanation:
The right Riemann sum (also known as the right endpoint approximation) uses the right endpoints of a sub-interval:
[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].
To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using right endpoints you must:
We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].
Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]
Now, we just evaluate the function at the right endpoints:
[tex]f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5\\\\f\left(x_{4}\right)=f(b)=f\left(2\right)=6[/tex]
Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\frac{1}{2}(16.5+12+8.5+6)=21.5[/tex]
The left Riemann sum (also known as the left endpoint approximation) uses the left endpoints of a sub-interval:
[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].
To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using left endpoints you must:
We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].
Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]
Now, we just evaluate the function at the left endpoints:
[tex]f\left(x_{0}\right)=f(a)=f\left(0\right)=22\\\\f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\\\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5[/tex]
Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\frac{1}{2}(22+16.5+12+8.5)=29.5[/tex]
Express it in slope-intercept form.
Answer:y=3/2x-3
Step-by-step explanation: the slope of the graph is (y2-y1)/(x2-x1)
If we take points (0,-3) (2,0) the slope would be (0--3)/(2-0) = 3/2
And the y-intercept of the slope is -3
Marty's friend Tom makes and hourly wage of $15.00 per hour. Using that there are 40 hours in a standard work week, there are 52 weeks in a year, Social Security Tax is $6.20 for every $100 earned, Medicare Tax is $1.45 for every $100 earned, and the following income tax designations, calculate the following (round your answers to the nearest penny if needed):
a. Tom's annual income is:_______
b. Tom's annual social security tax is:_______
c. Tom's annual medicare tax is:______
Answer:
a. annual income = $31,200
b. Social Security tax = $1,934.40
c. Medicare = $452.40
Step-by-step explanation:
40 hours in a week
52 weeks in a year
Tom makes $15 / hour
In a year, the
a. annual income = 15*40*52 = 31200
b. Social Security tax = 31200 * 0.062 = 1934.40
c. Medicare = 31200 * 0.0145 = 452.40
PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this? (it's not 15)
Answer: 20
Step-by-step explanation:
I guess that we want to distribute all the 7 candies between 4 kids
We have 3 options:
first 3, 2, 1 and 1. (the number of candies that each kid gets)
The possible permutations in this case:
if we leave the 3 fixed, the ones do are equal, so the permutations are only given by the change in the kid that gets 2 candies, we have 3 permutations for this.
And for the fixed 3, we have 4 possible places where we can fix it, so the total number of combinations is:
c = 3*4 = 12.
and the second option is (2, 2, 2, 1)
Here the only change is the kid that gets only one candy, we have 4 options in this case:
c = 4.
the third option is (4, 1, 1, 1)
Here the only change is the kid that gets 4 candies, and we have 4 options for this, so we have 4 combinations:
c = 4.
Then the total number of possible combinations is:
C = 12 + 4 + 4 = 20
a line pass through the point (4,-2) and has a slope of 1/2 what is the value of (-4,a)
Answer:
if you are trying to find the value of a then a= -6
Step-by-step explanation:
i used the information along with desmos graphing calculator and i graphed the line and got the second point (-4,-6)
Answer:
a=-6
Step-by-step explanation:
slope=(y2-y1)/x2-x1)
1/2=(a-(-2))/(-4-4)
1/2=(a+2)/-8
a+2=1/2×-8=-4
a=-4-2=-6
Which composition of transformations will create a pair of similar, not congruent triangles?
a rotation, then a reflection
a translation, then a rotation
a reflection, then a translation
a rotation, then a dilation
Answer: D a rotation, then a dilation
Step-by-step explanation:
A triangle is said to be congruent when all angles are equal to each other and and has the same side.
it is similar when the two angles correspond with each other and has different sides.
so for a triangle to be different in side only a dilation has to be apply to it. Performing a rotation,reflection, and translation doesn't change the size of the shape it changes the position of the shape.
A rotation, then a dilation will create a pair of similar, not congruent triangles.
Congruent trianglesTwo triangles are said to be congruent if they have the same shape and their corresponding sides are congruent. Hence all the three sides and three angles are congruent.
Rotation, translation and reflection are rigid transformation and would produce a congruent shape while dilation produces a similar and not congruent shape.
A rotation, then a dilation will create a pair of similar, not congruent triangles.
Find out more on Congruent triangles at: https://brainly.com/question/1675117
31
z – 40-12
2
Solution
Answer:
31z-162
Step-by-step explanation:
[tex]-40-122=-162[/tex]
[tex]=31z-162[/tex]
Hartman Motors has $15 million in assets, which were financed with $6 million of debt and $9 million in equity. Hartman's beta is currently 1.4, and its tax rate is 30%. Use the Hamada equation to find Hartman's unlevered beta, bU. Do not round intermediate calculations. Round your answer to two decimal places.
Answer:
Unlevered beta ≈ 1.09
Step-by-step explanation:
Unlevered beta is basically the unlevered weighted average cost as it shows the volatility of returns without financial leverage. Unlevered beta is also known as asset beta, while the levered beta is commonly known as equity beta. Unlevered beta is calculated from the hamada equation as:
Unlevered beta = Levered beta/[1 + ((1 - Tax rate) × (Debt / Equity))]
We are given;
Levered beta = 1.4
Tax rate = 30% = 0.3
Debt = $6 million
Equity = $15 million
Thus, plugging these into the hamada equation, we have;
Unlevered beta = 1.4/[1 + ((1 - 0.3) × (6/15))]
Unlevered beta = 1.4/(1 + (0.7 × 0.4)
Unlevered beta = 1.4/(1 + 0.28)
Unlevered beta = 1.4/1.28
Unlevered beta = 1.09375
To 2 decimal places;
Unlevered beta ≈ 1.09
To determine whether or not grade level influences time spent studying, Samuel has designed a survey. What is the response variable?
Answer:
time spent studying
Step-by-step explanation:
A Response Variable is also called a dependent variable. It derives that if there is any change so what would be the response. In other words, we can say that the variation or changes based on other variables
Therefore in the given case, the time spent studying is treated as a response variable and the same is to be considered
For the following data at the near-ground level, which location will residents likely see dew on their lawns in the morning? Group of answer choices City C: Dew Point Temperature = 25°F, expected low Temperature = 20°F City A: Dew Point Temperature = 65°F, expected low Temperature = 60°F City B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
Answer: CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
Step-by-step explanation:
CITY C: Dew Point Temperature = 25°F, expected low Temperature = 20°F
CITY A: Dew Point Temperature = 65°F, expected low Temperature = 60°F
CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
city B is going to have dew on their lawn in the morning as the dew point temperature is less than the lowest temperature.
When surface temperature drops, eventually reaching the dew point, atmospheric water vapor condenses to form small droplets on the surface. Thus dew will be formed as the conditions are suitable only for city B.