The rocket's mass is 100 kg. How would you find the net force on the rocket?

Answer:

Silicon tetrafluoride

Explanation:

The symbol Si represents the element silicon, as shown in the periodic table.

The are 4 fluorines, so the prefix for fluoride must have tetra-

Answer:

60

Explanation:

Answer:

C. BaO

Explanation:

Answer:

C. BaO

Explanation:

aPe.x

The body is accelerating upward toward the center of the circle it traces out with magnitude

a = v ² / R

where

v = linear speed of the body

R = 3.4 m = radius of the circle it traces/length of the string

The only forces acting on it at the lowest point are the tension T of the string pulling upward on the body and weight W = mg of the body pulling it downward. By Newton's second law, we have

∑ F = T - mg = ma

Replace the acceleration with the expression from earlier and solve for v :

300 N - (17 kg) g = (17 kg) v ² / (3.4 m)

v ² = ((3.4 m) 300 N - (17 kg) g) / (17 kg)

v = √[ ((3.4 m) 300 N - (17 kg) g) / (17 kg) ]

v ≈ 5.16527 m/s ≈ 5.2 m/s

Answer:

speed is a scalar quantity

because it has magnitude but not the direction

vector quantity have magnitude as well as direction

hope it helps

Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.  

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.

haha ctrl + v go brrrrrrrrrrrrrr

Answer: I think ions I’m not 100% sure if it’s not let me know

Explanation:

I am using the equation F=ma (force equals mass times acceleration) to solve these problems.

1. You are looking for force, and have mass and acceleration. You just plug in the values for mass and acceleration to get the force needed.

F=(15kg)(5m/s^2)

F=75N

2. Again, you are looking for force, and just need to plug in the values for mass and acceleration

F=(3kg)(2.4m/s^2)

F=7.2N

3. In this problem, you have force and mass, but need to find acceleration. To do this, you need to get acceleration alone on one side of the equation - divide each side by m. Your equation will now be F/m=a

a=(5N)/(3.7kg)

a=18.5m/s^2

I did not use significant figures. Let me know if you need to do that and need any help on that. Hope this helps!

14.0.5 cm 13. wind speed surface area temperature

Answer:

the time is measured with instrument such time,I hope this help

Answer:

42k

Explanation:

The increase in temperature is needed to increase the length of an aluminum meter-stick by 1.0 mm is 42 K. The option 1 is the correct option.

Thermal expansion is the property of the matter to change its shape, size, length, volume, density etc with change in the temperature.

The thermal expansion can be calculate as,

[tex]\Delta L=aL\Delta T[/tex]

Here, [tex]L[/tex] is the original length, [tex]\Delta T[/tex] is the change in the temperature and [tex]a[/tex] is the coefficient of the expansion.

Given information-

The change in the length of the aluminum mater-stick is 1.00 mm.

Let the initial size of the aluminium mater-stick is 1.00 m or 1000 mm . The thermal expansion coefficient of aluminium is [tex](2.4\times10^{-5})[/tex] per unit Kelvin.

Put the values in the above formula as,

[tex]1=(2.4\times10^{-5})\times 1000\times\Delta T[/tex]

Solve for temperature as,

[tex]\Delta T=\dfrac{1}{(2.4\times10^{-5})\times 1000} \\\Delta T=42K[/tex]

Hence the increase in temperature is needed to increase the length of an aluminum meter-stick by 1.0 mm is 42 K. The option 1 is the correct option.

Learn more about the thermal expansion here;

https://brainly.com/question/1166774

Answer:

a)  force between them is attraction,   b)  F = 1.125 10⁻² N

Explanation:

In this case the electric force is given by Coulomb's law

          F =[tex]k \frac{q_1q_2}{r^2}[/tex]

In the exercise they give us the values ​​of the loads

          q1 = - 10 mC = -10 10⁻³ C

          q2 = 5 mC = 5 10⁻³ C

           d = 20 cm = 0.20 m

let's calculate

          F = 9 10⁹ [tex]\frac{10 \ 10^{-3} \ 5 \ 10^{-3}}{0.20^2}[/tex]

          F = 1.125 10⁻² N

To find the direction of the force we use that charges of the same sign repel each other, as in this case there is a positive and a negative charge, the force between them is attraction

Answer:

Gravity.

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

This ultimately implies that, this force is a pull between all objects. It is the force that gives us weight here on Earth. And, if we throw a rock off of a cliff, it is the force that causes the rock to fall to Earth.

Answer:

Electrical Energy and Sound Energy

Explanation:

Answer:

678.2 km/h and 80.54° north of east

Explanation:

From the question,

Using pythagoras theorem,

a² = b²+c²..................... Equation 1

Where a = resultant velocity

Given: b = 600 km/h, c = 100 km/h

Substitute these values into equation 1

R² = 600²+100²

R² = 360000+10000

R² = 460000

R  = √460000

R = 678.2 km/h.

And the direction is

tanθ = 600/100

tanθ = 6

tanθ = 6

θ = tan⁻¹(6)

θ = 80.54°.

Hence the resultant velocity of the aircraft is 678.2 km/h and 80.54° north of east

Answer:

60 sec

Explanation:

60m because in every 30min in 2sec so 30 × 2= 60 min

research the different time zone around the world, and characteristics of each

Answer:

t = 1.4 s

Explanation:

momentum of the trapeze just before hitting the net = 50 x 14 kg m/s

= 700 kg m/s

final momentum = 0

change in momentum required = 700 - 0 = 700

If F be the maximum force and t be the time of action of force

impulse = force x time = F x t

500 x t

impulse = change in momentum

500 x t = 700

t = 1.4 s .

Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, [tex]R_{max}[/tex] = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, [tex]R_{max}[/tex], of a projectile motion is found by using the following formula

[tex]R_{max} = \dfrac{u^2}{g}[/tex]

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

[tex]R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }[/tex]

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, [tex]g_{Moon}[/tex] = 1/16 × g

∴ [tex]g_{Moon}[/tex] = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

[tex]R_{max \ Moon} = \dfrac{u^2}{g_{Moon}} = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m[/tex]

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is [tex]R_{max \ Moon}[/tex] ≈ 48 m

Answer:

lowkeyyyy

explanation:

Answer:

The wavelength of the light in a vacuum is 575.89 nm

Explanation:

The given parameter in the are;

The wavelength of the ray of light in water, λ₁ = 433 nm

The refractive index of water, n₁ = 1.33

The relationship between wavelength, λ, and refractive index, 'n', is presented as follows;

λ₁·n₁ = λ₂·n₂

Where;

λ₁ and λ₂ are the wavelength of the wave within  the two mediums

n₁ and n₂ are the respective refractive indices of the mediums

The refractive index of vacuum, n₂ = 1

Let λ₂ represent the wavelength of light in vacuum

Therefore, we have;

1.33 × 433 nm = 1 × λ₂

∴ λ₂ = 1.33 × 433 nm/1 = 575.89 nm

Therefore, the wavelength in a vacuum, λ₂ = 575.89 nm

Answer: 576

Explanation: Its correct for acellus!

1 ; Components. Rockets consist of a propellant, a place to put propellant (such as a propellant tank), and a nozzle.

2; The aerodynamic shape of the nose cone helps prevent air from slowing the rocket. The fins help guide the rocket to fly straight. Finally, the propellant system includes a mixture of fuel and a chemical called an "oxidizer" that gives off oxygen. The fuel and oxidizer burn together to launch the rocket off the ground.

3; At supersonic speeds (faster than the speed of sound), the best shape is a narrower and sharper point. Rockets with a larger diameter have more drag because there is more air being pushed out of the way

hi..

its option C..

cuz everyone is equal before the law.. and no one an be discriminated on the basis of their gender, religion, caste, race, colour or anything!..

hope it helps:)

Answer:

a = -1 m/s^2

Explanation:

Vi = 75 m/s

Vf = 25 m/s

t = 50 s

Plug those values into the following equation:

Vf = Vi + at

25 = 75 + 50a

---> a = -1 m/s^2

Answer:

970 kN

Explanation:

The length of the block = 70 mm

The cross section of the block = 50 mm by 10 mm

The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN

The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN

By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force

The pressure due to the force F₁ = 60 kN/(50 mm × 10 mm) = 120 MPa

The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa

The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa

The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN