Answers
Answer:
The correct answer is C) To determine whether NPY can modulate LH secretion.
Explanation:
NPY means Neuropeptide Y while LH means enhances luteinizing hormone.
In the study above, LH is the dependent variable.
Studies have shown that NPY increases LH secretion in part by enhancing the release of LH in response to GnRH. GnRH is an acronym for Gonadotropin-Releasing Hormone.
The above study is a branch of science (Physiology and medicine) which deals with the study of endocrine glands and hormones - Endocrinology.
Cheers!
Related Questions
The process of succession is necessary to maintain and establish stable communities. T or F
Answers
Answer: True it is necessary
Answer:
True
Explanation:
How do humans affect climate change ?
Answers
Answer:
By using too much Fossil fuels like coal and oil, gas.
Some amateur and professional athletes take anabolic steroids to help them "bulk up" or build strength. The health risks of this practices are extensively documented. Apart from health considerations, how do you feel about the use of chemicals to enhance athletic performance? Is an athlete who takes anabolic steroids cheating, or is such use part of the preparation that is required to succeed in competition?
Answers
Answer:
Personally, yes I feel that taking steroids is cheating. Its giving you an "unnatural" edge. An athlete that takes steroids will develop more muscle mass than the athlete that doesn't. Also steroids increase aggression which could definitely edge out the "clean" athlete. It's also really unhealthy and can lead to a shorter life. A true athlete will work for their strength and be the natural human they are rather that an "enhanced" animal. This question is all about opinion so its depends on what you think, this is just my opinion.
Hope this helps!
- Quinn <3
From the following list, correctly identify the reason(s) that might explain a decrease in Vmax due to a suboptimal pH during an enzyme assay.
a. Protonation of the substrate
b. Deprotonation of the amino acids in the enzyme’s active site
c. Denaturation of the protein’s tertiary structure
d. Decrease in the rate of substrate collisions with the enzyme’s active site
e. Change in the entropy of the reaction
f. Increase in the molar extinction coefficient (e) of the product
Answers
Answer:
The correct answer is -
a. Protonation of the substrate.
b. Deprotonation of the amino acids in the enzyme active site.
c. Change in tertiary structure in extreme conditions.
Explanation:
During an enzyme assay, suboptimal pH is changed and affect the Vmax to decrease and this could take place due to various reasons such as-
A) protonation of the substrate - Upon protonating or adding a proton or hydrogen cation to a substrate atom, the mass and the charge of the species each increase by one unit which make a conjugate acid.
B) Deprotonation of the amino acids in the enzyme’s active site -Changing the pH will affect the charges on the amino acid molecules.
C) Denaturation of the protein’s tertiary structure- Tertiary structure of the protein is basically a backbone of peptide chain with one or more secondary domains of proteins that increasing the pH or decreasing the pH get denature.
Thus, the correct answer is : option A, B, C.
1. D Value is determined as a
A. Removing of microorganisms by washing
B. Concentration of disinfectant required to reduce microbial population 10 times
C. Time required to kill 10% of microbial population
D. Time frame in which microbial population of 5,600,000 cells would decrease to 560,000 cells
E. None of the above
2. The betadine or alcohol swab before blood donation is an example of A. Pasteurization
B. Disinfection
C. Sterilization
D. Preservation
E. None of the above
Answers
Answer:
1. D. Time frame in which microbial population of 5,600,000 cells would decrease to 560,000 cells.
2. Disinfection
Explanation:
Hope it helps .
What Similarities Do You See in the DNA Bases?
WARM-UP
Relative Proportions (%) of Bases in DNA
Organism
A
T
G
с
ОО
In a single organism, what do you notice about the
relative proportions of DNA bases?
A and T occur in similar proportions.
T and G occur in similar proportions.
c A and C occur in similar proportions.
G and C occur in similar proportions.
Human
30.9
29.4
19.9
19.8
Chicken
28.8
29.2
20.5
21.5
Grasshopper
29.3
29.3
20.5
20.7
DONE
Sea urchin
328
32.1
17.7
17.3
Wheat
27.3
271
22.7
228
Yeast
31.3
329
18.7
17.1
E coli
24.7
23.6
26.0
25.7
2 of 4
Answers
Answer:
it follows 1:1 stoichiometric ratio
Explanation:
G must be equal to C
A must be equal to T
Answer:
A and T occur in similar proportions.
G and C occur in similar proportions.
Explanation:
Which statement correctly describes glucose (CGH120.?
It is made of matter and contains twenty-four molecules.
It is an element made of three types of atoms.
It is an atom made up of carbon, hydrogen, and oxygen.
It is a compound made of twenty-four total atoms of three different elements
Answers
Answer:
It is made of matter and contains twenty-four molecules.
Why is protein synthesis different in prokaryotes and eukaryote
Answers
Answer:
hope this helps you :)
Explanation:
Prokaryotic protein synthesis can be fairly fast because one gene can be transcribed and translated simultaneously. Eukaryotic synthesis is slower, but more precious. They can "check" the mRNA before it is translated into protein.
Answer:
A prokaryotic cell is a cell without a nucleus or membrane bound cell, a Eukaryotic cell has a nucleus and membrane bound cells, a virus is unrelated
Explanation:
maggots feed on dead and decaying organisms for energy. what are maggots
Answers
Answer:
Decomposers, or as they're alternatively known, detritovores.
Explanation:
Their job is to break down decaying/dead organic matter to recycle it into the soil for plants (mainly). Fungi and bacteria make up the vast majority of decomposers.
The basic unit of structure and function of living things is the A nucleus B cell C tissue or D membrane PLZ QUICK worth 20 points
Answers
Answer:
B. cell
Explanation:
A cell is the smallest unit of a living thing. A living thing, whether made of one cell (like bacteria) or many cells (like a human), is called an organism. Thus, cells are the basic building blocks of all organisms
Answer:
cell
Explanation:
A single point mutation in a gene results in a nonfunctional protein. Individuals heterozygous for this mutation were identified using a Southern blot. Which pair of wild-type (WT) and mutant alleles most likely contains the mutation?
A. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGATGCTTAGGCATCT-3
B. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGAAGCTTAGGCATAT-3
C. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTTGAAGCTTAGGCATCT-3
D. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCCAAGCTTAGGCATCT-3
Answers
Answer:
C. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTTGAAGCTTAGGCATCT-3
Explanation:
In the wild type, the DNA sequence encodes the following aminoacidic segment: SRSLGI; while the mutant form has a stop codon in the second codon (TGA). A stop codon is a trinucleotide sequence in the messenger RNA (mRNA) that indicates a stop signal in protein synthesis. There are three types of stop codons: UGA, UAG and UAA, where U represents Uracile in the mRNA instead of Thymine in the DNA sequence.
Representation:
C. WT 5-T AGT CGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = SRSLGI
Mutant 5-T AGT TGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = S-, where - represents a stop codon (TGA) and therefore it is the end of the protein.
Comparison of glycogen synthesis and breakdown in muscle and liver reveals: A. Stimulation of glycogen breakdown in both tissues by epinephrine leads to enhanced glucose uptake by liver cells and enhanced glucose export from muscle cells. B. Stimulation of glycogen synthesis by insulin in both tissues leads to glycogenolysis in both liver and muscle. C. Inhibition of glycogen synthesis in both tissues by epinephrine leads to glycogenolysis in both liver and muscle. D. Stimulation of glycogen synthesis by insulin in both tissues is accompanied by decreased glycogenolysis. E. Epinephrine stimulates glycogen uptake in liver and breakdown in muscle.
Answers
Answer:
The correct options are C and D:
C- The inhibition of glycogen synthesis in both tissues by epinephrine leads to glycogenolysis in both the liver and muscle.
D- The stimulation of glycogen synthesis by insulin in both tissues is accompanied by a decrease in glycogenolysis.
Explanation:
The presence of epinephrine causes the glycogen reserve that is present in the liver and muscle to enter the glycogenolysis stage, that is, the chemical structures of glycogen are broken and simplified in energy coins (ATP) so that the activity muscle contract against stimulation of the adrenergic nervous system.
The adrenergic nervous system is one that promotes physical activity, physiological stress, flight from danger, and other activities, is also known as the sympathetic system and is where epinephrine or adrenaline predominates as a neurotransmitter.
The liver and muscle are the only possible organs to reserve glycogen in a limited way, once its reserve limits are exceeded it will begin to deposit in the form of adipose tissue, glycogenogenesis or formation of glycogen as reserve is promoted by insulin and the system parasympathetic nerve, visceversa to what we explained above with the sympathetic nervous system and epinephrine, since the latter break the glycogen reserves releasing glucose into the blood for muscle contraction.
Which of the following is a known limiting factor for good nutrition
Answers
Answer:
seems you forgot the "followings" but here are some known limiting factors
Explanation:
Exercise,Physiology, Mindset, Nutrition and Genetics.
a strand of mRNA has the bases adenine- cytosine- uracil which amino acid corresponds to these bases?
Answers
Answer:
Threonine
Explanation:
Using the amino acid chart, the mRNA strand ACU corresponds to the amino acid Threonine.
Answer:
thr
Explanation:
i did test
molecular genetics experiment: In what way do the percentages of yellow leaves vary between dishes on Day 2? How do you account for this difference? Compare the percentage of yellow seedlings in dish 2 on day 2 with the percentage on day 4. What is the difference? What experimental variable accounts for this difference? How can you account for the difference between the seedlings in dish 1? Is the yellow color genetically or environmentally controlled? How can environmental factors affect inheritance? (Use human height as an example.)
Answers
Answer:
See below
Explanation:
There were yellow seedlings in Dish #1 during the light phase and also during the dark in Dish #2. The difference in these results is likely due to the period of exposure to light.
There are more number of yellow seedlings on Day 4. This is probably because of being kept in the dark for a long period of time. Light intensity is the experimental variable that accounts for this difference in appearance.
The yellow color is being environmentally controlled since the parent phenotype was wildtype in this experiment. The environment has an effect on which genes are expressed in the organism, which in turn influences the phenotype observed.
If it is accepted that the information for how a protein is intended to fold lies within its primary sequence, explain why a purified protein denatured in vitro might not be able to renature accurately.
Answers
Answer:
Denaturation and renaturation are properties of protein but in some cases denaturation is irreversible and protein is unable to renature.
The primary sequence of a protein determines which portion of protein fold closely together in order to form three-dimensional conformation and the conformations are held by hydrogen bonds.
Denaturation of protein in-vitro is generally obtained by increasing temperature. Heat or high temperature disrupts hydrogen bonds that held between protein folds because high temperature increases the kinetic energy and the bonds are disrupted due to rapid heating. Disruption of hydrogen bonds will change the 3D structure of the protein and denatured proteins lose its function.
Chemicals are also used to disrupt hydrogen bonds such as alcohol.
So, high temperature and chemicals denature protein by affecting the hydrogen bonds holding 3D shape of primary sequence in protein and the change in protein becomes irreversible.
Some present-day bacteria use a system of anaerobic respiration characterized by an electron transport chain analogous to that found in aerobic organisms. Which of the following correctly characterizes the anaerobic electron transport chain?
a. It uses oxygen as a final electron acceptor.
b. It is embedded in the outer mitochondrial membrane rather than the inner mitochondrial membrane.
c. It establishes a proton gradient between the cytoplasm and the extracellular fluid.
d. It establishes a proton gradient between the intermembrane space and the cytoplasm.
e. None of these answer options accurately characterizes the anaerobic electron transport chain.
Answers
Answer:
The correct answer would be:
Neither of these response options accurately features the anaerobic electron transport chain.
Explanation:
The anaerobic respiration system vibrated by an electron transport chain is a mechanism that anaerobic bacteria have to maintain their respiration.
This mechanism does not require oxygen in the atmosphere, that is why it is said to be an anaerobic mechanism.
Bacteria do not all need oxygen in the environment to live, some need that oxygen is not exactly present (strict anaerobes) or that it is at low partial pressures (facultative anaerobes).
This mechanism is very characteristic in its location since it is located in the inner membrane of the mitochondria, that is why it will decide to indicate that option as the correct one.
3. What is true of the cattle industry in the US?
O A. The US has $75 billion worth of cattle
O B. The US doesn't export beef.
C. Cattle are second only to poultry as the most valuable animals raised for profit
D. There were nearly 95 million cattle and calves in 2017.
Answers
Answer:
D. There were nearly 95 million cattle and calves in 2017.
Explanation:
hope it helps .
The women has had two miscarriages. What is the chance that she could have a normal child? a. The chance of a normal child is approximately one in four; however, all of the normal children will be translocation carriers.b. The chance of a normal child is approximately one in two; however, all of the normal children will be translocation carriers.c. The chance of a normal child is approximately one in four; however, half of the normal children will be translocation carriers.d. The chance of a normal child is approximately one in two; however, half of the normal children will be translocation carriers
Answers
Tryptophan is an amino acid necessary for E. coli survival and growth. E. coli contain genes coding for enzymes that synthesize tryptophan. These genes are grouped together on a segment of DNA called the tryptophan (trp) operon. Cells can use these enzymes to synthesize tryptophan when it is not present in the environment. owever, when tryptophan is already present in the environment, cellular resources are shifted away from manufacturing the enzymes for tryptophan synthesis. Tryptophan binds with and activates the trp repressor, which then binds to the trp promoter and blocks RNA polymerase. Blocking RNA polymerase decreases the normal transcription rate of the operon. What type of regulation does the trp operon exhibit?a. positive regulation b. protein modification c. negative regulation d. translational regulation
Answers
Answer:
The correct answer is - The tryptophan operon shows C. negative regulation.
Explanation:
Tryptophan is an amino acid, excessively synthesized by the organism, it regulates its transcription through “trp Operon.” In this operon, the corepressor of the tryptophan binds to the repressor protein and gets activated.
This activated repressor now binds to the operator site, and prevents the binding of RNA polymerase enzyme and inhibits the protein synthesis.
Please describe the regulation of the blood glucose 6 hours after a meal?
Please include all relevant organs, hormones, and actions.
Answers
Answer:
Find the description below in the explanation section
Explanation:
The body system regulates the blood sugar level via the hand-in-hand working of insulin and glucagon hormones, both produced by the Pancreas. After a meal, the food undergoes digestion and is broken down into glucose, which is absorbed into the bloodstream. Insulin hormone is released by the pancreas (stimulated by a negative feedback) when the sugar level of the blood increases. This secretion of insulin causes cells to absorb glucose as source of energy, while liver and muscle cells store some of the excess blood glucose as GLYCOGEN.
However, after about 6 hours of taking the meal, the blood sugar (glucose) level must have decreased. This triggers the secretion of Glucagon hormone by the Pancreas. Glucagon hormone, acts in an opposite manner as Insulin hormone, by causing the stored GLYCOGEN in the liver and muscle cells to be converted back to Glucose in order for cells to make use of it.
This continuous process occurs and it is how the body regulates the blood glucose levels.
The allosteric effector molecule 2,3-BPG facilitates transfer of oxygen between maternal and fetal blood in the placenta. Which of the following correctly describes the role of BPG in this process?
a. Fetal hemoglobin binds oxygen better than maternal hemoglobin because BPG is unable to cross the placenta into fetal blood, causing more fetal hemoglobin to be in the R state.
b. Fetal hemoglobin binds oxygen better than maternal hemoglobin because BPG is present at similar levels in fetal and maternal blood, but it binds poorly to fetal hemoglobin, causing more fetal hemoglobin to be in the R state.
c. Fetal hemoglobin binds oxygen better than maternal hemoglobin because BPG is present at similar levels in fetal and maternal blood, but it binds poorly to fetal hemoglobin, causing more fetal hemoglobin to be in the T state.
d. Fetal hemoglobin releases oxygen better than maternal hemoglobin because BPG is present at similar levels in fetal and maternal blood, but it binds more effectively to fetal hemoglobin causing more fetal hemoglobin to be in the T state.
Answers
Answer:
b. Fetal hemoglobin binds oxygen better than maternal hemoglobin because BPG is present at similar levels in fetal and maternal blood, but it binds poorly to fetal hemoglobin, causing more fetal hemoglobin to be in the R state.
Explanation:
BPG is a chemical compound which is found in red blood cells. It is known for decreasing the affinity of hemoglobin with oxygen and thus helps in unloading oxygen from hemoglobin.
Owing to the structural difference, fetal hemoglobin binds to BPG with less affinity as compared to maternal hemoglobin thus it shifts the oxyhemoglobin curve to the left i.e. causes fetal hemoglobin to be in the R state. Due to this, fetal hemoglobin can carry up to 30% more oxygen as compared to maternal hemoglobin. As a result of this, oxygen is readily transferred to fetal blood when maternal blood enters placenta which restricts hypoxia in fetus.
Suppose a plant breeder wants to isolate mutants in tomatoes that are defective in DNA repair. However, this breeder does not have the expertise or equipment to study enzymes in DNA repair systems.
Which methods would best allow the breeder to identify tomato plants that are deficient in DNA repair?
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants. Measure the somatic mutation rates for the putative DNA repair mutant plants.
C) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
D) Measure the germ line spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Answers
The provided question has marked options incorrectely the correct order as follows:
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants.
C) Measure the somatic mutation rates for the putative DNA repair mutant plants.
D) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
E) Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Answer:
The correct answer is: A), C) and E)
Explanation:
The breeder wants to isolate the mutants in tomatoes that are defective in DNA repair, to identify such plants breeder should follow these methods as they will allow best to identifying the defective tomatoes-
Measure the somatic mutation rates for the putative DNA repair mutant plants.
Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants. This will allow the breeder to see and analyze the ability of DNA repair in tomatoes
answer the questions above
Answers
Answer:
1. Herbivores are plant eating animals.
2. Goat and sheep
3. Humans and monkey
4. It usually begins with a producer.
5. Lion and tiger
6. The function of the lateral line is to pick up vibrations from the water.
7. To make it slippery so as to escape from enemies.
8. A predator is an animal which depends on other animals for food.
9. Enamel
10. Incisors
11. 32 teeth
12. Molars
13. Pulp cavity
14. Canine
15. 3 incisors
Hope this helps.
Homologous recombination occurs in a heterozygote in which alleles D and d differ by a single base pair. The D allele has a G at one position, whereas the d allele has a C at the same position. If branch migration causes heteroduplex formation across this position, what is the expected outcome
Answers
Answer:
The DNA repair pathway will recognize the mismatch (G-G) to convert guanine to cytosine (C), thus reverting the DNA sequence to the d allele
Explanation:
DNA repair pathways correct mismatches that can arise during DNA replication and recombination, which can be naturally caused or as consequence of mutagenic treatments (for instance, exposure to UV light). However, these pathways are not always efficient and there are occasions that mismatches escape from the mechanisms of correction. If these mismatches occur in gametic cells, mutations could be fixed in the next generation. The base mismatch repair mechanism during recombination is known as 'gene conversion', since this process produces the conversion of one allele to other as result of an inappropriate base mismatch.
During which phase of mitosis do the nuclear membrane, nucleoli, nucleus dissolve
Answers
Answer:
Prophase stage
Hope this helps
Which type of mutation results in a frame shift mutation? Check all that apply? Substitute Insertion Deletion Point mutation
Answers
Answer: Insertion, Deletion
Explanation:
The frameshift mutation can be defined as a genetic mutation that is caused by the deletion or insertion of the DNA sequence or base pairs that shifts the sequence to be read. As a result of this the abnormal proteins are produced along with incorrect amino acid sequence that either shorter or longer than the normal protein.
Second class levers are best described as follows:___________.
A) "The muscle force and resistive force act on opposite sides of the fulcrum, and the effort required to move the load is at a mechanical advantage"
B) "The muscle force and resistive force act on opposite sides of the fulcrum, but the effort required to move the load is at a mechanical disadvantage"
C) "The muscle force and resistive force act on the same side of the fulcrum, with a longer moment arm for the effort than for the load"
D) "The muscle force and resistive force act on the same side of the fulcrum, with a longer moment arm for the load than for the effort"
Answers
Answer:
A, B, C, D!
Explanation:
g If a pair of sister chromatids fail to separate during anaphase II (meiosis II), what will be the chromosome number of the four resulting gametes with respect to the normal haploid number (n)
Answers
Answer:
The result will be two gametes with a normal haploid number (n), one gamete containing an extra chromosome (n + 1) and one gamete missing one chromosome (n − 1).
Explanation:
Nondisjunction is caused by the failure in the mechanism of separation of homologous chromosomes or sister chromatids during meiosis and/or mitosis. The failure in the separation of sister chromatids during meiosis II is referred to as 'secondary nondisjunction' and it produces two daughter cells with abnormal chromosome numbers.
The fusion of one gamete containing an extra chromosome (n + 1) with a normal (n) gamete will lead to trisomy (2n + 1), while the fusion of one gamete missing one chromosome (n - 1) with a normal gamete will lead to monosomy (2n-1).
If your observations do not support your hypothesis, what
should you
you do?
Answers
Answer:
than admit defeat
Explanation: