the nutrition facts label from a 12 oz can of soft drink is shown below. Note that a serving of the soft drink is defined as 8 oz, so this can contains 1.5 servings of the drink. The nutritional information relates to the amounts per serving, not the amounts in the can.

The Nutrition Facts Label From A 12 Oz Can Of Soft Drink Is Shown Below. Note That A Serving Of The Soft

Answers

Answer 1

The correct answer is C. 65

Explanation:

The serving size of the soft drink is 8oz, besides this, the amount of sugar for this serving size according to the label is 26 grames. Now, to calculate the amount of sugar in 20oz, one of the simplest methods is to use a rule of three, because three values are known, and one is missing. The process is shown below:

1. Write the known values and use x to represent the unknown values

8 oz  =  26 grames of sugar      

20 oz  =  x

2. Use cross multiplication (this means multiply 8 x 6) and divide it into the remaining value

[tex]x = \frac{26 x 20}{ 8}[/tex]   or  x = 26 x 20 / 8

3. Solve the equation

[tex]x =\frac{520}{8}[/tex]      or x = 520 / 8

[tex]x = 65[/tex]

Answer 2

Answer:65

Step-by-step explanation:


Related Questions

The nth term of a geometric sequence is given by an = 27(0.1)n - 1. Write the first five terms of this sequence.

Answers

Answer:

The first first five terms of this sequence are

27 ,2.7 ,0.27 ,0.027 , 0.0027

Step-by-step explanation:

[tex]a(n) = 27(0.1)^{n - 1} [/tex]

where n is the number of term

For the first term

n = 1

[tex]a(1) = 27(0.1)^{1 - 1} = 27(0.1) ^{0} [/tex]

= 27(1)

= 27

Second term

n = 2

[tex]a(2) = 27(0.1)^{2 - 1} = 27(0.1)^{1} [/tex]

= 27(0.1)

= 2.7

Third term

n = 3

[tex]a(3) = 27(0.1)^{3 - 1} = 27(0.1)^{2} [/tex]

= 0.27

Fourth term

n = 4

[tex]a(4) = 27(0.1)^{4 - 1} = 27(0.1)^{3} [/tex]

= 0.027

Fifth term

n = 5

[tex]a(5) = 27(0.1)^{5 - 1} = 27(0.1)^{4} [/tex]

= 0.0027

Hope this helps you

It was found that the mean length of 200 diodes (LED) produced by a company
was 20.04 mm with a standard deviation of 0.02mm. Find the probability that a diode
selected at random would have a length less than 20.01mm​

Answers

Answer:

6.68% probability that a diode selected at random would have a length less than 20.01mm​

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 20.04, \sigma = 0.02[/tex]

Find the probability that a diode selected at random would have a length less than 20.01mm​

This is the pvalue of Z when X = 20.01. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{20.01 - 20.04}{0.02}[/tex]

[tex]Z = -1.5[/tex]

[tex]Z = -1.5[/tex] has a pvalue of 0.0668

6.68% probability that a diode selected at random would have a length less than 20.01mm​

Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their smartphones to be (0.56 , 0.62). Select the correct answer to interpret this interval.

a. A 98% of customers click on ads on their smartphones.
b. We are 98% confident that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.
c. We are 98% confident that the true proportion of customers who click on ads on their smartphones is 0.59.
d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Answers

Answer:

d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Step-by-step explanation:

Confidence interval:

x% confidence

Of a sample

Between a and b.

Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.

In this question:

I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.

Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.

Plz. Can anyone explain and tell the answer of this question.I promise I will mark it as brainliest Question.

Answers

Answer:

x = 15

y = 90

Step-by-step explanation:

Step 1: Find x

We use Definition of Supplementary Angles

9x + 3x = 180

12x = 180

x = 15

Step 2: Find y

All angles in a triangle add up to 180°

3(15) + 3(15) + y = 180

45 + 45 + y = 180

90 + y = 180

y = 90°

slope of (-2, -5) and (1, -3)

Answers

Start by making a table for the ordered pairs with the x-values

in the left column and the y-values in the right column.

            --x--|--y--

             -2  |  -5

              1   |  -3

                  |

                  |

Now remember that the slope is equal to the rate of change

or the change in y over the change in x.

We can see that the y-values go from -5 to -3 so the change in y is 2.

The x-values go from -2 to 1 so the change in x is 3.

So the change in y over the change in x is 2/3.

This means that the slope is also equal to 2/3.

At 95% confidence, what is the margin of error of the number of eligible people under 20 years old who had a driver's license in year A? (Round your answer to four decimal places.

Answers

Answer:

(0.6231 , 0.6749)

Step-by-step explanation:

With the information we have, it is impossible to solve the exercise, therefore I was looking for information to complete it and we have to:

the sample proportion is 64.9%, or 0.649 plus the sample size is 1300 (n)

Now, we have that the standard error is given by:

SE = (p * (1 - p) / n) ^ (1/2)

replacing

SE = (0.649 * (1 - 0.649) / 1300) ^ (1/2)

SE = 0.0132

Now we have that confidence level is 95%, hence α = 1 - 0.95 = 0.05

α / 2 = 0.05 / 2 = 0.025, Zc = Z (α / 2) = 1.96

With this we can calculate margin of error like so:

ME = z * SE

ME = 1.96 * 0.0132

ME = 0.0259

Finally the interval would be:

CI = (p - ME, p + ME)

CI = (0.649 - 0.0259, 0.649 + 0.0259)

CI = (0.6231, 0.6749)

A car travelling from Ibadan to Lagos at 90 km/hr

takes 1 hour 20 min. How fast must one travel to

cover the distance in one hour?

Answers

Answer:

A velocity of 120km/h is needed to cover the distance in one hour

Step-by-step explanation:

The velocity formula is:

[tex]v = \frac{d}{t}[/tex]

In which v is the velocity, d is the distance and t is the time.

A car travelling from Ibadan to Lagos at 90 km/hr takes 1 hour 20 min.

This means that [tex]v = 90, t = 1 + \frac{20}{60} = 1.3333[/tex]

We use this to find d.

[tex]v = \frac{d}{t}[/tex]

[tex]90 = \frac{d}{1.3333}[/tex]

[tex]d = 90*1.3333[/tex]

[tex]d = 120[/tex]

The distance is 120 km.

How fast must one travel to cover the distance in one hour?

Velocity for a distance of 120 km(d = 120) in 1 hour(t = 1). So

[tex]v = \frac{d}{t}[/tex]

[tex]v = \frac{120}{1}[/tex]

[tex]v = 120[/tex]

A velocity of 120km/h is needed to cover the distance in one hour

Which comparison is correct?
0.298 < 0.289
0.420 > 0.42
1.32 < 1.319
d) 3.544 > 3.455

Answers

Step-by-step explanation:

Option D is the correct answer because 3.544 is greater than 3.455

Option D is true in given comparison.

Here,

We have to find the correct comparison.

What is Decimal expansion?

The decimal expansion terminates or ends after finite numbers of steps. Such types of decimal expansion are called terminating decimals.

Now,

In option D;

The one tenth of 3.544 is 5 and place value of one tenth number in 3.455 is 4.

Clearly, 5 > 4

So, 3.544 > 3.455

Hence, option D; 3.544 > 3.455 is true.

Learn more about the Decimal expansion visit:

https://brainly.com/question/26301999

#SPJ2

A case-control study was conducted to evaluate the relationship between artificial sweeteners and bladder cancer. 3,000 cases and 3,000 controls were enrolled in the study. Amongst the cases, 1,293 had used artificial sweeteners in the past, while 1,707 had never used artificial sweeteners. Among the controls, 855 had used sweeteners and 2,145 had not. Calculate the odds of being a case.

Answers

Answer:

Odds of being a case = 1.90

Step-by-step explanation:

Relationship between artificial sweeteners and bladder cancer.

Amongst the cases, 1,293 had used artificial sweeteners in the past, while 1,707 had never used artificial sweeteners.

used AS = 1,293

Not used AS = 1,707

Among the controls, 855 had used sweeteners and 2,145 had not.

We can prepare a table from the above information,

                                 Cases              Controls

used AS                  a = 1,293            b = 855

Not used AS           c = 1,707            d = 2,145

The odds of being a case may be calculated as

[tex]$ odds = \frac{a \times d}{b \times c} $[/tex]

[tex]$ odds = \frac{1,293 \times 2,145}{855 \times 1,707} $[/tex]

[tex]odds = 1.90[/tex]

Therefore, we can conclude that a person having bladder cancer used artificial sweeteners was 1.90 times the odds that a person without bladder cancer used artificial sweeteners .

Question: A, B, C, or D?

Answers

Answer:

Hello There!

Your best choice is B. Both the mean and median will decrease, But the mean will decrease by more than the median. Because, A. wouldn't make sense at all. Well, C. The mean will decrease but also the median aswell too. And, D. They both will decrease aswell but the mean will drop down more than the median. So, Your best answer is B. Hope This Example help your homework!!~

Answer:

Hey!

I definitely think that B is the answer!

Step-by-step explanation:

(a, c and dont work with The Question!!)

HOPE THIS HELPS!!

:>

Still timed. More math needing help with, i'll double points and mark brainliest! 1. (y - 6) (y + 3) 2. (4x - 5) (x - 7) 3.(3x - 2) ( 4x - 1)

Answers

Answer:

1. y² - 3x - 18

2. 4x² - 33x + 35

3. 12x² - 11x + 2

Step-by-step explanation:

All we do with these questions are expanding the factored binomials. Use FOIL:

1. y² + 3y - 6y - 18

y² - 3y - 18

2. 4x² - 28x - 5x + 35

4x² - 33x + 35

3. 12x² - 3x - 8x + 2

12x² - 11x + 2

Answer:

1) (y-6) (y+3)

=> [tex]y^2+3y-6y-18[/tex]

=> [tex]y^2-3y-18[/tex]

2) (4x-5) (x-7)

=> [tex]4x^2-28x-5x+35[/tex]

=> [tex]4x^2-33x+35[/tex]

3) (3x - 2) ( 4x - 1)

=> [tex]12x^2-3x-8x+3[/tex]

=> [tex]12x^2-11x+3[/tex]

What is the value of x?

Enter your answer in the box.

Answers

Answer:

x=11

Step-by-step explanation:

Since the lines in the middle are parallel, we know that both sides are proportional to each other.

6:48 can be simplified to 1:8

Since we know the left side ratio is 1:8, we need to match the right side with the same ratio

We can multiply the ratio by 5 to match 5:3x+7

5:40

5:3x+7

Now we can set up the equation: 40=3x+7

Subtract 7 from both sides

3x=33

x=11

HELP!!!! 25 POINTS AND BRAINLIEST ANSWER!!!!


Look at photo above!

Answers

Answer:

8.96 seconds

Step-by-step explanation:

Bailey and Jade both play basketball. The table and graph show the total number of games that each of their teams won over six weeks. A coordinate plane labeled Jade's Team. The x-axis is labeled Weeks and the y-axis is labeled Wins. Points plotted are (1, 0), (2, 1), (3, 3), (4, 5), (5, 6), and (6, 7). Bailey’s Team Number of weeks Wins 1 2 2 2 3 3 4 4 5 4 6 6 After which week had the two teams won the same number of games? week 1 week 2 week 3 week 5

Answers

Answer:

Week 3

Step-by-step explanation:

Week one was 1,0

Week two was 2,1

Week three was 3,3 which is the same number the teams have won

Therefore the answer is week 3

Hope this helps

is a parallelogram sometimes always or never a trapezoid

Answers

yes

Step-by-step explanation:

parallelogram are quadrilaterals with two sets of parallel sides. since square must be quadrilaterals with two sets of parallel sides ,then all squares are parallelogram ,a trapezoid is quadrilateral.

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow. Click on the datafile logo to reference the data. 6 4 6 8 7 7 6 3 3 8 10 4 8 7 8 7 5 9 5 8 4 3 8 5 5 4 4 4 8 4 5 6 2 5 9 9 8 4 8 9 9 5 9 7 8 3 10 8 9 6Develop a 95% confidence interval estimate of the population mean rating for Miami.

Answers

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\[/tex]

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=50-1=49[/tex]

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=2.01 \cdot 0.305=0.61[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95[/tex]

The 95% confidence interval for the mean is (5.73, 6.95).

Can somebody help me with this question

Answers

The answer of the are is : area = x^2+8x

Or x(x+8)

Both answer are correct just choose one


Explain

Area =1/2 base x height


Base : 2x

Height: x+8

Area : 1/2 base x height 1/2 x(2x) x (x+8)


1/2 x (2x) x (x+8)

Cancel 2

( x) x (x+8)

Open the bracket

X^2 +8x


Have a great day

Stay safe

What is the first step when solving the equation below for x?
4
0.2
= 1.9
Add 1.9 to both sides of the equation.
Divide each side of the equation by 4.
Add 0.2 to both sides of the equation.
Subtract 0.2 from both sides of the equation.

Answers

Step-by-step explanation:

4x + 0.2=0.9

transposing 0.2 to RHS

=> 4x =0.9-0.2 => 4x=0.7

transposing 4 to RHS

=> x=0.7÷4

=> x=0.175

if it helps plzz mark it as brainliest

Answer: add 0.2

Step-by-step-explanation:

If someone weighs 130 kilos what is the conversion in lbs

Answers

Answer:

286.60

Please tell me if I'm wrong.

Amanda is constructing equilateral triangle JKL inscribed in circle M. To construct the inscribed polygon, she is going to use a compass to partition the circle into congruent arcs. To what width should she set the compass when partitioning the circle? A. The width must be equal to the radius of circle M. B. The width must be equal the diameter of circle M. C. The width can be equal to either the radius or the diameter of circle M. D. The width can be any size greater than the radius but less than the diameter of circle M. E. The width must be less than the radius of circle M. help meee please!!!!!!!!!!!!!!!!!

Answers

Given:

An equilateral triangle JKL inscribed in circle M.

Solution:

To draw an equilateral triangle inscribed in circle follow the steps:

1: Draw a circle with any radius.

2. Take any point A, anywhere on the circumference of the circle.

3.  Place the compass on point A, and swing a small arc crossing the circumference of the circle.

Remember the span of the compass should be the same as the radius of the circle.

4. Place the compass at the intersection of the previous arc and the circumference and draw another arc but don't change the span of the compass.

5. Repeat this process until you return to point A.

6. Join the intersecting points on the circle to form the equilateral triangle.

So the correct option is A. The width must be equal to the radius of circle M.

The amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and standard deviation 13 mL. Suppose that 43 randomly selected people are observed pouring syrup on their pancakes. Round all answers to 4 decimal places where possible.

What is the distribution of XX? XX ~ N(_______,_________)
What is the distribution of ¯xx¯? ¯xx¯ ~ N(______,_________)
If a single randomly selected individual is observed, find the probability that this person consumes is between 61.4 mL and 62.8 mL. ________
For the group of 43 pancake eaters, find the probability that the average amount of syrup is between 61.4 mL and 62.8 mL. _________
For part d), is the assumption that the distribution is normal necessary? No Yes
please only answer if you are able to answer all parts correctly

Answers

Answer:

(a) X ~ N([tex]\mu=63, \sigma^{2} = 13^{2}[/tex]).

    [tex]\bar X[/tex] ~ N([tex]\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}[/tex]).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

Step-by-step explanation:

We are given that the amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and a standard deviation of 13 mL.

Suppose that 43 randomly selected people are observed pouring syrup on their pancakes.

(a) Let X = amount of syrup that people put on their pancakes

The z-score probability distribution for the normal distribution is given by;

                      Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean amount of syrup = 63 mL

            [tex]\sigma[/tex] = standard deviation = 13 mL

So, the distribution of X ~ N([tex]\mu=63, \sigma^{2} = 13^{2}[/tex]).

Let [tex]\bar X[/tex] = sample mean amount of syrup that people put on their pancakes

The z-score probability distribution for the sample mean is given by;

                      Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean amount of syrup = 63 mL

            [tex]\sigma[/tex] = standard deviation = 13 mL

            n = sample of people = 43

So, the distribution of [tex]\bar X[/tex] ~ N([tex]\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}[/tex]).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < X < 62.8 mL)

   P(61.4 mL < X < 62.8 mL) = P(X < 62.8 mL) - P(X [tex]\leq[/tex] 61.4 mL)

  P(X < 62.8 mL) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{62.8-63}{13}[/tex] ) = P(Z < -0.02) = 1 - P(Z [tex]\leq[/tex] 0.02)

                                                           = 1 - 0.50798 = 0.49202

  P(X [tex]\leq[/tex] 61.4 mL) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{61.4-63}{13}[/tex] ) = P(Z [tex]\leq[/tex] -0.12) = 1 - P(Z < 0.12)

                                                           = 1 - 0.54776 = 0.45224

Therefore, P(61.4 mL < X < 62.8 mL) = 0.49202 - 0.45224 = 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < [tex]\bar X[/tex] < 62.8 mL)

   P(61.4 mL < [tex]\bar X[/tex] < 62.8 mL) = P([tex]\bar X[/tex] < 62.8 mL) - P([tex]\bar X[/tex] [tex]\leq[/tex] 61.4 mL)

  P([tex]\bar X[/tex] < 62.8 mL) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{62.8-63}{\frac{13}{\sqrt{43} } }[/tex] ) = P(Z < -0.10) = 1 - P(Z [tex]\leq[/tex] 0.10)

                                                           = 1 - 0.53983 = 0.46017

  P([tex]\bar X[/tex] [tex]\leq[/tex] 61.4 mL) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] [tex]\leq[/tex] [tex]\frac{61.4-63}{\frac{13}{\sqrt{43} } }[/tex] ) = P(Z [tex]\leq[/tex] -0.81) = 1 - P(Z < 0.81)

                                                           = 1 - 0.79103 = 0.20897

Therefore, P(61.4 mL < X < 62.8 mL) = 0.46017 - 0.20897 = 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

What is the correct solution to -3x > 12?

Answers

Answer:

x < -4

Step-by-step explanation:

-3x > 12

Divide both parts with -3.

-3x/-3 > 12/-3

x < -12/3

x < -4

It would be any number bigger then the number 4, so try 5.

The scientist performs additional analyses and observes that the number of major earthquakes does appear to be decreasing but wonders whether the relationship is statistically significant. Based on the partial regression output below and a 5% significance level, is the year statistically significant in determining the number of earthquakes above magnitude 7.0?Dependent Variable: Earthquakes above Magnitude 7.0 Coefficients Standard t Stat P-value Lower 95% Upper 95% ErrorIntercept 64.67 38.08 4.32 89.22 240.12Year -0.07 0.02 -3.82 -0.11 -0.04

Answers

Answer:

Step-by-step explanation:

Hello!

A regression model was determined in order to predict the number of earthquakes above magnitude 7.0 regarding the year.

^Y= 164.67 - 0.07Xi

Y: earthquake above magnitude 7.0

X: year

The researcher wants to test the claim that the regression is statistically significant, i.e. if the year is a good predictor of the number of earthquakes with magnitude above 7.0 If he is correct, you'd expect the slope to be different from zero: β ≠ 0, if the claim is not correct, then the slope will be equal to zero: β = 0

The hypotheses are:

H₀: β = 0

H₁: β ≠ 0

α: 0.05

The statistic for this test is a student's t: [tex]t= \frac{b - \beta }{Sb} ~~t_{n-2}[/tex]

The calculated value is in the regression output [tex]t_{H_0}= -3.82[/tex]

This test is two-tailed, meaning that the rejection region is divided in two and you'll reject the null hypothesis to small values of t or to high values of t, the p-value for this test will also be divided in two.

The p-value is the probability of obtaining a value as extreme as the one calculated under the null hypothesis:

p-value: [tex]P(t_{n-2}\leq -3.82) + P(t_{n-2}\geq 3.82)[/tex]

As you can see to calculate it you need the information of the sample size to determine the degrees of freedom of the distribution.

If you want to use the rejection region approach, the sample size is also needed to determine the critical values.

But since this test is two tailed at α: 0.05 and there was a confidence interval with confidence level 0.95 (which is complementary to the level of significance) you can use it to decide whether to reject the null hypothesis.

Using the CI, the decision rule is as follows:

If the CI includes the "zero", do not reject the null hypothesis.

If the CI doesn't include the "zero", reject the null hypothesis.

The calculated interval for the slope is: [-0.11; -0.04]

As you can see, both limits of the interval are negative and do not include the zero, so the decision is to reject the null hypothesis.

At a 5% significance level, you can conclude that the relationship between the year and the number of earthquakes above magnitude 7.0 is statistically significant.

I hope this helps!

(full output in attachment)

Suppose you are forming a committee from a group of 15 biology student, 12 math students, and 9 physics students. How many possibilities are there if

Answers

Answer:

12,474,000 possibilities

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Suppose you are forming a committee from a group of 15 biology student, 12 math students, and 9 physics students. How many possibilities are there if your committee needs to have at most 2 biology students, exactly 3 math students, and exactly 2 physics students?

To tackle this question, we will use the concept of combination since it deals with selection. Generally, selecting 'r' objects out of 'n' pools of object can be done using the formula;

nCr = n!/(n-r)!r!

If we are to form a committee of at most 2 biology students, exactly 3 math students and exactly 2 physics students from a group of 15 biology student, 12 math students, and 9 physics students, this can be done in the following ways;

For Physics students:

Selecting exactly 2 physics students from a group of 9 students will be:

9C2 = [tex]\frac{9!}{(9-2)!2!}\\[/tex]

= [tex]\frac{9!}{(7)!2!}\\[/tex]

[tex]= \frac{9*8*7!!}{(7)!2!}\\= 9*4\\= 36ways[/tex]

for Mathematics students:

Selecting exactly 3 math students from a group of 12 students will be:

[tex]12C3 = \frac{12!}{12-3)!3!}\\= \frac{12!}{9!3!}\\= \frac{12*11*10*9!}{9!*6}\\= 220 ways[/tex]

For Biology Students:

Selecting at most 2 biology students from a group of 15biology student will be:

15C1 * 15C2 (at most 2 students)

= [tex]\frac{15!}{14!1!} * \frac{15!}{13!2!}\\\\[/tex]

= 15*105

= 1,575 ways

The total number of possibilities will be = 36*220*1,575 = 12,474,000 possibilities

The Mathalot Company makes and sells textbooks. They have one linear function that represents the cost of producing textbooks and another linear function that models how much income they get from those textbooks. Describe the key features that would determine if these linear functions ever intercepted. (10 points)

Answers

this is the answer trust me i got it right

A 3-digit security code can use the numbers 0–9. How many possible combinations are there if the numbers can be repeated?

Answers

1000 possible combination

0-9= 10 numbers

10*10*10=1000

Which equation represents a line that passes through (2,-2) and has a slope of 3?

y-2 = 3(x +
y – 3 = 2(x + ?)
y +
= 3(x - 2)
y +
= 2(x - 3)

Answers

y=3x-8 is the answer , maybe u can find it in this equations

Find f o g and g o f to determine if f and g are inverse functions. If they are not inverses, pick the function that would be the inverse with f(x). f(x) = (-2/x) – 1; g(x) = -2/(x+1) Choices: a. g(x) has to be: (1+x)/2 b. g(x) has to be: x/2 c. g(x) has to be: 2 – (1/x) d. Inverses

Answers

Answer:

(f o g) = x, then, g(x) is the inverse of f(x).

Step-by-step explanation:

You have the following functions:

[tex]f(x)=-\frac{2}{x}-1\\\\g(x)=-\frac{2}{x+1}[/tex]

In order to know if f and g are inverse functions you calculate (f o g) and (g o f):

[tex]f\ o\ g=f(g(x))=-\frac{2}{-\frac{2}{x+1}}-1=x+1-1=x[/tex]

[tex]g\ o\ f=g(f(x))=-\frac{2}{-\frac{2}{x}+1}=-\frac{2}{\frac{-2+x}{x}}=\frac{2x}{2-x}[/tex]

(f o g) = x, then, g(x) is the inverse of f(x).

What’s the probability of getting each card out of a deck?

Determine the probability of drawing the card(s) at random from a well-shuffled regular deck of 52 playing cards.​

a. a seven​​​​​​​​​​​​ __________

b. a six of clubs​​​​​​​​​​​​. ___________

c. a five or a queen​​​​​​​​​​​ ___________

d. a black card​​​​​​​​​​​​. ___________

e. a red card or a jack​​​​​. ___________

f. a club or an ace​​​​​​​​​​​. ___________

g. a diamond or a spade​​​​​​​​​​​. ___________

Answers

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen​​​​​​​​​​​ is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

A triangle has sides of lengths 9, 7, and 12. Is it a right triangle? Explain.

Answers

Answer:

Yes based on the numbers .

Step-by-step explanation:

Answer:Yes

Step-by-step explanation:Based on the number given, it shows that there is a hypotenuse (The longest side of a right triangle, in this case being 12), And opposite (Another part of the right triangle, that could be either 9 or 7), and the adjacent (The line next to the opposite, which could be 9 or 7)

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