The maximum speed of the piston is 8.6 m/s and the maximum force acting on the piston when the engine is running at 3 800 rpm is 7 486 N
The given information is that the motion of a piston in an auto engine is simple harmonic. if the piston travels back and forth (side to side) over a distance of 12 cm, and the piston has a mass of 1.5 kg, The maximum speed of the piston is determined by the equation for the simple harmonic motion:
v = (2πfA)^0.5 where f is the frequency of the motion (in this case, 3 800 rpm), and A is the maximum displacement (in this case, 12 cm).
v = (2π(3800)(0.12))^0.5 v = 8.6 m/s.
The maximum force acting on the piston is determined by the equation for the simple harmonic motion:
F = mω^2A, where m is the mass of the piston (in this case, 1.5 kg), ω is the angular velocity (in this case, 2πf = 2π(3800) = 23 883 rad/s) and A is the maximum displacement (in this case, 12 cm).
F = (1.5)(23 883)^2(0.12) F = 7 486 N
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the uniform seesaw shown below is balanced on a fulcrum located 3.0 m from the left end. the smaller boy on the right has a mass of 40 kg and the bigger boy on the left has a mass 80 kg. what is the mass of the board?
126 kg is the mass of the board (in kg)
m1=41 kg
m2= 85 kg
r1=3m
mass of the board= m1+m2
mass of the board=41+85
mass of the board=126 kg
In physics, mass is a way to describe inertia, a quality that all matter shares. Essentially, it is a mass of matter's resistance to altering its direction or speed in reaction to the application of a force. The amount of change caused by an applied force decreases as a body's mass increases. The kilogram, the ISU's unit of mass, is equal to 6.62607015 1034 joule seconds using Planck's constant (SI). One joule is created by multiplying one kilogram by one square meter per second. The kilogram is determined by exact measurements of Planck's constant because the second and the meter have already been defined in terms of other physical constants.
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after 10 seconds the car body is 1/3 foot above its equilibrium position and at the high point in its cycle. what were the initial conditions ?
force is required to stretch it a certain length than you would need to stretch a less stiff spring the same length.
How do you find the amplitude of oscillation?The angular frequency ω, period T, and frequency f of a simple harmonic oscillator are given by ω=√km, T = 2π√mk, and f = 12π√km, where m is the mass of the system and k is the force constant.if one increases the mass of a simple harmonic oscillator (and keeps everything else the same) the frequency of oscillation must decrease. This means that the oscillator will move more slowly. On the other hand if one increases the spring constant K the frequency will increase.So, recapping, the period of a mass on a spring does not depend on the amplitude. You can change the amplitude, but it will not affect how long it takes this mass to go through a whole cycle.x(t) = A cos(ωt + φ). A is the amplitude of the oscillation, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction.0.43622 seconds
0.9158 foot
-4.43 ffot/sec
we first find the period of oscillation
= 2π√w/gk
= 2π√4000/32x2600
= 2π√0.00481
= 2π0.0694
= 0.43622
b. we find the angular velocity
2π/T
= 2π/0.43622
= 14.41 rad/sec
we find displacement
rom the calculation in the attachment
Ф = -144.1
initial condition
1*cos(-144.1 rad)
= 0.9158 foot
initial velocity of the car
= (-1)(14.41)sin(ω(0)-144.1)
= -4.44 foot/sec
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heat is radiated from earth to space predominately in the form of: a) infrared radiation. d) solar flares. b) radioactivity.
Answer: a) infrared
Explanation:
A spaceship of mass spaceship = 110000.0 kg starts at rest (vi= 0), then accelerates by releasing
exhaust gas of mass gas = 10600.0 kg with a velocity of gas = -100. What is the speed of the spaceship
Answer:
Approximately [tex]9.64\; {\rm m\cdot s^{-1}}[/tex] (assuming that the velocity of the exhaust is [tex](-100)\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of this object will be [tex]p = m\, v[/tex].
Assume that there is no external force on this spaceship. The total momentum of the ship and the exhaust will be conserved. In other words,
[tex]\begin{aligned}& (\text{Momenum of Spaceship, before}) \\ &+ (\text{Momentum of Exhaust, before}) \\ =\; & (\text{Momenum of Spaceship, after}) \\ &+ (\text{Momentum of Exhaust, after})\end{aligned}[/tex].
Rearrange to find the momentum of the spaceship after releasing the exhaust:
[tex]\begin{aligned} & (\text{Momenum of Spaceship, after}) \\ =\; & (\text{Momenum of Spaceship, before}) \\ &+ (\text{Momentum of Exhaust, before}) \\ &- (\text{Momentum of Exhaust, after})\end{aligned}[/tex].
It is given that the spaceship and the exhaust were initial stationary. Hence, initial momentum will be [tex]0\; {\rm kg \cdot m\cdot s^{-1}}[/tex] for both the ship and the exhaust.
[tex]\begin{aligned} & (\text{Momenum of Spaceship, after}) \\ =\; & (0\; {\rm kg \cdot m\cdot s^{-1}}) \\ &+ (0\; {\rm kg \cdot m\cdot s^{-1}}) \\ &- (\text{Momentum of Exhaust, after})\end{aligned}[/tex].
Since the exhaust is of mass [tex]10600\; {\rm kg}[/tex] and velocity [tex](-100)\; {\rm m\cdot s^{-1}}[/tex], the momentum of the exhaust after release will be:
[tex]\begin{aligned} & (\text{Momenum of Exhaust, after}) \\ =\; & (\text{mass of Exhaust})\, (\text{Velocity of Exhaust, after}) \\ =\; & (10600.0\; {\rm kg})\, ((-100)\;{\rm m \cdot s^{-1}}) \\ =\; & (-1.06000\times 10^{6})\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}[/tex].
Divide the momentum of the spaceship by mass to find velocity:
[tex]\begin{aligned} & (\text{Velocity of Spaceship, after}) \\ =\; & \frac{(\text{Momentum of Spaceship})}{(\text{mass of Spaceship})} \\ =\; & \frac{((-1.06000\times 10^{6})\; {\rm kg \cdot m\cdot s^{-1}})}{(110000.0\; {\rm kg})} \\ \approx\; & 9.64\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 x 107 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 x 1027 kg). Part A What is the value of g on this large, but low-density, world? Express your answer with the appropriate units. НА ? g= Value Units Submit Request Answer Provide Feedback
3.86 m/s^2 is the value of gravity on this large, but low-density, world.
given :
Kepler-12b
diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),
mass = 0.43 Jupiter (M_Jupiter = 1.90 × 10^27 kg ).
g = GM/r^2
g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2
g = 3.859 ~ 3.86 m/s^2
Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.
On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.
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you look down at a coin that lies at the bottom of a pool of liquid of depth d and index of refraction n (fig. 34.33). because you view with two eyes, which intercept different rays of light from the coin, you perceive the coin to be where extensions of the intercepted rays cross, at depth da instead of d. assuming that the intercepted rays in fig. 34.33 are close to a vertical axis through the coin, show that da da = d=n.
The water is medium 1, so
n₁ = n(w)
which we simply write as n. The air is medium 2, for which
n₁≈ 1
We refer to points where the light rays strike the water surface as A (on the left side of Figure) and B (on the right side of the picture). The point midway between A and B (the center point in the picture) is C. The penny P is directly below C, and the location of the “apparent” or virtual penny is V.
We note that the angle ∠CVB (the same as angle ∠CVA) is equal to θ₂ and the angle ∠CPB (the same as angle ∠CPA) is equal to θ₁.
The triangles CVB and CPB share a common side, the horizontal distance from C to B (which we refer to as x).
Therefore,
tan θ₂ = x / dₐ
tan θ₁ = x / d
Using the small-angle approximation (so a ratio of tangents is nearly equal to a ratio of
sines) and the law of refraction, we obtain
tan θ₁ / tan θ₂ = sin θ₁ / sin θ₂
⇒ (x / dₐ) / (x / d) ≈ n₁ / n₂
⇒ d / dₐ ≈ n
⇒ dₐ = d / n
Therefore, the above calculations shows that using law of refraction, dₐ = d / n. Hence, proved.
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suppose two cards, one twice as massive as the other, fly apart when compressed, spring that joins them is released. how fast does the heavier car roll compared with the lighter card
Answer: The heavier car rolls with half the acceleration as the lighter car.
the primary coil of a transformer has 260 260 turns and its secondary coil has 520 520 turns. round all answers to two decimal places, as needed. if the ac voltage applied to the primary coil is 150 150 v, what voltage is present in its secondary coil?
3V voltage is present in its secondary coil.
As per the question:
Primary coil turns(Np)=260
Secondary coil turns(Ns)=520
AC voltage to primary coil (Ep)=150V
AC voltage to secondary coil(Es)=?
Es/Ep=Ns/Np
Es=Ns*Ep/Np
Es=520*150/260
Es=300V
Round to two decimal places,
so, Es=3V
What is transformer?The transformer can be defined as a device that steps up or down voltage in the most basic sense. The output voltage is increased in a step-up transformer and dropped in a step-down transformer. For the system to maintain an equal input and output power, the step-up transformer will reduce the output current and the step-down transformer will increase the output current.
What is the principle of transformer?The transformer works on the principle of Faraday's law of electromagnetic induction and mutual induction.
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I understand that the question you are looking for is:
The primary coil of a transformer has 260 turns and its secondary coil has 520 turns. Round all answers to two decimal places, as needed. If the AC voltage applied to the primary coil is 150 v, what voltage is present in its secondary coil?
a bicyclist is riding north on level ground and has zero net force. a single force pointing south then acts on the bicycle. which effect does the new force have on the motion of the bicycle? responses
If the single force pointing south acts on the bicycle then it will slow down or even stop, depending on the size of the force applied.
The cyclist is travelling north at a constant speed because the question says there is no net force acting on him.
The new force is against the direction of travel so will decelerate (slow down) the cyclist because,
Force, mass and acceleration are linked by the formula
= Force = mass x acceleration
= F = m X a
Moreover, it is given that the net force acting initially on the bicycle is zero.
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the filament of a light bulb has a resistance of 20.0 ω at 20oc and 160 ω when the light is on. find the temperature of the filament when the light is on. (the temperature coefficient of resistivity is 3.50x10-3 oc-1.)
The temperature of the filament of the bulb when the light is on is equal to 2020° C.
What is temperature of coefficient of resistance?
The change in electrical resistance of a substance with respect to each degree of temperature change is known as the temperature coefficient of resistance sometimes also called as Coefficient of resistivity.
As a result, the process of electron collision within the material determines the electrical resistance of conductors like gold, aluminum, silver, and copper. The process of electron collision speeds up and becomes more rapid as temperature rises. As a result, the resistance will climb as the conductor's temperature rises.
Given in the question,
Initial temperature, T₀ = 20°C
Initial Resistance, R₀ = 20.0 Ω
Final resistance, R = 160 Ω
Coefficient of resistivity, α = 3.50 * 10⁻³ °C⁻¹
and we have to fund the final temperature, T
The change in resistance and temperature is given by the equation:
[tex]R = R_0 [ 1 + \alpha (T - T_0)][/tex]
This equation can also be written as:
[tex]T = \frac{{\frac{R}{R_0}-1} }{\alpha} + T_0[/tex]
On putting the values from the question we get:
[tex]T = \frac{{\frac{160}{20}-1} }{3.5 \times 10^{-3}} + 20[/tex]
T = 2020° C
Hence, the final temperature of the filament is 2020° C.
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Which is the correct name of this compound? *
N₂03
2 pts
Answer: Dinitrogen trioxide
Explanation:
The chemical compound with the formula N2O3 is dinitrogen trioxide. One of the straightforward nitrogen oxides. It has covalent type of compound. It is a powerful oxidizer. It is combined with other chemical compounds to be used as an oxidizing agent. It is also used in the chemical industry, such as in making nylon, dyes, etc.
Nitrogen trioxide, sometimes known as N2O3, is a chemical compound made of nitrogen and oxygen. Nitrogen sesquioxide or dinitrogen trioxide are other names for it. It is a substance that is extremely toxic and irritating to mucous membranes.
Dinitrogen trioxide is a blue liquid with a sharp, disagreeable odor. It is a deep blue solid with an acidic nature.
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A planet moves in an elliptical orbit around the sun. The mass of the sun is Ms . The minimum and maximum distances of the planet from the sun are R1 and R2, respectively. Using Kepler's 3rd law and Newton's law of universal gravitation, find the period of revolution of the planet as it moves around the sun. Assume that the mass of the planet is much smaller than the mass of the sun. Use for the gravitational constant. Express the period in terms of G, Ms,R1 , and R2.
Assume that the planet's mass is substantially lower than that of the sun. Use in relation to the gravitational constant. Describe the duration in terms of G, Ms,R1 , and R2 is π√(R1+R2)³2GM.
By applying Newton's law, we can state that the centripetal force experienced by the planet due to its elliptical orbit will equalize the gravitational force exerted by the sun on the planet.
mv₂/(R1+R2)/2=GMm/(R1+R2/2)²
Here, m is the mass of the planet, v is the orbital velocity of the planet and G=6.67×10⁻¹¹N⋅m²⋅kg⁻² is the universal gravitational constant.
The period of revolution is given by,
P=2π(R1+R2)/v
Substituting we get,
P=2π((R1+R2)/2)√2GM/R1+R2
=π√(R1+R2)³2GM.
Hence, the time period of revolution is π√(R1+R2)³2GM.
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Which of the following statements are true of free-
falling objects of different mass? Include all that apply.
a. The rate of acceleration is the same despite their
different masses.
b. They experience the same force of gravity.
c. They have the same g value but a different
acceleration.
d. They have the same acceleration but a different g
value.
e. nonsense! None of these statements are true of
such objects.
Statement "a" is true.
it's the only one of the bunch.
The true statement for free-falling objects of different masses is the rate of acceleration is the same despite their different masses. The correct option is a.
What is acceleration?Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
If things of different masses are dropped from the same height, they will still impact the ground at the same time because Earth provides everything with the exact same acceleration.
Therefore, the correct option is a, The rate of acceleration is the same despite their different masses.
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(a) a certain lens has a focal length of 79.0 cm in air and a refractive index of 1.55. find its focal length in water.
The focal length of lens in water is 23.75cm if focal length of same lens in air is 79cm and refractive index is 1.55
Delineation of the frequency and refraction points. The refractive file decides how much the way of light is bowed, or refracted, while entering a material. This is depicted by Snell's law of refraction, n1 sin θ₁ = n2 sin θ₂, where θ1 and θ2 are the point of frequency and point of refraction, separately, of a beam crossing the connection point between two media with refractive records n1 and n2.
The refractive records likewise decide how much light that is reflected while arriving at the point of interaction, as well as the basic plot for all out inward reflection, their power (Fresnel's conditions) and Brewster's angle.
According to lens maker's formula, we know that
1/f=(μ-1)(1/R₁-1/R₂)
where f is the focal length of lens and μ is refractive index ,and R₁,R₂ are the radius of given lens.
For focal length in air
=>1/f₁=(1.55-1)(1/R₁-1/R₂)-----eq1
Now, for focal length in water
=>1/f₂=(1.55/1.33-1)(1/R₁-1/R₂)------eq2
On dividing eq2 by eq1,we get
=>f₁/f₂ = [(1.55-1)×1.33] / (1.55-1.33)]
=>79 / f₂ =[(0.55)×1.33] / (0.22)]
=> f₂ =79 / [(0.7315/0.22)]
=> f₂ = 79/3.325
=>f₂ =23.75cm
Hence, focal length in water is 23.75cm.
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ultrasound is used to view the interior of the body, much as x rays are utilized. for sharp imagery, the wavelength of the sound should be around one-fourth (or less) the size of the objects to be viewed. approximately what frequency of sound is needed to produce a clear image of a tumor that is 1.00 mm across if the speed of sound in the tissue is 1550 m/s ?
The frequency of sound needed to produce a clear image of a tumour that is 1.00 mm across is approximately 6.2 MHz (6,200,000 Hz).
What is frequency?
The amount of times this same alternating current (AC) circuits from positive to negative in a second is referred to as frequency. In direct currents, this switching doesn't really take place (DC). Hertz is the unit of frequency (Hz). For instance, a current is said to have a frequency of 60 Hz if it switches from positive to negative 60 times per second. The period of an AC current is the length of time it takes for one cycle to complete, during which the voltage changes from 0 (zero) to positive to negative and back to 0 (zero). The frequency is the reciprocal of the period. In contrast to low frequency, which has fewer waves per second as well as a longer period, high frequency refers to the number of waves produced per second.
This can be calculated using the equation f = v/λ,
which states that the frequency of sound (f) is equal to the speed of sound (v) divided by the wavelength (λ).
The wavelength of sound for this scenario is equal to the size of the object being viewed (1.00 mm), and the speed of sound in the tissue is 1550 m/s. Therefore, plugging these values into the equation, we get f = 1550/0.001 = 6,200,000 Hz, or 6.2 MHz.
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if his arms are capable of exerting a force of 14001400 n on the rope, what is the maximum speed he can tolerate at the lowest point of his swing?
Given Data
Mass of tarzan: m=80kg
Length of vine:L=4.8m
Maximum force exerted by tarzan on the vine: F=1400N
The expression of the net force along the direction of vein is
F-mg-mv²/L=0
mv²/L=F-mg
v²=L(F-mg)/m
v=√L(F-mg)/m
Substitute the given values in the above expression.
v=√4.8 kg (1400N-80kg×9.8m/80kg
v≈6.08m/s
Thus, the maximum tolerable speed at the lowest point is 6.08m/s
What is centrifugal acceleration?
Where RV is the vertical curve's radius in meters and v is the speed in meters per second, we can calculate the centrifugal acceleration.
I understand that the question you are looking for
If his arms are capable of exerting a force of 1400Non the rope, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 80 kg and the vine is 4.8m long.
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What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?
Answer:
Explanation:
The centripetal acceleration:
aₙ = F /m = 125 /19 ≈ 6.6 m/s²
Abigail's toaster produces 50 units of heat and 5 units of light for every 100 units of electricity it uses. What is the efficiency of her toaster?.
The efficiency of her toaster is 45 %
Explain in detail
The efficiency of a system in electronics and electrical engineering is defined as the ratio of useful power output to the total electrical power consumed. For example, if a system uses 50 units of energy to produce a desired task, but also produces 5 units of energy that is wasted, then the efficiency of the system would be calculated as 45 percent. This is because the wasted energy is subtracted from the total energy used for the desired task, resulting in a ratio of 45 percent.Therefore, we can conclude that correct answer is 45%
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Exercise 1:
A small puck of mass m=150g is at rest on a horizontal surface. Ignore the frictional forces.
a) Calculate the magnitude of the normal force.
b) At t=0, we apply on the puck a horizontal and constant force F-0. 30 N.
b. 1) Calculate the acceleration of the puck.
b. 2) Calculate the distance covered by the puck then its speed at t₁-0. 50 s.
| Take
Take g-9. 80m/s²
0N is the magnitude of the normal force. 0.002 m/s is the acceleration of the puck when we apply on the puck a horizontal and constant force F-0. 30 N (Newton).
What is the S.I unit of Force?the S.I unit of force is Newton (N) which is defined as 1N=1Kgm/[tex]s^{2}[/tex].
Data given:
Mass of puck=150g
puck at rest means a (acceleration =0)
Now to find the magnitude of the normal force.
F=ma
F=150*0
F=0N
Hence, 0N is the magnitude of the normal force.
Now, When we apply on the puck a horizontal and constant force F-0. 30 N.
then to find the acceleration of the puck.
a=F/m
a=0.30N/150
a=0.002 m/s
Hence, 0.002 m/s is the acceleration of the puck when we apply on the puck a horizontal and constant force F-0. 30 N.
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explain the relationship between diffraction angle and wavelength using the two dimensional diffraction relationship n
Diffraction is described as the bending of waves around the corners of an obstruction or through an opening into the region of the barrier.
The angle of diffraction is directly proportional to the size of the wavelength.
How to. Define relationship between angle of diffraction and wavelength using 2-D diffraction?
Angular displacement ∅ = wt = 2 × 10 = 20 rad
Here w = constant
Thus, angular acceleration will be zero.
Here,
∅=wt=4×20= =80 rad
w= constant
∅=wt=3×8=24 rad
w= constant.
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why can't the lowest-mass main-sequence stars become giants? giants are huge, so they are massive stars. actually, low-mass stars do become giants. they are not massive enough to fuse helium. they are not hot enough.
Low-mass stars can become giants when they reach the end of their main sequence lifetimes.
What is Low-mass stars?
Low mass stars use the proton-proton chain to fuse hydrogen to helium inside of their cores over the course of billions of years. They typically have a convection zone, and depending on how active it is, we can tell whether the star's activity resembles the sunspot cycle on our Sun. Some tiny stars have convection zones that are incredibly deep. Some of these stars as well rotate quickly, twisting the magnetic fields around them. A flare of radiation, including X rays, may result from the alignment of these field lines. A low mass star uses up its core hydrogen over the course of its lifetime and transforms it into helium. The star gradually grows brighter as the core gradually contracts and heats up. The star's core eventually runs out of hydrogen due to nuclear fusion.
The star will expand significantly and become increasingly luminous as it evolves off the main sequence. This is known as the Red Giant branch, and it occurs as the star runs out of hydrogen fuel and starts to fuse helium in its core. This causes the star to swell in size and increase in luminosity, eventually becoming a Red Giant.
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To practice Problem-Solving Strategy 24.1 Magnetic field problems.
The element niobium, which is a metal, is a superconductor at temperatures below 9 K . This means that at such low temperatures a niobium wire has no electrical resistance. The superconductivity of the wire, however, is destroyed if the magnetic field at the surface of the wire exceeds 0.10 T . What is the maximum current in a straightsuperconducting niobium wire of radius 1.5 mm ? You may assume that all the current flows in the center of the wire.
Prepare
Create a visual representation of the problem. First choose the best orientation for the wire, then draw the magnetic field created by the current. You can then determine your known variables and identify those that you must find.
Recall that you are to treat the current as if it all runs through the center of the wire, and you are interested in the value of the magnetic field at the surface of the wire. Sort the following variables as known or unknown: the magnitude of the magnetic field B, the current I, and the distance r between the current and the point at which the magnetic field has a value of B.
u0= 4pi*10^-7
r=1.5mm= 1.5*10^-3m
substitute these values
The answer is 750 A
Long straight wire :B =µ01/2πr = Icrit==(2π)*(r=D/2)(Bcrit))/µ0
what is the speed of visible light waves when traveling through a vacuum? about 3 cross 10^8 m/s about 350 m/s about 1 cross 10^8 m/s light waves cannot travel through a vacuum. about 2 cross 10^8 m/s
The speed of visible light waves when travelling through a vacuum is about 3 X 10⁸ m/s.
The speed of electromagnetic waves, which includes visible light, radio light and x-rays is 3 X 10⁸ m/s. This is same as that of the speed of visible light in the presence of air.
The speed of light is depicted using the letter 'c', and it a universal constant value. It is a physical constant and important in many areas of physics.
The speed of light in water is 2.25 X 10⁸ m/s and that in glass is 2 X 10⁸ m/s. The speed varies with respect to the medium.
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for a counter flow double pipe heat exchanger insulated from its surroundings, the mean outlet temperature of the initially cold fluid can exceed the outlet temperature of the initially hot fluid.
Yes, In case of the counter-flow warmth exchangers the hot and bloodless fluids enter the warmth exchanger from the alternative ends and the outlet temperature of the bloodless fluid may exceed the hole temperature of the new fluid.
Observe that in a counter-flow warmth exchanger the outlet temperature of the cold fluid can exceed the opening temperature of the hot fluid but this can not take place in a parallel glide device. right here, ΔTk refers to temperature difference among the recent and cold fluids at factor okay (okay = 1 or 2).
This distributes the warmth extra calmly across the warmth exchanger and permits for maximum efficiency. In principle, the bloodless fluid can exit the heat exchanger at a better temperature than the temperature of the recent fluid outlet, despite the fact that in reality that is very tough to achieve.
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if the power delivered were 59.32 kw, evaluate the outer surface temperature, in k, and the rate of entropy production, in kw/k, for the gearbox as the system, keeping input power, h, and a from example 2.4 the same.
In the case of the gearbox as the system, the outer surface temperature is 297 K, and the rate of entropy formation is 2.3*10⁻³ kW. A surface's temperature is its ambient temperature.
More specifically, it can be talking about: Surface temperature, the temperature of the air at the earth's Surface temperature. A state of disorder, randomness, or uncertainty are frequently associated with the scientific notion of entropy, which is also a quantifiable physical attribute. Since work is produced by ordered molecular motion, entropy also serves as a proxy for a system's molecular disorder or unpredictability.
Given,
Power = 59.32
Q = ha(Ta-Tb) (Ta-Tb)
Q = (0.171)((1.0)(347k) (347k)
Q = 2.3*10⁻³ kW
Therefore the rate entropy of the gearbox is 2.3*10⁻³ kW.
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Dancers experience large forces associated with the jumps they make. For example, when a dancer lands after a vertical jump, the force exerted on the head by the neck must exceed the head?s weight by enough to cause the head to slow down and come to rest. The head is about 9. 4% of a typical person?s mass. Video analysis of a 64 kg dancer landing after a vertical jump shows that her head slows down from 4. 2 m/s to rest in a time of 0. 21 s.
Compared with the force her neck exerts on her head during landing, the force that head exerts on her neck is 1845.76 N. Deceleration is same during first half and second half and hence force will also be same.
What is force?In physics, an influence that change the motion of an object is called force.
The head decelerates from 4 m /s to zero in .21 sec ;
Deceleration = (4 - 0) / 0.21
= 19.04 m/s²
If F is the average force, then
F - mg = ma
So Force, F = m ( g + a )
= 64 ( 9.8 + 19.04 )
F = 1845.76 N.
This force will be uniformly acting on head in the upward direction . Therefore deceleration is same during first half and second half and hence force F will also be same.
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NASA's Skylab, the largest spacecraft ever to fall back to the Earth, reentered the Earth's atmosphere on July 11,1979, and broke into a myriad of pieces. One of the largest fragments was a 1770-kg, lead-lined film vault, which landed with an estimated speed of 120 m/s.
If its speed at an altitude of 146 km was 7950 m/s, how much nonconservative work was done on the film vault during reentry?
When the movie vault landed, it had a kinetic energy of 12744000J. The energy an object has as a result of motion is known as kinetic energy in physics.
It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. Where m is the mass and v is the velocity, the definition of kinetic energy is:
Equation 1 can be used to calculate the kinetic energy of the movie vault when it landed.
As a result, 12744000J of kinetic energy was present when the movie vault landed.
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A 15-kilogram cart is at rest on a horizontal surface. A 5-kilogram box is placed in the cart. Compared to the mass and inertia of the cart, the cart-box system has.
Compared to the mass and inertia of the cart, the cart-box system has more mass and more inertia.
Inertia refers to the position in which a body repels a change in its position of motion or rest. Moreover, it also includes a change in the direction of an object.A 15-kilogram cart at rest and a 5-kilogram box would make up a 20-kilogram cart and box that is at rest on a horizontal surface.The mass changed into something more, of course, as a result of combining the two object into one and by combining the two objects' mass, the inertia that it previously possessed as a cart by itself was increased when the inertia of the box was also combined to the cart.To know more about Inertia visit:
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Answer:
More mass and more inertia
Explanation:
No explanation
A satellite that goes around the earth once every 24 hours is called a geosynchronous satellite. If a geosynchronous satellite is in an equatorial orbit, its position appears stationary with respect to a ground station, and it is known as a geostationary satellite.
Find the radius R of the orbit of a geosynchronous satellite that circles the earth. (Note that R is measured from the center of the earth, not the surface.) You may use the following constants:
The universal gravitational constant G is 6.67×10−11Nm2/kg2.
The mass of the earth is 5.98×1024kg.
The mass of the satellite is 2.10×102kg.
The radius of the earth is 6.38×106m.
Give the orbital radius in meters to three significant digits.
The radius of the orbit of a geosynchronous satellite that circles the Earth is calculated to be 4.23 x 10^7 m
As the given time period is 24 hours, we first convert it into seconds as follows;
24 x 3600 = 86,400 seconds
The formula for the time period of the satellite can be given as;
T = 2π √r³ ÷ GM
Here r represents the radius, M represents the mass of the Earth and G illustrates the universal gravitational constant.
86,400 = 2 × 3.14 √r³ ÷ (6.67×10^−11) (5.98×10^24)
1.89 × 10^8 = r³ ÷ (6.67×10^−11) (5.98×10^24)
r = 4.23 x 10^7 m
Therefore the radius of the orbit of a geosynchronous satellite is 4.23 x 10^7 m
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between 1998 and 2018, the proportion of adults who met both the weekly goal of 150 minutes of moderate exercise and the weekly goal of 75 minutes of intense exercise has by percent.
The percentage of adults who reached both the weekly objective of 150 minutes of moderate exercise and the weekly goal of 75 minutes of intensive exercise has increased from 1998 to 2018 by 22.9%.
The activities listed below all meet the criterion of moderate exercise: In 30 minutes, two miles of walking. five kilometers on a bike in thirty minutes. 20 minutes spent swimming laps. 15 minutes to complete 1.5 miles of running. a 30-minute session of water aerobics. 45 minutes were spent playing volleyball. twenty minutes of basketball. Is a moderate exercise.
Basically, anything that requires you to exert intensive exercise, uses numerous muscle groups, and is performed at or close to your maximum heart rate qualifies. So go ahead and create your own unique form of hard workout. Is known as intensive exercise.
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