What mass of H2 forms when
35.25 g Al reacts with excess
hydrochloric acid?

The net force on the man is 10 newtons forward. The parachute is pushing the man forward with 10 newtons of force. Therefore, option A is correct.

The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.

In accordance with Newton's second rule of motion, it causes the particle to accelerate at a rate equal to the sum of all those actual forces.

The vector sum of all forces exerted on an object is known as the net force. The net force acting on an object is zero when it is in equilibrium, whether it is at rest or moving at a constant speed. Only when all of a vector's components are zero can a vector have a magnitude of zero.

Thus, option A is correct.

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Answer: A

Explanation:

Answer:

What is the pH of an aqueous solution with a hydrogen ion concentration of [H+]=7.7×10−4 M?

The pH of an aqueous solution with a hydrogen ion concentration of [H+]=7.7×10−4 M is 3.11.

Answer:

an inference is an educated answer based on a piece of information you have been given

Explanation:

e.g. they had pigtails in their long blonde hair.

from this we can infer that I am speaking about a girl

sorry it's not clear anyway hope you can see the H and C .. the hydrogen atoms are 8

Answer:

Radon, Bismuth, Lead, and Thallium

Explanation:

Its from smallest to largest. Hope it helps!

The temperature change of the resulting solution, given that the soluton has a specific heat of 1 cal/g·°C is 18.7 °C

We know that heat released is related to change in temperature according to the following formula:

Q = MCΔT

Where

Using the above formula, the temperature change of the solution can be obtained as follow:

Q = MCΔT

-8.8×10² = 47 × 1 × ΔT

-8.8×10² = 47 × ΔT

Divide both side by 47

ΔT = -8.8×10² / 47

ΔT = -18.7 °C

Thus, the temperature change is 18.7 °C

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Answer:

Molar mass of dye = 225.8 g/mol

Mass of dye = 17.26 mg

Volume of stock solution = 500.0 mL

Concentration of dye (M) = (17.26 mg/225.8 g/mol) / (500.0 mL/1000 L) = 0.000769 M

Concentration of dye (mM) = 0.769 mM

According to the molar concentration, the concentration of the dye in the stock solution is 15.04×10⁻³M and 15.04×10⁻⁶mM.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

Substitution of values in formula gives, M= 0.017/225.8×1/0.5=15.04×10⁻³ M or 15.04×10⁻⁶ mM.

Thus, the concentration of the dye in the stock solution is 15.04×10⁻³M and 15.04×10⁻⁶mM.

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[tex]{ \blue{ \sf{Albumin}}}[/tex] is a soluble and globular monomeric protein encoded by chromosome 4 that comprises about half of the protein found in blood serum. It functions as a carrier protein for steroids, fatty acids, and thyroid hormones as well as stabilizing extracellular fluid volume.

Answer:

3 grams C₅H₁₀O₅

Explanation:

To find the mass of ribose needed to prepare the sample, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the number of moles (M = moles / L)

(3) convert moles to grams (using the molar mass of ribose)

The molecular formula of ribose is C₅H₁₀O₅. It is important to arrange all of the ratios/conversions in a way that allows for the cancellation of units.

(Step 1)

 200 mL C₅H₁₀O₅                   1 L
----------------------------  x  ----------------------  =  0.2 L C₅H₁₀O₅
                                           1,000 mL

(Step 2)

Molarity (M) = moles / volume (L)                 <----- Molarity ratio

0.1 M = moles / 0.2 L                                     <----- Insert values

0.02 = moles                                                  <----- Multiply both sides by 0.2 L

(Step 3)

Atomic Mass (C): 12.011 g/mol

Atomic Mass (H): 1.008 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (C₅H₁₀O₅): 5(12.011 g/mol) + 10(1.008 g/mol) + 5(15.999 g/mol) = 150.13 g/mol

 0.02 moles C₅H₁₀O₅              150.13 g
----------------------------------  x  -------------------  =  3 grams C₅H₁₀O₅
                                                  1 mole

Answer:

KE=1\2mv2

KE=0.5 *0.15*(36)2

97.2j

No. of moles of Ni = 1.7 mole

No of atoms of Ni = 1.023× 10²⁴ atom

A mole is equivalent to 6.022 × 10²³ units of that material (such as atoms, molecules, or ions). Avogadro's number, or Avogadro's constant, is 6.022 × 10²³

For instance, a mole of carbon-12 atoms weighs 12 grammes. Additionally, a mole of hydrogen atoms weighs 1 gram, but a mole of hydrogen molecules weighs 2 gram.

Given that,

mass of nickel (m) =  100 gm

Now, no. of moles of Ni = mass / molar mass

                                        = 100 gm/ (59 gm/mole)

[ As we know, molar mass of Nickel (Ni) = 59 gm/mole ]

                                        = 1.7 mole

Now, no of atoms = no. of mole × Avogadro's No. ([tex]N_{A}[/tex])

                             = 1.7 mole × 6.022 × 10²³ atom/mole

                             = 10.23 × 10²³ atom

                             = 1.023× 10²⁴ atom

Thus, no. of moles of Ni = 1.7 mole

no. of atoms of Ni = 1.023× 10²⁴ atom

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To solve this type of question we must know the concept of rate law for first order kinetics and first law related to this. Therefore, the half-life of the given compound is 12.8hr.

There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law.

The expression for half life for first order reaction is

[tex]t_{1/2} = \frac{0.693}{K}[/tex]

k= rate constant= 5.40×10⁻²/hr

Substituting all the given values in the above equation, we get

[tex]t_{1/2} = \frac{0.693}{ 5.40 *10^{-2}}[/tex]

On solving this, we get

half life =0.128×10²=12.8hr

Therefore, the half-life of the given compound is 12.8hr.

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The mass of [tex]CO_2[/tex] that will be produced when 25.0 g of [tex]C_8H_{18[/tex] reacts completely in the equation would be 154.035 g.

From the balanced equation of the reaction which goes thus:

[tex]C_8H_{18} + 25 O_2 -- > 16 CO_2 + 18 H_2O[/tex]

The mole ratio of [tex]C_8H_{18[/tex] that reacts and the [tex]CO_2[/tex] that is produced is 1:16.

Recall that: mole = mass/molar mass

The molar mass of [tex]C_8H_{18[/tex] is 114.23 g/mol

Mole of 25.0 g  [tex]C_8H_{18[/tex] = 25/114.23

                                     = 0.22 mol

Since the mole ratio is 1:16, the moles of [tex]CO_2[/tex] that will be produced by 0.22 mol of [tex]C_8H_{18[/tex] would be:

0.22 x 16 = 3.50 mol

The molar mass of [tex]CO_2[/tex] is 44.01 g/mol, thus, the mass of 3.50 mol of the gas can be determined as:

Mass = mole x molar mass

         = 3.5 x 44.01

         = 154.035 g

In other words, the mass of [tex]CO_2[/tex] that will be produced when 25.0 g of [tex]C_8H_{18[/tex] reacts completely in the equation would be 154.035 g.

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The partial pressure of oxygen is the product of its mole fraction and the total pressure. Partial pressure of O₂ here, is 0.82 atm.

Partial pressure of an individual gas in a mixture of gases is its contribution to the total pressure of the gas mixture. According to Dalton's law of partial pressures, the total pressure of the mixture is the sum of partial pressures of the individual gases.

The partial pressure of the individual gases will be the product of the mole fraction and total pressure.

mass of oxygen = 16 g/mol

number of moles in 50 g = 50 /16 = 3.125 moles.

mass of neon = 20 g/mol

moles in 50 g =  50 / 20 = 2.5 moles.

Mole fraction of oxygen =  3.125/ (3.125 + 2.5) = 0.55.

Partial pressure = mole fraction × total pressure

                           = 0.55 × 1.50 atm = 0.82 atm.

Therefore, the partial pressure of O₂ in the mixture is 0.82 atm.

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Answer:

H/Hydrogen atoms = 12

reason:

no. of carbon=5

so it'll be C5H12

Answer:

no. of H = 10

no. of C = 4

C4H10

The final temperature of the sample of nitrogen dioxide gas that occupies 625 cm³ at 70.0 °C and 15.0 psi is 299.12K.

The temperature of a gas can be calculated by using the combined gas law formula as follows:

P₁V₁/T₁ = P₂V₂/T₂

Where;

According to this question, a sample of nitrogen dioxide gas occupies 625cm³ at 70.0 °C and 15.0 psi. The final temperature can be calculated as follows:

15 × 625/343 = 15 × 545/T

27.33T = 8175

T = 299.12K

Therefore, 299.12K is the final temperature of the sample of nitrogen dioxide gas.

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Average kinetic energy is the average sum of all kinetic energy of all the molecules of gases. Therefore, the new kinetic energy is 48 times the original kinetic energy.

It is a energy which is possess  by a moving object. It is very difficult to find the correct value of kinetic energy so we find average kinetic energy. Which is very easy to calculate as compared to calculating kinetic energy

Average kinetic energy is directly proportional to temperature. It is not dependent on the type of gases or mass of gases

Mathematically,

K.E=2/3KT

Where,

K= Boltzmann constant

T is the temperature

Gases at higher temperature will have higher average kinetic energy. For every 10 degree rise in temperature, kinetic energy of reaction gets double. There are 24 times 10 between the given temperature  -49C to 287C. So, the new kinetic energy is 48 times the original kinetic energy.

Therefore, the new kinetic energy is 48 times the original kinetic energy.

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The balanced chemical equation is 3 Sr(OH)₂ + Al₂(SO₄)₃[tex]\rightarrow[/tex] 3 SrSO₄ + 2 Al(OH)₃.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Variations in the solar resource are probably the first and main consideration. You can use local weather stations where available, otherwise satellite data (eg from NASA's website) or commercial databases such as Meteonorm. Also there is quite a comprehensive set of data files in the SAM software

Other important considerations are

local environment: plants and animals that could be affected by the system; community support and buy-in.wind, hail, rain, snow profile for the location in question. if there are high/tropical winds then it will increase the plant cost.flight paths and roads near the plant which could be affected by glint and glareproximity to a local town where staff will be able to live both during construction and later during operationproximity to a electricity transmission line with available capacityavailability of water for mirror cleaning and steam blowdown.cost (and availability) of electricity in the area. If remote, electricity/energy may be very expensive, which will enable a high price for electricity sold from the plant.quality of road to the plant, required to bring equipment and materials to sitepolitical stability of the region -- potential impact on perceived bankability of the project.

Many of these items will have a large influence on the cost of the plant and/or the revenue it will generate during its life. Others relate to environmental and risk factors and are also critically important to consider.

Hope this helps!!

Answer:

ethyl ethanoate

Explanation:

it helps you

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the volume of gas will be collected for the complete reaction of 24.23 g of NiO is 4.19L.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of gas sample

V= volume of gas sample

n =number of moles of gas sample

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

Substituting all the given values, we get

Molar mass of NiO=74.6928g/mol

mass of NiO= 24.23 g

Number of moles of NiO =0.324

From reaction the molar ratio between NiO and O[tex]_2[/tex] is 2:1

Number of moles of O[tex]_2[/tex] =0.16moles

applying ideal gas equation

0.98atm×V =0.16× 0.0821×313

V =4.19L

Therefore, the volume of gas will be collected for the complete reaction of 24.23 g of NiO is 4.19L.

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The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of the reactant and product is conserved. Therefore the mass of HF is 28grams.

According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier. Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved.

H[tex]_2[/tex] + F[tex]_2[/tex] → 2HF

Mass of  H[tex]_2[/tex]=8Grams

mass of F[tex]_2[/tex]= 20grams

According to law of conservation f mass

mass of H[tex]_2[/tex] + mass of F[tex]_2[/tex]   = mass of HF

Substituting all the given values, we get

8grams + 20grams =mass of HF

mass of HF=28grams

Therefore the mass of HF is 28grams.

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Answer:The pressure exerted by the gas is 100kPa

Explanation:Let's apply the Charles Gay Lussac law, to solve the question.

At constant volume, the pressure varies proportionally with the temperature.

P initial / T° initial = P final / T° final

50kPa / 20°C = P final / 40°C

Temperature has increased the double, so the pressure will be increased, the double too.

100 kPa

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A rhombus is a quadrilateral with all the sides of equal measurements. Therefore, the value of x, y, and z are 45, 7, and 7, respectively.

A rhombus is a quadrilateral with all the four sides having equal measurements. The opposite sides are parallel to each other which gives it the shape of a kite.

The value of x, y, and z can be calculated as all the sides have equal value.

x - 5 = 6y -2 = 5z + 5 = 40

Therefore, on solving each equation separately we get.

x - 5 = 40

x = 40 + 5

x = 45

6y - 2 = 40

6y = 40 + 2

6y = 42

y = 42/ 6

y = 7

5z + 5 = 40

5z = 40 - 5

5z = 35

z = 35/ 5

z = 7

Therefore, the values of x, y, and z are 45, 7, and 7, respectively.

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The standard enthalpy change for the reaction 2A + B ⇌ 2C + 2D   is 195 kJ/mol.

The enthalpy of a reaction is a measure of the heat changes that occur when reactants form a product in a given reaction.

The enthalpy change of a reaction can be calculated using the formula given below:

Enthalpy of reaction = sum of enthalpies of the products  - sum of enthalpies of the reactants

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction = (2 * C + 2 * D) - (2 * A + B)

Enthalpy of reaction = {[2 * 177 + 2 * (-515)] - [2 * (-231) + (-409)]}

Enthalpy of reaction = 195 kJ/mol

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The mass of the original iridium‑192 remains after 5 days is 1.16 g.

Mass is defined as the body's resistance to acceleration when a net force is applied; a measure of inertia. Gravity and inertia, which are the two main forces influencing how objects move in space, make mass crucial.

Radioactive isotope iridium-192 (Ir-192) is iridium. It is a gamma emitter with a 74-day half-life. 1/4 of the sample will experience radioactive decay in 3.36 days. The substance's decay constant can be found. Subtract ln 2 from the substance's decay constant.

λ = ln2 / T 1/2

λ = ln2 / 5 1/2

λ = 1.16 g

Thus, the mass of the original iridium‑192 remains after 5 days is 1.16 g.

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On the decomposition of 2.60 moles of hydrogen peroxide, 254.8 KJ energy will be released.

A decomposition reaction can be defined as a reaction in which a chemical compound breaks down into two or more simple compounds. The general form  to express a decomposition reaction is:

AB    →   A   +    B

Most decomposition reactions accept energy in the form of heat, radiation, or electricity. The decomposition reaction of hydrogen peroxide is shown below:

2H₂O₂(l)    →   2H₂O (l)  +  O₂(g)                        ΔH = - 196 KJ/mol

2 moles of  hydrogen peroxide decomposes energy released = 196 KJ

2.60 of H₂O₂  decomposes energy released = 196 ×2.60/2 = 254.8 KJ

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As per the standard data, the heat evolved during one mole of calcium carbonate decomposes is 177.8 KJ. Thus 15 g or 0.15 moles of calcium carbonate when decomposed will produce 26.67 KJ of heat.

Reaction enthalpy of a substance is the heat evolved or absorbed during a reaction. Reaction enthalpy is negative for an exothermic reaction and positive for an endothermic reaction.

Molar mass of calcium carbonate = 100 g.

no.of moles in 15 g = 15 /100 = 0.15 moles.

One mole or 100 g of calcium carbonate decompose to evolve 177.8 KJ according to the scientific record.

Thus, heat evolved by the decomposition of 0.15 moles is 0.15 × 177.8 KJ = 26.67 KJ.

Hence, the heat evolved during the decomposition of 15 g of calcium carbonate is 26.67 KJ.

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