The main office staff collected 55 cans, the counseling staff collected 89 cans, and the custodial staff collected 67 cans.

Answer:

well thats high school stuff so pay attention in ur classes.

Step-by-step explanation:

Answer:

x>-1

Step-by-step explanation:

[tex] \frac{17}{17}x > - \frac{17}{17} \\x > - 1 [/tex]

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8             -8

4x >_ 4

/4       /4

x >_ 1

Answer:

[tex]ADC = 70[/tex]

Step-by-step explanation:

Given

[tex]BCA = 50[/tex]

[tex]DCA = 60[/tex]

See attachment for parallelogram and complete question

Required

Find ADC

From the attachment:

[tex]BCD = BCA + DCA[/tex]

[tex]BCD = 50+60[/tex]

[tex]BCD = 110[/tex]

Adjacent angles add up to 180.

So:

[tex]ADC + BCD = 180[/tex]

[tex]ADC = 180-BCD[/tex]

[tex]ADC = 180-110[/tex]

[tex]ADC = 70[/tex]

Answer:

x=-2

Step-by-step explanation:

[tex]\sqrt{x+3}+4=5[/tex]

subtract 4 from each side

[tex]\sqrt{x+3} +4-4=5-4[/tex]

square both sides

[tex]\sqrt{x+3}^2=1^2[/tex]

so we have

[tex]x+3=1[/tex]

subtract 3 from each side

[tex]x+3-3=1-3[/tex]

so our answer is [tex]x=-2[/tex]

Answer:

x = -8

Step-by-step explanation:

-3x -6 = 18

-3x = 24

x = -8

Hi there!

[tex]\large\boxed{-12,600 N}[/tex]

Recall that the equation to calculate force is:

F = m · a where m = mass, a = acceleration, and F = net force.

Since we are given the velocity, and time needed to stop, we can calculate the acceleration using the following kinematic equation:

vf = vi + at

The initial velocity is 36 m/s and the final velocity is 0 m/s, therefore:

0 = 36 + at

Move 36 to the other side and plug in the given time:

-36 = 4a

Divide both sides by -4 to find a:

-36/4 = a

a = -9 m/s².

Since the acceleration is -9 m/s² and the mass is 1400 kg, use the above force equation to solve:

F = -9 × 1400 = -12600 N. (negative refers to the force working in the opposite direction of the car's travel. If simply needing the magnitude of the force, it would be 12600 N)

Answer:

When you multiply the number by its reciprocal the numerator of the one becomes the denominator of the other and is equals to 1 .

Answer:

there is no picture?

Step-by-step explanation:

26-4s=9s

⇔26=9s+4s

⇔26=13s

⇔s=2

Answer:

s = 2

Step-by-step explanation:

26 - 4s = 9s

add 4s to 4s and 9s

that equals 13

26/13 = 13s/13

s = 2

Answer:

what is this a maths problem

Answer:

10.333

Step-by-step explanation:

If you use percentage, we will get 10.3325.

But it's money, so we will have to round it up.

We then get 10.333.

Answer:

3

Step-by-step explanation:

If you count the units its three units away from each other.

9514 1404 393

Answer:

  -5/y

Step-by-step explanation:

The wording "the quotient of A and B" is used to signify A/B.

Here, we want the quotient of -5 and y:

  -5/y

Answer:

Step-by-step explanation:

x = width

6x - 8 = length

2x + 6x - 8 = 40

8x = 48

width = 6 feet

length = 28 feet

Answer:

The vertex is at [tex](0, -9)[/tex]

The axis of symmetry [tex]x = 0[/tex]

Step-by-step explanation:

Note: You can answer all the questions looking at the graph

We have the function [tex]f: \mathbb{R} \rightarrow\mathbb{R}[/tex](I am assuming this) such that [tex]f(x) = y = (x-3)(x+3)[/tex]

We note that

[tex](x-3)(x+3) = x^2-9[/tex] once we have a difference of squares

Therefore, we have a quadratic function.

So

[tex]y = x^2-9[/tex]

The vertex [tex](h, k)[/tex] is

[tex]h = \dfrac{-b}{2a} = \dfrac{-0}{2 \cdot 1} = 0[/tex]

[tex]k= h^2 - 9 = 0^2 - 9 =-9[/tex]

Therefore, the vertex is at [tex](0, -9)[/tex]

As we know the vertex, we conclude that the axis of symmetry [tex]x = 0[/tex]

The x-intercepts occur at [tex]y = 0[/tex]

[tex]y = (x-3)(x+3) \implies x = -3, x=3[/tex]

So, the left x-intercept is [tex](-3, 0)[/tex] and the right x-intercept is [tex](3, 0)[/tex]

As I stated in the beginning, the domain is the set of all real numbers. Precisely,

[tex]Dom(f) = \mathbb{R} = (-\infty, \infty)[/tex]  

Once, we know the vertex, we also conclude that the Range is

[tex]Ran(f)= [-9,\infty)[/tex]

Greater than or equal to -9

Answer:

Perimeter: 18u^2

Area: 18u^2

Step-by-step explanation:

perimeter is just adding all the sides together so 6+3+6+3

area is multiplying length by width so 6•3

both give us 18

hope this helps chu <3

Answer: 5/12

Step-by-step explanation:

Answer:

5/12

Step-by-step explanation:

We are going to change both number so they have the same denominators.

1/4x3/3= 3/12

2/3x4/4=8/12

Once we changed the number we are going to subtract the numbers.

8/12-3/12=5/12

We can't simplify 5/12 so the answer is 5/12.  

Answer:

4(9 – c)

36 – 4c

Step-by-step explanation:

An example of two equivalent expressions includes the general expression and then the one that is factored.

Answer:

the answer is B hope it helps

Answer:

answer is B

Step-by-step explanation:

The sample of 3 seventh graders who own a bracelet out of 30 seventh graders does not closely estimate the thirty percent of all seventh graders owning bracelets.

Percentages are fractions where the denominator is 100.

We have,

Number of seven grade students = 30

Number of students who own a bracelet = 3

The percentage of seven grade student who owns a bracelet:

= (3 / 30) x 100

= (1/10) x 100

= 10 %

This means that 10% of seven grade student owns a bracelet.

Thus, the sample does not closely estimate the percentage of seventh graders who owns bracelets.

Learn more about percentages here:

https://brainly.com/question/17151247

#SPJ2

Answer:

yes

Step-by-step explanation:

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]

If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.

⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]

☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]

Hope I helped ! ♡

⋆ Have a wonderful day / night ! ♪

Let me know if you have any questions regarding my answer! ツ

[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

Step-by-step explanation:

1. 2

2. 3

3. 6

4. 2

5. 4

Answer:

FD = 25.94

Step-by-step explanation:

13x - 16 = 4x + 11 (Tangents drawn from an external point are equal)

13x - 4x = 11 + 16

9x = 27

x = 3

substituting x in 4x + 11,

4(3) + 11

12 + 11

23

ΔFED is a right triangle,

FD² = FE² + DE²

FD² = 12² + 23²

FD² = 144 + 529

FD² = 673

FD = 25.94

Answer:

FD= +-25.94

Step-by-step explanation:

EF=CF=r(radius)=12

we know,

FD^2=EF^2+ED^2 ......(1)

and

FD^2=CF^2+CD^2 ......(2)

We Know,

area of triangle, a= 1/2xbasexHeight

a=1/2xEFxED .......(3)

and

a=1/2xCFxCD .....(4)

from equation 3 and 4

1/2xEFxED=1/2xCFxCD

=> 1/2x12xED=1/2x12xCD

=>ED=CD

=>13x-16=4x+11

13x-4x=16+11

9x=27

x=3

so

FD^2=EF^2+(ED)^2

FD^2=(12)^2+(4x3+11)^2

=>FD^2=144+529

=>FD^2=673

FD=+-25.94

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

Answer:

[tex]Rate = 0.935042^\circ /cm[/tex]

Step-by-step explanation:

Given

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

[tex]T(x,y) =x\sin2y[/tex]

[tex]r = 1m[/tex]

[tex]v = 2m/s[/tex]

Express the given point P as a unit tangent vector:

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

[tex]u = \frac{\sqrt 3}{2}i - \frac{1}{2}j[/tex]

Next, find the gradient of P and T using: [tex]\triangle T = \nabla T * u[/tex]

Where

[tex]\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j[/tex]

So: the gradient becomes:

[tex]\triangle T = \nabla T * u[/tex]

[tex]\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j][/tex]

By vector multiplication, we have:

[tex]\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}[/tex]

[tex]\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)[/tex]

[tex]\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5[/tex]

[tex]\triangle T = 0.935042[/tex]

Hence, the rate is:

[tex]Rate = \triangle T = 0.935042^\circ /cm[/tex]

Answer how but just put it on brainly

Step-by-step explanation:

it tells you the answer