The code below is supposed to display the name and score for the student with the highest score one time before the program ends. It is displaying Jim as the student with the highest score. It is displaying the highest score of 95. Unfortunately, Jim does not have a score of 95. Correct the following code:

Declare String students[SIZES] = {"Jen", "Jon", "Jan", "Joe", "Jim"}
Declare Integer scores[SIZES] = 70, 85, 72, 95, 90
Declare Integer index Declare Integer highest = scores[0]
Declare Integer highest Name = " " For index = 0
To SIZES //Assume that this translates to For (index = 0; index <= SIZES, index ++)
If scores[index] > highest then highest = scores[index]
End Of highestName = students[index]
End For Display "

The name of the student with the highest score is ", highest Name Display "The highest score is ", highest

Answer:

when a file is double clicked it opens so you can see the file.

Explanation:

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is an online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers,  and offer real-time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.

Why other options are not correct

Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement.   however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.

Answer: the answer is A.

Explanation: He has to listen to what the people tell him and think about the information he has and make a choice on what to reply with.

Answer:

The corrected program is:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int qtr, dime, nickel, penny;

double dollars;

System.out.print("Quarters: ");

qtr =scnr.nextInt();

System.out.print("Dimes: ");

dime = scnr.nextInt();

System.out.print("Nickel: ");

nickel = scnr.nextInt();

System.out.print("Penny: ");

penny = scnr.nextInt();

dollars = qtr * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

}

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

ok so u have take the 5 and put 6

Explanation:

5-5. Ethernet network design: UTP connections from client PC and server to workgroup switches, 900m fiber optic link between switches, 800 Mbps communication.

5-6. Additional client connects to the same switch, UTP connection, maintains existing fiber optic link, 800 Mbps communication with the server.

5-5. For connecting a single client PC to a single server, both located 900 meters apart and requiring communication at 800 Mbps, the following Ethernet network design can be implemented:

- Client PC and server connect to their respective workgroup switches via UTP.

- Use fiber optic cables for the 900-meter transmission link between the switches.

- Install switches at the client PC and server locations.

- Ensure that the switches support at least 1 Gbps Ethernet speeds to accommodate the required transmission speed.

5-6. In addition to the previous design, for adding another client next to the first client:

- Connect both clients to the same switch.

- Use UTP cables to connect the second client to the switch.

- Ensure the switch supports 1 Gbps Ethernet speeds.

- Maintain the existing fiber optic transmission link between the switches.

- The second client can also communicate with the server at the required 800 Mbps transmission speed.

Learn more about Network Design at:

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Answer:

The equivalent if statements is:

ranforce = randi([0, 12]);

if (ranforce == 0)

     disp('There is no wind')

else  if(ranforce>0 && ranforce <7)

     disp('There is a breeze')

else  if(ranforce>6 && ranforce <10)

     disp('This is a gale')

else  if(ranforce>9 && ranforce <12)

     disp('It is a storm')

else  if(ranforce==12)

     disp('Hello, Hurricane!')

end

Explanation:

The solution is straight forward.

All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

Answer:

import random

decisions = int(input("How many decisions: "))

for i in range(decisions):

   number = random.randint(0, 1)

   if number == 0:

       print("heads")

   else:

       print("tails")

Explanation:

*The code is in Python.

import the random to be able to generate random numbers

Ask the user to enter the number of decisions

Create a for loop that iterates number of decisions times. For each round; generate a number between 0 and 1 using the randint() method. Check the number. If it is equal to 0, print "heads". Otherwise, print "tails"

Answer:

Follows are the code to this question:

def weeklypay(hour_rate,hour ):#defining a method weeklypay that accepts two parameters

   pay=hour_rate* hour#defining variable pay that calculate payable amount

   return pay#return pay value

hour_rate=float(input("Enter your hour rate $: "))#defining variable hour_rate that accepts rate vlue

hour=int(input("Enter total hours: "))#defining hour variable that accepts hour value

print('The total amount you will get $: ',weeklypay(hour_rate,hour))#call method and print return value

Output:

Enter your hour rate $: 300

Enter total hours: 3

The total amount you will get $:  900.0

Explanation:

In the above-given code, a method "weeklypay" is declared, which holds two value "hour_rate and hour" in its parameter, inside a method a "pay" variable is declared, that calculate the total payable amount of the given inputs and return its value.

In the next step, the above variable is used to input the value from the user-end and uses the print method to call the "weeklypay" method and print its return value.

Answer:

7. true

8.B

Hopefully those are correct!

Explanation:

public class Drive {

   int miles;

   int gas;

   String carType;

   public String getGas(){

       return Integer.toBinaryString(gas);

   }

   public Drive(String driveCarType){

       carType = driveCarType;

   }

   public static void main(String [] args){

       System.out.println("Hello World!");

   }

}

I'm pretty new to Java myself, but I think this is what you wanted. I hope this helps!

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is the Bar graph.

Because we use this chart type to visually compare values across a few categories when the charts show duration or when the category text is long.

However, we can present information similarly in the bar graph and in column charts, but if you want to create a chart with the horizontal bar then you must use the Bar graph. In an Excel sheet, you can easily draw a bar graph and can format the bar graph into a 2-d bar and 3-d bar chart.

A column chart is used to compare values across a few categories. You can present values in columns and into vertical bars.

A line graph chart is used to show trends over months, years, and decades, etc.

Pie Chart is used to show a proportion of a whole. You can use the Pie chart when the total of your numbers is 100%.

Answer:

Bar graph option A

Explanation:

I did the test

This is python code.

In python, you are supposed to put a colon at the end of while loops. This code does not have a colon after the while loop, therefore, you need to add a colon to the end of the statement.

The error to be fixed in the while loop is to add a colon at the end of the while statements.

x = 1

while (x<26)

     print(x)

     x = x + 1

This is the right code;

x = 1

while(x < 26):

   print(x)

   x = x + 1

The actual code , the while statement is missing a colon at the end of it.

The code is written in python. In python while or for loops statements always ends with a colon.

In the error code, there was no colon at the end of the while loop.

The right codes which I have written will print the value 1 to 25.

learn more on python loop here: https://brainly.com/question/19129298?referrer=searchResults

Explanation:

question a) answer:

At the moment when it sends the package, then it has a waiting time for the acknowledgement from the receiver, however, the time will be split in two when the frameset size becomes two, meaning that two packages have been sent together, causing the receiver to acknowledge only one package.

question b) answer:

The timeout is equal to two times.

In cases when the frame size is 3, the frame will be lost since the timeout turns to be 2 times. Because the sender has to wait for the acknowledgement, therefore it will send other of the parcels.

Answer:

4096 VLANs

Explanation:

A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.

An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²).  This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs

A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.

But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.

Learn more about VLANs from

https://brainly.com/question/25867685

Answer:

a task and a calendar entry

Explanation:

ITS RIGHT

Answer:

its A) a task and a calendar entry

Explanation:

correct on e2020

I believe the answer is A. because he has to listen to what the people tell him and he information he has to think about and make a choice on what to reply with.

I hope this helps and its correct please let me know if its wrong have a great day//night.

Answer:

lookup value

Explanation:

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //PrompT the User to enter a String

   System.out.println("Enter a sentence or phrase: ");

   //Receiving the string entered with the Scanner Object

   Scanner input = new Scanner (System.in);

   String string_input = input.nextLine();

   //Print out string entered by user

   System.out.println("You entered: "+string_input);

   //Call the first method (GetNumOfCharacters)

   System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

   //Call the second method (OutputWithoutWhitespace)

   System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

   }

 //Create the method GetNumOfCharacters

   public static int GetNumOfCharacters (String word) {

   //Variable to hold number of characters

   int noOfCharactersCount = 0;

   //Use a for loop to iterate the entire string

   for(int i = 0; i< word.length(); i++){

     //Increase th number of characters each time

     noOfCharactersCount++;

   }

   return noOfCharactersCount;

 }

 //Creating the OutputWithoutWhitespace() method

 //This method will remove all tabs and spaces from the original string

 public static String OutputWithoutWhitespace(String word){

   //Use the replaceAll all method of strings to replace all whitespaces

   String stringWithoutWhiteSpace = word.replaceAll(" ","");

   return stringWithoutWhiteSpace;

 }

}

database = ([[]])

while True:

   first_name = input("Enter the student's first name: ")

   if first_name == "0":

       while True:

           search = input("Enter a student ID number to find a specific student: ")

           if [] in database:

               database.pop(0)

           if search == "0":

               exit()

           k = 0

           for w in database:

               for i in database:

                   if i[2] == search:

                       print("ID number: {} yields student: {} {}".format(i[2], i[0], i[1]))

                       search = 0

   last_name = input("Enter the student's last name: ")

   id_number = input("Enter the student's ID number: ")

   database.append([first_name, last_name, id_number])

I hope this helps!

Answer:

True

Operating System

Booting

Answer:

C. O(n).

Explanation:

for better understanding, the os is a program that helps in telling how much resources can be used and when processor can be accessed.

to each programme data structures would load and unload every time that a programme is to be run.

while a programme is being managed there would be extra overheads and based on whatever type of os or programme that this is, it may or may not have fixed overhead

from our question overhead is fixed at 100ms

we have,

net time as: 300-100, 510-100, 905-100, 1750-100, 3305-100,

which is, 200, 410, 805, 1650, 3205

when we double 2¹⁰ to 2¹¹ to 2¹² etc, the programme ran is also doubling

this says that run time is same as size of instance n

O(n)

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers,  and offer real time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.

Why other options are not correct

Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement.   however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.

Answer:

online toutoring.

helpful games give mind relaxation.

Answer:

Written in Python

numVal = int(input("Input: "))

for i in range(numVal,0,-1):

    print(i)

print("Ready!")

Explanation:

This line prompts user for numVal

numVal = int(input("Input: "))

This line iterates from numVal to 1

for i in range(numVal,0,-1):

This line prints digits in descending order

    print(i)

This line prints the string "Ready!"

print("Ready!")

Answer:

Press and hold the power button for up to 10 seconds, until your Mac turns off. If that doesn't work, try using a cellular device to contact Apple Support.

Explanation:

If that also doesn't work try click the following keys altogether:

(press Command-Control-Eject on your keyboard)

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This makes the laptop (macOS) instruct to restart immediately.

Hopefully this helps! If you need any additional help, feel free and don't hesitate to comment here or private message me!. Have a nice day/night! :))))

Another Tip:

(Press the shift, control, and option keys at the same time. While you are pressing those keys, also hold the power button along with that.)

(For at least 10 seconds)

The one that is not a period of the Middle Ages is the High Middle Ages. The correct option is c.

The Middle Ages, which roughly correspond to the years 500 to 1400–1500 BCE, is the term used to describe this time of European history. The phrase was initially used by academics in the 15th century to refer to the time frame between their own era and the dissolution of the Western Roman Empire.

The period between the fall of Imperial Rome and the start of Early Modern Europe is referred to as the “Middle Ages” for this reason. The reason the Middle Ages are known as the Dark Ages is that life was hard and brief in Europe, and contrasted with the orderliness of classical antiquity.

The time period in European history from roughly 500 AD to 1500 AD. This time period's early years are commonly referred to as the Dark Ages.

Therefore, the correct option is c, High Middle Ages.

To learn more about the middle ages, refer to the link:

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In python:

number = input("Enter a 10-character phone number: ")

for i in number:

   if i.isalpha():

       if i == "A" or i == "B" or i == "C":

           i = "2"

       elif i == "D" or i == "E" or i == "F":

           i = "3"

       elif i == "G" or i == "H" or i == "I":

           i = "4"

       elif i == "J" or i == "K" or i == "L":

           i = "5"

       elif i == "M" or i == "N" or i == "O":

           i = "6"

       elif i == "P" or i == "Q" or i == "R" or i == "S":

           i = "7"

       elif i == "V" or i == "T" or i == "U":

           i = "8"

       elif i == "W" or i == "X" or i == "Y" or i == "Z":

           i = "9"

   print(i, end="")

I hope this helps!

Code:

def phonenumber():

alpha = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']

n =[2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9]

phone = input('Enter phone number in format of XXX-XXX-XXXX : ').upper()

index = 0

for index in range(len(phone)):

if phone[index].isalpha():

print (n[alpha.index(phone[index])], end = ' ')

else:

print (phone[index], end = ' ')

phonenumber()

Compilation output is attached below:

Learn More:https://brainly.com/question/15687460