Answer:
550 m/s
Explanation:
The average molecular speed (v) is the speed associated with a group of molecules on average. We can calculate it using the following expression.
[tex]v = \sqrt{\frac{3 \times R \times T}{M} }[/tex]
where,
R: ideal gas constantT: absolute temperatureM: molar mass of the gasWe can use the info of argon to calculate the temperature for both samples.
[tex]T = \frac{v^{2} \times M}{3 \times R} = \frac{(391m/s)^{2} \times 39.95g/mol}{3 \times 8.314J/k.mol} = 2.45 \times 10^{5} K[/tex]
Now, we can use the same expression to find the average molecular speed in a sample of Ne gas.
[tex]v = \sqrt{\frac{3 \times R \times T}{M} } = \sqrt{\frac{3 \times (8.314J/k.mol) \times 2.45 \times 10^{5}K }{20.18g/mol} } = 550 m/s[/tex]
Which of the following cannot have hydrogen bonds? Select one: A. NH3 B. H2O C. HF D. CH3NH2 E. Which of the following cannot have hydrogen bonds? Select one: A. NH3 B. H2O C. HF D. CH3NH2 E. HCl
Answer:
E. HCl
Explanation:
Cl atom does not have enough electronegativity to make enough positive charge on H.
HCl is the compound which doesn't have hydrogen bonds. This is because of
the higher size of the chlorine atom.
There is no hydrogen bond because of the high size of the chlorine.
Chlorine have electrons with a very low density. It is also very
electronegative which explains why the formation of hydrogen bonds in the
compound HCl is not possible.
Instead, HCl has covalent bonds in which electron is shared between the
hydrogen and chlorine to achieve a stable configuration.
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4Ga + 3S2 ⇒ 2Ga2S3
How many grams of Gallium Sulfide would form if 20.5 moles of Gallium burned?
Answer:
2415.9g (corrected to 1 d.p.)
Explanation:
(Take the atomic mass of Ga=69.7 and S=32.1)
Assuming Ga is the limiting reagent (because the question did not mention the amount of sulphur burnt),
From the balanced equation, the mole ratio of Ga:Ga2S3 = 4: 2 = 2: 1, which means, every 2 moles of Ga burnt, 1 mole of Ga2S3 is produced.
Using this ratio, let y be the no. of moles of Ga2S3 produced,
[tex]\frac{2}{1} =\frac{20.5}{y}[/tex]
y = 20.5 / 2
= 10.25 mol
Since mass = no. of moles x molar mass,
the mass of Ga2S3 produced = 10.25 x (69.7x2 + 32.1x3)
= 2415.9g (corrected to 1 d.p.)
Determine the [OH⁻] concentration in a 0.344 M Ca(OH)₂ solution.
Answer:
[tex]0.688M[/tex]
Explanation:
Hello,
In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]
In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):
[tex]0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}[/tex]
Or simply:
[tex]0.688M[/tex]
Regards.
g what would happen to the solubility of a gas in a solution if the pressure above the solution is increased
Answer: The solubility of gas increases in a solution if the pressure above the solution is increased
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
[tex]C=K_H\times p[/tex]
where,
C = solubility
[tex]K_H[/tex] = Henry's constant
p = partial pressure
As the solubility is directly proportional to the pressure, thus increasing the pressure increases the solubility.
What is a heterogeneous mixture?
Answer:
The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.
for eg, mixture of sand and sugar.
hope it helps..
Using GRIGNARDS REAGENT convert methane to ethanol
Answer:
J
Explanation:
Organic chemistry too eazy but why 90% students avoid ?
Answer:
because it covers a large area as there are more then 1 lakh compounds of organic chemistry.
➔ Which compound has both ionic and covalent bonds? A. Ammonium chloride B. Carbon dioxide C. Ethyl ethanoate D. Sodium chloride
Answer:
Choice A. Ammonium chloride.
Explanation:
Consider the bonds in each of the four compounds.
Ammonium chlorideAmmonium chloride [tex]\rm NH_4Cl[/tex] is an ionic compound. Each
The [tex]\rm {NH_4}^{+}[/tex] and [tex]\rm Cl^{-}[/tex] ions in [tex]\rm NH_4Cl[/tex] are connected with ionic bonds.
What make [tex]\rm NH_4Cl[/tex] special is that its cation [tex]\rm {NH_4}^{+}[/tex] is polyatomic. In other words, each [tex]\rm {NH_4}^{+}[/tex] ion contains more than one atoms. These atoms (one [tex]\rm N[/tex] atom and four [tex]\rm H[/tex] atoms) are connected with covalent bonds. Therefore, [tex]\rm NH_4Cl[/tex] has both ionic and covalent bonds.
Carbon dioxideCarbon dioxide [tex]\rm CO_2[/tex] is a covalent compound. Each [tex]\rm CO_2[/tex] molecule contains two [tex]\rm C=O[/tex] double bonds in total. [tex]\rm CO_2[/tex] molecules have no ionic bond.
Ethyl ethanoateThe name "ethyl ethanoate" might sound like the name of a salt (think about sodium ethanoate.) However, in reality, ethyl ethanoate [tex]\rm CH_3COOCH_2CH3[/tex] is an ester. The "ethyl" here refers to the [tex]\rm -OCH_2CH3[/tex] part, originating from ethanol. On the other hand, "ethanoate" refers to the [tex]\rm CH_3C(O)-[/tex] part, which can be obtained from ethanoic acid.
These two parts are connected with a covalent [tex]\rm C-O[/tex] single bond. (The [tex]\rm C[/tex] in ethanoic acid is connected to the [tex]\rm O[/tex] in ethanol.) As a result, there's no ionic bond in ethyl ethanoate, either.
Sodium chlorideSodium chloride [tex]\rm NaCl[/tex] is an ionic compound. Both the [tex]\rm Na^{+}[/tex] ion and the [tex]\rm Cl^{-}[/tex] are monoatomic. While the [tex]\rm Na^{+}[/tex] and [tex]\rm Cl^{-}[/tex] in sodium chloride are connected with ionic bonds, neither [tex]\rm Na^{+}[/tex] nor [tex]\rm Cl^{-}[/tex] contains covalent bond.
Sort the resources into the correct categories.
are replaced by natural processes
Renewable Resources
Nonrenewable Resources
cannot be replaced in a short time
are used more quickly than replaced
have fixed amounts
are considered unlimited
are replaced faster than used
Intro
✓ Done
Answer:
Renewable Resources: are considered unlimited, are replaced faster than used.
Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.
Explanation:
Renewable resources are natural resources that are able to naturally regenerate themselves, hence, they are considered to be unlimited. They are usually replaced faster than they are used because they have a short regeneration time. A good example is the solar energy.
Nonrenewable resources are those natural resources that cannot naturally regenerate and when they do, it takes a very long time (usually millions of years). They are therefore used at a much faster rate than they are being replaced and their natural deposits are more or less fixed due to the long regeneration time. A good example is the crude oil deposit.
Hence:
Renewable Resources: are considered unlimited, are replaced faster than used.
Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.
Answer: !
Explanation:
Five mol of calcium carbide are combined with 10 mol of water in a closed, rigid, high-pressure vessel of 1800 cm3 internal empty volume. Acetylene gas is produced by the reaction:
Answer:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Explanation:
In order to find out the reaction, we must know the reactants.
For this situation, we make acetylene gas from carbide calcium CaC₂ and H₂O (water); therefore the reactants are:
- CaC₂ and H₂O
Acetylene is one of the products made → C₂H₂
So the reaction can be formed as this: CaC₂ + H₂O → C₂H₂
We missed the calcium, and this reaction also makes, Calcium Hydroxide, so the complete equation must be:
CaC₂ + H₂O → C₂H₂ + Ca(OH)₂
This is unbalanced, because we have 1 O in left side and 2 in right side so we add 2 in water so now, we get the complete reaction:
1 mol of calcium carbide reacts to 2 mol of water in order to produce 1 mol of acetylene and 1 mol of calcium hydroxide.
For the reaction 2 A - Products, the concentration of A is monitored over time. A graph of [A] versus time was found to be linear, with a negative slope. Select the true statement regarding this reaction.
A) The reaction is first order with respect to A.
B) The reaction is second order with respect to A.
C) The rate constant has a negative value.
D) In 2 The reaction has a half-life equal to k.
E) None of these statements is true.
Answer:
none of these statements is true
according to the question E) None of these statements is true.
What is a concentration in chemistry?The concentration of a chemical substance expresses the amount of a substance present in a mixture. There are many different ways to express concentration. Chemists use the term solute to describe the substance of interest and the term solvent to describe the material in which the solute is dissolved
What is concentration in chemistry units?
Quantitative units of concentration include molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.
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How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is
40.7 k/mol.)
2.09 x 1020
O 2.31% 10110
O 1.18 x 102 103
O 1.11% 1021)
PLEASE ANSWER AS SOON AS POSSIBLE REALLY WOULD APPRECIATE IT
Answer:
The answer is option D.
Hope this helps you
Calculate the volume of 0.500 M C2H3O2H and 0.500 M C2H3O2Na required to prepare 0.100 L of pH 5.00 buffer with a buffer strength of 0.100 M. The pKa of C2H3O2H is 4.75.
Answer:
You require 12.8mL of the 0.500M C₂H₃O₂Na and 7.2mL of the 0.500M C₂H₃O₂H
Explanation:
It is possible to obtain pH of a weak acid using H-H equation:
pH = pKa + log₁₀ [A⁻] / [HA]
For the buffer of acetic acid/acetate, the equation is:
pH = pKa + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]
Replacing:
5.00 = 4.75 + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]
1.7783 = [C₂H₃O₂Na] / [C₂H₃O₂H] (1)
Buffer strength is the concentration of the buffer, that means:
0.1M = [C₂H₃O₂Na] + [C₂H₃O₂H] (2)
Replacing (2) in (1):
1.7783 = 0.1M - [C₂H₃O₂H] / [C₂H₃O₂H]
1.7783 [C₂H₃O₂H] = 0.1M - [C₂H₃O₂H]
2.7783 [C₂H₃O₂H] = 0.1M
[C₂H₃O₂H] = 0.036MAlso:
[C₂H₃O₂Na] = 0.1M - 0.036M
[C₂H₃O₂Na] = 0.064MThe moles of both compounds you require is:
[C₂H₃O₂Na] = 0.1L × (0.064mol / L) = 0.0064moles
[C₂H₃O₂H] = 0.1L × (0.036mol / L) = 0.0036moles
Your stock solutions are 0.500M, thus, volume of both solutions you require is:
[C₂H₃O₂Na] = 0.0064moles × (1L / 0.500M) = 0.0128L = 12.8mL
[C₂H₃O₂H] = 0.0036moles × (1L / 0.500M) = 0.0072mL = 7.2mL
You require 12.8mL of the 0.500M C₂H₃O₂Na and 7.2mL of the 0.500M C₂H₃O₂HCarbon dioxide gas reacts with liquid water to produce aqueous carbonic acid.” Which chemical equation correctly translates this description? CO2 (s) + H2O (g) → H2CO3 (s) CO2 (l) + H2O (l) → H2CO3 (l) CO2 (g) + H2O (g) → H2CO3 (aq) CO2 (g) + H2O (l) → H2CO3 (aq)
Answer: CO2(g)+H2O(I) > H2CO3(Aq)
Explanation:
Got it right?
4. What are the potential sources of error that might cause disagreement between the activity series' prediction of reactions and your observations of reactions
Answer:
1. Not to have enough salt water on the foil
2.not cleaning the foil well to remove interfering materials
Which products are formed when aluminum is added to a silver chlorine solution?
Answer:
Alcl3 and Cl2
Explanation:
the product above will be formed
Answer:
silver (Ag) and aluminum chloride (AlCl₃)
Explanation:
The reaction between aluminum and silver chloride is a single replacement reaction. A single replacement reaction is when one element switches places with another.
Al + 3AgCl ➔︎ 3Ag + AlCl₃
In the reaction, the cations (positively charged ions) switch places. Aluminum (Al) switches places with Silver (Ag). So, the products of the reaction are silver and aluminum chloride.
Hope this helps.
Gallium chloride is formed by the reaction of 2.25 L of a 1.50 M solution of HCl according to the following equation: 2Ga 6HCl --> 2GaCl3 3H2 Determine the mass of gallium chloride, in grams, produced. Group of answer choices
Answer:
198.56g of GaCl3
Explanation:
We'll begin by calculating the number of mole HCl in 2.25 L of a 1.50 M solution of HCl. This is illustrated below:
Molarity of HCl = 1.50 M
Volume = 2.25 L
Mole of HCl =..?
Molarity = mole /Volume
1.5 = mole /2.25
Cross multiply
Mole = 1.5 x 2.25
Mole of HCl = 3.375 mole
Next, we shall determine the number of mole Gallium chloride, GaCl3 produced from the reaction. This is shown below:
2Ga + 6HCl —> 2GaCl3 + 3H2
From the balanced equation above,
6 moles of HCl reacted to produce 2 moles of GaCl3.
Therefore, 3.375 mole of HCl will react to produce = (3.375 x 2)/6 = 1.125 mole of GaCl3.
Therefore, 1.125 moles of GaCl3 were produced from the reaction.
Next, we shall convert 1.125 mole of GaCl3 to grams. This is illustrated below:
Molar mass of GaCl3 = 70 + (35.5x3) = 176.5g/mol
Mole of GaCl3 = 1.125 mole
Mass of GaCl3 =..?
Mole = mass /Molar mass
1.125 = mass of GaCl3 /176.5
Cross multiply
Mass of GaCl3 = 1.125 x 176.5
Mass of GaCl3 = 198.56g
Therefore, 198.56g of GaCl3 were produced from the reaction.
Lead can be prepared from galena [lead(II) sulfide] by first heating with oxygen to form lead(II) oxide and sulfur dioxide. Heating the metal oxide with more galena forms the metal and more sulfur dioxide. Write a balanced equation for the overall reaction by adding the balanced equations for the two steps.
Answer:
2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)
Explanation:
Lead can be prepared from galena [lead(II) sulfide] by first heating with oxygen to form lead(II) oxide and sulfur dioxide. The corresponding chemical equation is:
PbS(s) + 1.5 O₂(g) ⇒ PbO(s) + SO₂(g)
Heating the metal oxide with more galena forms the metal and more sulfur dioxide. The corresponding chemical equation is:
2 PbO(s) + PbS(s) ⇒ 3 Pb(s) + SO₂(g)
We can get the overall reaction by adding both steps and canceling what is repeated on both sides.
2 PbS(s) + 1.5 O₂(g) + 2 PbO(s) ⇒ PbO(s) + 2 SO₂(g) + 3 Pb(s)
2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)
For the reaction Ca(s)+Cl2(g)→CaCl2(s) calculate how many grams of the product form when 14.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant.
Answer:
[tex]m_{CaCl_2}=39.96gCaCl_2[/tex]
Explanation:
Hello,
In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:
[tex]m_{CaCl_2}=14.4gCa*\frac{1molCa}{40gCa} *\frac{1molCaCl_2}{1molCa} *\frac{111gCaCl_2}{1molCaCl_2}\\ \\m_{CaCl_2}=39.96gCaCl_2[/tex]
Clearly, chlorine is not used since it is said there is enough for the reaction to go to completion.
Best regards.
A sample of an unknown substance has a mass of 0.158kg. If 2,520.0 j of heat is required to heat the substance from 32.0C to 61.0C what is the specific heat of the substance
Using the volumes of EDTA solution you just entered and the corresponding dry unknown sample masses entered earlier, calculate the percent mass of calcium carbonate in the unknown sample mixture.
Enter the calculated percent mass of calcium carbonate in the dry unknown sample for each of the 3 acceptable trials.
Be sure to enter your mass percentages to the correct number of significant digits and in the corresponding order that you entered your masses of your dry unknown samples and volumes of your EDTA previously. The dry unknown sample mass you entered for entry #1 below should correspond to the percent mass of calcium carbonate you enter for entry #1 here.
Trial #: Mass (Grams):
#1: 0.015
#2: 0.015
#3: 0.015
Volume (mL)
#1: 16.4
#2: 15.00
#3: 18.70
Molarity of EDTA Solution: 0.0675
Answer:
#1
Explanation:
molarity of EDTA solution 0.0675
no1
Convert 120 degrees F to K.
[?]K
Answer:
322
Explanation:
This is easy
The element nitrogen would be expected to form covalent bond(s) in order to obey the octet rule. Use the octet rule to predict the formula of the compound that would form between nitrogen and hydrogen , if the molecule contains only one nitrogen atom and only single bonds are formed. Formula:
Answer:
The compound formula will be "NF₃". The further explanation is given below.
Explanation:
Nitrogen seems to have an electrical structure consisting of 1S², 2S² as well as 3S² and it requires three electrons to fulfill or conclude the octet. This will, therefore, form three bonds (covalent). Even though only single nitrogen has been present, that can only represent a single bond including fluorine. Therefore the methodology for something like the compound would be NF₃.So that the above would be the right answer.
Using the determined equivalence point from question 2 and the balanced reaction of acetic acid and sodium hydroxide, calculate the molarity of the acetic acid in your hot sauce packet.
Equivalance point is 3.0 mL NaOH, 0.6 g hot sauce, 0.1 M NaoH.
Answer:
Molarity of the packet is 0.5M
Explanation:
In the reaction of acetic acid with NaOH:
CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺
1 mole of acetic acid reacts with 1 mole of NaOH.
When you are titrating the acid with NaOH, you reach equivalence point when moles of acid = moles of NaOH.
Moles of NaOH are:
3.0mL = 3.0x10⁻³L ₓ (0.1 mol / L) = 3.0x10⁻⁴ moles of NaOH = moles of CH₃COOH.
Now, you find the moles of acetic acid in the hot sauce packet. But molarity is the ratio between moles of the acid and liters of solution.
As you don't know the volume of your packet, you can assume its density as 1g/mL. Thus, volume of 0.6g of hot sauce is 0.6mL = 6x10⁻⁴L.
And molarity of the packet is:
3.0x10⁻⁴ moles acetic acid / 6x10⁻⁴L =
0.5MCalculate the grams of solute needed to prepare 107 mL of a 2.75 M magnesium
chloride solution
Your Answer:
Answer
Answer: 28.02 g
Explanation:
The M stands for molarity. It is moles of solute/liters of solution. We can use the molarity to convert liters to mL, then make a proportion to find the grams.
[tex]\frac{2.75 mol}{L} *\frac{1L}{1000mL} =\frac{2.75 mol}{1000mL}[/tex]
Now that we have molarity in moles and mL, we can use the 107mL to get moles.
[tex]\frac{2.75moles}{1000mL} *107mL=0.29425mol[/tex]
We would multiply moles by molar mass to get grams. The molar mass of magnesium chloride is 95.211 g/mol.
[tex]0.29425mol*\frac{95.211g}{mol} =28.02g[/tex]
g The "Coulomb barrier" is defined to be the electric potential energy of a system of two nuclei when their surfaces barely touch. The probability of a nuclear reaction greatly increases if the energy of the system is above this barrier. What is the Coloumb barrier (in MeV) for the absorption of an alpha particle by a lead-208 nucleus
Answer:
The Coulomb Barrier U is 25.91 MeV
Explanation:
Given that:
Atomic Mass of lead nucleus A = 208
atomic mass of an alpha particle A = 4
Radius of an alpha particle [tex]R_\alpha = R_o A^{^{\dfrac{1}{3}}[/tex]
where;
[tex]R_\alpha = 1.2 \times 10 ^{-15} \ m[/tex]
[tex]R_\alpha = R_o A^{^{\dfrac{1}{3}}[/tex]
[tex]R_\alpha = 1.2 \times 10 ^{-15} \ m \times (4) ^{^{\dfrac{1}{3}}[/tex]
[tex]R_\alpha = 1.905 \times 10^{-15} \ m[/tex]
Radius of the Gold nucleus
[tex]R_{Au}= R_o A^{^{\dfrac{1}{3}}[/tex]
[tex]R_{Au}= 1.2 \times 10 ^{-15} \ m \times (208) ^{^{\dfrac{1}{3}}[/tex]
[tex]R_{Au} = 7.11 \times 10^{-15} \ m[/tex]
[tex]R = R_\alpha + R_{Au}[/tex]
[tex]R = 1.905 \times 10^{-15} \ m + 7.11 \times 10^{-15} \ m[/tex]
[tex]R = 9.105 \times 10 ^{-15} \ m[/tex]
The electric potential energy of the Coulomb barrier [tex]U = \dfrac{Ke \ q_{\alpha} q_{Au}}{R}[/tex]
[tex]U = \dfrac{8.99 \times 10^9 \ N.m \ ^2/C ^2 \ \times 2 ( 82) \times \(1.60 \times 10^{-19} C \ \ e } {9.105 \times 10^{-15} \ m }[/tex]
U = 25908577.7eV
U = 25.908577 × 10⁶ eV
U = 25.91 MeV
The Coulomb Barrier U is 25.91 MeV
The complete combustion of ethanol, C2H5OH(l), to form H2O(g) and CO2(g) at constant pressure releases 1235 kJ of heat per mole of C2H5OH.
Write a balanced equation for this reaction.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Write a balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product.
Answer:
2 CH₃OH + 3 O₂ ⇒ 2 CO₂ + 4 H₂O
Explanation:
Methanol is CH₃OH. Oxygen is O₂. A combustion produces CO₂ and H₂O. Create an equation using this information and balance.
CH₃OH + O₂ ⇒ CO₂ + H₂O
2 CH₃OH + 3 O₂ ⇒ 2 CO₂ + 4 H₂O
The balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is
CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)
From the question,
We are to write a balanced equation for the combustion of liquid methanol in air.
The combustion of liquid methanol in air is the reaction between methanol (CH₃OH) and oxygen (O₂). The reaction yields carbon(IV) oxide and water.
Now, for the balanced equation for the combustion of liquid methanol in air
The balanced chemical equation is
CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)
Hence, the balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)
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Which of the following is an alkali metal?
A. Lithium (LI)
B. Boron (B)
c. Calcium (Ca)
D. Krypton (Kr)
Answer:
lithium is akali metal
Answer:
lithium is an alkali metal as it lies in group 1st in modern perodic table.