Suppose that you have a class called Student that is defined in student.h file. The class is in a namespace called fhsuzeng. Fill in the following blanks for the structure of the header file student.h.

#ifndefine STUDENT_H
______________
namespace _______
{
___________Student
{
};
}
_____________________

+41.50 = 0 10000100 01001100000000000000000  [single precision]

-72.125 = 1 10000000101 0010000010000000000000000000000000000000000000000000 [double precision]

(I) +41.50 using single precision

Follow the following steps:

(a) Single precision has 32 bits in total and is divided into three groups: sign (has 1 bit), an exponent (has 8 bits) and a mantissa (also called fraction, has 23 bits)

(b) Divide the number (41.50) into its whole and decimal parts:

Whole = 41

Decimal = 0.50

(c) Convert the whole part to binary:

2    |    41

2    |    20 r 1

2    |    10 r 0

2    |    5 r 0

2    |    2 r 1

2    |    1 r 0

     |    0 r 1

Reading upwards gives 41 = 101001₂

(d) Convert the decimal part to binary:

0.50 x 2 = 1.0  = 1 [number in front of decimal]

0.0 x 2 = 0.0 = 0  [number in front of decimal]

Reading downwards gives 0.5 = 10₂

(e) Put the two parts together as follows;

    101001.10₂

(f) Convert the result in (e) to its base 2 scientific notation:

Move the decimal to just before the leftmost bit as follows;

1.0100110

In doing so, we have moved over 5 numbers to the left. Therefore, the exponent is 5. Moving to the left gives a positive exponent while moving to the right gives a negative exponent.

Altogether we have;

1.0100110 x 2⁵

(g) Determine the sign bit of the number and display in binary: Since the number +41.50 is positive, the sign bit is 0.

(h) Determine the exponent bits.

Since this is a single precision conversion, the exponent bias is 127.

To get the exponent we add the exponent value from (e) to the exponent bias and get;

5 + 127 = 132

(i) Convert the exponent to binary:

2    |    132

2    |    66 r 0

2    |    33 r 0

2    |    16 r 1

2    |    8 r 0

2    |    4 r 0

2    |    2 r 0

2    |    1 r 0

     |    0 r 1

Reading upwards gives 132 = 10000100₂

(j) Determine the mantissa bits:

The mantissa is the rest of the number after the decimal of the base 2 scientific notation found in (f) above.

0100110 from 1.0100110 x 2⁵                  [Just remove the leftmost 1 and the decimal point]

(k) Combine the three parts: sign bit (1 bit), exponent bits (8 bits) and mantissa bits (23 bits)

sign bit = 0                [1 bit]

exponent bits = 10000100        [8 bits]

mantissa bits = 0100110        [7 out of 23 bits]

Then fill out the remaining part of the mantissa with zeros to make it 23 bits.

mantissa bits = 01001100000000000000000        

Putting all together we have

0 10000100 01001100000000000000000 as +41.50 in  a IEEE 754 single precision format.

(II) -72.125 using double precision

Follow the following steps:

(a) Double precision has 32 bits in total and is divided into three groups: sign (has 1 bit), an exponent (has 11 bits) and a mantissa (also called fraction, has 52 bits)

(b) Divide the number (72.125) into its whole and decimal parts:

Whole = 72

Decimal = 0.125

(c) Convert the whole part to binary:

2    |    72

2    |    36 r 0

2    |    18 r 0

2    |    9 r 0

2    |    4 r 1

2    |    2 r 0

2    |    1 r 0

     |    0 r 1

Reading upwards gives 72 = 1001000₂

(d) Convert the decimal part to binary:

0.125 x 2 = 0.25  = 0 [number in front of decimal]

0.25 x 2 = 0.50 = 0  [number in front of decimal]

0.50 x 2 = 1.00 = 1  [number in front of decimal]

0.00 x 2 = 0.00 = 0  [number in front of decimal]

Reading downwards gives 0.125 = 0010₂

(e) Put the two parts together as follows;

    1001000.0010₂

(f) Convert the result in (e) to its base 2 scientific notation:

Move the decimal to just before the leftmost bit as follows;

1.0010000010

In doing so, we have moved over 6 numbers to the left. Therefore, the exponent is 6. Moving to the left gives a positive exponent while moving to the right gives a negative exponent.

Altogether we have;

1.0010000010 x 2⁶

(g) Determine the sign bit of the number and display in binary: Since the number -72.125 is negative, the sign bit is 1.

(h) Determine the exponent bits.

Since this is a double precision conversion, the exponent bias is 1023.

To get the exponent we add the exponent value from (e) to the exponent bias and get;

6 + 1023 = 1029

(i) Convert the exponent to binary:

2    |    1029

2    |    514 r 1

2    |    257 r 0

2    |    128 r 1

2    |    64 r 0

2    |    32 r 0

2    |    16 r 0

2    |    8 r 0

2    |    4 r 0

2    |    2 r 0

2    |    1 r 0

     |    0 r 1

Reading upwards gives 1029 = 10000000101₂

(j) Determine the mantissa bits:

The mantissa is the rest of the number after the decimal of the base 2 scientific notation found in (f) above.

0010000010 from 1.0010000010 x 2⁶                  [Just remove the leftmost 1 and the decimal point]

(k) Combine the three parts: sign bit (1 bit), exponent bits (11 bits) and mantissa bits (52 bits)

sign bit = 1                [1 bit]

exponent bits = 10000000101    [11 bits]

mantissa bits = 0010000010        [10 out of 52 bits]

Then fill out the remaining part of the mantissa with zeros to make it 52 bits.

mantissa bits = 0010000010000000000000000000000000000000000000000000

Putting all together we have

1 10000000101 0010000010000000000000000000000000000000000000000000 as -72.125 in  a IEEE 754 double precision format.

Answer:

Assuming this is Python, I would do something like the following:

Explanation:

hourWage= float(input ("What is your hourly wage?: "))

regularHours= float(input ("How many regular hours did you work this week?: "))

overtimeHours= float(input ("How many overtime hours did you have this week?: "))

overtimeWage= (1.5*hourWage)

totalWeeklyPay= (hourWage*regularHours)+(overtimeHours*overtimeWage)

print= ("Your total weekly pay is: " ,totalWeeklyPay)

I hope this works!

Following are the program to calculate weeklyPay value:

Program Explanation:

Program:

Wage = float(input("Enter hourly wage: "))#defining a variable Wage that inputs float value

Hour = float(input("Enter total number of regular hours: "))#defining a variable Hour that inputs float value

Hours = float(input("Enter overtime hours: "))#defining a variable Hours that inputs float value

weeklyPay = (Wage*Hour) + (1.5*Wage*Hours)#defining a variable weeklyPay that calculates the values

print (weeklyPay)#defining a print method that prints weeklyPay value

Output:

Please find the attached file.

Learn more:

brainly.com/question/8020777

Answer:

Distributed Consensus

Explanation:

A distributed system refers to a set of connected computers to achieves a goal. They can each work independently and they usually appear as a single computer system to end users.

Database computations usually require each connected computer node to agree on the computations and results  before submitting it to the database.

This process is referred to as a Distributed Consensus.

A distributed consensus makes sure that in a distributed system, the data among nodes all reach an agreement and make confirmations before submitting to a database.

Answer:

a) True

Explanation:

A macro virus infects executable portions of code. A virus that attaches to an executable program can do anything the program is permitted to.

Most use an Email for spreading macro viruses, which is a common method and is rather easy. Although, more advanced softwares trick people into giving personal information.

Answer:

Car insurance

Explanation:

they are machines with ai

Answer: YES

Explanation:

int year=2019;

int yearNext=2020;

 int &ref=year;

&ref=yearNext; {This line leads to error as references cannot be reassigned}

(//compilation error: lvalue required as left operand of assignment

) lvalue(&ref) is not something which can be assigned.

To get this better, here are the difference between pointers and reference variables

Pointers

Pointers can be incremented

Array can be formed with pointers

Pointers can be reassigned

Pointer can be declared as void  

Reference variable

References cannot be incremented

Array cannot be formed with references

References cannot be reassigned as references shares the address of the variable its assigned

References can never be void

Answer:

The program written in Python is as follows

nums = []

for i in range(0,68):

-->nums.append(i)

print(nums)

Explanation:

Please note that --> is used to denote indentation

The first line creates an empty list

nums = []

This line creates an iteration from 0 to 67, using iterating variable i

for i in range(0,68):

This line saves the current value of variable i into the empty list

nums.append(i)

At this point, the list has been completely filled with 0 to 67

This line prints the list

print(nums)

Answer:

Here is the JavaScript program:

function MatricesMul(matrix1, matrix2) {

   var product = [];

   for (var i = 0; i < matrix1.length; i++) {

       product[i] = [];

       for (var j = 0; j < matrix2[0].length; j++) {

           var total = 0;

           for (var k = 0; k < matrix1[0].length; k++) {

               total += matrix1[i][k] * matrix2[k][j];  }

           product[i][j] = total;        }    }

   return product;}

var matrix1 = [[1,2,3],[4,5,6],[7,8,9]]

var matrix2 = [[3,2,1],[6,5,4],[1,2,3]]

var output = MatricesMul(matrix1, matrix2)

document.write(output);

Explanation:

The function MatricesMul(matrix1, matrix2) takes two matrices (matrix1 and matrix2) as parameters.

var product = [];  product works as an array to contain the result of the multiplication of the two matrices matrix1 and matrix2.

for (var i = 0; i < matrix1.length; i++) this is a loop which iterates through the matrix1 and it continues to execute until the loop variable i exceeds the length of the matrix1. This is basically the loop which iterates through the rows of matrix1.

for (var j = 0; j < matrix2[0].length; j++) this is a loop which iterates through matrix2 and it continues to execute untill the loop variable j exceeds the length of the element of matrix2 at 0-th index (first element). This is basically the loop which iterates through the colulmns of matrix2.

var total = 0;  variable total is initialized to 0 and this variable is used to compute the sum.

for (var k = 0; k < matrix1[0].length; k++) this loop is used for the multiplication of the two matrices matrix1 and matrix2.

total += matrix1[i][k] * matrix2[k][j];  this statement first multiplies each element of matrix1 row to each element of the matrix2 column, takes the sum of pairwise products.

return product; returns the result of the multiplication of matrix1 and matrix2.

For example let matrix1 = [[1,2,3],[4,5,6],[7,8,9]]  and matrix2 = [[3,2,1],[6,5,4],[1,2,3]] .

The first for loop moves through each row of matrix1. The first element of first row of matrix1 is 1, the second element is 2 and third is 3. The second loop iterates through each column of matrix2. Lets take the first column matrix2. The first element of first column of matrix2 i.e. 3, the second element is 6 and the third is 1. Third loop performs the pairwise multiplication of row of matrix1 to column of matrix2 and takes the sum of pairwise product. This means 1 is multiplied to 3, 2 is multiplied with 6 and 3 is multiplied to 1. This will take the form: 1*3 + 2*6 + 3*1 = 3 + 12 + 3 Now their sum is taken and the result is stored in total variable. So the sum of 3 + 12 + 3 is 18. This process will continue until all the rows elements of matrix1 and elements in all columns of matrix2 are multiplied and the sum of each pairwise product is taken.

var matrix1 = [[1,2,3],[4,5,6],[7,8,9]]

var matrix2 = [[3,2,1],[6,5,4],[1,2,3]]

The above two statements two (3,3) square matrices are given values.

var output = MatricesMul() this calls the MatricesMul method and passes the two matrices (matrix1, matrix2) to the function and stores the result of this multiplication to output variable.

document.write(output); displays the result of the multiplication of two square matrices .

Answer:

third ighjojdudjz

ghddduewjj

wkckdjjj

Explanation:

cchmddkhwmx

ndhdnahdd

jruditndjed

Answer:

milespergallon = float(input())

dollarspergallon = float(input())

milestodrive = int(input())

trip_cost = milestodrive / milespergallon * dollarspergallon

print('Cost to drive {:d} miles at {:f} mpg at $ {:.2f}/gallon is: $ {:.2f}'.format(milestodrive, milespergallon, dollarspergallon, trip_cost))

Explanation:

Get the inputs from the user for milespergallon, dollarspergallon and milestodrive

Calculate the trip_cost, divide the milestodrive by milespergallon to get the amount of gallons used. Then, multiply the result by dollarspergallon.

Print the result as requested in the question

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation:

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\ 2 & 17 & 1 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\ 2 & 1 & 1 \\ \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\ 2 & 13 & 1 \\ 2 & 6 & 0 \\ 2 & 3 & 1 \\ 2 & 1 & 1 \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1 \\\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Answer:

Following are the description of the given points:

Explanation:

A) The Multiple greedy approaches could exist, which could be to reach for the closest emergency diamond, and yet clearly we are going to miss some very essential routes in that case. So, it can make every argument quickly, and seek to demonstrate a reference case for that.

B) An approach to the evolutionary algorithm and its users are going to just have states M x N. But each state (i, j) indicates the absolute difference between the amount of the selected diamond and the amounts of the costs incurred.

DP(i, j) = DimondVal(i, j) + max ((DP(i, j-1)-2), (DP(i-1,j-1)-3))

DP(i, j) is a description of the state.

DimondVal(i, j) is the diamond value at (i j), 0 if there is no diamond available.

This states must calculate the states of M N  and it involves continuous-time for each State to determine. Therefore the amount of time of such an algo is going to be O(MN).

Answer:

The classification including its given topic has always been outlined in section through below justifications.

Explanation:

Answer: C. both single threaded and multithreaded

Explanation:

A process can either be single threaded and multithreated. Single threaded processes is when the execution of instructions are in a single sequence i.e the sequence is one command at a time while for multithreaded processes, there are. execution of several multiple parts of a program that occurs at the same time.

A single threaded process only runs on one CPU, whereas for the execution of a multi-threaded, it may be divided amongst the available processors.

Answer:

True

Explanation:

Solution

ZigBee uses unlicensed frequency bands but operate at slower speed or data rates.

ZigBee: This communication is particular designed for control and sensor networks on IEEE 802.15.4 requirement for wireless personal area networks (WPANs), and it is a outcome from Zigbee alliance.

This communication level defines physical and  (MAC) which is refereed to as the Media Access Control layers to manage many devices at low-data rates.

Answer:

Here is the C++ program for Employee class with fields id,name and sal.

#include <iostream>  // to use input output functions

#include <string>  //to manipulate and use strings

using namespace std;   // to access objects like cin cout

class Employee {  //class Employee

private:  

/* the following data members are declared as private which means they can only be accessed by the functions within Employee class */

  string name;  //name field

  int id; //id field

  double sal;   //salary field

public:    

  Employee();  // constructor that initializes an object when it is created

/* setName, setID and setSalary are the mutators which are the methods used to change data members. This means they set the values of a private fields i.e. name, id and sal */

  void setName(string n)  //mutator for name field

     { name = n; }        

  void setId(int i)  //mutator for id field

     { id = i; }        

  void setSalary(double d)  //mutator for sal field

     { sal = d; }  

/* getName, getID and getSalary are the accessors which are the methods used to read data members. This means they get or access the values of a private fields i.e. name, id and sal */

  string getName()  //accessor for name field

     { return name; }        

  int getId()  //accessor for id field

     { return id; }        

  double getSalary()  //accessor for sal field

     { return sal; }  };  

Employee::Employee() {  //default constructor where the fields are initialized

  name = "";  // name field initialized

  id = 0;  // id field initialized to 0

  sal = 0;   }   // sal field initialized to 0

void display(Employee);  

// prototype of the method display() to display the data of Employee

int main() {  //start of the main() function body

  Employee emp;  //creates an object emp of Employee class

/*set the name field to Abc Xyz which means set the value of Employee class name field to Abc Xyz  through setName() method and object emp */

  emp.setName("Abc Xyz");  

/*set the id field to 1234 which means set the value of Employee class id field to 1234  through setId() method and object emp */

  emp.setId(1234);

/*set the sal field to 1000 which means set the value of Employee class sal field to 1000  through setSalary() method and object emp */

  emp.setSalary(1000);    

  display(emp);  }   //calls display() method to display the Employee data

void display(Employee e) {  // this method displays the data in the Employee //class object passed as a parameter.

/*displays the name of the Employee . This name is read or accessed through accessor method getName() and object e of Employee class */

  cout << "Name: " << e.getName() << endl;  

/*displays the id of the Employee . This id is read or accessed by accessor method getId() and object e */

  cout << "ID: " << e.getId() << endl;

/*displays the salary of the Employee . This sal field is read or accessed by accessor method getSalary() and object e */

  cout << "Salary: " << e.getSalary() << endl;  }

Explanation:

The program is well explained in the comments mentioned with each statement of the program.

The program has a class Employee which has private data members id, name and sal, a simple default constructor Employee(), mutatator methods setName, setId and setSalary to set the fields, acccessor method getName, getId and getSalary to get the fields values.

A function display( ) is used to display the Employee data i.e. name id and salary of Employee.

main() has an object emp of Employee class in order to use data fields and access functions defined in Employee class.

The output of the program is:

Name: Abc Xyz                                                                                                      

ID: 1234                                                                                                                  

Salary: 1000

The program and its output are attached.

Answer:

Brainly is not meant to give paragraph answers to large questions.

In a computer (desktop)

There are 8-9 main components to a PC

Motherboard

CPU

GPU (for gamers)

RAM

SSD

HDD

PSU

Cooling fans (for AMD processors stock fans are included)

Case (some fans included)

I personally build my computers (desktops) as its cheaper and I won't have to pay a build fee.

Answer:

No

Explanation:

The other websites provide very detailed information, when you search the same information that is mentioned at CDC website. The information related to causes and symptoms of brain injuries is similar on both the websites. The reliability of information provided on other websites is questioned. These websites provide a lot of information and it is sometimes time consuming to find the relevant information.

Answer:

Replace the first blank with:

message = "Hello " + name + ". Your lucky number is " + str(number)

Replace the second blank with:

return message

Explanation:

The first blank needs to be filled with a variable; we can make use of any variable name as long as it follows the variable naming convention.

Having said that, I decided to make use of variable name "message", without the quotes

The next blank is meant to return the variable on the previous line;

Since the variable that was used is message, the next blank will be "return message", without the quotes

In other to make the function lucky_number return the message rather than print, we use the return keyword.

def lucky_number(name):

number = len(name) * 9

message = "Hello " + name + ". Your lucky number is " + str(number)

return message

In other to return a variable or expression in a defined function such as the lucky_number function defined above, all we have to do is use the return keyword with the message.

When we use :

The returned value could also be printed using the statement :

print(lucky_number(name)) : This statement prints the content of the returned message variable.

Learn more : https://brainly.com/question/17027551

If my computer has 4 gigabytes of ram memory then I have 4e+9 bytes of memory.  I think-

Answer: That isn't a software problem, its a hardware problem. There is a difference between 12gb of ram versus 100 gb of HDD. Ram is temporary storage, you can not turn SSD or HDD storage into RAM. If you are a gamer, STEER AWAY FROM LAPTOPS, DO NOT BUY A GAMING LAPTOP. Either buy a DESKTOP (or build) or a console. They give more performance for the price and they are easily upgradable. Not many people can open up a laptop and put in more RAM because the hardware is incredibly small.

Answer:

Validity

Explanation:

Personnel Selection encompasses all the processes and methods involved in the selection of workers. The purpose of personnel selection is to determine the best candidate for the job and in so doing the recruiting organization must play by the rules laid down by the government for recruitment. Validity refers to the relationship between interviews and excellent performance at the job.

Validity implies that the method of selection must meet up to a standard criterion. This standard criterion is the expected job performance required of the potential employee. Different interview types (such as job-related, situational, and psychological) have different validity levels.  

Answer:

Here is the Python program.

def DigitList(number):  

   return sum(map(int, str(number)))  

list = [18, 23, 35, 43, 51]  

ascendList = sorted(list, key = DigitList)  

print(ascendList)

Explanation:

The method DigitList() takes value of numbers of the list as parameter. So this parameter is basically the element of the list. return sum(map(int, str(number)))  statement in the DigitList() method consists of three methods i.e. str(), map() and sum(). First the str() method converts each element of the list to string. Then the map() function is used which converts every element of list to another list. That list will now contain digits as its elements. In short each number is converted to the string by str() and then the digit characters of each string number is mapped to integers. Now these digits are passed to sum() function which returns the sum. For example we have two numbers 12 and 31 in the list so each digit is 1 2 and 3 1 are added to get the sum 3 and 4. So now the list would have 3 4 as elements.

Now list = [18, 23, 35, 43, 51] is a list of 5 numbers. ascendList = sorted(list, key = DigitList)  statement has a sorted() method which takes two arguments i.e. the above list and a key which is equal to the DigitList which means that the list is sorted out using key=DigitList. DigitList simply converts each number of list to a another list with its digits as elements and then returns the sum of the digits. Now using DigitList method as key the element of the list = [18, 23, 35, 43, 51] are sorted using sorted() method. print(ascendList) statement prints the resultant list with values in the list in ascending order sorted by the sum of their digits.

So for the above list [18, 23, 35, 43, 51] the sum of each number is 9 ,5, 8, 7, 6 and then list is sorted according to the sum values in ascending order. So 5 is the smallest, then comes 6, 7, 8 and 9. So 5 is the sum of the number 23, 6 is the sum of 51, 7 is the sum of 43, 8 is the sum of 35 and 9 is the sum of 18. So now after sorting these numbers according to their sum the output list is:

[23, 51, 43, 35, 18]                                                                                                          

Answer:

The tokens are:

January

space

1

,

space

2008

Explanation:

StringTokenizer class is basically used to break a string into tokens. The string consists of numbers, letters, quotation marks commas etc,

For example if the string is "My name is ABC" then StringTokenizer will break this string to following tokens:

My

name

is

ABC

So in the above example, the string is "January 1, 2008". It contains January with a space, then 1, then a comma, then 2008

The last comma and true in the statement do not belong to the string. They are the parameters of the StringTokenizer constructor i.e.

StringTokenizer(String str, String delim, boolean flag)

So according to the above constructor str= "January 1, 2008"

String delim is ,

boolean flag = true

So  the StringTokenizer strToken = new StringTokenizer("January 1, 2008", ", ", true); statement has:

a string January 1, 2008

a delim comma with a space (, ) which is used to tokenize  the string "January 1, 2008".

boolean flag set to true which means the delim i.e. (, ) is also considered to be a token in the string. This means the comma and space are considered to be tokens in the given string January 1, 2008.

Hence the output is January space 1 comma space 2008.

Check the attached image to see the output of the following statement.

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

Answer:

1 (true)

Explanation:

10 == 10 is valid=> 10 >= 10 is valid => 10 >=(5*2) is valid

10 == 10 is valid=> 10 <= 10 is valid => 10 <=(5*2) is valid

=>  ((10 >= 5*2) and (10 <= 5*2)) is valid => Return 1 or True

Answer:

Linked lists and arrays are both linear data structures but while an array is a collection of items that can be accessed randomly, a linked list can be accessed sequentially.

A sparse matrix contains very few non-zero elements. For example;

_                        _

|  0   0   3  0  6    |

|   0   5   0  0  4   |

|   2   0   0  0  0   |

|_ 0   0   0  0  0 _|

In the implementation of a sparse matrix, the following are some of the pros and cons of using a linked list over an array;

PROS

i.  Linked lists are dynamic in nature and are readily flexible - they can expand and contract without having to allocate and/or de-allocated memory compared to an array where an initial size might need to be set and controlled almost manually. This makes it easy to store and remove elements from the sparse matrix.

ii. No memory wastage. Since the size of a linked list can grow or shrink at run time, there's no memory wastage as it adjusts depending on the number of items it wants to store. This is in contrast with arrays where you might have unallocated slots. Also, because the zeros of the sparse matrix need not be stored when using linked lists, memory is greatly conserved.

CONS

i. One of the biggest cons of linked lists is the difficulty in traversing items. With arrays, this is just of an order of 0(1) since the only requirement is the index of the item. With linked lists, traversal is sequential which means slow access time.

ii. Storage is another bottle neck when using linked lists in sparse matrix implementation. Each node item in a linked list contains other information that needs to be stored alongside the value such as the pointer to the next or previous item.

Answer:

Bulk Ethernet Cable - Category 5e or CAT5e

Bulk RJ45 Crimpable Connectors for CAT-5e

Explanation:

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

The code for function calling is coded below.

To assign the maximum sum of `(numA, numB)` plus the maximum of `(numY, numZ)` to the variable `maxSum` using just one statement, you can call the `FindMax()` function twice in an expression.

Here's the code:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

This code calls the `FindMax()` function twice, once with the parameters `(numA, numB)` and again with the parameters `(numY, numZ)`.

It calculates the maximum of each pair of numbers using the `FindMax()` function and then adds the two maximum values together. The result is assigned to the `maxSum` variable.

Learn more about Function call here:

https://brainly.com/question/31798439

#SPJ6

Answer:

c. Purging

Explanation:

Based on the information provided it can be said that the best method for sanitizing the data would be Purging. This is a process that permanently erases the data from a specific storage unit. Doing so prevents data from being recovered by an expert and also frees up storage and memory space to be used for other information. Since it is very inexpensive and provides the best overall results this would be the best option in this scenario.

Answer:

Excel Solver

Explanation: