Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
(a) Use a linear approximation to estimate g(2.95) and g(3.05).
g(2.95) =
g(3.05) =
(b) Are your estimates in part (a) too large or too small? Explain.
A) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie below the curve. Thus, the estimates are too small.
B) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie below the curve. Thus, the estimates are too small.
C) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie above the curve. Thus, the estimates are too large.
D) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie above the curve. Thus, the estimates are too large.

Answer:

The answer is "Option A"

Step-by-step explanation:

The valid linear programming language equation can be defined as follows:

Equation:

[tex]\Rightarrow \ Min\ 4x + 3y + (\frac{2}{3})z[/tex]

The description of a linear equation can be defined as follows:

It is an algebraic expression whereby each term contains a single exponent, and a single direction consists in the linear interpolation of the equation.

Formula:

[tex]\to \boxed{y= mx+c}[/tex]

Answer:

[tex] \mu = 23.33, \sigma =6.13[/tex]

And for this case we are analyzing the value os 33.44 and we can use the z score formula given by:

[tex] z=\frac{X -\mu}{\sigma}[/tex]

And replacing we got:

[tex] z=\frac{33.44 -23.33}{6.13}= 1.649[/tex]

We know that the proportion of area beyond the Z score associated with this age is  .05 so then the percentile would be: 95

Step-by-step explanation:

For this case we have the following parameters:

[tex] \mu = 23.33, \sigma =6.13[/tex]

And for this case we are analyzing the value os 33.44 and we can use the z score formula given by:

[tex] z=\frac{X -\mu}{\sigma}[/tex]

And replacing we got:

[tex] z=\frac{33.44 -23.33}{6.13}= 1.649[/tex]

We know that the proportion of area beyond the Z score associated with this age is  .05 so then the percentile would be: 95

Answer:

m = rise /run = (y2-y1)/(x2-x1)

Step-by-step explanation:

In math, slope is the ratio of the vertical and horizontal changes between two points on a surface or a line. The vertical change between two points is called the rise, and the horizontal change is called the run. The slope equals the rise divided by the run.

Answer: Run is the horizontal change between two points on a line.

Step-by-step explanation:

Answer:

equation is inconclusive

Step-by-step explanation:

you average the two speeds getting 200 mph. then you need to know the time is took to fully complete the race to get the unit rate which you would multiply to find yiur time.

Answer:

Monthly: $4,821

Weekly: $1112.54

Step-by-step explanation:

Monthly

A monthly salary can be found by dividing the yearly salary by the number of months.

salary / months

His salary is $57,852 and there are 12 months in a year.

$57,852/ 12 months

Divide

$4,821 / month

Jeremy makes $4,821 per month.

Weekly

To find the weekly salary, divide the yearly salary by the number of weeks.

salary / weeks

He makes $57,852 each year and there are 52 weeks in one year.

$57,852 / 52 weeks

Divide

$1112.53846 / week

Round to the nearest cent. The 8 in the thousandth place tells use to round the 3 up to a 4 in the hundredth place.

$1112.54 / week

Jeremy makes $1112.54 per week

Answer:

Mia:10 Maya:5 Maria:3

Step-by-step explanation:

3+7= 10= Mia's age

10÷2=5= Maya's age

Answer:

Mia - 10

Maya - 5

Maria - 3

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We have two events, A and B.

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

In which:

[tex]P(A \cup B)[/tex] is the probability of at least one of these events happening.

P(A) is the probability of A happening.

P(B) is the probability of B happening.

[tex]P(A \cap B)[/tex] is the probability of both happening.

In this question:

Event A: Passes the first course.

Event B: Passes the second course.

The probability she passes the first course is 0.7.

This means that [tex]P(A) = 0.7[/tex]

The probability she passes the second course is 0.67.

This means that [tex]P(B) = 0.67[/tex]

The probability she passes at least one of the courses is 0.79.

This means that [tex]P(A \cup B) = 0.79[/tex]

What is the probability she passes both courses

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

[tex]0.79 = 0.70 + 0.67 - P(A \cap B)[/tex]

[tex]P(A \cap B) = 0.58[/tex]

0.58 = 58% probability she passes both courses

Answer:

Solution,

[tex](5x + 1)(2x - 1)(2x - 3)[/tex]

[tex] = 5x(2x - 1) + 1(2x - 1) \times (2x - 3) \\ = (10 {x}^{2} - 5x + 2x - 1)(2x - 3) \\ = (10 {x}^{2} - 3x - 1)(2 x - 3) \\ = 10 {x}^{2} (2x - 3) - 3x(2 x - 3) - 1(2x - 3) \\ = 20 {x}^{3} - 30 {x}^{2} - 6 {x }^{2} + 9x - 2x + 3 \\ = 20 {x}^{3} - 36 {x}^{2} + 7x + 3[/tex]

Hope this helps..

Good luck on your assignment...

Answer:

The degrees of freedom are given by:

[tex] df =n-1= 15-1=14[/tex]

And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:

[tex] \chi^2 = 7.790[/tex]

And then the best answer would be:

c. 7.790

Step-by-step explanation:

For this case we know that we are using a one tailed (lower tail) critical value using a significance level of [tex]\alpha=0.1[/tex] and for this case we know that the ample size is n=15. The degrees of freedom are given by:

[tex] df =n-1= 15-1=14[/tex]

And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:

[tex] \chi^2 = 7.790[/tex]

And then the best answer would be:

c. 7.790

Answer:

Step-by-step explanation:

A graphing calculator can perform logarithmic regression, as can a spreadsheet. The least-squares best fit log curve is about ...

  y ≈ 33.7·ln(x) -45.9

The value of x estimated to make y = 5.2 is about 4.6.

Answer: probability =  0.506

Step-by-step explanation:

The data we have is:

Total people: 205 + 160 + 40 = 405

prefer cats: 205

prefer dogs: 160

neither: 40

The probability that a person chosen at random prefers cats is equal to the number of people that prefer cats divided the total number of people:

p = 205/405 = 0.506

in percent form, this is 50.6%

Answer:

n = 55/8

Step-by-step explanation:

You can solve it by cross multiplying. Where you multiply the denominator of the fraction on the left side with the numerator on the right side, and vice versa.

11/n = 8/5

n x 8 = 11 x 5

8n = 55

n = 55/8

(or 6.875)

Answer:

[tex]\boxed{\pink{n = 7 \frac{3}{8} }}[/tex]

Step-by-step explanation:

[tex] \frac{11}{n} = \frac{8}{5} \\ [/tex]

Use cross multiplication

[tex]11 \times 5 = 8 \times n \\ 55 = 8n \\ \frac{55}{8} = \frac{8n}{8} \\ n = 7 \frac{3}{8} [/tex]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

[tex]P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k![/tex]

a) The probability that exactly 3 arrivals occur during a particular hour is:

[tex]P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\[/tex]

b) The probability that at least 3 people arrive during a particular hour is:

[tex]P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938[/tex]

c) In this case, t=0.25, so we recalculate the parameter as:

[tex]\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5[/tex]

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

[tex]E(x)=\lambda=1.5[/tex]

Answer:

Correct!

Step-by-step explanation:

-5(x+8)=-25

x+8=5

x=-3

Answer:

here, -5(x+8)=-25

or, -5x +(-40)= -25

or, -5x=-25+40

or, x= 15/-5

therefore the value of x is -3....ans..

hope u understood..

Answer:

A. The mean mileage per gallon is _____ 28.99__

A. The median mileage per gallon is _____27.905_____

B. The mode does not exist.

Step-by-step explanation:

Mean= Sum of values/ No of Values

            Mean =  24.2 + 22.2+  37.8+ 22.7 + 35.4 +31.61/ 6

           Mean = 173.91/6= 28.985 ≅ 28.99

The median is the middle value of an ordered data which divides the data into two equal halves. For an even data the median is  the average of n/2 and n+1/2 value where n is the number of values.

Rearranging the above data

22.2 , 22.7 , 24.2 , 31.61 , 35.4, 37.8

Third and fourth values are =24.2 + 31.61 = 55.81

Average of third and fourth values is = 55.81/2= 27.905

Mode is the values which is occurs repeatedly.

In this data there is no mode.

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

[tex](1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)[/tex]

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

[tex](5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)[/tex]

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  [tex]=\dfrac{20}{36}[/tex]

The probability distribution of this event is given as follows.

[tex]\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|[/tex]

First, we determine the expected Value of this event.

Expected Value

[tex]=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67[/tex]

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  [tex]=\dfrac{20}{36}[/tex]

If the game is played 100 times

Number of times expected to win

[tex]=\dfrac{20}{36} \times 100\\=56$ times[/tex]

Therefore, number of times expected to loose

= 100-56

=44 times

Answer:

f(x) = -3x + 4

Step-by-step explanation:

Step 1: Move the 9x over

3y = 12 - 9x

Step 2: Divide everything by 3

y = 4 - 3x

Step 3: Rearrange

y = -3x + 4

Step 4: Change y to f(x)

f(x) = -3x + 4

Answer:

1, 2.2, 5.5, 10.2.

Step-by-step explanation: these are simplified to the nearest tenth

Answer:

a) 77.3-73/10.7= 0.40187

b) 62.9-66.8/10.8= -0.36111

c) Kylie did relatively better

Step-by-step explanation:

Answer:

1.5

Step-by-step explanation:

6 to the log base of 6 will be one (they essentially cancel each other out, log is the opposite of exponents) and we are left with 1.5.

Answer:

B. g(x) = (x-2)^2 +1

Step-by-step explanation:

When you see this type of equation your get the variables H and K in a quadratic equation. In this case the (x-2)^2 +1  is your H. The (x-2)^2 +1 is your K.

For the H you always do the opposite so in this case instead of going to the left 2 times you go to the right 2 times (affects your x)

For the K you go up or down which in this case you go up one (affects your y)

And that's how you got your (2,1) as the center of the parabola

-Hope this helps :)

Answer:

Option C.

Step-by-step explanation:

This is a function because all of the numbers have a partner, and none of them have more than one.

                                    Example of Not a Function

Function                                Not a Function

-4 to 5                                       -4 to 5                             <

9 to 7                                       -4 to 3                              <

13 to 3                                       13 to 3                              ^

-7 to 5                                        9 to 7                               ^

                                                 -7 to 5                               ^

                                           Not a Function because of this

Answer:

  √17

Step-by-step explanation:

The Pythagorean theorem can be used for the purpose.

  hypotenuse² = base² +height²

  (√26)² = 3² +height²

  26 -9 = height²

  height = √17

The length of the other leg is √17.

Answer:

Hey there!

15/k, when k=3

15/3=5

Answer:

5

Step-by-step explanation:

its a simple as 15/3 = 5

have fun

Answer:

Length = 29 m

Width = 29 m

Step-by-step explanation:

Let x and y be the length and width of the rectangle, respectively.

The area and perimeter are given by:

[tex]A=xy\\p=116=2x+2y\\y=58-x[/tex]

Rewriting the area as a function of x:

[tex]A(x) = x(58-x)\\A(x) = 58x-x^2[/tex]

The value of x for which the derivate of the area function is zero, is the length that maximizes the area:

[tex]A(x) = 58x-x^2\\\frac{dA}{dx}=0=58-2x\\ x=29\ m[/tex]

The value of y is:

[tex]y = 58-29\\y=29\ m[/tex]

Length = 29 m

Width = 29 m

Answer:

D.  4

Step-by-step explanation:

If he leaves the science assignments for the next day, he will spend zero hours on science assignments.  This means that y is equal to 0.  Plug this into the given equation and solve for x.

2x + y = 8

2x + 0 = 8

2x = 8

x = 4

Gerald can complete 4 math assignments.

Answer:

One solution

Step-by-step explanation:

99% of the time, linear equations (equations that have the first degree) have only one solution. However, it's always good to check.

6 - 3x = 12 - 6x

6 = 12 - 3x

-3x = -6

x = 2

As you can see, only one solution. Hope this helps!