SOMONE PLEASE HELP ASAP!!!!

Archimedes' principle states that a body immersed in a fluid is subjected to an upwards force equal to the weight of the displaced fluid. This is a first condition of equilibrium. We consider that the above force, called force of buoyancy, is located in the centre of the submerged hull that we call centre of buoyancy.

Answer:

Amphere's law state that the sum of over element of the component of magnetic field along the direction of the element, times the element length,is proportional to the current that passes through the loop:This is the general statement of Amphere's law.

Answer:

C

Explanation:

Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes, and 4 seconds with respect to other, distant, stars. Earth's rotation is slowing slightly with time; thus, a day was shorter in the past. This is due to the tidal effects the Moon has on Earth's rotation.

Answer: the answer is b.

ps: the other answer is wrong, the earth rotates around the sun, and the sun doesn't rotate around the earth.

Explanation:

Answer:

The time period of the empty car will be "1.00 s".

Explanation:

The given values in the question will be:

Mass,

m = 250 kg

Loaded car's time period will be:

T = 1.08 s

Shock absorbers compression,

x = 4 cm

or,

  = 0.04 m

Now,

Weight of passengers will be:

⇒  [tex]F=mg[/tex]

         [tex]=250\times 9.8[/tex]

         [tex]=2450 \ N[/tex]

The spring constant of shock absorbers will be:

⇒  [tex]k=\frac{F}{x}[/tex]

        [tex]=\frac{2450}{0.04}[/tex]

        [tex]=61.250 \ N/m[/tex]

As we know,

Time period, [tex]T = 2 \pi\sqrt{\frac{M}{k} }[/tex]

On substituting the values, we get

                   [tex]1.08=2\pi \sqrt{\frac{M}{61250} }[/tex]

                  [tex]\frac{M}{61250}=0.02955[/tex]

                      [tex]M=0.02955\times 61250[/tex]

                           [tex]=1809.6 \ kg[/tex] (Total mass of car as well as its passengers)

Now,

The mass of the empty car will be:

⇒  [tex]m'=M-m[/tex]

          [tex]=1809.6-250[/tex]

          [tex]=1559.6 \ kg[/tex]

hence,

The time period of empty car will be:

⇒  [tex]T'=2\pi\sqrt{\frac{m'}{k} }[/tex]

         [tex]=2\pi\sqrt{\frac{1559.6}{61250} }[/tex]

         [tex]=2\pi \sqrt{0.0254}[/tex]

         [tex]=1.003 \ s[/tex]

or,

         [tex]=1.00 \ s[/tex]

Answer:

most common energy transformations is the transformation between potential energy and kinetic energy. In waterfalls such as Niagara Falls, potential energy is transformed to kinetic energy. The water at the top of the falls has gravitational potential energy. As the water plunges, its velocity increases.

Explanation:

Hope this helps you

( I got this from transformation and conservation article)

Answer:

[tex]3.5\:\mathrm{m/s^2}[/tex]

Explanation:

Newton's 2nd law is given as [tex]\Sigma F = ma[/tex].

To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.

Using trigonometry to find the horizontal component of the force:

[tex]\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}[/tex]

Use this horizontal component of the force to solve for for the acceleration of the object:

[tex]\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}[/tex]

Answer:

e. 4 rad/s

Explanation:

The maximum amount of angular velocity that can be reached by the disk can be found using the following formula:

[tex]v = r\omega\\\\\omega = \frac{v}{r}[/tex]

where,

ω = maximum angular velocity = ?

v = linear speed = 5 m/s

r = radius of disc = 1.5 m

Therefore,

[tex]\omega = \frac{5\ m/s}{1.5\ m} \\\\\omega = 3.33\ rad/s[/tex]

Therefore, the angular speed can be lower than this value due to frictional losses, but it can not exceed this value in the given linear speed limit of 5 m/s.

Hence, the correct option is:

e. 4 rad/s

Answer:

28.1 degrees

Explanation:

Use formula: [tex]N_1Sin(Angle_1) = N_2Sin(Angle_2)[/tex]

* use angles given

Answer:

Negative

Explanation:

Answer:

The magnitude of the electrostatic force on [tex]\mathrm{+32\,\mu C}[/tex] is:   [tex]\mathbf{12\;N}[/tex]

Explanation:

Consider

The sum of all horizontal forces on [tex]q_1[/tex] is given as

  [tex]\sum F_x=F_{12}+F_{13}[/tex]

where

The force on [tex]q_1[/tex] exerted by [tex]q_2[/tex] is repulsive, so the direction of the force [tex]F_{12}[/tex] is to the left (negative direction). Thus

  [tex]F_{12}=-\frac{K\,|q_1|\,|q_2|}{r_{12}^2}\\F_{12}=-\frac{K\,|q_1|\,|q_2|}{(x_2\;-\;x_1)^2}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,|+32\;\mu C|\,|+20\;\mu C|}{(40\;cm\;-\;0\;cm)^2}}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,(32\;\mu C)\,(20\;\mu C)}{(40\;cm)^2}}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,(32\times10^{-6}\;C)\,(20\times10^{-6}\;C)}{(0.40\;m)^2}}\\F_{12}=\mathrm{-36\;N}[/tex]

The force on [tex]q_1[/tex] exerted by [tex]q_3[/tex] is attractive, so the direction of the force [tex]F_{13}[/tex] is to the right (positive direction). Thus

  [tex]F_{13}=+\frac{K\,|q_1|\,|q_3|}{r_{13}^2}\\F_{13}=+\frac{K\,|q_1|\,|q_3|}{(x_3\;-\;x_1)^2}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,|+32\;\mu C|\,|-60\;\mu C|}{(60\;cm\;-\;0\;cm)^2}}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,(32\;\mu C)\,(60\;\mu C)}{(60\;cm)^2}}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,(32\times10^{-6}\;C)\,(60\times10^{-6}\;C)}{(0.60\;m)^2}}\\F_{13}=\mathrm{+48\;N}[/tex]

Therefore

  [tex]\sum F_x=\mathrm{-36\;N+48\;N} \;\;\;\;\;\Rightarrow\;\;\;\;\; \mathbf{\sum F_x=+12\;N}[/tex]

the electrostatic force on [tex]q_1[/tex] is to the right and has a magnitude of [tex]\mathbf{12\;N}[/tex]

Answer:

S = (√(ε₀/μ₀)(Eo²Sin²(kx- ωt)i

Explanation:

The instantaneous energy of the wave is given by the Poynting vector, S = 1/μ₀(E × B) where μ₀ = permeability of free space

So, substituting the variables into the equation with E= EoSin(kx- ωt)j and B= BoSin (kx- ωt)k

So,  S = 1/μ₀(E × B)

S = 1/μ₀(EoSin(kx- ωt)j × BoSin (kx- ωt)k)

S = 1/μ₀(EoSin(kx- ωt) × BoSin (kx- ωt) (j × k)

S = 1/μ₀(EoBoSin²(kx- ωt)i  (i = j × k)

Now,

Eo/Bo = c where c = speed of light

So, Bo = Eo/c

Thus

S = 1/μ₀(EoBoSin²(kx- ωt)i

S = 1/μ₀(Eo(Eo/c)Sin²(kx- ωt)i

S = 1/cμ₀(Eo²Sin²(kx- ωt)i

Also,c = 1/√μ₀ε₀ where ε₀ =permittivity of free space

So,

S = 1/cμ₀(Eo²Sin²(kx- ωt)i

S = 1/(1/√μ₀ε₀)μ₀(Eo²Sin²(kx- ωt)i

S = 1/(1/√(ε₀/μ₀)(Eo²Sin²(kx- ωt)i

S = (√(ε₀/μ₀)(Eo²Sin²(kx- ωt)i

which is the instantaneous energy in the electric field.

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a               (1)

m₂g - T = m₂a    (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

Answer:

was possible, using an experimental aircraft," said Håvard Grip, Ingenuity’s chief pilot at NASA's Jet Propulsion Laboratory in Southern California. "With Ingenuity, we're trying to do the same for Mars."

Here are six things you should know about the first helicopter going to another planet:

1. Ingenuity is a flight test.

Ingenuity is what is known as a technology demonstration – a project that seeks to test a new capability for the first time, with limited scope. Previous groundbreaking technology demonstrations include the Mars Pathfinder rover Sojourner and the tiny Mars Cube One (MarCO) CubeSats that flew by Mars in 2018.

Ingenuity features four specially made carbon-fiber blades, arranged into two rotors that spin in opposite directions at around 2,400 rpm – many times faster than a passenger helicopter on Earth. It also has innovative solar cells, batteries, and other components. Ingenuity doesn't carry science instruments and is a separate experiment from the Mars 2020 Perseverance rover.

2. Ingenuity will be the first aircraft to attempt controlled flight on another planet.

NASA's Ingenuity Mars Helicopter will make history's first attempt at powered flight on another planet next spring. It is riding with the agency's next mission to Mars (the Mars 2020 Perseverance rover) as it launches from Cape Canaveral Air Force Station later this summer. Perseverance, with Ingenuity attached to its belly, will land on Mars February 18, 2021.

Credits: NASA/JPL-Caltech

What makes it hard for a helicopter to fly on Mars? For one thing, Mars' thin atmosphere makes it difficult to achieve enough lift. Because the Mars atmosphere is 99% less dense than Earth's, Ingenuity has to be light, with rotor blades that are much larger and spin much faster than what would be required for a helicopter of Ingenuity's mass on Earth.

It can also be bone-chillingly cold at Jezero Crater, where Perseverance will land with Ingenuity attached to its belly in February 2021. Nights there dip down to minus 130 degrees Fahrenheit (minus 90 degrees Celsius). While Ingenuity's team on Earth has tested the helicopter at Martian temperatures and believes it should work on Mars as intended, the cold will push the design limits of many of Ingenuity's parts.

In addition, flight controllers at JPL won't be able to control the helicopter with a joystick. Communication delays are an inherent part of working with spacecraft across interplanetary distances. Commands will need to be sent well in advance, with engineering data coming back from the spacecraft long after each flight takes place. In the meantime, Ingenuity will have a lot of autonomy to make its own decisions about how to fly to a waypoint and keep itself warm.

3. Ingenuity is a fitting name for a robot that is the result of extreme creativity.

High school student Vaneeza Rupani of Northport, Alabama, originally submitted the name Ingenuity for the Mars 2020 rover, before it was named Perseverance, but NASA officials recognized the submission as a terrific name for the helicopter, given how much creative thinking the team employed to get the mission off the ground.

"The ingenuity and brilliance of people working hard to overcome the challenges of interplanetary travel are what allow us all to experience the wonders of space exploration," Rupani wrote. "Ingenuity is what allows people to accomplish amazing things."

NASA's Mars 2020 Perseverance rover and NASA's Ingenuity Mars Helicopter (shown in an artist's concept)

In February 2021, NASA's Mars 2020 Perseverance rover and NASA's Ingenuity Mars Helicopter (shown in an artist's concept) will be the agency's two newest explorers on Mars. Both were named by students as part of an essay contest.

Credits: NASA/JPL-Caltech

Full image and caption

4. Ingenuity has already demonstrated feats of engineering.

In careful steps from 2014 to 2019, engineers at JPL demonstrated that it was possible to build an aircraft that was lightweight, able to generate enough lift in Mars' thin atmosphere, and capable of surviving in a Mars-like environment. They tested progressively more advanced models in special space simulators at JPL. In January 2019, the actual helicopter that is riding with Perseverance to the Red Planet passed its final flight evaluation. Failing any one of these milestones would've grounded the experiment.

5. The Ingenuity team will count success one step at a time.

Given the firsts Ingenuity is trying to accomplish, the team has a long list of milestones they'll need to pass before the helicopter can take off and land in the spring of 2021. The team will celebrate each time they meet one. The milestones include:

Answer: 63 m/s

Explanation: If wheel drops vertically, you can use

conservation of energy : Ep = Ek.  mgh = ½mv^2  and

solve v = √(2gh ) = √ (2·9.81 m/s²·200 m) = 62.6 m/s.

NOTE: wheel has also horizontal speed which was not mentioned here.

Answer:

Electromagnetic waves differ in their wavelengths and frequencies. The higher the frequency of an electromagnetic wave, the greater its energy. The speed of an electromagnetic wave is the product of its wavelength and frequency, so a wave with a shorter wavelength has a higher frequency, and vice versa.

Explanation:

Answer:

The correct answer will be:

(a) 27.3 m/s

(b) 3.8 s

Explanation:

According to the question:

Acceleration,

[tex]a= 4.2 \ m/s^2[/tex]

Time,

[tex]t = 6.5 \ s[/tex]

(a)

The gazelles top speed will be:

⇒  [tex]V_{max} = at[/tex]

             [tex]=4.2\times 6.5[/tex]

             [tex]=27.3 \ m/s[/tex]

or,

             [tex]= 27 \ m/s[/tex]

(b)

As we know,

s = 30 m

Now,

⇒  [tex]s = \frac{1}{2} at^2[/tex]

or,

⇒  [tex]t=\sqrt{\frac{2s}{a} }[/tex]

On putting the given values, we get

       [tex]=\sqrt{\frac{2\times 30}{4.2} }[/tex]

       [tex]=\sqrt{\frac{60}{4.2} }[/tex]

       [tex]=3.78 \ s[/tex]

or,

       [tex]=3.8 \ s[/tex]

Answer:

126000 J

Explanation:

Applying,

Q = cm(t₂-t₁).................. Equation 1

Where Q = Amount of heat, c = specifc heat capacity of water, m = mass of water, t₁ = Initial temperature, t₂ = Final temperature.

From the question,

Given: m = 2 kg, t₁ = 25°C, t₂ = 40°C

Constant: c = 4200 J/kg.°C

Substitute these value into equation 1

Q = 2×4200(40-25)

Q = 2×4200×15

Q = 126000 J

Answer:

0.027 N

Explanation:

From the question,

According to Archimedes principle,

The buoyancy force on the material = weight of oil displaced by the solid cube = Upthrust on the solid cube.

Applying,

U =ρ×V×g................ Equation 1

Where U = Upthrust on the solid cube, ρ = density of oil, V = Volume of the solid cube, g = acceleration due to gravity

But,

V = l³................ Equation 2

Substitute equation 2 into equation 1

U = gρl³.............. Equation 3

Given: ρ = 820 kg/m³, l = 1.50 cm = 0.015 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

U = 820×0.015³×9.8

U = 0.027 N

Answer:

3243q534w6ea5346w73sya53647w

Explanation:

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and [tex]$a=\frac{v^2}{r}$[/tex]

Substituting these values in the second law of Newton,

[tex]$qvB=\frac{mv^2}{r}$[/tex]

Now solving for B, we get:

[tex]$B = \frac{mv}{rq}$[/tex]

  [tex]$=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$[/tex]

 = 0.261 T

The field strength can be obtained by using the technology of today.

Answer:

Explanation:

From the information given:

The half-life [tex]t_{1/2}[/tex] = 1.6103 years

The no. of the initial nuclei [tex]N_o[/tex] = [tex]4.00 \times 10^6[/tex]

Using the formula:

[tex]N = N_o exp(-\lambda t)[/tex]

where;

decay constant [tex]\lambda = \dfrac{In2}{1.6*10^3} y^{-1}[/tex]

∴

[tex]N = N_o exp ( \dfrac{-In2}{1.6*10^3}\times 4.4 \times 10^3)[/tex]

[tex]N = N_o exp (- 1.906154747)[/tex]

The number of radium nuclei N = 5.94 × 10¹⁵

The initial activity[tex]A_o = \lambda N_o[/tex]

[tex]A_o =(\dfrac{In (2)}{1.61\times 10^3 \times 365 \times 24 \times 3600}\times 4.00 \times 10^{16})[/tex]

[tex]A_o =546075.8487 \ Bq[/tex]

Since;

1 curie = 3.7 × 10¹⁰ Bq

Then;

[tex]A_o =\dfrac{546075.8487 }{3.7\times 10^{10}}[/tex]

[tex]A_o = 1.47588 \times 10^{-5}Ci[/tex]

[tex]A_o = 14.7588 \ \mu Ci[/tex]

c) The activity at a later time is:

[tex]=5.94 \times 10^{15}( \dfrac{In (2)}{1.60 \times 10^3 \times 365\times 24 \times 3600})[/tex]

[tex]= 81599.09018 \ Bq \\ \\ = \dfrac{81599.09018}{3.7\times 10^{10}} \ Ci \\ \\ = 2.20538 \times 10^6 \ Ci \\ \\ = 2.20538 \ \mu Ci[/tex]

Answer:

v = fy

speed is equal to frequency × wavelength

5 × 2

[tex]10m.s^{ - 1} [/tex]

Answer:

Explanation:

The wave of light is being reflected two times while going from lower to higher refractive index mediums

So there will be phase reversal two times .

Condition of destructive index

2 μ t = ( 2m+1) λ / 2

Substituting the values

2 x 1.25 x t = ( 2 x 3 + 1 ) x 600nm / 2

2.5 t = 2100 nm

t = 840 nm .

Answer:

We can say that when we multiply both the force given by the two body and along with the distinct lengths they are situated from centre of mass (fulcrum) will be the same

So the let the distance seperated from the centre of mass on the right side where the boy sits be x

so 60×3 = 45x

=> x = (180/45)

=> x = 4 metres

Hope it helps

Answer:

The answer is "[tex]55.05 \ \frac{J}{K}[/tex]"

Explanation:

Given value:

[tex]Q_m=4.184 \times 10^3 \ J\\T_0=100^{\circ}\\T_1=24^{\circ}[/tex]

Calculating the heat capacity of this chunk of metal:

Using formula:

[tex]C_m=\frac{Q_m}{T_0-T_1}\\[/tex]  

      [tex]=\frac{4.184 \times 10^3}{100 -24}\\\\=\frac{4.184 \times 10^3}{76}\\\\=55.05 \ \frac{J}{K}[/tex]

Answer: The first box is 1.47

The second box is 1.323

Explanation:

The potential energy of the pendulum bob at position B is 1.323 J.

Potential energy is the energy a body has by virtue of its position or state above the ground.

The mass of the bob = 0.3 kg

height above the ground = 0.45 m

acceleration due to gravity, g = 9.8 m/s^2

Potential energy = 0.3 × 0.45 × 9.8 = 1.323 J

Therefore, the potential energy of the pendulum bob at position B is 1.323 J.

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Answer:

less energy is needed to heat the house

the roof is a better insulator

The correct advantage of having a roof with a lower thermal conductivity is Less energy is needed to heat the house. The correct answer is option 1.

A roof with lower thermal conductivity acts as a better insulator, reducing heat transfer between the interior and exterior of the house. This means that during colder months, less heat escapes through the roof, requiring less energy to maintain a comfortable temperature indoors. Additionally, a roof with lower thermal conductivity will help regulate indoor temperatures more effectively, making it a better insulator against external weather conditions. It does not directly affect the likelihood of roof leaks or increase the rate of energy transfer by conduction. Option 1 is correct.

To know more about thermal conductivity, here

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--The complete Question is, What are the advantages of having a roof with a lower thermal conductivity?

Which of the following two is correct

1. Less energy is needed to heat the house

2. The roof is a better insulator

3. The roof is less likely to leak

4. The rate of energy transfer by conduction is greater

5. Weather will have a greater effect on the temperature of the house. --