someone help i will give branliest:)

Answer:

3.45E24

Explanation:

calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho

Answer: Molar mass of [tex]NH_3[/tex] is 17.00 g and moles in 50.0 grams is 2.94.

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

Atomic Mass of Nitrogen (N) = 14.00 g

Atomic Mass of Hydrogen (H) = 1.00 g

Molar mass of [tex]NH_3[/tex] = 1(14.00)+3(1.00) g = 17.00 g

According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles and weigh equal to its molecular mass.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{Number of moles of }NH_3==\frac{50.0g}{17.00g/mol}=2.94moles[/tex]

Answer:

MgS + KI = K2S + MgI2

Answer:

yes correct salt hardens soap

Answer:

stress

Explanation:

people cn get stressed and not want to do work

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =[tex]\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9[/tex]

[tex]8.2^0C=1\times K_f\times 1.9[/tex]

[tex]K_f=4.32^0C/m[/tex]

Now Depression in freezing point for sodium chloride is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=20.0^0C[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant  

m= molality = [tex]\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45[/tex]

[tex]20.0^0C=i\times 4.32^0C\times 2.45[/tex]

[tex]i=1.9[/tex]

Thus vant hoff factor for sodium chloride in X is 1.9

Answer:

Explanation:

It processes the environment and sends out signals.

Answer:

resources that you can use more than 1 time like rechargeable battery or solar energy

Explanation:

Answer:

[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]

Explanation:

In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.

Self-condensation:

Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.

Cross-condensation:

Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.

[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]

Answer:

partB: n=2N205

partc:17.20

Answer:

A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).

Answer:

I think it would be B.

Explanation:

Answer:

A Bose-Einstein condensate or BEC in simple words is a group of atoms cooled near absolute zero.

Answer:

B. The limiting reactant determines the maximum amount of product that can be formed.

A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.

In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

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Answer:

Electrostatic smoke precipitators work by forcing dirty flue gas (the gas escaping from a smokestack) past two electrodes (electrical terminals), which take the form of metal wires, bars, or plates inside a pipe or smokestack

Explanation:

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Answer:

3 moles of NH₄Cl

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e

Xmol of NH₄Cl = –528 / –176

Xmol of NH₄Cl = 3 moles

Thus, 3 moles of NH₄Cl where obtained from the reaction.

Answer: potential energy is stored

Explanation:

[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]

_BaS + _PtF2 → _BaF2 + _Pts

Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.

=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS

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HOPE IT HELPS

PLEASE MARK ME BRAINLIEST☺️

This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answer:

The three components of a chemical formula are the empirical formula, the molecular formula, and the structural formula.Hope this answer helps.

Answer:

Option B.

Explanation:

First we convert 9.90 g of Pb(NO₃)₂ into moles, using its molar mass:

Then we convert moles of Pb(NO₃)₂ into moles of PbO, using the stoichiometric coefficients:

Now we convert 0.0299 mol PbO into grams, using its molar mass:

So 6.67 g is the theoretical yield. With that in mind we calculate the percent yield:

So the correct answer is option B.

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]

Answer: I believe it's C

Hope this helped<3

Can you please make my answer brainly

Answer:

It is 98 degrees C.

Explanation:

Answer:

your answer is C

Explanation:

because when u make P1 the subject formula then P2 V2 will be divided with V1