Answer:
Uiiikjhb+2
Explanation:
I’m gonna swinggggggf
A white light shined onto a green brick bricks science
Answer:what’s the question?
Explanation:
Which atom is oxidized in the reaction of benzhydrol with bleach?
Answer:
Which atom is oxidized in the reaction of benzhydrol with bleach?
Explanation:
n this experiment, students will perform a simple oxidation reaction of a secondary
alcohol. Recall that Oxidation Is a Loss of electrons while Reduction Is a Gain of electrons (OIL
RIG). In order to apply this mnemonic, you must know the oxidation states of each atom within
the compound, with particular interest on carbon. Carbon can carry oxidation states ranging
from -4 to +4. A few examples are shown in Figure 1 below. It is also common for carbon to
carry an oxidation state of -3, -1, +1, and +3.
Figure 1. Examples of carbon’s oxidation levels.
You may have noticed that all of the compounds in Figure 1 are neutral and carbon has
zero formal charge in each example. The concept of oxidation state and formal charge are
similar with one important difference in the calculation. Both are calculated by taking the
difference between the valence electrons (from the periodic table) and the number of electrons
belonging to that atom within the molecule. For a given atom, the valence electrons will never
change but the electrons ‘belonging’ the atom in the molecule will vary depending on number of
lone pairs and attachments to more or less electronegative atoms. The important difference in
the calculation of oxidation states and formal charge is based on the following assignment of
bonding electrons (Figure 2). This is how the highlighted carbon in ethanol can have an
oxidation state of -1 but a formal charge of zero.
- Oxidation states assign bonding electrons to the more electronegative atom in a bond,
except when the two atoms are the same and the bonding electrons are split equally.
Answer:
so the reaction would probably would be a chemical reaction
"When benzophenone reduces to diphenylmethanol, leftover products include the CH2OH and NaBH3 species. The energetic CH2OH and NaBH3 quickly bond to give (CH2OH)H3B-Na+. This complex is the main second product of benzophenone reduction."
Reactant Ratios
"In life, four benzophenone molecules react with each BH4 complex. Since four benzophenone molecules each attract a hydrogen atom from the “BH4” hydrogen donor, four “CH2OH”s bond with each boron (B) atom. Realistically, the secondary product is (CH2OH)4B-Na+ and four diphenylmethanol molecules. Focusing on one benzophenone molecule at a time is helpful for explaining and understanding reaction steps."
i hope it helps
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A reactive metal that burns with oxygen and makes a white bright light is?
sodium
iron
magnesium
copper
Answer:
it is magnesium hope it helps
2-Methyl-2-pentanol can be made starting from two different ketone electrophiles using two different Grignard reagents: one from a lower molecular mass Grignard reagent and one from a higher molecular mass Grignard reagent. Provide the retrosynthetic analysis for both routes using bromine as the halogen.
Answer:
Explanation:
In this case, we can do this by thinking a little.
Both ways use a grignard reagent, the difference between both ways is that one use an electrophile ketone with a low molecular mass, and the other has a high molecular mass.
The grignard reagent is commonly used to reduce carbonyle groups to alcohols. In the first step, a complex with the reagent is formed in the carbonile, and in the second step, the oxygen atom is hidrated in acid or basic medium and form the respective alcohol.
For the first way, we will use a high molecular mass ketone. In this case the 2-pentanone reacting with CH₃MgBr as a grignard reagent.
For the second way, we will use a low molecular mass ketone, in this case Acetone, reacting with CH₃CH₂CH₂MgBr. Both of them, will give the same product of 2 methyl-2-pentanol. See picture below for that
Hope this helps