SOMEOME PLEASE HELP ASAP ITS DUENSOON I NEED HELP!!!

SOMEOME PLEASE HELP ASAP ITS DUENSOON I NEED HELP!!!

Answers

Answer 1
The answer is C 123 ft because if you find the surface area it is 12.52 so if you round up it is 123

Related Questions

Need help with this as soon as possible.

Answers

Answer:

after 9 weeks it would become 9*1+10=19 inches

and after w weeks it will be w*1+10 inches tall

hope this helps

Step-by-step explanation:

Answer:

a) 19 inches

b) 10+w inches

Step-by-step explanation:

The equation for this problem is 10 + w.  In the first part, w = 9, so the plant is 19 inches tall.

Find the slope and y-intercept: 4x-y+6=0

Answers

Answer:

The slope is 4, and the y-intercept is 6.

Step-by-step explanation:

The equation of the line is generally written as y = mx + b.

Where m is the slope, and b is the y-intercept.

4x - y + 6 = 0

Solve for y.

- y = 0 - 4x - 6

y = -1(-4x - 6)

y = 4x + 6

The slope of the line is 4, and the y-intercept of the line is 6.

Answer:

Y-intercept is (0,6). The slope is 4

Step-by-step explanation:

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than negative 0.84 and draw a sketch of the region.

Answers

Answer:

The "probability that a given score is less than negative 0.84" is  [tex] \\ P(z<-0.84) = 0.20045[/tex].

Step-by-step explanation:

From the question, we have:

The random variable is normally distributed according to a standard normal distribution, that is, a normal distribution with [tex] \\ \mu = 0[/tex] and [tex] \\ \sigma = 1[/tex].We are provided with a z-score of -0.84 or [tex] \\ z = -0.84[/tex].

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]

Where

x is the raw value coming from a normal distribution that we want to standardize.And we already know that [tex] \\ \mu[/tex] and [tex] \\ \sigma[/tex] are the mean and the standard deviation, respectively, of the normal distribution.

A z-score represents the distance from [tex] \\ \mu[/tex] in standard deviations units. When the value for z is negative, it "tells us" that the raw score is below [tex] \\ \mu[/tex]. Conversely, when the z-score is positive, the standardized raw score, x, is above the mean, [tex] \\ \mu[/tex].

Solving the question

We already know that [tex] \\ z = -0.84[/tex] or that the standardized value for a raw score, x, is below [tex] \\ \mu[/tex] in 0.84 standard deviations.

The values for probabilities of the standard normal distribution are tabulated in the standard normal table, which is available in Statistics books or on the Internet and is generally in cumulative probabilities from negative infinity, - [tex] \\ \infty[/tex], to the z-score of interest.

Well, to solve the question, we need to consult the standard normal table for [tex] \\ z = -0.84[/tex]. For this:

Find the cumulative standard normal table.In the first column of the table, use -0.8 as an entry.Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)The intersection of these two numbers "gives us" the cumulative probability for z or [tex] \\ P(z<-0.84)[/tex].

Therefore, we obtain [tex] \\ P(z<-0.84) = 0.20045[/tex] for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the standard normal distribution, [tex] \\ N(0,1)[/tex], at the left of z = -0.84.

To "draw a sketch of the region", we need to draw a normal distribution (symmetrical bell-shaped distribution), with mean that equals 0 at the middle of the distribution, [tex] \\ \mu = 0[/tex], and a standard deviation that equals 1, [tex] \\ \sigma = 1[/tex].

Then, divide the abscissas axis (horizontal axis) into equal parts of one standard deviation from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).  

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, [tex] \\ -\sigma[/tex], from it). All the area to the left of this value must be shaded because it represents [tex] \\ P(z<-0.84) = 0.20045[/tex] and that is it.

The below graph shows the shaded area (in blue) for [tex] \\ P(z<-0.84)[/tex] for [tex] \\ N(0,1)[/tex].

Four students are working on a Math problem to find the soulution to 2x-3=11. Each student got a different answer. The four answers were 5,6,7 and 8. Which of these numbers make the equation true?

Answers

Answer:

7

Step-by-step explanation:

2x-3=11

Move the -3 to the right side by adding 3 to both sides of the equation

2x=14

Divide both sides by 2 to get x by itself

x=7

Answer:

  7

Step-by-step explanation:

2x -3 = 11

2x = 14 . . . . add 3

x = 7 . . . . . . divide by 2

The number 7 makes the equation true when substituted for x.

Subtract :2/3z-(5/6z^2-z+3/z) what is the resulting rational expression
A.3z^2+3/6z^2
B.6z^2+10/6z^2
C.3z^2+10z-8/6z^2
D.6z^2+22z-5/6z^2

Answers

Answer:

The correct answer is D

Step-by-step explanation:

i just did the assignment

Answer:

Correct answer: D

Step-by-step explanation:

just did it on edge

Which of the following (x,y) pairs is the solution for the system of equations x+2y=4 and -2x+y=7

Answers

Answer:

(-2 ,3)

Step-by-step explanation:

Step 1: Rewrite first equation

x = 4 - 2y

-2x + y = 7

Step 2: Substitution

-2(4 - 2y) + y = 7

Step 3: Solve y

-8 + 4y + y = 7

-8 + 5y = 7

5y = 15

y = 3

Step 3: Plug in y to find x

x + 2(3) = 4

x + 6 = 4

x = -2

Find the values of b and c so g(x)=6x^2+bx+c has a vertex of (7,-9).

Answers

Answer:

b = -84

c = 285

Step-by-step explanation:

Given that:

[tex]g(x)=6x^2+bx+c[/tex]

Vertex of (7, -9).

To find:

Value of b and c = ?

Solution:

It can be seen that the given equation is of a parabola.

Standard equation of a parabola is given as:

[tex]y =Ax^2+Bx+C[/tex]

x coordinate of vertex is given as:

[tex]h=\dfrac{-B}{2A}[/tex]

Here, A = 6, B = b and C = c, h = 7 and k = -9

[tex]7=\dfrac{-b}{2\times 6}\\\Rightarrow b = -84[/tex]

So, the equation of given parabola becomes:

[tex]y=6x^2-84x+c[/tex]

Now, putting the value of vertex in the equation to find c.

[tex]-9=6\times 7^2-84\times 7+c\\\Rightarrow -9=294-588+c\\\Rightarrow -9=-294+c\\\Rightarrow c = 285[/tex]

So, the answer is :

b = -84

c = 285

The weight of a box of cereal can vary by of an ounce and still be sold as a full box. Each box is supposed to contain 18 ounces of cereal. Which graph represents the possible weights of boxes that are overfilled or underfilled and cannot be sold as full boxes?

Answers

Answer:

Its B

Step-by-step explanation:

Answer:

The answer is B

Step-by-step explanation:

Its B on edge

HElp 64 points and Brainlyiest to who ever can solve the problem question on the picture
Which property was applied in this step?
Addition Property of Equality
O Subtraction Property of Equality
Multiplication Property of Equality
Division Property of Equalit

Answers

Answer:

Addition Property of Equality

Step-by-step explanation:

You are adding 3/4 to both sides to isolate the x.

PLS HELP ASAP!!!!........

Answers

Answer:

aaaaha pues

Step-by-step explanation:

Answer:

what happened

Step-by-step explanation:


An organization will give a prize to a local artist. The artist will be randomly chosen from among 11 painters, 3 sculptors, and 5 photographers. What is the
probability that the artist chosen will be a sculptor or a photographer?
Write your answer as a fraction in simplest form.

Answers

Answer: 8/19

Work Shown:

3 sculptors + 5 photographers = 8 of either

this is out of 11+3+5 = 19 artists total

the probability of getting a sculptor or photographer is 8/19

Suppose that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6. Find the 95% confidence interval of the mean score for all bowlers in this league, using the accompanying data set of 10 random scores. Round your answers to two decimal places and use ascending order. Score 86 86 93 88 98 107 93 75 89

Answers

Answer:

A 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

Step-by-step explanation:

Since in the question only 9 random scores are given, so I am performing the calculation using 9 random scores.

We are given that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6.

The accompanying data set of 9 random scores in ascending order is given as; 75, 86, 86, 88, 89, 93, 93, 98, 107

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = sample mean score = [tex]\frac{\sum X}{n}[/tex] = [tex]\frac{815}{9}[/tex] = 90.56

            [tex]\sigma[/tex] = population standard deviation = 6

            n = sample of random scores = 9

            [tex]\mu[/tex] = population mean score for all bowlers

Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\bar X-\mu}[/tex] < [tex]1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] =  [ [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]

                                          = [ [tex]90.56-1.96 \times {\frac{6}{\sqrt{9} } }[/tex] , [tex]90.56+1.96 \times {\frac{6}{\sqrt{9} } }[/tex] ]

                                          = [86.64 , 94.48]

Therefore, a 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

what is 1% of 62 like i dont understand this

Answers

1% of 62 would be 0.62

Answer:

0.62

Step-by-step explanation:

1. We assume, that the number 62 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 62 is 100%, so we can write it down as 62=100%.

4. We know, that x is 1% of the output value, so we can write it down as x=1%.

5. Now we have two simple equations:

1) 62=100%

2) x=1%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

62/x=100%/1%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 1% of 62

62/x=100/1

(62/x)*x=(100/1)*x       - we multiply both sides of the equation by x

62=100*x       - we divide both sides of the equation by (100) to get x

62/100=x

0.62=x

x=0.62

now we have:

1% of 62=0.62

What number must you add to complete the square?
X^2 + 8x= 11
A. 12
B. 16
c. 8
D. 4​

Answers

Answer:

16

Step-by-step explanation:

X^2 + 8x= 11

Take the coefficient of x

8

Divide by 2

8/2 =4

Square it

4^2 = 16

Add 16 to each side

Vhat percent of the area underneath
this normal curve is shaded?

Answers

Answer:

99.7

be careful there is a very similar problem to this one which is the answer 95

The percentage of the shaded area underneath this normal curve is 95% because it lie within two (2) standard deviations of the mean.

What is standard deviation?

A standard deviation (or σ) is a measure of how dispersed the data is in relation to the mean. Low standard deviation means data are clustered around the mean, and high standard deviation indicates data are more spread out.

here, we have,

The 68-95-99.7 rule is also referred to as the empirical rule or the three-sigma rule and it can be defined as a shorthand which is used in statistics to determine the percentage of a population parameter that lie within an interval estimate in a normal distribution curve.

Basically, the 68-95-99.7 rule states that 68%, 95%, and 99.7% of the population parameter lie within one (1), two (2), and three (3) standard deviations of the mean respectively.

so, we get,

This ultimately implies that, the percentage of the shaded area underneath this normal curve is 95% because it lie within two (2) standard deviations of the mean.

Learn more about standard deviation here:

brainly.com/question/23907081

#SPJ7

Talk about why you think it is sometimes important to represent a procedure mathematcally. Give an example in life that a mathematcal procedure helped you solve a problem. In this procedure, what is independent quanity, what is dependent quanity?

Answers

Answer:

See Explanation

Step-by-step explanation:

Representing a procedure mathematically enables us to model life situations, solve for the unknown variables, and interpret back into the given situation for implementation.

A typical example is determining the gallons of gasoline a car would consume at a certain speed.

In this example, the independent variable is the driving speed, and the dependent variable is the gasoline consumption.

Gasoline consumption will either increase or decrease based on the speed of the car. The speed of the car is not affected by gasoline consumption.

Find the product of all positive integer values of $c$ such that $3x^2+7x+c=0$ has two real roots. I will award a lot of points

Answers

Answer:  24

Step-by-step explanation:

Let's find one solution:

3x² + 7x + c = 0

a=3 b=7  c=c

First, let's find c so that it has REAL ROOTS.

⇒ Discriminant (b² - 4ac) ≥ 0

                         7² - 4(3)c ≥ 0

                         49 - 12c ≥ 0

                               -12c  ≥ -49

                                [tex]c\leq\dfrac{-49}{-12}\quad \rightarrow c\leq \dfrac{49}{12}[/tex]      

Since c must be a positive integer, 1 ≤ c ≤ 4

Example: c = 4

3x² + 7x + 4 = 0

(3x + 4)(x + 1) = 0

x = -4/3, x = -1         Real Roots!

You need to use Quadratic Formula to solve for c = {1, 2, 3}

Valid solutions for c are: {1, 2, 3, 4)

Their product is: 1 x 2 x 3 x 4 = 24

Answer:

$3x^2+7x+c=0$

comparing above equation with ax²+bx+c

a=3

b=7

c=1

using quadratic equation formula

[tex]x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{ 2a} [/tex]

x=(-7+-√(7²-4×3×1))/(2×3)

x=(-7+-√13)/6

taking positive

x=(-7+√13)/6=

taking negative

x=(-7-√13)/6=

please i need this answer right now !!!! Dx

Answers

Answer: the answer is d sin30degrees equal 5/x because sin is opposite over hyponuese

Here are summary statistics for randomly selected weights of newborn​ girls: nequals153​, x overbarequals31.5 ​hg, sequals7.1 hg. Construct a confidence interval estimate of the mean. Use a 90​% confidence level. Are these results very different from the confidence interval 30.4 hgless thanmuless than32.8 hg with only 15 sample​ values, x overbarequals31.6 ​hg, and sequals2.7 ​hg?

Answers

Answer:

yes it is little different  from the confidence interval (30.4 ≤μ≤ 32.8) changes statistics

90% confidence interval estimate of the mean is

(30.1048 , 33.0952)

Step-by-step explanation:

Step(I):-

Given sample size 'n' = 153

Given mean of the sample x⁻ = 31.5

Sample standard deviation 'S' = 7.1 h g

90% confidence interval estimate of the mean is determined by

[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]

Degrees of freedom

ν = n-1 = 153-1 =152

t₀.₀₅ =1.9757

Step(ii)

90% confidence interval estimate of the mean is

[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]

[tex](31.5 - 1.9757 } \frac{7.1}{\sqrt{153} } , 31.5 + 1.9757 \frac{7.1}{\sqrt{153} } )[/tex]

( 31.5 - 1.1340 , 31.5 + 1.1340)

(30.366 , 32.634)

90% confidence interval estimate of the mean is

(30.4 , 32.6)

b)

Given sample size 'n' = 15

Given mean of the sample x⁻ = 31.6

Sample standard deviation 'S' = 2.7 h g

90% confidence interval estimate of the mean is determined by

[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]

Degrees of freedom

ν = n-1 = 15-1 =14

t₀.₀₅ =2.1448

90% confidence interval estimate of the mean is

[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]

[tex](31.6 - 2.1448 } \frac{2.7}{\sqrt{15} } , 31.6 + 2.1448 \frac{2.7}{\sqrt{15} } )[/tex]

( 31.6 - 1.4952 , 31.6 + 1.4952)

(30.1048 , 33.0952)

Conclusion:-

yes it is little different  from the confidence interval (30.4 ≤μ≤32.8)

Your bank balance is $102.35 and you've just made purchases for $20, $33.33, and $52.80. You then make deposits of $25 and $24.75. What's your new balance?
A. 565.77
B. 54102
C. $45.97
D. 551.22

Answers

Answer:

C

Step-by-step explanation:

102.35-20-33.33-52.80+25+24.75

45.97

C.$45.97 because $102.35 minus $20, $33.33, and $52.80 is -$3.78 but if you add $25 and $24.75 it's $45.97

If the 2412 leaves are not a random sample, but the researchers treated the 2412 leaves as a random sample, this most likely made the data more:_____________.1. accurate, but not precise2. precise, but not accurate3. neither4. both accurate and precise

Answers

Answer:

2. Precise but not accurate

Step-by-step explanation:

In a high precision, low accuracy case study, the measurements are all close to each other (high agreement between the measurements) but not near/or close to the center of the distribution (how close a measurement is to the correct value for that measurement)

F (X) = x² - 2x and 6(x) = 3x+1
A) Find F(g(-4))
B) Find F(g(x)) simply
C) find g^-1 (x)

Answers

Part A

g(x) = 3x+1

g(-4) = 3(-4)+1 ... every x replaced with -4

g(-4) = -12+1

g(-4) = -11

Plug this into the f(x) function

f(x) = x^2 - 2x

f( g(-4) ) = (g(-4))^2 - 2( g(-4) )

f( g(-4) ) = (-11)^2 - 2(-11)

f( g(-4) ) = 121 + 22

f( g(-4) ) = 143 is the answer

====================================================

Part B

Plug the g(x) function into the f(x) function

f(x) = x^2 - 2x

f( g(x) ) = ( g(x) )^2 - 2( g(x) ) ... replace every x with g(x)

f( g(x) ) = (3x+1)^2 - 2(3x+1)

f( g(x) ) = (9x^2+6x+1) + (-6x-2)

f( g(x) ) = 9x^2+6x+1-6x-2

f( g(x) ) = 9x^2-1  is the answer

Note that we can plug x = -4 into this result and we would get

f( g(x) ) = 9x^2-1

f( g(-4) ) = 9(-4)^2-1

f( g(-4) ) = 9(16)-1

f( g(-4) ) = 144-1

f( g(-4) ) = 143 which was the result from part A

====================================================

Part C

Replace g(x) with y. Then swap x and y. Afterward, solve for y to get the inverse.

[tex]g(x) = 3x+1\\\\y = 3x+1\\\\x = 3y+1\\\\3y+1 = x\\\\3y = x-1\\\\y = \frac{1}{3}(x-1)\\\\y = \frac{1}{3}x-\frac{1}{3}\\\\g^{-1}(x) = \frac{1}{3}x-\frac{1}{3}\\\\[/tex]

Make x the subject of the formula a x + 2 c = b x + 3 d

Answers

Answer:

x = (3d - 2c)/(a - b)

Step-by-step explanation:

ax + 2c = bx + 3d

ax - bx = 3d - 2c

x(a - b) = 3d - 2c

x = (3d - 2c)/(a - b)

Answer:

[tex]\boxed{x = \frac{3d-2c}{a-b}}[/tex]

Step-by-step explanation:

=> [tex]ax+2c = bx+3d[/tex]

Subtracting bx to both sides

=> [tex]ax-bx+2c= 3d[/tex]

Subtracting 2c to both sides

=> [tex]ax-bx = 3d-2c[/tex]

Taking x common

=> [tex]x(a-b) = 3d-2c[/tex]

Dividing both sides by (a-b)

=> [tex]x = \frac{3d-2c}{a-b}[/tex]

In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground spots.

Answers

Answer:

[tex] n= 1500[/tex] represent the random sample selected

[tex] X= 1188[/tex] represent the number of pots that were bare ground (no vegetation

[tex]\hat p=\frac{X}{n}[/tex]

And replacing we got:

[tex] \hat p=\frac{1188}{1500}= 0.792[/tex]

So then the sample proportion of bare ground spots is 0.792 for this sample

Step-by-step explanation:

We have the following info given from the problem:

[tex] n= 1500[/tex] represent the random sample selected

[tex] X= 1188[/tex] represent the number of pots that were bare ground (no vegetation)

And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

[tex]\hat p=\frac{X}{n}[/tex]

And replacing we got:

[tex] \hat p=\frac{1188}{1500}= 0.792[/tex]

So then the sample proportion of bare ground spots is 0.792 for this sample

(0, 3) and (-2, -1)
Write an equation in slope intercept from of the line that passes through the given points.

Answers

Answer:

y = 2x + 3

Step-by-step explanation:

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope-Intercept Form: y = mx + b

Step 1: Find slope m

m = (-1 - 3)/(-2 - 0)

m = -4/-2

m = 2

y = 2x + b

Step 2: Rewrite equation

y = 2x + 3

*You are given y-intercept (0, 3), so simply add it to your equation.

A lady buys bananas at 3 Rs 5 and sells them at 2 Rs for Rs 5; find her gain percent.​

Answers

Answer:

50%

Step-by-step explanation:

Cost of 3 bananas= Rs. 5 ⇒ cost of 1 banana= Rs. 5/3

Selling price of 2 bananas= Rs. 5 ⇒ selling price of 1 banana= Rs. 5/2

Gain= Rs. (5/2- 5/3)= Rs. (15/6- 10/6)= Rs. 5/6

Gain %= 5/6÷5/3 × 100%= 50%

Solve the system of equations for the variables: x+2y-z=3 x+y-2z= -1

Answers

Answer:

z=0

x= -5

y=4

Step-by-step explanation:

Check the attachment please

Hope this helps :)

Step-by-step explanation:

x + 2y − z = 3

x + y − 2z = -1

There are three variables but only two equations, so this system of equations is undefined.  We cannot solve for the variables, but we can eliminate one of them and reduce this to a single equation.

Double the first equation:

2x + 4y − 2z = 6

Subtract the second equation.

(2x + 4y − 2z) − (x + y − 2z) = (6) − (-1)

2x + 4y − 2z − x − y + 2z = 7

x + 3y = 7

A new landowner has a triangular piece of flat land she wishes to fence. Starting at the first corner, she measures the first side to be 5.7 m long and is directed 0.3 radians north of east. From the second corner, the second side is 9 m long and is directed 0.9 radians west of north. What is the length of the third side of the fence?

Answers

Answer:

The length of the third side of fence is 11.4 m

Step-by-step explanation:

Solution:-

- We are to mow a triangular piece of land. We are given the description of motion and the orientation of land-mower while fencing.

- From one corner of the triangular land, the land-mower travels H1 = 5.7 m at θ1 = 0.3 radians north of east. We will use trigonometric ratios to determine the amount traveled ( B1 ) in the east direction.

                                  [tex]cos ( theta_1 ) = \frac{B_1}{H_1}[/tex]

Where,

                          B1: Is the base length of the right angle triangle

                          H1: Hypotenuse of the right angle triangle

Therefore,

                                [tex]B_1 = H_1*cos ( theta_1 )\\\\B_1 = 5.7*cos ( 0.3 )\\\\B_1 = 5.44541 m[/tex]

- Similarly, from the other corner of the triangular land. The land-mower moves a lateral distance of H2 = 9m and directed θ2 = 0.9 radians north of west. We will use trigonometric ratios to determine the amount traveled ( B2 ) in the west direction.

                                [tex]cos ( theta_2 ) = \frac{B_2}{H_2} \\[/tex]

Where,

                          B2: Is the base length of the right angle triangle

                          H2: Hypotenuse of the right angle triangle

Therefore,

                                 [tex]B_2 = H_2*cos ( theta_2 )\\\\B_2 = 9*cos(0.9)\\\\B_2 = 5.59448 m[/tex]

- The total length of the third side of the fence would be the sum of bases of the two right angles formed by the land-mower motion at each corner.

                                [tex]L = B_1 + B_2\\\\L = 5.44541 + 5.59448\\\\L = 11.4 m[/tex]

Please check my answer! The faculty at a particular school have attended up to an average 4 years of college with a standard deviation of 2 years. Faculty members who are in the lower 10% of the distribution will be offered the opportunity to obtain additional training. A faculty member must have attended less than ___________ years of school to qualify for the training. Round your answer to the year. My answer: 1 – 0.10 = 0.90 0.9 - 0.5 = 0.40 z-score = 1.28 (corresponds with 0.3997) x = (1.28)(2) + 4 = 7 years (rounded)

Answers

Answer:

1 year

Step-by-step explanation:

1. Convert 10% into a z-score, using a calculator or whateva

2. Z = -1.281551 ( you can find this by doing the following equation: (x - mean) / (standard deviation)

3. Hence -1.281551 = (x - 4) / 2 or, x = 1.436898, ( rounded to the nearest year ) = 1 year

are the two triangles below similar​

Answers

Answer:

Hey!

Your answer is YES!

AKA the Last Option on your screen!

Step-by-step explanation:

It is this because...

They both have the angles 105 in it...

And looking at the other angle on the smaller one (25)

50 + 25 = 75 ... 180 - 75 = 105

WE HAVE 105 as an angle on the larger triangle...which makes them SIMILAR but congruent Angles!

It cant be the "corresponding sides" as we do not have the notations (lines intersecting the sides) that let us know that the lines are the same.

Hope this helps!

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