Answer:
C. √105
Step-by-step explanation:
105 = 3·5·7 has no square factors, so its root cannot be simplified.
√105 simplified is √105.
The dose of a drug is 0.05 mg for each kg of a patient’s weight.The Drug is available as an oral liquid containing 50 mcg/0.1 ml.Calculate the dose of the oral liquid in ml for a patient who weighs 132 lb
Answer:
6 mL
Step-by-step explanation:
It is a matter of units conversion.
volume = (mass) × (dose/mass) ÷ (dose/volume)
(132 lb)/(2.2 kg/lb) × (0.05 mg/kg) / (0.05 mg/0.1 mL) = 6 mL
If Brooklyn College students have an IQ of 100, on average, with a standard deviation of 16 points, and I collect 48 BC Psychology students to see how Psych majors compare to all of BC, find the following:_______.
1. mu =
2. sigma =
3. mu _x bar =
4. sigma _x bar =
Answer:
1 [tex]\mu = 100[/tex]
2 [tex]\sigma = 16[/tex]
3 [tex]\mu_x = 100[/tex]
4 [tex]\sigma _{\= x } = 2.309[/tex]
Step-by-step explanation:
From the question
The population mean is [tex]\mu = 100[/tex]
The standard deviation is [tex]\sigma = 16[/tex]
The sample mean is [tex]\mu_x = 100[/tex]
The sample size is [tex]n = 48[/tex]
The mean standard deviation is [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]\sigma _{\= x } = \frac{16 }{\sqrt{48} }[/tex]
[tex]\sigma _{\= x } = 2.309[/tex]
the bus fare in a city is $2.00. people who use the bus have the option of purchashing a monthly coupoun book is $20.00. with the copoun bok, the fare is reduced to $1.00 Determine the number of times in a month the bus be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book
Answer:
but I can do it if you want but I don't you too too y u your help and you have time can you
Step-by-step explanation:
guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house
A consultant wants to ask workers at a factory about the workers' job satisfaction. Which of the following best describes a cluster sample of workers?
a. The consultant takes a list of the workers and selects every 6" worker until 60 workers are selected.
b. The consultant forms 5 groups of workers based on the workers' shifts. Then, he selects 12 workers at random from each group.
c. The consultant forms groups of 12 workers based on the lengths of time the workers have worked at the factory. Then, he randomly chooses 5 groups and selects all of the workers in these groups
Answer:
i think option c must be correct because it has formed the grops on the basis of length of time and made the group by random selection.
A statistics tutor wants to assess whether her remedial tutoring has been effective for her five students. She decides to conduct a related samples t-test and records the following grades for students prior to and after receiving her tutoring.
Tutoring
Before After
2.4 3.1
2.5 2.8
3.0 3.6
2.9 3.2
2.7 3.5
Test whether or not her tutoring is effective at a 0.05 level of significance. State the value of the test statistic. (Round your answer to three decimal places.)
t =
Compute effect size using estimated Cohen's d. (Round your answer to two decimal places.)
d =
Answer:
The test statistic value is, t = -5.245.
The effect size using estimated Cohen's d is 2.35.
Step-by-step explanation:
A paired t-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.
The hypothesis can be defined as follows:
H₀: The remedial tutoring has not been effective, i.e. d = 0.
Hₐ: The remedial tutoring has been effective, i.e. d > 0.
Use Excel to perform the Paired t test.
Go to Data → Data Analysis → t-test: Paired Two Sample Means
A dialog box will open.
Select the values of the variables accordingly.
The Excel output is attached below.
The test statistic value is, t = -5.245.
Compute the effect size using estimated Cohen's d as follows:
[tex]\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}[/tex]
[tex]=\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35[/tex]
Thus, the effect size using estimated Cohen's d is 2.35.
Find the value of s(t(-2)):
s(x)= - 3x-2
t(x)=5x-4
P-value test and Ctitical Value test are identical. P-value and Critical value are two different names for the same steps. They can be used interchangeably.
a. true
b. false
Answer:
Option B - False
Step-by-step explanation:
Critical value is a point beyond which we normally reject the null hypothesis. Whereas, P-value is defined as the probability to the right of respective statistic which could either be Z, T or chi. Now, the benefit of using p-value is that it calculates a probability estimate which we will be able to test at any level of significance by comparing the probability directly with the significance level.
For example, let's assume that the Z-value for a particular experiment is 1.67, which will be greater than the critical value at 5% which will be 1.64. Thus, if we want to check for a different significance level of 1%, we will need to calculate a new critical value.
Whereas, if we calculate the p-value for say 1.67, it will give a value of about 0.047. This p-value can be used to reject the hypothesis at 5% significance level since 0.047 < 0.05. But with a significance level of 1%, the hypothesis can be accepted since 0.047 > 0.01.
Thus, it's clear critical values are different from P-values and they can't be used interchangeably.
Construct 3 linear equation starting with qiven solution z = 1/3
Answer:
(a)[tex]9z+2=5[/tex]
(b)[tex]21z-11=-4[/tex]
(c)[tex]4z=2-2z[/tex]
Step-by-step explanation:
We are required to construct 3 linear equations starting with the given solution z = 1/3.
Equation 1
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 9
[tex]9z=\frac{1}{3}\times 9\\9z=3[/tex]
Rewrite 3 as 5-2
9z=5-2
Add 2 to both sides
Our first equation is: [tex]9z+2=5[/tex]
Equation 2
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 21
[tex]21z=\frac{1}{3}\times 21\\21z=7[/tex]
Rewrite 7 as 11-4
21z=11-4
Subtract 11 from both sides
Our second equation is: [tex]21z-11=-4[/tex]
Equation 3
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 6
[tex]6z=\frac{1}{3}\times 6\\6z=2[/tex]
Rewrite 6z as 4z+2z
4z+2z=2
Subtract 2z from both sides
Our third equation is: [tex]4z=2-2z[/tex]
An efficiency expert hired by a manufacturing firm has compiled these data relating workers output to their experience:
Experience t (months) 0 3
Output Q (units per hour) 200 190
Suppose output Q Is related to experience t by a function of the form Q (t) = 300 - A e^-kt. Find the function of this form that fits the data.
Answer:
Q(t) = 300 - 100e^0.0318tStep-by-step explanation:
Given the relationship between the output as related to the experience t to be Q (t) = 300 - A e^-kt.
From the table, at t = 0, Q(t) = 200, substituting this into he equation to get A we have:
200 = 300 - A e^-k(0).
200 = 300 - A e^-0
200 = 300 - A
A = 300-200
A = 100
Secondly we need to get the constant k by substituting the other condition into the equation. When t = 3, Q(t) = 190
190 = 300 - A e^-k(3)
190 = 300 - 100e^-3k
190-300 = -100e^-3k
-110 = -100e^-3k
e^-3k = -110/-100
e^-3k = 1.1
Taking the natural logarithm of both sides we have;
ln(e^-3k) = ln1.1
-3k = 0.09531
k = 0.09531/-3
k = -0.0318
The function of this form that fits the data can be gotten by substituting A = 100 and k = -0.0318 into the modeled equation given as shown:
Q(t) = 300 - A e^-kt
Q(t) = 300 - 100e^-(-0.0318)t
Q(t) = 300 - 100e^0.0318t
A school is 16km due west of a school q.
What is the bearing of q from p?
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
Pls help me help me
Answer:
C.
Step-by-step explanation:
When two lines are parallel, their slopes are the same.
Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.
The answer is C.
Answer:
C. 2/7
Step-by-step explanation:
Parallel lines are lines that have the same slopes.
We know that line l is parallel to line m.
Therefore, the slope of line l is equal to the slope of line m.
[tex]m_{l} =m_{m}[/tex]
We know that line l has a slope of 2/7.
[tex]\frac{2}{7} =m_{m}[/tex]
So, line m also has a slope of 2/7. The answer is C. 2/7
What is the distance between (−11, −20) and (−11, 5)?
−25 units
−15 units
15 units
25 units
Answer:
IT'S NOT -15 FOR SUREEE
Step-by-step explanation:
I Believe it's 15
A(2,9), B(4,k), and C(9, -12) are 3 collinear points.
Find the value of k.
==========================================================
Explanation:
We're going to be using the slope formula a bunch of times.
Find the slope of the line through points A and C
m = (y2 - y1)/(x2 - x1)
m = (-12-9)/(9-2)
m = -21/7
m = -3
The slope of line AC is -3. The slopes of line AB and line BC must also be the same for points A,B,C to be collinear. The term collinear means all three points fall on the same straight line.
-------
Let's find the expression for the slope of line AB in terms of k
m = (y2 - y1)/(x2 - x1)
m = (k-9)/(4-2)
m = (k-9)/2
Set this equal to the desired slope -3 and solve for k
(k-9)/2 = -3
k-9 = 2*(-3) ..... multiply both sides by 2
k-9 = -6
k = -6+9 .... add 9 to both sides
k = 3
If k = 3, then B(4,k) updates to B(4,3)
-------
Let's find the slope of the line through A(2,9) and B(4,3)
m = (y2 - y1)/(x2 - x1)
m = (3-9)/(4-2)
m = -6/2
m = -3 we get the proper slope value
Finally let's check to see if line BC also has slope -3
m = (y2 - y1)/(x2 - x1)
m = (-12-3)/(9-4)
m = -15/5
m = -3 we get the same value as well
Since we have found lines AB, BC and AC all have slope -3, we have proven that A,B,C fall on the same straight line. Therefore, this shows A,B,C are collinear.
Vance ate a salad and Four-fifths of a turkey burger for dinner. The salad contained 80 calories and his entire meal contained 440 calories. Which equation can be used to determine x, the number of calories in the entire turkey burger?
The correct answer is A. 440 = [tex]\frac{4}{5}[/tex] x + 80
Explanation:
In mathematics, equations are often used to find an unknown value. Additionally, equations display two mathematical expressions that have an equality relation, and based on this equality the unknown value can be found. Moreover, if you need to write an equation it is important to include all the important values, and understand the relationship between them because this determines the mathematical signs that need to be used.
In the case presented, it is known the total of the calories for the burger and salad is 440. Because of this, the mathematical expression on one side should be 440. Additionally, on the other side, it is necessary to include the calories of the salad (80) plus the calories of the burger. However, because you know Vance ate only 4/5 of the burger and the value of the burger is not known the correct expression for this section is [tex]\frac{4}{5}[/tex] x as x represents the unknown value. Thus, the correct equation is "440 = [tex]\frac{4}{5}[/tex] x + 80"
Answer:
The correct answer is A. 440 = 4/5x + 80
Assume that T is a linear transformation. Find the standard matrix of T:R2→R2T:R 2→R 2 first rotates points through −3π/4−3π/4 radian (clockwise) and then reflects points through the horizontal x1x 1-axis.
Answer:
An object balances itself when a perpendicular line drawn through its Centre of Gravity (CG), passes through its base.
See the picture of a popular toy given below. The horse, the rider and the ball are all joined together as one single unit. This entire unit is balanced on the thin black rod shown. At which of the indicated positions, could the Centre of Gravity (CG) of the horse, rider and ball unit be?
July 10 book Science up55 down8
AA BB
CC DD
Step-by-step explanation:
Mrs. Lang is 4 times as old as her daughter Jill. The sum of their ages is 60 years. Set up the two equations that can be used to find each of their ages. Constraint 1: The solution must satisfy the ratio of their ages. Constraint 2: The solution must satisfy the sum of their ages. Only constraint would be met if Mrs. Lang is 32 and Jill is 8. Only constraint would be met if Mrs. Lang is 45 and Jill is 15.
Answer:
The two equations that can be used to find each of their ages are [tex]x=4 \times y[/tex] and [tex]x+y=60[/tex] .
Step-by-step explanation:
We are given that Mrs. Lang is 4 times as old as her daughter Jill. The sum of their ages is 60 years.
Let the age of Mrs. Lang be 'x years' and the age of her daughter Jill be 'y years'.
Now, according to the question;
The first condition states that Mrs. Lang is 4 times as old as her daughter Jill, that means;[tex]x=4 \times y[/tex] ----------------- [equation 1]
The second condition states that the sum of their ages is 60 years, that means;[tex]x+y=60[/tex]
[tex]4y + y = 60[/tex] {using equation 1}
[tex]5y=60[/tex]
[tex]y=\frac{60}{5}[/tex]
y = 12 years
Now, putting the value of y in equation 1 we get;
[tex]x=4 \times y[/tex]
[tex]x= 4 \times 12[/tex] = 48 years
Hence, the age of Mrs. Lang is 48 years and her daughter Jill is 12 years old.
Answer:
Mrs. Lang is 48 and her daughter is 12 years old.
Step-by-step explanation:
What is the equation of the line that is parallel to the given line and passes through the point (12, -2)? A) y = -6/5x + 10 B) y= -6/5x + 12 C) y = -5/6x -10 D) y = 5/6x - 12
Answer:
D
Step-by-step explanation:
Parallel lines are those that have the same slope, or coefficient of x.
Here, let's calculate the slope of the given line. Slope is the difference in the y-coordinates divided by the difference in the x-coordinates, so given the two coordinates (12, 6) and (0, -4):
slope = m = (-4 - 6) / (0 - 12) = -10 / (-12) = 10/12 = 5/6
So the slope is 5/6. That means the equation we want should also have a slope of 5/6. Already, we can eliminate A, B, and C, leaving D as our answer. But, let's check.
The equation of a line can be written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is the coordinates of a given point.
Here, our slope is 5/6 and our given point is (12, -2). So plug these in:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-(-2)=(5/6)(x-12)[/tex]
[tex]y+2=\frac{5}{6} x-10[/tex]
[tex]y=\frac{5}{6} x-12[/tex]
This matches D, so we know that it's the correct answer.
~ an aesthetics lover
The answer is D I just took the test
which of the following is the probability that when rolled a die will come up with either a 1 or 2?
Answer:
33%
Step-by-step explanation:
A respiratory therapist predicts that the proportion of U.S. college students who smoke hookah is greater than 30%. To test this prediction, she surveys 300 random U.S. college, and it is determined that 80 of them smoke hookah. The following is the setup for this hypothesis test: H0:p=0.30 H0:p>0.30 The p-value for this hypothesis test is 0.10. At the 5% significance level, should she reject or fail to reject the null hypothesis? Select the correct answer below: Reject the null hypothesis because 0.30>0.05. Fail to reject the null hypothesis because 0.30>0.05. Reject the null hypothesis because the p-value =0.10 is less than the significance level α=0.05. Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Answer:
Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Step-by-step explanation:
The significant level for this case study is 5% - 0.05. If the results gotten is less than the significance level, we reject the null hypothesis, but if greater, we fail to reject the null hypothesis.
In this case study, the p-value is 0.10 which is a lot higher than 0.05, thus we will fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Suppose that a certain brand of light bulb has a mean life of 450 hours and a standard deviation of 73 hours. Assuming the data are bell-shaped: (Show work to get full credit)
a. Would it be unusual for a light bulb to have a life span of 320 hours? 615 hours? Justify each response.
b. According to the Empirical Rule, 99.7% of the light bulbs have a lifetime between what two values?
c. Determine the percentage of light bulbs that will have a life between 304 and 596 hours.
Answer:
yes it is correct
Step-by-step explanation:
plz give brainliest.
Identify the slope and y-intercept of the line −2x+5y=−30.
Answer:
slope = 2/5 , y-intercept = -30
Step-by-step explanation:
-2x + 5y = -30
5y = 2x - 30
y = 2/5x - 6
we know that the general form is:
y = (slope)*x + (y- intercept)
so, from our equation, we can say that...
slope = 2/5
y- intercept = -30
A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places.
Answer:
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Step-by-step explanation:
For this case we have the following dataset given:
[tex] n= 146[/tex] represent the sample size
[tex] \hat p =0.23[/tex] represent the estimated proportion of interest
[tex] Conf=0.95[/tex] represent the confidence level
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Compute the critical value z Subscript alpha divided by 2 that corresponds to a 86% level of confidence.
Answer:
z = 1.476
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.86}{2} = 0.07[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.07 = 0.93[/tex], so [tex]z = 1.476[/tex]
The answer is z = 1.476
Find A x B, where A=(5i+j) , B=(i-5j)
Answer:
5i² - 25ij +ji-5j²
Step-by-step explanation:
Use distributive property
Answer:
The answer is 5i² - 24ij - 5j²Step-by-step explanation:
A = (5i+j)
B = (i-5j)
A × B is
( 5i + j) ( i - 5j)
Expand
We have
5i² - 25ij + ij - 5j²
The final answer is
5i² - 24ij - 5j²
Hope this helps you.
WHAT IS THE ANSWER ?? PLEASE HELP !!
Answer:
B. 43°
Step-by-step explanation:
Internal angles of the triangle are:
180°-90°=90° and180°-133°= 47°So It is a right triangle and the missing angle is:
p= 90°- 47°= 43°Answer:
The answer is B) 43°
Step-by-step explanation:
180° - 133° = 47° (that's one of the angles inside the triangle)
180° - 90° = 90° (the other angle)
Every angle inside a triangle added equals 180°, therefor:
180° - (47° + 90°) = 43°
An object of mass 2kg is attached to a spring. A force of 5nt is applied to move the object 0.5m from its equilibrium position. The damping force of the object sliding on the table is int when the velocity is 0.25m/second. The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right.
Set up an I.V.P. to describe the motion of the object and solve it, then state the amplitude function of the motion.
Answer:
[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]
Step-by-step explanation:
Given that:
mass of the object = 2 kg
A force of 5nt is applied to move the object 0.5m from its equilibrium position.
i.e
Force = 5 newton
Stretchin (x) =0.5 m
Damping force = 1 newton
Velocity = 0.25 m/second
The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right
SOLUTION:
If F = kx
Then :
5 N = k(0.5 m)
where ;
k = spring constant.
k = 5 N/0.5 m
k = 10 N/m
the damping force of the object sliding on the table is 1 newton when the velocity is 0.25m/second.
SO;
[tex]C \dfrac{dx}{dt}= F_d[/tex]
[tex]C* 0.25 = 1[/tex]
C = [tex]\dfrac{1 \ N }{0.25 \ m/s}[/tex]
C = 4 Ns/m
NOW;
[tex]m \dfrac{d^2x}{dt^2}+ C \dfrac{dx}{dt}+ kx = 0[/tex]
Divide through by m; we have;
[tex]\dfrac{m}{m}\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+ \dfrac{k}{m} x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+\dfrac{k}{m}x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ \dfrac{4}{2} \dfrac{dx}{dt}+\dfrac{10}{2}x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ 2 \dfrac{dx}{dt}+5x= 0[/tex]
we all know that:
[tex]x(t) = Ae^{(\alpha \ t)}[/tex] ------ (1)
SO;
[tex]\alpha ^2 + 2\alpha + 5 = 0[/tex]
[tex]\alpha = \dfrac{-2 \pm \sqrt{(4)-(4*5)}}{2}[/tex]
[tex]\alpha = -1 \pm 2i[/tex]
Thus ;
[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex] ------------ (1)
However;
[tex]\dfrac{dx}{dt} = e^{-t}[A \sin (2t)+ B cos (2t)]+ 2e ^{-t} [A \cos (2t)- B \ Sin (2t)][/tex] ------- (2)
From the question ; we are being told that;
The object is pulled to the left until the spring is stretched 1 m and then released with the initial velocity of 2m/second to the right.
So ;
[tex]x(0) = -1 \ m[/tex]
[tex]\dfrac{dx}{dt}|_{t=0} = 2 \ m/s[/tex]
x(0) ⇒ B = -1
[tex]\dfrac{dx}{dt}|_{t=0} =- B +2A[/tex]
[tex]=- 1 +2A[/tex]
1 = 2A
A = [tex]\dfrac{1}{2}[/tex]
From (1)
[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]
[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)+ (-1) cos (2t)][/tex]
[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)-cos (2t)][/tex]
Assuming;
[tex]A cos \ \phi = \dfrac{1}{2}[/tex]
[tex]A sin \ \phi = 1[/tex]
Therefore:
[tex]A = \sqrt{\dfrac{1}{4}+1}[/tex]
[tex]A = \sqrt{\dfrac{1+4}{4}}[/tex]
[tex]A = \sqrt{\dfrac{5}{4}}[/tex]
[tex]A ={ \dfrac{ \sqrt5}{ \sqrt4}}[/tex]
[tex]A ={ \dfrac{ \sqrt5}{ 2}}[/tex]
where;
[tex]\phi = tan ^{-1} (2)[/tex]
Therefore;
[tex]x(t) = \dfrac{\sqrt 5}{2}e^{-t} \ sin (2 t - \phi)[/tex]
From above ; the amplitude is ;
[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]
Simplify the expression below.
Answer:
6x^2 +8x
Step-by-step explanation:
(12x^3 -14x^2 -40x) / (2x-5)
Factor the numerator by factoring out the greatest common factor
2x( 6x^2 -7x-20) / (2x-5)
Factor inside the parentheses
2x (3x+4)(2x-5)/ (2x-5)
Cancel like terms
2x( 3x+4)
Distribute
6x^2 +8x
What is the value of$$\left( \sqrt{100} - \sqrt{36} \right)^2?$$
Answer:
16
Step-by-step explanation:
The square root of 100 is 10, and the square root of 36 is 6. 10-6 = 4, and 4 squared is 16.
Hope this helped!
Answer:
16
Step-by-step explanation:
[tex]\left( \sqrt{100} - \sqrt{36} \right)^2 = (10 -6)^2 = 4^2 = \boxed{16}[/tex]
Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?
Answer:
Hello!
______________________
Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?
This type of sampling is called Stratified.
Hope this helped you!
:D
Ben bought the enormous box of juice shown below. He drinks 450 cubic centimeters of juice each day. How many days does it take Ben to drink the box of juice?
Answer:
Step-by-step explanation:
to find the answer you have to find the vulume and then divide by 450
Answer:
7 days
Step-by-step explanation:
vol = 20*15*10.5
vol = 3150
how many days to drink 3150 cu.cm if Ben drinks 450 cu.cm per day?
3150 cu.cm / 450 cu.cm per day = 7 days