Answers
Choice A: they did distributive property and removed the parentheses
Choice B: they did the same thing from Choice A but they didn’t remove the +. When a negative is multiplied to any POSITIVE number it will ALWAYS be negative.
Choice D: they did the same thing from choice A and B but they moved the parentheses
Related Questions
From first to last, when did the presidents serve?
Drag the presidents' names into the correct order according to when they served.
Answers
Answer:
The answer is Gerald R. Ford, Jimmy Carter, Ronald Reagan, and lastly George H.W Bush
Step-by-step explanation:
ILL GIVE BRAINLIEST NEEDED BY TONIGHT
find the surface area of the figure below
Answers
Answer:
96 sq. ft
Step-by-step explanation:
surface area = (2×½×6×8) + (6+8+10)×2
= 48+48
= 96 sq. ft
if r=3 and h=5
then what is 8r+h=?
Answers
Answer:
29 IS THE ANSWER PLEASE MARK AS BRAIN IST
Step-by-step explanation:
Answer:
[tex]r=3\\h=5\\\\8r+h\\= 8(3) + (5)\\= 24 + 5\\= 29[/tex]
What is the volume of the prism, In cubic inches?
Answers
Answer:
55 in²
Step-by-step explanation:
Base x Height
The Sea Wharf Restaurant would like to determine the best way to allocate a monthly advertising budget of $1000 between newspaper advertising and radio advertising. Management decided that at least 25% of the budget must be spent on each type of media, and that the amount of money spent on local newspaper advertising must be at least twice the amount spent on radio advertising. A marketing consultant developed an index that measures audience exposure per dollar of advertising on a scale from 0 to 100, with higher values implying greater audience exposure. If the value of the index for local newspaper advertising is 50 and the value of the index for spot radio advertising is 80, how should the restaurant allocate its advertising budget in order to maximize the value of total audience exposure?
a. Formulate a linear programming model that can be used to determine how the restaurant should allocate its advertising budget in order to maximize the value of total audience exposure.
b. Solve the problem using the graphical solution procedure.
Answers
Answer:
Step-by-step explanation:
to find the answer you will want to gather the indenpent varible and dependent varrible. SO when you look at the problem you see 25%. You have to find the amount of money on each thing they bought. The budget and how much they have to spend.
Find the value of x.
PLEASE HELP MEEEE!!! PLEASE AND THANK YOUU!!
Answers
hay again friendssssssssssssssssssssssssssssssssssssssssssssssssssssss
Answers
What is the perimeter of this tile?
in?
4 in
1 in
Answers
Answer:
perimeter of tile =2(l+b)
2(4+1)2×510 inhope it helps
stay safe healthy and happy.
Find the common difference of the arithmetic sequence -2,6,14,...
Answers
Lets note the change between each of the numbers in the sequence:
-2 --> 6 ---> 14
Next, make an equation between each of these numbers with x being the change between them
-2+ x = 6, 6 + x = 14 .
Now, solve each of these equations:
-2+ x = 6 --> -2+ x = 6 Add 2 on both sides to cancel out the -2 --> x = 8
6+ x = 14 --> -2+ x = 6 Minus 6 on both sides to cancel out the 6 --> x = 8
From this, the common difference will be 8.
Hope that helps.
A high school drama club is selling tickets for a fundraiser event. Based on data from past events, the number of tickets sold can be modeled by a linear function Q(x)=-40x+640, where x is the price, in dollars, of each ticket.
Answers
Answer:
600 or 16
Step-by-step explanation:
Answer:
A high school drama club is selling tickets for a fundraiser event. Based on data from past events, the number of tickets sold can be modeled by a linear function Q(x)=-40x+640, where x is the price, in dollars, of each ticket.
Question 4 of 9
(10.2). 3 = 10. (2:3)
A. True
B. False
SUBMIT
Answers
Answer:
false is the correct answer right
PLEASE HELP ME
Angelique makes beaded jewelry. The graph below shows the number of beads on varying cord lengths. Jewelry  A necklace contains 88 beads. Based on the information above, which is the best estimate for the cord length? 21 inches 26 inches 34 inches 36 inches.
Answers
Answer:
please show answer choices
Step-by-step explanation:
The positions on a lacrosse team are called defenders (D). midfielders (M) and attackers (A) One player is chosen at random to lead the team in
exercises before each game. The letters MDD mean that a midfielder was chosen at the first game and a defender was chosen at the next two
games. The list of all possible outcomes is shown, where each outcome has equal probability of occurring.
MDA
DDA
AMA
AMM
AAA
AAM
AAD
ADA
ADM
ADD
DMA
DMM
MAA
MAM
MAD
MMA
MMM
DDM
DAA
DAM
DAD
MDM
MDD
MMD
DMD
AMD
DDD
What is the probability that a defender is chosen at least once, given that a midfielder is chosen at the first game?
Answers
Answer:
[tex]P(D|M) = \frac{5}{9}[/tex]
Step-by-step explanation:
Given
The sample space
Required
Probability that D is chosen at least twice provided that M is chosen first
First, list out all outcomes where M is selected first
[tex]M = \{MDA,,MAA,MAM,MAD,MMA,MMM,MDM,MDD,MMD\}[/tex]
[tex]n(M) = 9[/tex]
Next, list out all outcomes where D appears at least 1 when M is first
[tex]D\ n\ M= \{MDA,MAD,MDM,MDD,MMD\}[/tex]
[tex]n(D\ n\ M) = 5[/tex]
So, the required probability is:
[tex]P(D|M) = \frac{n(D\ n\ M)}{n(M)}[/tex]
[tex]P(D|M) = \frac{5}{9}[/tex]
find the vertex and the x- and y- intercept of the following quadratic equations
y = 5x² +15x+10
Answers
Answer:
x int. (-1,0) and (-2,0). y-int,(0,10)
Step-by-step explanation:
y-int. it's 10 because the y-int is always the c value.
x-int.
x=-b±√b²-4ac/2a
x=-15±√15²-4(5)(10)/2(5)
x=-15±√225-200/10
x=-15±√25/10
x= -15+5/10. x=-15-5/10
x=-10/10. x=-20/10
x=-1. x=-2
HELP ME! Look at the stem-and-leaf plot. What is the mode of the numbers?
Answers
Given:
The stem-and-leaf plot or a date set.
To find:
The mode of data set.
Solution:
From the given stem-and-leaf plot, we get the numbers of the data set.
64, 67, 70, 70, 71, 75, 76, 78, 78, 80, 82, 82, 88, 91, 93, 94, 97, 98, 100, 100, 100
Mode of a date set is the most frequent value.
In the given data set the most frequent value is 100 with frequency 3.
Therefore, the mode of data set is 100. Hence, option A is correct.
Answer:it is A: 100
Step-by-step explanation:
i got it right
good luck with your test :)
How many cm are in 5mm
Answers
Answer:
0.5 cm
Step-by-step explanation:
the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence
Answers
Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms ([tex]S_{5}[/tex]) = 250
or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]
or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]
or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
Need help!!!!!!!!!!!!!!!! PLEASE!!!!!!!!!!!!!!
Answers
Answer:
Your answer is 20
Step-by-step explanation:
It minuses 1 to every other.
Answer:
The answer is 20
What is the degree of the following polynomial?
g(t)=2t2−4t+t5+3
8
3
2
5
Answers
The results of a poll show that the percent of people who want a new restaurant is in the interval (62%, 88%). There are 109,482 people in the city. What is the interval for the number of people who are likely to want this restaurant in their city? Round to the nearest person. Enter your answer in the boxes.
Answers
Answer:
(67879,96344)
Step-by-step explanation:
I took the test
Mr X arranges to pay off a Debt of #9600 in 48 annual instalments which form an AP, when 40 of these instalments are paid, Mr X become insolvent,and he still owe his creditor #2400 find the value of each of the first three instalmentsof Mr X?
Answers
Answer:
The first 3 installments of Mr. X were $ 180.
Step-by-step explanation:
Since Mr X arranges to pay off a Debt of $ 9600 in 48 annual installments which form an AP, and when 40 of these installments are paid, Mr X become insolvent, and he still owe his creditor $ 2400, to find the value of each of the first three installments of Mr X the following calculation must be performed:
((9,600 - 2,400) / 40) = X
7,200 / 40 = X
180 = X
Therefore, the first 3 installments of Mr. X were $ 180.
240% of what number is 360? +
Answers
Answer:
240% of 150 is 360
Step-by-step explanation:
240% of [tex]x[/tex] = 360
[tex]\frac{240}{100}[/tex] x [tex]x[/tex] = 360
2.4 [tex]x[/tex] = 360
[tex]x[/tex] = [tex]\frac{360}{2.4}[/tex]
[tex]x[/tex] = 150
Pls HELP
3. Which image shows a reflection over the linex=2?
Answers
Answer:
C
Step-by-step explanation:
C is the answe
Plz help me well mark brainliest if correct.......??
Answers
Answer:
A
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
6 x 8 x 3 = 144
have a great day.
Three quarters of the 12 farms breed cattle. How many farms breed cattle?
Answers
Answer:
Your answer is 9 farms breed cattle.
Step-by-step explanation:
(3/4)*12 = 9
or
.75*12 = 9
Answer:
9
Step-by-step explanation:
Three quarter means ¾
¾ of 12
3 × 3
9
Which digit in the following number is the one that determines its precision?
16.82
A. 8
B. 2
o
C. 6
D. 1
SUBMIT
Answers
Answer:
B. 2
Step-by-step explanation:
The precision of a scientific measuring tool can be defined as how close the values between multiple measurements are to each other, when repeated under the same conditions.
This ultimately implies that, the precision of a scientific measuring tool reflects the reproducibility and repeatability of its measurements, irrespective of how accurate the measurements are.
In science, one of the most effective ways to determine the precision of a scientific measuring tool is to find the difference between the highest and lowest measurements (measured values).
Given the following number; 16.82
The last digit "2" in 16.82 represents the hundredth value and should be used to determine the level of precision of the number.
Find the slope of the line that contains (5, -4) and (-9, 8)
I'll give Brainliest to the right answer!
Answers
Answer: m = [tex]- \frac{6}{7}[/tex]
Based on the number of voids, a ferrite slab is classified as either high, medium, or low. Historically, 5% of the slabs are classified as high, 85% as medium, and 10% as low. A group of 20 slabs that are independent regarding voids is selected for test ing. Let X, Y, and Z denote the number of slabs that are classified as high, medium, and low, respectively.
(a) What are the name and values of the parameters of the joint probability distribution of X, Y , and
Z?
(b) What is the range of the joint probability distribution of X, Y, and Z?
(c) What are the name and the values of the parameters of the marginal probability distribution of X?
(d) Determine E[X] and Var(X).
Determine the following:
(e) P{X = 1, Y = 17, Z = 3}
(f) P{X ? 1, Y = 17, Z = 3}
(g) P{X ? 1}
(h) E[Y ]
Answers
Answer:
(a) Name: Multinomial distribution
Parameters: [tex]p_1 = 5\%[/tex] [tex]p_2 = 85\%[/tex] [tex]p_3 = 10\%[/tex] [tex]n = 20[/tex]
(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]
(c) Name: Binomial distribution
Parameters: [tex]p_1 = 5\%[/tex] [tex]n = 20[/tex]
[tex](d)\ E(x) = 1[/tex] [tex]Var(x) = 0.95[/tex]
[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]
[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]
[tex](g)\ P(X \le 1) = 0.7359[/tex]
[tex](h)\ E(Y) = 17[/tex]
Step-by-step explanation:
Given
[tex]p_1 = 5\%[/tex]
[tex]p_2 = 85\%[/tex]
[tex]p_3 = 10\%[/tex]
[tex]n = 20[/tex]
[tex]X \to[/tex] High Slabs
[tex]Y \to[/tex] Medium Slabs
[tex]Z \to[/tex] Low Slabs
Solving (a): Names and values of joint pdf of X, Y and Z
Given that:
[tex]X \to[/tex] Number of voids considered as high slabs
[tex]Y \to[/tex] Number of voids considered as medium slabs
[tex]Z \to[/tex] Number of voids considered as low slabs
Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution
The parameters are:
[tex]p_1 = 5\%[/tex] [tex]p_2 = 85\%[/tex] [tex]p_3 = 10\%[/tex] [tex]n = 20[/tex]
And the mass function is:
[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]
Solving (b): The range of the joint pdf of X, Y and Z
Given that:
[tex]n = 20[/tex]
The number of voids (x, y and z) cannot be negative and they must be integers; So:
[tex]x + y + z = n[/tex]
[tex]x + y + z = 20[/tex]
Hence, the range is:
[tex]\{(x,y,z)| x + y + z=20\}[/tex]
Solving (c): Names and values of marginal pdf of X
We have the following parameters attributed to X:
[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]
Hence, the name is: Binomial distribution
Solving (d): E(x) and Var(x)
In (c), we have:
[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]
[tex]E(x) = p_1* n[/tex]
[tex]E(x) = 5\% * 20[/tex]
[tex]E(x) = 1[/tex]
[tex]Var(x) = E(x) * (1 - p_1)[/tex]
[tex]Var(x) = 1 * (1 - 5\%)[/tex]
[tex]Var(x) = 1 * 0.95[/tex]
[tex]Var(x) = 0.95[/tex]
[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]
In (b), we have: [tex]x + y + z = 20[/tex]
However, the given values of x in this question implies that:
[tex]x + y + z = 1 + 17 + 3[/tex]
[tex]x + y + z = 21[/tex]
Hence:
[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]
[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]
This question implies that:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]
Because
[tex]0, 1 \le 1[/tex] --- for x
In (e), we have:
[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]
So:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]
In (a), we have:
[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]
So:
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]
Expand
[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]
[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]
Using a calculator, we have:
[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]
So:
[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]
[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]
[tex](g)\ P(X \le 1)[/tex]
This implies that:
[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]
In (c), we established that X is a binomial distribution with the following parameters:
[tex]p_1 = 5\%[/tex] [tex]n = 20[/tex]
Such that:
[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]
So:
[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]
[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]
[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]
[tex]P(X=0) = 0.3585[/tex]
[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]
[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]
[tex]P(X=1) = 0.3774[/tex]
So:
[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]
[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]
[tex]P(X \le 1) = 0.7359[/tex]
[tex](h)\ E(Y)[/tex]
Y has the following parameters
[tex]p_2 = 85\%[/tex] and [tex]n = 20[/tex]
[tex]E(Y) = p_2 * n[/tex]
[tex]E(Y) = 85\% * 20[/tex]
[tex]E(Y) = 17[/tex]
Can someone Please help
Answers
Answer:
80
Step-by-step explanation:
20+80+x=180
100+x=180
x=180-100
x=80
plz mark as brainliest
How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points. I was able to graph them on Desmos, but I can't seem to figure out how I would go about figuring out the slope and y-intercept in this case... the fractions are what's throwing me off here. Please help!
Answers
Answer: [tex]m=\frac{-30}{79},\ y=5.40[/tex]
Step-by-step explanation:
Given
Points are [tex]\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)[/tex]
Convert mixed numeral to fraction
[tex]\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)[/tex]
Slope of the line is
[tex]\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}[/tex]
Equation of line
[tex]\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40[/tex]