Answer:
Ellen is correct
Step-by-step explanation:
Roger:
The left side 20 does not equal to the right side 0.002 , which means that the given statement is false.
Ellen:
The left side 20 is equal to the right side 20, which means that the given statement is always true.
Hope I helped, Brainliest would be appreciated :)
Have a fantastic day!
-Aadi x
How do you find the x-intercept of a parabola?
I will mark you brainalist
Answer:
the answer is X=-7
,,,,,
Answer:
it would be x=7
Step-by-step explanation:
brainliest pls
What is the slope of the line below?
(1-2)
(
4-2)
A. negative
B. undefined
C. positive
D. Zero
Answer: D. Zero
Step-by-step explanation:
It’s a flat line. Flat horizontal lines are ALWAYS zero
HELP ME PLEASE I HAVEE 5 MINNS lEft HELP
Answer:
im going to guess the last answer. theone that i can't see
Step-by-step explanation:
3 |a| +5 |b| if a = −2; b = −1
WILL AWARD BRAINLIEST
Answer:
-11
Step-by-step explanation:
[tex]3( - 2) + 5( - 1)[/tex]
[tex] - 6 + ( - 5)[/tex]
[tex] - 11[/tex]
I'll give points and brainalist for answer / explanation
Answer:
D. 8
Step-by-step explanation:
C= 2πr
π= 3.14
C= 25.12
25.12 = 2 * 3.14 * r
r= 4
d= 2r
d= 8
find the area of the figure use 3.14
Answer:
466.08 m²
Step-by-step explanation:
The figure is composed of a triangle and a semicircle.
Therefore,
Area of the figure = area of the triangle + area of the semicircle
= ½*b*h + ½*πr²
Where,
b = 24 m
h = 20 m
π = 3.14
r = ½ of 24 m = 12 m
Substitute each value into the equation
Area of the figure = ½*24*20 + ½*3.14*12²
= 240 + 226.08
= 466.08 m²
Broccoli cost 1.50 at a store. How much does 32 ounces of broccoli cost?
Answer:
48.00
Step-by-step explanation:
Answer:
48.0 hope it helps you out
Need someone to help me with my maths tutorial ASP!!
Answer:
hi! how can i help? <3
Step-by-step explanation:
okay i can stand in for you
For the following right triangle, find the side length x.
15
Step-by-step explanation:
Pythagorean Theorem
a^2+b^2=c^2
8^2+15^2=c^2
64+225=c^2
289=c^2
Now square both sides
x=17
Answer:
x = 17
Step-by-step explanation:
[tex]c^{2} = a^{2} + b^{2}[/tex]
[tex]c^{2} = 8^{2} + 15^{2}[/tex]
[tex]c^{2} = 64 + 225[/tex]
[tex]c^{2} = 289[/tex]
[tex]\sqrt{c^2} = \sqrt{289}[/tex]
[tex]c = 17[/tex]
A number greater than or equal to 41.
Answer:
42
Step-by-step explanation:
¯\_(ツ)_/¯
Calculate the SQRT485 Express answer to nearest hundredth.
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer: 22.02
Explanation:
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
The average of Aaron's three test scores must be at least 93 to earn an A in the class. Aaron scored 89 on the first
test and 94 on the second test. What scores can Aaron get on his third test to guarantee an A in the class? (The
highest possible score is 100.)
15
Write an inequality that models this situation. Use the variable s to represent his score on his third test.
Answer:
Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.
Step-by-step explanation:
Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:
93 x 3 = 279
89 + 94 + S = 279
S = 279 - 89 - 94
S = 96
Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.
Aaron must score atleast 90 marks in third test.
Aaron scores in the first test = 89
Aaron scores in the second test = 94
And the average of Aaron's three test scores must be at least 93 to earn an A.
Let Aaron scores in the third test = s
Then,
Average = sum of terms divided by the number of terms.
[tex]\frac{89+94+s}{3} \leq 93\\89+94+s\leq 93\times3\\183+s\leq 279\\s\leq 279-189\\s\leq 90[/tex]
So, Aaron must score atleast 90 marks in third test.
Learn more:https://brainly.com/question/19982277
HELP ME PLS ITS URGENT .. !❗❗❗❗❗❗❗❗❗❗❗❗❗
The commuting distances, in miles, of 10 employees were used to make the box plot shown above. Which of the sets of distances below matches the given box plot?
A.
Commuting Distances: 10, 15, 15, 20, 20, 20, 30, 30, 45, 45
B.
Commuting Distances: 10, 15, 15, 20, 20, 30, 30, 30, 45, 45
C.
Commuting Distances: 10, 15, 20, 20, 20, 20, 30, 30, 45, 45
D.
Commuting Distances: 10, 15, 15, 20, 20, 20, 30, 45, 45, 45
Answer:
A the answer is A ^w^ hope this helps
What is the lateral surface area of this net
Help!!!
9514 1404 393
Answer:
720 square feet
Step-by-step explanation:
The lateral area is the area of the central rectangle of the net. It is 12+12+12 = 36 feet long and 20 ft wide.
The lateral area is (36 ft)(20 ft) = 720 ft².
Select all the expressions that have the same value
so what was the question again?
Answer:
Step-by-step explanation:
Ms. Annand baked an apple pie. The boys in the house ate ⅛ of it and the girls ate 3/5. What fraction of the pie did the boys and girls eat altogether? Please answer
Answer:
29/40
Step-by-step explanation:
1/8 + 3/5 =
We need a common denominator.
8 = 2^3
5 = 5
8 and 5 have no common factors, so the LCD is their product.
LCD = 5 * 8 = 40
1/8 + 3/5 =
= 5/40 + 24/40
= 29/40
Need Help (WILL GIVE BRAINLIEST)
Answer:
A
Step-by-step explanation:
(y-5) / (7-5) = (x-1) / (2-1)
(y-5) / 2 = x-1
y-5 = 2x -2
y = 2x +3
answer fast plz sjsjzjz
Answer:
104
Step-by-step explanation:
Just separate the whole thing into two shapes. Multiply the first shape: 12 x 7 = 84
Multiply the second shape: 5 x 4 = 20
Cart 1 (500 g) moves to the right at 0.40 m/s. Cart 2 (250g) moves to the left at 0.50 m/s. a. If the carts stick after the collision, what will be their velocity?
Answer:
after the collision cart 1 will stop and cart 2 will keep moving will 0.1.m/s after stop.
A recipe calls for 2 cups flour and 1 1/2 cup milk to make seven servings. Ming has plenty of flour, but only 5 cups of milk. How many servings can he make? Ming can make (answer) servings with 5 cups of milk.
Answer:
21 or 23 servings.
Step-by-step explanation:
Help..................
Write each product using an exponent. 9 x 9 x 9 x 9 x9
(Will be giving brainliest)
Answer: 9^ 5
Step-by-step explanation: since there is 5 9’s multiplied by each other, it would be 9 to the 5th power.
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathtt{9\times9\times9\times9\times9}\\\mathtt{= 81\times 81\times9}\\\mathtt{= 6,561\times9}\\\mathtt{= 59,049}\\\mathtt{= 9\times 9\times 9 \times 9 \times 9 \rightarrow 9^5}[/tex]
[tex]\huge\text{Therefore your answer should be:}[/tex]
[tex]\huge\boxed{\mathtt{9^5}}\huge\checkmark[/tex]
[tex]\huge\boxed{\mathtt{Good \ luck \ on \ your \ assignment\ \& \ enjoy}}\\\huge\boxed{\mathtt{your \ day!}}[/tex]
WILL MARK B!
Please I need help I have a quiz
Answer:
a) 2x² - x + 3 = x(2x + 1) - 2x
<=> 2x² - x + 3 = 2x² + x - 2x
<=> 3 - x = - x
<=> 3 = 0
=> no solution
b) x/2 - x/3 - x/4 = 1/12
[tex] \frac{6x}{12} - \frac{4x}{12} - \frac{3x}{12} = \frac{1}{12} \\ \\ \frac{ - x}{12} = \frac{1}{12} \\ \\ = > - x = 1 \\ \\ \\ < = > x = 1[/tex]
=> the euqation has the solution x = 1
c) |x - 5| = 2|x|
=> x - 5 = 2x
or x - 5 = -2x
<=> x = -5
or 3x = 5
<=> x = -5
x = -5or x = 5/3
d) defined conditions: 2 - x 》 0
<=> x 《 2
we have:
[tex] \sqrt{x + 4} = 2 - x \\ < = > x + 4 = (2 - x) {}^{2} \\ < = > x + 4 = {x}^{2} - 4x + 4 \\ < = > {x}^{2} - 5x = 0 \\ < = > x(x - 5) = 0 \\ [/tex]
<=> x = 0 (because x 《 2)
e)
[tex] \sqrt{5} = \frac{1}{25 {}^{x} } \\ = > 5 = \frac{1}{25 {}^{2x} } \\ < = > 5.25 {}^{2x} = 1 \\ < = > 5.5 {}^{4x} = 1 \\ < = > 5 {}^{4x + 1} = 1 \\ = > 4x + 1 = 0[/tex]
<=> x = -1/4
Answer:
[tex]a) [x: - \infty < x < \infty ][/tex]
[tex]b)[x: - 1][/tex]
[tex]c) [x:- \frac{5}{3} ][/tex]
[tex]d) [x: 3, 0][/tex]
[tex]e) [x: - \frac{1}{4} ][/tex]
Asha is tiling the lobby of the school with one-foot square tiles. She has 6 bags
of tiles with 50 tiles in each. The lobby is a 30-foot by 8-foot rectangle. How
many tiles will Asha have left over after she tiles the lobby?
Answer:
60 tiles left over
Step-by-step explanation:
the lobby needs 30 x 8 = 240 tiles.
she has 6 x 50 = 300 tiles
300 - 240 = 60 left over
8. Determine the area of a sector
with a central angle of 42° in a
circle with radius 3 inches.
NEED IT ASAP
Answer:
[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]
Step-by-step explanation:
Since we are given the central angle in degrees, we should use the following formula for sector area.
[tex]A= \frac {\theta}{360}* \pi r^2[/tex]
The angle is 42 degrees and the radius is 3 inches. Therefore,
[tex]\theta= 42 \\r=3 \ in[/tex]
[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]
Solve the exponent.
(3 in)²= 3 in*3in = 9 in²[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]
Multiply all three numbers together.
[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]
[tex]A=3.29867228627 \ in^2[/tex]
Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.
[tex]A \approx 3.3 \ in^2[/tex]
The area of the sector is approximately 3.3 square inches.
If John gets paid $45.00 an hour and works 10 hours, how much does he earn?
SOMEONE HELP ME PLEASE!!!!?
Answer:
139
Step-by-step explanation:
supplementary angles add up to equal 180
so to find the measure of angle ABC we subtract the given angle from 180
180-41=139
so we can conclude that angle ABC= 139
Step-by-step explanation:
< ABC and < CBD are supplementary angles.
< CBD = 41°
< ABC + < CBD = 180° ( Being supplementary angles)
< ABC + 41° = 180°
< ABC = 180° - 41°
< ABC = 139°
Hope it will help :)❤
6) Supplementary Exercise 5.51
A consumer advocate claims that 80 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue.
(a)
Suppose that the advocate's claim is true, and suppose that a random sample of five cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that four or more subscribers in the sample are not satisfied with their service. (Do not round intermediate calculations. Round final answer of p to 1 decimal place. Round other final answers to 4 decimal places.)
The answer for 6(a) is P( Xâ¥4) = P ( x = 4) + P (x = 5) = 5/4 * 0.84 * 0.21 + 5/5 * 0.85 * 0.20 = 0.737
(b)
Suppose that the advocate's claim is true, and suppose that a random sample of 25 cable subscribers is selected. Assuming independence, find each of the following: (Do not round intermediate calculations. Round final answer of p to 1 decimal place. Round other final answers to 4 decimal places.)
1.
The probability that 15 or fewer subscribers in the sample are not satisfied with their service.
The answer for 6(b)1 is P(Yâ¤15) = 1 - P( Y > 20) - X20, i = 16 P ( Y = i) = 1- 0.421 - 0.562 = 0.017
2.
The probability that more than 20 subscribers in the sample are not satisfied with their service.
The answer for 6(b)2 is
3.
The probability that between 20 and 24 (inclusive) subscribers in the sample are not satisfied with their service.
The answer for 6(b)3 is P(20 > Y < 24) = 1 - 0.421 - 0.1867 - 0.1358 - 0.0708 - 0.0236 = 0.1621
4.
The probability that exactly 24 subscribers in the sample are not satisfied with their service.
The answer for 6(b)4 is P( Y = 24) = 0.0236
(c)
Suppose that when we survey 25 randomly selected cable television subscribers, we find that 15 are actually not satisfied with their service. Using a probability you found in this exercise as the basis for your answer, do you believe the consumer advocate's claim? Explain. (Round your answer to 4 decimal places.)
Answer:
[tex]P(X \le 4) = 0.7373[/tex]
[tex]P(x \le 15) = 0.0173[/tex]
[tex]P(x > 20) = 0.4207[/tex]
[tex]P(20\ge x \le 24)= 0.6129[/tex]
[tex]P(x = 24) = 0.0236[/tex]
[tex]P(x = 15) = 1.18\%[/tex]
Step-by-step explanation:
Given
[tex]p = 80\% = 0.8[/tex]
The question illustrates binomial distribution and will be solved using:
[tex]P(X = x) = ^nC_xp^x(1 - p)^{n-x}[/tex]
Solving (a):
Given
[tex]n =5[/tex]
Required
[tex]P(X\ge 4)[/tex]
This is calculated using
[tex]P(X \le 4) = P(x = 4) +P(x=5)[/tex]
This gives:
[tex]P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}[/tex]
[tex]P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0[/tex]
[tex]P(X \le 4) = 0.4096 + 0.32768[/tex]
[tex]P(X \le 4) = 0.73728[/tex]
[tex]P(X \le 4) = 0.7373[/tex] --- approximated
Solving (b):
Given
[tex]n =25[/tex]
i)
Required
[tex]P(X\le 15)[/tex]
This is calculated as:
[tex]P(X\le 15) = 1 - P(x>15)[/tex] --- Complement rule
[tex]P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]
[tex]P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}[/tex]
[tex]P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]
[tex]P(x > 15) = 0.98266813045[/tex]
So:
[tex]P(X\le 15) = 1 - P(x>15)[/tex]
[tex]P(x \le 15) = 1 - 0.98266813045[/tex]
[tex]P(x \le 15) = 0.01733186955[/tex]
[tex]P(x \le 15) = 0.0173[/tex]
ii)
[tex]P(x>20)[/tex]
This is calculated as:
[tex]P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]
[tex]P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]
[tex]P(x > 20) = 0.42067430925[/tex]
[tex]P(x > 20) = 0.4207[/tex]
iii)
[tex]P(20\ge x \le 24)[/tex]
This is calculated as:
[tex]P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)[/tex]
[tex]P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1[/tex]
[tex]P(20\ge x \le 24)= 0.61291151859[/tex]
[tex]P(20\ge x \le 24)= 0.6129[/tex]
iv)
[tex]P(x = 24)[/tex]
This is calculated as:
[tex]P(x = 24) = 25* 0.8^{24}*0.2^1[/tex]
[tex]P(x = 24) = 0.0236[/tex]
Solving (c):
[tex]P(x = 15)[/tex]
This is calculated as:
[tex]P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}[/tex]
[tex]P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}[/tex]
[tex]P(x = 15) = 0.01177694905[/tex]
[tex]P(x = 15) = 0.0118[/tex]
Express as percentage
[tex]P(x = 15) = 1.18\%[/tex]
The calculated probability (1.18%) is way less than the advocate's claim.
Hence, we do not believe the claim.
Find the annual percentage rate of change for the population of Oregon. In 2000, there were 4.8
million people, and in 2010, there were 8.7 million people.
Answer:
The annual percentage rate of change for the population of Oregon is of 8.125%.
Step-by-step explanation:
Total percentage change:
Change multiplied by 100 and divided by the initial value.
Change: 8.7 - 4.8 = 3.9 million
Initial value: 4.8
Percentage change: 3.9*100/4.8 = 81.25%
Annual percentage rate of change
81.25% during 10 years(from 2000 to 2010).
So, per year
81.25%/10 = 8.125%
The annual percentage rate of change for the population of Oregon is of 8.125%.