Richard and Teo have a combined age of 31. Richard is 4 years older than twice Teo's age. Write a system of equations. How old are Richard and Teo?

I need to write an equation for this, please help

Answer:

[tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 52[/tex]

Step-by-step explanation:

Given

[tex]Sequence: 12, 16, 20, 24[/tex]

Solving (a): Write a formula

The above sequence shows an arithmetic progression

Hence:

The formula can be calculated using:

[tex]T_n = a + (n - 1) d[/tex]

In this case:

[tex]a = First\ Term = 12[/tex]

Difference (d) is difference of 2 successive terms

So:

[tex]d = 16 - 12 = 20 - 16 = 24 - 20[/tex]

[tex]d = 4[/tex]

Substitute 4 for d and 12 for a in [tex]T_n = a + (n - 1) d[/tex]

[tex]T_n = 12 + (n - 1) * 4[/tex]

Open Bracket

[tex]T_n = 12 + 4n - 4[/tex]

Collect Like Terms

[tex]T_n = 12 - 4+ 4n[/tex]

[tex]T_n = 8+ 4n[/tex]

Hence, the explicit formula is: [tex]T_n = 8+ 4n[/tex]

Solving (b): 11th term

This implies that n = 11

Substitute 11 for n in: [tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 8+ 4 * 11[/tex]

[tex]T_{11} = 8+ 44[/tex]

[tex]T_{11} = 52[/tex]

Answer:

A) The explicit formula for the sequence is [tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex].

B) The 11th term of the sequence is 62.

Step-by-step explanation:

A) Let [tex]f(0) = 12[/tex], we notice that sequence observes an arithmetic progression, in which there is a difference of 4 between two consecutive elements. The formula for arithmetic progression is:

[tex]f(n) = f(0) +r\cdot n[/tex] (1)

Where:

[tex]f(0)[/tex] - First value of the sequence, dimensionless.

[tex]r[/tex] - Arithmetic increase rate, dimensionless.

[tex]n[/tex] - Term of the value in the sequence, dimensionless.

If we know that [tex]f(0) = 12[/tex] and [tex]r = 4[/tex], then the explicit formula for the sequence is:

[tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex]

B) If we know that [tex]f(n) = 12+4\cdot n[/tex] and [tex]n = 10[/tex], the 11th term of the sequence is:

[tex]f(10) = 12+4\cdot (10)[/tex]

[tex]f(10) = 62[/tex]

The 11th term of the sequence is 62.

Answer:

The maximum amount of apples she could buy is 7

Step-by-step explanation:

3 mangos would be 4.50 dollars. Subtract that from her current amount of money (20 dollars). You would get 15.5 dollars. Then, find how many apples she can buy with 15.5 dollars. You can't buy 8 because that would be above 15.5. So do the next smallest amount, 7.

Answer:

1.2

Step-by-step explanation:

0.3 * 4

= 3 * 0.1  * 4

= 3 * 4 * 0.1

= 12 * 0.1

= 1.2

Answer:

he will fill 6 pitchers

Step-by-step explanation:

4.8÷0.8=6

Answer:

a) 2260 cm³

b) 3390 grams

Step-by-step explanation:

3.

a)The radius of the solid cylinder = 6cm

The height of the cylinder is =20 cm

The volume = π*r²*h

The volume = 3.14 * 6²*20 =2260 cm³

b) Density of the material = 1.5 g/cm³

  Volume of the cylinder = 2261 cm³

  Mass of the cylinder = Density * Volume

  Mass of the cylinder = 1.5 * 2261 = 3390 grams

Answer:

The instantaneous rate of change as x approaches 3 is 18.

Step-by-step explanation:

From Differential Calculus and Geometry we remember that instantaneous rate of change of the function is represented by a tangent line, whose slope is determined by the first derivative of the curve. Let [tex]f(x) = 3\cdot x^{2}[/tex], the instantaneous rate of change of the function when x approaches 3 is deducted from the definition of derivative:

[tex]f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex] (1)

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x^{2}+2\cdot x\cdot h +h^{2})-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot x^{2}+6\cdot x\cdot h+3\cdot h^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{6\cdot x\cdot h +3\cdot h^{2}}{h}[/tex]

[tex]f'(x) = \lim _{h\to 0} (6\cdot x+3\cdot h)[/tex]

[tex]f'(x) = 6\cdot x \cdot \lim_{h\to 0} 1 + 3\cdot \lim_{h\to 0} h[/tex]

[tex]f'(x) = 6\cdot x[/tex] (2)

If we know that [tex]x = 3[/tex], then the instantaneous rate of change as x approaches 3 is:

[tex]f'(3) = 6\cdot (3)[/tex]

[tex]f'(3) = 18[/tex]

The instantaneous rate of change as x approaches 3 is 18.

Answer:

so what is the question?

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A right turn represents a clockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by -i.

A left turn represents a counterclockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by i.

The attached table shows the desired values and expressions.

Step-by-step explanation:

[tex]\boxed{\begin{array}{c|c|c} \underline{Intial -d} & \underline {Left-turn} & \underline{Right-turn} \\ -1 & -i & i \\ 1 & i & -i \\ i & -1 & 1\\ -i & 1 & -1 \\ d & di & -di \end{array}}[/tex]

Answer:

8.033

Step-by-step explanation:

Answer:

the answer is there should be another digit in the quotient

Answer:

No, because there should be another digit in the quotient

Answer:

2a^2 b^3(3a^2 b^3 - 4ab^2 + 6)

9514 1404 393

Answer:

  24 cups

Step-by-step explanation:

One batch takes a combined total of 4 + 2 cups = 6 cups of milk and flour. Then 4 recipes will take ...

  4 × 6 cups = 24 cups . . . combined

Answer:

y = 4/5x

Step-by-step explanation:

Her ya go!

Answer:

Two complex (imaginary) solutions.

Step-by-step explanation:

To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.

The discriminant formula for a quadratic in standard form is:

[tex]\Delta=b^2-4ac[/tex]

We have:

[tex]3x^2+7x+5[/tex]

Hence, a=3; b=7; and c=5.

Substitute the values into our formula and evaluate. Therefore:

[tex]\Delta=(7)^2-4(3)(5) \\ =49-60\\=-11[/tex]

Hence, the result is a negative value.

If:

Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.

Answer:

There are 18 pictures on the wall

Step-by-step explanation:

6 x 3 = 18

there is no way that simple multiplication is college level.

May I have brainliest please? :)

Answer:

hope this helps :)

Step-by-step explanation:

Since we know how far she can walk in 1/5 (one fifth) of an hour, if we multiply this distance by 5, we will find out how far she can walking in 5/5 (five fifths) of an hour, or to be clear: in one hour.

So, 5 x 1/4 miles = 5/4 or 1.25 miles per hour

Jazmeen can walk 1.25 miles in one hour.

Answer:

Step-by-step explanation:

4x^3 + 7x^3 - 5x + 9x + 3 + 11 = 11x^3 + 4x + 14

Answer:

280

Step-by-step explanation:

Month 1: 100 + 30 = 150

Month 2: +30

Month 3: +30

Month 4: +30

Month 5: +30

Month 6: +30

Total: 280

Hope this helps!

Answer:

$280

Step-by-step explanation:

For this problem, we simply need to take the initial cost of membership and add that to the reoccurring cost from a time period, in this case, 6 months.  So let's make an equation to represent this.

The initial cost is $100

The per month cost is $30

Total cost after 6 months = Inital cost + Per Month Cost * 6 months

Total cost = $100 + $30 * 6

Total cost = $100 + $180

Total cost = $280

Thus, a member will spend $280 after 6 months on the membership.

Cheers.

Answer:

66 2/3

Step-by-step explanation:

(2/3)(100) = 66 2/3

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Question reads....}[/tex]

[tex]\large\textbf{What percent is equivalent to }\rm{\bf \dfrac{2}{3}}\large\textbf{ ?}[/tex]

[tex]\huge\textbf{Let's simplify the current fraction}\\\huge\textbf{to find the overall result to this question.}[/tex]

[tex]\mathbf{\dfrac{2}{3}}[/tex]

[tex]\mathbf{= 2\div3}[/tex]

[tex]\mathbf{= 0.66666667}[/tex]

[tex]\mathbf{= 0.66666667 \times 100}[/tex]

[tex]\mathbf{= 66.6666667\%}[/tex]

[tex]\mathbf{\approx 66.67\%}[/tex]

[tex]\huge\textbf{Let's do process of elimination to find}\\\huge\textbf{the fraction that is equivalent to yours.}[/tex]

[tex]\huge\textsf{Option A.}[/tex]

[tex]\mathbf{66 \dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+1}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 +1}{3}}[/tex]

[tex]\mathbf{= \dfrac{199}{3}}[/tex]

[tex]\mathbf{= 199\div3}[/tex]

[tex]\mathbf{= 66.3333333}[/tex]

[tex]\mathbf{= 66.3333333 \times100}[/tex]

[tex]\mathbf{= 6,633.33333\%}[/tex]

[tex]\mathbf{\approx 6,633.33\%}[/tex]

[tex]\huge\textsf{This eliminates Option A. as your result.}[/tex]

[tex]\huge\textsf{Option B.}[/tex]

[tex]\mathbf{66 \dfrac{3}{5}}[/tex]

[tex]\mathbf{= \dfrac{66\times5 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{330 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{333}{5}}[/tex]

[tex]\mathbf{= 333\div5}[/tex]

[tex]\mathbf{= 66.6}[/tex]

[tex]\mathbf{= 66.6 \times 100}[/tex]

[tex]\mathbf{= 6,660}[/tex]

[tex]\mathbf{\approx 6,660\%}[/tex]

[tex]\huge\textsf{This eliminates Option B. as your result.}[/tex]

[tex]\huge\textsf{Option C.}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+2}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 + 2}{3}}[/tex]

[tex]\mathbf{= \dfrac{200}{3}}[/tex]

[tex]\mathbf{= 200\div3}[/tex]

[tex]\mathbf{= 66.6666667}[/tex]

[tex]\mathbf{= 66.6666667\times100}[/tex]

[tex]\mathbf{= 6,666.66667}[/tex]

[tex]\mathbf{\approx 6,666.67\%}[/tex]

[tex]\huge\textsf{This eliminates Option C. as your result.}[/tex]

[tex]\huge\textsf{Option D.}[/tex]

[tex]\mathbf{66\dfrac{7}{10}}[/tex]

[tex]\mathbf{= \dfrac{66\times10 +7}{10}}[/tex]

[tex]\mathbf{= \dfrac{660 + 7}{10}}[/tex]

[tex]\mathbf{= \dfrac{667}{10}}[/tex]

[tex]\mathbf{= 667\div10}[/tex]

[tex]\mathbf{= 6.67}[/tex]

[tex]\mathbf{= 6.67\times100}[/tex]

[tex]\mathbf{= 6,670}[/tex]

[tex]\mathbf{\approx 6,670\%}[/tex]

[tex]\huge\textsf{This eliminates Option D. as your result.}[/tex]

[tex]\huge\textbf{It seems like none of the above matches }\\\huge\textbf{the original fraction, so we will use the}\\\huge\textbf{that is close to the original answer.}[/tex]

[tex]\huge\textbf{The closest answer was:}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\huge\textbf{Therefore the answer MIGHT be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ C. \ 66 \dfrac{2}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

Exact form: 157/20

Decimal Form: 7.85

Mixed Number Form: 7/17/20

Step-by-step explanation:

Answer:

x=5

Both are vertical lines and parallel to each other.

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer:  5/2

============================================

Problem 3

(f o f o f)(1) = f(  f(f(1)) )

(f o f o f)(1) = f(  (f o f)(1) )

(f o f o f)(1) = f(  5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f(   f(f(f(1))   )

(f o f o f o f)(1) = f(   (f o f o f)(1)    )

(f o f o f o f)(1) = f(   29/10   )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f(   f(f(f(f(1))))   )

(f o f o f o f o f)(1) = f(   (f o f o f o f)(1)  )

(f o f o f o f o f)(1) = f(   941/290  )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

A function assigns the values. The value of (f•f•f•f•f)(1)​ is 969581/272890.

A function assigns the value of each element of one set to the other specific element of another set.

1.)

The value of f(1) for the given function f(x) =x+1/x can be calculated as shown below,

f(x) = x + 1/x

f(1) = 1 + 1/1

    = 1 + 1

    = 2

2.)

(f · f)(1) = f( f(1) )

Since the value of f(1)=2, therefore, it can be rewritten as,

(f · f)(1) = f(2)

           = 2 + 1/2

           = 4/2 + 1/2

           = 5/2

3.)

(f · f · f)(1) = f(  f(f(1)) )

Since the value of f(f(1))=5/2, therefore, it can be rewritten as,

(f · f · f)(1) = f(  (f·f)(1) )

              = f(  5/2 )

              = 5/2 + 1/(5/2)

              = 5/2 + 2/5

              = 25/10 + 4/10

              = 29/10

4.)

(f · f · f · f)(1) = f(  f(f(f(1))  )

Since the value of f(f(f(1)))=29/10, therefore, it can be rewritten as,

(f · f · f · f)(1) = f(   (f·f·f)(1)    )

                  = f( 29/10 )

                  = 29/10 + 1/(29/10)

                  = 29/10 + 10/29

                  = 841/290 + 100/290

                  = 941/290

5.)

(f · f · f · f · f)(1) = f(   f(f(f(f(1))))   )

Since the value of f(f(f(1)))=29/10, therefore, it can be rewritten as,

(f o f o f o f o f)(1) = f(   (f·f·f·f)(1)  )

                           = f(  941/290 )

                           = 941/290 + 1/(941/290)

                           = 941/290 + 290/941

                           = 885481/272890 + 84100/272890

                           = 969581/272890

Hence, the value of (f•f•f•f•f)(1)​ is 969581/272890.

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Answer:

Is this in a different language?

Step-by-step explanation:ok:)

Answer:

5

Step-by-step explanation:

Answer:

Less Than :)

Step-by-step explanation:

Answer:

The anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Step-by-step explanation:

Given the function

[tex]\:f\left(x\right)=10x^4\:+\:12.5[/tex]

Taking the anti-derivative of f(x)

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:[/tex]

[tex]\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx[/tex]

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

Solving

[tex]\int 10x^4dx[/tex]

[tex]\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx[/tex]

[tex]=10\cdot \int \:x^4dx[/tex]

[tex]\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]

[tex]=2x^5[/tex]

similarly,

[tex]\int 12.5dx[/tex]

[tex]\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax[/tex]

[tex]=12.5x[/tex]

so substituting these values

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

                                [tex]=2x^5+12.5x[/tex]

                               [tex]=2x^5+12.5x+C[/tex]   ∵ Add constant to the solution

Therefore, the anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Answer:

Jahmya's Lunch cost more

Step-by-step explanation:

Stephen's Lunch

Jahmya's Lunch

Answer:

a. 50 - 4h < 32

Step-by-step explanation:

The question is "When will the temperature be below 32F?" so it can't be less than or equal to (≤), it has to be less than (<).

If the temperature is decreasing every hour you have to decrease 4 for each hour.

hope that helps!

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)