Recall the steps of the engineering design process. Compare and contrast the
similarities and differences between the stages of the web design process and the
engineering design process.

Answer:

12

Explanation:

Answer:

[tex]Pressure = 16\ pa[/tex]

Explanation:

Given

[tex]Force = 4000N[/tex]

[tex]Area = 250m^2[/tex]

Required

Determine the pressure

Pressure is calculated using:

[tex]Pressure = \frac{Force}{Area}[/tex]

Substitute values for Force and Area

[tex]Pressure = \frac{4000N}{250m^2}[/tex]

[tex]Pressure = 16N/m^2[/tex]

Change units

[tex]Pressure = 16\ pa[/tex]

Answer:

I believe its emotional because it says satisfaction and most of the time that has to deal with emotions running through the body.

Explanation:

Explanation:

there are no limits of the number of junction boxes in any particular circuit.

Answer: The engineer will create a detailed sketch that labels all of the visual components.

Explanation:

It should be noted that the reverse engineering is required for the replacement and the modification of an existing product.

With regards to the question, the correct answer is option A "The engineer will create a detailed sketch that labels all of the visual components".

Answer:

visual engineer

Explanation:

took da class

Answer:

Mechanical Engineering

Chemical Engineering

Civil Engineering

Explanation:

I got it from my old homework And I learn those at school ( Thank You For The Points)

Answer:

A

Explanation:

I don`t know I need points hope it was correct.

A good safety rule, when you are sure you have a legal right of  way is: B. Never insist on it.

Even if you are certain that you have a legal right-of-way, it is still crucial to put safety first and avoid being overly insistent on it. When driving, safety should always come first, even if you have the right-of-way legally.

Being cautious and courteous while driving are essential components of defensive driving, and this includes letting other drivers go ahead of you if doing so will help you avoid potential collisions or problems.

Therefore the correct option  is B.

Learn more about safety rule here:https://brainly.com/question/29789032

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Answer:

1.[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴

Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴

2. [tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴

Iₓ = 457.[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴

3. The maximum deflection of the beam is 2.55552 inches

Explanation:

1. The height of the beam having a rectangular cross section is h = 2.5 in.

The breadth of the beam, is = 5.5 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

[tex]I_{xc}[/tex] = b·h³/12 = 5.5 × 2.5³/12 = 1375/192 = 7.161458[tex]\overline 3[/tex]

[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = h·b³/12 = 2.5 × 5.5³/12 = 6655/192 = 36.661458[tex]\overline 3[/tex]

[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 5.5 × 2.5³/3 = 625/24 = 28.6458[tex]\overline 3[/tex]

Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 6655/48= 138.6548[tex]\overline 3[/tex]

[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴

2. The height of the beam having a rectangular cross section is h = 7 in.

The breadth of the beam, b = 4 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

[tex]I_{xc}[/tex] = b·h³/12 = 4 × 7³/12 = 114.[tex]\overline 3[/tex]

[tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = h·b³/12 = 7 × 4³/12 = 37.[tex]\overline 3[/tex]

[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 4 × 7³/3 = 457.[tex]\overline 3[/tex]

Iₓ = 457.[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 149.[tex]\overline 3[/tex]

[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴

3. The deflection, [tex]\delta _{max}[/tex], of a simply supported beam having a point load at the center is given as follows;

[tex]\delta_{max} = \dfrac{W \times L^3}{48 \times E \times I}[/tex]

The given parameters of the beam are;

The length of the beam, L = 22 ft. = 264 in.

The applied load at the center, W = 750 lbs

The modulus of elasticity for Cedar = 10,000,000 psi

The height of the wood, h = 3 in.

The breadth of the wood, b = 5 in.

The moment of inertia of the wood, [tex]I_{xc}[/tex] = b·h³/12 = 5 × 3³/12 = 11.25 in.⁴

By plugging in the given values, we have;

[tex]\delta_{max} = \dfrac{750 \times 264^3}{48 \times 10,000,000 \times 11.25} = 2.55552[/tex]

The maximum deflection of the beam, [tex]\delta _{max}[/tex] = 2.55552 inches

Answer:

the product design

Explanation:

i think??

Answer:

Among us is the answer

Explanation:

If you play among is everyday then Among us is always the answer

B be should answer The