Raven throw a baseball directly downward from a terrace froma speed of 5.0 m/s. How fast it will be moving when it hits the path way 3.0 m below

Answer:

The moment of inertia is  [tex]I =0.14 \ kg \cdot m^2[/tex]

Explanation:

From the question we are told that

    The length of the rod is  [tex]l = 0.900 \ m[/tex]

     The mass of the rod is  [tex]m = 0.500 \ kg[/tex]

      The distance of the center of mass from the pivot is  [tex]d = 0.500 \ m[/tex]

      The period of the rod's motion is  [tex]T = 1.49 \ s[/tex]

Generally the period of the motion is mathematically represented as

       [tex]T = 2 \pi * \sqrt{\frac{I}{m* g * d} }[/tex]

Where [tex]I[/tex] is the moment of inertia about the pivot so making [tex]I[/tex] the subject of formula

      [tex]I = [\frac{T}{2\pi } ]^2 * m * g * d[/tex]

substituting values

        [tex]I = [\frac{1.49}{2* 3.142 } ]^2 * 0.5 * 9.8 * 0.5[/tex]

       [tex]I =0.14 \ kg \cdot m^2[/tex]

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

[tex]f_o = \frac{v - v_o}{v}f[/tex]

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

[tex]f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz[/tex]

The frequency heard by the observer is 993.52 Hz.

Answer:

The minimum speed required  is 2.62m/s

Explanation:

The value of  gravitational acceleration = g = 9.81 m/s^2

Radius of the vertical circle = R = 0.7 m

Given the mass of the pail of water = m

The speed at the highest point of the circle = V

The centripetal force will be needed must be more than the weight of the pail of water in order to not spill water.

Below is the calculation:

[tex]\frac{mV^{2}}{R} = mg[/tex]

[tex]V = \sqrt{gR}[/tex]

[tex]V = \sqrt{9.81 \times 0.7}[/tex]

[tex]V = 2.62 m/s[/tex]

Answer:

a) -z direction, b) +z direction, c) F=0  

Explanation:

The magnetic force is given by the expression

        F = q v x B

the bold indicate vectors, this equation can be separated in its module

        F = a v B sin θ

and where θ is the angles between the speed and the magnetic field.

The direction of the force can be found with the right-hand rule. For a positive charge, the thumb goes in the direction of speed, the fingers extended in the direction of the magnetic field and the palm points in the direction of the force, if the charge is negative the force is in the opposite direction.

a) Let's apply this to our case

the proton is positively charged

moves in the direction of + x

The magnetized field goes in the direction of y

therefore applying the right hand rule the force must be in the direction of the negative part of the z-axis (-z)

The right-hand rule is used to find this address.

b)  in this case it indicates that the proton moves in the recode of -y

again we apply the right hand rule and the force is in the direction of + z

c)   The proton moves in the x direction

In this case the force is zero because the angle between the field and the speed is zero and the sine is zero, therefore the force is zero

Answer:

A

Explanation:

since the wooden bat is an opaque object placed after a translucent object, light will come through the plastic sheet but will be unable to go through the bat. hence the dark shadow of the bat on a lit sheet

Answer:

This would be capillary action.

Explanation:

The physics behind it is gravity adhesion. The forces that attract between dissimilar molecules or atoms, in our case the contact area between the particles of the liquid and the particles forming the tube.

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

[tex]F_G=G\,\frac{M_1\,\,M_2}{D^2}[/tex]

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

[tex]F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G[/tex]

which is 16 times the original force.

So the ratio of the new force over the original force is 16

The ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance between them stays the same is 16:1.

Newton's law of gravitation states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.

The formula for Newton's law of gravitation is:

[tex]F = G \frac{m_1m_2}{r^{2} }[/tex]

where,

The initial force between the planets is:

[tex]F_1 = G \frac{m_1m_2}{r^{2} }[/tex]

The force between the planets if the masses of both planets are quadrupled but the distance between them stays the same is:

[tex]F_2 = G \frac{4m_14m_2}{r^{2} } = 16 G \frac{m_1m_2}{r^{2} }[/tex]

The ratio of F₂ to F₁ is:

[tex]\frac{F_2}{F_1} =\frac{16 G \frac{m_1m_2}{r^{2} }}{G \frac{m_1m_2}{r^{2} }} = \frac{16}{1}[/tex]

The ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance between them stays the same is 16:1.

Learn more about Newton's gravitational law here: https://brainly.com/question/9373839

Answer:

Electrical equipment should be guarded with exposed parts operating at 50 volts or more to avoid the accidental shock and also to prevent accidental contact by workers and their tools.

Explanation:

Electrical guarding involves the process by which electrical equipment are enclosed so that people do not accidentally come in contact with it in order to avoid accidental shock.

Electrical components operating at 50 volts or more must be guarded with covers or other permanent barriers and it should be put where the people that are authorized to it have acess to it.

Answer:

The  angular speed is [tex]w = 5.89 \ rad/s[/tex]

Explanation:

From the question we are told that

    The time taken is  [tex]t = 1.6 s[/tex]

    The number of somersaults  is n  =  1.5

The total angular displacement during the somersault is mathematically represented as

         [tex]\theta = n * 2 * \pi[/tex]

substituting values

        [tex]\theta = 1.5 * 2 * 3.142[/tex]

       [tex]\theta = 9.426 \ rad[/tex]

 The angular speed is mathematically represented as

         [tex]w = \frac{\theta }{t}[/tex]

substituting values

         [tex]w = \frac{9.426}{1.6}[/tex]

          [tex]w = 5.89 \ rad/s[/tex]

Complete question:

A particle located at the position vector r = (i + j) m has a force F = (2i + 3j) N acting on it. The torque about the origin is

Answer:

The torque about the origin is (5k) N.m

Explanation:

The torque about the origin is the vector or cross product of the two vectors.

τ = r x F (N.m)

Where;

τ is the torque about the origin

τ = r x F

τ = (i + j) x (2i + 3j)

For cross product;

i x j = k

i x k = j

j x k = i

i x i = 0

j x j = 0

k x k = 0

τ = (i + j) x (2i + 3j)

τ = (i x 2i) + (i x 3j) + (j x 2i) + (j x 3j)

τ = (0) + (3k)+ (2k) + 0

τ = (5k) N.m

Therefore, the torque about the origin is (5k) N.m

The question is incomplete. Here is the complete question.

A uniform electric field of 2kN/C points in the +x-direction.

(a) What is the change in potential energy of a +2.00nC test charge, [tex]U_{electric,b} - U_{electric,a}[/tex] as it is moved from point a at x = -30.0 cm to point b at x = +50.0 cm?

(b) The same test charge is released from rest at point a. What is the kinetic energy when it passes through point b?

(c) If a negative charge instead of a positive charge were used in this problem, qualitatively, how would your answers change?

Answer: (a) ΔU = 3.2×[tex]10^{-6}[/tex] J

(b) KE = 2×[tex]10^{-6}[/tex] J

Explanation: Potential Energy (U) is the amount of work done due to its position or condition and its unit is Joule (J). Kinetic Energy (KE) is the ability to do work by virtue of velocity and the unit is also (J). Mechanical Energy is the sum of Potential and Kinetic Energies of a system.

(a) Related to electricity, Potential Energy can be calculated as:

ΔU = Eqd

where E is the electric field (in N/C);

q is the charge (in C);

d is the distance between plaques (in m);

For a at x = - 30cm and b at x = 50 cm:

E = 2×[tex]10^{3}[/tex] N/C

q = 2×[tex]10^{-9}[/tex] C

d = 50 - (-30) = 80×[tex]10^{-2}[/tex] = 8×[tex]10^{-1}[/tex]m

ΔU = [tex]U_{electric,b} - U_{electric,a}[/tex] = Eqd

[tex]U_{electric,b} - U_{electric,a}[/tex] = 2×[tex]10^{3}[/tex] .  2×[tex]10^{-9}[/tex] . 8×[tex]10^{-1}[/tex]

ΔU = 3.2×[tex]10^{-6}[/tex] J

(b) Mechanical Energy is constant, so:

[tex]KE_{i} + U_{i} = KE_{f} + U_{f}[/tex]

Since the initial position is zero and there is no initial kinetic energy:

[tex]KE_{f} = - U{f}[/tex]

[tex]KE_{f} =[/tex] - (2×[tex]10^{3}[/tex]. 2×[tex]10^{-9}[/tex] . 5×[tex]10^{-1}[/tex])

[tex]KE_{f} = - 2.10^{-6}[/tex] J

(c) If the charge is negative, electric field does positive work, which diminishes the potential energy. The charge flows from the negative side towards the positive side and stays, not doing anything.

Answer:

α(0) = 0 rad/s²

α(5) = 15 rad/s²

Explanation:

The angular velocity of the flywheel is given as follows:

w(t) = A + B t²

where, A and B are constants.

Now, for the angular acceleration, we must take derivative of angular velocity with respect to time:

Angular Acceleration = α (t) = dw/dt

α(t) = (d/dt)(A + B t²)

α(t) = 2 B t

where,

B = 1.5

AT t = 0 s

α(0) = 2(1.5)(0)

α(0) = 0 rad/s²

AT t = 5 s

α(5) = 2(1.5)(5)

α(5) = 15 rad/s²

Answer:

the resistance of the longer one is twice as big as the resistance of the shorter one.

Explanation:

Given that :

For the shorter cylindrical resistor

Length = L

Diameter = D

Resistance = R1

For the longer cylindrical resistor

Length = 8L

Diameter = 4D

Resistance = R2

So;

We all know that the resistance of a given material can be determined by using the formula :

[tex]R = \dfrac{\rho L }{A}[/tex]

where;

A = πr²

[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]

For the shorter cylindrical resistor ; we have:

[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]

since 2 r = D

[tex]R = \dfrac{\rho L }{\pi (\frac{2}{2 \ r}) ^2}[/tex]

[tex]R = \dfrac{ 4 \rho L }{\pi \ D ^2}[/tex]

For the longer cylindrical resistor ; we have:

[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]

since 2 r = D

[tex]R = \dfrac{ \rho (8 ) L }{\pi (\frac{2}{2 \ r}) ^2}[/tex]

[tex]R = \dfrac{32\rho L }{\pi \ (4 D) ^2}[/tex]

[tex]R = \dfrac{2\rho L }{\pi \ (D) ^2}[/tex]

Sp;we can equate the shorter cylindrical resistor to the longer cylindrical resistor as shown below :

[tex]\dfrac{R_s}{R_L} = \dfrac{ \dfrac{ 4 \rho L }{\pi \ D ^2}}{ \dfrac{2\rho L }{\pi \ (D) ^2}}[/tex]

[tex]\dfrac{R_s}{R_L} ={ \dfrac{ 4 \rho L }{\pi \ D ^2}}* { \dfrac {\pi \ (D) ^2} {2\rho L}}[/tex]

[tex]\dfrac{R_s}{R_L} =2[/tex]

[tex]{R_s}=2{R_L}[/tex]

Thus; the resistance of the longer one is twice as big as the resistance of the shorter one.

Answer:

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Explanation:

In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:

[tex]\vec{F_B}=q\vec{v}\ X\ \vec{B}[/tex]       (1)

v: speed of the proton = 9.9*10^5 m/s

q: charge of the proton = 1.6*10^-19C

B: magnetic field = ?

FB: magnetic force on the proton = 1.6*10^-13N

When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:

^j X (-^i) = -(-^k)=^k

To obtain the magnitude of the magnetic field you use:

[tex]F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T[/tex]

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Answer:

The magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T

Explanation:

Given;

current in the first wire, I₁ = 10 A

current in the second wire, I₂ = 20 A

distance between the two wires, d = 1.0 m

Magnetic field at mid point between two parallel wires is calculated as;

[tex]B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r}(I_1 +I_2)[/tex]

where;

r is the midpoint between the wires, = 0.5 m

μ₀ is the permeability of free space, = 4π x 10⁻⁷

[tex]B = \frac{\mu_o }{2\pi r}(I_1 +I_2)\\\\B = \frac{4\pi*10^{-7} }{2\pi *0.5}(10 +20)\\\\B = \frac{4\pi*10^{-7} *30}{2\pi *0.5}\\\\B = 1.2 *10^{-5} \ T[/tex]

Therefore, the magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T

Answer:

17.94 kN/C is the electric field intensity at the origin due to the charges.

Explanation:

From the question, we are told that

The distance of 1 μC from origin = 1 m

The distance of 2 μC from origin = 2 m

The distance of 3 μC from origin = 3 m

The distance of 4 μC from origin = 5 m

Therefore, for us to find the electric field intensity, we'll solve below:

The formula for Electric field intensity = ( k * q ) / ( r * r )

where , r is distance ,

k = 9 * 10^9 ,

and , q is charge .

now ,

electric field intensity at the origin = [ k * 10^(-6) / 1 * 1 ] +[ k * 2 * 10^(-6) / 2 * 2 ] + [ k * 3 * 10^(-6) / 3 * 3 ] + [ k * 4 * 10^(-6) / 5 * 5 ]

=> electric field intensity at the origin = k * 10^(-6) [ 1 + 1/2 + 1/3 + 4/25 ] N/C

=> electric field intensity at the origin = 9 * 10^9 * 10^(-6) * 1.99 N/C

=> electric field intensity at the origin = 17.94 kN/C

Answer:

Density = 10,933.93 kg/m^3

the density of the material is 10,933.93 kg/m^3

Explanation:

Density is the mass per unit volume

Density = mass/volume = m/V

Volume of a cylinder V = πr^2 h

Given;

Height h = 48.5mm = 0.0485 m

Radius r = diameter/2 = 49mm÷2 = 24.5mm = 0.0245m

Substituting the values;

Volume V = π×(0.0245^2)×0.0485

V = 0.000091458438030 m^3

V = 0.000091458 m^3

The mass is given as;

Mass = 1 kg

So, the density can be calculated as;

Density = 1/0.000091458

Density = 10933.92825785 kg/m^3

Density = 10,933.93 kg/m^3

the density of the material is 10,933.93 kg/m^3

━━━━━━━☆☆━━━━━━━

▹ Answer

B. Anxiety

▹ Step-by-Step Explanation

Anxiety isn't a behavior since it's a feeling. Behavior and feeling are different things therefore, anxiety is the correct answer.

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Eating, sleeping, and crying all are considered as behaviors. However, anxiety cannot be considered as a behavior because it is a feeling. Thus, the correct option is B.

Anxiety is an intense feeling of excessive, and persistent worry and the fear about everyday situations. This includes fast heart rate, rapid breathing, sweating, and feeling tired constantly may occur.

Behavior is the range of actions and mannerisms which are made by individuals, organisms, systems or the artificial entities in some environment. These systems can include other systems or organisms as well as the inanimate physical environment. Behaviors include eating, sleeping, and crying. Anxiety is not a behavior, it is a feeling.

Therefore, the correct option is B.

Learn more about Anxiety here:

https://brainly.com/question/28481974

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Answer:

The linear density is  [tex]K = 3.863 *10^{-3 } \ kg/m[/tex]

Explanation:

From the question we are told that

     The density of  steel is  [tex]\rho = 7800 \ kg/m^3[/tex]

      The diameter of the string is  [tex]d = 0.794 \ mm = 7.94 *10^{-4} \ m[/tex]

       The  radius of  the string is  evaluated as  [tex]r = \frac{D}{2} = \frac{7.94 *10^{-4}}{2} = 3.97*10^{-4} \ m[/tex]

The volume of the string is  mathematically evaluated as

       [tex]V = \pi * r ^2 * L[/tex]

Now assuming that the length of the string is  L = 2 m  

      So  

         [tex]V = 3.142 * (3.97 *10^{-4})^2 * (2)[/tex]

        [tex]V = 9.9041 *10^{-7} \ m^3[/tex]

Then the mass of the string would be  

       [tex]m = \rho * V[/tex]

substituting value  

       [tex]m = 7800*9.904 14 *10^{-7}[/tex]

      [tex]m = 7.73*10^{-3} \ kg[/tex]

Looking at the question we see that the unit of the linear density is  [tex]\frac{kg}{m}[/tex]

Hence the linear density is evaluated as

        [tex]K = \frac{m}{L}[/tex]

substituting value  

        [tex]K = \frac{7.73 *10^{-3}}{2}[/tex]

        [tex]K = 3.863 *10^{-3 } \ kg/m[/tex]

Answer:

1.007 × 10^(10) electron

Explanation:

We are given;

Electric Field;E = 1450 N/C

Diameter;d = 20 cm = 0.2 m

So, Radius: r = 0.2/2 = 0.1 m

Formula for Electric field just outside the sphere is given by the formula;

E = kq/r²

Where;

E is the magnitude of the electric field. q is the magnitude of the point charge r is distance from the point charge

k is a constant with a value of 9 x 10^(9) N.m²/C²

Making q the subject, we have;

q = Er²/k

Thus,

q = 1450 × 0.1²/(9 × 10^(9))

q = 1.61 × 10^(-9) C

Now, total charge q is also given by the formula;

q = Ne

Where;

e is charge on electron which is 1.6 × 10^(-19)

N is number of excess electrons

Making N the formula, we have;

N = q/e

N = (1.61 × 10^(-9))/(1.6 × 10^(-19))

N = 1.007 × 10^(10) electron

Answer:

C) There will be more electrons ejected

Explanation:

The number of electrons ejected whenever a photoelectric effect is identified it is proportional to the intensity of the incident light

Nevertheless, the photoelectrons' maximal kinetic energy is independent of their light intensity

Therefore, the maximum speed of the electron ejected doesn't really depend on the light intensity

So,  if the intensity rises, only the number of electrons ejected will rised

Therefore the option c is correct

Answer:

C) There will be more electrons ejected

Explanation:

In the photoelectric effect, photons with an energy of E are shone upon a piece of metal, and if the energy of the photons overcome the work function ϕ of the metal, then electrons with will be ejected from the metal with a kinetic energy KE.

E_photon = Φ + KE

Each photon is capable of ejecting one electron from the metal. Therefore, increasing the intensity of the light (the number of photons shone on the metal) will increase the number of electrons ejected from the metal.

Answer:

e

Explanation:

i took it myself and got it right

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

[tex]T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\[/tex]

Now, determine the amplitude of oscillation, A;

[tex]E = \frac{1}{2} kA^2[/tex]

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

[tex]E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm[/tex]

Therefore, the amplitude of the oscillation is 2.82 cm

Answer:

Explanation:

Magnetic field due to moving charge =

[tex]B=\frac{\mu_0}{4\pi} \times \frac{qv}{r^2}[/tex]

q is charge moving with velocity v and r is distance from point at which field is calculated .

For alpha particle

[tex]B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}[/tex]

= 0.1316 x 10⁻³ T

For electron

[tex]B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}[/tex]

= .0658 x 10⁻³ T .

Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .

Hence

Total magnetic field

= B₁ + B₂ = .1974 x 10⁻³

= 1.974 x 10⁻⁴ T .

The total magnetic field produced by these charges at the given point is 1.98 x 10⁻⁴ T.

The given parameters;

The magnetic field produced by each charge is calculated using Biot-Savart law;

[tex]B = \frac{\mu _o q}{4\pi } \times \frac{v}{r^2} \\\\B_1 = \frac{(4\pi \times 10^{-7} ) \times (1.602 \times 10^{-19})}{4\pi } \times \frac{2.8 \times 10^5}{(8.25 \times 10^{-9} )^2}\\\\B_1 = 6.6 \times 10^{-5} \ T[/tex]

[tex]B_2 = \frac{(4\pi \times 10^{-7} ) \times (2\times 1.602 \times 10^{-19})}{4\pi } \times \frac{2.8 \times 10^5}{(8.25 \times 10^{-9} )^2}\\\\B_2 = 1.32 \times 10^{-4} \ T[/tex]

The total magnetic field produced by these charges at the given point P;

[tex]B_T = B_1 + B_2\\\\B_T = 6.6\times 10^{-5} \ + \ 1.32 \times 10^{-4}\\\\B_T = 1.98 \times 10^{-4} \ T[/tex]

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Complete question:

The pv diagram in the figure below (see attached file) shows a process abc involving 0.920 of an ideal gas.

How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×10⁴ J ?

Answer:

The amount of heat required to increase the internal energy of the gas is 2,000 J

Explanation:

Work done in gas is given as;

W = ΔPV

The pressure of the gas at "a" = 2 x 10⁵ Pa

The pressure of the gas at "b" = 5 x 10⁵ Pa

The volume of the gas at "a" = 0.01 m³

The volume of the gas at "b" = 0.07 m³

The work done = (5 x 10⁵ Pa - 2 x 10⁵ Pa) x (0.07 m³ - 0.01 m³)

The work done = 3 x 10⁵ Pa x 0.06 m³

The work done = 18000 J

The work done = 1.8 x 10⁴ J

Determine, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴ J.

1.8 x 10⁴ J + H = 2.00 x 10⁴ J

H = 2.00 x 10⁴ J - 1.8 x 10⁴ J

H = 0.2 x 10⁴ J

H = 2,000 J

Therefore,  the amount of heat required to increase the internal energy of the gas by 2.00×10⁴J is 2,000 J

Answer:

5.3×10⁴ m/s

Explanation:

From the question,

Momentum = mass× velocity

M = mV................ Equation 1

Where M = momentum of the airplane, m = mass of the airplane, V = Velocity of the airplane

make V the subject of the equation

V = M/m.................. Equation 2

Given: M = 1.6×10⁹ Kg.m/s, m = 3.0×10⁴ kg

Substitute these values into equation 2

V = 1.6×10⁹/3.0×10⁴

V = 5.3×10⁴ m/s

Answer:

It would be 450 or 640. My final answer would be about 450

Explanation: Because it would't be to high if it was shot Voy = 100

btw i think i know what i know what i am talking about.

The answer would be about 450 m.

The top isn't the standard for a cliff to be reckoned as a cliff as such. Any steep rock face particularly at the edge of the sea can be specified as a cliff.

A 'clifftop' just refers to any pinnacle of a cliff. A 'plateau' is any flat extended geologic floor. An 'overhang' is a part of a structure or formation that protrudes from the primary frame and rests such that it is 'overhanging' the ground (striking above it).

Learn more about the height of the cliff here https://brainly.com/question/14524817

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Answer:

200volts

Explanation:

Pls see attached file

Answer:

100 V

Explanation:

Electric field E = 100 V/m

Potential at the origin = 300 V

Potential at point (-2m, 0) i.e 2 m behind the origin = ?

From the equation ΔV = EΔd,

ΔV = [tex]V_{0} - V_{x}[/tex]

where [tex]V_{0}[/tex] is the potential at origin,

and [tex]V_{x}[/tex] is the potential at point (-2, 0)

E = electric field

Δd = 0 - (-2) = 2 m

[tex]V_{0} - V_{x}[/tex] = 300 - [tex]x[/tex]

equating, we have

 300 - [tex]x[/tex] = 100 x 2

300 - [tex]x[/tex] = 200

[tex]x[/tex] = 100 V

Answer:

The temperature of molecules exhausted through the nozzle

is lower than the temperature in the chamber before being exhausted.

Explanation: