Q3. Recall the equation that links gravitational field
strength, mass and weight

Answer:

It takes the Sun's light 7.17 minutes to reach us.

Explanation:

We can calculate the time that takes the light to reach us by using the following equation:

[tex] t = \frac{d}{c} [/tex]    

Where:

d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m

c: si the speed of light = 2.99792x10⁸ m/s  

Hence, the time is:

[tex] t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min [/tex]

Therefore, it takes the Sun's light 7.17 minutes to reach us.

I hope it helps you!

Answer:

D. Compact fluorescent lightbulb

Explanation:

Compact fluorescent lightbulb

A compact fluorescent light bulb would produce the most energy in light

waves, therefore the correct option is D.

Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.

Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.

Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.

Learn more about electromagnetic radiation

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Answer:

work done=fdcosø

f=mg=450N

d=+3m

ø=180

450×3×cos(180°) power=work done/

time taken

1350×-1 p=135watts

Answer:

I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.

Explanation:

Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.

Please give me Brainliest!

v=u+at

v=0+8.0×30

v=240

Answer:

3.5kgm/s

Explanation:

We can calculate the momentum of Julieta

momentum = m(v-u)

Momentum = 0.2(20-2.5)

Momentum = 0.2(17.5)

Momentum = 3.5

Hence the momentum of Julieta is 3.5kgm/s

Answer:

The correct option is (d). "3x stronger".

Explanation:

The force between two charged particle is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

If one charge is tripled, [tex]q_1'=3q[/tex]

New force will be :

[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]

It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.

Given :

A solution contained 0.05g of sodium hydroxide in 25 cm3 of water.

To Find :

The concentration of the solution in g/dm³.

Solution :

We know, 1 cm = 0.1 dm

So, 1 cm³ = 0.001 dm³

Now, 25 cm³ = 25 × 0.001 dm³

25 cm³ = 0.025 dm³

Now, concentration of the solution in g/dm³ is [tex]\dfrac{0.05\ g}{0.025\ dm^3} = 2 \ g/dm^3[/tex].

Therefore, the concentration of the solution is  2 g/dm³.

Answer:

(10 L)(100° C) + (90 L)(10°) = (100 L)T

1,000 + 900 = 100T

1,900 = 100T

100T = 1,900

T = 1,900/100

Explanation:

Answer:

1) q₃ is approximately -7.58 nC

2) The direction of the net force on 'q₃' is the negative '-' direction

3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

Explanation:

1) The force, 'F', between two charged spheres is given as follows;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]

The net force acting on the point charge, 'q₃', is given as follows;

[tex]F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}[/tex]

By substituting the given values, we have;

[tex]F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}[/tex]

[tex]3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}[/tex]

[tex]\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}[/tex]

K = 9 × 10⁹ N·m²·C⁻²

[tex]\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC[/tex]

q₃ ≈ -7.58 nC

2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin

The net force's direction on q₃ will be in the '-' direction

3) For zero net force, we have;

The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m

Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1

By substitution, we have;

[tex]0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)[/tex]

[tex]\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}[/tex]

From which we have;

[tex]\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}[/tex]

(r₁)²×4.10 = 2.20 × (0.57 - r₁)²

From the above equation, we have;

95,000·r₁²+ 125,400·r₁-35739 = 0

Solving, using a graphing calculator we get;

r₁ ≈ 0.241 or r₁ ≈ -1.561

Where, 'r₁', is measured from 'q₂', therefore, we have;

r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881

Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero

Answer:

v = 9.34 m/s

Explanation:

Given that,

The distance between crests, [tex]\lambda=14\ m[/tex]

The vertical distance from trough to crest = 3.6 m

Time taken, t = 1.5 s

The amplitude of wave = vertical distance from trough to crest /2

= 3.6/2

= 1.8 m

The speed of the wave is given by :

[tex]v=f\times \lambda\\\\=\dfrac{\lambda}{T}\\\\=\dfrac{14}{1.5}\\\\=9.34\ m/s[/tex]

So, the speed of the wave is 9.34 m/s.

Answer:

40 mph

Explanation:

pls mark as brainliest

F₂ = 1.723 x 10⁸ N

Given

Area of small piston : 0.004 m²

Area of large piston : 3.5 m²

Force 225 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

225/0.004 m² = F₂/3.5² m²

F₂ = 1.723 x 10⁸ N

The velocity at the bottom : v = 8.85 m/s

Given

height of the hill = 4 m

Required

The velocity at the bottom

Solution

The law of conservation energy :

ME₁=ME₂

(PE+KE)₁ = (PE+KE)₂

initially at rest⇒vo=0⇒KE₁=0

At the bottom⇒h=0⇒PE₂=0

So the equation becomes :

PE₁=KE₂

mgh=1/2.mv²

gh = 1/2v²

[tex]\tt v=\sqrt{2gh}[/tex]

v = √2x9.8x4

v = 8.85 m/s

Answer:

I haven't learnt physics at all yet but I'll try.

After the two cars collide, they move at 6 m/s.

This tells us that the 2nd car which collided with the first car which is 2000 kg is much heavier than the 1st one, if the second one was lighter, the two cars coupled together speed would be much more than just 6 m/s.

Refer to explanation for working.

Explanation:

Now find out how much g or kg is the 2nd car more than the 1st.

2000 ÷ 10 = 200 (I don't really know how to explain this part)

10 - 6 = 4 (Difference for 1st car average speed per second and the coupled cars average speed per second)

200 x 4 = 800

2000 + 800 = 2800 kg

(Final answer)

Answer:

59.18 kg

Explanation:

use f=ma

f= 580 N

a = 9.8 m/s 2

weigh(m) doesn't change only force(F) changes

Answer: 219.6N

Explanation:

Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma

580 = m*9.8

m = 59.18kg

Then multiply the mass by the new gravitational acceleration on Mars.

59.18*3.711 = 219.6N

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

[tex]\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\[/tex]

(A) the magnitude of its angular acceleration(rad/s^2);

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2[/tex]

(B) Time of motion;

[tex]\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s[/tex]

Answer: The metal is iron.

Explanation:

We have 59.1 grams of a given metal.

We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C

First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.

ΔT = 59.6°C - 26.1°C = 33.5°C

Now we can find the specific heat, which is calculated as:

c = Ε/(ΔT*m)

Where:

E = energy given to the material = 890.9 J

m = mass of the material = 59.1 gr

ΔT = change in temperature = 33.5°C

Replacing these in the above equation we get:

c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)

Now we need to look at a table of specific heats and see which metal has this specific heat.

We can see that iron is the best match, so we can assume that the metal is iron.

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.

Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body

An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.

An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.

The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.

The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.

Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.

To learn more about Newton's third law refer to the link;

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Answer:

it is somewhat frozen

Explanation:

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

Answer:

the bike

Explanation:

it has less mass than the motorcycle so so it would have more acceleration

Answer:

A

Explanation:

Answer:

The magnitude of the boat's velocity is 8.21 km/h.

Explanation:

We can find the boat's velocity as follows:

[tex] \Epsilon V_{x} = V_{w_{x}} + V_{b_{y}} [/tex]            

[tex] \Epsilon V_{y} = V_{w_{y}} + V_{b_{y}} [/tex]

Where:

[tex]V_{w_{x}}[/tex] and [tex]V_{w_{y}}[/tex] are the components of the velocity of the water in the x and y-direction

[tex]V_{b_{x}}[/tex] and [tex]V_{b_{y}}[/tex] are the components of the velocity of the boat in the x and y-direction

Since the angle is 15° we have:

[tex] \Epsilon V_{x} = -4.0 km/h*sin(15) + 0 = -1.04 km/h [/tex]  

[tex] \Epsilon V_{y} = 4.0 km/h*cos(15) - 12.0 km/h = -8.14 km/h [/tex]

Now, the velocity of the boat is:  

[tex] V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{(-1.04 km/h)^{2} + (-8.14 km/h)^{2}} = 8.21 km/h [/tex]

Therefore, the magnitude of the boat's velocity is 8.21 km/h.

I hope it helps you!

Answer:

a. Force = 30N

b. Fnet = 128N

Explanation:

Given the following data;

Mass = 10 kg

Acceleration = 3m/s²

a. To find the force;

Force = mass * acceleration

Substituting into the equation, we have

Force = 10 * 3

Force = 30N

b. To find the net force;

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

We know that acceleration due to gravity is equal to 9.8m/s²

To find the gravitational force;

We know that acceleration due to gravity, g = 9.8m/s²

Fg = mg = 10*9.8 = 98N

Substituting into the equation, we have;

Fnet = 30 + 98

Fnet = 128N

Answer:

The net charge on each sphere is -1.5 q

Explanation:

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]

The net charge on each sphere, Q = -1.5 q.

The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]

Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

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The organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.

The function of human insulin is to maintain the blood sugar level by converting the active form of sugar which is glucose into the stored form of glycogen in order to maintain the blood sugar level.

In this modern era of science and technology, recombinant human insulin is mainly synthesized or produced with the help of organisms like E. Coli which is classified in the category of bacteria, and Saccharomyces cerevisiae which is classified in the category of unicellular fungus.

Therefore, the organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.

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