Answer:
This is proved using Proof by induction method. There are two steps in this method
Let P(n) represent the given statement ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
1. Basis Step: This step proves the given statement for n = 1
2. Induction step: The step proves that if the given statement holds for any given case n = k then it should also be true for n = k + 1.
If the above two steps are true this means that given statement P(n) holds true for all positive n and the mathematical induction P(n): ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] is true.
Step-by-step explanation:
Basis Step:
For n = 1
∪[tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] = ∪[tex]{ {{1} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] = A₁ ⊆ B₁ = ∪[tex]{ {{1} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] = ∪[tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
We show that
∪[tex]{ {{1} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] = A₁ ⊆ B₁ = ∪[tex]{ {{1} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] for n = 1
Hence P(1) is true
Induction Step:
Let P(k) be true which means that we assume that:
for all k with k≥1, P(k): ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] is true
This is our induction hypothesis and we have to prove that P(k + 1) is also true
This means if ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] holds for n = k then this should also hold for n = k + 1.
In simple words if P(k): ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] is true then ∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] is also true
∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] = ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ∪ [tex]A_{k+1}[/tex]
⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] ∪ [tex]A_{k+1}[/tex] As ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] ∪ [tex]B_{k+1}[/tex] As [tex]A_{k+1}[/tex] ⊆ [tex]B_{k+1}[/tex]
= ∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
The whole step:
∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] = ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ∪ [tex]A_{k+1}[/tex] ⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] ∪ [tex]A_{k+1}[/tex] ⊆ ∪[tex]{ {{k} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] ∪ [tex]B_{k+1}[/tex] = ∪[tex]{ {{k+1} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
shows that the P(k+1) also holds for ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex]
hence P(k+1) is true
So proof by induction method proves that P(n) is true. This means
P(n): ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]A_{j}[/tex] ⊆ ∪ [tex]{ {{n} \atop {j=1}} \right.[/tex] [tex]B_{j}[/tex] is true
Jeff worked 4 and 2/3 hours in the morning and 3 and 3/4 hours in the afternoon. How many total hours did he work
1. 8 and 1/2 hours
2.7 and 5/7 hours
3.7 and 5/12 hours
4.8 and 5/12 hours
Answer:
4. 8 5/12
Step-by-step explanation:
4 2/3 + 3 3/4 =
= 4 + 2/3 + 3 + 3/4
= 4 + 3 + 8/12 + 9/12
= 7 + 17/12
= 7 + 12/12 + 5/12
= 7 + 1 + 5/12
= 8 5/12
Write an equation that expresses the following relationship. w varies directly with u and inversely with d In your equation, use k as the constant of proportionality.
Step-by-step explanation:
solution.
if variable d increases then w reduces
w=k.u ×1/d
=ku/d
therefore w=k.u/d
If nine of every 11 trick-or-treaters that came to your house last Halloween were dressed as pirates what proportion of trick-or-treaters were not dressed as pirates
Answer:
11 - 9 = 2 trick-or-treaters out of 11 were not dressed as pirates so the proportion is 2/11.
Answer: Ratio is 2:11
Step-by-step explanation:
So your ratio of pirates to non-pirates would be 9:11
So you subtract number of pirates from total trick-or-treaters and get 2.
So the proportion of non-pirates would be 2:11.
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one particular
customer for the past 20 months. Use the given data to answer parts (a) and (b).
325 517 424 395 494
396 351 379 408 426
523 421 434 373 456
535 394 437 403 513
(a) Determine the standard deviation and interquartile range of the data.
s=(Round to two decimal places as needed.)
Answer:
The answer is: 325 517 424 395 494
Step-by-step explanation:
The profit, in thousands of dollars, from the sale of x thousand candles can be estimated by P(x) = 5 x - 0.7 x ln x.
1) Find the marginal profit, P'(x).
2) Find P'(10), and explain what this number represents. What does P'(10) represent?
A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
B. The additional profit, in thousands of dollars, when 10,000 candles are sold.
C. The additional cost, in thousands of dollars, to produce a thousand candles once 10,000 candles have already been sold.
D The additional cost, in thousands of dollars, to produce 10,000 candles.
C. How many thousands of candles should be sold to maximize profit?
1) The marginal profit is [tex]4.3 - 0.7 ln(x)[/tex].
2) The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
Thus, option (A) is correct.
C) To maximize profit 462,481 thousands of candles should be sold.
Given: [tex]P(x) = 5 x - 0.7 x[/tex] [tex]{\text}ln x.[/tex]
1) Take the derivative of the profit function P(x) with respect to x.
P(x) = 5x - 0.7x ln(x)
To find P'(x), differentiate each term separately using the power rule and the derivative of ln(x):
[tex]P'(x) = 5 - 0.7(1 + ln(x))[/tex]
= [tex]5 - 0.7 - 0.7 ln(x)[/tex]
= [tex]4.3 - 0.7 ln(x)[/tex]
2) Substitute x = 10 into the derivative:
P'(10) = 4.3 - 0.7 ln(10)
= 4.3 - 0.7(2.30259)
= 4.3 - 1.61181
= 2.68819
Therefore, the additional profit for selling a thousand candles once 10,000 candles have already been sold.
Thus, option (A) is correct.
C) Set P'(x) = 0 and solve for x:
[tex]4.3 - 0.7 ln(x) = 0[/tex]
[tex]0.7 ln(x) = 4.3[/tex]
[tex]{\text} ln(x) = 4.3 / 0.7[/tex]
[tex]{\text} ln(x) = 6.14286[/tex]
[tex]x = e^{6.14286[/tex]
[tex]x = 462.481[/tex]
Therefore, 462,481 thousands of candles should be sold.
Learn more about Derivative here:
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1) The marginal profit, P'(x), is -0.7ln(x) + 4.3.
2) The number of thousands of candles that should be sold to maximize profit is approximately 466.9.
1) To find the marginal profit, P'(x), we need to take the derivative of the profit function, P(x), with respect to x. Using the power rule and the chain rule, we can differentiate the function:
P(x) = 5x - 0.7x ln(x)
Taking the derivative with respect to x:
P'(x) = 5 - 0.7(ln(x) + 1)
Simplifying:
P'(x) = 5 - 0.7ln(x) - 0.7
P'(x) = -0.7ln(x) + 4.3
2) To find P'(10), we substitute x = 10 into the marginal profit function:
P'(10) = -0.7ln(10) + 4.3
Using a calculator, we can evaluate this expression:
P'(10) ≈ -0.7(2.3026) + 4.3 ≈ -1.6118 + 4.3 ≈ 2.6882
The value of P'(10) is approximately 2.6882.
Now, let's interpret what P'(10) represents:
The correct interpretation is A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
P'(10) represents the rate at which the profit is changing with respect to the number of candles sold when 10,000 candles have already been sold. In other words, it measures the additional profit (in thousands of dollars) for each additional thousand candles sold once 10,000 candles have already been sold.
Lastly, to determine the number of thousands of candles that should be sold to maximize profit, we need to find the critical points of the profit function P(x). This can be done by setting the derivative P'(x) equal to zero and solving for x.
-0.7ln(x) + 4.3 = 0
-0.7ln(x) = -4.3
ln(x) = 4.3 / 0.7
Using properties of logarithms:
x = e^(4.3 / 0.7)
Using a calculator, we can evaluate this expression:
x ≈ e^(6.1429) ≈ 466.9
for such more question on marginal profit
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PLSS GUYS I NEED HELP
Answer:
Option B. is the right choice.
Step-by-step explanation:
f(-3) = 3 and f(3) = 5 (First and the last column of table B)
Best Regards!
A ball is thrown upward off of a 100 meter cliff with an initial velocity of 6 m/s. The function f(x)=-5x2+6x+100 (graphed below) represents this situation where x is time and y is the distance off of the ground. will mart brainliest yeah
Answer:
a) The domain of the function is [tex]x \geq 0\,s[/tex] [tex]\wedge[/tex] [tex]x \leq 5.112\,s[/tex]. [tex][0\,s, 5.112\,s][/tex], [tex]\forall x \in \mathbb{R}[/tex], b) The range of the function is [tex]0\,m \leq y \leq 100\,m[/tex]. [tex][0\,m,100\,m][/tex], [tex]\forall y\in \mathbb{R}[/tex], c) The ball is 73 meters off of the ground at x = 3 seconds.
Step-by-step explanation:
The complete statement is: A ball is thrown upward off of a 100 meter cliff with an initial velocity of 6 m/s. The function [tex]f(x) = -5\cdot x^{2} + 6\cdot x + 100[/tex] represents this situation where x is time and y is the distance off of the ground.
a) What domain does the function make sense?
b) What range does the function make sense ?
c) How far off the ground is the ball at time x = 3 seconds?
a) Let [tex]x[/tex] and [tex]f(x)[/tex] be the time, measured in seconds, and the distance of the ground, measured in meters, respectively. Time is a positive variable, so domain corresponds to the interval when [tex]f(x) \geq 0[/tex] and [tex]t \geq 0[/tex]. That is:
[tex]-5\cdot x^{2} + 6\cdot x + 100 \geq 0[/tex]
[tex]-(x-5.112\,s)\cdot (x+3.912\,s) \geq 0[/tex]
Therefore, the domain of the function is [tex]x \geq 0\,s[/tex] [tex]\wedge[/tex] [tex]x \leq 5.112\,s[/tex]. [tex][0\,s, 5.112\,s][/tex], [tex]\forall x \in \mathbb{R}[/tex]
b) The distance off of the ground is also a positive variable, where ball is thrown upward at a height of 100 meters and hits the ground at a height of 0 meters. Hence, the range of the function is [tex]0\,m \leq y \leq 100\,m[/tex]. [tex][0\,m,100\,m][/tex], [tex]\forall y\in \mathbb{R}[/tex]
c) The distance of the ball off of the ground at x = 3 seconds is found by evaluating the function:
[tex]f(3\,s) = -5\cdot (3\,s)^{2} + 6\cdot (3\,s) + 100[/tex]
[tex]f(3\,s) = 73\,m[/tex]
The ball is 73 meters off of the ground at x = 3 seconds.
What is the simplified value of this expression pls help
Answer:
7
Step-by-step explanation:
Remove parentheses.
[tex]\frac{-8+4(4.5)}{6.25-8.25} \\[/tex]
Add −8 and 4.5.
[tex]\frac{4(-3.5)}{6.25 - 8.25} \\\\[/tex]
Subtract 8.25 from 6.25.
[tex]\frac{4*-3.5}{-2}[/tex]
Multiply 4 by −3.5.
[tex]\frac{-14}{-2}[/tex]
Divide −14 by −2.
= 7
. A box contains four red, three yellow, and seven green balls. Three balls are randomly selected from the box without replacement. (a) What is the probability that all three balls are the same colo
Answer:
10/91
Step-by-step explanation:
Number of Red balls = 4
Number of Yellow balls = 3
Number of green balls=7
Total=4+3+7=14
If we pick three balls of the same color, there are three possibilities: (All Red, All Green Or all Yellow).
Therefore:
The probability that all three balls are the same color (note that the selections are without replacement)
=P(RRR)+P(GGG)+P(YYY)
[tex]=(\frac{4}{14} \times \frac{3}{13} \times \frac{2}{12})+(\frac{3}{14} \times \frac{2}{13} \times \frac{1}{12})+(\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12})\\\\=\frac{1}{91} + \frac{1}{364}+ \frac{5}{52}\\\\=\frac{10}{91}[/tex]
The probability that all three balls are the same color is 10/91.
From a group of graduate students including 25 men and 22 women, 37 are chosen to participate in a presentation. What is the probability that exactly 19 men and 18 women are chosen
Answer:
25.02% probability that exactly 19 men and 18 women are chosen
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the men and the women are selected is not important, so we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Desired outcomes:
19 men, from a set of 25
18 women, from a set of 22
[tex]D = C_{25,19}*C_{22,18} = \frac{25!}{19!6!}*\frac{22!}{18!4!} = 1295486500[/tex]
Total outcomes:
37 people from a set of 25 + 22 = 47. So
[tex]T = C_{47,37} = \frac{47!}{37!10!} = 5178066751[/tex]
Probability:
[tex]p = \frac{D}{T} = \frac{1295486500}{5178066751} = 0.2502[/tex]
25.02% probability that exactly 19 men and 18 women are chosen
can anyone help me with this?
Answer: 16y² - x²
Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)
10 is not a square so that one is eliminated (though the y² and the 4x² are squares)
16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.
Mario and tabitha are calculating the probability of getting a 4 and a 2 if they roll a die twice. Who is correct?
Answer:
[tex]\frac{2}{12}[/tex] simplified to [tex]\frac{1}{6}[/tex]
Step-by-step explanation:
4 = [tex]\frac{1}{12}[/tex]
2 = [tex]\frac{1}{12}[/tex]
[tex]\frac{1}{12}[/tex] + [tex]\frac{1}{12}[/tex] = [tex]\frac{2}{12}[/tex] ÷ 2 = [tex]\frac{1}{6}[/tex]
A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?
Answer:
3lbs
Step-by-step explanation:
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets.
Complete Question
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.
Answer:
Yes it is possible to take the 9 children and 4 adults to both shows
Step-by-step explanation:
From the question we are told that
The cost of the Matinee tickets for a child is z = $4
The cost of the Matinee tickets for an adult is a = $ 4
The cost of the Evening tickets for a child is k = $6
The cost of the Evening tickets for an adult is b = $8
The maximum amount to be spent on Matinee tickets is m = $80
The maximum amount to be spent on Evening tickets is e = $100
The number of child to be taken to the movies is n = 9
The number of adults to be taken to the movies is j = 4
Now the total amount of money that would be spent on Matinee tickets is mathematically evaluated as
[tex]t = 4 n + 4 j[/tex]
substituting values
[tex]t = 4 * 9 + 4* 4[/tex]
[tex]t = 52[/tex]
Now the total amount of money that would be spent on Evening ticket is mathematically evaluated as
[tex]T = 6n + 8j[/tex]
substituting values
[tex]T = 6(9) + 8(4)[/tex]
[tex]T = 86[/tex]
This implies that it is possible to take 9 children and 4 adults to both shows
given that
[tex]t \le m[/tex]
i.e $56 [tex]\le[/tex]$ 80
and
[tex]T \le e[/tex]
i.e $ 86 [tex]\le[/tex] $ 100
Toby cuts a pizza into 6 equal slices. He eats half a slice. What fraction of the pizza has he eaten?
The pizza is cut into 6 slices so each slice would be 1/6 of the pizza.
He at 1/2 of a slice:
1/6 x 1/2 = 1/12 of the pizza
find the value of x if (1.1)^x=100
Answer:
x ≈ 48.3177
Step-by-step explanation:
This is what logarithms are for (among other things).
log(1.1^x) = log(100)
x·log(1.1) = 2
x = 2/log(1.1) ≈ 48.3177
Three polynomials are factored below but some coefficients and constants are missing. all of the missing values of a, b, c and d are integers. 1. x^2 +2x-8=(ax+b)(cx+d) 2. 2x^3+2x^2-24x=2x(ax+b)(cx+d) 3. 6x^2-15x-9=(ax+b)(cx+d) Fill in the table with the missing values of a,b,c and d.
Answer:
1) d = 42) b = -3. c = 1 3) a = 3 and d = 1Step-by-step explanation:
To get the missing values in the table, we will factorize the given expression and compare the factored expression with the expression containing the missing constants.
1) For the expression x²+2x-8, on factorizing we have;
x²+2x-8
= (x²+4x)-(2x-8)
Factoring out the common terms from both parenthesis;
= x(x+4)-2(x+4)
= (1x+4)(1x-2)
= (1x-2)(1x+4)
Comparing the resulting expression with (ax+b)(cx+d)
a = 1, b = -2, c = 1 and d = 4
2) For the expression 2x³+2x²-24x
Factoring out the common term we will have;
= 2x(x²+x-12)
= 2x(x²-3x+4x-12)
= 2x{x(x-3)+4(x-3)}
= 2x{(x+4)(x-3)}
= 2x(1x-3)(1x+4)
Comparing the resulting expression with 2x(ax+b)(cx+d)
a = 1, b = -3. c = 1 and d = 4
3) For the expression 6x²-15x-9 we will have;
On simplifying,
= 6x²+3x-18x-9
= 3x(2x+1)-9(2x+1)
= (3x-9)(2x+1)
Comparing the resulting expression with (ax+b)(cx+d)
a = 3, b = -9, c = 2 and d = 1
Answer:
see picture attachment
Step-by-step explanation:
Select the correct answer from each drop-down menu. Gino is buying wood screws at the corner hardware store. The table shows different numbers of bags of screws and their corresponding prices. Bags of Screws Price ($) 2 10 4 20 7 35 According to the table, the relationship between the number of bags and the price is proportional or not proportional
pls help me help me
Answer:
A
Step-by-step explanation:
Jason has bought a new pool and has already measured some of the sides. Using the figure below and your knowledge of quadrilaterals, solve for x and y.
Answer:
x = 12
y = 12
Step-by-step explanation:
Each triangle is a right angle triangle
5² + x² = 13²
x² = 169 - 25
x = √144
x = 12
The shape is a parallelogram
Therefore
x = y
y = 12
WHO CAN HELP ME WITH MY ACCOUNTING HOMEWORK???
Duran Manufacturing uses a process costing system and manufactures its product in three departments. Which of the following is NOT a way in which Duran can use the cost per unit of each process?
A) Duran can look for ways to cut the costs when actual process costs are more than planned process costs.
B) Duran needs to set the selling price to cover the costs of making the product and provide a profit.
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
D) Duran needs to know the ending balances in the following accounts: Work-In-Process Inventory, Finished Goods Inventory, and Cost of Goods Sold.
Answer:
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
Step-by-step explanation:
Duran uses cost accounting technique to identify cost per unit for its products. The costing techniques allows us to identify the cost of unit that are not completely finished. It is not necessary that all unit must be completed in order to find out the cost per unit of the product. The process costing is the best method to identify cost per unit for products that are in process.
3.
A passenger jet can fly 1,290 mil
in 3 hours with a tailwind bi
1,230 miles in 3 hours
headwind. Find the speed
the Jet in Still air and the
of the wind.
Answer:
Jet= 420 mph Wind = 10mph
Step-by-step explanation:
The speed of the plane in a tailwind can be modeled by x+y where x is the speed of the plane and y is the speed of the wind. Dividing 1290 by 3 gets you the average speed of the jet in a tailwind, which is 430.
The speed of the plane in a headwind can be modeled by x-y where x is the speed of the plane and y is the speed of the wind. Dividing 1230 by 3 gets you the average speed of the jet in a tailwind, which is 410.
This can be modeled by a system of equations, where x+y=430 and x-y=410. Solving the equation you get x=420 and y=10.
So, the speed of the jet is 420 mph and the speed of the wind is 10 mph.
Which of the following functions is graphed below?
Answer:
C
Step-by-step explanation:
C is the solution
Answer:
Option C
Step-by-step explanation:
The graph is a horizontal translation 4 units left and a vertical translation 2 units down ⇒ y= |x+4|-2
Which point is a solution to the inequality shown in this graph?
5
(3,-1)
(-3,-3)
O A. (5,-5)
O B. (1,5)
C. (-3,-3)
D. (3, -1)
Hey there!
To find the answer, we just need to see which point falls in this blue, which represents the inequality.
We see that the point (5,-5) is not on the blue.
We see that the point (1,5) is on the blue.
(-3,-3) is on the dotted line but not a solution of the inequality. The dotted line is excluded from the inequality. If it were a bold line, then it would be a solution of the inequality.
(3,-1) is also on the dotted line so it is not a solution.
Therefore, the answer is B. (1,5)
I hope that this helps!
We want to see which point is a solution for the graphed inequality.
We will find that the correct option is B, (1, 5)
Notice that the line that defines the inequality contains the points (-3, -3) and (3, -1)
Then the slope of that line is:
[tex]a = \frac{-1 -(-3)}{3 - (1)} = 1/2[/tex]
Then the line is something like:
y = (1/2)*x + b
To find the value of b, we use the fact that this line passes through the point (3, -1), then we have:
-1 = (1/2)*3 + b
-1 - 3/2 + b
-5/2 = b
So the line is:
y = (1/2)*x - 5/2
And we can see that the line is slashed, and the shaded area is above the line, then we have:
y > (1/2)*x - 5/2
Now that we have the inequality, we can just input the values of the points in the inequality and see if this is true.
First, options C and D can be discarded because these points are on the line, and the points on the line are not solutions.
So we only try with A and B.
A) x = 5
y = -5
then we have:
-5 > (1/2)*5 - 5/2
-5 > 0
Which clearly is false.
B) x = 1
y = 5
Then we have:
5 > (1/2)*1 - 5/2 = -4/2
5 > -4/2
This is true, then the point (1, 5) is a solution.
Thus the correct option is B.
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Hunter is 9 years older than 3 times the age of his nephew. Hunter is 33 years old. How old is his nephew?
Answer:
8 years old.
(3x+9)
(3(8)+9)=33
Choose the name of the highlighted part of the figure.
O A.
side
OB.
Vertex
O c. angle
Which of the following shows the intersection of the sets? {1, 5, 10, 15} {1, 3, 5, 7}
Answer:
{1,5}
Step-by-step explanation:
The intersection of the sets are all of the numbers that appear in both sets. In this case, the only numbers that appear in both are 1 and 5.
Answer:
{ 1,5}
Step-by-step explanation:
The intersection is what the two sets have in common
{1, 5, 10, 15}∩ {1, 3, 5, 7}
= { 1,5}
Andrea and Helen participated in a donut eating contest. Andrea ate six more than four times the number of donuts that Helen ate. Let d represents the number of donuts Helen ate. Write the expression that gives the number of donuts that Andrea ate.
Answer:
4d + 6
Step-by-step explanation:
Helen ate d donuts.
Andrea ate 6 more than 4 times d.
4d + 6
The equation x2 − 6x − 27 = 0 when solved is:
Answer:
-3 , 9
Step-by-step explanation:
Sum = - 6
Product = -27
Factors = 3, -9
x² - 6x-27 = 0
x² + 3x - 9x - 9*3 = 0
x(x + 3) - 9(x + 3) = 0
(x + 3) (x - 9) = 0
x +3 = 0 ; x - 9 = 0
x = - 3 ; x = 9
Solution: x = -3 , 9
Give the three-letter name of each of the angles in the drawing below. Lines and Angles a. ∠1 b. ∠2 c. ∠3 d. ∠4
Answer:
a. AEB
b. BEC
c. CED
d. AED
Step-by-step explanation:
Each angle is made up of three points. All three points in order is the name of the angle.
Answer:
a. ∠1 = ∠AEB or ∠BEA
b. ∠2 = ∠BEC or ∠CEB
c. ∠3 = ∠CED or ∠DEC
d. ∠4 = ∠DEA or ∠AED
Step-by-step explanation: Penn <3