Answer:
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
Explanation:
just took test
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Balanced force is when the net force applied on the object is zero than said to be balanced.
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
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How much work is done by the gravitational force on the block?
Answer:
Work = Mass * Gravity * Height and is measured in Joules. Imagine you find a 2 -Kg book on the floor and lift it 0.75 meters and put it on a table. Remember, that “force” is simply a push or a pull. If you lift 100 kg of mass 1-meter, you will have done 980 Joules of work.
Explanation:
An object of mass 3.00 kg, moving with an initial velocity of 5.05 m/s, collides with and sticks to an object of mass 2.76 kg with an initial velocity of -3.66 m/s. Find the final velocity of the composite object.
Answer:
0.752 m/s
Explanation:
m1 = 3.00kg
u1 = 5.05m/s
m2 = 2.76kg
u2 = -3.66m/s
According to the law of conservation of momentum,
m1u1 + m2u2 = (m1+m2)v
3(5.05) + 2.76(-3.66) = (5.05+2.76)v
15.15 - 9.2736 = 7.81v
5.8764 = 7.81v
v = 5.8764/7.81
v = 0.752m/s
A 4.5 kg puffer fish expands to 40% of its mass by taking in water. When the puffer fish is threatened, it releases the water toward the threat to move quickly forward. What is the ratio of the speed of the puffer fish forward to the speed of the expelled water backwards?
Answer:
2:5
Explanation:
We have the initial mass of the fish = 4.5kg
The mass of water intake = 40%of 4.5kg
= 0.40x4.5kg
= 1.8kg
The formula for conserving momentum
M1V1 = M2V2
M1 = mass of the puffer fish = 4.5kg
M2 = mass of the applied water = 1.8kg
V1 = velocity of the puffer fish
V2 = velocity of water
We are then to find v1/v2
V1/V2 = M2/M1
V1/V2 = 1.8/4.5
= 1/2.5
This is also 2/5
Therefore we have the ratio to be 2:5
Heidi (39 kg) is walking her tiny chihuahua, Chaxi (5.60 kg), on the sidewalk. To encourage Chaxi along, Heidi pulls forward with a force of 9.55 N. Identify the correct reaction force in response to Heidi’s action force.
a. The friction is less than 660 N since the beam can be moved at a constant velocity.
b. There is no friction acting on the beam since it is accelerating.
c. The friction is equal to 660 N since the beam is not accelerating.
d. The friction is greater than 660 N since the beam is not in equilibrium.
Answer:
The correct reaction force in response to Heidi's action force is:
c. The friction is equal to 660 N since the beam is not accelerating.
Explanation:
Heidi's action force does not affect the beam. Since friction resists the sliding or rolling of one solid object over another, there is no friction acting on the beam, in this respect. The reaction force is what makes the dog to move because it acts on it. According to Newton's Third Law of Motion, forces always come in action-reaction pairs. This Third Law states that for every action force, there is an equal and opposite reaction force. This means that the dog exerts some force on Heidi, as he pulls it "forward with a force of 9.55 N."
If the particles were moving with a speed much less than c, the magnitude of the momentum of the second particle would be twice that of the first. However, what is the ratio of the magnitudes of momentum for these relativistic particles?
Answer:
p₂ / p₁ = 2 (v₁ / v₂)
Explanation:
The moment is a very useful concept, since it is one of the quantities that is conserved during shocks and explosions, for which it had to be redefined to be consistent with special relativity,
p = m v / √[1+ (v/c)² ]
for the case of speeds much lower than the speed of light this expression is close to
p = m v
In this exercise they indicate that the moment of the second particle is twice the moment of the first, when their velocities are small
p₂ = 2 p₁
p₂/p₁ = 2
in consecuense
m v₂ = 2 m v₁
v₂ = 2 v₁
consider particles of equal mass.
By the time their speeds increase they enter the relativistic regime
p₂ = mv₂ /√(1 + v₂² /c²)
p₁ = m v₁ /√(1 + v₁² / c²)
let's look for the relationship between these two moments
p₂ / p₁ = mv₂ / mv₁ [√ (1+ v₁² / c²) /√ (1 + v₂² / c²)
from the initial statement
p₂ / p₁ = 2 √(c² + v₁²) / (c² + v₂²)
we take c from the root
p₂ / p₁ = 2 √ [(1+ v₁²) / (1 + v₂²)]
this is the exact result, to have an approximate shape suppose that the velocities are much greater than 1
p₂ / p₁ = 2 √ [v₁² / v₂²] = 2 √ [(v₁ / v₂)²]
p₂ / p₁ = 2 (v₁ / v₂)
we see the value of the moment depends on the speed of the particles
answer plz answer plzzz I am a little confused with full time
(b) In the USA, drones are not allowed to be flown too high above the ground.
Suggest one possible risk of flying a drone too high above the ground.
Plz complete thank you in advance
The 400-foot altitude limit was put in place for the sake of airspace safety, and there is a risk to country security as well as the privacy of citizens.
What are drones?Unmanned aerial vehicles (UAVs), sometimes known as drones, are used for a variety of jobs, from routine to extremely dangerous. These robotic-looking planes can be seen practically everywhere, from delivering groceries to your home to rescuing avalanche victims.
The 400-foot altitude restriction was ultimately implemented for airspace safety. Given the breadth of the airspace above 400 feet, the likelihood of a drone colliding with a human aircraft is exceedingly remote, but the consequences might be disastrous.
Any aerial vehicle that uses software to fly autonomously or that may be controlled remotely by a pilot is referred to as a drone. Numerous drones come equipped with cameras to gather visual data and propellers to stabilize flying paths. Drone technology has been incorporated into industries like videography, search and rescue, agriculture, and transportation.
When in uncontrolled (Class G) airspace, your drone must be flown 400 feet above the ground or less.
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True or False when an object speeds up it gains momentum
Answer: True
Explanation:
5.
An 80 newton force and a 45 newton force act on an object
as shown below.
80 N
30°
4S N
Which of the following vectors would bets represent an
equilibrant when added to this system?
(1) 24 N to the left (3) 24 N to the right
(2) 114 N to the right (4) 45 N to the left
Tirant Showroiculations
Answer:
the answer is a time your welcome
Answer:
(1)
Explanation:
2) What does the specific heat capacity of a material tell you about how easy it is to heat up
that material
Answer:
High specific heat -> takes more energy to raise/lower object's temperature
Low specific heat -> takes less energy to raise/lower object's temperature
Explanation:
The specific heat capacity is the amount of heat required to raise the temperature of something per unit of mass.
A high specific heat value for an object means it takes more energy to raise or lower that object's temperature. A low specific heat value for an object means it does not take very much energy to heat or cool that object.
When the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0 * 10-4 T. What is the radius of the loop?
Answer:
ill get back to this question once i get the answer
The radius of the loop is 13 cm
To find the radius of the loop, the values are given as,
Current I = 6A
Magnetic field, B = 2* 10⁻⁴ T
How to find the radius of the loop?The magnetic field in a circular loop will have same magnitude and direction. The current carrying loops will be formed due to the magnetic field and there will be n times of loops adds up for every turns.
Formula for magnetic field in the circular loop is,
B = µ₀ I 2R Tesla
Here, we have to find the radius of the loop,
R = B / µ₀ I × 2
µ₀ = 4π × 10-7 H/m.
Substituting all the values in the equation,
R = ( 2 × 10⁻⁴ ) / ( 4π × 10-7 × 6 × 2)
= ( 2 × 10⁻⁴ ) / ( 0.0000150796)
Radius, R = 13 cm
Thus, the radius of the loop is 13 cm.
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Answer as soon as possible
Answer:
the velocity of the acorn
Explanation:
just do in in real life and see
Answer:
it is probably the velocity of the acorn
What type of meter would be connected on both sides of a resistor in a circuit?
Type of meter would be connected on both sides of a resistor in a circuit is a a voltmeter , which measures potential difference .
What is a voltmeter ?A voltmeter is an instrument used for measuring the potential difference , or voltage between two points in an electrical circuit .
A voltmeter is always attached in a series combination and an ammeter (which measures current in a circuit ) always attached in parallel combination with the circuit.
Since , in question it is given that a meter would be connected on both sides of a resistor in a circuit that means it must be a series combination
hence , correct answer is B) a voltmeter , which measures potential difference .
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Which of the following is the main idea of Thomas Paine's "Common Sense"?
plzzzzzzzzzzzzzzzzzzzzzzzzzz help 20 points
Answer:
1.23
Explanation:
[tex]{\underline{\pink{\textsf{\textbf{ Answer : }}}}}[/tex]
➩ 1.23 feet
[tex]{\underline{\purple{\textsf{\textbf{Explanation : }}}}}[/tex]
Given :
Simon cuts a pipe that was 4.92 feet long Then he cuts it into four equal pieces.To find :
What is the length of the each piece.Solution :
As it is told that it's divided into four equal pieces
Therefore,
We must divide it by 4 to get the length of each piece.
So,
[tex] \sf \to \: \frac{4.92}{4} \\ \sf \to \: 1.23 \: feet \: ans.[/tex]
A falling stone takes delta t = 0.32s to travel past a window 2.2m Tall. From what height above the top of the window did the stone fall?
Answer:
The height above the top of the window is 1.44 m
Explanation:
Given;
time of motion, t = 0.32 s
height traveled at the given time, h = 2.2m
determine the initial velocity of the stone;
h = ut + ¹/₂gt²
2.2 = u(0.32) + ¹/₂ x 9.8 x 0.32²
2.2 = 0.32u + 0.502
0.32u = 2.2 - 0.502
0.32u = 1.698
u = 1.698 / 0.32
u = 5.31 m/s
This initial velocity on top of the window becomes the final velocity from the height above the window.
v² = u² + 2gh
where;
u is the initial velocity of the stone from the height above the window;
5.31² = 0 + (2 x 9.8)h
19.6h = 28.196
h = 28.196/19.6
h = 1.44 m
Therefore, the height above the top of the window is 1.44 m
he gravitational force between two objects of masses m1m1m_1 and m2m2m_2 that are separated by distance rrr is
Answer:
[tex]F = \frac{6.67408m_1 m_2}{10^{11}r^2}[/tex]
Explanation:
Given
[tex]Object_1 = m_1[/tex]
[tex]Object_2 = m_2[/tex]
[tex]Distance = r[/tex]
Required
Determine the force of attraction
This is calculated as:
[tex]F = \frac{GMm}{d^2}[/tex]
Where
M = mass of object 1
m = mass of object 2
d = distance
Where G = gravitational constant
[tex]G = 6.67408 * 10^{-11}\ m^3 kg^{-1} s^{-2}[/tex]
Substitute these values in
[tex]F = \frac{GMm}{d^2}[/tex]
[tex]F = \frac{6.67408 * 10^{-11} * m_1 * m_2}{r^2}[/tex]
[tex]F = \frac{6.67408 * m_1 * m_2* 10^{-11}}{r^2}[/tex]
[tex]F = \frac{6.67408m_1 m_2* 10^{-11}}{r^2}[/tex]
[tex]F = \frac{6.67408m_1 m_2}{10^{11}*r^2}[/tex]
[tex]F = \frac{6.67408m_1 m_2}{10^{11}r^2}[/tex]
What is the similarity between relative dating and radioactive dating? I will mark brainlest. I dont know how btw
Answer:
relative dating and radioactive dating are two methods in archeaology to determine the age of fossils and rocks
Explanation:
the act of or study of fossils is important for the determination of the kind of organism it represents how the organism lived and how it was preserved on the Earth’s surface over the past 4600000000 years
a. What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren?
b. What frequency does she receive after the ambulance has passed?
Answer:
A)828.8Hz
B)869.2Hz
Explanation:
Here is a complete question;
What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren? Speed of sound is 345m/s
b. What frequency does she receive after the ambulance has passed?
Vs= speed of the ambulance
, We convert to m/s for unit consistency
= 115 km/h= 115km× 1000m/1m × 1hr/3600s= 31.94m/s
Dopler effect is when observed frequency of wave changes with respect to the source or when observed moves relative to transmitting medium can be expressed as
f'=[ (v + vo)/(v- vs)]*f
=[ (v )/(v- vs)]*f
The sign vo and vs depends on vthe direction of the velocity
f= frequency of ambulance siren= 753Hz
v= speed of sound in air= 345m/s
Vo= speed of observer= 0
A) we are to determine the f' of ambulance as heard by person as ambulance approaching.
To find the frequency f' observed by the person we use the expresion below
Then substitute the values
f'=[ (v )/(v- vs)]*f
=[ (345)/(345-31.94)]×753
= 828.8Hz
B)What frequency does she receive after the ambulance has passed?
To find the frequency f' observed by the person we use the expresion below
Then substitute the values
f'=[ (v )/(v + vs)]*f
=[ (345)/(345 + 31.94)]×753
= 869.2Hz
=
A racecar accelerates from rest at 6.5 m/s2 for 4.1 s. How fast will it be going at the end of that time?
Answer:
The final velocity of the car is 26.65 m/s.
Explanation:
Given;
acceleration of the racecar, a = 6.5 m/s²
initial velocity of the car, u = 0
time of motion, t = 4.1 s
The final velocity of the car is given by;
v = u + at
where;
v is the final velocity of the car
suvstitute the givens
v = 0 + (6.5)(4.1)
v = 26.65 m/s.
Therefore, the final velocity of the car is 26.65 m/s.
It increases, f = ma both mass and acceleration are directly proportional to force so if mass is constant acceleration must increase to increase the force.
Answer:
is that a question?
Explanation:
thankyou for the points
Can someone please answer how to convert mass into weight?
Answer:
To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.
Explanation:
Power is the rate at which work is done true or false
Answer:
false
Explanation:
answer plese lang po
Answer:
hi
Explanation:
how to convert gumbauan baboy to kung burger p
A 3520 kg truck moving north makes an INELASTIC collision with an 1480 kg car moving 13.0 m/s east. After colliding, they have a velocity of 9.80 m/s at 66.9 degrees. What was the initial velocity of the truck? (m/s)
Answer:
v = 12.8 m/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.Since momentum is a vector, their components must be conserved too.Choosing a pair of axes coincident with the N-S and W-E directions, naming x to the W-E axis and y to the N-S one, we can write the following algebraic equations:[tex]p_{ox} = p_{fx} (1)[/tex]
[tex]p_{oy} = p_{fy} (2)[/tex]
Since we know all the information needed to solve (1), assuming a completely inelastic collision, we can focus in (2), writing both sides of the equation as follows:[tex]p_{oy} = m_{t} * v_{ot} = 3520 kg* v_{ot} (3)[/tex]
[tex]p_{fy} = m_{f} * v_{fy} = 5000 kg* 9.8 m/s * sin 66.9 = 45080 kg*m/s (4)[/tex]
Since (4) and (3) are equal each other, we can solve for vot, as follows:[tex]v_{ot} =\frac{45080kg*m/s}{3520kg} = 12.8 m/s (5)[/tex]
A plane starts from rest accelerates to 40 m/s in 10 seconds. How far did the plane travel during this time?
200 m
Explanation:We are given:
Initial velocity of the plane (u) = 0 m/s
Final velocity of the plane (v) = 40 m/s
Time interval (t) = 10 seconds
Displacement of the plane (s) = x m
Solving for x:
Acceleration of the plane
v = u + at [First equation of motion]
40 = 0 + a(10) [replacing known variables]
a = 4 m/s² [dividing both sides by 10]
Displacement of the Plane:
s = ut + 1/2 (at²) [Second equation of motion]
s = (0)(10) + 1/2(4)(10)² [replacing known variables]
s = 200 m
Hence, the Plane covers a distance of 200 m in the given time interval
Suppose you put an ice cube into a cup of hot tea. In what direction does energy in the form of heat flow? What happens to the ice cube as this flow of energy occurs?
Answer:
The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.
When particles get close to the surface, they interact with atoms in
the
(Finish the sentence)
The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of 30° with the wall. The line AB goes through the center of the ball, and the contact point with the wall is at the same vertical height as the center of the ball. The ball presses against the wall with a force of magnitude:
Answer: T = 692.82 and 346.4 N
Explanation:
Given that;
w = 600 N
∅ = 30°
ΣFy = ma
a = 0 m/s²
ΣF = T(cos30°) - W = 0
T(cos30°) = W
we Divide both sides by cos30°
T = W / cos30o
T= 600N / cos30°
T = 692.82
and ∑fx
F = T sin∅
F = 692.82 × (sin30°)
F = 346.4 N
The equilibrium condition allows finding the result for the force of the ball against the wall is:
The force of the ball directed towards the wall is 346.4 N
Newton's second law gives a relationship between force, mass and acceleration of bodies. In the case where the acceleration is zero, it is called the equilibrium condition.
∑ F = 0
A free-body diagram is a diagram of the forces without the details of the bodies. In the attached we have a free-body diagram of the system.
Let's use trigonometry to break down stress.
sin 30 = [tex]\frac{T_x}{T}[/tex]
cos 30 = [tex]\frac{T_y}{T}[/tex]
T_y = T cos 30
Tₓ = T sin 30
Let's write the equilibrium condition for the system.
y-axis.
T_y -W = 0
T cos 30 = W
[tex]T = \frac{W}{cos 30}[/tex]
x-axis.
R - Tₓ = 0
R = T sin 30
We substitute
[tex]R = \frac{W}{cos 30} \ sin 30 \\R = W \ tan 30[/tex]
Let's calculate.
R = 600 tan 30
R = 346.4 N
This force is directed from the wall towards the ball, by Newton's third law the force of the ball is of equal magnitude and opposite direction, that is, directed towards the wall.
In conclusion with the equilibrium condition we can find the result for the force of the ball against the wall is:
The force of the ball directed towards the wall is 346.4 N
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A copper collar is to fit tightly about a steel shaft whose diameter is 6.0000 cm at 19°C. The inside diameter of the copper collar at that temperature is 5.9800 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the temperature of both the steel shaft and copper collar are raised simultaneously?
Answer:
T' = 865.15 °C
Explanation:
In order for the copper collar to just slip on the steel shaft the, assuming are heated simultaneously, we must find the final parameters of both and equate them. Because the final diameters of both must be same for the slipping to occur.
FOR COPPER COLLAR:
dc' = dc(1 + ∝c*ΔT)
where,
dc' = final diameter of copper ring
dc = initial diameter of copper ring = 5.98 cm
∝c = coefficient of linear expansion for copper = 16 x 10⁻⁶ °C⁻¹
ΔT = Change in Temperature
Therefore,
dc' = (5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] ------------- equation (1)
FOR STEEL SHAFT:
ds' = ds(1 + ∝s*ΔT)
where,
ds' = final diameter of steel shaft
ds = initial diameter of steel shaft = 6 cm
∝s = coefficient of linear expansion for steel = 12 x 10⁻⁶ °C⁻¹
ΔT = Change in Temperature
Therefore,
dc' = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT] ------------- equation (2)
Comparing equation (1) and equation (2):
(5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT]
(5.98 cm/6 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = [1 + (12 x 10⁻⁶ °C⁻¹)ΔT]
0.9967 + (1.59 x 10⁻⁵ °C⁻¹)ΔT = 1 + (12 x 10⁻⁶ °C⁻¹)ΔT
1 - 0.9967 = [(15.9 -12) x 10⁻⁶ °C⁻¹]ΔT
0.0033/3.9 x 10⁻⁶ °C⁻¹ = ΔT
ΔT = 846.15 °C
but,
ΔT = T' - T = T' - 19°C = 846.15°C
T' = 846.15 °C + 19 °C
T' = 865.15 °C