1. Work = Force × Distance
Work = (20 kg) × (9.8 m/s^2) × (2.2 m) = 431.2 J
2. Yes, work is done as the car undergoes acceleration, indicated by a change in velocity.
3. Work done by friction = (force of friction) × (distance) = (160 N) × (8 m) = 1280 J
Work done by the huskie = (700 N) × (8 m) = 5600 J
Work done by gravity = (82 kg) × (9.8 m/s^2) × (8 m) = 6393.6 J
4. Work = Weight × Height = (81 kg) × (9.8 m/s^2) × (4.2 m) = 3290.44 J
5. The work done is the same whether moving all 6 books at once or one book at a time.
6. Work = Weight × Height = (0.023 N) × (450 m) = 10.35 J
7. Longer ramps with turns allow for a gradual increase in potential energy, minimizing the force required to ascend and providing convenience for individuals.
8. Work = Weight × Height = (150,000 N) × (1 m) = 150,000 J
9. Number of times = Work / (Force × Distance) = 200 Nm / (40 N × 0.18 m) ≈ 27.78 times
10. No work is done when holding a motionless object.
11. Work = Weight × Height = (200 N) × (1.5 m) = 300 J
1. To find the work done by the weightlifter, we can use the formula:
Work = Force × Distance
Given:
Mass of barbell = 20 kg
Distance lifted = 2.2 m
Acceleration due to gravity = 9.8 m/s^2 (assuming vertical motion)
Weight (force) = mass × acceleration due to gravity
Substituting the values, we get:
Work = (20 kg) × (9.8 m/s^2) × (2.2 m) = 431.2 J
2. Work is done when there is a displacement in the direction of the applied force. In this case, since the car is moving in the same direction as the force applied (acceleration), work is done. The work done can be calculated using the formula mentioned in question 1:
Work = Force × Distance
Since the mass of the car is given, we can use the equation:
Work = (1/2) × mass × (final velocity^2 - initial velocity^2)
Substituting the values, we get:
Work = (1/2) × (2700 kg) × [(12 m/s)^2 - (3.5 m/s)^2] = 219,660 J
3. Work done by friction can be calculated using the formula:
Work = Force of friction × Distance
Work done by friction = (force of friction on the sled) × (distance)
Work done by friction = (160 N) × (8 m) = 1280 J
Work done by the huskie = Force × Distance
Work done by the huskie = (700 N) × (8 m) = 5600 J
Work done by gravity = Weight × Height
Work done by gravity = (mass × acceleration due to gravity) × (distance)
Work done by gravity = (82 kg) × (9.8 m/s^2) × (8 m) = 6393.6 J
4. Work done against the force of gravity is given by:
Work = Weight × Height
Work = (mass × acceleration due to gravity) × (height)
Work = (81 kg) × (9.8 m/s^2) × (4.2 m) = 3290.44 J
5. The work done would be the same regardless of whether you move all 6 books at once or one book at a time. Work done is independent of the number of objects moved simultaneously.
6. Work done on the penny can be calculated using the formula:
Work = Weight × Height
Work = (0.023 N) × (450 m) = 10.35 J
7. The design of long ramps with turns for handicapped people is based on minimizing the effort required to overcome the force of gravity while ascending. By providing a longer distance to cover, the incline of the ramp can be made shallower, reducing the force needed to ascend. This makes it more convenient for individuals using wheelchairs or other mobility aids to navigate the ramp.
8. The work done to raise one block to a height of one meter can be calculated as:
Work = Weight × Height
Work = (150,000 N) × (1 m) = 150,000 J
9. Work is calculated as the product of force and displacement. Given the work done as 200 Nm, we can rearrange the formula to solve for the force:
Work = Force × Distance
200 Nm = Force × 0.18 m
Force = 200 Nm / 0.18 m = 1111.11 N
The force required to move the handle down is 1111.11 N. As the force required to pump the handle is 40 N, we can calculate the number of times by dividing the force required:
Number of times = 1111.11 N / 40 N ≈ 27.78 times
10. When holding the barbell motionless above your head, there is no displacement, and hence no work is done against gravity.
11. The work done against gravity can be calculated using the formula:
Work = Weight × Height
Work = (mass × acceleration due to gravity) × (height)
Work = (200 N) × (1.5 m) = 300 J
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In which of the following is convection the main type of heat transfer?
O A. Gas and vacuum
B. Solid and liquid
O C. Liquid and gas
O D. Solid and vacuum
Convection is the primary mode of heat transfer in liquids and gases.
The correct answer is option C.
Convection is a process of heat transfer that occurs in fluids (liquids and gases) due to the movement of the fluid itself. It involves the transfer of heat energy through the bulk movement of the fluid particles. This mechanism is different from conduction, which is the direct transfer of heat through molecular collisions, and radiation, which is the transfer of heat through electromagnetic waves.
In the case of liquids and gases, convection occurs when a temperature difference exists within the fluid. The heated regions of the fluid become less dense and rise, while the cooler regions sink. This creates a continuous circulation of the fluid, known as convection currents, which transfer heat from one location to another.
Option A, Gas and vacuum, does not involve the presence of a fluid medium, so convection cannot occur. In a vacuum, heat transfer primarily occurs through radiation. Option B, Solid and liquid, includes the possibility of conduction in solids but not convection. Option D, Solid and vacuum, does not involve any fluid medium, so convection is not applicable.
Therefore, option C, Liquid and gas, is the correct choice where convection is the main type of heat transfer. In liquids and gases, convection plays a significant role in heat transfer processes, such as the movement of heat in boiling water, air currents in a room, and oceanic circulation patterns.
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As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω0 e −σ t , where ω0 and σ are constants. The angular speed changes from an initial angular speed of 2.88 rad/s to 1.38 rad/s in 3.92 s. (a) Determine the magnitude of the angular acceleration after 1.88 s. Answer in units of rad/s 2 . (b) How many revolutions does the wheel make after 2.6 s ? Answer in units of rev. (c) Find the number of revolutions it makes before coming to rest.
poste en français s’il vous plaît
Why is radiant energy classified as Kinetic energy
Answer:
Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat.
Answer:
Explanation:
Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat. Radio signals: Similar to x-rays, radio waves also travel in the form of waves.
If distance between two charges increased 5 times then force between them
decreased 5 times
Explanation: if the force increases 5 times between them would decrease 5 times
A temperature scale has an upper fixed point of 260mm and the lower fixed point of 50mm.what will be the reading on this scale when the thermometer read 125°F
Answer:
the reading on the scale is 158.5 mm.
Explanation:
Given;
upper fixed point of the temperature scale, x₁ = 260 mm
lower fixed point of the temperature scale, x₂ = 50 mm
upper temperature scale, T₁ = 212 °F
lower temperature scale, T₂ = 32 °F
thermometer reading, t = 125 °F, let the reading on the scale = x
Interpolate as follows to determine the value of "x"
[tex]\frac{X_1 - X}{X_1-X_2} = \frac{T_1-t}{T_1-T_2} \\\\\frac{260-X}{260-50} = \frac{212-125}{212-32} \\\\\frac{260 -X}{210} =\frac{87}{180} \\\\180(260-X) = 87(210)\\\\46800 -180 X = 18270 \\\\180X = 46800-18270\\\\180X = 28530\\\\X = \frac{28530}{180} \\\\X = 158.5 \ mm[/tex]
Therefore, the reading on the scale is 158.5 mm.
consider an electromagnetic wave of frequency f=3x10^6 Hz. does this radiation belong to the visible range to the ultraviolet or to the infrared of radio waves ?why?
Answer:
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
44e
The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very efficient when the train is moving slowly. The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very efficient when the train is moving slowly. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become weaker.
Answer:
The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.
Explanation:
A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.
Let us find the drag force which is proportional to the velocity of two conducting plates.
The EMF that is induced in the eddy currents are : [tex]$E=v(B \times L)$[/tex]
The force which is due to the induced magnetic field is, [tex]$F=l(L \times B)$[/tex]
Therefore, [tex]$F=\frac{E}{R} \times (L \times B)$[/tex]
[tex]$F=\frac{v(B \times L)}{R} \times (L \times B)$[/tex]
Here, force is directly proportional to the velocity of the two conducting plates.
Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.
Explain how wavelength, frequancy and energy changes in the electromagnetic spectrum
Answer:
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
15. Which tectonic boundary would have many normal faults associated
with it?
A. Convergent
B. Divergent
C. Transform
How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
50 J,
12.5 J,
25 J,
49 J
Answer:
The correct option is (b).
Explanation:
We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.
We know that, the work done is equal to the kinetic energy of an object i.e.
[tex]W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J[/tex]
So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.
A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the water rises part-way along the straight sides, and then 5.00 cm3 of oil is poured into one end. As a result, the top surface of the oil ends up 0.550 cm higher than the water surface on the other side of the U. What is the density of the oil
Answer:
0.89 g/cm^3 = 890 kg/m^3
Explanation:
Cross sectional area of U-tube ( A ) = 1.00 cm^2
volume of oil ( V ) = 5.00 cm^3
change between top surface = 0.550 cm
height of oil = 5 cm ( volume / area )
height of water = 5 - 0.550 = 4.45 cm
pressure at the oil-water junction = Pressure on the second side of the U-tube at same level
Po * g * Hoil = Pw * g * Hwater
Po * 5 = 1 * 4.45
∴ Density of oil ( Po ) = 4.45 / 5 g/cm^3 = 0.89 g/cm^3
which of the following phenomena suggest that light may be transverse wave
#polarization
#reflection
#photoelectric effect
#diffraction
Answer:
Polarization.
Reason being that phenomena verifies the transverse nature of light
The state of the atmosphere at a particular time and place is called the ————-.
Answer:
= weather
Explanation:
called.
4) The object that changes its position relative to a fixed point with time is called ...
3) Theratiobetweentotaldisplacementandtotaltimeisсalled..
5) The motion that repeats itself in equal intervals of time is called
6) If the body moves at uniform velocity its acceleration is equal to
7) Acceleration of an object's motion when it changes its velocity with unequal
amounts in equal time is called.
8) When an object started motion from rest, its initial velocity is equal to
9) When a body moves with uniform velocity its initial velocity and its final velocity
are ....
10If an object is thrown upwards its horizontal range reached by it is
Answer:
4) Object in motion
5) Velocity
6) 0 m/s²
7) non - uniform acceleration
8) 0 m/s
9) Equal
10) distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.
Explanation:
4) Object in motion
5) Ratio between displacement and time is velocity. Displacement is in metres(m) and time is in seconds(s). Thus, displacement/time is in m/s which is velocity.
6) Acceleration = 0 m/s² since it loves with uniform velocity and therefore doesn't accelerate.
7) Since the object changes its velocity with unequal amounts in equal time, the acceleration is called non - uniform acceleration since the acceleration will differ at different points.
8) Initial velocity of an object that starts motion from rest is zero.
9) They are equal since velocity is uniform.
10) The horizontal range will be distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.
Plants are known as producers because they can make their own food. Which of the following provides a list of basic needs a plant must have for photosynthesis to happen?
A.
water and oxygen in the air
B.
soil, energy from the sun, and oxygen in the air
C.
energy from the sun, carbon dioxide in the air, water
D.
soil, carbon dioxide in the air, energy from the sun
HELP PLEASE
Answer:
C .energy from the sun, carbon dioxide in the air, water
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A car wheel turns through 12pi in 10.7s calculate the angular speed of the wheel
Answer:
The answer should be D..
Explanation:
What is the process by which water particles move through a membrane?
active transport
homeostasis
osmosis
cell division
photosynthesis
A 10 N force is applied to a 2 kg block for 3 seconds. During the 2nd second, which property increases in the block?
Answer:
inertia
Explanation:
A inertia is the answer
Consider two insulating balls with evenly distributed equal and opposite charges on their surfaces, held with a certain distance between the centers of the balls. Construct a problem in which you calculate the electric field (magnitude and direction) due to the balls at various points along a line running through the centers of the balls and extending to infinity on either side. Choose interesting points and comment on the meaning of the field at those points. For example, at what points might the field be just that due to one ball and where does the field become negligibly small?
PLEASE HELP NOW
How is a hemisphere's ability to gather solar energy affected when the hemisphere is tilted toward the Sun?
A.
The hemisphere will not gather any more or any less energy than when tilted away.
B.The hemisphere will gather less solar energy because it receives less direct sunlight.
C.
The hemisphere will gather more solar energy because it receives more direct sunlight.
D.
The hemisphere will not be able to gather any solar energy.
You've always wondered about the acceleration of the elevators in the 101 story high Empire State Building. One day, while visiting New York, you take your bathroom scale into the elevator and stand on it. The scale reads 177 lb as the door closes. As the elevator moves upward the scale reading varies between a minimum value of 138 lb and a maximum value of 227 lb as the elevator travels 101 floors.
a. What is the magnitude of the acceleration as the elevator starts upward?
b. What is the magnitude of the acceleration as the elevator brakes to a stop?
Answer:
a) 2.8 m/s2
b) 2.2 m/s2
Explanation:
The lecture on the bathroom scale is equal to the normal force that the scale exerts on you, and is directed upward.There is another force acting on you, which is gravity.This force (which we call weight) is the product of the mass times the acceleration due to gravity, g, and is directed downward, opposite to the normal force.When the elevator is at rest, no acceleration takes place, so according Newton's 2nd Law, no net force must be exerted on you.In this condition, the normal force Fn₀ must be equal to the weight:[tex]F_{no} = m * g = 177 lb (1)[/tex]Since the normal force takes any value needed to satisfy Newton's 2nd law, the two extreme lectures can be expressed as follows, in terms of the two forces acting on you while the elevator is moving upward:[tex]F_{n1} = m * (g +a_{1}) = 227 lb (2)[/tex]
[tex]F_{n2} = m * (g +a_{2}) = 138 lb (3)[/tex]
Replacing m by 177lb/g (a given), and rearranging, we can solve (1) for a₁, as follows:[tex]a_{1} = (\frac{227lb}{177lb} *g) - g = 0.28*g = 0.28*9.8m/s2 = 2.8 m/s2 (4)[/tex]
As it can be seen, the normal force takes a larger value in order to be compliant with the upward acceleration that opposes to gravity.In the same way, we can find the magnitude of the downward acceleration when the elevator brakes to a stop, from (3):[tex]a_{2} = (\frac{138lb}{177lb} *g) - g = -0.22*g =- 0.22*9.8m/s2 = -2.2 m/s2 (5)[/tex]
In this case, the normal force takes a lower value than at rest, due to the acceleration has the same direction as gravity.Can someone help me with this one please I need help I will mark brainless
Answer:
Your answer is A) 3.33ft/min E
Explanation:
i know this because i know to find the velocity you have to divide distance and time. So for this question your distance=10 and your time=3.
What is the name for a compound formed with covalent bonds?
Answer:
These are called molecular compounds. ex. organic compounds like lipids or proteins.
what makes 60% of your arm and what makes the other 40%
When light wave strike a red object, what happens to the light waves of all colors except red?
Answer:
the object absorbs all light except for red. the red light is reflected back into your eyes, which is why it looks red.
*15 points*
How much louder is the sound of heavy street traffic (60dB) than the sound of normal conversation(40dB)?
A. 20 times louder
B. 100 times louder
C. 240 times louder
D. 2 times louder
The sound of heavy street traffic is 100 times louder than the sound of normal conversation.
What is street traffic?Street traffic is the movement of vehicles and pedestrians in a designated public space, such as a street or alley. Traffic is generally regulated by signs, signals, and lane markings. It is important to obey these rules, as they are intended to keep pedestrians and drivers safe. Street traffic can involve many types of vehicles, including cars, buses, motorcycles, bicycles, and trucks.
The sound of heavy street traffic is 60dB, while the sound of normal conversation is 40dB. This means the sound of the heavy street traffic is 20dB louder than the sound of a normal conversation. To calculate the difference in loudness, we need to take the difference in decibels and raise it to the power 10. This means that the sound of heavy street traffic is 100 times louder than the sound of normal conversation.
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What's the definition of wavelength?
I need help really quick plz... :
Answer:
a,b,c plus can you brainliest me pls? its beside the rating and it looks like a king icon
Explanation:
A 105-kg rubber mat is pushed on a dry concrete floor. What is the coefficient of static friction, if the force required to start the mat sliding is 1030 N?
Answer:
[tex]\mu=1[/tex]
Explanation:
Given that,
Mass of a rubber mat, m = 105 kg
We need to find the coefficient of static friction, if the force required to start the mat sliding is 1030 N.
The applied force is given by :
[tex]F=\mu mg\\\\\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{1030}{105\times 9.8}\\\\\mu=1[/tex]
So, the required coefficient of static friction is equal to 1.
A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B field (B is constant in time) and then back into a field free region to the left. The self inductance of the loop is negligible.
a. True
b. False
Answer:
False
Explanation:
This is because when the loop is leaving or going out, it will experience magnetic force to the right direction.
When the loop is leaving the field, the magnetic flux present at the loop will reduce. Therefore, the induced magnetic field will have to increase the magnetic flux which means the induced magnetic flux will be in the same direction as the field.