Answers
Answer:
20
Step-by-step explanation:
1/2(a+b)=180
1/2(6+12)=18
1/2(18)=180
9/9=180/9
=20
Related Questions
Adam tabulated the values for the average speeds on each day of his road trip as 60.5, 63.2, 54.7, 51.6, 72.3, 70.7, 67.2, and 65.4 mph. The sample standard deviation is 7.309. Adam reads that the average speed that cars drive on the highway is 65 mph. The t-test statistic for a two-sided test would be __________. Answer choices are rounded to the hundredths place.
Answers
Answer:
We accept null hypothesis
Step-by-step explanation:
We assume a normal distribution
The population mean μ₀ = 65 mph
Sample mean μ = 63,2 mph ( calculated from data )
Sample standard deviation σ = 7,309
Sample size n = 8
Degree of freedom is n - 1 8 - 1 = 7
As n < 30 we have to use the t-student test
We will do our test with a confidence interval of 95 % that means α = 5 %
or α = 0,05 and as we are going through a two-tail test α/2 = 0,025
Test Hypothesis:
Null Hypothesis: H₀ μ = μ₀
Alternate Hypothesis Hₐ μ ≠ μ₀
From t-student table for the degree of freedom 7, α/2 = 0,025 two-tail test we find tc
tc = 2,365
And calculate ts as
ts = ( μ - μ₀ ) / σ /√n
ts = ( 63,2 - 65 ) / 7,309/ √8
ts = - 1,8 *2,828/ 7,309
ts = - 5,091 /7,309
ts = - 06965
Now we compare ts and tc
tc = 2,365 or tc = - 2,365 ( by simmetry) tc = -2,37
and ts = -0,06965 ts = - 0,07
As |ts| < |tc|
ts is in the acceptance zone so we accept null hypothesis
Answer:
-0.70
Step-by-step explanation:
For the tabulated value the mean is calculated as:
Mean = (60.5 + 63.2 + 54.7 + 51.6 + 72.3 + 70.7 + 67.2 + 65.4)/8
= 505.6/8
Mean \bar{x}= 63.2
and population mean as assumption u= 65
and given that the sample standard deviation is: s= 7.309
The test statistic is calculated as:
Ζ = Τ –μ 63.2 - 65 = -0.696 -0.70 S
Hence the T statistic would be -0.70
perform the indicated operations a. 3/10+6/10. b. 1/3+2/4+1/6. c. 5/6-3/6 d. 2/3-6/10 e. 4/10×3/7 f. 1/6x6/15 g. 1/8÷4/9 h. 1/5÷3/4
Answers
Answer:
A. [tex]\frac{9}{10}[/tex]
B. 1
C. [tex]\frac{2}{6}[/tex] or [tex]\frac{1}{3}[/tex]
D. [tex]\frac{2}{30}[/tex] or [tex]\frac{1}{15}[/tex]
E. [tex]\frac{12}{70}[/tex] or [tex]\frac{6}{35}[/tex]
F. [tex]\frac{6}{90}[/tex] or [tex]\frac{1}{15}[/tex]
G. [tex]\frac{9}{32}[/tex]
H. [tex]\frac{4}{15}[/tex]
Answer:
Step-by-step explanation:
Reducing the given expressions to the lowest terms:
A. 3/10 + 6/10:
B. 1/3 + 1/4 + 1/6:
C. 5/6-3/6:
D. 2/3-6/10:
E. 4/10*3/7:
F. 1/6*6/15:
G. 1/8 divided by 4/9:
H. 1/5 divided by 3/4:
Periodically, customers of a financial services company are asked to evaluate the company's financial consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use
α = 0.05
and test to see whether the consultant with more experience has the higher population mean service rating.
Consultant A Consultant B
n1 = 16
n2 = 10
x1 = 6.82
x2 = 6.28
s1 = 0.65
s2 = 0.75
(a)
State the null and alternative hypotheses.
H0:
μ1 − μ2 ≤ 0
Ha:
μ1 − μ2 = 0
H0:
μ1 − μ2 > 0
Ha:
μ1 − μ2 ≤ 0
H0:
μ1 − μ2 ≠ 0
Ha:
μ1 − μ2 = 0
H0:
μ1 − μ2 ≤ 0
Ha:
μ1 − μ2 > 0
H0:
μ1 − μ2 = 0
Ha:
μ1 − μ2 ≠ 0
(b)
Compute the value of the test statistic. (Round your answer to three decimal places.)
(c)
What is the p-value? (Round your answer to four decimal places.)
p-value =
(d)
What is your conclusion?
Reject H0. There is sufficient evidence to conclude that the consultant with more experience has a higher population mean rating.Do not reject H0. There is insufficient evidence to conclude that the consultant with more experience has a higher population mean rating. Do not Reject H0. There is sufficient evidence to conclude that the consultant with more experience has a higher population mean rating.Reject H0. There is insufficient evidence to conclude that the consultant with more experience has a higher population mean rating.
Answers
Answer:
A) Null hypothesis; H0: μ1 − μ2 ≤ 0
Alternative hypothesis; Ha: μ1 − μ2 > 0
B) Test statistic = t = 1.878
C) p-value is 0.038823.
D) Reject the Null hypothesis H0
Step-by-step explanation:
We are given;
α = 0.05
n1 = 16
n2 = 10
bar x1 = 6.82
bar x2 = 6.28
s1 = 0.65
s2 = 0.75
A) The hypothesis is as follows;
Null hypothesis; H0: μ1 − μ2 ≤ 0
Alternative hypothesis; Ha: μ1 − μ2 > 0
B) Formula yo determine the test statistic is;
t = ((bar x1) - (bar x))/√((s1)²/n1) + (s2)²/n2))
Plugging in the relevant values, we have;
t = (6.82 - 6.28)/√((0.65)²/16) + (0.75)²/10))
t = 0.54/√(0.02640625 + 0.05625)
t = 0.54/0.2875
t = 1.878
C) The formula for the degree of freedom is;
Δ = [(s1)²/n1) + (s2)²/n2))]²/[((s1²/n1)²/(n1 - 1)) + ((s2²/n2)²/(n1 - 1))
Plugging in the relevant values, we have;
Δ = [(0.65)²/16) + (0.75)²/10))]²/[((0.65²/16)²/(16 - 1)) + ((0.75²/10)²/(10 - 1))
Δ = 0.00683205566/(0.000046486 + 0.0003515625)
Δ ≈ 17
Thus, the P-value;
From online p-value calculator from t-score and DF which i attached, we have the p-value as;
The p-value is 0.038823.
D) The p-value result is significant at p < 0.05
Thus, we reject the Null hypothesis H0
A) Null hypothesis: μ1 − μ2 ≤ 0
B) Test statistic = t = 1.878
C) The p-value is 0.038823.
D) Reject the Null hypothesis H0.
HypothesisWhat all information we have ?
α = 0.05
n1 = 16
n2 = 10
bar x1 = 6.82
bar x2 = 6.28
s1 = 0.65
s2 = 0.75
Part A)
The hypothesis is as follows;
Null hypothesis; H0: μ1 − μ2 ≤ 0
Alternative hypothesis; Ha: μ1 − μ2 > 0
Part B)
The formula to determine the test statistic is :
t = ((bar x1) - (bar x))/√((s1)²/n1) + (s2)²/n2))
t = (6.82 - 6.28)/√((0.65)²/16) + (0.75)²/10))
t = 0.54/√(0.02640625 + 0.05625)
t = 0.54/0.2875
t = 1.878
The formula to determine the test statistic is t = 1.878.
Part C)
The formula for the degree of freedom is;
Δ = [(s1)²/n1) + (s2)²/n2))]²/[((s1²/n1)²/(n1 - 1)) + ((s2²/n2)²/(n1 - 1))
Δ = [(0.65)²/16) + (0.75)²/10))]²/[((0.65²/16)²/(16 - 1)) + ((0.75²/10)²/(10 - 1))
Δ = 0.00683205566/(0.000046486 + 0.0003515625)
Δ ≈ 17
Thus, the P-value is 0.038823.
Part D)
The p-value result is significant at p < 0.05 is :
Thus, we reject the Null hypothesis H0.
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If A and B are independent events, P(A) = 0.25, and P(B) = 0.3, what is P(AB)?
O A. 0.25
B. 0.3
C. 0.15
O D. 0.075
Answers
Answer:
[tex] P(A) = 0.25, P(B= 0.3[/tex]
And if we want to find [tex] P(A \cap B)[/tex] we can use this formula from the definition of independent events :
[tex] P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075[/tex]
And the best option would be:
[tex] P(A \cap B) =0.075[/tex]
Step-by-step explanation:
For this case we have the following events A and B and we also have the probabilities for each one given:
[tex] P(A) = 0.25, P(B= 0.3[/tex]
And if we want to find [tex] P(A \cap B)[/tex] we can use this formula from the definition of independent events :
[tex] P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075[/tex]
And the best option would be:
[tex] P(A \cap B) =0.075[/tex]
Find the length of KC
Answers
Answer:
54
give me brainliest please please please and follow my page
Step-by-step explanation:
To find length of KC...we need to find the length of HM and MU first ...
so....HM= 96- 78 = 14
JU = 96 + HM = 96 + 14 = 110
....
KU = 110 - JK = 110 - 82 = 28
....
UN = 105+ 82 -( 96 + 14 )
187 - 110
= 77
UC = 77 - 51 = 26
KC = UC + KU = 26 + 28 = 54
The length of [tex]\overline{KC}[/tex] along line [tex]\overline{JN}[/tex] is given as 54 (Option A) See the computation below.
How do you compute the length of [tex]\overline{KC}[/tex]?To determine the length of [tex]\overline{KC}[/tex], the length of [tex]\overline{HM}[/tex] and [tex]\overline{MU}[/tex]must first be derived.
[tex]\overline{HM}[/tex] = 96 - 78
[tex]\overline{HM}[/tex] = 14
[tex]\overline{JU}[/tex] = 96 + [tex]\overline{HM}[/tex]
= 96 + 14
[tex]\overline{JU}[/tex]= 110
[tex]\overline{KU}[/tex] = 110 - [tex]\overline{JK}[/tex]
= 110 - 82
[tex]\overline{KU}[/tex]= 28
[tex]\overline{UN}[/tex] = 105+ 82 -( 96 + 14 )
=187 - 110
[tex]\overline{UN}[/tex]= 77
[tex]\overline{UC}[/tex] = 77 - 51
[tex]\overline{UC}[/tex]= 26
Thus,
[tex]\overline{KC}[/tex] = [tex]\overline{UC}[/tex] + [tex]\overline{KU}[/tex]
[tex]\overline{KC}[/tex]= 26 + 28
[tex]\overline{KC}[/tex]= 54
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find the area of the shaded region. 27.8 in and 150 degrees
Answers
Answer: 57769.8 in²
Let A be the area of the shaded region
We have a relation that can help us calculate its area
A= 0.5*(θ-sin(θ))*r² where r is the radius and θ the angle
A= 0.5*(150-sin(150°))* 27.8² =57769.79≈57769.8 in²
Answer:
818.4
Step-by-step explanation:
Forty one people were riding bus number 527. At 8:45 am,it arrived at the 109th street stop. There,19 people got off and then 20 people boarded. How many riders were on the bus when it traveled to the next stop?
Answers
Answer:
1 because jahahdhekskdbsks
a patient is taking 65 grams of medicine if it is increased by 20% how many grams are they taking
Answers
Answer:
78 grams
Step-by-step explanation:
20% is 1/5
1/5 of 65 is 13
65 + 13 = 78
brainliest?
A particular fruit's weights are normally distributed, with a mean of 476 grams and a standard deviation of 36 grams. The heaviest 19% of fruits weigh more than how many grams? Give your answer to the nearest gram.
Answers
Answer:
Step-by-step explanation:
Given that:
mean (μ) = 476 grams, standard deviation (σ) = 36 grams. P(z) = 19%
The z score shows by how many standard deviation the raw score is above or below the mean. It is given by the equation:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Since the 19% weigh more, therefore 81% (100% - 19%) weigh less.
From the normal distribution table, the z score that corresponds to a probability of 81%(0.81) = 0.87
We substitute z = 0.88 in the z score equation to find the raw score. Therefore:
[tex]z=\frac{x-\mu}{\sigma}\\0.87=\frac{x-476}{36}\\ x-476=31.32\\x=31.32+476\\x=507.32\\[/tex]
x ≅ 507 grams
Therefore 19% of fruits weigh more than 507 grams
Suppose a random sample of 80 measurements is selected from a population with a mean of 25 and a variance of 200. Select the pair that is the mean and standard error of x.
a) [25, 2.081]
b) [25, 1.981
c) [25, 1.681]
d) [25, 1.581]
e) [80. 1.681]
f) None of the above
Answers
Answer:
d) [25, 1.581]
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation(which is the square root of the variance) [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation, which is also standard error, [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
[tex]\sigma = \sqrt{200}, n = 80[/tex]
So the standard error is:
[tex]s = \frac{\sqrt{200}}{\sqrt{80}} = 1.581[/tex]
By the Central Limit Theorem, the mean is the same, so 25.
The correct answer is:
d) [25, 1.581]
A sample of size 42 college students produced a 95% confidence interval of (3.1, 5.2) for the mean number of coats owned. Then there is a 95% chance that these 42 students own on average between 3.1 and 5.2 coats.
a. True
b. False
Answers
Answer:
b. False.
Step-by-step explanation:
According to the presented information, at the 95% confidence level, the mean number of coats owned will be between 3.1 and 5.2. That does not mean that there is a 95% chance that they will own that many coats; just that you are 95% confident that they will own the coats.
Hope this helps!
Charlotte is running at a rate of 9 (km)/(h) what is charlotte speed in (m)/(s)
Answers
Answer:
2.5 meters per second
Step-by-step explanation:
9x1000=9000m/h
9000/60/60=2.5m/s
Answer:
2.5 m/s
Step-by-step explanation:
convert kilometers to meters and then use a conversion calc to do the rest
Galina had two boxes with pieces of paper in each. In the first box, each piece of paper had one possible outcome from flipping a coin 4 times (e.g. HHTH). There was one piece of paper for every possible outcome.
How many pieces of paper were in the first box?
Answers
Answer:
B
Step-by-step explanation:
A trough of water is 8 meters deep and its ends are in the shape of isosceles triangles whose width is 5 meters and height is 2 meters. If water is being pumped in at a constant rate of 6 m3Isec. At what rate is the height of the water changing when the water has a height of 120 cm?
Answers
Answer:
0.3 m/s
Step-by-step explanation:
The first thing is to attach the allusive graphic to the question. Now yes, let's move on to the solution that would be:
If the through is completely filtered the its volume will:
V = l * [1/2 w * h] = 1/2 l * w * h
Now we derive with respect to time and we are left with:
dV / dt = 1/2 * l * w * dh / dt
We solve by dh / dt and we have:
dh / dt = (2 / (l * w)) * (dV / dt)
We know that l = 8 and w = 5, in addition to dV / dt = 6, we replace:
dh / dt = (2 / (8 * 5)) * (6)
dh / dt = 0.3
Therefore the rate at which the height of the water changes is 0.3 m / s
is -17 a natural number
Answers
━━━━━━━☆☆━━━━━━━
▹ Answer
-17 isn't a natural number
▹ Step-by-Step Explanation
Positive integers are only natural numbers, meaning negative numbers aren't natural numbers.
Hope this helps!
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Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
According to the Stack Overflow Developers Survey of 20184 , 25.8% of developers are students. The probability that a developer is a woman given that the developer is a student is 7.4%, and the probability that a developer is a woman given that the developer is not a student is 76.4%. If we encounter a woman developer, what is the probability that she is a student
Answers
Answer:
3.26%
Step-by-step explanation:
The computation of the probability that she is a student is shown below:
Percentage of student developers = 25.8% = SD
The Percentage of the developer is student = 7.4% = DS
The percentage of the developer is not student = 76.4% = ND
Based on this, the probability is
[tex]= \frac{SD \times DS}{SD \times DS + DS \times ND}[/tex]
[tex]= \frac{25.8\% \times 7.4\%}{25.8\% \times 7.4\% + 7.4\% \times 76.4\%}[/tex]
=3.26%
we simply considered all the elements
find an angle between 0 and 2π that is coterminal with -3π /10
Answers
Answer:
17π/10
Step-by-step explanation:
To find a co-terminal angle in a specific range, add or subtract multiples of 2π until you have an angle in the desired range. Here, you can add 2π.
-3π/10 +20π/10 = 17π/10 . . . . angle co-terminal with -3π/10
Find a solution to the linear equation y=12x−24
Answers
Answer:
I didn't know which one you wanted...
Step-by-step explanation:
1. Finding the x an y-intercepts
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept(s): (2,0)
y-intercept(s): (0,−24)
2. Finding the slope and y-intercept
Use the slope-intercept form to find the slope and y-intercept.
Slope: 12
y-intercept: −24
Travis bought $9.45 worth of 49-cent stamps and 21-cent stamps. The number of 21-cent stamps was 5 fewer than the number of 49-cent stamps. Solve the equation 0.49s+0.21(s−5)=9.45 for s to find the number of 49-cent stamps Travis bought.
Answers
Answer:
15 49-cent stamps
Step-by-step explanation:
We can solve this problem with the equations 0.49(x) + 0.21(y) = 9.45 and x - 5 = y. Well, 0.49(15) + 0.21(10) = 9.45, so we know that there are 15 49-cent stamps and 10 21-cent stamps. The question is asking for the number of 49-cent stamps, so we can tell Travis bought 15 49-cent stamps.
Hope this helps! Plz give me brainliest, it will help me achieve my next rank.
The number of 49-cent stamps that Travis bought given the equation is 15.
What he number of 49-cent stamps Travis bought?Given this equation: 0.49s+0.21(s−5)=9.45 take the following steps to determine the value of s
Expand the bracket: 0.49s + 0.21s - 1.05 = 9.45Combine similar terms : 0.49s + 0.21s = 9.45 + 1.05Add similar terms: 10.50 = 0.70sDivide both sides of the equation by 0.70: s = 15To learn more about mathematical equations, please check: https://brainly.com/question/26427570
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The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let mu denote the true average reflectometer reading for a new type of paint under consideration. A test of
H0:μ=20 versus Ha:μ is greater than 20 will be based on a random sample of size n from a normal population distribution. What conclusion is appropriate in each of the following situations? (Round your P-values to three decimal places.)
a. n = 17, t = 3.1, α=0.05
State the conclusion in the problem context.
A. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
B. Reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
C. Do not reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
D. Reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
b. n = 10, t = 1.8, α=0.01
State the conclusion in the problem context.
A. Do not reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
B. Reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
C. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
D. Reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
c. n = 24, t = -0.4, p-value =
Answers
Answer:
a) D. Reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
b) C. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.
Step-by-step explanation:
a) We have a hypothesis test with the following hypothesis:
[tex]H_0: \mu=20\\\\H_a:\mu> 20[/tex]
The significance level is 0.05 for this right-tailed test.
The sample size is n=17.
This means we have 16 degrees of freedom.
[tex]df=n-1=17-1=16[/tex]
The test statistic has already been calculated and has a value of t=3.1.
This test is a right-tailed test, with 16 degrees of freedom and t=3.1, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t>3.1)=0.0034[/tex]
As the P-value (0.0034) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
At a significance level of 0.05, there is enough evidence to support the claim that the new paint has a reflectometer reading higher than 20.
b. The hypothesis are the same as point a:
[tex]H_0: \mu=20\\\\H_a:\mu> 20[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=10-1=9[/tex]
The significance level is 0.01.
The test statistic has already been calculated and has a value of t=1.8.
This test is a right-tailed test, with 9 degrees of freedom and t=1.8, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t>1.8)=0.0527[/tex]
As the P-value (0.0527) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.01, there is not enough evidence to support the claim that the new paint has a reflectometer reading higher than 20.
The table shows claims and their probabilities for an insurance company.
O A. (a)
O B. (a)
Amount of Claim
$0
$50,000
$100,000
$150,000
$200,000
$250,000
Probability
0.60
0.25
0.09
0.04
0.01
0.01
O c. (a) $
OD. (a) $
(a) Calculate the expected value.
(b) How much should the company charge as an average premium so that it breaks even on its claim
costs?
(c) How much should the company charge to make a profit of $60 per policy?
Answers
Answer:
a) Expected Value of Claims = $32,000
b) Average premium per claim, in order to break-even on claim costs
= $5,333.33
c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:
= $5,393.33 per policy
Step-by-step explanation:
a) Data and Calculations:
Amount of Claim Probability Expected Value
$0 0.60 $0
$50,000 0.25 $12,500
$100,000 0.09 9,000
$150,000 0.04 6,000
$200,000 0.01 2,000
$250,000 0.01 2,500
Expected Cost of claims = $32,000
b) Average premium per claim, in order to break-even on claim costs
= Total Claim cost divided by number of policies
= $32,000/6 = $5,333.33
c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:
Total Claim cost + Total profit / 6 or Average Premium plus Profit per policy =
= ($32,000 + $360)/6 or $5,333.33 + $60
= $32,360/6 or $5,393.33
= $5,393.33
The total expected value is $32000, the average premium so that it breaks even on its claim costs are $5333.33 and the company charge to make a profit of $60 per policy is $5393.33.
Given :
The table shows claims and their probabilities for an insurance company.
Amount of Claim Probability Expected Value
$0 0.60 0
$50000 0.25 $12500
$100000 0.09 $9000
$150000 0.04 $6000
$200000 0.01 $2000
$250000 0.01 $2500
A) So, the total expected value is = 12500 + 9000 + 6000 + 2000 + 2500
= $32000
B) The average premium is given by:
[tex]=\dfrac{32000}{6}[/tex]
= $5333.33
C) The company charge to make a profit of $60 per policy is:
[tex]= \dfrac{32000+360}{6}[/tex]
[tex]=\dfrac{32360}{6}[/tex]
= $5393.33
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An object of height 2.50cm is placed 20.0cm from a converging mirror of focal length 10.0cm. What are the height and the magnification of the image formed?
Answers
First find the distance it is reflected:
D = 20.0 x 10.0 /(20-10) = 200/10 = 20cm away.
Now calculate the magnification: -20/ 20 = -1
Now calculate the height:
-1 x 2.50 = -2.50
The negative sign means the image is inverted.
The mirrored image would be inverted, 2.50 cm tall and 20 cm in front of the mirror.
a coin will be tossed 10 times. Find the chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses
Answers
Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:
[tex]P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{5}{k}\cdot0.5^k\cdot0.5^{5-k}[/tex]
Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:
[tex]P(x=2)=\dbinom{5}{2}\cdot0.5^{2}\cdot0.5^{3}=10\cdot0.25\cdot0.125=0.3125\\\\\\[/tex]
For the last five tosses, the probability that are exactly 4 heads is:
[tex]P(x=4)=\dbinom{5}{4}\cdot0.5^{4}\cdot0.5^{1}=5\cdot0.0625\cdot0.5=0.1563\\\\\\[/tex]
Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:
[tex]P(H_1=2;H_2=4)=P(H_1=2)\cdot P(H_2=4)=0.3125\cdot0.1563=0.0488[/tex]
Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.
b=573
Ob= -573
b=35
b= -35
Ob= 253
Answers
Answer:
[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
Step-by-step explanation:
Given
[tex]f(b) = b^2 - 75[/tex]
Required
Determine the roots
To get the root of the function, then f(b) must be 0;
i.e. f(b) = 0
So, the expression becomes
[tex]0 = b^2 - 75[/tex]
Add 75 to both sides
[tex]75 + 0 = b^2 - 75 + 75[/tex]
[tex]75 = b^2[/tex]
Take square roots of both sides
[tex]\sqrt{75} = \sqrt{b^2}[/tex]
[tex]\sqrt{75} = b[/tex]
Reorder
[tex]b = \sqrt{75}[/tex]
Expand 75 as a product of 25 and 3
[tex]b = \sqrt{25*3}[/tex]
Split the expression
[tex]b = \sqrt{25} *\sqrt{3}[/tex]
[tex]b = \±5 *\sqrt{3}[/tex]
[tex]b = \±5 \sqrt{3}[/tex]
[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
The options are not clear enough; however the roots of the equation are [tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
Figure ABCDE was reflected across the line y=x to create figure A’B’C’D’E’. What are the coordinates of the pre image of E?
Answers
Answer
so I need to know the coordinates for me to tell you the answer but I think I can still help you by explaining.
In order for E to become E' the rule for reflection over y=x is (y, x) so you basically switch the x and the Y to have E'. so for you to be able find out E, you need to witch the x and the y.
for example:
if E' was (-2, 3)
E in the pre image would be (3, -2)
hope this helps :)
Answer:
(-2,6)
Step-by-step explanation:
Just did it edge 2021
in QRS, m Q = 70°, m R = 44", and m S = 66º. Which side of QRS is the shortest?
Answers
Answer:
QS
Step-by-step explanation:
The side opposite to the smallest angle must be the shortest side. The smallest angle is ∠R so the opposite side is QS.
Answer:
Hey there!
Smaller angles are opposite smaller sides, so the side opposite to angle R would be the shortest. (Or side SQ)
Hope this helps :)
Scott has eight CDs, and he picks two to take to work each day. How many different ways can Scott choose two CDs?
Answers
Answer:
The total number of ways to select 2 CDs from 8 CDs is 28.
A taxi company charges $2.25 per ride plus $0.30 per mile. Enter a linear model represents the cost, C, as a function of d, the number of miles of the ride.
Answers
Answer:
C(d) = d(2.25) + m(0.3)
Step-by-step explanation:
A taxi company charges $2.25 per ride plus $0.30 per mile.
Let d represent number of rides..
Let m represent number of Miles...
Then let C represent the total cost for each ride at a specific number of Miles.
The linear model representing the cost as a function of d the total ride
C(d) = d(2.25) + m(0.3)
The values stand independently because the customer can choose a different right and a different mile.
This is not an incomplete question, it has come from a very reliable source, please dont delete. If 60% of the students in Mr. Bobby's class are bio majors, which of the following could be the total number of students in his class? 28 32 35 39 PLZHELPTHANKS
Answers
Answer:
35 students
Step-by-step explanation:
Take the number of students in the class and multiply by 60% and see if you get an integer number
28 * .60 =16.8 not an integer
32 * .6 =19.2
35 * .6 =21 yes
39*.6 =23.4
George has opened a new store and he is monitoring its success closely. He has found that this store’s revenue each month can be modeled by r(x)=x2+5x+14 where x represents the number of months since the store opens the doors and r(x) is measured in hundreds of dollars. He has also found that his expenses each month can be modeled by c(x)=x2−3x+4 where x represents the number of months the store has been open and c(x) is measured in hundreds of dollars. What does (r−c)(3) mean about George's new store?
Answers
This is a great question!
When we are given ( r - c )( 3 ), we are being asked to take 3 as x in the functions r( x ) and c( x ), taking the difference of each afterwards -
[tex]r( 3 ) = ( 3 )^2 + 5( 3 ) + 14,\\x( 3 ) = ( 3 )^2 - 3( 3 ) + 4[/tex]
____
Let us calculate the value of each function, determine their difference, and multiply by 100, considering r( x ) and c( x ) are measured in hundreds of dollars,
[tex]r( 3 ) = 9 + 15 + 14 = 38,\\x( 3 ) = 9 - 9 + 4 = 0 + 4 = 4\\----------------\\( r - c )( 3 ) = 38 - 4 = 34,\\34 * 100 = 3,400( dollars )\\\\Solution = 3,400( dollars )[/tex]
Therefore, ( r - c )( 3 ) " means " that George's new store will have a profit of $3,400 after it's third month in business, given the following options,
( 1. The new store will have a profit of $3400 after its third month in business.
( 2. The new store will have a profit of $2400 after its third month in business.
( 3. The new store will sell 2400 items in its third month in business.
( 4. The new store will sell 3400 items in its third month in business.
The required answer is , [tex](r-c)(5)[/tex] means the revenue less expenses in 5 months i.e. the new store will have a profit of $ 5400 after 5 months.
Substitution:The substitution method is the algebraic method to solve simultaneous linear equations.
Given function is,
[tex]r(x) = x^2+5x+14[/tex]...(1)
And [tex]c(x) = x^2-4x+5[/tex]...(2)
Now, substituting the value into the equation (1) and (2).
[tex]r(5) = (5)^2+5(5)+14=64[/tex]
[tex]c(5) = (5)^2-4(5)+5=10[/tex]
Therefore,
[tex](r-c)(5)=r(5)-c(5)\\=64-10\\=54[/tex]
Now, [tex](r-c)(5)[/tex] means the revenue less expenses in 5 months i.e. the new store will have a profit of $ 5400 after 5 months.
Learn more about the topic Substitution:
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