Please help, this is due in 20 minutes, I need to do other work, please help. 7) Chris pays €18 for a meal, the Exchange rate is £1 = €1.65. What is the price of the meal in pounds? 8) In the USA a jacket costs $96. The Exchange rate is £1= $1.54. How much is the jacket in pounds? 9) In Hungary, Jack pays 874 Forints for a box of chocolates. The Exchange rate is £1= 350 Forints. How much does he pay for the chocolates to the nearest pence? 10) Jan buys a pair of sunglasses in Boots for £12.50. In Portugal the same pair of glasses is €15. If the exchange rate is £1 = €1.12, where are the glasses the cheapest? Show your working.

Answer:

45

Step-by-step explanation:

g(4) = 3 * 4 - 7 = 5

f[g(4)] = f(5) = 2 * 5² - 5 = 45

Answer:

45

Step-by-step explanation:

Answer: 8/7 And simplified simplified 1 1/7

Step-by-step explanation:

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Slopes and Tangents.

Basically the above data is the representation of the linear equation.

Thus the slope of linear equation is given as,

m = (y2-y1) / (x2-x1)

so taking any randoms numbers from the given table, we get as,

m = (14-7)/(16-8)

m= (7)/(8)

slope = m = 0.875

Answer:

-17.5℃

Step-by-step explanation:

Current temperature = 0 ℃

Rate of falling per hour = -3.5 ℃

Temperature in 5 hours = -3.5 * 5 = -17.5 ℃  

Answer:

logarithmic I think

Step-by-step explanation:

Use process of elimination

Answer:

C). linear

Step-by-step explanation:

test

Answer: A. 3 red squares to 6 green squares

Step-by-step explanation:

Method 1) Find a common factor between 15 and 30. For this problem, I'll pick 5. Divide both numbers by this common factor.

15/5=3 red squares

30/5=6 green squares

3 red squares to 6 green squares

Method 2) Find the greatest common factor between 15 and 30. The GCF is 15. Divide both numbers by the GCF.

15/15=1

30/15=2

This leaves you with a ratio of 1 red square to 2 green squares. 1:2 is equivalent to 3:6

3 red squares to 6 green squares

Answer:

B.

Step-by-step explanation:

Since we are moving the graph f(x) to the right 2 and down 1 with a reflection over the x-axis, we modify a, h, and k in f(x) = a(bx - h)² + k:

We would get f(x) = -(x - 2)² - 1 as our answer.

Answer:

x=pm-rm

Step-by-step explanation:

[tex]\frac{x}{m}+r=p\\\\ \frac{x}{m}+r-r=p-r\\\\\frac{x}{m}=p-r\\\\\frac{x}{m}*m=(p-r)*m\\\\\boxed{x=pm-rm; m\neq 0}[/tex]

Step-by-step explanation:

What was Given was that Point G is rotated 90°. The coordinate of the pre-image point G was (7, –5), and its image G’ is at the coordinate (5, 7).

What you need to find was : What is the direction of the rotation.

So coming to conclusions is we have given that Point G is rotated 90°.

The Pre-image of G = ( 7, -5).

Translated image G' = ( 5 ,7).

By the Rotation rule of 90° is : (-y, x) 90 degree rotation counterclockwise around the origin.

(y, -x) 90 degree rotation clockwise about the origin.

We can from G (7,-5) and G'( 5 ,7) it is rotation counterclockwise around the origin.

Therefore, Direction of rotation is counterclockwise around the origin.

Answer:

The answer is COUNTERCLOCKWISE

Step-by-step explanation:

edg

Answer:

A, C and D

Step-by-step explanation:

The missing inequality is:

y > 2x -4

To verify if a point is a solution, replace x into the equation, compute y, and see their relationship.

Option A: (-2,-5)

2(-2) -4 = -8

y = -5 > -8

then, the point is solution

Option B: (0,-4)

2(0) -4 = -4

y = -4 = -4

then, the point is not solution

Option C: (1,1)

2(1) -4 = -2

y = 1 > -2

then, the point is solution

Option D: (3,5)

2(3) -4 = 2

y = 5 > 2

then, the point is solution

Option E: (5,5)​

2(5) -4 = 6

y = 5 < 6

then, the point is not solution

Answer:

-4a + b

Step-by-step explanation:

Take away the parentheses (brackets) and solve.

-a + 2b - 3a - b

-a - 3a + 2b - b

-4a + b

Answer:

It's -[tex]4a + b[/tex]

Step-by-step explanation:

Simplify the expression.

Answer:

A. m∠2 + m∠3

Step-by-step explanation:

The exterior angle theorem states that the exterior angle formed when you extend the side of a triangle is equal to the sum of its non-adjacent angles.

So m∠4's non-adjacent angles are 2 and 3 NOT 1. Therefore, the measure of ∠4 = m∠2 + m∠3.

Hope this helps!

Answer:

A) m∠2 + m∠3

Step-by-step explanation:

Triangle Exterior Angle Theorem: The Sum of the outside angle is found using by adding the two opposite interior angles.

In the case of ∠4, the opposite interior angles are ∠2 & ∠3.

~

The correct expression with the correct statement has matched below.

The percentage is defined as a given amount in every hundred. It is a fraction with 100 as the denominator percentage is represented by the one symbol %.

The percentage is equivalent to the quantity of that value between 1 and 100, and it is highly helpful for forecasting. For instance, if you say 678, we must also know the whole number, but if you say 80%, it is obvious.

The price of a game that’s been discounted by 18% of its list price

It will be (x - 0.18x)  =  0.82x

The price of a toy that sells for 18% more than the amount needed to build the toy

It will be (x + 0.18x) = 1.18x

The volume of water remaining in a tank after 3/10 of its original volume is drained out.

It will be [ x - (3/10)x ] = 7/10x

The total amount of flour in a bakery after receiving new stock equal to 3/10 of the current stock.

It will be [ x + (3/10)x ] =  13/10x

For more about the percentage,

brainly.com/question/13450942

#SPJ5

Answer:

15

Step-by-step explanation:

you need to get to 35. if one bag is 5 pounds what else plus 5 is 35. so each bag is 15 pounds

Answer: 15

Step-by-step explanation:

35 - 5 = 30

30 ÷ 2 = 15

Hope this helped.

(15 each)

Answer:

-7.9, -7.881, -7.88, 0.07, 7.03.  

Step-by-step explanation:

Ascending, is just another word for "least to greatest."

To arrange these numbers from least to greatest, we start with the negative numbers. The negative numbers are: -7.88, -7.9, -7.881.

The greatest of these numbers would be the number that is closest to 0, and that would be -7.88.

Arranging these numbers should give us: -7.9, -7.881, -7.88.

The positive numbers are naturally greater than the negatives, and we see that 7.03 is greater than 0.07. Thus, we have the list of numbers to be: -7.9, -7.881, -7.88, 0.07, 7.03.  

Let me know if this helps :)

Answer:

I'm confused what's the question ?

The function that models the inverse variation is y=96/x. Thus, the correct option is A.

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

p = kq

where k is some constant number called the constant of proportionality.

This directly proportional relationship between p and q is written as

p∝q where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n be two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n} \\\\ \text{or} \\\\ n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called the constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n} \\\\ \text{or} \\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

Given that x and y vary inversely. Therefore, the relation can be written as,

y  ∝ 1/x

y = k × 1/x

y = k/x

Also, when y =8, the value of x is 12, therefore, if we substitute the points in the above-formed equation,

y = k/x

8 = k /12

k = 96

Hence, the function that models the inverse variation is y=96/x. Thus, the correct option is A.

Learn more about Directly and Inversely proportional relationships:

https://brainly.com/question/13082482

#SPJ2

Answer:

Tash scores 40 baskets

Step-by-step explanation:

Rani = R

Layla = L

Tash = T

R = 4L

T = 4L-8

As L + R + T = 100

L + 4L + 4L-8 = 100

Collect like terms

9L - 8 = 100

+ 8 both sides

9L = 108

divide by 9 both sides

L = 108 / 9

L = 12

Now..... T = 4L-8 substitute L with 12

T = 48 - 8

T = 40

Answer:

40/46+x=30/46-x

Step-by-step explanation:

Speed=distance/time

s=d/t

x=speed of the boat

Downstream speed=x+46

Upstream speed=x-46

Downstream

s=d/t

x+46=40/t

t=40/(x+46)

Upstream

s=d/t

x-46=30/t

t=30/(x-46)

Equate upstream and downstream

30/x-46=40/x+46

30(x+46)=40(x-46)

30x+1380=40x-1840

30x+1380-40x+1840=0

-10x+3220=0

-10x=-3220

Divide both sides by -10

x=322

x=322 miles/hour

Answer:

(a) The probability that a male is selected, then two females is 0.4352.

(b) The probability that a female is selected, then two males is 0.3348.

(c) The probability that two females are selected, then one male is 0.4352.

(d) The probability that three males are selected is 0.0717.

(e) The probability that three females are selected is 0.1583.

Step-by-step explanation:

We are given that a math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probability experiment.

(a) The probability that a male is selected, then two females is given by;

Number of ways of selecting a male from a total of 11 male = [tex]^{11}C_1[/tex]

Number of ways of selecting two female from a total of 14 female = [tex]^{14}C_2[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{11}C_1 \times ^{14}C_2}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{11!}{1! \times 10!} \times \frac{14!}{2! \times 12!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{1001}{2300}[/tex]  =  0.4352

(b) The probability that a female is selected, then two males is given by;

Number of ways of selecting a female from a total of 14 female = [tex]^{14}C_1[/tex]

Number of ways of selecting two males from a total of 11 male = [tex]^{11}C_2[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_1 \times ^{11}C_2}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{14!}{1! \times 13!} \times \frac{11!}{2! \times 9!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{770}{2300}[/tex]  =  0.3348

(c) The probability that two females is selected, then one male is given by;

Number of ways of selecting two females from a total of 14 female = [tex]^{14}C_2[/tex]

Number of ways of selecting one male from a total of 11 male = [tex]^{11}C_1[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_2 \times ^{11}C_1}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{14!}{2! \times 12!} \times \frac{11!}{1! \times 10!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{1001}{2300}[/tex]  =  0.4352

(d) The probability that three males are selected is given by;

Number of ways of selecting three males from a total of 11 male = [tex]^{11}C_3[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{11}C_3}{^{25}C_3}[/tex]

                                           =  [tex]\frac{ \frac{11!}{3! \times 8!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{165}{2300}[/tex]  =  0.0717

(e) The probability that three females are selected is given by;

Number of ways of selecting three females from a total of 14 female = [tex]^{14}C_3[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_3}{^{25}C_3}[/tex]

                                           =  [tex]\frac{ \frac{14!}{3! \times 11!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{364}{2300}[/tex]  =  0.1583

(a) The probability that a male is selected, then two females is 0.4352.

(b) The probability that a female is selected, then two males is 0.3348.

(c) The probability that two females are selected, then one male is 0.4352.

(d) The probability that three males are selected is 0.0717.

(e) The probability that three females are selected is 0.1583.

Answer:

v = -52

Step-by-step explanation:

Divide both sides by -5

v + 65 = 13

v = 13 - 65

v = -52

Answer:

v= -52

Step-by-step explanation:

-5(v+65)=-65

-5v-325=-65

-5v=260

v=-52

Answer:

[tex]1.\ \ p^2q = (\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}}[/tex]

[tex]2.\ \ pq^{\frac{3}{2}}} = (\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}[/tex]

[tex]3.\ \ pq^2 = \frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}[/tex]

[tex]4.\ \ p^2q^{\frac{1}{2}} = (p^6q^{\frac{3}{2}})^{\frac{1}{3}}[/tex]

Step-by-step explanation:

Required

Match each expression to their simplified form

1.

[tex](\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}}[/tex]

Simplify the expression in bracket by using the following law of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

The expression becomes

[tex](\frac{p^{5-(-3)}}{q^{-4}})^{\frac{1}{4}}[/tex]

[tex](\frac{p^{5+3}}{q^{-4}})^{\frac{1}{4}}[/tex]

[tex](\frac{p^8}{q^{-4}})^{\frac{1}{4}}[/tex]

Split the fraction in the bracket

[tex](p^8*\frac{1}{q^{-4}})^{\frac{1}{4}}[/tex]

Simplify the fraction by using the following law of indices;

[tex]\frac{1}{a^{-m}} = a^m[/tex]

The expression becomes

[tex](p^8*q^4)^{\frac{1}{4}}[/tex]

Further simplify the expression in bracket by using the following law of indices;

[tex](ab)^m = a^m * b^m[/tex]

The expression becomes

[tex](p^{8*\frac{1}{4}}\ *\ q^4*^{\frac{1}{4}})[/tex]

[tex](p^{\frac{8}{4}}\ *\ q^{\frac{4}{4}})[/tex]

[tex]p^2q[/tex]

Hence,

[tex](\frac{p^5}{p^{-3}q^{-4}})^{\frac{1}{4}} = p^2q[/tex]

2.

[tex](\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}[/tex]

Simplify the expression in bracket by using the following law of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

The expression becomes

[tex]({p^2q^{7-4}}})^{\frac{1}{2}}[/tex]

[tex]({p^2q^3}})^{\frac{1}{2}}[/tex]

Further simplify the expression in bracket by using the following law of indices;

[tex](ab)^m = a^m * b^m[/tex]

The expression becomes

[tex]{p^{2*\frac{1}{2}}q^{3*\frac{1}{2}}}}[/tex]

[tex]pq^{\frac{3}{2}}}[/tex]

Hence,

[tex]pq^{\frac{3}{2}}} = (\frac{p^2q^7}{q^{4}})^{\frac{1}{2}}[/tex]

3.

[tex]\frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}[/tex]

Simplify the numerator as thus:

[tex]\frac{p^{\frac{1}{2}} * q^3*^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}[/tex]

[tex]\frac{p^{\frac{1}{2}} * q^{\frac{3}{2}}}{(pq)^{\frac{-1}{2}}}[/tex]

Simplify the denominator as thus:

[tex]\frac{p^{\frac{1}{2}} * q^{\frac{3}{2}}}{p^{\frac{-1}{2}}q^{\frac{-1}{2}}}[/tex]

Simplify the expression in bracket by using the following law of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

The expression becomes

[tex]p^{\frac{1}{2} - (\frac{-1}{2} )} * q^{\frac{3}{2} - (\frac{-1}{2}) }[/tex]

[tex]p^{\frac{1}{2} +\frac{1}{2} } * q^{\frac{3}{2} + \frac{1}{2} }[/tex]

[tex]p^{\frac{1+1}{2}} * q^{\frac{3+1}{2}}[/tex]

[tex]p^{\frac{2}{2}} * q^{\frac{4}{2}}[/tex]

[tex]pq^2[/tex]

Hence,

[tex]pq^2 = \frac{(pq^3)^{\frac{1}{2}}}{(pq)^{\frac{-1}{2}}}[/tex]

4.

[tex](p^6q^{\frac{3}{2}})^{\frac{1}{3}}[/tex]

Simplify the expression in bracket by using the following law of indices;

[tex](ab)^m = a^m * b^m[/tex]

The expression becomes

[tex]p^6*^{\frac{1}{3}}\ *\ q^{\frac{3}{2}}*^{\frac{1}{3}}[/tex]

[tex]p^{\frac{6}{3}}\ *\ q^{\frac{3*1}{2*3}}[/tex]

[tex]p^2 *\ q^{\frac{3}{6}}[/tex]

[tex]p^2 *\ q^{\frac{1}{2}[/tex]

[tex]p^2q^{\frac{1}{2}[/tex]

Hence

[tex]p^2q^{\frac{1}{2}} = (p^6q^{\frac{3}{2}})^{\frac{1}{3}}[/tex]

Answer:

A domain of a parabola is all real numbers because you can input any x-value into the equation.

Step-by-step explanation:

Since there are no restrictions of numbers you can put in x², we can plug anything in. Therefore, our domain is infinite numbers.

Answer:

y-intercept: (0, 2.5)

x-intercept: (1.67, 0)

Step-by-step explanation:

Right now, you have 3x + 2y = 5. You want to change it into slope-intercept form to make the problem easier to solve.

2y = -3x + 5

y = -3/2x + 5/2

From here, you can see that the y-intercept is (0, 5/2). You can also say that the y-intercept is (0, 2.5).

To get the x-intercept, substitute 0 for y.

0 = -3/2x + 5/2

3/2x = 5/2

3x = 5

x = 5/3

So, the x-intercept is (5/3, 0). You can also say that the x-intercept is (1.67, 0).

Hope this helps!

Answer:

Step-by-step explanation:

To find the x-intercept, let y = 0.  Then 3x = 5 and x = 5/3, or x = 1.667, and the x-intercept is (1.667, 0).

To find the y-intercept, let x = 0.  Then 2y = 5 and y = 5/2 or 2.5.  Then the y-intercept is (0, 2.5).

Answer:

see below

Step-by-step explanation:

1.the equations have different slopes?  They will intersect at one point so one solution

2.the equations have the same slope and different y-intercepts.  They are parallel lines with a different y intercept so they will never intersect - no solutions

3.the equations have the same slope and same y-intercepts. they are the same line so they have infinite solutions

Answer:

1. One solution

2. no solution

3. infinite number of solutions.

Step-by-step explanation:

How many solutions a system of linear equations have if: Questions.

(assuming a system of two equations)

1.the equations have different slopes?

One unique solution, which is at the intersection point.

2.the equations have the same slope and different y-intercepts.

The equations/lines are then parallel but NOT coincident.  They will never meet, therefore NO solution.

3.the equations have the same slope and same y-intercepts.

The two lines/equations are in effect coincident.  Therefore there is an infinite number of solutions.

Answers. A.no solutions. B.infinetly as many solutions C.two solutions. D.one solution

Answer:

? = 56.

Step-by-step explanation:

In the problem, the side 20 corresponds to side 32 and side 20 + 35 corresponds to side 32 + ?.

[tex]\frac{20}{32} =\frac{20 + 35}{? + 32}[/tex]

[tex]\frac{5}{8} =\frac{55}{? + 32}[/tex]

[tex]\frac{1}{8}=\frac{11}{? + 32}[/tex]

? + 32 = 8 * 11

? + 32 = 88

? = 56.

Hope this helps!

Answer:

56

Step-by-step explanation:

We can find the missing side length through ratios.

20/35 = 32/x

Cross multiply.

20x = 35(32)

20x = 1120

x = 1120/20

x = 56

Answer:

y intercept is -19/6

Step-by-step explanation:

The slope intercept form of a line is given by

y = mx+b where m is the slope and b is the y intercept

y = 16/13x - 19/6

The slope is 16/13 and the y intercept is -19/6

Answer:

[tex]\boxed{-\frac{19}{6} }[/tex]

Step-by-step explanation:

Use slope-intercept formula.

[tex]y=mx+b[/tex]

[tex]m[/tex] is the slope of the line.

[tex]b[/tex] is the y-intercept of the line.

The equation of the line is already in slope-intercept form.

[tex]y=\frac{16}{3} x+-\frac{19}{6}[/tex]

[tex]b= -\frac{19}{6}[/tex]

Answer:

1 10/17

I answered it in the pervious question

Answer:

Your correct answer is option C. Equilateral triangles

Step-by-step explanation:

In similar polygons, it is all the corresponding angles that are congruent.

Answer:

4

Step-by-step explanation:

I'm guessing that each number represents the number of rectangles that overlap. Where you see 1, there is only one rectangle, 2 shows where two rectangles overlap, and so on.

At the question mark, it appears as though four rectangles overlap. So a 4 would go there.