Answer:
Can you give me your snap, so I can send you the foto
5. How many moles of aluminum sulfate would contain 3.54 x 1025 sulfur atoms?
Answer:
19.6 moles of aluminum sulfate
Explanation:
Given parameters:
Number of sulfur atoms = 3.54 x 10²⁵ atoms
Unknown:
Number of moles of aluminum sulfate = ?
Solution:
Aluminum sulfate is expressed as;
Al₂(SO₄)₃
1 mole of Aluminum sulfate contains 3 moles of sulfur.
6.02 x 10²³ atoms are found in 1 mole of any substance;
3.54 x 10²⁵ sulfur atoms will be found in [tex]\frac{3.54 x 10^{25} }{6.02 x 10^{23} }[/tex] = 58.8moles of sulfur
1 mole of Aluminum sulfate contains 3 moles of sulfur.
or ;
3 moles of sulfur is contained in 1 mole of aluminum sulfate
58.8moles of sulfur will contain [tex]\frac{58.8}{3}[/tex] moles of aluminum sulfate
= 19.6 moles of aluminum sulfate
How did the instrument in the picture help to disprove part of Dalton's atomic model?
A)
It showed all matter is made of atoms and that atoms are indivisible and
indestructible.
B)
It showed that all atoms of a particular element are not identical.
C)
It showed that compounds are formed by a combination of two or more
different kinds of atoms.
D)
It showed that a chemical reaction is a rearrangement of atoms.
No
Answer:
It’s b;)
Explanation:
Answer:
B is correct
Explanation:
Write the overall molecular equation for the reaction of hydroiodic acid ( HI ) and potassium hydroxide. Include physical states. Enter the formula for water as H2O .
Answer:
HI(aq) + KOH(aq) --> KI(aq) + H2O(l)
Explanation:
HI is an acid and KOH is a base, this means that the reaction would be a neutralization reaction.
The equation is given as;
HI + KOH --> KI + H2O
Adding the physical states we have;
HI(aq) + KOH(aq) --> KI(aq) + H2O(l)
3. What is the pairing arrangement of the nitrogenous bases? _____________ pairs with __________ and ____________ pairs with ___________.
Answer:
Adenine pairs with thymine and guanine pairs with cytosine
Consider the balanced equation.
CuSO4 + Zn Right arrow. ZnSO4 + Cu
If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?
1.253 g
50.72 g
79.63 g
194.3 g
Answer:
79.63
Explanation:
what is the source of the force that moves the tectonic plates along this plate boundary
Answer:
Mantle convection
Explanation:
The source of the force that moves tectonic plates along plate boundaries is as a result of the mantle convection.
Heat energy produced in the mantle especially from radioactive decay is a very important source of internal heat that drives plate motion. Denser and cold materials close to the over-riding lithosphere above sinks deep into the mantle. Hotter and lighter materials rises to the surface. This sets up a convection cell by which the plates above are driven.2. Suppose 13.7 g of C2H2 reacts with 18.5 g O2 according to the reaction below. C2H2(g) + O2(g) → CO2(g) + H2O(ℓ) a. What is the mass of CO2 produced? b. What is the limiting reagent?
Answer:
Mass of CO₂ produced = 20.328 g
Oxygen is limiting reagent.
Explanation:
Given data:
Mass of C₂H₂ = 13.7 g
Mass of O₂ = 18.5 g
Mass of CO₂ produced = ?
What is limiting reagent = ?
Solution:
Chemical equation:
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
Number of moles of C₂H₂:
Number of moles = mass /molar mass
Number of moles = 13.7 g/ 26.04 g/mol
Number of moles = 0.526 mol
Number of moles of O₂:
Number of moles = mass /molar mass
Number of moles = 18.5 g/ 32 g/mol
Number of moles = 0.578 mol
Now we will compare the moles of CO₂ with C₂H₂ and O₂
C₂H₂ : CO₂
2 : 4
0.526 : 4/2×0.526 = 1.052
O₂ : CO₂
5 : 4
0.578 : 4/5×0.578 = 0.462
The number of moles of CO₂ produced by O₂ are less thus oxygen will be limiting reactant.
Mass of CO₂ produced:
Mass = number of moles × molar mass
Mass = 0.462 mol × 44 g/mol
Mass = 20.328 g
How many grams of CO2 are produced from 10 grams of C2H6
Answer:
Explanation:
no of moles of C2H6=10/30=0.33
complete combustion of 2 moles of ethane produce 4 moles of CO2 therefore 0.33 moles of C2H6 produced 0.66 moles of CO2
now moles =given mass/molar mass
mass= moles*molar mass
mass of CO2=0.67*44=29.48 g
A sample of compound contains 5.65x10 21 molecules molar mass of the compound is 89.06g/ mol determine the mass of the sample in grams
Answer:
Explanation:
no of molecules=5.65*10^21
NA=6.23*10^23
no of moles=no of molecules/avogadro number
no of moles=5.65*10^21/6.23*10^23
no of moles=9.07*10^-3
now we know that
no of moles=mass/molar mass
mass=no of moles*molar mass
mass=9.07*10^-3*89.06
mass=0.808 g
How many milliliters of 2.00 M H2SO4 will react with 28.0 g of NaOH?
Taking into account the reaction stoichiometry and the definition of molarity, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.
Reaction stoichiometryIn first place, the balanced reaction is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
H₂SO₄: 1 moleNaOH: 2 moles Na₂SO₄: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
H₂SO₄: 98 g/moleNaOH: 40 g/moleNa₂SO₄: 142 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
H₂SO₄: 1 mole× 98 g/mole= 98 gramsNaOH: 2 moles× 40 g/mole= 80 gramsNa₂SO₄: 1 mole× 142 g/mole= 142 gramsH₂O: 2 moles× 18 g/mole= 36 gramsDefinition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity= \frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Moles of H₂SO₄ requiredThe following rule of three can be applied: If by reaction stoichiometry 80 grams of NaOH react with 1 mole of H₂SO₄, 28 grams of NaOH react with how many moles of H₂SO₄?
[tex]moles of H_{2}S O_{4} =\frac{28 grams of NaOHx1 mole ofH_{2}S O_{4} }{80 grams of NaOH}[/tex]
moles of H₂SO₄= 0.35 moles
Volume of H₂SO₄ requiredIn this case, you know:
Molarity= 2 M= 2 [tex]\frac{moles}{liter}[/tex]amount of moles= 0.35 molesReplacing in the definition of molarity:
[tex]2 \frac{moles}{liter}= \frac{0.35 moles}{volume}[/tex]
Solving:
2 [tex]\frac{moles}{liter}[/tex] × volume= 0.35 moles
volume= 0.35 moles ÷ 2 [tex]\frac{moles}{liter}[/tex]
volume= 0.175 liters= 175 mL (being 1 L= 1000 mL)
Finally, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.
Learn more about
the reaction stoichiometry:
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molarity:
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The internal energy of reaction is -855.1). The reaction has a change of
temperature of 63.20°C that consist of 8.85g of material. Assume the
heat capacity of 2.650J/g °C. What is the work energy of this process..
The work energy of this process : 2337.298 J
Further explanationThe laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created
ΔU=Q-W
Q=m.c.Δt
[tex]\tt Q=8.85\times 2.650\times 63.2=1482.198~J[/tex]
the work (W) :
[tex]\tt W=Q-\Delta U\\\\W=1482.198-(-855.1)=2337.298~J[/tex]
Sulfur has an electronegativity of 2.58, while Cesium has a value of 0.79. Based on this information, they would have what kind of chemical bond?
Answer:
Ionic
Explanation:
Because sulphur is a non-metal and cesium is part of the group 1 Alkali Metals, this creates an ionic bond
Ionic bonds are created from one metal and one non-metal element.
This still is declared as Ionic despite the balance of this is Cs2S
what are the reactants in a cheese sandwich
Answer:
cheese and bread
Explanation:
2 bread 1 cheese = cheese sandwich
Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reaction below. What mass (in grams) of NaN4is required to provide 40.0 L of N2 at 25°C and 763 torr?
Answer:
The answer is 95 degree celcius
WILL GIVE 50 POINTS AND BRAINLIEST
Plate Tectonics Lab Report
Instructions: In the Plate Tectonics lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name Boundary Type
(C=Convergent, D=Divergent, or T=Transform) Year Observed
(5, 10, or 20 million years) Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas 5 Event 1-
20 Event 2-
Location Two
East Africa 5 Event 1-
10 Event 2-
20 Event 3-
Location Three
San Andreas fault zone 5 Event 1-
10 Event 2-
20 Event 3-
Location Four
Aleutian Islands 5 Event 1-
20 Event 2-
Location Five
Mid-Atlantic Ridge 5 Event 1-
10 Event 2-
20 Event 3-
Location Six
Alpine Fault 5 Event 1-
20 Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
Answer:
here are what i have so far, im doing this right now
Explanation:
Plate Tectonics Lab Report
Instructions: In the Plate Tectonic lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. Y
Objective(s):
To look at interactions between continental and oceanic plates, etc.
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select three events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
• earthquakes
• mountains
• volcanoes
Location Two: Select three events that you predict will be observed. If explore two continental plates at a divergent boundary, then I will observe:
• ocean formation
• volcanoes
• seafloor spreading
you will submit your completed report
ps; you might want to change up the objective.
A geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
What is geological event?A geological event is a brief, spatially diverse, dynamic (diachronous), and ongoing occurrence in the history of the Earth that aids in the modification of the Earth system and the production of geological strata. The concept of event stratigraphy initially came up as a way to identify, analyse, and correlate how significant physical and biological events have affected the overall stratigraphical record.
Israel's Dead Sea basin Holocene sediments contain seismic activity. This can be considered a record of a geological event, an earthquake, that altered the strata. Geological events can occur over timescales of order of magnitude, from just a few seconds through millions of years, as well as on a variety of spatial scales, from the local to the globe.
1. Volcanoes and minor earthquakes
2. Volcanoes, earthquakes and fold mountains.
3. Earthquakes and fold mountains.
4. Magma from volcanoes is filled with nutrients that makes land fertile.
Therefore, a geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
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A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine if each addition would exceed the capacity of the buffer to neutralize it.
a. 250 mg NaOH
b. 350 mg KOH
c. 125 g HBr
d. 1.35g Hl
Answer:
no one additions exceed the capacity of the buffer
Explanation:
given
Volume buffer = 500.0 mL = 0.5 L
mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂
mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻
solution
we know when any base more than 0.05 (HNO2) than exceed buffer capacity
and when any base more than 0.075 (KNO2) than exceed buffer capacity
when we add 250 mg NaOH (0.250 g)
than molar mass NaOH =40 g/mol
and mol NaOH = 0.250 g ÷ 40g/mol
mol NaOH = 0.00625 mol
0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂
so it would not exceed the capacity of the buffer.
and
when we add 350 mg KOH (0.350 g)
than molar mass KOH =56.10 g
and mol KOH = 0.350 g ÷ 56.10 g/mol
mol KOH = 0.0062 mol
here also capacity of the buffer will not be exceeded
and
now we add 1.25 g HBr
than molar mass HBr = 80.91 g/mol
and mol HBr = 1.25 g ÷ 80.91 g/mol
mol HBr = 0.015 mol
0.015 mol Hbr will neutralize 0.015 mol NO₂⁻
so the capacity will not be exceeded.
and
we add 1.35 g HI
molar mass HI = 127.91 g/mol
so mol HI = 1.35 g ÷ 127.91 g/mol
mol HI = 0.011 mol
capacity of the buffer will not be exceed
Why is Mg++ smaller than Mg atom?
Answer:
The magnesium ion is much smaller than the magnesium atom because magnesium atom contains more electrons as compared to magnesium ion. Explanation: ... Whereas when an atom tends to lose an electron then it acquires a positive charge and size of the atom tends to increase.
Answer:
Because it looses it two electrons to form a stable octet Ionic form..........
Based on your lab report, provide the chemical reaction that occurs in Benedict's test for the following molecule.
Explanation:
I DONT UNDERSTAND WHAT U WANT TO SAY
What happens to the gravitational potential energy of an object if you bring it higher with respect to the ground? *
Answer:
Increases
Explanation:
The gravitational potential energy of an object increases as you bring it higher with respect to the ground.
Gravitational potential energy depends on the mass, height and gravity between two bodies;
Gravitational potential energy = mgh
m is the mass
g is the height
h is the height
We can clearly see that the higher the elevation, the more the value of the gravitational potential energy.A ballon that contains 0.75 l of gad at 25 c is cooled to - 100 c. Calculate the new volume of the baloon
Answer:
0.44L
Explanation:
Given parameters:
Initial volume = 0.75L
Initial temperature = 25°C = 273 + 25 = 298K
Final temperature = -100°C = 273 + (-100) = 173K
Unknown:
New volume of the balloon = ?
Solution:
According to Charles's law;
"the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".
Mathematically;
[tex]\frac{V_{1} }{T_{1} }[/tex] = [tex]\frac{V_{2} }{T_{2} }[/tex]
V and T are temperature values
1 and 2 are the initial and final states
Insert the parameters and solve;
[tex]\frac{0.75}{298}[/tex] = [tex]\frac{V_{2} }{173}[/tex]
298V₂ = 129.75
V₂ = 0.44L
PLS HURRY
What methods are you using to test this (or each) hypothesis?
Answer:
Fair test.
PLS GIVE BRAINLIEST
compare the size of I, I+ and I-
umm explanation pls so i answee
Which determines the reactivity of an alkali metal?
a. it's boiling and melting points
b. the shininess of its surface
c. the number of protons it has
d. it's ability to lose electrons
Answer:
d. It's ability to lose electrons
Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Write the equation for the ionization of ammonia in water.
List all species present in the solution AND determine the concentrations of each.
Determine the pH of this solution.
The concentrations : 0.15 M
pH=11.21
Further explanationThe ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
[tex]\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}[/tex]
[tex]\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21[/tex]
Graphite is sometimes used to reduce the friction between
two surfaces that are rubbing together.
Explain how it does this.
Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. Therefore, this happen because of weak covalent bond.
What is graphite?Graphite is among the most prevalent carbon allotropes. It is also the stable allotrope for carbon, and as such, it is employed in electrochemistry to define the heat of synthesis of carbon compounds. With a hardness of 2.09-2.23 g/cm3, graphite is an excellent conductor of electricity and heat.
Graphite is a large covalent structure in which each carbon atom is covalently linked to three other carbon atoms. Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.
Therefore, graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.
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In a classroom, which comparison would a teacher most likely use for describing a mole?
a cup of water and a liter of oil
a dozen eggs and a dozen jellybeans
a jar of jellybeans and a gram of salt crystals
20 marbles in a bag and 10 large ice cubes
Answer:
B
Explanation:
a mole is "a chemist's dozen" lol
state Graham's law diffusion of gas mathematical expression ?
Answer:
Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight
Explanation:
Can someone please help me quick !!!
9. What are the advantages of using an indicator to inform pH measurements? What are the advantages of using a pH meter?
Answer:
The advantages of using an indicator to inform pH measurements:
It gives a mathematically result of the pH, in addition, it gives the precise pH of solvent, and it also gives an idea of the straight of the solution also.
Now, the advantage of using a pH meter:
It is a rapid method to characterize between acids, bases. However, this method does not show how strong acid or base actually are, plus it tends to gives a range of acidity or basicity not quite accurate as a result.
Considering the patterns you have noticed in this activity, which statement best explains why a compound with the molecular formula CH3 doesn't exist in nature?
A. Hydrogen typically needs four bonds to reach a noble gas configuration.
B. Carbon needs more than just three bonds to reach a noble gas configuration. C. The chemical CH3 does not react with other substances because of its high stability.
D. CH3 has three double bonds, which fails to give it a noble gas configuration
Answer:
The answer is B
Explanation:
I had the same question and I chose B and it was correct.
Answer:
B. Carbon needs more than just three bonds to reach a noble gas
Explanation:
PLATO ANSWER
PLATO EXPLANATION-
Each hydrogen atom can make only one bond, but a carbon atom needs four bonds to be stable. Therefore, three hydrogen atoms are not enough for the carbon atom to make four bonds.