Please help i will mark brainliest for correct answers!​

Answer:

C

Step-by-step explanation:

It is an iscoceles triangle because there are 180 degrees in a triangle and the right angle plus the 45 degree equals 135 and 180 minus 135 is 45.

Since it is an iscoceles triangle that means that n = 3 and the pythagorean theorom says that a^2 + b^2 = c^2 which means that m = 3^2 plus 3^2 with a root.

3^2 is 9 so you get 18

the root of 18 is infinite, however can be simplified to 3 root to 2 because 3 times 3 equals 9 times 2 equals a root of 18

Hope this helps!

Answer:

$0.56/lb

Step-by-step explanation:

Given

Cost of a chicken = $2.15 per pound

26 pound of a chicken = $41.34

Required

Calculate how much saved.

The first step is to calculate the unit price of a chicken when 26 pound of chicken was bought.

Unit Price = Price ÷ Weight

Unit Price = $41.34 ÷ 26lb

Unit Price = $1.59/lb

The next step is to calculate the difference between these two prices

Difference = |$1.59/lb - $2.15/lb|

Difference = |-$0.56/lb|

Difference = $0.56/lb

The calculated difference is the amount saved per pound of chicken when I bought 26 pound of chicken.

Answer:

the amount of fuel consumed every 100 kilometers is 62.5 litres.

Step-by-step explanation:

To determine the amount of fuel consumed every 100 kilometers.

Note: since the graph is a straight line graph (linear graph) the amount of fuel consumed every 100 kilometers is constant (i.e the same for every 100 kilometers). So, we only need to derive the amount of fuel consumed any 100 kilometers on the graph.

From the graph, the amount of fuel consumed for the first 100 kilometers is;

[tex]F = F_0 - F_{100} .........................1[/tex]

[tex]F_0 = 500\\F_{100} \simeq 437.5\\[/tex]

substituting into equation 1.

[tex]F = F_0 - F_{100} \\F = 500 - 437.5\\ F = 62.5 litres\\[/tex]

Therefore, the amount of fuel consumed every 100 kilometers is 62.5 litres.

Answer:500

Step-by-step explanation:got it on Kahn

Answer:

True.

Step-by-step explanation:

The function is indeed a polynomial. We have the single variable [tex]x[/tex] plus a constant [tex]\pi[/tex] (it's irrational, but it's still simply just a constant number). This fits the definition of polynomials.

Answer:

Option A) Speed = 1/20 of an inch per minute

Step-by-step explanation:

Given:

Distance = 6 inches

Time = 120 mins

Required:

Average Speed = ?

Formula:

Average Speed = Total Distance Covered / Total Time Taken

Solution:

Speed = 6/120

Speed = 1/20 of an inch per minute

Answer:

[tex]\frac{1}{20}[/tex] of an Inch per minute

Step-by-step explanation:

Speed = Distance ÷ Time

So....

6 ÷ 120 = 0.05 or [tex]\frac{1}{20}[/tex]

Also by process of elimination

[tex]\frac{1}{2}[/tex] of an inch per min would complete 6 inches in 12 min.

2 inches per min would complete 6 inches in 3 min

20 inches per minute would complete 6 inches in a few seconds.

Drop a perpendicular from [tex]\overline{AK}[/tex] to $\overline {DE}$.

Let $l(AK)=h$ and $l(AB)=l(DC)=L$

$h$ is the height of the parallelogram and the triangle.

$L$ is the length of the base of the triangle and one of the sides of parallelogram.

We have area of parallelogram $=A_{para}=hL$

And the area of triangle is:

$A_{tria}=\frac{1}{2} h\times (L+L)=hL$

Thus we can see that they are equal.

Answer:

See below

Step-by-step explanation:

Given:

ABCD is a parallelogram

DC = CE

To Prove:

area of the ADE triangle is equal to the area of the parallelogram​.

Proof:

Let The Point between B and C be F

To prove that area of the ADE triangle is equal to the area of the parallelogram​, we'll first prove that ΔADF ≅ ΔECF

Statements                             |               Reason

DC ≅ CE                                  |                Given

But,  CD ≅ AB                         |    Opposite sides of a ║gm

So,  CE ≅ AB                           |   Transitive Property of Equality

∵  ΔABF ↔ ΔECF                    |

 CE ≅ AB                                |       Already Proved

  ∠CFE ≅ ∠ BFE                     |       Vertical Angles

  ∠ECF ≅ ∠ABF                      |      Alternate Angles

So, ΔABF ≅ ΔECF                   |    S.A.A.  Postulate

Now,                                         |

Area of ║gm = Area of            |

quad ADCF + ΔABF                |

But,    ΔABF ≅ ΔECF               |        Already Proved

So,                                            |

Area of ║gm = Area of            |

quad ABCF + ΔECF                 |

But Area of ΔADE = Area of   |

quad ABCF + ΔECF                 |

So,                                            |

Area of ║gm = Area of ΔADE |     Hence Proved

Answer:

Step-by-step explanation:

x + 2x + 4x = 49

7x = 49

x = 7

2(7)= 14 hours he worked on Wednesday

Answer:

Simplifying

41 = 12d + -7

Reorder the terms:

41 = -7 + 12d

Solving

41 = -7 + 12d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-12d' to each side of the equation.

41 + -12d = -7 + 12d + -12d

Combine like terms: 12d + -12d = 0

41 + -12d = -7 + 0

41 + -12d = -7

Add '-41' to each side of the equation.

41 + -41 + -12d = -7 + -41

Combine like terms: 41 + -41 = 0

0 + -12d = -7 + -41

-12d = -7 + -41

Combine like terms: -7 + -41 = -48

-12d = -48

Divide each side by '-12'.

d = 4

Simplifying

d = 4

Answer:

Greater than the original = 2, 4

Less than the original = 5

Same as the original = 1, 3

Step-by-step explanation:

Let the original value be x.

1. A $30 increase followed by a $30 decrease.

New value [tex]=x+30-30=x[/tex], it is same as original value.

2. A 20% decrease followed by a 40% increase.

Afer 20% decrease.

New value [tex]=x-\dfrac{20}{100}x=x-0.2x=0.8x[/tex]

Afer 40% increase.

New value [tex]=0.8x+\dfrac{40}{100}(0.8x)=0.8x+0.32x=1.12x[/tex], it is greater than original value.

Similarly check the other values.

3. A 100% increase followed by a 50% decrease.

New value [tex]=x+\dfrac{100}{100}x-\dfrac{50}{100}(x+x)=x[/tex], it is same as original value.

4. A 75% increase followed by a 33% decrease

New value [tex]=x+\dfrac{75}{100}x-\dfrac{33}{100}(x+0.75x)=1.1725x[/tex], it is greater than the original value.

5. 55% decrease followed by a 25% increase

New value [tex]=x-\dfrac{55}{100}x+\dfrac{25}{100}(x-0.55x)=0.5625x[/tex], it is less than the original value.

Therefore, Greater than the original = 2, 4, Less than the original = 5, Same as the original = 1, 3 .

A 100% increase followed by a 50% decrease

A $30 increase followed by a $30 decrease

55% decrease followed by a 25% increase

A 20% decrease followed by a 40% increase

A 75% increase followed by a 33 1/3% decrease

Answer:

Step-by-step explanation:

7 + 3i / 2 - 5i would be clearer if written as (7 + 3i) / (2 - 5i).  We must remove the symbol i from the denominator, and that can be accomplished by multiplying both 7 + 3i and 2 - 5i by the conjugate 2 + 5i:

(2 + 5i)(7 + 3i)

--------------------

     4 + 29

which simplifies to     14 + 6i + 35i - 15 over 33, or

-1 + 41i

------------

    33

Answer:

a= 4[tex]\sqrt{6}[/tex]

b= 8[tex]\sqrt{2}[/tex]

c= 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

45-45-90 triangle

x - x - [tex]\sqrt{2}[/tex]

30-60-90 triangle

x - 2x - x[tex]\sqrt{3}[/tex]

Answer:

First question = 800 cm^3

Second question =120π

Step-by-step explanation:

The formula for volume is base x height x width.

The formula for area of cylinder is 2πrh+2πr^2 but it has no lid so

2πrh+πr^2.

Answer:

Step-by-step explanation:

The relation describe in the table Continuous .

The domain of the relation is X- values greater than or equal to 0 .

The range of the. Relation is Y- values greater than or equal to 0

Answer:

The relation described in the table is  continuous

The domain of the relation is   x-values greater than or equal to 0

The range of the relation is  y-values greater than or equal to 0

Step-by-step explanation:

Any number of pounds of almonds can be purchased, including partial amounts, so the relation described in the table is continuous.

Because x can be any positive number of pounds, the domain of the relation is x ≥ 0, or x-values greater than or equal to 0.

Because y can be any positive dollar amount, the range of the relation is y ≥ 0, or y-values greater than or equal to 0.

Answer:

Step-by-step explanation:

let width=x

length=3x

area=3x×x=3x²

3x²=192

x²=192/3=64

x=√64=8

width=8 m

length=3×8=24 m

Answer:

Solution,

Let the length be 3x meter.

Let the width be X meter

Area of rectangle= 192 square metres

Now,

Area of rectangles= length * breath

[tex]192 = 3x \times x \\ 192 = 3 {x}^{2} \\ {x}^{2} = \frac{192}{3} \\ x^{2} = 64 \\ x = \sqrt{64} \\ x = 8 \: meter[/tex]

Replacing value,

[tex] \: \: \: 3 \times x \\ \: \: = 3 \times 8 \\ \: \: \: \: = 24[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

(5a^2-4)*(25a^4+20a^2+16)

Step-by-step explanation:

Answer:

Its B, (5a^2-4)(25a^4+20a^2+16)

Step-by-step explanation:

Edge 2020

Answer:

Step-by-step explanation:

x=✓64*36=✓8^2*6^2

x=8*6

x=48

Answer:

Step-by-step explanation:

5. cut the five fruits into 3 equal parts....

5x3=15 pieces

15/3(bowls)=5 pieces in each bowl

cut the fruits in multiples of 5 divisible by 3....that many ways possible

(similarly 4th qstion can be done)!!

The number of possible outcomes there could be at the end of their game is 6 outcomes

This is a permutation problem since it required arrangement

If Alex, Toby, and Samuel are playing a game together and at the end, they will make a classification with one of them in first  place, one of them in Second place and one of them in Third place, this can be done in 3! ways

Since n! = n(n-1)(n-2)!

Hence 3! = 3(3-1)(3-2)

3! = 3 * 2 * 1

3! = 6 ways

Hence the number of possible outcomes there could be at the end of their game is 6 outcomes

Learn more here: https://brainly.com/question/24115376

Answer:

The correct statements are:

1: mEFD = mEGD

3: mED = mFD

5: mFD = 120°

Step-by-step explanation:

Let's analyse each statement:

1: mEFD = mEGD

Let's find the value of the angle ECD, using the sum of the internal angles of a quadrilateral:

[tex]60 + 90 + 90 + mECD = 360[/tex]

[tex]mECD = 120\°[/tex]

The angle ECD is a central angle, related to the arc ED, so the arc ED also has 120°.

The angle EFD inscribes the arc ED, so we have:

[tex]mEFD = mED/2[/tex]

[tex]mEFD = 120/2 = 60\°[/tex]

So the angles mEFD and mEGD are equal. The statement is TRUE.

2. mEGD = mECD

This statement is FALSE, because mEGD = 60° and mECD = 120°

3. mED = mFD

If mED is 120° and mEF = mFD, we have:

[tex]mED + mEF + mFD = 360[/tex]

[tex]2*mFD = 360 - 120[/tex]

[tex]mFD = 120\°[/tex]

So the statement is TRUE, both arcs have 120°.

4. mEF = 60°

This statement is FALSE, because we calculated before that mEF = mFD = 120°

5. mFD = 120°

This statemente is TRUE, because we calculated before that mFD = 120°.

So the correct statements are 1, 3 and 5

The true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]

Start by calculating the measure of angle ECD.

We have:

[tex]\angle ECD = 2 * \angle EGD[/tex]

So, we have:

[tex]\angle ECD = 2 * 60[/tex]

[tex]\angle ECD = 120[/tex]

The above means that:

[tex]\overset{\huge\frown}{ED} = 120[/tex]

So, the measure of angle EFD is:

[tex]\angle EFD = 0.5 * \overset{\huge\frown}{ED}[/tex]

[tex]\angle EFD = 0.5 * 120[/tex]

[tex]\angle EFD = 60[/tex]

From the question, we have:

[tex]\angle EGD = 60[/tex]

So, it is true that:

[tex]\angle EFD =\angle EGD[/tex]

To calculate the measure of arc FD, we have:

[tex]\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} + \overset{\huge\frown}{EF} =360[/tex]

Lengths EF and DE are congruent.

So, we have:

[tex]2\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} =360[/tex]

[tex]\overset{\huge\frown}{DE} = \overset{\huge\frown}{ED} = 120[/tex]

So, we have:

[tex]2\overset{\huge\frown}{FD} + 120 =360[/tex]

Divide through by 2

[tex]\overset{\huge\frown}{FD} + 60 =180[/tex]

Subtract 60 from both sides

[tex]\overset{\huge\frown}{FD} =120[/tex]

This means that:

[tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex] are true

Hence, the true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]

Read more about cyclic theorems at:

https://brainly.com/question/26168678

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Answer:

134 will be heads.

Step-by-step explanation:

200÷3 = 66.66

Round that of to the nearest whole number = 67

67 x 2 = 134

Answer:

75

Step-by-step explanation:

i took the semester exam

Answer:

15

Step-by-step explanation:

Try 1, 2, 3, or 4 blue pencils. Then green is 6 times as many. Red must be the rest to make up 20 total.

No. of blue        No. of green      No. of red

1                          6                           13

2                        12                           6

3                        18                           -1

You can't have 3 blue pencils because 3 blue + 18 green = 21 pencils, and there are only 20.

If you have 1 blue and 6 green, then there must be 13 red, but red must be less than green, and 13 is not less than 6.

The only possibility is

2 blue, 12 green, 6 red

If you start taking out pencils, when you take out the first 14 they may be all blues or green, so only when you take out the 15th pencil do you know for sure there must be 1 green pencil.

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Quadrilaterals.

Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.

so applying this law here, we get as,

2X + (3X-10) = 180°

=> 5X - 10° = 180°

=> 5X = 190°

=> X = 190°/5

=> X = 38°

thus the angle X= 38°.

Answer.

Step-by-step explanation:

Answer:

a) 8

b) 2 1/4 hours

c) 4 7/8 hours

d) 4 1/8 hours

Step-by-step explanation:

a) LCD to be used to solve this problem is calculated as the Lowest common denominator of the above mixed fractions.

We have 1 1/2 hours and 1 1/8 hours

The lowest common denominator is the denominator calculated by

Multiplying the two denominators together and dividing by the common factor of the two denominators

Hence , we have

2 × 8 = 16

The common factor of 2 and 8 = 2

LCD = 16/2 = 8

b) How long did Matt drive?

We are told that Matt drove twice as long as John

John drove for 1 1/8 hours

Hence, the number of hours that Matt drove for =2 × 1 1/8

= 2 × 9/8 = 9/4 hours = 2 1/4 hours

c) How long the Sam, John and Matt drive ?

We are told in the question that

Sam drove for 1 1/2 hours

John drove for 1 1/8 hours

Matt drove for 2 1/4 hours

We would sum up the number of hours that each of them drove.

1 1/2 + 1 1/8 + 2 1/4

The Lowest common multiple of denominators is 8

= (1 + 1 + 2)( 4 + 1 +2/8)

= 4(7/8)

= 4 7/8 hours

d) How many hours is left for Bob to drive

We are told that the entire journey = 9 hours

The number of hours Sam, John and Matt drove for has been calculated in question c as 4 7/8 hours

The number of hours Bob will drive for is calculated as

9 hours - 4 7/8 hours

= 4 1/8 hours

Answer: draw a straight line trough point B, same thing with the second one,for the third you must draw a straight line from the angle across to the segment. (make sure all of the intersections are 90 degrees

Answer:

The length of the missing segment is 36

Step-by-step explanation:

Given

The figure above

Required

Determine the missing segment

Let the missing segment be represented with x

Given that, there exist parallel lines between the two triangles;

The relationship between the sides of the triangles is as follows;

[tex]\frac{20}{24} = \frac{30+20}{24+x}[/tex]

[tex]\frac{20}{24} = \frac{50}{24+x}[/tex]

Cross Multiply

[tex]20 * (24 + x) = 24 * 50[/tex]

[tex]20 * (24 + x) = 1200[/tex]

Divide both sides by 20

[tex]\frac{20 * (24 + x)}{20} = \frac{1200}{20}[/tex]

[tex](24 + x)= \frac{1200}{20}[/tex]

[tex]24 + x= 60[/tex]

Subtract 24 from both sides

[tex]24 - 24 + x = 60 - 24[/tex]

[tex]x = 60 - 24[/tex]

[tex]x = 36[/tex]

Hence, the length of the missing segment is 36

Answer:

1st blank: substitution property of equality

2nd blank: linear pair theorem

3rd blank: substitution property of equality

Step-by-step explanation:

1st blank

∠EIJ ≅ ∠GJI (eq. 1)

∠EIJ ≅ ∠IKL (eq. 2)

∠GJI ≅ ∠JLK (eq. 3)

Substituting eq. 3 into eq. 1:

∠EIJ ≅ ∠JLK

and then, substituting eq. 2:

∠IKL ≅ ∠JLK

which means that m∠IKL = m∠JLK

2nd blank

The Linear Pair Theorem states that two angles that form a linear pair are supplementary

3rd blank

m∠JLK + m∠JLD = 180°

Substituting with the previous result:

m∠IKL + m∠JLD = 180°

Answer:

1st blank: substitution property of equality

2nd blank: linear pair theorem

3rd blank: substitution property of equality

Step-by-step explanation:

there u go

Answer:

[tex]m = 5 \sqrt{3}[/tex]

[tex]n = 5[/tex]

Step-by-step explanation:

Given

The triangle above

Required

Find the missing lengths

The missing lengths can be calculated by applying trigonometry ratios

From the triangle above,

the Hypotenuse is 10

Angle = 60

Calculating m

The relationship between m, the Hypotenuse and angle 60 is defined as follows;

[tex]sin \theta = \frac{Opp}{Hyp}[/tex]

Where [tex]\theta = 60[/tex]

[tex]Opp = m[/tex]

[tex]Hyp = 10[/tex]

The above formula becomes

[tex]sin60= \frac{m}{10}[/tex]

Multiply both sides by 10

[tex]10 * sin60= \frac{m}{10} * 10[/tex]

[tex]10 * sin60= m[/tex]

In radical from, [tex]sin60 = \frac{\sqrt{3}}{2}[/tex]

[tex]10 * sin60= m[/tex] becomes

[tex]10 * \frac{\sqrt{3}}{2}= m[/tex]

[tex]\frac{10* \sqrt{3}}{2}= m[/tex]

[tex]5 \sqrt{3}= m[/tex]

[tex]m = 5 \sqrt{3}[/tex]

Calculating n

The relationship between n, the Hypotenuse and angle 60 is defined as follows;

[tex]cos\theta = \frac{Adj}{Hyp}[/tex]

Where [tex]\theta = 60[/tex]

[tex]Adj = n[/tex]

[tex]Hyp = 10[/tex]

The above formula becomes

[tex]cos60= \frac{n}{10}[/tex]

Multiply both sides by 10

[tex]10 * cos60= \frac{n}{10} * 10[/tex]

[tex]10 * cos60= n[/tex]

In radical from, [tex]cos60= \frac{1}{2}[/tex]

[tex]10 * cos60= n[/tex] becomes

[tex]10 * \frac{1}{2}= n[/tex]

[tex]\frac{10*1}{2}= n[/tex]

[tex]5 = n[/tex]

[tex]n = 5[/tex]