Answers
Related Questions
na 5-day
a) in 1 hour
7. If you run a half marathon (21 km) in 2 hours 6 minutes, how
a) t
b) t
c)
does it take you to run one kilometre?
Answers
reason beacuse it just makes sense and i did this question before
B:
The usual monthly expenses of midas family is 3500.00 for their electric and and with bill, 10,
000 for house and 5,000.00 for their food. The rest of their income will be their savings How much
will be their savings if the couple both earn 10,000.00each
Answers
Answer:
$1,500
Step-by-step explanation:
Income - Expenses = Savings
Income = 2 × 10,000 = $20,000
Expenses = 3,500 + 10,000 + 5,000 = $18,500
$20,000 - $18,500 = $1,500 left for Savings
Three of the sides will require fencing and the fourth wall already exists. If the farmer has 144 feet of fencing what is the largest area the farmer can enclose ?
Answers
Complete question is;
A farmer is building a fence to enclose a rectangular area against an existing wall. Three of the sides will require fencing and the fourth wall already exists. If the farmer has 144 feet of fencing, what is the largest area the farmer can enclose?
Answer:
A_largest = 2592 ft²
Step-by-step explanation:
Let the width which is going to be perpendicular to the already existing fourth wall be denoted by y. Since there will be 2, it means total width = 2y.
Since the farmer has 144 ft of fencing and the total width is 2y,it means that the length of the fence will be expressed as;
Length = 144 - 2y
Area of rectangular fencing is;
A = y(144 - 2y)
A = 144y - 2y²
To find the largest area, we will find the first derivative and the equate to 0 after which we plug the value of y back into the area equation to get it.
dA/dy = 144 - 4y
At dA/dy = 0;
144 - 4y = 0
y = 144/4
y = 36 ft
Thus, largest area is;
A_largest = 144(36) - 2(36)²
A_largest = 2592 ft²
The largest area the farmer can enclose with the fence with him will be 2592 square feet.
Let the length of the field = [tex]x[/tex] feet
And the width of the field = [tex]y[/tex] feet
Therefore, area of the rectangular field = Length × Width
A = [tex]x\times y[/tex] square feet
Since, length of the fence = 144 feet
And the farmer has to enclose three sides of the rectangle as shown in the figure attached.
Therefore, length of the fence = length + 2(width)
= [tex](x+2y)[/tex] feet
Hence, [tex](x+2y)=144[/tex]
[tex]x=144-2y[/tex]
By substituting the value of 'x' in the expression for the area of the rectangular field.
[tex]A=(144-2y)y[/tex]
[tex]A=-2y^2+144y[/tex]
Find the derivative of the expression with respect to [tex]y[/tex],
[tex]A'=-4y+144[/tex]
Now equate it to zero to get the value of y,
[tex]A'=-4y+144=0[/tex]
[tex]y=36[/tex]
Now substitute the value of 'y' in the expression of area to get the maximum area enclosed.
[tex]A=-2(36)^2+144(36)[/tex]
[tex]=-2592+5184[/tex]
[tex]=2592[/tex] square feet
Therefore, maximum area the farmer can enclose with the 144 feet of fencing will be 2592 square feet.
Learn more,
https://brainly.com/question/16880549
find the area of the figure 27 1/2 yd and 17 1/5 yd
Answers
if the figure is a rectangle the answer is 473
Answer:
473
Step-by-step explanation:
First you need to make the fractions mixed numbers
27 1/2= 55/2
17 1/5= 86/5
Then you multiply across
55/2*86/5= 4730/10
then you divide 4730 by 10 to make it an improper fraction.
(because the denominator is 10 just take the 0 out of the end of 4630, this trick only works if the last number in the numerator is 0.)
And your anwser should be 473
I hope this helps!!!!!
List the PROs and CONs of using coal as a power source.
Answers
Answer:
pros:Affordability,Known technologies,Safety.
cons:Greenhouse gas emissions,Mining destruction,Emission of harmful substances.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The pros of using coal as an energy souse is have alot of electicity and the con s of using coal as an energy souse is globlal warming, pollued air limited supply of coal in Earth
Pls Comment
Read each of the statements that describe possible decompositions of the polygon in the image into two triangles that can represent the area of the polygon For each statement, determine if "Yes, it is a possible decomposition" or "No, Is it not a possible decomposition and explain your reasoning.
Statement A: the area of triangle GHL plus of triangle HIJ
Statement B: the area of triangle GHK plus the area triangle HIK
Statement C: the area of triangle GHK plus the area of triangle ILK
Statement D: the area of triangle GHK plus the area of triangle ILK
Answers
The statements to determine the area of the polygon by division into triangles are evaluated as follows;
Statement A: the area of triangle GHL plus of triangle HIJ --NoStatement B: the area of triangle GHK plus the area triangle HIK --YesStatement C: the area of triangle GHK plus the area of triangle ILK. --NoStatement D: the area of triangle GHK plus the area of triangle ILK. --NoPolygons and TrianglesFrom the given description;
The polygon given can only be divided into two triangles if divided into triangles; GHK and HIK.
Hence, it follows that the area of triangle GHK plus the area triangle HIK is equivalent to the area of the given polygon.
Read more on Area of polygons;
https://brainly.com/question/17589084
corresponding sides of similar triangles are 4cm and 3metres .What is the enlargement factor 'k'?
Answers
Answer:
[tex]k = 75[/tex]
Step-by-step explanation:
Given
Corresponding sides: 4cm and 3m
Required
Determine the enlargement factor
This is calculated as:
[tex]k = \frac{New}{Old}[/tex]
So:
[tex]k = \frac{3m}{4cm}[/tex]
Convert to cm
[tex]k = \frac{3*100cm}{4cm}[/tex]
[tex]k = \frac{300cm}{4cm}[/tex]
[tex]k = \frac{300}{4}[/tex]
[tex]k = 75[/tex]
what is the quotient of the polynomials shown below? (10x^3+16x^2+16)÷(2x+4)
Answers
Answer:
5x^2 - 2x + 4
Step-by-step explanation:
Find such a coefficient a for the linear equation ax –y=4, so that the graph of the equation would pass through the point M (3, 5).
GRAPH AFTERWARDS/TELL ME POINTS TO PUT ON GRAPH I BEG YOU
Answers
Answer:
a=3; (3,5) and (4,0) for the graph
Step-by-step explanation:
ax-y=4
x=3, y=5 so...
a(3)-5=4
3a-5=4
+5 +5
3a=9
/3 . /3
a=3
For the graph, use (3,5) and substitute x and y for anything:
ax-y=4
if x=0...
a(0)-y=4
-y=4
y=4
a=3; (3,5) and (4,0) for the graph!
3 units
8 units
9 units
13 units
21 units
What is the area of the figure in
square units.
Answers
Answer:
Area = 132 Square units
Step-by-step explanation:
Looking at the diagram, the top horizontal chord distance that's missing is calculated as;
21 - (9 + 3) = 9 units
Total distance of top horizontal chord = 9 + 3 = 12 units
Now, formula for area of trapezium is;
Area = ½(a + b)h
Where h is height = 8 units
The parallel sides are a & B.
In this case; a = 12 units
b = 21 units
Thus;
Area = ½(12 + 21)8
Area = 4 × 33
Area = 132 Square units
5x-2y=-20 and 5x-8y=-50 what is the ordered pair
Answers
Answer:
Solution Set: (-2,5)
Step-by-step explanation:
Enter your answers in the boxes to correctly complete this statement. 6.184×105= because the number 105 has zeros when it is written without an exponent.+
Answers
Answer:
74.94×103= 3
because the number 10³ has
zeros when it is written without an exponent.
Step-by-step explanation:
74.94×103=
because the number 10³ has
zeros when it is written without an exponent.
3 zeros
liana cubed the number of flowering plants in her garden, then added 2 vegetable plants. Let p represent the original number of plants in her garden. Which shows an expression to represent the total number of plants in her garden and the total number of plants if p = 3? 3 p minus 2; when p = 3 the number of plants is 7 3 p + 2; when p = 3 the number of plants is 11 p cubed minus 2; when p = 3 the number of plants is 25 p cubed + 2; when p = 3 the number of plants is 29
Answers
Answer:
11 maybe
Step-by-step explanation:
cant recheck the test
Helppppp meeeee!!!!!!!!!!!
Answers
Answer and Step-by-step explanation:
When it says (f + g)(x), it means that it wants you to add the functions together.
So, let's add them.
[tex](2x^2 + 6x - 4) + (5x^3 -6x^2-3)\\\\\\5x^3 - 4x^2 + 6x - 7\\\\\\\\\\\\\\5x^3 - 4x^2 + 6x - 7[/tex]is the answer. (Answer choice B.)
#teamtrees #PAW (Plant And Water)
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.78.
(a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85. (Round your answers to two decimal places.)
(b) Compute a 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.)
(c) How large a sample size is necessary if the width of the 95% interval is to be 0.46? (Round your answer up to the nearest whole number.)
(d) What sample size is necessary to estimate true average porosity to within 0.18 with 99% confidence? (Round your answer up to the nearest whole number.)
Answers
Answer:
a) The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).
b) The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).
c) A sample size of 12 is needed.
d) A sample size of 125 is needed.
Step-by-step explanation:
(a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85.
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 1.96\frac{0.78}{\sqrt{15}} = 0.39[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.39 = 4.46
The upper end of the interval is the sample mean added to M. So it is 4.85 + 0.39 = 5.24
The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).
(b) Compute a 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.)
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 2.327\frac{0.78}{\sqrt{11}} = 0.55[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.56 - 0.55 = 4.01
The upper end of the interval is the sample mean added to M. So it is 4.56 + 0.55 = 5.11
The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).
(c) How large a sample size is necessary if the width of the 95% interval is to be 0.46?
95% CI means that [tex]z = 1.96[/tex]
A sample of n is needed, and n is found when M = 0.46. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.46 = 1.96\frac{0.78}{\sqrt{n}}[/tex]
[tex]0.46\sqrt{n} = 1.96*0.78[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*0.78}{0.46})^2[/tex]
[tex]n = 11.05[/tex]
Rounding up
A sample size of 12 is needed.
(d) What sample size is necessary to estimate true average porosity to within 0.18 with 99% confidence?
99% CI means that [tex]z = 2.575[/tex]
A sample of n is needed, and n is found when M = 0.18. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.18 = 2.575\frac{0.78}{\sqrt{n}}[/tex]
[tex]0.18\sqrt{n} = 2.575*0.78[/tex]
[tex](\sqrt{n})^2 = (\frac{2.575*0.78}{0.18})^2[/tex]
[tex]n = 124.5[/tex]
Rounding up
A sample size of 125 is needed.
Can you plz help me with number one
Answers
Answer: C. 2
Step-by-step explanation:
Use the following number line to determine if the expressions are true or false.
0
True False
akb
Valo O
(al <10 D
Answers
Answer:
true
Step-by-step explanation:
1 point
At a cost of $200, your club bought 175 frisbees to sell at the pep rally. You plan on selling them for $5 each. Which of the following represents the profit function, P.
after selling a certain number of frisbees, f.
Answers
Answer:
p(f)=5f-200
Step-by-step explanation:
----------------
Megan bought two baseball gloves
and one baseball bat. She paid for 40%
with her birthday money and her uncle
paid the remaining amount. How much
did Megan pay and how much did her
uncle pay?
Answers
well if she payed 40% and an average baseball glove costs $120 – $300
and a bat costs $75-$185. that would mean she spent around $197 or $485
which would mean
40% out of 197 is 78.8
and 291
i believe is the correct answer
Two numbers have prime factors of 2, 3, 5, and 11 that they share. What is the greatest common factor of the two numbers?
Answers
Answer:
5
Step-by-step explanation:
Brainliest will be given ASAP question below!
Answers
Answer:
3/32
Step-by-step explanation:
9/16 × 3/4=27/144=3/16×1/2=3/32
si f(X)=1/X2, determina el conjunto finito de pares ordenados para X={1,3,7,11,13}
Answers
Answer:
El conjunto finito de pares ordenados son;
(1, 1), (1, 1/9), (1, 1/49), (1, 1/121), (1, 1/169)
Step-by-step explanation:
si f (X) = 1 / X2, determine el conjunto finito de pares ordenados para X = {1,3,7,11,13}
Dado que f (X) = 1 / X²
Para X = {1, 3, 7, 11, 13}
Tenemos;
f (X) = 1 / X²
f (1) = 1 / 1² = 1, Por lo tanto, tenemos el primer par ordenado, (1, 1)
f (3) = 1 / 3² = 1/9, por lo tanto, tenemos el segundo par ordenado (1, 1/9) ≈ (1. 0.11)
f (7) = 1 / 7² = 1/49, por lo tanto, tenemos el tercer par ordenado (1, 1/49) ≈ (1. 0.02)
f (11) = 1 / 11² = 1/121, por lo tanto, tenemos el cuarto par ordenado (1, 1/121) ≈ (1. 0083)
f (13) = 1 / 13² = 1/169, por lo tanto, tenemos el quinto par ordenado (1, 1/169) ≈ (1. 0.006)
What is the slope of a line that is perpendicular to the line y = 1/6+ 4
+4?
Answers
Answer:
y = 6x + 8?
Step-by-step explanation:
The starting equation was unclear but if its perpindecular, flip the given slope. For example, if the slope was 3/4, its perpindecular slope would be 4/3.
What’s 123988+81937297+81937192827-29283729?
Answers
Answer:
81989970383
Step-by-step explanation:
la probabilidad de que un caballo viva 20 años es dos tercios y la de una vaca viva 20 años es decir 3 puntos Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años
Answers
Answer:
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.
Step-by-step explanation:
Probabilidades Independientes:
Quanto las probabilidades de dos eventos son independientes, la probabilidad de los dos ocurrir simultáneamente es la multiplicacion de las dos probabilidades.
La probabilidad de que un caballo viva 20 años es dos tercios
Entonces [tex]P(C) = \frac{2}{3}[/tex]
La de una vaca viva 20 años es
Incomplete, entonces dire que es [tex]P(V) = \frac{a}{b}[/tex]
Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años
[tex]P(C \cap V) = P(C) \times P(V) = \frac{2}{3}*\frac{a}{b} = \frac{2a}{3b}[/tex]
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].
Sean [tex]A[/tex] y [tex]B[/tex] dos eventos independientes aunque no mutuamente excluyentes, es decir, que la esperanza de vida del caballo ([tex]A[/tex]) no dependa de la esperanza de vida de la vaca ([tex]B[/tex]) y viceversa y que pueden ocurrir al mismo tiempo.
En este caso, la probabilidad de que tanto el caballo como la vaca vivan 20 años equivale a una operación de intersección que se manifiesta en la siguiente ecuación:
[tex]P(A \cap B) = P(A)\cdot P(B)[/tex] (1)
Si sabemos que [tex]P(A) = \frac{2}{3}[/tex] y [tex]P(B) = \frac{3}{5}[/tex], entonces la probabilidad de que tanto caballo como la vaca vivan 20 años es:
[tex]P(A\cap B) = \frac{2}{3}\times \frac{3}{5}[/tex]
[tex]P(A\cap B) = \frac{2}{5}[/tex]
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].
Invitamos cordialmente a ver esta pregunta sobre probablidades: https://brainly.com/question/24290732
Nota - El enunciado original presenta omisiones y errores tipográficos, la forma completa se presenta a continuación:
La probabilidad de que un caballo viva 20 años es de dos tercios y la de que una vaca viva 20 años es de tres quintos. ¿Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años?
An airplane’s altitude changes −378 feet over 7 minutes. The airplane's current altitude is 2,700 feet.
Determine the number of minutes required for the plane to reach the ground.
Enter your answer in the box _______.
Answers
It will take 50 minutes!
-378/7=-54
2700/-54=-50
Are the sets equivalent?
2) A = {17, 19, 21, 23, 25)
16.
B = {18, 20, 22, 24, 26}
Answers
Answer:
Step-by-step explanation:
number of elements in set A=5
number of elements in set B=5
so they are equivalent.
10in 8 in 8 in What is the surface area of the solid? A. 384 square inches B. 184 square inches C. 192 square inches D. 224 square inches
Answers
Answer:
Step-by-step explanation:
224 sq in.
A probability experiment is conducted in which the sample space of the experiment is S={7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18}. Let event E={9, 10, 11, 12, 13, 14, 15, 16}, event F={5, 6, 7, 8, 9}, event G={9, 10, 11, 12}, and event H={2, 3, 4}. Assume that each outcome is equally likely. List the outcome s in For G. Now find P( For G) by counting the numb er of outcomes in For G. Determine P (For G ) using the General Addition Rule.
Answers
Answer:
[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]
[tex]P(F\ or\ G) = \frac{2}{3}[/tex]
Step-by-step explanation:
Given
[tex]S= \{7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18\}[/tex]
[tex]E=\{9, 10, 11, 12, 13, 14, 15, 16\}[/tex]
[tex]F=\{5, 6, 7, 8, 9\}[/tex]
[tex]G=\{9, 10, 11, 12\}[/tex]
[tex]H=\{2, 3, 4\}.[/tex]
Solving (a): Outcomes of F or G
F or G is the list of items in F, G or F and G.
So:
[tex]F=\{5, 6, 7, 8, 9\}[/tex]
[tex]G=\{9, 10, 11, 12\}[/tex]
[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]
Solving (b): P(F or G)
The general addition rule is:
[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]
Where:
[tex]P(F) = \frac{n(F)}{n(S)} = \frac{5}{12}[/tex]
[tex]P(G) = \frac{n(G)}{n(S)} = \frac{4}{12}[/tex]
[tex]P(F\ and\ G) = \frac{n(F\ and\ G)}{n(S)}[/tex]
[tex]F\ and\ G = \{9\}[/tex]
So:
[tex]P(F\ and\ G) = \frac{1}{12}[/tex]
[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]
[tex]P(F\ or\ G) = \frac{5}{12} + \frac{4}{12} - \frac{1}{12}[/tex]
[tex]P(F\ or\ G) = \frac{5+4-1}{12}[/tex]
[tex]P(F\ or\ G) = \frac{8}{12}[/tex]
[tex]P(F\ or\ G) = \frac{2}{3}[/tex]
Cellulon, a manufacturer of home insulation, wants to develop guidelines for builders and consumers on how the thickness of the insulation in the attic of a home and the outdoor temperature affect natural gas consumption. In the laboratory, it varied the insulation thickness and temperature. A few of the findings are:
Monthly Natural Gas Consumption (cubic feet), Thickness of Insulation (inches), Outdoor Temperature (ºF),
y x1 x2
30.3 6.0 32.0
25.2 12 40
30.5 8 49
On the basis of the sample results, the regression equation is:
yˆ y^ = 57.25 − 1.07x1 − 0.64x2
Answers
According to the regression equation, the predicted Monthly Natural Gas Consumption (ŷ) can be estimated by subtracting 1.07 times the Thickness of Insulation (x1) and 0.64 times the Outdoor Temperature (x2) from 57.25.
The regression equation provided is:
ŷ = 57.25 - 1.07x1 - 0.64x2
Where:
ŷ represents the predicted value of Monthly Natural Gas Consumption (cubic feet)
x1 represents the Thickness of Insulation (inches)
x2 represents the Outdoor Temperature (ºF)
Based on the regression equation, the coefficients indicate the relationship between the independent variables (Thickness of Insulation and Outdoor Temperature) and the dependent variable (Monthly Natural Gas Consumption).
The coefficient for x1 (Thickness of Insulation) is -1.07. This means that, holding the Outdoor Temperature constant, for every 1-inch increase in the Thickness of Insulation, the predicted Monthly Natural Gas Consumption is expected to decrease by 1.07 cubic feet.
The coefficient for x2 (Outdoor Temperature) is -0.64. This means that, holding the Thickness of Insulation constant, for every 1-degree Fahrenheit increase in the Outdoor Temperature, the predicted Monthly Natural Gas Consumption is expected to decrease by 0.64 cubic feet.
The constant term in the equation is 57.25. This represents the predicted Monthly Natural Gas Consumption when both the Thickness of Insulation and Outdoor Temperature are zero.
for such more question on regression equation
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