Answer:
a) P(Y=10)=0.0013
b) P(Y≤5)=0.00000035
c) Mean = 17.5
S.D. = 2.29
Step-by-step explanation:
We can model this as a binomial random variable with n=25 and p=0.7.
The probability that k students from the sample are foreign students can be calculated as:
[tex]P(y=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(y=k) = \dbinom{25}{k} 0.7^{k} 0.3^{25-k}\\\\\\[/tex]
a) Then, for Y=10, the probability is:
[tex]P(y=10) = \dbinom{25}{10} p^{10}(1-p)^{15}=3268760*0.0282475249*0.0000000143\\\\\\P(y=10)=0.0013\\\\\\[/tex]
b) We have to calculate the probability P(Y≤5)
[tex]P(y\leq5)=P(Y=0)+P(Y=1)+...+P(Y=5)\\\\\\P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0=0\\\\\\P(y=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.7*0=0\\\\\\P(y=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.49*0=0.0000000001\\\\\\P(y=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.343*0=0.0000000025\\\\\\P(y=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.2401*0=0.0000000318\\\\\\P(y=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.16807*0=0.0000003114\\\\\\\\[/tex]
[tex]P(y\leq5)=0+0+0.0000000001+0.0000000025+0.0000000318+0.00000031\\\\P(y\leq5)= 0.00000035[/tex]
c) The mean and standard deviation for this binomial distribution can be calculated as:
[tex]\mu=np=25\cdot 0.7=17.5\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot0.7\cdot0.3}=\sqrt{5.25}=2.29[/tex]
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
[tex]g(2) = 4(2) + 6 = 14[/tex]
[tex]f(2) = 2(2) + 3 = 7[/tex]
[tex](g - f)(2) = 14 - 7 = 7[/tex]
problem decoded dude
thank and follow meh
The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the feasibility of providing a dental insurance plan. A random sample of 12 employees reveals the following family dental expenses (in dollars). See Attached Excel for Data. Construct a 97% confidence interval estimate for the average family dental expenses for all employees of this corporation.
The data cited is in the attachment.
Answer: 308.2±106.4
Step-by-step explanation: To construct a confidence interval, first calculate mean (μ) and standard deviation (s) for the sample:
μ = Σvalue/n
μ = 308.2
s = √∑(x - μ)²/n-1
s = 147.9
Calculate standard error of the mean:
[tex]s_{x} = \frac{s}{\sqrt{n} }[/tex]
[tex]s_{x}[/tex] = [tex]\frac{147.9}{\sqrt{12} }[/tex]
[tex]s_{x}[/tex] = 42.72
Find the degrees of freedom:
d.f. = n - 1
d.f. = 12 - 1
d.f. = 11
Find the significance level:
[tex]\frac{1-0.97}{2}[/tex] = 0.015
Since sample is smaller than 30, use t-test table and find t-score:
[tex]t_{11,0.015}[/tex] = 2.4907
E = t-score.[tex]s_{x}[/tex]
E = 2.4907.42.72
E = 106.4
The interval of confidence is: 308.2±106.4, which means that dental insurance plan varies from $201.8 to $414.6.
The Toyota Camry is one of the best-selling cars in North America. The cost of a previously owned Camry depends on many factors, including the model year, mileage, and condition. To investigate the relationship between the car’s mileage and the sales price for Camrys, the following data show the mileage and sale price for 19 sales (PriceHub web site, February 24, 2012).Miles(1000s) Price($1,000s) 22 16.2 29 16.0 36 13.8 47 11.5 63 12.5 77 12.9 73 11.2 87 13.0 92 11.8 101 10.8 110 8.3 28 12.5 59 11.1 68 15.0 68 12.2 91 13.0 42 15.6 65 12.7 110 8.3A. Test whether each of the regression parameters b0 and b1 are equal to zero at 0.01 level of significance.B. What are the correct interpretations of the estimated regression parameters?C. Are these interpretations reasonable?
Answer:
Step-by-step explanation:
Hello!
Given the variables
Y: Cost of a previously owned Camry.
X: Mileage of a previously owned Camry.
Scatter plot in attachment.
As you can see in the scatter plot, the price of the previously owned Camry decreases as their mileage increases this suggest that there is a negative linear regression between these two variables.
Hypothesis test for the y-intercept
H₀: β₀ = 0
H₁: β₀ ≠ 0
Level of significance α: 0.01
p-value < 0.0001
The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry, when the mileage is zero, is different from zero.
H₀: β = 0
H₁: β ≠ 0
Level of significance α: 0.01
p-value: 0.0003
The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry is modified when the mileage increases in one unit.
(X+3)(x+5)
Expand and simplify?
[tex](x+3)(x+5)[/tex]
[tex]x(x+5)+3(x+5)[/tex]
[tex]x^2+5x+3x+15[/tex]
[tex]\displaystyle x^2+8x+15[/tex]
2 = x-3, then x equals
Answer:
x = 5
Step-by-step explanation:
2 = x-3
Adding 3 to both sides
2+3 = x
5 = x
OR
x = 5
Answer:
[tex] \times = 2 + 3 \\ \\ x = 5[/tex]
When a ladder of length 2.5 m leans against the
of 55° with the ground. When the ladder leans
top edge of a window of a building, it forms an
angle
against the lower edge of the same window,
it forms an angle of 38° with the ground. Find the
height of the window, giving your answer in
centimetres.
Answer: window = 0.50 m
Step-by-step explanation:
First, draw a picture (see image below).
Then set up two equations that eventually you can set equal to each other.
Given: Ladder (hypotenuse) = 2.5
Angle to Top edge of window = 55°
Angle to Lower edge of window = 38°
[tex]\sin \text{Top}=\dfrac{opposite}{hypotenuse}\qquad \qquad \sin \text{Lower}=\dfrac{opposite}{hypotenuse}\\\\\\\sin 55^o=\dfrac{h+y}{2.5}\qquad \qquad \qquad \sin 38^o=\dfrac{y}{2.5}\\\\\\\underline{\text{Solve both equations for y:}}\\2.5\sin 55^o-h=y\qquad \qquad 2.5\sin 38^o=y\\\\\\\underline{\text{Set the equations equal to each other and solve for h:}}\\\\2.5\sin 55^o-h=2.5\sin 38^o\\2.5\sin 55^0-2.5\sin 38^o=h\\\large\boxed{0.50=h}[/tex]
standard form of line that passes thru (-3,5) and (-2,-6)
Answer:
11x + y = -28
Step-by-step explanation:
Step 1: Find slope
(6-5)/(-2--3) = -11
Step 2: Find y-intercept
y = -11x + b
5 = -11(-3) + b
5 = 33 + b
b = -28
Step 3: Write in slope-intercept form
y = -11x - 28
Step 4: Convert to standard form
11x + y = 28
And we have our final answer!
Suppose you have a set of requests {1,2,...,n} where the ith request corresponds to an interval of time starting at s(i) and finishing at f(i). How can you choose the largest subset of these requests such that none overlap?
Answer:
You can choose the largest subset by using ; Earliest finish time first
Step-by-step explanation:
In the set of requests { 1,2,....n} where the ith request corresponds to an interval of time for you to choose the largest subset such that none will overlap is by employing/using EARLIEST FINISH TIME FIRST method.
This is because we will have to sort out the finish times of the set of requests before we can proceed to choosing the largest subset contained in the set of requests.
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation to (4|3)? A. (4|-3)
B.(-3|4)
C.(3|-4)
D.(-4|3)
Answer:
C.(3|-4)
Step-by-step explanation:
Given the vector:
[tex]\left[\begin{array}{ccc}4\\3\end{array}\right][/tex]
The transformation Matrix is:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right][/tex]
The image of the vector after applying the transformation will be:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right][/tex]
The correct option is C
The image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
What is a matrix ?Matrix, a set of numbers arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.
It is given that the vector is
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}[/tex]
and the transformation matrix is
[tex]\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
The image after applying the transformation
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}0*4+0*3 \\-1*4+0*3 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex]
Therefore the image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
To know more about Matrix
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Please answer this correctly
Answer:
9 bags
Step-by-step explanation:
130, 134, 136, 145, 145, 147, 147, 151, 154
9 bags had at least 130 peanuts.
Use the diagram to find the angle measures that satisfy each case. Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
Answer:
m∠1=45 degreesm∠2=135 degreesm∠3=45 degreesm∠4=135 degreesStep-by-step explanation:
Given that: 3(m∠1+m∠3) = m∠2+m∠4.
From the diagram:
m∠1=m∠3 (Vertical Angles)m∠2=m∠4 (Vertical Angles)Therefore:
3(m∠1+m∠1) = m∠2+m∠2
3(2m∠1)=2m∠2
Divide both sides by 2
3m∠1=m∠2
m∠1+m∠2=180 (Linear Postulate)
Therefore:
m∠1+3m∠1=180
4m∠1=180
Divide both sides by 4
m∠1=45 degrees
Since m∠1=m∠3
m∠3=45 degrees
Recall: m∠1+m∠2=180 (Linear Postulate)
45+m∠2=180
m∠2=180-45
m∠2=135 degrees
Since m∠2=m∠4
m∠4=135 degrees
A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sales call and that the probability of a sale of a particular piece of equipment is 0.15. If the supplier has four pieces of the equipment available for sale, what is the probability that it will take fewer than six customer contacts to clear the inventory?
Answer:
The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.
Step-by-step explanation:
We have a probability of making an individual sale of p=0.15.
We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:
[tex]P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}[/tex]
As we see in the equation, n has to be equal or big than 4.
In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.
This probability can be calculated adding the probability from n=4 to n=6:
[tex]P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008[/tex]
Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given the number of pairs of data n and the significance level α. n = 12, α = 0.01
Answer:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
Step-by-step explanation:
In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:
Null hypothesis: [tex]\rho =0[/tex]
Alternative hypothesis: [tex]\rho \neq 0[/tex]
The statistic to check the hypothesis is given by:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking samples of sizes n = 160 units. Suppose that today’s sample contains 14 defectives. How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today’s sample--that is using the result that f$hat {767} =0.0875f$
Answer:
[tex]n=\frac{0.0875(1-0.0875)}{(\frac{0.02}{1.96})^2}=766.82[/tex]
And rounded up we have that n=767
Step-by-step explanation:
We know the following info:
[tex] n=160[/tex] represent the sample size selected
[tex] x= 14[/tex] represent the number of defectives in the sample
[tex]\hat p= \frac{14}{160}= 0.0875[/tex] represent the estimated proportion of defectives
[tex] ME = 0.02[/tex] represent the margin of error desired
The margin of error for the proportion interval is given by this formula:
[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex] (a)
And on this case we have that [tex]ME =\pm 0.02[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex] (b)
The crtical value for a confidence level of 95% is [tex] z_{\alpha/2}=1.96[/tex]
And replacing into equation (b) the values from part a we got:
[tex]n=\frac{0.0875(1-0.0875)}{(\frac{0.02}{1.96})^2}=766.82[/tex]
And rounded up we have that n=767
9+9+3=21
1234+1234+1234= 30
9+1224+12=?
Answer:
9+1224+12=1245
Hope this helps
Answer:
Mathematically,
9+1224+12 = 1245
But, Logically, here:
9+1224+12 = 21
Tell whether the following set is an empty set or not? A = { A quadrilateral having 3 obtuse angles}
Answer:
No.
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.
Answer:
[tex]\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}[/tex]
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible.
A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.
Let’s say three angles are measuring 91 degrees in a quadrilateral.
91 + 91 + 91 + x = 360
x = 87
The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.
What is the slope of the line that passes through the points (9, 4) and (9,-5)?
Write your answer in simplest form.
Answer: it’s undefined or 0
Step-by-step explanation:
Answer:
Undefined
Step-by-step explanation:
Slope= (y^2-y^1)/(x^2-x^1)
(x^1,y^1) and (x^2,y^2)
(9,4) and (9,-5)
SLOPE:
(-5-4)/(9-9)
-9/0
Undefined
kinda hard to show on brainy but there you go hope this helps
Evaluate (x + y)0 for x = -3 and y = 5
Answer:
0Step-by-step explanation:
[tex](x + y)0 \\ x = -3 \\y = 5\\(-3+5)0\\(2)0\\= 0[/tex]
Mighty Casey hits two baseballs out of the park. The path of the first baseball can be described by the displacement (distance and direction) vector,
b1 = 100 i ^ + 10 j ^. The path of the second baseball can be described by the displacement vector b2 = 90 i ^ + (−20) j ^.
(a) How much farther did the first ball travel than the second? (Round your final answer to the nearest tenth.)
(b) How far are the baseballs apart? (Round your final answer to the nearest tenth.)
Answer:
a) 8.3 units of length
b) 31.6 units of length
Step-by-step explanation:
a) The distances traveled by each ball are given by:
[tex]d_1^2=100^2+10^2=10,100\\d_1=100.5\\\\d_2^2=90^2+(-20^2)=8,500\\d_2=92.2[/tex]
The diference between the distance traveled by both balls is:
[tex]d_1-d-2=100.5-92.2\\d_1-d_2=8.3[/tex]
The first ball traveled 8.3 units of length farther than the second ball.
b) The distance between both balls is:
[tex]d^2=(i_1-i_2)^2+(j_1-j_2)^2\\d^2=(100-90)^2+(10-(-20))^2\\d^2=1,000\\d=31.6[/tex]
The balls are 31.6 units of length apart.
Find the value of m that makes ABC~DEF when AB= 3, BC= 4, DE= 2m, EF= m+5, and ∠B≅∠E.
Answer:
m = 3
Step-by-step explanation:
It is given that there are two triangles [tex]\triangle[/tex]ABC and
[tex]\triangle[/tex]ABC ~
Also, the sides are:
AB= 3
BC= 4
DE= 2m
EF= m+5 and
∠B≅∠E
Please have a look at the attached figure for [tex]\triangle[/tex]ABC and
The triangles are similar so as per the property of similar triangles, the ratio of corresponding sides will be same.
i.e.
[tex]\dfrac{AB}{DE} = \dfrac{BC}{EF}\\\Rightarrow \dfrac{3}{2m} = \dfrac{4}{m+5}\\\Rightarrow 3 \times (m+5) = 4 \times 2m\\\Rightarrow 3m +15= 8m \\\Rightarrow 5m=15\\\Rightarrow m = 3[/tex]
So, value of m = 3.
Do all systems of linear inequalities have solutions? If not, write a system of inequalities that has no solution. What would the graph of a system of linear inequalities with no solution look like?
Answer: There are systems with no solutions, and the graphs may show two regions with no intersections (as you know, the solution set is in the intersection of the sets of solutions for each inequality)
Step-by-step explanation:
Ok, suppose that our system is:
y > x
and
y < x.
This system obviously does not have any solution, because y can not be larger and smaller than x at the same time.
The graph of y > x is where we shade all the region above the line y = x (the line is not included)
and the graph of y < x is where we sade all the region under the line y = x (the line is not included)
So we will look at a graph where we never have a region with the two shades overlapping (so we do not have a intersection in the sets of solutions), meaning that we have no solutions.
Determine whether the following individual event are independent or dependent. Then find the probability of the combined event.
Randomly drawing and immediately eating two red pieces of candy in a row from a bag that contains 55 red pieces of candy out of 49 pieces of candy total.
Answer:
dependent and 1.26
Step-by-step explanation:
These two individual events are dependent on each other as first they draw it and then instant they eat two red candy pieces
Now the probability of the combined event is as follows
P(Probability of combined event) is
[tex]= P(Event 1) \times P \frac{Event 2}{Event 1}[/tex]
[tex]= \frac{55}{49} \times \frac{54}{48}[/tex]
[tex]= 1.122 \times 1.125[/tex]
= 1.26
We simply applied the above formula so that we can get the dependency or independency plus the probability of the combined event
Answer: independent & .057
Step-by-step explanation:
Which is the cosine ratio of
Answer:The answer is B
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Cos A = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
Where Adjacent = 28, Hypotenuse = 197
Cos A = [tex]\frac{28}{197}[/tex]
if each angle of triangle is less than the sum of of other two show that the triangle is acute angled triangle
5. A worker can do a piece of
piece of wook
in 14 days.
How much coook does he do ini day!
. How much work does he do in 7 days?
lijIt he works for 2 days and leaves,
how much work is left to finish it?
Answer:
therefore the left work of worker will be 6/7 part of work
If it takes 4 hours for 2 men to mow a sports field,how long would it take 6 men working at the same rate to do the job?solution plis
Answer:
4/3 hours
Step-by-step explanation:
[tex]\frac{4*2}{6}\\=\frac{8}{6} \\= 4/3 hours[/tex]
SOMEONE PLEASE HELP ME ASAP PLEASE!!!
Answer:
A = 45 units^2
Step-by-step explanation:
This is a trapezoid
A = 1/2 (b1+b2) h
b1 is the top = 7
b2 is the bottom = 11
h = 5
A = 1/2 ( 7+11) *5
A = 1/2 ( 18)*5
A = 45 units^2
30 students, along with some of their parents, are going to a trip to Washington DC. Some of the adults are driving cars, and each car can accommodate up to 5 people including the driver. What is the smallest number of adults that should be invited on the trip to get all 30 students to Washington?
Answer:
Minimum 08 adults / drivers
Maximum 10 adults / drivers
Step-by-step explanation:
Total students are 30
Each car can take total 5 incl. drive
There needs to be 7 cars taking the 30 students, which also means there have to be minimum 7 drivers / adults.
Min. passengers = 30 + 7
Of course, there will be space for 3 more in the 8th car since 5 x 8 = 40
In accounting, cost-volume-profit analysis is a useful tool to help managers predict how profit will be affected by changes in prices or sales volume. Net income, NININ, I, is calculated using the formula NI = (SP-VC)(V)-FCNI=(SP−VC)(V)−FCN, I, equals, left parenthesis, S, P, minus, V, C, right parenthesis, left parenthesis, V, right parenthesis, minus, F, C, where SPSPS, P is the sales price, VCVCV, C is the variable cost per unit, VVV is the sales volume, and FCFCF, C are fixed costs. Rearrange the formula to solve for sales volume (V)(V)left parenthesis, V, right parenthesis.
Answer:
(a)[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
(b)V=240 Units
Step-by-step explanation:
NI=(SP-VC)V-FC
We are required to make V the subject of the equation
Add FC to both sides
NI+FC=(SP-VC)V-FC+FC
NI+FC=(SP-VC)V
Divide both sides by SP-VC
[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
When
Net Income(NI)=$5000Sales Price(SP)=$40Variable Cost(VC)=$15Fixed Costs(FC)=$1000Volume of Sales
[tex]V=\dfrac{5000+1000}{40-15}\\=\dfrac{6000}{25}\\\\=240[/tex]
Please answer this correctly
Answer:
sorry about that that was my sister . the correct answer is yes
Step-by-step explanation:
please mark as brainliest