Answer:
0.01, 1%, or 1/100
Step-by-step explanation:
These are all the same.
At his new job, Jeremiah can choose an hourly rate of $9 plus a $50 weekly bonus for opening the store, or an hourly rate of $10 per hour with no opening bonus. The equations model his salary options.
y = 9x + 50
y = 10x
What does x represent?
the number of times he opened the store
the number of hours worked per week
the total amount he earns each week
the amount of money earned per day
Answer:
The correct option is B
Step-by-step explanation:
just did the test on Ed.
ALL MY POINTS FOR THIS QUESTION!!! SHOW WORK! SHOW WORK! SHOW WORK! EXPLAIN!!!!
Answer:
2 should be added to the data
Step-by-step explanation:
Hope this helps!
If im wrong im sorry!
Answer:
18 should be added
Step-by-step explanation:
So we have one 10 and one 11 in this data set, and we need to figure out which number we need to add to get a mean of 13
let's make this unknown number x
to find the mean, we add up all the values of the numbers on the data set, and divide it by how many numbers we have.
we have 3 numbers, and our numbers are 10, 11, and x. When we add 10, 11, and x together, and then divide by 3, the value is 13
as an equation we will have:
(10+11+x)/3=13
combining like terms in the numerator, it will be:
(21+x)/3=13
We need to solve this equation, and the denominator of 3 just makes harder to do that.
Clear the fraction by multiplying both sides by 3
21+x=39
subtract 21 from both sides
x=18
so that means that 18 should be added to the data set to get a mean of 13.
Hope this helps!
in slope intercept form slope=2/7 y-intercept=0
Answer:
y=2/7x
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept
y=2/7x+0
y=2/7x
$3000 is invested for a period of 3 years at a rate of 6% compound monthly. What will the balance in the account be at the end of 3 years?
Answer:
Hence, the total amount of money that the investor would have after 6 years will be $ 536.04 .
Step-by-step explanation
Answer:
Interest = $3573.048
Step-by-step explanation:
Given: $3000 is invested for a period of 3 years at a rate of 6% compound monthly. What will the balance in the account be at the end of 3 years?
The formula to compound interest is:
I = P(1 + R)^T
First, put in the terms:
I = $3000(1 + 6%)^3
Then calculate:
I = $3000(1 + [tex]\frac{6}{100}[/tex])^3
I = $3000(1 + 0.06)^3
I = $3000(1.06)^3, 1.06^3 = 1.191016
I = $3000 x 1.191016
I = $3573.048
PLZ PLZ HELP!! BRAINLIEST IF RIGHT!!
Which function represents uninhibited growth?
The uninhabited growth represented by the function is [tex]N(t) = N_0e^{kt}[/tex]. The correct option is A.
What is uninhabited growth?Uninhibited Growth and Decay Models: Things that expand or deteriorate in a limitless, proportional manner are said to exhibit "uninhibited" growth or decay. Examples include population increase, bacterium growth, and radioactive decay.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
The expression for the uninhabited growth is,
[tex]N(t) = N_0e^{kt}[/tex]
To know more about uninhabited growth follow
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Can someone solve only this it’s shorttt, pleaseeeee I only have 5 minutes
The first term in a sequence is 13. The term to term rule is "take away 5" write an expression in terms of n , for the nth term of the sequence
9514 1404 393
Answer:
an = 13 -5(n -1)
Step-by-step explanation:
The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...
an = a1 +d(n -1)
an = 13 -5(n -1)
Someone help me with the last question please! Free brainliest
Answer: 6
Step-by-step explanation: [tex]log_{2} 64 = 6[/tex]
1.02 sinusoidal graph
WHAT IS THE AMPLITUDE OF THE SINUSOIDAL FUNCTION?
Enter your answer in the box.
___
Answer:
[tex]\displaystyle 5[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
OR
[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
I need help!
The foot of a ladder is placed 77 meters from a wall. If the top of the ladder rests 99 meters up on the wall, how long is the ladder?
Elsa has two coupons for a jacket coupon a: 45% off a $73 jacket coupon B: $30 rebate off $73 jacket which coupon has a lower price
Answer: 45% off a $73 jacket coupon
Step-by-step explanation:If you multiply 45% by 73 (.45 x 73) you get $32.85.. which means that is how much money would be reduced from the original price. If you have have a $30 rebate off a $73 jacket, you would be paying a higher price if you used the rebate instead of the coupon
Here are two squares, A and B. A B The length of each side of square B is 4cm greater than the length of each side of square A. The area of square B is 70cm2 greater than the area of square A. Find the area of square B. Give your answer correct to 3 significant fi
Answer:
La²+8La+16 = La²+70
Step-by-step explanation:
8La+16 = 70
8La=70-16
La=54/8
La= 6.75
Area b = (6.75+4)*(6.75+4)
Area b = 10.75*10.75
Area b =115.563
The area of a square is the square of its side lengths
The area of square B is 116 centimeter square
Let the side length of square A be (a), and the side length of square B be (b)
So, we have:
[tex]\mathbf{A_a = a^2}[/tex]
[tex]\mathbf{A_b = b^2}[/tex]
From the question, we have:
[tex]\mathbf{A_b = 70 + a^2}[/tex]
[tex]\mathbf{b = 4 + a}[/tex]
Take square of both sides
[tex]\mathbf{b^2 = (4 + a)^2}[/tex]
[tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex]
Substitute [tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex] in [tex]\mathbf{A_b = b^2}[/tex]
[tex]\mathbf{A_b = 16 + 8a+ a^2}[/tex]
So, we have:
[tex]\mathbf{16 + 8a+ a^2 = 70 + a^2}[/tex]
Subtract a^2 from both sides
[tex]\mathbf{16 + 8a = 70}\\[/tex]
Subtract 16 from both sides
[tex]\mathbf{8a = 54}[/tex]
Divide both sides by 8
[tex]\mathbf{a = 6.75}[/tex]
Recall that:
[tex]\mathbf{A_b = 70 + a^2}[/tex]
So, we have:
[tex]\mathbf{A_b = 70 + 6.75^2}[/tex]
[tex]\mathbf{A_b = 115.5625}[/tex]
Approximate
[tex]\mathbf{A_b = 116}[/tex]
Hence, the area of square B is 116 centimeter square
Read more about areas at:
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Describe the error in the work below.
Poppy has one bag of beads. She is going to make three difference necklaces.
For the first necklace, she needs 3/8 of a bag of beads. For the second, she
needs 1/8 of a bag of beads. For the third, she needs 5/8 of a bag. What
fraction of a bag of beads does she need? Does she have enough? Explain.
Answer:
9/8 of a bag
she doesn't have enough beads.
Step-by-step explanation:
Bag of bead poppy has = 1
Bag of bead needed for necklace 1 = 3/8 of a bag
Bag of bead needed for necklace 2 = 1/8 of a bag
Bag of bead needed for necklace 3 = 5/8 of a bag
Total bag of beads needed = 3/8 + 1/8 + 5/8
= (3+1+5)/8
= 9/8
She needs 9/8 of a bag of bead
9/8 = 1 1/8
Therefore, she doesn't have enough beads.
The bar graph shows the recommended number of hours of sleep for each age group.
How many hours of sleep are recommended for elementary-age children?
A. exactly 9 hours
B. exactly 10 hours
C. about 10 hours
D. about 12 hours
Answer:
Step-by-step explanation:
c
Evaluate the expression 1/4y + 10 + y2
Answer:
9/4y+10
Step-by-step explanation:
1/4y+10+2y
9/4y+10
unless u meant y^2 then the answer would be
0.25(y+40+4y^2)
help!!!!? pleaseeeeee
Answer:
19.47
Step-by-step explanation:
I plugged it into a right triangle trig calculator
Answer:
HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .
See attachment below!
Step-by-step explanation:
If your in High school Geometry, I could help with that and more!
If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!! I took Geometry and have good notes!
Please contact me for any concerns or questions!can someone pls help i will mark u brainliest!? :)
Answer:
28.5
Step-by-step explanation:
Plzz mark brainlies thanks!!
Which function best models the data?
Time, t (s) 0 0.5 1.0 1.5 2.0
Height, h (m) 3.0 6.8 8.2 7.0 3.3
A. h(t) = −15.9t2 + 2.99t + 10.22
B. h(t) = −16.1t2 + 10.22t + 2.99
C. h(t) = −5.03t2 + 10.22t + 2.99
D. h(t) = −5.03t2 + 2.99t + 10.22
Answer:
Step-by-step explanation:
Option c
Imperialism can be defined as:
A. the adoption of a new government with a Prime
Minister.
B. a system of humanitarian efforts to support a country.
C. a policy of extending a country's power and influence
through diplomacy or military force.
4x2-24x+34=0 answer rounded to the nearest hundredth ASAP PLEASEEE ILL GIVE 20 POINTS AND A BRAINLIEST
Answer:
x=[tex]-3+\frac{1}{2}\sqrt{2}[/tex]
x=[tex]-3+\frac{-1}{2} \sqrt{2}[/tex]
Step-by-step explanation:
Write a polynomial with 5 terms in standard form.
Identify the leading coefficient and the degree of the polynomial and name the polynomial.?
Answer:
Step-by-step explanation:
5x⁴ - 2x³ + 12x² + 24x - 26
Degree = 4
Leading term = 5x⁴
Leading coefficient = 5
Slove the system
Linear equations
by substation
Y+11=6x
2x+3y=7
Step-by-step explanation:
y = 6x-11
substitute y into 2x+3y=7
2x+3(6x-11)=7
2x + 18x-33 = 7
20 x = 7+33
x = 2
y?
y= 6(2)-11
y = 12-11 = 1
so, x = 2 and y = 1
Express 90 as the product of its prime factors.
Write the prime factors in ascending order.
|
I
Answer:
fafafasda
Step-by-step explanation:
wdwasdsa wr 1+11123121
Pleaseeeeee helpppppp fasttttttt 11 pointssss
Answer:
x = 9
m∠1 = m∠2 = 54°
Step-by-step explanation:
Two lines r and s are the parallel lines and a transversal line is intersecting these lines at two distinct points.
a). ∠1 ≅ ∠2 [Corresponding angles]
Therefore, m∠1 = m∠2
(63 - x)° = (72 - 2x)°
2x - x = 72 - 63
x = 9
b). m∠1 = (63 - x)°
= 63 - 9
= 54°
m∠2 = (72 - 2x)°
= 72 - 18
= 54°
How does the graph of the
function g(x) = 3x + 4 differ from
the graph of f(x) = 3X?
It is moved (a). unit(s) (b)
Answer:
Math (way) is good if you wanna try that.
ee
Step-by-step explanation:
Answer:
the graph of f(x) = 7x. 3x + 4 = 7x
a. Calculate the average yearly rate of change in home runs hit from 1990
to 1992.
Answer:
Step-by-step explanation:
Use the rise over run formula
y2-y1/x2-x1
1992-1990/3317-3038
2/-279
-139.5
Pretty pretty please if ur good at geometry!! Help a girl out!!
Answer:
Yes, They are similar by SSS PMK similar to LMQ.
Step-by-step explanation:
Similar triangles corresponding side lengths are in a proportion.
KM corresponds with MQ
PM corresponds with LM.
Set up this proportion.
[tex] \frac{km}{pm} = \frac{lm}{mq} [/tex]
[tex] \frac{15}{28} = \frac{21}{39.2} [/tex]
Cross multiply
[tex]588 = 588[/tex]
So the triangles ARE Similar.
PM corresponds with LMKM corresponds with MQPK corresponds with LQSo PMK is similar to LMQFind the slope that passes. through the two points (5-8 and (4,6)
Answer:
-14
Step-by-step explanation:
Line is passing through the points (5, -8) and (4, 6).
Therefore,
[tex]slope = \frac{ - 8 - 6}{5 - 4} \\ \\ = \frac{ - 14}{1} \\ \\ = - 14[/tex]