Once the hydrogen in the core of a star runs out, then the element, Helium begins to fuse.
Helium begins to fuse, once the core of a star runs out, as helium is then, the only lightest element left in the core of the star.
The energy produced in the fusion processes decreases, as heavier and heavier element starts to fuse. Stars become the main sequence stars after they fuse hydrogen.
Once the hydrogen in the core runs out, the stars could not hold against gravity more, thereby increasing the pressure and temperature in the core of the star.
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I NEED ASAP
What part of the water cycle involves convection transporting water?
A.
rainfall being absorbed by the ground
B.
rain forming and falling from the sky
C.
water evaporating and rising into the air
D.
flow of water down a stream
A 1.0 kg block is pushed 3.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26.0 ◦ with the horizontal, as shown in the figure. The acceleration of gravity is 9.81 m/s 2 . If the coefficient of kinetic friction between the block and the wall is 0.40, find a) the work done by the force on the block. Answer in units of J.
Explanation:
a) 8.2 J
The work done by the force on the block is equal to the force multiplied by the distance moved in the direction of the force. Since the force is applied at an angle of 26.0° with the horizontal, only a component of the force is acting in the direction of motion. The component of the force in the direction of motion is equal to the magnitude of the force multiplied by the cosine of the angle between the force and the direction of motion. Therefore, the work done by the force on the block is equal to:
Work = Force x Distance x cos(26.0°)
= (1.0 kg)(9.81 m/s2)(3.0 m) x cos(26.0°)
= 8.2 J
The separation distance in B is _____ times greater than in A, the force of attraction is _______ than A.
The separation distance in B is two times greater than in A, the force of attraction is greater than A.
What is force of attraction?Force of attraction is described as a force that pulls the body near due to its attraction. Some of these force of attraction include:
magnetic force, electric force, electrostatic force and gravitational force.The force of attraction is given by the formula:
Fg = G* m1m2/r2
where
Fg is the force of attraction,
G is the gravitational constant with the value of 6.67 ×10−11 Nm2/kg2,
m1 is the mass of a body,
m2 is the mass of other body.
r is the distance between the two bodies.
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(Figure 1) shows a container with a cross-section area of 15 cm^2 in which a layer of water floats on top of a layer of mercury. A 1.0 kg wood block with a cross-section area of 10 cm^2 floats on the water. The water depth, measured from the bottom of the block, is 25 cm. A pressure gauge at the bottom of the container reads 26 kPa.
A container with vertical walls is filled with a layer of mercury of height h at the bottom and a layer of water above it. A rectangular block of 1.0 kilogram floats on the water. The distance from the mercury layer to the bottom side of the block is 25 centimeters. The area of the horizontal cross section of the block is 10 square centimeters. The area of the bottom of the container is 15 square centimeters. A pressure gauge is located at the bottom of the container.
Part A
What is the depth dm of the mercury? Use ρw = 1000 kg/m3 as the density of water and ρm = 13,600 kg/m3 as the density of mercury.
Pressure gauge is located at the bottom of the container thus, the depth of the mercury = 11.05 cm
What is pressure?Pressure refers to the force applied on a unit area of a surface. It works parallel to the pressure-applied surface. Pressure = force multiplied by the area on which it operates. The stronger the power, the smaller the area.
Given that,
pressure exerted by block ([tex]P_{B}[/tex])= weight / cross-section area of block
[tex]P_{B}[/tex] = (1 ×9.81) ÷ (10 × 10⁻⁴)
= 9810 Pa
Now, pressure at bottom of container is given as:
[tex]P_{Bottom}[/tex] = [tex]P_{B}[/tex] + ρ × g × h + ρ₁ × g × h₁
[ ρ = density of water,
ρ₁ = density of Hg,
h = height of water and
h₁ = height of Hg ]
Thus, 27000 = 9810 + (1000 × 9.81 × 0.25) + (13600 × 9.81 × h₁)
h₁ = 14737.5 ÷ 133416
h₁ = 0.1105 m
h₁ = 11.05 cm
Thus, depth of the mercury = 11.05 cm.
So, the depth of the mercury = 11.05 cm
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6. Mikey can kick the ball to Sage with a force of 20 N, making it travel 60m. Give the work done on the ball.
Answer:
Explanation:
Given:
F =20 N
D = 60 m
________
W - ?
W = F·D = 20·60 = 1 200 J
To drill or not to drill? That is the big question as Americans face climbing gas prices. Mobil Oil is considering drilling for oil off the coast of California and concerned citizens have protested their attempts to set up drilling sites off-shore. As a result of the controversy, a group of research scientists have been employed by the State of California to study the possible impacts of oil drilling on near-by ecosystems and investigate the likelihood of future oil spills.
The most appropriate method to study the potential impacts of oil drilling on coastal California would be which of these options?
Responses
A research other areas where unsuccessful oil drilling has occurredresearch other areas where unsuccessful oil drilling has occurred
B check historical data in drilling areas to see the likelihood of an oil spillcheck historical data in drilling areas to see the likelihood of an oil spill
C design a computer simulation of an oil spill in the area to determine the environmental impactdesign a computer simulation of an oil spill in the area to determine the environmental impact
D perform a mark and recapture population study on the wildlife in the area prior to drilling
The most appropriate method to study the potential impacts of oil drilling on coastal California would be design a computer simulation of an oil spill in the area to determine the environmental impact design a computer simulation of an oil spill in the area to determine the environmental impact. The correct option to this question is C.
Drilling There are a number of preliminary surveys that must be completed before drilling may be confirmed in the off-coast area, includingTo learn more about the subsurface structures that may make drilling difficult, seismic surveys are conducted in the area.To produce a thorough study, a facias analysis is performed. It aids in identifying the type of facies present, the time the rocks were deposited, and their lithological properties.Additionally, it selects the most promising locations for oil and gas prospecting.So, following a thorough analysis of this criteria and after meeting all requirements, the scientists report these findings and then start digging.For more information on drilling kindly visit to
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The air of an average sneeze travels around 100 miles an hour. Rebecca believes a sneeze induced by a stimulant will produce air that travels at a faster speed than the typical 100 miles per hour. She designs an experiment to induce sneezing. She subjects four participants to different stimulants: pepper, bright light, pollen, and fizzy soda. Once a sneeze is induced, Rebecca measures how fast the air traveled through the nasal passage.
Which statement WOULD NOT be an appropriate hypothesis for Rebecca's experiment?
A Induced sneezes move air at a faster speed than naturally occurring sneezes.
B There is no difference in air speed of induced versus naturally occurring sneezes.
C Using pepper as a stimulant induces more sneezing than any other stimulants.
D All sneezes move air at the same rate of speed.
Based on the study conducted by Rebecca, the statement that would not be an appropriate hypothesis for Rebecca's experiment is:
Using pepper as a stimulant induces more sneezing than any other stimulant; option CWhat is a hypothesis?A hypothesis is an explanation that is given in the form of a statement to explain an observation based on limited evidence and which serves as a starting point for further investigation.
A hypothesis may or may not be true and must be investigated to prove or disprove it.
Experiments are conducted to prove or disprove a given hypothesis.
A hypothesis is divided into a null and an alternate hypothesis.
A null hypothesis is a hypothesis that state that the treatment given to the subjects of the experiment does not produce any significant effect.
An alternate hypothesis states that the treatment given to the subjects of the experiment produces significant effects on the subjects.
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A sound pulse emitted underwater reflects off a school of fish and is detected at the same place 0.10 s later. How far away are the fish? (Assume the water temperature is 20 degrees C.)
I'll assume that the properties of the water are that sound waves in fresh water move at a speed of 1497 m/s at a temperature of 25 °C. If the speed is 0.01s, you must divide it by 100 to get 14.97; but, since it travels there and back in 0.01s, you must split it in half i.e 7.485m.
Without a medium, what kind of wave can travel?
Electromagnetic waves
In contrast to mechanical waves, electromagnetic waves can travel without a medium. This implies that electromagnetic waves can pass not only through solid objects like air and rock but also through empty space.
Why do electromagnetic waves not require a medium to travel?Answer and justification Since electromagnetic waves are not conveyed by the vibration of particles, they do not need a medium to travel. Electric and magnetic fields, which can exist anywhere, oscillate, creating waves. Waves can therefore exist in solids, liquids, gases, or empty space.
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A 7.50 kg bowling ball moving directly east at 6.42 m/s strikes a 1.60 kg bowling pin at rest. After, the pin moves 14.8 m/s at a -47.0° angle. What is the x and y component of the ball’s final velocity?
The x component of the ball's final velocity is 7.35 m/s.
The y component of the ball's final velocity is 4.90 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball along x axis: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin at a -77.0° angle.: v = 20.1 m/s
Let the x component of the ball's final velocity is V₁ m/s.
The y component of the ball's final velocity is V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, The x component of the ball's final velocity is 7.35 m/s.
The y component of the ball's final velocity is 4.90 m/s.
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if you walk 6 km at an average speed of 3 km/h how much time does it take
Answer:
7,229sec
Explanation:
first convert 6km to m and km/h to m/s
1km = 1000m
6km = 6 × 1000m = 6000m
3km/h to m/s
3 × 1000m/ 60min × 60sec = 3000m/3600sec = 0.83m/s
Time=?
distance= average speed/velocity × Time
6000 = 0.83 × t
t=6000/0.83
t= 7,229 sec
or 120min 29sec
what is the acceleration of a 38 kg crate being pushed horizontally by an 83 N force?
The magnitude of acceleration of the crate be 7.14 m/s².
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Mass of the create be: m = 38kg.
Force applied on the create : F = 83N.
From Newton's second law of motion, we can write:
force = mass × acceleration
⇒ acceleration = force/mass = 38/83m/s² = 0.45 m/s².
Hence, acceleration of the create be 0.45 m/s².
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The driver of a car slams on the brakes, causing the car to slow down at a rate of 19.0ft/s2 as the car skids 195ft to a stop.
How long does the car take to stop?
What was the car's initial speed?
The time taken by the car to stop will be 4.53 seconds. The final velocity is zero and the initial velocity will be 86.08 ft./s.
What is velocity?Velocity is a vector quantity which measures distance covered per unit time. It is given that the acceleration of the car a is 19 ft/s². The distance it covered is 195 ft.
We have the expression for final velocity v initial velocity u and the time t with acceleration a as follows where the final velocity v for the car is zero.
0 = U - at
u = at.
The relation between time, acceleration and initial velocity with distance d is written as:
d = u t - 1/2 at²
= at² -1/2 at²
= 1/2 at²
Thus, t = √(2d/a)
= √(2×195 ft / 19 ft/s²)
= 4.53 s.
Initial velocity u = a t
= 4.53 s ×19 ft/s²
= 86.08 ft./s
Therefore, the initial velocity will be 86.08 ft./s.
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A satellite of mass M2 orbits a planet of mass M1 in a uniform circular orbit with a constant tangential velocity, v. The distance between the satellite and the center of the planet is d. If the satellite is moved such that the distance between the satellite and the center is doubled, what is the new gravitational field strength compared to the original gravitational field strength?
The gravitational field strength of the moon at this new distance is gr/4
What is meant by gravitational field ?The gravitational field is the amount of gravitational force that would be applied to a little mass at that location per unit of mass. It is a vector field that is oriented in the mass's expected direction of force.
A gravitational field is the force field that surrounds any mass or collection of masses in space. Although this field spreads out in all directions, the gravitational force becomes weaker the further an object is from the source. This is a method of calculating the gravitational pull. Weight divided by mass equals the strength of the gravitational field. Strength of gravitational field = mass/weight in kilograms, or N/kg.
The complete question is : A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v.
The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?
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Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
The L-shaped object in the figure(Figure 1) consists of three masses connected by light rods.
Part A
What torque must be applied to this object to give it an angular acceleration of 1.00 rad/s2 if it is rotated about the xaxis?
Part B
If it is rotated about the y axis?
Part C
If it is rotated about the z axis (which is through the origin and perpendicular to the plane of the figure)?
The torque required, obtained by finding the product of the moment of inertia and the angular acceleration are as follows;
The torque, τ, that must be applied to the object to give it an angular acceleration of 1.00 rad/s² are;
Part A
τₓ = 9.0 N·mPart B
[tex]\tau_y[/tex] = 10.0 N·mPart C
[tex]\tau_z[/tex] = 19 N·mWhat is an angular acceleration?Angular acceleration is the rate of change of angular velocity with time.
The torque is found from the product of the moment of inertia and the angular acceleration, therefore;
τ = I·α
Where;
τ = The torque
I = The moment of inertia of the mass
α = The angular acceleration
The moment of inertia of a point mass is; I = m·r²
Part A
The mass rotating about the x-axis, m = 9.0 kg
The distance to the point mass, r = 1.0 m
Therefore;
Iₓ = 9.0 kg × (1.0 m)² = 9.0 kg·m²
At α = 1.00 rad/s², we get;
τₓ = 9.0 kg·m² × 1.00 rad/s² = 9.0 N·mThe torque that must be applied to give it an angular acceleration of 1.00 rad/s² if it is rotated about the x-axis is; 9.0 N·m
Part B
If it is rotated about the y-axis, we get;
m = 2.5 kg
r = 2.0 m
[tex]I_y[/tex] = 2.5 kg × (2.0 m)² = 10.0 kg·m²
[tex]\tau_y[/tex] = 10.0 kg·m² × 1.00 rad/s² = 10.0 N·mPart C
The combined moment of inertia of the point masses are therefore;
[tex]I_z[/tex] = (9.0 + 10.0) kg·m² = 19.0 kg·m²
The torque required is therefore;
[tex]\tau_z[/tex] = 19.0 kg·m² × 1.00 rad/s² = 19.0 N·mLearn more about the moment of inertia of an object here:
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An average person with good physical condition can work at the rate of 1 hp for a short period (1 min). Calculate the time needed to run up two flights of stairs with a total H of 8 meters
The time needed to run up two flights of stairs is 8.41 Second.
What is power?Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.
The power of an average person with good physical condition: P = 1 hp = 745.7 watts.
The work done to run up two flights of stairs with a total height of 8 meters = mgh = 80×9.8×8 Joule = 6272 joule.
So the time needed to run up two flights of stairs is= 6272/745.7 second = 8.41 Second.
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Assume that one object collides with a second object that is at rest. In which of the following scenarios would you expect that momentum would not be conserved?
a) When both objects move in the direction of initial motion after colliding.
b) When the objects move in opposite directions after colliding (the second object moves in the direction of initial motion, the first object moves in the reverse direction).
c) When the objects stick together after colliding.
d) When there is an external force (like friction) acting on the objects in the system.
The momemtum is not conserved in scenario d.
What is momentum?Momentum of an object is the product of its mass and velocity.
How to determine In which of the following scenarios would you expect that momentum would not be conserved?To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.
What is the law of conservation of momentum?The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.
If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.
In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.
So, the momemtum is not conserved in scenario d.
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The figure shows a 23 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s . The rails have negligible resistance, but the rod has a resistance of 0.75 Ω .(Figure 1)
A) What is current in the rod?
B) What is magnitude of force required to keep the rod moving at a constant speed?
C) Direction of the force?
a. The induced current is i = 1.42 A
b. The force is F = 0.46 N
c. The force is in the positive z - direction along the rod
What is current?Current is the flow of electric charge ina circuit.
What is force?Force is that thing which causes a change in motion of an object.
A) What is current in the rod?Since the figure shows a 23 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s . The rails have negligible resistance, but the rod has a resistance of 0.75 Ω, the current in the rod is the induced current given by
i = BLv/R where
B = magnetic field = 1.4 TL = length of rod = 23 cm = 0.23 mv = speed of rod = 3.3 m/s and R = resistance of rod = 0.75 ΩSubstituting the values of the variables into the equation, we have
i = BLv/R
i = 1.4 T × 0.23 m × 3.3 m/s/0.75 Ω
i = 1.0626 Tm²/s/0.75 Ω
i = 1.4168 A
i ≅ 1.42 A
The current is i = 1.42 A
B) What is magnitude of force requiredThe magnitude of the force the force on a metallic conductor is given by
F = B²L²v/R where
B = magnetic field = 1.4 TL = length of rod = 23 cm = 0.23 mv = speed of rod = 3.3 m/s and R = resistance of rod = 0.75 ΩSubstituting the values of the variables into the equation, we have
F = B²L²v/R
F = (1.4 T)² × (0.23 m)² × 3.3 m/s/0.75 Ω
F = 1.96 T² × 0.0529 m² × 3.3 m/s/0.75 Ω
F = 0.3422 T²m³/s ÷ 0.75 Ω
F = 0.456 N
F ≅ 0.46 N
The force is F = 0.46 N
C) Direction of the force?We know that the force F = q(v × B) where
v = speed of rod = -vi and B = magnetic field = -BjSo, F =q(v × B)
= q(-vi × Bj)
= q(vB (i × j)
= (qvB)k
Since F is in the positive k direction, the force is in the positive z - direction along the rod
The force is in the positive z - direction along the rod
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A fluid in an insulated, flexible bottle is heated by a high resistance wire and expands. If 9.0 kj of heat is applied to the system and it does 5.0 kj of work, how much does the internal (thermal) energy of the fluid change?
The change in the internal energy of the system is 4 kJ.
What is the first law of thermodynamics?We know that according to the first law of thermodynamics, energy can neither be created nor destroyed but it can be converted from one form to the other.
In this case we know that the internal energy can be obtained by the use of the formula;
ΔE = q + w
ΔE = Change in internal energy
q = Heat absorbed or evolved
w = work done
Where;
q = 9.0 kJ
w = 5.0 kJ
It then follows that;
ΔE = 9 - 5
ΔE = 4 kJ
The gas expands hence the work done is negative.
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In an experiment, a jewel is placed in
water. A laser beam is passed from the
water through the jewel. The angle of
incidence is 50.0°, and the angle of
refraction is 28.0°. What is the index of
refraction, and what type of jewel is it?
Pls help
Answer:
dimond and 21
Explanation:
A 100 Newton tin box is prevented from falling by holding it on both sides. If the pushing forces are 400 newtons each, what is the coefficient of friction?
The coefficient of friction is 0.125
What is the coefficient of friction?The friction coefficient is defined as the ratio of the frictional resistive force to the perpendicular force pushing the objects together. The friction coefficient is represented as, μ = f × N
where is the friction coefficient μ ,
F is the frictional force,
and N is the normal force.
As we know, 2f = W
and f = μ × N
Where, W = weight of tin box
Thus, the co-efficient of friction,
μ = W ÷ 2 N
μ = 100N ÷ (2 × 400 N)
μ = 0.125
Thus, the coefficient of friction is 0.125
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A 6.35 kg bowling ball moving 8.49 m/s strikes
a 1.59 kg bowling pin at rest. After, the pin moves 20.1 m/s at a -77.0° angle. What is
the x and y component of the ball's final velocity?
The x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin: v = 20.1 m/s at a -77.0° angle.
Let the x and y component of the ball's final velocity are respectively V₁ m/s and V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
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Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?
The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.
What is the gravitational force on both planets?
The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.
F = GmM/r²
where;
G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planetThe gravitational force on planet X is written as;
F_X = Gm(mt) / r²
where;
m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet xThe gravitational force on planet Y is written as;
F_y = G(½m)(mt) / (¼r)²
F_y = ½(Gm(mt) / (¹/₁₆ r²)
F_y = (16 Gm mt)/(2r²)
F_y = 8(G m(mt) ) / r²
F_y = 8(F_X)
F_X = ¹/₈(F_Y)
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.
A 2155 kg demolition ball swings at the end of a 17.5m cable on the arc of a vertical
circle. At the lowest point of the swing, the ball is moving at 8.6m/s. Determine the
tension in the cable at the lowest point. (Hint: T-mg =mv^2/r)
Answer:
Thread tension:
T = F + P = 9 108 + 21 120 ≈ 30 230 N
Explanation:
Given:
m = 2155 kg
R = 17.5 m
V = 8.6 m/s
g = 9.8 m/s²
_______________
T - ?
Modulus of centripetal force (force is directed towards the center of the circular arc):
[tex]F = \frac{m\cdot V^2}{R} = \frac{2155\cdot 8.6^2}{17.5} = 9108 N[/tex]
Ball weight (directed vertically down):
W = m·g = 2155·9.8 ≈ 21 120 N
Let's use the hint. Thread tension:
T = F + W = 9 108 + 21 120 ≈ 30 230 N
The tension in the cable at the lowest point of the swing is [tex]30248.196 N[/tex].
To determine the tension in the cable at the lowest point of the swing, we can use the hint provided:
[tex]T-mg=\frac{mv^{2}}{r}[/tex]
where T represents tension,
m is the mass of the demolition ball (2155 kg),
g is the acceleration due to gravity (approximately 9.8 m/s^2),
v is the velocity of the ball (8.6 m/s), and
r is the radius of the circular path (17.5 m).
Plugging in the given values, we have:
[tex]T-2155\times 9.81=\frac{2155\times 8.6^{2}}{17.5}[/tex]
[tex]T=30248.196 N[/tex]
Therefore, the tension in the cable at the lowest point of the swing is approximately [tex]30248.196 N[/tex].
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Using the right hand rule, what do the three numbered vectors represent in the diagram below?
Carl notices that his window air conditioner takes thermal energy from the room and transfers it to the air outside. He thinks he has found an exception to the rules of physics. Which is the most likely reason he is incorrect?
A. Heat does not flow outside naturally. It requires an input of work by the air conditioner.
B. Heat always flows naturally from inside to outside.
C. The room air is actually warmer than the outside air.
D. The air conditioner is actually taking cold from the outside and transferring it into the room.
The heat of the room does not flow outside naturally actually it requires an input of work by the air conditioner. Therefore, option (A) is correct.
How does the air conditioner work?The air conditioner work on the principles of heat sinks. It functions to cool the temperature of a closed space while transferring the heat from a closed space to another place known as a sink. This process consists of four thermodynamic stages that result in the transformation of electrical energy into a thermal heat absorption system.
Air Conditioners are cooling devices that are used to cool large spaces. The capacity of the air conditioner depends on how much space it needs to cool. An air conditioner takes the thermal energy away to make the air cooler.
Therefore, the heat flow outside the room due to work done by the air conditioner.
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(Figure 1) shows a thin liquid film bounded on the right side by a sliding wire that is attached to a spring with spring constant 0.50 N/m. The spring is stretched by 1.3 cm. What is the liquid's surface tension in mN/m?
The liquid's surface tension in N/m is determined as 0.25 N/m.
What is surface tension?
Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.
Mathematically, the formula for surface tension of a liquid is given as;
γ = F/L
γ = F/2x
where;
F is the applied forcex is the extension of the springγ is the surface tensionFrom Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.
F = kx
where;
k is the spring constantx is the extension of the springThe final equation for the surface tension of the liquid film becomes;
γ = F/2x
γ = kx/2x
γ = k/2
γ = (0.5 N/m) / 2
γ = 0.25 N/m
Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.
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An airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, how many degrees east of north does the airplane travel relative to the ground?
a. 66°
b. 63°
c. 27°
d. 24°
please help me
With the knowledge of bearing, the airplane will be 24 degrees east of north relative to the ground. The correct answer is option d
What is Relative Motion ?Relative motion can be defined as a change of position of an object with a point or frame of reference which we may assumed to be at rest.
Given that an airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, the magnitude of degrees Ф east of north in which the airplane will travel relative to the ground can be known by using a trigonometry ratio.
The Y component is 190 km/h heads due north.
The X component is 86 km/h from west to east.
TanФ = Y/X
Ф = [tex]Tan^{-1} (\frac{Y}{X})[/tex]
Ф = [tex]Tan^{-1} (\frac{190}{86})[/tex]
Ф = [tex]Tan^{-1} (2.209)[/tex]
Ф = 65.65°
The degrees east of north = 90 - 65.65
The degree east of north = 24.4°
Therefore, the magnitude of degrees east of north in which the airplane will travel relative to the ground is 24° approximately.
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Bryan rolls a 2kg ball across a rough, grassy field. The field slows the ball with an acceleration of -0.5 m/s^2.
a. Draw the FBD
b. Determine the frictional force the field acts on the ball.
The drawing of free body diagram is attached in answer.
The frictional force the field acts on the ball is 1 newton.
What is acceleration?
Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the ball: m = 2 kg.
Acceleration of the ball during slow down: a = -0.5 m/s².
We have to find: the frictional force the field acts on the ball: f =?
In this case, the frictional force the field acts on the ball: f = mass × acceleration = 2 kg × 0.5 m/s² = 1 newton.
Hence, the frictional force the field acts on the ball is 1 newton.
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Identify the element by its symbol and name after looking at the element model pictured below. Symbol: Name:
The atom that has been shown is an atom of carbon(C).
What is the atom?We know that in an atom is the smallest particle of a substance that can be able to take part in a chemical reaction. In this case, we have a an atom that have been shown. As expected, the protons that are in the atom have been shown as the circle that is in the innermost part of the image.
The electrons are found around the shells of the atom. The electrons that are in the shells of the atom must be equal to the number of protons that are in the atom of the element.
Given that the number of electrons must be equal to the number of protons and the number of protons gives us the identity of the element that have been shown in the image, we can conclude that this is an atom of carbon.
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