Answer:
Explanation:
From the given information; we are to assign the correct naming for the molecular binary compounds.
01. CaCl2 → Calcium CHloride
02. HI (g) → Hydrogen mono iodide gas
03. HI (aq) → Hydroiodic acid
04. BH3 → Borontrihydride
05. Cl2O6 → Dichlorine hexoxide
06. ClF → Chlorine monoflouride
07. P2Cl4 → Phosphorus tetrachloride
08. I2O5 → Diiodine pentaoxide
09. BrF5 → Bromine pentaflouride
10. HBr(aq) → Hydrobromic acid
11. IF7 → Iodine heptaflouride
12. NF3 → nitrogen triflouride
13. H2Se(aq) → hydroselenic acid
14. BrCl → Bromine monochloride
15. H2Se(g) → Hydrogen Selenide
16. SnO2 → Tindeoxide
17. HBr(g) → Hydrogenbromide gas
18. AsF3 → Arsenic triflouride
19. N2O3 → Dinitrogentrioxide
20. IF4 → Iodine pentafluoride
01. hydroiodic acid → HI (aq)
02. hydrogen monoiodide gas → HI (g)
03. diiodine tetraoxide → I2O4
04. bromine monofluoride → BrF
05. silicon tetrahydride → SiH4
06. tetraphosphorus hexaoxide → P4O6
07. disulfur monoxide → S2O
08. carbon monooxide → CO
09. hydrogen monochloride gas → Hcl
10. tetraphosphorus decaoxide → P4O10
11. dibromine monoxide → Br2O
12. dinitrogen tetrafluoride → N2F4
13. disilicon hexahydride → SiH6
14. tetraarsenic hexaoxide → As4O6
15. hydrochloric acid → HCl (aq)
16. arsenic trihydride → AsH3
17. iodine heptafluoride → IF7
18. bromine dioxide → BrO2
19. disulfur decafluoride → S2F10
20. dichlorine heptaoxide → Cl2O7
If energy cannot be created or destroyed, what happens to the kinetic and potential energy?
Answer:
According to the law of conservation of energy, energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant. ... As the car coasts down the hill, it moves faster and so it's kinetic energy increases and it's potential energy decreases. hope this helps
Explanation:
Answer:
They cannot be destroyed or created however,
Explanation:
it can only be transformed or transferred from one form to another.
I have to make this question longer so im just typing thisgjfgjfjvndfi nufnvfjnvfjnjn vnfj
(Go all the way to the bottom)
Don't forget to drink water
Answer:
Ok, thank you
Explanation:
calculate the percentage mass of calcium chloride, CaCi^2
Answer: m-%(Ca) = 40.08 / 110.98
Explanation: molar mass of CaCl2 is 40.08+ 2·35.45 = 110.98
Think you have one mole substance. It contains 40.08 g Ca
Solution remained colorless.
During the experimentation, the test tube was gently heated in a Bunsen burner flame for 60 seconds. What was the reason for this specific
procedure?
A)
Heating was done to initiate the combustion of the metal in water.
B)
Heating was done to confirm that no chemical reaction would take
place in acid
0
Heating was done to precipitate the chemical change in each test
tube containing water
D)
Heating helped released the hydrogen contained in water
molecules so students would have a positive H+ test.
2H2O ---> 2H2O + O 2
Please help me as soon as possible!!! How many grams of H3PO4 are in a 4 L sample of a 17 M solution?
Answer:
about 6664 grams of hydro phosphoric acid are in a sample of 4 L of 17 M solution
Explanation:
grams of H3PO4 = 4 L | 17 mol | 98 grams H3PO4
| 1 L | 1 mol
If anyone could help I’d appreciate it
Answer: 2.00 mol
Explanation:
The balanced chemical equation is:
[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]
According to stoichiometry :
2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex] of [tex]O_2[/tex]
Thus both will act as limiting reagents and will be fully consumed.
2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex] of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.
According to the text, fission occurs when the nucleus
two lighter nuclei.
Answer:
Splits into
Explanation:
Because fission reaction is divided into two or more pieces.
Express these temperatures in degrees Fahrenheit and in kelvins. A.-252.97 C B. -40 C C. 1,064 C
Answer:
A. -423.346 °F, 20.18 K
B. -40°F, 233.15K
C. 1947.2 °F, 1337.15 K
Explanation:
A.
(-252.97 °C × 9/5) + 32 = -423.346 °F
-252.97 °C + 273.15 = 20.18 K
B.
(-40 °C × 9/5) +32 = -40 °F
-40 °C + 273.15 = 233.15 K
C.
(1064 °C ×9/5) + 32 = 1947.2 °F
1064 °C + 273.15 = 1337.15 K
i
CH3-CH2-CO-CH2-CH2-CH3 + H2
Pd
Answer:
i don't know but I just want to have coins
Balance C3H8 + O2 + CO2 + H2O
Assuming the second plus sign is a typo and was meant to be a reaction arrow, this would be the balanced equation:
C3H8 + 5O2 —> 3CO2 + 4H2O
How many Protons, Electrons and Neutrons does Helium-6 have?
Answer:
12 neutrons
2 protons
2 electrons
Answer:
Hello There!!
Explanation:
Helium 6 has:
-two protons
-two electrons
-two neutrons
hope this helps,have a great day!!
~Pinky~
Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-life of approximately billion years, and U-235, which has a half-life of approximately million years. Both were present in equal amounts at the time of thecreation of the Earth, billion years ago. How many years after the creationof the Earth had the amount of radiation from uranium decayed to half theamount present at the time of the creation of the Earth
Answer:
Hello your question is poorly written below is the well written question
Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5 billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth
Answer : 140 billion years
Explanation:
Given that :
U-238 h1/2 = 4.5 billion years
U-235 h1/2 = 700 million years
At the beginning both Isotopes where present in equal amount
Determine the T years before the amount of Uranium decays to Half
T = ? N'2 = N1 / 2
we know that N = No ( 1/2 )^h where h = time / half-life time
attached below is the detailed solution of the given problem
The molecular weight for the compound from the previous question is
64.07 g/mol. What is its molecular formula?
How does size affect weight?
(20 points, write at least 5 sentences answer pls thx!)
Fission and fusion are alike in many ways. However, one difference is
A)
Fusion forms dangerous nuclear waste that is difficult to dispose whereas
fission does not.
Eliminate
B)
Fission is a controllable chain reaction and fusion is not.
Fusion results in a greater product mass whereas fission does not.
D)
Raw materials for fission are cheaper and easy to get.
Explanation:
Fusion vs Fission
In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium. Both reactions release energy which, in a power plant, would be used to boil water to drive a steam generator, thus producing electricity.
Answer:
B
Explanation:
i did this
How can you determine if elements have the same properties?
Answer:
You will know if elements have the same properties if they are in the same column (up and down) on the periodic table.
Explanation:
Ex: Lithium and a hydrogren has the same properites bcause they are both on the same line/column. Columns are up and down the table and rows are left and right. Hope this helps
Mg(s) + 2HCl (aq) -----> MgCl2 (aq) + H2
You have 6.00 g HCl and 4.8 g Mg.
What is the limiting reaction
Answer:
HCl is the limiting reactant
Explanation:
To find the limiting reactant of a reaction we must find the moles of each one as follows:
Moles Mg (Molar mass: 24.305g/mol)
4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg
Moles HCl (Molar mass: 36.46g/mol)
6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl
Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:
0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl
As there are just 0.165 moles of HCl:
HCl is the limiting reactant7x[(7+7)divide7]
PLEASE HELP
Answer:
ik this isnt the answer but mathwa will solve all yours problems
Explanation:
is oxygen a beginning substance or ending substance?
calculate the ph of one solution containing 0.1 M formic acid and 0.1 M sodium formate before and after the addition of 1mL of 5 M Naoh. how much could the Ph change if the NaOh were added to 1 L of pure water
Answer:
Pka of formic acid (HCOOH)= 3.75
pH= PKa +log [ Sodium formate/ formic acid] = 3.75
NaOH reacts with HCOOH as HCOOH (aq) + NaOH(aq) --> NaCHO2 (aq) and H2O (l)
Moles of HCOOH= 0.1*1= 0.1 moles
Moles of NaOH= 5*1/1000= 0.005 moles
HCOOH is in excess and the excess is = 0.1 - 0.005 = 0.095
Moles of sodium formate = 0.005 + 0.1 = 0.105 moles of HCOOH= 0.095
volume after mixing = 1 + 5 /1 000=1.005
Concentrations : HCOOH= 0.095/1.005 sodium formate= 0.105/1.005
pH= 3.75+log (0.105/0.095)=3.85
When NaOH is added, molarity is , 1*5= 1000*M
M= 5/1000=0.005
The pH remains the same. Only the molarity of NaOH changes.
Estimate the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm. [Note: This is a high-field (low-spin) complex.]
Answer:
The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole
Explanation:
Lets calculate -:
Crystal field stabilization energy -
[tex]E=\frac{hc}{\pi }[/tex]
where h = planks constant = [tex]6.626\times10^-^3^4 Js[/tex]
c= velocity of light = [tex]3\times10^8m/second[/tex]
[tex]\pi =wavelength=600nm=600\times10^-^9m[/tex]
[tex]E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}[/tex]
=[tex]0.033\times10^-^1^6 J/ion[/tex]
= [tex]0.033\times10^-^1^6\times6.023\times10^2^3[/tex]
= [tex]0.198759\times10^7 J/mole[/tex] = [tex]1987.59\times10^3J/mole[/tex]
= [tex]1987.59kJ/mole[/tex]
Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is 1987.59kJ/mole
1/5 divided by 3/4 fraction
Answer:
4/15
Explanation:
we can write out an equation by doing (1/5 ÷ 3/4) and then switch the sign to multiplication and we can keep the first fraction the same (in this case 1/5) and then we flip the second fraction BUT when we flip the second fraction upside-down we have to change the symbol to multiplication (1/5x4/3)
then after that all we do is multiply the denominators and numerators :)
1 x 4 = 4
_______
5 x 3 = 15
answer would be 4/15
Choose the best answer
1. Gas A diffuses twice as fast as another gas B. If the density of the gas A is 2, the molecular mass of
(a)2
(b) 4
(c) 8
(d) 16
i think it is
(b) 4
:) hope its correct :)
write the value of atmosphere pressure at sea level .
Answer:
standard sea- level pressure,by definition,equals 760 mm of Mercury,14.70 pounds per square inch, 1,013.25x10³ dynes per square centimetre, 1,013.25 millibars,one standard atmosphere,or 101.325 kilopascale
Here's your answerl hope it's helpful for u....
Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.
Answer: An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.
Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.
What is the concentration of a solution with a
volume of 2.5 liters containing 660 grams of
calcium phosphate Ca3(PO4)2 ?
Answer:
660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).
Explanation:
The number of moles of 660 grams of calcium phosphate is 2.127. Then the molarity of the solution of 2.5 liter volume is 0.85 M.
What is molarity ?Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.
The molarity of a solution is a colligative quantity as well as temperature dependent.
Given,
molar mass calcium phosphate, Ca₃(PO₄)₂ =310.18 g/mol
Then,
no.of moles of calcium sulphate in 660 g = 660 g/310.18 g/mol = 2.127 moles
volume of solution = 2.5 L
Molarity = no.of moles of solute/ volume of solution in L
M = 2.127 moles/ 2.5 L
= 0.85 M.
Therefore, the molarity of the given solution is 0.85 molar.
Find more on molarity:
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Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
A
A and B
B
B and C
с
A, B, and C
D
B, C, and D
Answer:
B, B and C
Explanation:
The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.
What is Smog?This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.
(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.
Read more about Smog here https://brainly.com/question/14029972
What are the types of forces involved in the production of hydro-electricity
Answer:
There are three types of hydropower facilities: impoundment, diversion, and pumped storage. Some hydropower plants use dams and some do not. The images below show both types of hydropower plants.
Explanation:
What is the molality of a solution containing 18.2 g HCl and 250. g of water?
Answer:
m=2.0mol/kg
Explanation:
Hello there!
In this case, according to the formula to compute molality, which requires moles of solute (HCl) and kilograms of solvent (water), we first compute the moles of the former with its molar mass as shown below:
[tex]n=\frac{18.2g}{36.46g/mol}= 0.50mol[/tex]
And then the kilograms of water:
[tex]\frac{250.g}{1000g/kg} =0.250kg[/tex]
Finally, the molality turns out to be:
[tex]m=\frac{0.50mol}{0.250kg}\\\\m=2.0mol/kg[/tex]
Best regards!