n the preceding question, you have calculated the frequency of a molecular vibration. the molecule can absorb light at this frequency. the light happens to be in the infrared (ir) part of the spectrum. it is common to quantify the energy of ir photons using inverse centimeters instead of inverse seconds. to do so, one divides the frequency by the speed of light expressed in cm/sec. what is the energy of the infrared photon corresponding to the frequency from the preceding problem, in cm-1?

Answers

Answer 1

The Energy of the Infrared photon is  45.678* [tex]10^{-21}[/tex] J

The parameters are :

Frequency (f) = [tex]6.9 * 10^{13}[/tex] Hz

Energy is given by E = hf

where h is the Planck's constant = h = 6.62* [tex]10^{26}[/tex]

Putting these values in the formula for energy,

We evaluate the energy of the infrared photon as,

E = hf

E = [tex]6.62 *10^{-34} * 6.9 *10^{13}[/tex] = 45.678* [tex]10^{-21}[/tex]

IR emissions from materials are measured using infrared spectroscopy at certain wavelengths. As photons (light particles) are absorbed or released by electrons in molecules as the electrons pass between orbits, or energy levels, the IR spectrum of a material will exhibit distinctive dips and peaks.

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Related Questions

using newton law of gravity calculate the lenghth of the year. consider the orbit of earth is a circule

Answers

Using Newton's Law of gravity, the length of the year is 364.24 days.

According to Newton's law, there exist a force of gravitation between the sun and the earth, The gravitational force is responsible for the revolution of earth around the sun,

So, we can write,

MW²/R = GMm/R²

Where,

M is the mass of earth,

m is the mass of the sun,

R is the distance between the sun and the earth,

G is the universal Gravitational constant.

Solving the relation,

W² = Gm/R

W = √(Gm/R)

The time period of revolution is given by,

T = 2π/W

So, we can write,

T = 2π√(R/Gm)

Bow, putting all the values,

T = 2π(147 x 10⁶/2 x 10³⁰ x 6 x 10⁻¹¹)

T = 364.24 Days.

So, the length of the year is 364.24 years.

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if a pendulum-driven clock gains 7.2 s/day, what fractional change in pendulum length must be made for it to keep perfect time?

Answers

Pendulum length must be made for it to keep perfect time of 100 or 0.0167 % or 0.017 % nearly.

What is time?

Time is the  measure of to  non-stop, consistent change by  in our surroundings, or it is  usually from a specific to  viewpoint.

Total number of seconds in a normal day is 24×60×60 = 86400 seconds

We know that time period of pendulum is

T= 2π √l/g

Then we use fractional error method

∆T/T = 1/2 ( ∆l /l )

Here l is length of pendulum string

So 7.2/86400 = 1/2 ( ∆l/l)

∆l/l = 0.000167

So percentage change is

∆l/l *100 or 0.0167 % or 0.017 % nearly.

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An electron is accelerated from rest through a potential difference V. Its final speed is proportional to???

Answers

Answer:

E = V q      energy attained by charge q thru potential energy V

E = 1/2 m v^2      kinetic energy of charge q

1/2 m v^2 = V q        equating energy attained

v^2 = 2 V q / m

v = (2 V q / m)^1/2

The final  speed is proportional to the square roots of V, q, and inverse of square root of m.

a fluid flows through a horizontal pipe of radius 1.5 cm at a speed of 5.0 m/s. the density of the fluid is 900 kg/m3 and the pressure is 1.30 x 105 n/m2. when the fluid flows into a connecting pipe of radius 1.0 cm, the speed is increases to 11.0 m/s. what is the pressure in the connecting pipe in pa?

Answers

The pressure in the connecting pipe is 88 pa.

Stress is the pressure applied perpendicular to the floor of an object according to unit place over which that force is sent. Gauge strain is the strain relative to the ambient pressure. diverse gadgets are used to explicit strain.

Calculation:-

radius of pipe = 1.5 cm

speed = 5 m/s

The speed is increases to 11.0 m/s

density of the fluid = 900 kg kg/m³

Pressure = 1.30 × 10⁵ N/m²

The pressure in the connecting pipe in pa = ρdv/dl

                                                                        = 88 pa.

Stress is defined because the bodily pressure exerted on an item. The force applied is perpendicular to the surface of objects in step with unit place. The primary components for strain is F/A (force in keeping with unit location). Unit of pressure is Pascals (Pa). forms of Pressures are Absolute, Atmospheric, Differential, and Gauge pressure.

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Light having a wavelength in vacuum of 600 nm enters a liquid of refractive index 2. 0. In this liquid, its wavelength will be

Answers

The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10 m/s and the wavelength is

4 x 10^-7 m

Given that,

Wavelength X = 600 nm

Refractive index n = 1.5

We know that,

The frequency is the ratio of the speed of light and wavelength of the light.

f = c/λ

f = 3 x 10^8/600 × 10^-9

f = 5 x 10^14 Hz

The speed in the medium is the ratio of the speed of the light in the vacuum and the refractive index.

n = c/v

1.5 = 3 x 10^8/υ

v = 2 × 10^8 m/s

The wave length is the ratio of the speed of the light in the medium and frequency.

λ = v/f

λ = 2 × 10^8/5 x 10^14

λ = 4 × 10^-7 m

Hence, The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10^8 m/s and the wavelength is 4 x 10^-7 m

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What is the maximum speed at which a car can safely travel around a circular track of radius 55. 0 m if the coefficient of friction between the tire and road is 0. 350?.

Answers

The maximum speed at which a car can safely travel around a circular track of radius 55. 0 m is 10.84  m/s

What does it imply to speak of centripetal forces?

Any object is drawn toward the center of a curved surface by a centripetal force. Imagine that you are a yo-yo being spun. The yo-yo is set in motion by your arm movement, and as you twirl it, the tension of the string keeps it spinning.

Given : r=30 m            

μ=0.4                  

g=9.8m/s

2The maximum speed        

v max =μgr= 0.4×9.8×30 =10.84  m/s

How would you describe centripetal force to a young person?

A force known as centripetal force keeps things moving in a circular motion. The object will keep rotating in a circle as long as the centripetal force persists and all other forces are equally balanced. One object that moves in a circle as a result of centripetal force is a yo-yo.

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a 6.0 v ideal battery is being used to charge a 5.0 x 10-6 f capacitor through a resistor r. the capacitor attains a potential difference of 3.6 v in 1.0 s after the charging begins. the value of the resistance r is

Answers

The value of the resistance R in the above case is 120000 Ohms.

In this case

Charge is given by

Q=CV

=6*5*10^-6

=30*10^-6 C

Then the current through the resistor, R is

I=Q/t

=(30*10^-6)/1

=30*10^-6 A

From Ohm's law

R=V/I

=3.6/(30*10^-6)

=120000 Ohms

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your friend is 1.7 m tall. (a) when she stands 3.2 m from you, what is the height of her image formed on the retina of your eye? (consider the eye to consist of a thin lens 2.5 cm from the retina.) (b) what is the height of her image when she is 4.2 m from you?

Answers

(a) Formulae for magnification (m) = distance of image/image of object

                                             =.025/3.2 = 0.00781

so, magnification of eye = 0.00781

now. m = image size / actual size

so, image size = actual size x m

                        = 1.7 x 0.00781

                        = 0.0132 m

(b) similarly, in this case the size of the image can be calculated as follows:

m = distance of image/image of object = 0.00595

image size = actual size x m = 0.0101

What is magnification?

Magnification in physics can be defined as the ratio of size of the image to the size of the object. Magnification in simple terms means enlargement in the size of the image of an object.

It can be denoted by the formulae:

[tex]magnification = \frac{size of the image}{size of the object}[/tex]

It has no SI unit.

Why Magnification has no SI unit?

It has no SI unit because it is a ratio of length.

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metallic bonding occurs when a. a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction b. positive metallic ions are bonded with delocalized free electrons. c. the negative side of one molecule bonds with the positive side of a neighboring molecule d. two metallic atoms share electrons in their outer valence shells

Answers

The answer is A. Metallic bonding occurs when a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction

Metallic bonds are formed when the charge is spread over a larger distance than the size of single atoms in solids. Metallic bonding is a chemical bonding that arises from the attractive electrostatic force between conduction electrons (in the form of an electron cloud of delocalized electrons) and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions (cations). Metallic bonding is not the only type of chemical bonding a metal can exhibit, even as a pure substance.

Metallic bonding occurs when you have a metal in a solid or liquid state. The s and p valence electrons of metals are loosely held. They leave their “own” metal atoms. This forms a "sea" of electrons that surrounds the metal cations. The electrons are free to move throughout this electron sea. A strong metallic bond will be the result of more delocalized electrons, which causes the effective nuclear charge on electrons on the cation to increase, in effect making the size of the cation smaller.

Metallic bonds are strong and require a great deal of energy to break, and therefore metals have high melting and boiling points. A metallic bonding theory must explain how so much bonding can occur with such few electrons (since metals are located on the left side of the periodic table and do not have many electrons in their valence shells). The theory must also account for all of a metal's unique chemical and physical properties.

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v high - speed stroboscopic photographs show that the head of a 2.00 3 102 - g golf club is traveling at 55.0 m/s just before it strikes a 46.0 - g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40.0 m/s. find the speed of the golf ball just after impact.

Answers

Velocity of golf ball after collision with golf club using law of conservation of momentum is 65.21 m/s

What is momentum ?

Momentum seem to be directly dependent on the value of mass as well as velocity of the object in the direction of motion.  it is quantified by "mass velocity". Since mass is a scalar quantity but velocity is a vector, momentum is a vector quantity.

From the given information-

mass of golf club = 200 g

mass golf ball = 46 g

velocity of club before collision = 55 m/s

velocity club after collision =40 m/s

velocity of golf ball before collision = 0 m/s

You need to use conservation of momentum here.

momentum = mass x velocity

Prior to impact, the golf club has a momentum of 0.200 kg * 55 m/s = 11.00 kg m/s.

The ball's not moving before impact, so it has a momentum of zero. Therefore the total momentum before impact will be 11.00 kg m/s. Conservation of momentum dictates the total momentum of the two objects after impact will also be 11.00 kg m/s.

We know the speed of the club after the impact, so the momentum of the club after impqact is 0.200 kg * 40 m/s =8 kg m/s.

So the momentum of the ball must be 11.00 kg m/s - 8 kg m/s = 3 kg m/s, and dividing by the mass of the ball (0.046 kg) gives the speed of the ball, 65.217 m/s

Velocity of golf ball after collision wit golf club is 65.21 m/s

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A wooden loop and a wire loop, both with the same shape and size, are placed next to the north poles of identical magnets. Then, the loops are moved closer to and farther from the magnets in exactly the same way. The emf generated around the wooden loop is zero. O less than the emf generated around the wire loop. equal to the emf generated around the wire loop. O greater than the emf generated around the wire loop.

Answers

The emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.

Give an explanation about EMF.

The electric potential created by either modifying the magnetic field or by an electrochemical cell is known as electromotive force (emf).

Due to the fact that Faraday's law is independent of the material and only considers how the flux is changing, the emf produced around the wooden loop is equivalent to the emf produced around the wire loop. Due to the fact that the loop material moves close to the end of the bar magnet, modifying the magnetic flux through the loop, even though it is not a part of the magnetic flux expression, an emf is nevertheless produced.

Hence, the answer is the emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.

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a cannon sits on a stationary railroad flatcar with a mass of 1000 kg. when a 10-kg cannonball is fired to the left at a speed of 50 m/s, what is the recoil speed of the flatcar? the recoil speed of the flatcar is m/s.

Answers

The recoil speed of the flatcar is0.5 m/s.

Step by Step Explanation:

The cannon's momentum equals the flatcar's momentum according to Newton's third law of motion.

mv = MV........................ Equation 1:

where m is the cannon's mass, v is its velocity, and m is the flatcar's mass, v is its velocity.

Assign V as the subject of the equation V = mv/M... Equation 2

Given: M = 1000 kg

m = 10 kg,

and v = 50 m/s

Replace with V = 1050/1000 V = 500/1000

V = 0.5 m/s in equation 2.

Consequently, the flatcar's speed is equal to 0.5 meters per second.

What is Newton's Third Law of Momentum?An object interacts with another object when a push or pull is applied to it. A product of an interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies interact, they exert force on one another. This force is referred to as an action and reaction pair.According to Newton's third law of motion,The first body receives a force that is equivalent in magnitude to the force applied in the opposite direction when one body exerts a force on another.

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A lever requires an energy input of 10,000 J to move a 35 kg box up a distance of 18 m. What is the efficiency of this lever?

Answers

The efficiency of the lever will be 62%

What is Efficiency?

Efficiency is the ratio of the work performed by a machine to the total energy expended or heat consumed.

Efficiency refers to how close we can get to a particular outcome of the given input with as much less wastage as possible. Efficiency is the ability to minimise wasting materials, efforts, energy and time in performing something or producing the desired result.

The ratio of energy transferred to a useful form compared to the total energy supplied initially is called the efficiency of the device.

Efficiency (%) = (work output/work input) x 100%

work output = mgh

work input = 10,000J

Efficiency (%) = (35 x 18 x 9.8/10,000) x 100

Efficiency (%) = 0.62 x 100

Efficiency (%) = 62%

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if quasars are at the distances most astronomers believe they are, then (for the most luminous ones) their luminosities must be:

Answers

If quasars are located at the distances that the majority of astronomers think they are, then their luminosities must equal the sum of one hundred trillion (1014) Suns.

What kind of brilliance is that?

Something's luminosity is determined by how much light it emits or reflects. A big, sparkling diamond's brightness is its most distinguishing feature. You might talk about the luminosity of an energetic and vibrant oil painting or be in awe of the luminosity of a spectacular sunset.

Does light improve intelligence?

Small (2–3 point) training benefits are obtained via lumosity training. If you exercise for 12 and a half hours over several weeks, you can enhance your IQ, working memory, and other cognitive abilities by about 2-3 points.

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A circular loop of wire with a radius of 13.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.5 T is directed along the positive z-direction, which is upward.part.aIf the loop is removed from the field region in a time interval of 2.7 msms , find the average emf that will be induced in the wire loop during the extraction process.

Answers

A circular loop of wire with a radius of 13.0 cm and oriented in the horizontal XY-plane is located in a region of the uniform magnetic field. A field of 1.7 T is directed along the positive z-direction, which is upward. A) If the loop is removed from the field region in a time interval of 2.9 ms,

The average emf that will be induced in the wire loop during the extraction process=

e =(pi) r^2B/t

e = pi*169*10^-4*1.7/(2.9*10^-3) = 31.12 V

In classical geometry, a radius of a circle or sphere is any of the line segments from its middle to its perimeter, and in greater present-day usage, it is also their length. The call comes from the latin radius, which means ray but additionally, the spoke of a chariot wheel.

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Keiko is riding a skateboard 2 m/s, west. How long will it take her to reach a velocity of 8 m/s, west if her acceleration is 2 m/s2?By definition, acceleration is the measure of a velocity change in time. In a particular case when the acceleration is constant, the velocity of an object is changed uniformly (linearly) with time.
If we denote the initial velocity as V_0, the constant acceleration as a and the time since the initial moment as t, then the new speed V at time t will be
V=V_0+at.
In our problem the velocities and the acceleration are given, and we need to solve the above equation for t. It is simple:
t=(V-V_0)/a=(8-2)/2=3(s).This is the answer. Note that it is important that the initial velocity and the final velocity have the same direction (west). If they would have opposite direction, one of them should be taken with a minus sign, and the acceleration might be negative.

Answers

The time taken to reach a velocity of 8 m/s, west if her acceleration is 2 m/s is 3 seconds

Given,

Velocity of Keiko's skateboard = 2 m/s

Velocity to reach = 8 m/s

Acceleration = 2 m/s²

Velocity is known to be the total displacement that occurred in a particular given time.

It is a vector quantity that has both magnitude and direction.

By the 1st equation of motion regarding velocities,

v = u + at ...........(1)

where,

v = final velocity = 8 m/s

u = initial velocity  = 2 m/s

t = time = ?

a = acceleration = 2 m/s²

Now put all the given values in the above equation 1, we get:

8 m/s = 2m/s + (2 m/s²)t

t = 3 seconds

Therefore, using the velocities, we got the the time taken will be 3 seconds.

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An elastic cord is 61 cm long when a weight of 75 N hangs from it but is 85 cm long when a weight of 210 N hangs from it. What is the "spring" constant k of this elastic cord? also, find the frequency of the motion with the 210N object hanging on it (Physics 'Algebra base')

Answers

The spring constant of this elastic cord is 562.64 Nm.The frequency of the motion with the 210 N is 0.817Hz.

Elastic cord is a fairly versatile stretchy rope. it is small diameter makes it ideal for indoor craft makes use of and light duty strapping. Use this elastic string for sewing initiatives, scrapbooking, and kids' crafts.

Calculation:-

Spring constant K = f/x

= 75/0.61 - L

= 75/0.61 - 0.4767

= 562.64 Nm

Frequency when 210 N is hanging is

extension X = 0.85 -L

= 0.87 - 0.4767

= 0.3733

Frequency = 1/2π√g/X

= 1/2π √9.8/0.3733

= 0.816 Hz.

The free movement of a frame with appreciate to time is called motion. for example-the fan, the dirt falling from the carpet, the water that flows from the tap, a ball rolling around, a shifting car etc. Even the universe is in chronic motion.

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a 0.030-kg bullet is fired vertically at 200 m/s into a 0.15-kg baseball that is initially at rest. how high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?

Answers

If a 0.030-kg bullet is shot vertically at 200 m/s into a 0.15-kg baseball, the combined height of the bullet and baseball following the collision is at most 56.6 m, provided the bullet embeds itself in the ball.

This phase will begin immediately prior to the collision and conclude immediately following the impact (when the two objects are on the verge to move up as a single unit). Note that we are assuming the ball will initially be moving at a speed of 200 m/s when the bullet then collision with it. At this point, we define the system as the ball plus the bullet. We are ignoring any outside factors, such as air resistance or even gravitational force, that can affect this system. As a result, the final velocity of the system immediately following the impact can be determined using the conservation of momentum principle, p=0. The gravitational potential energy is being ignored because we assume that the ball and the bullet were at the same level just before (and just after) colliding.

Yf = v1^2*2*9.8

Yf = 33.3^2*2*9.8

Yf = 56.6 metres.

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you shoot a 51 g pebble straight up with a catapult whose spring constant is 320 n/m. the catapult is initially stretched by 0.20 m. how high above the starting point does the pebble fly? ignore air resistance

Answers

Applying the Conservation of Energy, the point above the starting point of the pebble will fly is 12.8 m

Given Parameters:

Mass of the pebble (m) = 51 g

Spring Constant (k) = 320 N/m

Extension (x) = 0.20 m

Law Of Conservation Of Energy:

According to the rule of conservation of energy, energy cannot be created or destroyed. Energy doesn't evaporate when it is used by people.

Within a specific frame of reference, the total energy of an isolated system either remains constant or is conserved.

According to the law of conservation of energy

Kinetic Energy is equal to potential Energy,

[tex](1/2)kx^2 = mgh\\\\h = (kx^2) / (2mg)= [(320 N/m)(0.20m)^2] / [2(0.051kg)(9.8 m/s^2)]= 12.8 m[/tex]

Thus, The point above the starting point of the pebble will fly is 12.8 m.

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in the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. suppose the background signal level is 13 mv, the signal is 91 mv with no attenuator and is 25 mv with an attenuator in place. calculate pt/pi including the background correction. round your answer to 3 digits after the decimal point.

Answers

15.38 % is pt/pi including the background correction.

What is the definition of an amplitude simple?

The greatest deviation from equilibrium of a point on either a vibrating body or wave in terms of displacement or distance traveled. It is similar to the half-length of the vibration path.

Briefing :

Background [tex]=13mv[/tex]

corrected signal [tex]= 91mv - 13 mv = 78mv[/tex]

with attenuator[tex]=25mv - 13mv = 12 mv[/tex]

[tex]\frac{P_{t} }{P_{i} } = \frac{12}{78} . 100[/tex]

[tex]= 15.38 %[/tex] %

Therefore , the pt/pi is 15.38 %

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a 100 meter long copper wire has a resistance of 100 ω. another copper wire has the same mass but is 10 meters long. find the resistance of the second wire. group of answer choices 1 ω 10 ω 100 ω 1,000 ω

Answers

The resistance of the second wire will be 10 ω.

What is resistance?
Electrical resistance, or resistance to electricity, is a force that opposes the flow of current. It acts as a gauge for the difficulty of current flow in this way. Ohms (Ω) are used to express resistance values. Electricity would then flow from high to low when two terminals have an electron differential. That flow is countered by resistance. The current decreases as resistance increases. On the other hand, the current increases as the resistance decreases. Resistance could be calculated as a number using the circuit's voltage and current.

The resistance of a wire is inversely proportional to its length, so the second wire, which is 10 meters long, will have a resistance that is 10 times less than the first wire, which is 100 meters long. The resistance of the second wire will be 100 ω ÷ 10 = 10 ω.

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g two pool balls, each moving at 2 m/s, roll toward each other and collide. suppose after bouncing apart, each moves at 2 m/s. assume the positive direction is to the right. this collision violates conservation of group of answer choices kinetic energy momentum both kinetic and momentum none of the above

Answers

This collision violates conservation of both energy and momentum i.e, third option is correct.

According to the law of conservation of momentum, when two bodies collide their total momentum and energy before and after collision are equal.

According to the law of conservation of energy, energy can neither be created nor destroyed. However, it can be transformed from one form to another. It is also known as the first law of thermodynamics.

Given that, the two bodies move with same velocities after collision, means that the law has not been violated since, momentum = mass*velocity (where mass is said to be constant)

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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?

Answers

The kinetic energy of the bullet when it left the gun barrel is 1000J.

We know that ,

K.E. = F d

where, K.E. = kinetic energy

F = force

d = distance

Given, F = 1* 10^4 N

          d = 10cm = 0.1 m

Putting these values in above equation we get,

K.E. = 1000J

So the kinetic energy of the bullet when it left the gun barrel is 1000J.

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in the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in case 2 as in case 1. 1)how are the maximum velocities in the two cases related?

Answers

The maximum velocities in the two cases related are Vmax,2 = 2 Vmax,1

Simple harmonic motion :

In physics, simple harmonic motion is the repeated back-and-forth  motion through an equilibrium, or center, position so that the maximum displacement on one side of this position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.

Complete question:

In the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in Case 2 as in Case 1.

1)How are the maximum velocities in the two cases related?

Vmax,2 = Vmax,1

Vmax,2 = 2 Vmax,1

Vmax,2 = 4 Vmax,1

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which planet(s) will experience an increase in gravitational force and an increase in orbital speed from this added mass? explain your reasoning.

Answers

Saturn, Uranus, and Neptune

The reason is that  more mass is added interior to those planets' orbits. With a greater interior mass, Saturn, Uranus, and Neptune will experience a larger gravitational force and an increased orbital speed.

A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther   from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

As seen in the equation v = SQRT(G * Mcentral / R), the mass of the central body (earth) and the radius of the orbit affect orbital speed.

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a machine works with an efficiency of 18%. the energy input is 500 joules/second. how much useful energy will the machine generate in 15 minutes?(1 point)

Answers

The useful energy the machine will generate in 15minutes is 81000J

What is efficiency of a machine?

The efficiency of a machine indicates how well its input energy is converted to useful output energy or work. It is a major factor in the usefulness of a machine and is the fraction or percentage of the output divided by the input.

Therefore the efficiency of a machine is given as Energy output/ energy input ×100 or power output/ power input ×100

let the power output be x

therefore 18=( x/500)×100

100x = 18×500

x= 18×500/100= 90J/s

Energy = power ×time

in 15minutes = 15×60s, the machine will generate energy of 90×15×60= 81000J

Therefore the machine will generate a useful energy of 81000J

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an ideal gas is compressed from 900 cm3 to 425 cm3 while 125 j of heat energy is removed from it. if the gas's pressure remains constant at 400 kpa during the compression, how much work was done by the gas?

Answers

The work done by the gas is 190,000 J.

What is work?
Work in physics is the energy that is transferred to or from a object when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that moves the point of application, or it is said to have positive work. If the component of a force at the point of application is in the opposite direction of the displacement, the force is said to do negative work.

The work done by the gas can be calculated using the equation W = P∆V. In this equation, P represents the constant pressure of 400 kPa, ∆V is the change in volume, and W is the work done by the gas.

Since the volume of the gas changed from 900 cm3 to 425 cm3, the change in volume is ∆V = 900 cm3 - 425 cm3 = 475 cm3. Plugging this into the equation above, we get W = 400 kPa x 475 cm3 = 190,000 J.

Therefore, the work done by the gas is 190,000 J.

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what is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at 8.00 cm? take the lens-to-retina distance to be 2.00 cm.

Answers

Power of the eye is 62.5 diopter The size of the image is - 0.5 mm The size of the image be if the object were held at the normal 25.0 cm is -0.16 mm

What is the power of the eye when viewing an object?The power of the eye varies from 50.0 D (for distant entirely relaxed vision) to 54.0 D (for near fully accommodated vision), which is an increase of 8%, for an eye with this usual 2.00 cm lens-to-retina distance.In other words, multiply 50.5 diopters by 1 over 2.00 times 10 to the minus 2 meters, then take the difference and multiply the result by 1 then multiply that result by the exponent to obtain 2.00 meters. As a result, they can only see a maximum of 2 meters in front of them without glasses since they are severely nearsighted.It is 2.00 cm from the lens to the retina.

Given details :

a)  For this exercise we use the equation for thin lenses

              1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

In this case q is the distance from the lens to the retina q = 2.00 cmThe distance p is the distance from the object to the lens p = 8.00 cm

              1 / f = 1 / 8.00 + 1/2

              1 / f = 0.625 cm⁻¹

power is the inverse of the focal length in meters

             P = 1 / f [m]

             P = 0.625

             P = 62.5 diopter

b)  the size of the image

            m = - p / q

            m = - 2 / 8.00

            m = -0.25 X

if we assume that the object is right

           m = h´ / h

           h´ = m h

           h´ = -0.25 x 2

           h´ = -0.5 mm

if the height of the object h is straight the image and inverted

c) if the object were at p = 25.0 cm

          m = - 2/25

          m = -0.08

            h´ = -0.08 x 2

            h´ = -0.16 mm

the image would be much smaller

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the magnitude of the magnetic field 50 cm from a long, thin, straight wire is 8.0 μt. what is the current through the long wire?

Answers

The current through the long wire is 20A.

What is a magnetic field in simple terms?

The magnetic field is the area around a magnet in which the effect of magnetism is felt. We use the magnetic field as a tool to describe how the magnetic force is distributed in the space around and within something magnetic in nature.

What causes a magnetic field?

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the nucleus, or core, of an atom.

How do you find current in a wire in a magnetic field?

The strength of a magnetic field, , some distance  away from a straight wire carrying a current, , can be found using the equation  =   2  , where  is a constant known as “the permeability of free space”

What happens when a wire with a current is placed in a magnetic field?

The wire will bend away from the poles of the magnet.

[tex]i=\frac{2\pi RB}{m_{0}}[/tex]

Given : [tex]R=0.50m, B=8*10^{-6}[/tex]

[tex]i=\frac{2\pi *0.50*8*10^{-6}}{4\pi *10^{-7}}[/tex]

[tex]i=20A[/tex]

Thus, the current flowing in the wire is 20A.

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Nuclear decay occurs according to first-order kinetics. A nuclide decays in 23. 0 minutes from 12. 9 g to 2. 04 g. What is the rate constant for the nuclide?.

Answers

The rate constant for the nuclide is 0.08.

We know that rate of first order reaction is given by: [tex]kt = 2.303 * log(R'/R)[/tex]

where k = rate of reaction

           t = time = 23 minutes

           R' = initial mass = 12.9 grams

           R = final mass = 2.04 grams

Putting these values in above equation we get k = 0.08.

i.e. the rate constant for the nuclide is 0.08.

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