KEVIN HAS TWO PART-TIME JOBS. HE DELIVERS PIZZA FOR PEDRO'S PIZZERIA
AND MAKES $8 AN HOUR, PLUS $20 FOR DRIVING EXPENSES EACH WEEK. HE
ALSO DOES ODD JOBS FOR A LOCAL HARDWARE STORE, WHERE HE IS PAID $10
AN HOUR.
A. WRITE A SYSTEM OF EQUATIONS TO DESCRIBE THE SCENARIO WHERE H
REPRESENTS THE NUMBER OF HOURS KEVIN WORKS, AND A
REPRESENTS THE AMOUNT HE EARNS AT EACH JOB IN A WEEK.

Options

Answer:

[tex](E)0.7+0.4-0.2=0.9[/tex]

Step-by-step explanation:

In probability theory

[tex]P$(A or B)=P(A)+P(B)$-$P(A and B)[/tex]

Let the event that the show had animals in it = A

P(A)=0.7

Let the event that the show aired more than 10 times =B

P(B)=0.4

P(A and B)= 0.2

[tex]P$(A or B)$=0.7+0.4-0.2=0.9[/tex]

Therefore, the equation which  shows the correct use of the addition rule to determine the probability that a randomly selected show had animals in it or aired more than 10 times is:

[tex]0.7+0.4-0.2=0.9[/tex]

The correct option is E.

Answer:

Step-by-step explanation:

3x - 4y = -23

-x + 2y  = -19

3x - 4y = -23

-3x - 6y = -57

-10y = -80

y = 8

-x + 2(8) = -19

-x + 16 = -19

-x = -35

x = 35

(35, 8)

━━━━━━━☆☆━━━━━━━

▹ Answer

(-61, -40)

▹ Step-by-Step Explanation

3x - 4y = -23

2y - x = -19

3x - 4y = -23

x = 19 + 2y

3(19 + 2y) - 4y = -23

y = -40

x = 19 + 2 * (-40)

x = -61

(x, y) = (-61, -40)

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

[tex]0.0553 - 1.96\sqrt{\frac{0.0553(1-0.0553)}{380}}=0.0323[/tex]

[tex]0.0553 + 1.96\sqrt{\frac{0.0553(1-0.0553)}{380}}=0.0783[/tex]

Step-by-step explanation:

The info given is:

[tex] X= 21[/tex] number of students who said that they planned to work in a rural community

[tex] n= 380[/tex] represent the sample size selected

[tex]\hat p =\frac{21}{380}= 0.0553[/tex] the estimated proportion of students who said that they planned to work in a rural community

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

Replpacing we got:

[tex]0.0553 - 1.96\sqrt{\frac{0.0553(1-0.0553)}{380}}=0.0323[/tex]

[tex]0.0553 + 1.96\sqrt{\frac{0.0553(1-0.0553)}{380}}=0.0783[/tex]

A mean for estimation is the minimum-maximum variation estimate's C.I. The % of pupils planning to work in a rural community alters between 0.0323 and 0.0783.

Confidence interval:

Let's [tex]p^{}[/tex] represent the sampling fraction of the people who promised to work in a rural area.

Sample size:

[tex]n = 380[/tex]

x: the large number the pupils expected to work in a rural setting

[tex]p^{} = \frac{x}{n} \\\\p^{} = \frac{21}{ 380} = 0.0553\\\\(1- \alpha)\ \ 100\%[/tex]confidence for true proportion:

[tex]( p^{}\ \pm Z_{\frac{\alpha}{2}} \times \sqrt{p^{} \times \frac{(1-p^{})}{n}} ) \\\\[/tex]

For [tex]95\%[/tex]confidence interval:

[tex]\to 1 - \alpha = 0.95[/tex]

When:

[tex]\to \alpha = 0.05[/tex]

Calculating the value of Z by using the table:

[tex]\to Z_{0.025} = 1.96[/tex]

When the  [tex]95\%[/tex] of the confidence interval:

[tex]\to (0.0553 \pm Z_{0.025} \times \sqrt{(0.0553 \times \frac{(1- 0.0553)}{380}})\\\\\to (0.0553 - Z_{0.025} \times \sqrt{(0.0553 \times \frac{(1- 0.0553)}{380})},0.0553 + Z_{0.025} \times \sqrt{(0.0553 \times \frac{(1- 0.0553)}{380}))}\\\\[/tex]

by solving the value we get:

[tex]\to ( 0.0323 , 0.0783 )[/tex]

Find out more about the Confidence interval here:

brainly.com/question/2396419

Answer:

24 miles

Step-by-step explanation:

The area of a circle is given by: A = (pi)(r^2)

The problem gives the area as: 1,808.64 sq. mi.

So, (pi)(r^2) = 1,808.64 Solve for r. Divide both sides by pi (3.14)

r^2 = 1.808.64/3.14

r^2 = 576 Take the square root of both sides.

r = 24 Miles.

Answer:

23.99 miles

Step-by-step explanation:

The area of a circle is denoted by A = πr², where r is the radius.

Here, we know the circular area is A = 1808.64 square miles, so plug this into the formula to find r:

A = πr²

1808.64 = πr²

r² = 1808.64 / π ≈ 575.71

r = √575.71 ≈ 23.99 miles

The answer is thus 23.99 miles.

~ an aesthetics lover

Answer: 52.8

Step-by-step explanation: it’s on khan ,

Answer:

Hey there!

3/4= 0.75

1/5=0.2

3/10=0.3

1/7=0.14

Thus, 1/7 is the smallest fraction.

Hope this helps :)

Answer:

The area formula of a triangle is (base * height) / 2 and the area of a square is s² where s is the length of one side.

Answer:

sorry but are you dyin why do u need help why do you need someone to save you just say i need answers to this equation pls

Answer:

A. (0,2) and (7,23)

Step-by-step explanation:

To solve, we set both equations equal to each other (because both equations equal y).

3x + 2 = x^2 -4x + 2

x^2 - 7x = 0

x(x-7)

so the x values are 7 and 0.

Plugging x back into the linear equation (because it’s easier)

3(7) + 2 = 23

3(0) + 2 = 2

so the answers are (7, 23) and (0,2)

Answer:

Hey there!

The solutions to a system are where the lines, or graphs intersect each other.

We see that the graphs intersect at (0, -4) and (2, 0).

Thus, the solutions are (0, -4) and (2, 0).

Hope this helps :)

Answer:

Step-by-step explanation:

Given the 3* 3 matrices [tex]\left[\begin{array}{ccc}0&4&1\\5&-3&0\\2&3&1\end{array}\right][/tex], to compute the determinant using the first row means using the row values [0 4 1 ] to compute the determinant. Note that the signs on the values on the first row are +0, -4 and +1

Calculating the determinant;

[tex]= +0\left[\begin{array}{cc}-3&0\\3&1\\\end{array}\right] -4\left[\begin{array}{cc}5&0\\2&1\\\end{array}\right] +1\left[\begin{array}{cc}5&-3\\2&3\\\end{array}\right] \\\\= 0 - 4[5(1)-2(0)] +1[5(3)-2(-3)]\\= 0 -4[5-0]+1[15+6]\\= 0-20+21\\= 1[/tex]

The determinant is 1 using the first row as co-factor

Similarly, using the second column [tex]\left[\begin{array}{c}4\\-3\\3\end{array}\right][/tex] as the cofactor, the determinant will be expressed as shown;

Note that the signs on the values are -4, +(-3) and -3.

Calculating the determinant;

[tex]= -4\left[\begin{array}{cc}5&0\\2&1\\\end{array}\right] -3\left[\begin{array}{cc}0&1\\2&1\\\end{array}\right] -3\left[\begin{array}{cc}0&1\\5&0\\\end{array}\right] \\\\= -4[5(1)-2(0)] - 3[0(1)-2(1)] -3[(0)-5(1)]\\= -4[5-0] -3[0-2]-3[0-5]\\= -20+6+15\\= -20+21\\= 1[/tex]

The determinant is also 1 using the second column as co factor.

It can be concluded that the same value of the determinant will be arrived at no matter the cofactor we choose to use.

Answer:

[tex]\boxed{Costing Price = $675}[/tex][tex]\boxed{Costing Price = $675}[/tex]Costing Price = $675

Step-by-step explanation:

Selling Price = $432

Discount = 36% of the costing price (36/100 * CP)

Then, Costing Price:

Let costing price be x

=> x - 0.36 x = 432

=> 0.64 x = 432

Dividing both sides by 0.64

=> x = $675

So, the costing Price is $675

Answer:

-4/8

Step-by-step explanation:

Using rise over run would give you -4/8. Since the rise is going downward four times the number would be negative. Since the run is going to the right 8 times it would be positive.

Answer:  the slope is -1/2

Step-by-step explanation:  The rise is -4. Easy to see from the y-intercept, 4 below the origin. The run is 8, again easy to see from the distance between the x-intercept at -8, 8 unite away from the origin.

So slope = rise/run -4/8   simplify (by LCM, 4) So you get slope = -1/2

Answer:

Probability = 0.10565

Step-by-step explanation:

Given:

Mean, u = 2

x = 2.5

CV = 20% = 0.2

To find standard deviation [tex] \sigma[/tex] use the formula:

[tex] CV = \frac{\sigma}{u} [/tex]

[tex] 0.2 = \frac{\sigma}{2} [/tex]

[tex] \sigma = 0.2 * 2 [/tex]

[tex] \sigma = 0.4 [/tex]

Find Z, using the formula:

[tex] Z = \frac{x - u}{\sigma} [/tex]

[tex] Z = \frac{2.5 - 2}{0.4} [/tex]

[tex] Z = \frac{0.5}{0.4} [/tex]

[tex] Z = 1.25 [/tex]

Using the p value table,

P(x > 1.25) = 0.10565

Therefore, The probability that this building will settle more than 2.5 inches is 0.10565

Answer:

if m is supposed to be the equals (=) sign then x = 25

Step-by-step explanation:

45 = (2x-5)

+5         +5

50 = (2x)

÷2     ÷2

25 = x

Answer: 70

Step-by-step explanation:

Answer:

Step-by-step explanation:

opp=x,hyp=16

sin 51°=[tex]\frac{x}{16}[/tex]

cross multiply

sin 51° x 16 =x

0.7771 x 16=x

12.4=x

Answer:

246000 in scientific notation is 2.46e5, or 2.46 x 10^5

Step-by-step explanation:

246000, move the decimal place 5 places to the left.

2.4x10^5

Answer:

2.46 × 10⁵

Step-by-step explanation:

The decimal point is after the first non-zero digit.

⇒ 2.46

Multiply the number with base 10 and an exponent which will equal to 246,000.

⇒ 10⁵

Answer:

Sphete B have a surface area of 48 square feet

Step-by-step explanation:

Two spheres of

Sphere A the smallest and sphere B the biggest has a scale factor of 1/3

Sphere A has surface area of 16 square feet.

Let's determine the surface area of sphere B.

Sphere A /sphere B = 1/3

Sphere A = 16

16/sphere B = 1/3

3*16= sphere B *1

48 = sphere B

Sphete B have a surface area of 48 square feet

Answer:

Validation

Step-by-step explanation: Validation is a term used to describe the processes involved when we compare a set of values and observations against a set standard or rules to ensure that they meet certain expectations or criteria.

Validation is meant to prove that something, a data set etc are acceptable based on known rules, the rules or standards which is used to evaluate what can be described as valid.

Answer:

The 99​% confidence interval estimate of the percentage of girls born is between 85.46% and 94.54%.

Usually, babies are equally as likely to be boys or girls. Here, it is desired to increase the probability of conceiving a girl, which is achieved, considering the lower bound of the confidence interval is considerably above 50%.

Step-by-step explanation:

Confidence interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 290, \pi = \frac{261}{290} = 0.9[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 - 2.575\sqrt{\frac{0.9*0.1}{290}} = 0.8546[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 + 2.575\sqrt{\frac{0.9*0.1}{290}} = 0.9454[/tex]

Percentage:

Proportion multplied by 100.

0.8546*100 = 85.46%

0.9454*100 = 94.54%

The 99​% confidence interval estimate of the percentage of girls born is between 85.46% and 94.54%.

Based on the​ result, does the method appear to be​ effective?

Usually, babies are equally as likely to be boys or girls. Here, it is desired to increase the probability of conceiving a girl, which is achieved, considering the lower bound of the confidence interval is considerably above 50%.

Answer:

The alternative hypothesis will state that there is significant difference between the mean list price of a three bedroom home and the mean list price of a four bedroom home.

[tex]H_a:\mu_1-\mu_2\neq 0[/tex]

Step-by-step explanation:

This would be an two-sample hypothesis test for the difference between two means.

As we are looking for differences, we are not testing if one population mean is bigger than the other. This will  be a two-tailed test and the alternative hypothesis will have a unequal sign.

The alternative hypothesis will state that there is significant difference between the mean list price of a three bedroom home and the mean list price of a four bedroom home.

This can be written as:

[tex]H_a:\mu_1-\mu_2\neq 0[/tex]

meaning that the population means are significantly different.

Answer:

I think its

             T

 R--------Q----------A

             U

Step-by-step explanation:

Because RA as a line bisects TU

Answer:

[tex]\large \boxed{\text{-1.8$^{\circ}$F/1000 ft}}[/tex]

Step-by-step explanation:

Identify the changes (Δ) in each consecutive pair of x-values and y-values, then calculate the corresponding values of Δy/Δx

Your working table should look like the one below.

[tex]\begin{array}{cccc}\textbf{Alt/1000 ft} & \textbf{B.p.$/^{\circ}$F} & \Delta\textbf{B. p}& \Delta\textbf{B.p/1000 ft}\\0 & 212.0 & & \\& &-0.9 & -1.8\\0.5 & 211.1 & & \\& &-0.9 & -1.8\\1.0 & 210.2 & & \\& &-1.8 & -1.8\\2.0 & 208.4 & & \\& &-1.8 & -1.8\\3.0 & 206.6 & & \\& &-1.8 & -1.8\\4.0 & 204.8 & & \\& &-0.9 & -1.8\\4.5 & 203.9 & & \\\end{array}[/tex]

[tex]\text{ The change in boiling point per thousand feet of altitude is $\large \boxed{\textbf{-1.8$^{\circ}$F/1000 ft}}$}[/tex]

Answer:

Answer:

Step-by-step explanation:

Identify the changes (Δ) in each consecutive pair of x-values and y-values, then calculate the corresponding values of Δy/Δx

Your working table should look like the one below.

Step-by-step explanation:

Hey there! :)

Answer:

16p + 6.

Step-by-step explanation:

Add the two binomials together by combining like terms:

12p + 9 + 4p - 3

12p + 4p + 9 - 3

16p + 6.

Answer:

16p+6

Step-by-step explanation:

You combine like terms you do not multiply.

Answer:

1. Point estimate M (sample mean): 83.33

2. The lower bound is $73.36 and the upper bound is $93.30. One can be______% confident that the mean travel tax for all cities is between these values.

3. A. The researcher could decrease the level of confidence.

Step-by-step explanation:

A point esimate for the population mean travel tax can be done with the sample mean.

We can calculate the sample mean as:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{8}(67.85+78.62+70.28+84.03+79.28+87.72+101.54+97.28)\\\\\\M=\dfrac{666.6}{8}\\\\\\M=83.33\\\\\\[/tex]

2. We have to calculate a 95% confidence interval for the mean.

The sample mean is M=83.33.

The sample size is N=8.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

We calculate the sample standard deviation as:

[tex]s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{7}((67.85-83.33)^2+(78.62-83.33)^2+(70.28-83.33)^2+. . . +(97.28-83.33)^2)}\\\\\\s=\sqrt{\dfrac{994.49}{7}}\\\\\\s=\sqrt{142.07}=11.92\\\\\\[/tex]

The standard error is:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{11.92}{\sqrt{8}}=\dfrac{11.92}{2.828}=4.214[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=8-1=7[/tex]

The t-value for a 95% confidence interval and 7 degrees of freedom is t=2.36.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=2.36 \cdot 4.214=9.97[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 83.33-9.97=73.36\\\\UL=M+t \cdot s_M = 83.33+9.97=93.30[/tex]

The 95% confidence interval for the mean travel tax is (73.36, 93.30).

We can be 95% confident that the true mean travel tax is within this interval.

3.. If we have no access to additional data, we can not decrease the standard deviation or increase the sample size.

The only way to have a narrower confidence interval is decreasing its level of confidence. With the same sample information, the lower the confidence, the narrower is the interval.

Answer:

The statistic for this case would be:

[tex] z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}[/tex]

And replacing we got:

[tex] z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92[/tex]

Step-by-step explanation:

For this case we have the following info:

[tex] n =700[/tex] represent the sample size

[tex] X= 305[/tex] represent the number of employees that earn more than 50000

[tex]\hat p=\frac{305}{700}= 0.436[/tex]

We want to test the following hypothesis:

Nul hyp. [tex] p \leq 0.4[/tex]

Alternative hyp : [tex] p>0.4[/tex]

The statistic for this case would be:

[tex] z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}[/tex]

And replacing we got:

[tex] z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92[/tex]

And the p value would be given by:

[tex] p_v = P(z>1.922)= 0.0274[/tex]

Answer:

  134 degrees

Step-by-step explanation:

Right so far. To find the numerical measure of the angle, you need to use x=7 in your expression for the angle measure:

  m∠STU = -27 +23(7) = 134 . . . degrees

Answer:  y=-(4/3)*x-6

Step-by-step explanation:

The equation of any straight line is y=a*x+b  (1).

So we have to find the coefficients a and b and substitute them to the equation (1).

If the required line is perpendicular to y= (3/4)*x-2 it means that

a= -(4/3)   (we have to inverse the fraction 3/4 and put the opposite sign after that.  3/4 has the sign + in front of it  so we have to put sign -)

So the equation of required line is y= -(4/3) *x+b .

Now we have to find b.   To do that pls remember that the point (-12;10)  belongs to the required line y= -(4/3) *x+b  . That means:

10=-(4/3)*(-12)+b  => 10=16+b =>  b=-6

So substitute b in equation (1) and get:

y=-(4/3)*x-6

Answer:

There is enough paint to cover the tank with one layer of paint.

Step-by-step explanation:

Given the cilindrical configuration of the tank and supposing that only external face must be painted, the surface area of the section (lateral wall + lid) can be calculated by the following expression:

[tex]A_{s} = 2\pi\cdot r\cdot h + \pi\cdot r^{2}[/tex]

Where [tex]r[/tex] and [tex]h[/tex] represent the radius and the height of the cube, respectively.

If [tex]r = 0.55\,m[/tex] (a diameter is two times the length of radius) and [tex]h = 1.4\,m[/tex], the intended surface area is:

[tex]A_{s} = 2\pi\cdot (0.55\,m)\cdot (1.1\,m)+\pi\cdot (0.55\,m)^{2}[/tex]

[tex]A_{s} \approx 4.751\,m^{2}[/tex]

It is known that 250 mL of paint are needed to cover a square meter of the surface area, the needed amount of paint to cover the required area is estimated by simple rule of three:

[tex]Q = \frac{4.751\,m^{2}}{1\,m^{2}}\times (250\,mL)[/tex]

[tex]Q = 1187.75\,mL\,(1.188\,L)[/tex]

In consequence, there is enough paint to cover the tank with one layer of paint.