Kay found four frogs on Monday and nine frogs on Tuesday in the pond by her house. Each frog has 5 warts. How many more warts are on the frogs from Tuesday than from Monday?

Answers

Answer 1

Answer: 25

Step-by-step explanation:

Given

Kay found 4 frogs on Monday

and 9 frogs on Tuesday by her house

each frog has 5 warts

So, total warts on Monday and Tuesday

[tex]\Rightarrow \text{Monday=}4\times 5\\\Rightarrow 20\\\\\Rightarrow \text{Tuesday =}9\times 5\\\Rightarrow 45[/tex]

The difference of warts is

[tex]\Rightarrow 45-20\\\Rightarrow 25[/tex]

Thus, there are25 more warts on frogs from Tuesday than from Monday  

Answer 2

Frogs On Monday:

4 frogs x 5 = 20 warts

Frogs On Tuesday:

9 frogs x 5 warts = 45

Last Step:

45 (9 frogs each with 5 warts) - 20 (4 frogs each with 5 warts) =

Answer: 25

            ~Hope this helps!

      ~Hocus Pocus


Related Questions

Whoever sees this first and answers it first get to be marked brainliest and gets 185 points​

Answers

aaa THIS IS HELPPING JE A LOT TYYaaaaaAnswer:

Step-by-step explanation:

Answer:

yooooooooooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

Find all the missing elements:
B
14
15
70°
A
b
с

Answers

Answer:

[tex]B=48.7\\[/tex]

[tex]c=61.3[/tex]

[tex]b=12[/tex]

Step-by-step explanation:

Using sines law for triangles,

[tex]\frac{15}{sinA} =\frac{14}{sinc} =\frac{b}{sinB} \\\\A= 70[/tex]

⇒ [tex]\frac{15}{sin70} =\frac{14}{sinC} =\frac{b}{sinB}[/tex]

⇒ [tex]\frac{15}{0.9397} =\frac{14}{sinC}=\frac{b}{sinB}[/tex]

⇒ [tex]15.9625=\frac{14}{sinC}[/tex]

⇒ [tex]SinC=\frac{14}{15.9625}=0.8771[/tex]

⇒ [tex]C=Sin^{-1}(0.8771)=61.29[/tex]

⇒ [tex]C=61 ~ or ~ 61.30[/tex]

[tex]\frac{b}{Sin B}=15.9625[/tex]

Now sum of angles a Δ is 180°

A+B+C=180°

[tex]70+B+61=180[/tex]

[tex]B=180-131=49~ or ~ 48.7[/tex]

[tex]b=sin(48.70)(15.9625)=(0.7547)*(15.9625)= 12.0[/tex]

╔════ ∘◦ ☆ ◦∘ ══════╗

       hope it helps..

      have a great day!!

╚═════ ∘◦ ❉ ◦∘ ═════╝

I need help with this ASAP!!!!

Answers

Answer:

B) 81.96°

Step-by-step explanation:

40.67 - (-41.29)

40.67 + 41.29 = 81.96

What is the area and perimeter?

Answers

Answer:

Perimeter: 26 units

Area: 24 units²

Step-by-step explanation:

12 + 9 + 5 = 26

A = 1/2BH

A = 1/2 12(4)

A = 1/2 48

A = 24

the permitter is 26 and the area is 24

help me out please ill give you 5 star, brainlist

Answers

Answer:

H

Step-by-step explanation:

you can see that it's increasing by 50 for each line

4*50=200

the answer? wowisoososksks

Answers

Answer:

1/6

Hope that this helps!

find a
polynomial P(x) of 2nd degree if P(1)=0
P (2) 3
P(-3)=0​

Answers

Given:

P(x) is a 2nd degree polynomial.

[tex]P(1)=0,\ P(2)=3,\ P(-3)=0[/tex]

To find:

The polynomial P(x).

Solution:

If P(x) is a polynomial and P(c)=0, then c is a zero of the polynomial and (x-c) is a factor of polynomial P(x).

We have, [tex]P(1)=0,\ P(-3)=0[/tex]. It means 1 and -3 are two zeros of the polynomial P(x) and (x-1) and (x+3) are two factors of the polynomial P(x).

So, the required polynomial is defined as:

[tex]P(x)=a(x-1)(x+3)[/tex]          ...(i)

Where, a is a constant.

We have, [tex]P(2)=3[/tex]. So, substituting [tex]x=2,\ P(x)=3[/tex] in (i), we get

[tex]3=a(2-1)(2+3)[/tex]

[tex]3=a(1)(5)[/tex]

[tex]3=5a[/tex]

[tex]\dfrac{3}{5}=a[/tex]

Putting [tex]a=\dfrac{3}{5}[/tex] in (i), we get

[tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex]

Therefore, the required polynomial is [tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex].

can someone please help
question: An airplane is flying at an elevation of 1500 feet. What is the airplane's angle of elevation from the runway when it is 5000 feet from the runway?

Answers

Answer:

Angle of elevation of the airplane = 17.46 degrees

Step-by-step explanation:

From the picture attached,

An airplane is flying at an altitude of 1500 ft at point A.

Runway starts from point B from which distance of the airplane is 5000 ft.

Now we apply sine rule in the given triangle ABC to measure the angle θ.

sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

sinθ = [tex]\frac{AC}{AB}[/tex]

       = [tex]\frac{1500}{5000}[/tex]

[tex]\theta=\text{sin}^{-1}(\frac{3}{10})[/tex]

[tex]\theta=17.46[/tex] degrees

12x - 24 + 3x = 1/3x + 4 + 10x plz no link or spam (i will report you)

Answers

Answer:

x=6

15x - 24 = 1/3x + 4 + 10x

=

45x - 72 = x + 12 + 30x

=

45x - 72 = 31x + 12

=

45x - 31x = 12 + 72

=

14x = 84

=

x = 6

find the difference between the points (-7,6) and (7,6) IM GOING CRAZY WITH THE POINT TODAY WORTH A LIFE TIME GET IT CORRECT YOU GET BRAINLEST YES SIRR

Answers

Answer: 14

Step-by-step explanation:

For:

(X1, Y1) = (-7, 6)

(X2, Y2) = (7, 6)

Distance Equation Solution:

=(7−(−7))2+(6−6)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

=(14)2+(0)2‾‾‾‾‾‾‾‾‾‾‾√

=196+0‾‾‾‾‾‾‾√

=1‾√96

=14

4 Students is___% of 20 students.

Answers

Answer:

20%

Step-by-step explanation:

4 / 20 = 0.2 = 20%

Hope this helps :)

Answer:

4 Students is 20% of 20 students.

Step-by-step explanation:

[tex] \frac{4}{20} \times 100[/tex]

= 4 × 5 %

= 20%

help poor mi............​

Answers

The chosen topic is not meant for use with this type of problem. Try the examples below.

[tex]cot (3x),x=\frac{2\pi }{3}[/tex]

[tex]cot ( \frac{x}{2}, x=\frac{\pi }{2}[/tex]

[tex]cos (x), x = \frac{x}{2}[/tex]

5. (08.01) Line M is represented by the following equation: x + y = -1 What is most likely the equation for line P so the set of equations has infinitely many solutions?
O 2x + 2y = 2
O 2x + 2y = 4
O 2x + 2y = -2
O x - y = 1​

Answers

Answer:

2x + 2y = -2

Step-by-step explanation:

you can divide a 2 from all three terms in 2x + 2y = -2 to get x + y = -1 which overlaps the original equation to provide an infinite number of solutions

Which of these are the constant?
4y+1+9x

Answers

Answer:

1 is the constant

Step-by-step explanation:

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 51 and 55

Answers

Answer:

percentage of lightbulb replacement requests =  34.15 %

Step-by-step explanation:

According to Empirical Rule

interval                                                          %

μ  ±  σ            55  ±  4     ( 51 ; 59 )              68.3

As the question is a percentage between    55  and  51

or  between  51   and  μ  -  σ    by symmetry    is  68.3/2

% of lightbulb replacement requests =  34.15 %

PLEASE HELP ASAP!!!

Given that PQ/ST = QR/TU = RS/US , select the postulate or theroem that you can use to conclude that the triangle are similar.

○ ASA similarly postulate
○ SAS similarly theorem
○ AA similarly postulate
○ SSS similarly theorem ​

Answers

SSS Similarity Theorem

Which of these is a two-step equation? Ax + 9 = 21incorrect answer Bx = 11 + 2incorrect answer C2x + 9 = 21incorrect answer Dx/3 = 9

Answers

Answer:

2x + 9 = 21

Step-by-step explanation:

Looking at option C;

2x + 9 = 21

Step 1: Subtract 9 from both sides

2x+9 - 9 = 21 - 9

2x = 12

Step 2: divide both sides by 2

2x/2 = 12/2

x = 6

Hence the expression which is a two-step equation is 2x + 9 = 21 since we arrived at the solution in two steps

'na1 18 43 written in expanded form?
A.
B.
C.
D.
4x3
4+4+4
3x3 x3 x3
4 x 4 x 4​

Answers

Whensjsyabsyhvqkaihsnsna

Help!!!!!!!!!!!!!!!
If f(x) = -(24 – 32) – x, find f(-2).

Answers

There are 2 answers.
Hope it helps :)

Circle A has a radius of 12 in., m( arc BC )=π/6, m( arc CD ) = π/4. What is the area of the sector with the central angle ∠BAD?

Answers

Answer:

Area of the sector = 94.25 in²

Step-by-step explanation:

From the picture attached,

Length of the radius of the circle = 12 in.

m(arc BC) = [tex]\frac{\pi }{6}[/tex]

m(arc CD) = [tex]\frac{\pi }{4}[/tex]

Therefore, m(arc BD) = m(arc BC) + m(arc CD)

m(arc BD) = [tex]\frac{\pi }{6}+\frac{\pi }{4}[/tex]

                 = [tex]\frac{5\pi }{12}[/tex]

Since, area of a sector with central angle 'θ' is given by,

Area of the sector = [tex]\frac{\theta}{2\pi }(\pi r^2)[/tex]

By substituting the measures in the given formula,

Area of sector BAD = [tex]\frac{\frac{5\pi }{12}}{2\pi }(\pi )(12)^2[/tex]

                                  = [tex]\frac{5}{24}(\pi )(144)[/tex]

                                  = [tex]30\pi[/tex]

                                  = 94.25 in²

Evaluate the expression 4x^2 + 3y for x = 5 and = 6.

Answers

Answer: 118

Step-by-step explanation:

If the simple interest earned on $6000 for 9 years is $2,160. Then what is the interest rate?

Answers

Answer:

4 %

Step-by-step explanation:

1 year interest =2160÷9

= £240

Interest rate=240/6000 ×100

=4%

SOMEONE ANSWER QUICK!!

Steven bought 4 pizzas to share with his family. Together, they ate 2 7/12 pizzas on Friday and another 2/3 of a pizza on Saturday. How much pizza is left??

Answers

Answer:

3/4 of a pizza leftover.

Step-by-step explanation:

2 7/12 + 2/3 = 3 1/4

4 -  3 1/4 = 3/4

so 3/4 of 1 pizza is left.

Whats the volume help pls

Answers

Answer:

36 Cubic Units

Step-by-step explanation:

Volume of a cube: Length x Width x Height

4 x 3 x 3 = 36

x^2 + y^2 =-6x-14-6y

Answers

Answer:

x=−3+√(−y−1)(y+5)

Step-by-step explanation:

thats if your solving for x if not to math w    l   ay

I will give brainlest please help

Answers

Answer:

The center of the circle would be (5,-8)

This is because you inverse the sign within the equation for the x/y coordinate part of it. Therefore, for this question:

(x-5)^2+(y+8)^2 = 121

The center would be (5,-8), since there is (x-5) and (y+8).

The radius of the circle would be 11

This is because within the equation for the circle, the finishing number is the radius squared. This means that if you square root this finishing number, you would get the radius. So with this question:

(x-5)^2+(y+8)^2 = 121

By doing √121, you would get 11 as the radius.

PLS HELP ASAP BRAINLIEST!!!

Suppose that the distance a car travels varies directly with the amount of gasoline it uses. A certain car uses 5 gallons of gasoline to travel 130 miles. If the car travels 442 miles, how much gasoline does it need?

Answers

Answer:

17 gallons

Step-by-step explanation:

What is the slope of the line that passes through the points listed in the table?

x | y
4 | 3
7 | 9

A. -2

B. 2

C. 3

D. 6

Answers

Answer:

B. 2

Step-by-step explanation:

(4, 3) (7, 9)     M = Slope

M = [tex]\frac{y^2-y^1}{x^2-x^1}[/tex]      Slope formula

[tex]M=\frac{9-3}{7-4}[/tex]       Using the slope formula, plot both x and y intercepts

[tex]M=\frac{6}{3}[/tex]           Slope needs to be simplified into a whole number

[tex]M=2[/tex]          

The third-degree Taylor polynomial about x = 0 of In(1 - x) is

Answers

Answer:

[tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

FunctionsFunction Notation

Calculus

Derivatives

Derivative Notation

Derivative Rule [Quotient Rule]:                                                                                [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

MacLaurin/Taylor Polynomials

Approximating Transcendental and Elementary functionsMacLaurin Polynomial:                                                                                     [tex]\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n[/tex]Taylor Polynomial:                                                                                            [tex]\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n[/tex]

Step-by-step explanation:

*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.

Step 1: Define

Identify

f(x) = ln(1 - x)

Center: x = 0

n = 3

Step 2: Differentiate

[Function] 1st Derivative:                                                                                  [tex]\displaystyle f'(x) = \frac{1}{x - 1}[/tex][Function] 2nd Derivative:                                                                                [tex]\displaystyle f''(x) = \frac{-1}{(x - 1)^2}[/tex][Function] 3rd Derivative:                                                                                 [tex]\displaystyle f'''(x) = \frac{2}{(x - 1)^3}[/tex]

Step 3: Evaluate Functions

Substitute in center x [Function]:                                                                     [tex]\displaystyle f(0) = ln(1 - 0)[/tex]Simplify:                                                                                                             [tex]\displaystyle f(0) = 0[/tex]Substitute in center x [1st Derivative]:                                                             [tex]\displaystyle f'(0) = \frac{1}{0 - 1}[/tex]Simplify:                                                                                                             [tex]\displaystyle f'(0) = -1[/tex]Substitute in center x [2nd Derivative]:                                                           [tex]\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}[/tex]Simplify:                                                                                                             [tex]\displaystyle f''(0) = -1[/tex]Substitute in center x [3rd Derivative]:                                                            [tex]\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}[/tex]Simplify:                                                                                                             [tex]\displaystyle f'''(0) = -2[/tex]

Step 4: Write Taylor Polynomial

Substitute in derivative function values [MacLaurin Polynomial]:                 [tex]\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3[/tex]Simplify:                                                                                                             [tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]

Topic: AP Calculus BC (Calculus I/II)

Unit: Taylor Polynomials and Approximations

Book: College Calculus 10e

Evaluate the expression.
3 + (50- 5^2)

Answers

The answer is = 28 …………….
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