Answer:
Examples of strong acids are hydrochloric acid (HCl), perchloric acid (HClO4), nitric acid (HNO3) and sulfuric acid (H2SO4). A weak acid is only partially dissociated, with both the undissociated acid and its dissociation products being present, in solution, in equilibrium with each other.
Explanation:
Hope this helps you
Which word best describes the relationship between polyps and algae
exoskeletal
Bleached
Photosynthetic
Symbiotic
Answer:
symbiotic
Explanation:
There like a close friendship
3. A very large distillation column is separating p-xylene (more volatile) from o-xylene. The column has two feeds that are saturated liquids. Feed 1 flows into the column at a rate of 90 kmol/h and contains 42 mol% p-xylene. Feed 2 flows at a rate of 20 kmol/h and contains 9 mol% p-xylene. The bottoms product should be 97 mol% o-xylene, and the distillate product should be 99 mol% p-xylene. Compute the distillate (D) and the bottoms (B) products flow rates
Answer:
the distillate (D) and the bottoms (B) products flow rates are;
B = 72.1875 kmol/hr
D = 37.8125 kmol/hr
Explanation:
Given the data in the question;
as illustrated in the image below;
F1 stream, ( 90 kmol/hr ) contains 42 mol% p-xylene and Feed 2 ( 20 kmol/hr) contains 9mol% p-xylene, so;
more volatile → p-xylene
less volatile → o-xylene
now, Overall balance;
F1 + F2 = D + B
90 + 20 = D + B
D + B = 110 ------------- let this be equation 1
p-xylene. component balance;
0.42F1 + 0.09F2 = 0.99D + 0.03B
0.42(90) + 0.09(20) = 0.99D + 0.03B
37.8 + 1.8 = 0.99D + 0.03B
0.99D + 0.03B = 39.6 --------------- let this be equation 2
from equation 1 and 2
input (D = 110 - B) into equation 2
0.99(110 - B) + 0.03B = 39.6
108.9 - 0.99B + 0.03B = 39.6
108.9 - 39.6 = 0.99B - 0.03B
69.3 = 0.96B
B = 69.3 / 0.96
B = 72.1875
now, input B = 72.1875 into equation 1
D + B = 110
D + 72.1875 = 110
D = 110 - 72.1875
D = 37.8125
Therefore, the distillate (D) and the bottoms (B) products flow rates are;
B = 72.1875 kmol/hr
D = 37.8125 kmol/hr
What is the difference between an introduced species and an invasive species?
Answer and Explanation:
The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.
An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.
how many grams of na2co3 would be needed to produce 1000g of nahco3
Answer:
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Explanation:
The balanced reaction is:
Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Na₂CO₃: 1 moles CO₂: 1 moleH₂O: 1 mole NaHCO₃: 2 molesBeing the molar mass:
Na₂CO₃: 106 g/moleCO₂: 44 g/moleH₂O: 18 g/moleNaHCO₃: 84 g/moleThen by stoichiometry the following quantities of mass participate in the reaction:
Na₂CO₃: 1 mole* 106 g/mole= 106 gCO₂: 1 mole* 44 g/mole= 44 gH₂O: 1 mole* 18 g/mole= 18 gNaHCO₃: 2 moles* 84 g/mole= 168 gYou can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?
[tex]mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}[/tex]
mass of Na₂CO₃= 630.95 grams
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
3. Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry?
Answer:
Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry? It refers to substances that easily lose electrons. It refers to substances that do not react with other substances. It refers to substances that have strong electrochemical charges.
Explanation:
Explain why NO is more soluble in water than either N2 or O2. Fill in the following blanks.
a. Compared to nitrogen, the ____________of ethylene makes it more soluble in water.
b. The high solubility of sulfur dioxide can be explained by its ______________
c. Nitric oxide is more soluble than nitrogen and oxygen because of its ______________
d. Compared to oxygen, nitrogen's _____________ makes it more difficult for water molecules to surround the nitrogen molecules.
1. Polarity
2. Ability to react with water
3. Shorter bond length
4. Larger molecular size
Answer:
a. Larger molecular size
b. Ability to react with water
c. Polarity
d. Shorter bond length
Explanation:
Ethene is a larger molecule than oxygen and nitrogen hence it is more soluble than the both other gases .
SO2 dissolves readily in water to yield an acid solution. It is an acid anhydride.
Nitric oxide is a polar compound. It remains very much polar while nitrogen and oxygen are non polar.
Nitrogen is sp hybrized, this leads to a very short bond and does not easily interact with oxygen and nitrogen
How many moles in 2.33E25 molecules of NO?
0.0258 mol
3.87E20 mol
38.7 mol
2.58E48 mol
please show work
Answer:
0.0258 mol Answer .......
DNA forms two strands. One of the strands of a piece of a DNA molecule has the bases ATA.
Which bases does the other strand have?
Select one:
A: CAC.
B: TAT.
C: GTG.
D: ATA.
Answer:
b
Explanation:
Combinations between two strands:
T - A
A - T
C - G
G - C
(so if one strand has A for example, then the other strand must have T in the same spot)
Bases which are present on the other strand of DNA are TAT.
What is DNA?DNA or deoxyribonucleic acid is a hereditary material present in humans as well as all living beings. Almost every cell present in the body has DNA. Most DNA are located inside the cell , that is in the nucleus of the cell. But a small portion of DNA can be found in the mitochondria of the cell as well.
The information in DNA is stored as a code which is composed of four chemical bases 1) adenine 2)guanine 3) cytosine 4) thymine . The human DNA consists of 3 billion bases . The order of of these bases determine information which is used for building and maintaining an organism.
The DNA bases can pair with each other .Adenine pairs with thymine and guanine with cytosine to form units which are called as base pairs.Each base apart from other complementary base it also attaches itself to a sugar and a phosphate molecule.
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Ethane is a hydrocarbon with a formula of C2H6 . How many Carbon and Hydrogen atoms are contained within 3 molecules of ethane ?
Answer:
Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.
Explanation:
PLS HELP ME WITH THIS ILL GIVE BRAINLIEST
Answer:
1 qualiative physical
2 qualiative chemical
3 quantitative physcial
4 quantiative chemical
5qualiative physcial
6quatiative chemcial
7quanatiative physcial
8 qualiative chemical
9quatliate physcial
forms of energy reflection
Answer:
any of these
Explanation:
kinetic energy: kinetic is motion, or released energy
Potential energy: porential energy is the energy of position or stored energy.
Thermal energy: is heat energy, it is stored energy that creats heat.
59. Which one has 0 dipole moment?
a. H2O2 b. Co2 c. HF
d. HBr
Answer:
the answer to this question is A H202
Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?
Answer:
See explanation
Explanation:
The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of tetraphenylcyclopentadienone and diphenylacetylene are Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.
The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of tetraphenylcyclopentadienone and diphenylacetylene.
Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.
What is the concentration of a Kl solution of 20.68 g of solute was dissolved in enough water to form 100. ml of solution?
Answer:
1.25M
Explanation:
What is the surface composition of planets in the solar system?
A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium
Answer:
A: Helium or Hydrogen
Explanation:
Terrestrial planets are the 4 inner most planets of the solar system which are mercury, venus, earth, Mars, while the giant planets are the 4 outer most which are Jupiter, Saturn, Uranus and Neptune.
Now, these outer most ones are the surface ones and are surrounded primarily by layers of hydrogen and helium gases.
Ethical Behavior Worksheet Situation 1. You are taking a very difficult chemistry course, which you must pass to maintain your scholarship and to avoid damaging your application for graduate school. Chemistry is not your strong suit, and, because of a just-below-failing average in the course, you will have to receive a grade of 90 or better on the final exam, which is two days away. A janitor, who is aware of your plight, informs you that he found the master for the chemistry final in a trash barrel and has saved it. He will make it available to you for a price, which is high but which you could afford. What would you do?
Answer:
I would not accept it.
Explanation:
Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.
Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
Answer:
65.0cp
Explanation:
Is energy absorbed or released during cellular respiration?
Absorbed
Released
Answer:
Released
Explanation:
they convert into a form of energy that can be used by cells
What is the molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution?
Answer:
0.389 M
Explanation:
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 g
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5 g
Number of mole of CuCl₂ =?
Mole = mass / Molar mass
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Number of mole of CuCl₂ = 0.584 mole
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389 M
The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
HOW TO CALCULATE MOLARITY?The molarity of a solution can be calculated
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 gVolume of solution = 1.50 LMolarity of CuCl₂ =?Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5g
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 moles
The determine the molarity of the solution. This can be obtained as follow:
Number of moles of CuCl₂ = 0.584 molesVolume of solution = 1.50LMolarity of CuCl₂ =?Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389M
Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
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What a main difference between Earth and Jupiter?
A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
B. Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.
C. Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.
D. Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.
Answer: A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
Answer: What a main difference between Earth and Jupiter?
Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.
Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.
Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.
Explanation:
Rank the following compounds in order of increasing stability, putting the least stable first. Group of answer choices II < I < III I < II < III III < II < I III < I < II
Hello. You forgot and show the compounds. The compounds are in the attached image.
Answer:
I < II < III
Explanation:
The stability of the presented compounds must be analyzed, taking into account the free electrons to form arrangements between the atoms. In this case, the molecules of greater stability follow the concept of valence and are characterized as those that manage to reach a large number of elements that manage to obey the octet rule.
What is the major organic product obtained from the reaction of 2,2-dimethyl-1-propanol aqueous HBr at reflux
Answer:
See explanation
Explanation:
The mechanism involves SN1 nucleophilic substitution reaction. The -OH group of the alcohol is first protonated. Since water is a good leaving group, -OH2 leaves the substrate creating a primary carbo cation.
A 1,2 methyl shift now occurs to create a tertiary carbo cation which is more stable leading to the major product shown in the image attached to this answer.
What is the surface composition of planets in the solar system?
A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium
Answer:
B
Explanation:
Most planets in the solar system don't have water. Helium and hydrogen are two of the many gasses in planets. Therefore, B is the best answer.
Using the van der Waals equation, determine the pressure exerted by 4.30 mol Ar in 3.6 L at 325K.
Answer:
37.7 atm
Explanation:
Using the relation;
(P + an^2/V^2) (V - nb) = nRT
(P + an^2/V^2) = nRT/(V - nb)
a = 0.0341 atm dm^2 Mol^2
b = 0.0237 dm/mol
P = nRT/(V - nb) - an^2/V^2
P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)
P = 114.595/(3.498) - 0.0487
P = 37.7 atm
What is the electrostatic potential energy (Eel) of the ionic bond between a Ca2+ ion and a S2– ion in joules? Before you do the calculation, predict whether the result you get will be less than (more negative) or greater than (less negative) than the Eel value for KCl. The ionic radii of Ca2+ and of S2– are 100 pm and 184 pm, respectively.
Answer: the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Explanation:
Given the data in the question;
I think the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has more charge that is +2 and -2 respectively when compared to Kcl which has +1 and -1 charge.so it will be more negative.
radius = r[tex]_{ca+2}[/tex] + r[tex]_{s-2}[/tex] = 100 + 184 = 284 pm = 2.84 × 10⁻¹⁰ m
we know that; k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
so
Ep = k × q1q2/r
so we substitute
Ep = 2.31 × 10⁻²⁸ × (+2×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Based on the data provided, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
What is electrostatic potential energy?The electrostatic potential energy is the work done in moving the charge from infinity to that point against the electric field.
The electrostatic potential energy between any two charges q1, q2 separated by distance r is derived from Coulomb’s law and mathematically given as:
E = k × [q1q2/r2]where
k is a constant = 2.31 × 10⁻²⁸ Jq1 and q2 are the chargesr is the distance of separationFrom the data provided:
ionic radii of Ca2+ r1 = 100 pm
ionic radii of S2– = 184 pm.
Chargeon Ca2+ = +2
Charge on S2_ = -2
From the data above, it most likely that the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has a greater charge of +2 and -2 respectively compared to Kcl which has +1 and -1 charge.
Calculating the electrostatic potential energy, Ep:
radius = r1 + r2 = 100 + 184 = 284 pm
r = 2.84 × 10⁻¹⁰ m
k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
Then:
Ep = k × q1q2/r
Substituting the values above in the equation:
Ep = 2.31 × 10⁻²⁸ × (+2 ×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J.
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8. Label the type and parts of the waves shown here.
longitudinal wave
WORD BANK
engitudinal wave
• transverse wave
compression
• rarefaction
crest
trough
Houghton Mifflin Harcourt
The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of an unknown solution:
a. The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
b. The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
c. The equation from the calibration curve can only be linear.
d. Domain and range restrictions must be observed.
Answer:
The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
Domain and range restrictions must be observed.
Explanation:
Calibration curves are tools necessary in understanding the instrumental response for any analyte.
A calibration curve is obtained by preparing a set of standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.
The equation of the best-fit line is used to determine the concentration of the unknown sample.
Consider the reaction 2H2(g)+O2(g)→2H2O(l) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) What is the mass of water, H2O(l) H 2 O ( l ) , produced when 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?hen 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?
Answer:
mH₂O = 6.4116 g
Explanation:
Let's write the given reaction:
2H₂ + O₂ -------> 2H₂O
The problem states that 5.7 g of oxygen reacts with excess hydrogen, hence, the limiting reagent is the oxygen. With this mass of oxygen, we can determine the moles, and then, the moles of water with the mole ratio:
moles = mass / atomic weight AW of O₂ = 16 g/mol
Replacing we have:
moles O₂ = 5.70 / (16 * 2)
moles O₂ = 0.1781 moles
According to the balanced reaction, 1 mole of Oxygen produces 2 moles of water, so we have a mole ratio 1:2, therefore the moles of water would be twice the moles of oxygen:
moles H₂O = 0.1781 * 2 = 0.3562 moles
Finally the mass of water can be calculated solving for the mass from the expression of moles, and using molecular mass of water:
m = moles * MM MM H₂O = 18 g/mol
m = 0.3562 * 18
mH₂O = 6.4116 gHope this helps
How many moles are there in 2.30 x 1024 atoms of silver?
Answer:
Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).
Step 1
Use dimensional analysis to convert the number of atoms to moles.
1 mole atoms = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag
Step 2
Convert the moles of Ag to mass.
mass (m) = moles (n) × molar mass (M)
n(Ag) = 3.8193 mol Ag
M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag
m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures
The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.
Explanation:
The number of moles that are present is 2.3 × 10²⁴ atoms of silver are 3.8193 moles that can be determined using Avogadro's law.
The calculation for number of moles:One mole:
A mole is defined as 6.022 × 10²³ of some chemical unit, be it atoms, molecules, ions, or others.
1 mole = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms)
n(Ag) = 3.8193 mol Ag
Thus, the number of moles is 3.8193 moles.
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A) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
B) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
C) Calculate the percent by mass of a solution made from 15 g NaCl (the solute) and 69 g water.
D) What percent of 73.0 g is 26.1 g?
Answer:
A-B) 94 %.
C) 17.9 %.
D) 35.8 %.
Explanation:
Hello!
A-B) In this case, since the total mass of the mixture is 3.02 g and 1.43g+1.41g=2.84 g are recovered in total, we can compute the percent recovery as shown below:
[tex]\%rec=\frac{2.84g}{3.02g}*100\%\\\\\%rec=94\%[/tex]
C) Here, since the solution is made up of NaCl and water, we can say that the mass of the solution is 15g+69g=84g; thus, the percent by mass would be:
[tex]\%=\frac{15g}{84g}*100\%\\\\\%=17.9\%[/tex]
D) In this case, we simply divide 26.1 g by 73.0 g in order to obtain the percent:
[tex]\%=\frac{26.1g}{73.0g}*100\%\\\\\%=35.8\%[/tex]
Best regards!
The percentage in the cases are as follows;
A and B is; 94%C is; 17.9%D is; 35.8%Questions A and B are similar and can be solved as follows;
The total mass of the mixture is 3.02g.The recovered mass = 1.43g + 1.41g = 2.84g% recovery = (2.84/3.02) × 100%% recovery = 94%Question C can be solved as follows;
Total mass of solution = 15 + 69 = 84gMass of solute = 15g% by mass = (15/84) × 100%% by mass = 17.9%Question D can be solved as follows;
% = (26.1/73) × 100%% = 35.8%Read more:
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