Answer:
False
Explanation:
In the question it is given that a proton travels in the right moves in between the two plates. An electric field that is pointing in the vertically upward direction has magnitude of 3 N/C. The electric field is produced by the plates.
Now from here we can conclude that the direction of the force acting on the proton when the proton is in between the plates acts in the downward direction. While the electric field lines points in the upward direction. Thus the electric point will not be in the direction of the force that acts on the proton.
A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.
Answer:
Acceleration = 3m/s^2
Vf= 0 Vi =35m/s t= 13s
Explanation:
[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]
Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most likely do?
He reduced the number of loops in the wire.
He increased the number of loops in the wire.
He reduced the length of the wire.
He increased the length of the wire.
Answer:
Its A
Explanation:
To reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
What is electromagnetic field strength?
The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.
The strength of an induced emf in a given magnetic field is given by;
emf = NBA/t
where;
N is number of turns of the magnetB is magnetic field strengthA is area of the coilDecrease in number of turns of the wire, reduces the strength of the magnetic field.
Thus, to reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
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4. When energy is transformed from one form to another, what kind of energy is
always part of the transformation ? (and is usually not in a useful form)
Biomechanical Energy
O Heat Energy
Nuclear Energy
Answer:
Energy conversion also termed as the energy transformation, is the process of changing one form of energy into another.
The Law of Energy Conversion.
Scenario Energy conversions involved
In steam engine The heat energy to Mechanical Energy
In Electric heater Electric Energy to Heat
During the transformation of energy from one form to another, the kind of energy that is always part of the transformation is: C. Heat energy.
What is energy?
Energy can be defined as the ability (capacity) to do work. Thus, the standard unit of measurement of energy is Joules (J).
The various kind of energy:
Basically, there are different kind of energy and these include:
Biomechanical energyWave energySound energyNuclear energyHeat energyThe Law of Conservation of Energy:
According to the Law of Conservation of Energy, energy can neither be created nor destroyed but it can only be transformed (converted) from one form to another such as potential energy to kinetic energy.
As a general rule, heat energy is always associated with the transformation of energy from one form to another.
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How much air resistance acts on a 100-N bag of nails that falls at its terminal speed?
What results when energy is transformed while juggling three bowling pins?
Answer:
his is an example of the transformation of gravitational potential energy into kinetic energy
Explanation:
The game of juggling bowling is a clear example of the conservation of mechanical energy,
when the bolus is in the upper part of the path mechanical energy is potential energy; As this energy descends, it becomes kinetic energy where the lowest part of the trajectory, just before touching the hand, is totally kinetic.
At the moment of touching the hand, a relationship is applied that reverses the value of the speed, that is, now it is ascending and the cycle repeats.
Therefore this is an example of the transformation of gravitational potential energy into kinetic energy
A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What
is the speed of recoil of the gun?
Answer: -.80m/s
Explanation:
A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y= -1.0 m. Point A is on the y axis at y= +4.0 m. Determine the electric potential at point A (relative to zero at the origin).
Answer:
The potential is [tex]V_A = 9600 \ V[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]
The position of the charge is [tex]x = + 3.0 \ m[/tex]
The magnitude of the second charge is [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]
The position is [tex]y_1 = - 1.0 \ m[/tex]
The position of point A is [tex]y_2 = + 4.0 \ m[/tex]
Generally the electric potential at A due to the first charge is mathematically represented as
[tex]V_a = \frac{k * q_1 }{r_1 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_1[/tex] is the distance between first charge and a which is mathematically represented as
[tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]
=> [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]
=> [tex]r_1 = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]
[tex]V_a = 7200 \ V[/tex]
Generally the electric potential at A due to the second charge is mathematically represented as
[tex]V_b = \frac{k * q_2 }{r_2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_2[/tex] is the distance between second charge and a which is mathematically represented as
[tex]r_2 = y_2 - y[/tex]
=> [tex]r _2 = 4.0 - (-1.0)[/tex]
=> [tex]r = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]
[tex]V_a = -3600 \ V[/tex]
So the net potential difference at point A due to the charges is mathematically represented as
[tex]V_n = V_a + V_b[/tex]
=> [tex]V_n = 7200 - 3600[/tex]
=> [tex]V_n = 3600 V[/tex]
Generally the net potential difference at the origin due to both charges is mathematically represented as
[tex]V_N = V_c + V_d[/tex]
Here
[tex]V_c = \frac{k * q_1 }{x}[/tex]
=> [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]
=> [tex]V_c = 12000 V[/tex]
and
[tex]V_d= \frac{k * q_2 }{y}[/tex]
=> [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]
=> [tex]V_c =- 18000 V[/tex]
Generally the net potential difference at the origin is
[tex]V_N = 12000 - 18000[/tex]
=> [tex]V_N = -6000[/tex]
Generally the potential difference at A relative to zero at the origin is mathematically evaluated as
[tex]V_A = V_n - V_N[/tex]
=> [tex]V_A = 3600 - (-6000)[/tex]
=> [tex]V_A = 9600 \ V[/tex]
A scientist is observing a eukarotic cell and a prokaryotic cell. Which structure could she only observe in the eukaryotic cell?
cytoplasm
DNA
ribosomes
a nucleus
Answer:
It's definitely Nucleus
Hope this Helps!
gold has a density of 19300 kg/m3 calculate the mass of 0.02m3 of gold in kilograms
Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.
What is density?Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.
Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.
Mass of an object is the product of its volume and density.
Given the volume of gold = 0.02 m³
density = 19300 kg/m³.
mass = volume × density
= 0.02 m³ × 19300 kg/m³
= 386 kg
Therefore, the mass of gold is 386 Kg.
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A standing wave has a frequency of 471 Hz and a wavelength of 1.9. What is the speed of the
wave? (Round to the 2nd number after the decimal)
1
I REALLY NEED HELP !
Answer:
c = 894.90 m/s
Explanation:
Given data:
Frequency of wave = 471 Hz
Wavelength of wave = 1.9 m
Speed of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
c = f×λ
c = 471 Hz × 1.9 m
Hz = s⁻¹
c = 471s⁻¹ × 1.9 m
c = 894.90 m/s
The speed of wave is 894.90 m/s.
True or False: A cloud’s only purpose is to create precipitation.
Answer:
I think it's false
Explanation:
clouds also help regulate the Earth's energy balance by reflecting and scattering solar radiation and by absorbing the Earth's infrared radiation.
Answer:
false
Explanation:
A cat rolls up a hill. It’s initial Velocity is 10 m/s.n It’s final velocity is 0 m/s. The time was five seconds. Calculate Acceleration
Answer:
[tex]\boxed {\boxed {\sf a= -2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The final velocity of the cat was 0 meters per second and the initial velocity was 10 meters per second. The time was 5 seconds.
[tex]v_f=0 \ m/s\\v_i=10 \ m/s\\t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-10 \ m/s}{5 \ s}[/tex]
Solve the numerator.
0 m/s-10 m/s= -10 m/s[tex]a=\frac{-10 \ m/s}{5 \ s}[/tex]
Divide.
[tex]a= -2 \ m/s^2[/tex]
The acceleration of the cat was -2 m/s². The negative acceleration indicates slowing down or stopping.
In order to determine the wavelength, you must know the distance from the (2 points)
Select one:
a. trough of one wave to the crest of the next wave
b. midpoint of a wave to the highest point of the next wave
c. crest of the wave to the equilibrium of the same wave
d. the crest of one wave to the crest of the next wave
Answer:
b
Explanation:
Answer:
a
Explanation:
because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur
HELPP ITS DUE IN 5 MINUTES FREE BODY DIAGRAMS
Answer:
I think it's part c . but sorry if its wrong
A pyrotechnical expert needs to fire a 15 kg projectile from a launching device that has a barrel length of 2 meters. The projectile will need to be launched horizontally 1 km in 5 seconds. Calculate the force needed to launch the projectile.
Answer:
The force needed to launch the projectile is 150000 N.
Explanation:
We can find the force using the following equation:
[tex] F = ma [/tex]
Where:
m: is the mass = 15 kg
a: is the acceleration
First, we need to find the acceleration of the projectile:
[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]
Where:
[tex]v_{f}[/tex]: is the final speed
[tex]v_{0}[/tex]: is the initial speed = 0
x: is the distance = 2 m
The final speed is:
[tex]v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s[/tex]
Then, the acceleration is:
[tex]a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}[/tex]
Finally, the force is:
[tex]F = ma = 15 kg*10000 m/s^{2} = 150000 N[/tex]
Therefore, the force needed to launch the projectile is 150000 N.
I hope it helps you!
What is Newtons third law of motion?
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction
Explanation:
In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.
How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.
Answer:
t = 3.35 s
Explanation:
It is given that,
Mass of a pumpkin, m = 8 kg
It is dropped from a height of 55 m
We need to find the time taken by it to hit the ground.
Initial velocity of the pumpkin, u = 0
Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s[/tex]
So, it will take 3.35 seconds to hit the ground.
-)
A 1100 kg car is accelerating at 2m/s2. Find the net force acting on the car.
Answer:
2200 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1100 × 2
We have the final answer as
2200 NHope this helps you
Numa determinada escala X, arbitrária, um termômetro marca 0°X para o ponto de fusão do gelo e 50°X para o ponto de ebulição da água, ao nível do mar. Que temperatura esse termômetro marcaria se fosse mergulhado em um líquido cuja temperatura é de 50°C?
Answer:
the temperature measured by the thermometer is 25 ° X
Explanation:
The computation of the temperature measured by the thermometer is shown below:
Here is the thermometric scale list
(X - 0) ÷ C - 0 = (50 - 0) ÷ (100 - 0)
X ÷ C = 50 ÷100
X = C ÷ 2
Now if there is 50 degrees celcius
So, the x would be
= 50 ÷ 2
= 25 ° X
Hence, the temperature measured by the thermometer is 25 ° X
The same is to be considere d
Why is an important to come up with a plan for how are you to respond to negative peer pressure before the situation happens
A: it is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future
C: both a and b
Answer:
C ( is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future)
A boat starts moving across a river at velocity v perpendicular to the river bank.
The boat encounters a current along the river of velocity u, as shown.
u
river
Which vector diagram shows the resultant velocity r of the boat?
A
B
с
D
u
A
r
u
A 1500 kg car is parked at the top of a hill 5.2 m high. What is the velocity of the car, in meters per second, when it reaches the bottom of the hill?
Answer:
Explanation:
The car will fall with acceleration due to gravity which is equal to 9.8 m /s²
For downward fall ,
initial velocity u = o
acceleration due to gravity = g = 9.8 m /s
final velocity v = ?
displacement h = 5.2 m
v² = u² + 2 gh
v² = 0 + 2 x 9.8 x 5.2
= 101.92
v = 10.1 m /s
Una larga fanja de pavimento tiene marcas a intervalos de 10m. Los estudiantes usan cronometros para registrar los tiempos en que un automovil pasa por cada marca. Asi han obtenido los datos siguientes: Distancia,m l 0 l 10 l 20 l 30 l 40 l 50 l Tiempo,s l 0 l 2.1 l 4.2 l 6.3 l 8.4 l 10.5 l A) Cual es la rapidez media del vehiculo? B) Al cabo de cuanto tiempo la distancia es igual a 34m? C) Cual es la aceleracion del automovil?
Answer:
men
Explanation:
____________ is an out made when a base runner, forced to run because another teammate must run to the base being occupied, cannot reach the next base safely *
Answer the following questions
Answer:
9 - 10N to the left
10 - There is no change on the object
Explanation:
Can I have brainliest answer pls?
Question 7 (2 points)
Rachel performed an experiment testing the hours students slept with their
performance on a test. In this experiment, the hours that they slept was the_____ variable, while the grade they got on
the test was the
_____ variable.
Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?
Explanation:
0.10kg
0.5kg×0.2kg=
0.10
A car slows down from 65 km/s to 30 km/s in 5 seconds. What is its acceleration?
A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and the ball continues forward at 4.0 m/s. What was the original velocity of the ball?
The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.
We don't have external forces, so:
[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]
Where:
mb is the mass of the bowling ball mp the mass of the pin[tex]v_{0b}\quad and\quad v_{0p}[/tex] the initial velocities of the bowling ball and the pin.[tex]v_{1b}\quad and\quad v_{1p}[/tex] the final velocities of the bowling ball and the pin.Solving for v0b:
[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]
R/ The original velocity of the ball was 5.71 m/s.The original velocity of the ball is 5.71 m/s.
The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.
From the principle of conservation of momentum,
MU+mu = MV+mv.................... Equation 1
Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.
From the question,
Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.
Substitute these values into equation 1 and solve for U
7(U)+2(0) = 7(4)+2(6)
7U = 28+12
7U = 40
U = 40/7
U = 5.71 m/s.
Hence, The original velocity of the ball is 5.71 m/s.
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A 62Kg rock climber is attached to a rope that is allowing him to hang horizontally with his feet against the wall. The tension of the rope is 7.1x10^2 N, and the rope makes an angle of 32 degrees with the horizontal. Determine the force exerted by the wall on the climber's feet? I need some help with understanding the problem through a FBD as well as how I will find the x and y components. Thank You !
Answer:
R= 602 .11 N
Explanation:
The horizontal component of tension T will give reaction of the wall and the vertical component of T will balance the weight of of the climber .
T cos32 = R
710 x .848 = R
R= 602 .11 N .