Answer:
The solution is too long. So, I included them in the explanation
Step-by-step explanation:
This question has missing details. However, I've corrected each question before solving them
Required: Determine the inverse
1:
[tex]f(x) = 25x - 18[/tex]
Replace f(x) with y
[tex]y = 25x - 18[/tex]
Swap y & x
[tex]x = 25y - 18[/tex]
[tex]x + 18 = 25y - 18 + 18[/tex]
[tex]x + 18 = 25y[/tex]
Divide through by 25
[tex]\frac{x + 18}{25} = y[/tex]
[tex]y = \frac{x + 18}{25}[/tex]
Replace y with f'(x)
[tex]f'(x) = \frac{x + 18}{25}[/tex]
2. [tex]g(x) = \frac{12x - 1}{7}[/tex]
Replace g(x) with y
[tex]y = \frac{12x - 1}{7}[/tex]
Swap y & x
[tex]x = \frac{12y - 1}{7}[/tex]
[tex]7x = 12y - 1[/tex]
Add 1 to both sides
[tex]7x +1 = 12y - 1 + 1[/tex]
[tex]7x +1 = 12y[/tex]
Make y the subject
[tex]y = \frac{7x + 1}{12}[/tex]
[tex]g'(x) = \frac{7x + 1}{12}[/tex]
3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]
Replace h(x) with y
[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]
Swap y & x
[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]
Add [tex]\frac{1}{3}[/tex] to both sides
[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]
[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]
Multiply through by -4
[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]
[tex]-4x - \frac{4}{3}= 9y[/tex]
Divide through by 9
[tex](-4x - \frac{4}{3})/9= y[/tex]
[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]
[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]
[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]
[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]
4:
[tex]f(x) = x^9[/tex]
Replace f(x) with y
[tex]y = x^9[/tex]
Swap y with x
[tex]x = y^9[/tex]
Take 9th root
[tex]x^{\frac{1}{9}} = y[/tex]
[tex]y = x^{\frac{1}{9}}[/tex]
Replace y with f'(x)
[tex]f'(x) = x^{\frac{1}{9}}[/tex]
5:
[tex]f(a) = a^3 + 8[/tex]
Replace f(a) with y
[tex]y = a^3 + 8[/tex]
Swap a with y
[tex]a = y^3 + 8[/tex]
Subtract 8
[tex]a - 8 = y^3 + 8 - 8[/tex]
[tex]a - 8 = y^3[/tex]
Take cube root
[tex]\sqrt[3]{a-8} = y[/tex]
[tex]y = \sqrt[3]{a-8}[/tex]
Replace y with f'(a)
[tex]f'(a) = \sqrt[3]{a-8}[/tex]
6:
[tex]g(a) = a^2 + 8a- 7[/tex]
Replace g(a) with y
[tex]y = a^2 + 8a - 7[/tex]
Swap positions of y and a
[tex]a = y^2 + 8y - 7[/tex]
[tex]y^2 + 8y - 7 - a = 0[/tex]
Solve using quadratic formula:
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes
[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]
[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]
Factorize
[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]
[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]
[tex]y = -4 \±\sqrt{(23 + a)}[/tex]
[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]
7:
[tex]f(b) = (b + 6)(b - 2)[/tex]
Replace f(b) with y
[tex]y = (b + 6)(b - 2)[/tex]
Swap y and b
[tex]b = (y + 6)(y - 2)[/tex]
Open Brackets
[tex]b = y^2 + 6y - 2y - 12[/tex]
[tex]b = y^2 + 4y - 12[/tex]
[tex]y^2 + 4y - 12 - b = 0[/tex]
Solve using quadratic formula:
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]
[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes
[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]
[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]
Factorize:
[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]
[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]
[tex]y = -2\±\sqrt{16+b}[/tex]
Replace y with f'(b)
[tex]f'(b) = -2\±\sqrt{16+b}[/tex]
8:
[tex]h(x) = \frac{2x+17}{3x+1}[/tex]
Replace h(x) with y
[tex]y = \frac{2x+17}{3x+1}[/tex]
Swap x and y
[tex]x = \frac{2y+17}{3y+1}[/tex]
Cross Multiply
[tex](3y + 1)x = 2y + 17[/tex]
[tex]3yx + x = 2y + 17[/tex]
Subtract x from both sides:
[tex]3yx + x -x= 2y + 17-x[/tex]
[tex]3yx = 2y + 17-x[/tex]
Subtract 2y from both sides
[tex]3yx-2y =17-x[/tex]
Factorize:
[tex]y(3x-2) =17-x[/tex]
Make y the subject
[tex]y = \frac{17 - x}{3x - 2}[/tex]
Replace y with h'(x)
[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]
9:
[tex]h(c) = \sqrt{2c + 2}[/tex]
Replace h(c) with y
[tex]y = \sqrt{2c + 2}[/tex]
Swap positions of y and c
[tex]c = \sqrt{2y + 2}[/tex]
Square both sides
[tex]c^2 = 2y + 2[/tex]
Subtract 2 from both sides
[tex]c^2 - 2= 2y[/tex]
Make y the subject
[tex]y = \frac{c^2 - 2}{2}[/tex]
[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]
10:
[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]
Replace f(x) with y
[tex]y = \frac{x + 10}{9x - 1}[/tex]
Swap positions of x and y
[tex]x = \frac{y + 10}{9y - 1}[/tex]
Cross Multiply
[tex]x(9y - 1) = y + 10[/tex]
[tex]9xy - x = y + 10[/tex]
Subtract y from both sides
[tex]9xy - y - x = y - y+ 10[/tex]
[tex]9xy - y - x = 10[/tex]
Add x to both sides
[tex]9xy - y - x + x= 10 + x[/tex]
[tex]9xy - y = 10 + x[/tex]
Factorize
[tex]y(9x - 1) = 10 + x[/tex]
Make y the subject
[tex]y = \frac{10 + x}{9x - 1}[/tex]
Replace y with f'(x)
[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]
(3x2)(−2x4) = 3(−2)x2∙4 = 6x8
Could you please find out what's wrong and say what should be there instead? The problem is : (3x to the power of 2 ) (-2x to the power of 4) = 3(-2)x to the power of 2.4 = 6x to the power of 8
Answer:
The correct answer is -6x⁶
Step-by-step explanation:
Given that:
[tex]3x^2 ( - 2x^4 ) \\ \\ =3(-2)x^{2.4} \\ \\ = 6x^8[/tex]
From the second step above, using the law of indices the correct format should be
[tex]= (3\times -2)x^{2+4}[/tex]
So, the problem lies where we have 2.4, it is not supposed to be (2*4). It supposed to be 2+4 because the law of indices states that we multiply the index together and add their power.
Then the result of that yields
= -6x⁶
In the third step, they also omit the negative sign, when multiplying (3 * -2).
Thus, the correct answer is -6x⁶
What is the value 6^-8/6^-5?
Answer:
0.00462962962
Step-by-step explanation:
Drag the tiles to the correct boxes to complete the pairs. Match each population trend to a contributing factor. government-sponsored family control programs agricultural economies medical advancements Industrial Revolution high birthrate arrowRight low death rate arrowRight increase in food supply arrowRight low birthrate arrowRight Reset Next
Answer:
Matching the population trend to a contributing factor:
Contributing Factors Population Trends
government-sponsored family control programs Low birth rate
agricultural economies increase in food supply
medical advancements low death rate
Industrial Revolution high birth rate
Step-by-step explanation:
a) Contributing factors are some negative or positive factors that influence or cause a single event or chain of events that result to the incident.
b) Defining population trends:
1) High birth rate: the industrial revolution triggered high birth rate, following increased food supply and medical advancements.
2) Low death rate: medical advancements brought about low death rate as better healthcare is provided to the sick.
3) Increase in food supply: large-scale agricultural economies ensured increasing food production and supply.
4) Low birth rate: when governments started sponsoring family control programs, the resulting effect was low birth rate.
Answer:
The first one is children and adolescents
the second one is adults
the third one is pregnancy
the last one is indivisuals with brittle bones
Step-by-step explanation:
hope this helps :D
-7[-8-4a]=25+a
A. a= -16
B. a=-5
C. a= -11
D. a=-3
Answer:
-1.48148148
Step-by-step explanation:
-7 x -8 = 56
-7 x -4a = 28a
25-56=-31
27a/-31
a=-1.48148148
A 2-column table with 3 rows. Column 1 is labeled Days, x with entries 3, 4, 5. Column 2 is labeled Miles, y with entries 771, 973, 1,175.
The Boden family is taking a road trip across the US. After initially driving for awhile, the Bodens decide to make a plan to drive a set number of miles each day. Days 3, 4, and 5 are displayed in the table. Assume the relationship is linear.
Identify how many miles per day the Boden family is planning to travel.
miles per day
Answer:
202 miles per day
Step-by-step explanation:
Answer:
165
Step-by-step explanation:
A 2-column table with 3 rows. Column 1 is labeled Days, x with entries 3, 4, 5. Column 2 is labeled Miles, y with entries 771, 973, 1,175.
The Bodens drove for awhile before they made a plan to drive a set number of miles each day. Days 3, 4, and 5 are displayed in the table. Assume the relationship is linear.
Determine the initial number of miles that the Boden family drove before they made their plan.
771 miles
367 miles
165 miles
135 miles
This is your correct answer 165, oops this is the wrong question sorry
Need help !!!! I would make you 100 edits if you answer this for me ! I need some help on this !! It’s due in a few minutes!! Help me !!
Answer:
6A7C8B
Step-by-step explanation:
Add them in and try to solve for 7 and 6, for 8. I usually put all number on one side and all x on other side.
What is the rectangular form of r=8sin(0)
Step-by-step explanation:
the regular form of r=8
please solve this for be before 7pm EDT
Answer for #5:
7 friends
Step-by-step explanation:
convert fraction into 4ths:
1/4, 2/4, 3/4, 1/4
add together:
7/4ths
if each friend ate 1/4 of the pizzas, then there are 7 friends
I will mark brainly if anyone can answer this
-2-4(6p-5)
-5(v-6)+10v
and 25 pts
Answer:
Ich weiß nicht =13
die Antwort -2 -4 (6p-5)
Step-by-step explanation:
the time, t, in seconds, is required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given this equation
Answer:
C. [tex] d = \frac{at^2}{2} [/tex]
Step-by-step explanation:
Given:
[tex] t = \sqrt{\frac{2d}{a}} [/tex]
Required:
Make d the subject of the formula.
SOLUTION:
[tex] t = \sqrt{\frac{2d}{a}} [/tex]
Square both sides
[tex] t^2 = (\sqrt{\frac{2d}{a}})^2 [/tex]
[tex] t^2 = \frac{2d}{a} [/tex]
Multiply both sides by a
[tex] a*t^2 = \frac{2d}{a}*a [/tex]
[tex] at^2 = 2d [/tex]
Divide both sides by 2
[tex] \frac{at^2}{2} = \frac{2d}{2} [/tex]
[tex] \frac{at^2}{2} = d [/tex]
[tex] d = \frac{at^2}{2} [/tex]
HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!
Answer:
the first questions answer is yes the seconds is no
HAVE A NICE DAY!!!
If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?
(0, 1)
(1, 1)
(2, 1)
Answer:
(1,1)
Step-by-step explanation:
Please Help
Please let me know how to do it, I don't only want the answer. Thank you!
(4y+3)-(y-2)
(There is no equal sign in the math problem)
A small pool is being drained. There are 1,320 gallons of water remaining in the pool after 2 minutes and 1, 040 gallons after 9
minutes. How long would it take for the pool to be completely drained? (1 point)
Answer: 35 minutes
Step-by-step explanation:
For us to solve the question, we have to calculate the amount of gallons of water that is drained every minute. This will be:
= (1320 - 1040) / (9 - 2)
= 280/7
= 40 gallons per minute
Since we are told that 1,320 gallons of water remain in the pool after 2 minutes. This means that the total water in the pool at the beginning was:
= 1320 gallons + (40 × 2)
= 1320 gallons + 80 gallons
= 1400 gallons
The time taken for the pool to be completely drained will be:
= Total water in pool / Gallons drained per minute
= 1400 / 40
= 35 minutes
z = 24a - 2b
solve for a
Answer:
a= (Z + 2b)/24
Step-by-step explanation:
given:
Z = 24a - 2b
to solve for a, we will try to move "a" to one side of the equation and all other terms to the other side:
Z = 24a - 2b (add 2b to both sides)
Z + 2b = 24a -2b +2b
Z + 2b = 24a (switch sides)
24a = Z + 2b (divide both sides by 24)
a/24 = (Z + 2b)/24
a= (Z + 2b)/24
1. Dilate A using P as the center of dilation and a scale factor of 3. Label the new point
A'.
2. Dilate Busing Pas the center of dilation and a scale factor of 2. Label the new point B'
Answer:
Step-by-step explanation:
Rule for the dilation of a point by a scale factor 'k',
(x, y) → (kx, ky)
If we impose this rule in this problem,
k = [tex]\frac{\text{Distance of A' from P}}{\text{Distance of A from P}}[/tex]
1). If k = 3
Therefore, Distance of A' from P = 3(Distance of A from P)
And point A' will be on the third circle.
2). If k = 2
Distance of B' from P = 2(Distance of B from P)
Since, B is on circle 2, B' will be on circle 4.
Now we can plot these points A' and B' on the graph.
After the dilation point A becomes A' and it is at a distance of 3 units from point P and after the dilation point B becomes B' and it is at a distance of 2 units from point P.
1)
Given :
Dilate A using P as the center of dilation and a scale factor of 3.
Let the coordinates of point A be (x,y) then after dilation point A becomes A'(3x , 3y). So, the distance of the point A' from the point P is 3 units
2)
Given :
Dilate Busing P as the center of dilation and a scale factor of 2.
Let the coordinates of point B be (x',y') then after dilation point B becomes B'(2x' , 2y'). So, the distance of the point B' from the point P is 2 units
For more information, refer to the link given below:
https://brainly.com/question/2856466
what is 4.25% as a decimal
Answer:
0.0425
Step-by-step explanation:
Answer:
0.0425
Step-by-step explanation:
hope this helped ^^
9x-7= -7
solve for x
Answer:
-2
Step-by-step explanation:
32a + 28 = 0
(Factor completely.)
Answer: 0.875
Step-by-step explanation:
what is 55 - 11u =55
A basketball team played six games. In those games, the team won by 7 points, lost by 20, won by 8, won by 11, lost by 3, and won by 9. What is the mean amount by which the team won or lost over the six games?
Answer:
the mean of which the team won is 8.75
The mean of which the team lost is 11.5
Step-by-step explanation:
add all the numbers of which the team won by then divide the sum by the number of numbers there are
example:
7+8+11+9=35/4=8.75
what is 9 time 64 what does it equal to
Answer:
It's 576 if you mean 64 times 9!
Step-by-step explanation:
Solve for r: 7r+ 30 = -65
Answer:
R= - 95/7
Step-by-step explanation:
Two numbers multiply to -24 and add up to -5
Answer:
-8 and 3
Step-by-step explanation:
The asked numbers are -8 and 3.
What are equations?An equation is a mathematical statement that shows that two mathematical expressions are equal.
For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.
Given that, two numbers multiply to -24 and add up to -5
Let the two numbers be x and y
x+y = -5...(i)
xy = -24
x = -24/y...(ii)
Put eq (ii) in eq (i)
-24/y + y = -5
-24 + y² = -5y
y²+5y-24 = 0
Factorizing,
y = 8 and 3
Taking y = 3, put it in eq(ii)
x = -24/3
x = -8
Hence, the asked numbers are -8 and 3.
Learn more about equations, click;
https://brainly.com/question/29657988
#SPJ5
A) {(0,1),(1,2),(2,3),(3,4),(1,5)}
B) {(0,0),(1,1),(2,4),(3,9),(4,16)}
C) {(-2,4),(-1,1),(0,0),(2,4),(3,9)}
Which one is a function?
And which is is not Non-function?
PLZ ANSWER PLZ 15 POINTS JUST PLZ
I WILL GIVE THE BRAINLIEST
Jack works after school. each day he earns a set amount, plus an hourly wage. the following table represents a linear function f jack can use to determine to his pay.
hours: 1, 2, 3 | Pay: 18, 28, 38
SLOPE is 10.
Using the slope, find the y-intercept and write the function.
Answer:
The y intercept is (0, 8). The equation of the function is f(x) = 10x + 8
Step-by-step explanation:
Given that after 1 hour of work, Jack will make 18 dollars and the slope is 10, subtract 10 dollars from 18 dollars to find his set amount, or y-intercept.
18 - 10 = 8 dollars.
Now that we have the m and b values, we can create our equation.
The equation in standard form is f(x) = mx +b, where m = the slope and b = the y-intercept. Plug our values in and the equation will be f(x) = 10x + 8. You can test if this is correct by plugging in x values from the table and seeing if your calculated value correctly corresponds to the given y value in the table.
Meteorology A Weather forecaster uses a barometer to measure air pressure and make weather predictions. Suppose a standard mercury barometer reads 29.8 in. The mercury rises 0.02 in. And then false 0.09 in . The mercury falls again 0.18 in. Before rising 0.07 in. What does the word "rise" suggest? What does the word "fall" suggest?
Answer:
rise : atmospheric pressure increases
fall : atmospheric pressure decreases
Step-by-step explanation:
In the context, it is given that a weather forecaster takes the help of the barometer to check the air pressure and predicts the weather. The column of mercury level in the barometer shows a rise or fall in the glass tube as the weight of the atmosphere falling on the mercury surface changes.
Here it is given that the mercury rises for 0.02 in, then it falls 0.09 in, it then rises by 0.07 in and then again falls by 0.18 in. The word "rise" here shows that the weight of the atmosphere is more. In other words, increase in atmospheric pressure increases the level of mercury in the glass tube and the decrease in or "fall" in the mercury level shows the drop in atmospheric pressure.
im bad at math so help ill mark the first person brainliest ty
Answer:
A. -x² + 2x + 8
General Formulas and Concepts:
Algebra I
Combining like termsStep-by-step explanation:
Step 1: Define
f(x) = 2x + 1
g(x) = x² - 7
(f - g)(x) is f(x) - g(x)
Step 2: Solve
Substitute: (f - g)(x) = 2x + 1 - (x² - 7)Distribute -1: (f - g)(x) = 2x + 1 - x² + 7Combine like terms: (f - g)(x) = -x² + 2x + 8Which property should be used next in this solution process?
3x + 2 + 3 = 7(x - 1) – 4
3x + 5 = 7(x - 1) – 4
A. Commutative Property of Addition
B. Identity Property of Multiplication
C. Associative Property of Multiplication
D.
Distributive Property
Answer:
niwebfasfbjsdfb
Step-by-step explanation:
jsdfhsdbfjhadsjbdsfhb
p+1/p=7 then p^3+1/p^3