Answer:
The effective nuclear charge in a cesium atom is greatest in the 1s orbital
Explanation:
Effective nuclear charge (Zeff) is the positive nuclear charge that is experienced by an electron in an atom. It is affected by the shielding effect and penetration of electrons of the atoms.
The shielding effect is the decrease in attraction between an electron and the nucleus in any atom with more than one electron shell. Innermost electrons shield the outermost electrons from the positive charge of the nucleus. The more electron shells there are, the greater the shielding effect experienced by the outermost electrons. and the more electron shielding an electron has, the lower the Zeff value.
Penetration is the ability of an electron to approach the nucleus. The closer the electron is to the nucleus, the higher the penetration. Electrons with higher penetration will shield outer electrons from the nucleus more effectively. The s orbital being closest to the nucleus has the highest penetration while the f orbital has the lowest penetration.
Cesium has an atomic number of 55 as well as nuclear charge of +55. It has 54 electrons in its filled 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s¹ shells and an outermost 6s electron. Based on the explanation above, the effective nuclear charge is greatest in the innermost 1s orbital and least in the outermost 6s orbital.
The electron in a cesium atom experience should be considered as the 1st orbital.
What is an Effective nuclear charge (Zeff)?It is considered to be the positive nuclear charge i.e. experienced via the electron in an atom. It should be impacted via the effect of shielding and the penetration of the electron with respect to the atoms.
The electronic configuration of cesium should be like
[tex]1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^6 6s^1[/tex]
Now
the electron which is in the innermost subshell will experience the highest effective nuclear charge and it should be 1s.
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A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent composition of fluorine
Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
[tex]percent composition element A=\frac{total mass of element A}{mass of compound} *100[/tex]
In this case, the percent composition of fluorine is:
[tex]percent composition of fluorine=\frac{39.6 g}{60.3 g} *100[/tex]
percent composition of fluorine= 65.67%
The percent composition of fluorine is 65.67%
Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
In this case, the percent composition of fluorine is:
percent composition of fluorine= 65.67%
The percent composition of fluorine is 65.67%
What is the electron geometry and molecular geometry of:
A. H2O
B. CH2CL2
C. OPCL3
D. CO3^2-
E. ALCL6^3-
F. SO2
G. PCL5
Answer:
H2O
Electron geometry-tetrahedral
Molecular geometry bent
CH2Cl2
Electron geometry- tetrahedral
Molecular geometry-tetrahedral
OPCL3
Electron geometry- tetrahedral
Molecular geometry- tetrahedral
CO3^2-
Electron geometry- trigonal planar
Molecular geometry- trigonal planar
ALCL6^3-
Electron geometry-octahedral
Molecular geometry- octahedral
SO2
Electron geometry-tetrahedral
Molecular geometry-bent
PCL5
Electron geometry-trigonal bipyramidal
Molecular geometry- trigonal bipyramidal
Explanation:
Water contains four electron domains this corresponds to a tetrahedral electron geometry. How ever, there are two lone pairs in the molecule hence it is bent.
CH2Cl2 is shows a tetrahedral molecular geometry and a tetrahedral electron geometry. This can only be observed from the structure of the compound.
OPCL3 is bonded to four groups making it a tetrahedral molecule. There are non lone pairs on phosphorus so the molecule is not bent.
CO3^2- is bonded to three groups which leads to a trigonal planar geometry.
ALCL6^3- contains six bonding groups which arrange themselves at the corners of a regular octahedron at a bond angle of 90°.
SO2 has four electron domains leading to a tetrahedral electron domain geometry according to valence shell electron pair repulsion theory. However, the lone pairs on the central atom in the molecule leads to a bent molecular geometry.
PCL5 has five electron domains without lone pairs of electrons on its central atom. Hence the molecule possess a trigonal bipyramidal geometry.
The electron geometry and molecular geometry of the molecule are as follows:
A. H₂O: The electron geometry is tetrahedral because it has four electron domains (two bonding pairs and two lone pairs). However, due to the presence of two lone pairs, the molecular geometry is bent or V-shaped.
B. CH2Cl₂: The electron geometry is tetrahedral. However, the molecular geometry is trigonal planar because two of the electron domains are occupied by chlorine atoms, resulting in a bent shape.
C. OPCl₃: The electron geometry is tetrahedral. However, the molecular geometry is trigonal pyramidal because one of the electron domains is occupied by a lone pair on phosphorus.
D. CO3⁻²: The electron geometry is trigonal planar because it has three electron domains (three single bonds). The molecular geometry is also trigonal planar.
E. AlCl6⁻³: The electron geometry is octahedral because it has six electron domains. The molecular geometry is also octahedral.
F. SO₂: The electron geometry is trigonal planar because it has three electron domains (two single bonds and one lone pair). The molecular geometry is bent or V-shaped due to the presence of a lone pair on sulfur.
G. PCl₅: The electron geometry is trigonal bipyramidal because it has five electron domains. The molecular geometry is also trigonal bipyramidal.
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Name MgSo4.7H2O /Cs3PO4.H2O
Answer:
MgSo4.7H2O = Magnesium sulfate
Cs3PO4.H2O = Cesium Phosphate
Hope this helps!
: Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050-L flask at 668 K, how many moles of Cl2(g) will be present at equilibrium
Answer:
The number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
Explanation:
The reaction is:
CO(g) + Cl₂(g) ⇄ COCl₂(g)
The equilibrium constant of the above reaction is:
K = 1.2x10³
To find the moles of Cl₂ present at equilibrium, let's evaluate the reverse reaction:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
The equilibrium constant for the reverse reaction is:
[tex] K_{r} = \frac{1}{1.2 \cdot 10^{3}} = 8.3 \cdot 10^{-4} [/tex]
Now, we need to calculate the concentration of CO and COCl₂:
[tex] C_{CO} = \frac{\eta_{CO}}{V} = \frac{0.3500 moles}{3.050 L} = 0.115 M [/tex]
[tex] C_{COCl_{2}} = \frac{\eta_{COCl_{2}}}{V} = \frac{0.05500 moles}{3.050 L} = 0.018 M [/tex]
Now, from the reaction we have:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
0.018 - x 0.115+x x
The concentration of Cl₂ is:
[tex] K_{r} = \frac{[CO][Cl_{2}]}{[COCl_{2}]} [/tex]
[tex] 8.3 \cdot 10^{-4} = \frac{(0.115 + x)(x)}{0.018 - x} [/tex]
[tex] 8.3 \cdot 10^{-4}*(0.018 - x) - (0.115 + x)(x) = 0 [/tex]
By solving the above equation for x we have:
x = 1.29x10⁻⁴ M = [Cl₂]
Finally, the number of moles of Cl₂ present at equilibrium is:
[tex] \eta_{Cl_{2}} = C_{Cl_{2}}*V = 1.29 \cdot 10^{-4} mol/L*3.050 L = 3.94 \cdot 10^{-4} moles [/tex]
Therefore, the number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
I hope it helps you!
if a 0.15% protein solution and a 0.12% protein solution are separated by a semipermeable membrane, what will happen?
Answer:
Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.
Explanation:
Due to the difference in the concentrations of the two solutions as well as the presence of a semipermeable membrane, a concentration gradient is setup. The 0.15% protein solutions contains more protein molecules than the 0.12% protein solution. Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.
Osmosis is the movement of water molecules across a semipermeable membrane from a region of lower solute concentration or higher concentration of water molecules to a region of higher solute concentration or lower concentration of water molecules until an equilibrium concentration is attained.
This is a passive process and is facilitated by the concentration gradient as well as a presence of a semipermeable membrane which allows only water molecules to move across it but not solute molecules.
The solubility of carbon tetrachloride (CCl4) in water at 25 ∘C is 1.2 g/L. The solubility of chloroform (CHCl3) at the same temperature is 10.1 g/L. Why is chloroform almost 10 times more soluble in water than carbon tetrachloride?
Answer:
I WOULD ANSWER IT VERY SOON
Explanation:
If the reaction starts with a mixture of PCl5, PCl3 and Cl2 at pressures of 0.820 atm, 1.322 atm and 0.911 atm respectively, is the reaction at equilibrium
Answer:
The reaction is not in equilibrium
Explanation:
For the reaction:
PCl₅ ⇄ PCl₃ + Cl₂
Equilibrium constant, Kp, is defined as:
[tex]Kp = \frac{P_{PCl_3}P_{Cl_2}}{P_{PCl_5}} = 0.497[/tex]
When this ratio is = 0.497, the reaction is in equilibrium. Replacing the pressures of the problem, reaction quotient, Q, is:
[tex]Q =\frac{1.322atm*0.911atm}{0.820atm} = 1.469[/tex]
As Q ≠ Kp, the reaction is not in equilibrium
To reach the equilibrium, the reaction will shift to the left producing more reactant and decreasing amount of products.
If a neutral acid donates a proton, the conjugate base will have a charge of _______. - Type both an integer and a sign for your answer.
Answer:
-1
Explanation:
If you donate a proton (positive charge) then the result will leave a negative charge. (a negative and positive charge result In a neutral charge)
The answer is -1
Now if i have an acid such as H2SO4. Recall that the neutral acid is dibasic as you cam see from the formula of the acid, the acid can give out a proton as follows;
[tex]H2SO4 ------> H^+ + HSO4^-[/tex]
We can see that the conjugate base (HSO4-) has a charge of -1 as written in the answer.
The same also happens for a monobasic acid and so on.
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Which of the following atoms would have the longest de Broglie wavelength, if all have the same velocity?
A) Li
B) Na
C) Fe
D) Pb
E) Not possible to tell with given information
Answer:
Li
Explanation:
The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;
λ= h/mv
Where;
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength
The atom that have the longest de Broglie wavelength is ; ( A ) Li
Wave particle duality is a phenomenon by de Broglie. that shows that The wavelength associated with matter waves is related to its mass and velocity .
Wave particle duality is represented as ; λ = h / mv
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
Given that the elements have the same velocity the atom that would have the longest de Broglie wavelength is Li
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What is the shape of a molecule that has 4 atoms bonded to a central atom
and no lone pairs of electrons?
A. Octahedral
B. Cubic
C. Tetrahedral
D. Trigonal-pyramidal
Answer:
C. Tetrahedral
Explanation:
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.
Tetrahedral is the shape of a molecule that has 4 atoms bonded to a central atom and no lone pairs of electrons. Hence, option C is correct.
What is an atom?An atom consists of a central nucleus that is usually surrounded by one or more electrons.
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which mean it has tetra (which translates to four) domains hence tetrahedral.
Hence, option C is correct.
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You are working on an experiment that requires Iodine (I) to have a full outer shell. What element could you combine it with to get a full outer shell? A. Lithium (Li) B. Sulfur (S) C. Neon (Ne) D. Oxygen (O)
Answer:
A. Lithium
Explanation:
Hello,
In this case, we can find out the required element by noticing that iodine has seven valence electrons as it is in group VIIA, therefore, it needs one spare electron to successfully attain the octet, that is completing eight electrons in total. For that reason, since lithium is group in IA, it will be able to provide the missing electron to iodine in order to get the full outer shell as required, thereby, lithium iodide will be formed.
Take into account that sulfur will share two electrons so two iodine atoms will be required, neon does not provide any electron as it is a noble gas and oxygen behave as well as sulfur.
Regards.
Answer:
Lithium
Explanation:
Answer via Educere/ Founder's Education
If you combine 24.2 g of a solute that has a molar mass of 24.2 g/mol with 100.0 g of a solvent, what is the molality of the resulting solution
Answer: 10 moles/kg.
Explanation:
Given, Mass of solute = 24.2 g
Molar mass of solute = 24.2 g/mol
[tex]\text{Moles of solute =}\dfrac{\text{Mass of solute}}{\text{Molar mass of solute}}\\\\=\dfrac{24.2}{24.2}=1[/tex]
Mass of solvent = 100.0g = 0.1 kg [1 g=0.001 kg]
[tex]\text{Molality}=\dfrac{\text{Moles of solute}}{\text{kilograms of Solvent}}\\\\=\dfrac{1}{0.1}\\\\=10\ moles/kg[/tex]
Hence, the molality of the resulting solution is 10 moles/kg.
The distance from the Moon to Earth is 5.46 * 108 km. How long does it take a laser need to travel between the moon and earth?
a. 1.64 X 1020 s
b. 1.82 X 103 s
c. 1.82 s
d. 0.182 s
e. 1.64 X 1017 s
Answer:
B. 1.82(10³) seconds (1820 seconds)
Explanation:
Speed of Light: 3.00(10⁸) m/s or 3.00(10⁵) km/s
We know the distance from the Moon to Earth as 5.46(10⁸) km
We simply divide the distance by the speed of light:
[tex]\frac{5.46(10^8)}{3.00(10^5)}[/tex]
We should get 1820 seconds or B. 1.82(10³) as our answer.
Status: Not yet answered | Points possible: 1.00
A sample of chlorine gas starting at 681 mm Hg is placed under a pressure of 992 mm Hg and reduced to a volume of 543.8 mL.
What was the initial volume, in ml, of the chlorine gas container if the process was performed at constant temperature?
Type answer:
Answer:
V1 = 792.1 ml
Explanation:
The product of pressure and volume is constant when temperature is constant. This relationship is known as Boyle's law.
To answer this, I assume the chlorine gas will behave as a perfect gas. In reality this is not completely true.
P1*V1 = P2*V2
Given:
P1 = 681 mm Hg
V1 = ?
P2 = 992 mm Hg
V2 = 543.8 ml
V1 = ( P2 * V2 ) / P1
V1 = (992 *543.8 ) / 681
V1 = 792.143318649046 ml
V1 = 792.1 ml
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
[Afus H° = 6.01 kJ/mol H2O(s)]
Answer:
[tex]m=33.9g[/tex]
Explanation:
Hello,
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J[/tex]
Afterwards, the mass of ice that can be melted is computed by:
[tex]Q=n \Delta _{fus}H[/tex]
So we solve for moles with the proper units handling:
[tex]n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol[/tex]
Finally, with the molar mass of water we compute the mass:
[tex]m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g[/tex]
Best regards.
mass=33.9g
Given:
n= 3.00 mol
Δfus H° = 6.01 kJ/mol H₂O(s)
Enthalpy of fusion is the change in its enthalpy resulting from providing energy, typically heat, to a specific quantity of the substance to change its state from a solid to a liquid, at constant pressure.
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nC_P[/tex]ΔT
[tex]Q=3.00\text{mol}*75.38\frac{J}{mol^oC} *50.0^oC\\\\Q=11307J[/tex]
Now, the mass of ice that can be melted is given by:
Q=nΔfus H°
So we solve for moles with the proper units handling:
n= Q/ Δfus H°
[tex]n=\frac{11307 J}{6010\frac{J}{mol} } =1.88 mol[/tex]
On substituting the moles with the molar mass of water we get:
[tex]m=1.88 mol*\frac{18 g}{1mol}\\\\m=33.9g[/tex]
The mass of ice is 33.9g.
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Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory.
Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),
Answer and Explanation:
1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)
on the other hand
Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.
2. The Chemical name and nature of acid is shown below:-
Nature Chemical Name
a. HCl Acidic Hydrochloric Acid
b. KOH Basic Potassium hydroxide
c. HNO Acidic Nitric Acid
d. Mg(OH)2 Basic Magnesium hydroxide
Which element has 4 valence electrons in the 3p sublevel?
The Periodic Table
A. Ga
B. Si
C. N
D. S
Answer:
D . Sulphur
Explanation:
the element with a 3p4 valence configuration, look in period 3 and group XVI, and that is ...
S, sulfur.
The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The abbreviation Q represents coenzyme Q. Use the appropriate abbreviation for the product.
FADH2 + Q →
The reactant that is reduced is: _____
Answer:
[tex]FADH_2 + Q --> FAD + QH_2[/tex]
The reactant that is reduced is [tex]FADH_2[/tex]
Explanation:
The complete equation is as below:
[tex]FADH_2 + Q --> FAD + QH_2[/tex]
Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.
In the above reaction, [tex]FADH_2[/tex] loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to [tex]QH_2[/tex] , hence the reducing agent.
In order words, [tex]FADH_2[/tex] is reduced while coenzyme Q is oxidized.
A sample of a pure compound that weighs 59.8 g contains 27.6 g Sb (antimony) and 32.2 g F (fluorine). What is the percent composition of fluorine
Answer:
53.85%
Explanation:
Data obtained from the question include:
Mass of antimony (Sb) = 27.6g
Mass of Fluorine (F) = 32.2g
Mass of compound = 59.8g
Percentage composition of fluorine (F) =..?
The percentage composition of fluorine can be obtained as follow:
Percentage composition of fluorine = mass of fluorine/mass of compound x 100
Percentage composition of fluorine = 32.2/59.8 x 100
= 53.85%
Therefore, the percentage composition of fluorine in the compound is 53.85%
The solubility of nitrogen gas at 25°C and a nitrogen pressure of 522 mmHg is 4.7 × 10 –4 mol/L. What is the value of the Henry's Law constant in mol/L·atm?
Answer:
6.8 × 10⁻⁴ mol/L.atm
Explanation:
Step 1: Given data
Solubility of nitrogen gas at 25°C (S): 4.7 × 10⁻⁴ mol/L
Partial pressure of nitrogen gas (P): 522 mmHg
Step 2: Convert the partial pressure of nitrogen to atm
We will use the relationship 1 atm = 760 mmHg.
[tex]522mmHg \times \frac{1atm}{760mmHg} = 0.687atm[/tex]
Step 3: Calculate the value of the Henry's Law constant (k)
We will use Henry's law.
[tex]S = k \times P\\k = \frac{S}{P} = \frac{4.7 \times 10^{-4}mol/L }{0.687atm} = 6.8 \times 10^{-4} mol/L.atm[/tex]
Write a balanced half-reaction for the reduction of aqueous arsenic acid H3AsO4 to gaseous arsine AsH3 in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Answer:
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Explanation:
Let's consider the half-reaction for the reduction of aqueous arsenic acid to gaseous arsine in a basic aqueous solution.
H₃AsO₄(aq) ⇒ AsH₃(g)
We see that there is an excess of 4 oxygen atoms on the left side. So, we add 4 molecules of water to the left side and 8 hydroxyl ions to the right side.
H₃AsO₄(aq) + 4 H₂O(l) ⇒ AsH₃(g) + 8 OH⁻(aq)
We need to add 8 electrons to the left side to balance the reaction electrically.
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Answer:
[tex]H_3AsO_4(aq)+8H^+(aq)+8e^-=AsH_3(g)+4H_2O(l)[/tex]
Explanation:
How does the carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere?
Answer:
The calculator add the CO2 released from the use of electricity, released from driving and the CO2 from the waste that we disposed.
Explanation:
The carbon dioxide, CO2 is what the human body does not need, therefore, we breathe it out, hence taking in oxygen(respiration process). The plants need oxygen for the production of their own food.
The carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere through the consideration of several factors such as the kind of food that we eat.
Therefore, if we are to use the carbon calculator to determine the amount of CO2 that each individual releases into the atmosphere we will have:
The amount of CO2 that each individual releases into the atmosphere =( CO2 released from the use of electricity) + (CO2 released from driving) + (the CO2 from the waste that we disposed).
Identify the following substances:
(1) An acidic gas which gives dense white fumes with NH3
(11 An alkane which can also be called a green house gas.
(iii) A solid which when kept in the open, forms a solution after som
(iv) An alloy used in electrical fittings.
(v) A metal which gives hydrogen gas on reacting with both dilute a
Write equations for the following reactions:
Aluminium oxide and Sodium hydroxide.
(ii) Zine and dilute sulphuric acid.
(
11
Answer:
1) HCl (Hydrochloric acid reacts with NH3 and forms dense fumes)
2) Methane (It is from the group of alkanes and is a green house gas)
3) Deliquescent substance (It is a solid which when kept in open forms a solution after sometime)
4) Brass (It is a solid-in-solid solution used to make electrical fittings)
5) Aluminium
Question 2:
1) Al₂O₃ + 2NaOH ⇒ 2NaAlO₂ (Sodium Aluminate) + H₂O
2) Zn + H₂SO₄ (dilute) => ZnSO₄ (Zinc Sulphate) + H₂
Answer:
HCl is the gasmethanedeliquescent substances (they absorbs water out of the air until they dissolve themselves into liquid solutions. )brassequations
Aluminium oxide and Sodium hydroxide react to form water and sodium aluminate
Al2O3 + 2NaOH → 2NaAlO2 + H2OZinc reacts with dilute sulphuric acid to form zinc sulphate and hydrogen gas
Zn + H2SO4 → ZnSO4 +H2
Chemistry question. Image attached.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Explanation:
What is the atomic mass of OsO4
Answer:
254.23 g/mol
Explanation:
Atomic mass for Osmium tetroxide would be 254.23 g/ml
Answer:254.2276
Explanation:
Consider 1 M solutions of NaCl, ethyl alcohol (CH3CH2OH), and hydrofluoric acid. Rank them in terms of how well they conduct electricity and explain why you ranked them this way.
Answer:
conductivity increasing order CH₃-CH₂-OH < HF< NaCl
Explanation:
NaCl is the better conductor comparing with remaining two. it is strong electrolyte. dissociation percent always nearly eqaul to 100% but HF is weaker acid than NaCl and dissociation percent <100% . So, the no of ions furnished by HF less than that of NaCl
CH₃-CH₂-OH organic compound . in general it is not treated as an electrolyte and it cannot carry any charge. If it carries, it is very very less compared to remaining two
why Al is a member of group 13 rather than group 3?
Answer:
Boron and Aluminium
Explanation:
Boron and Aluminium are present in Group 13 of the modern periodic table. Group 13 (IUPAC System) can also be referred to as Group III-A. Logically, Boron and Aluminum can't be placed alongwith elements such as Yttrium as they don't exhibit properties of a transition metal.
Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without re-arrangement give 2-butanol as the major product.
Answer:
See explanation
Explanation:
Hydration of alkenes is a common reaction in organic chemistry. Hydration is simply the addition of water to an alkene. This is an acid catalysed reaction as we can see from the mechanism attached.
Recall that our task is to carry out the synthesis of 2-butanol using an alkene starting material in which there will be no rearrangement of the intermediate carbocation. If we start with the compound shown in the image (but-2-ene), the first step is the formation of the secondary carbocation. This is followed by the addition of water. Subsequently, the added water is deprotonated by another water molecule to yield 2-butanol and the acid catalyst. All these steps have been clearly outlined in the image attached.
What does light do in the photoelectric effect?
O A. Light turns metal into electricity.
B. Light knocks electrons off metal atoms.
C. Light reacts with metal atoms.
D. Light is turned into electricity by the metal.
Answer:
it's B: light knocks electrons off metal atoms
Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?
boiling
freezing
chromatography
sorting
Answer:
a. boiling
Explanation: