Answer:
There are [tex]\mathbf{8.90172 \times 10^{-14}}[/tex] moles of bactoX present in a 3.0 μL sample volume that contains 7.512×106 bacterial cells
Explanation:
Given that:
The number of molecules present in one bacterial cell is [tex]7.140 \times 10^3[/tex] molecules
and the sample contains [tex]7.512 \times 10^6[/tex] molecules.
Number of moles = number of molecules /Avogadro's number
where;
Avogadro's number = 6.023 × 10²³
Number of moles = [tex]\dfrac{7.140 \times 10^3}{6.023 \times 10^{23}}[/tex]
Number of moles = [tex]1.185 \times 10^{-20}[/tex] moles
So; [tex]1.185 \times 10^{-20}[/tex] moles is present in one bacteria cell
Similarly; the sample contains [tex]7.512 \times 10^6[/tex] molecules.
Therefore; the number of moles present in the bactoX is = [tex]1.185 \times 10^{-20} \times 7.512 \times 10^6[/tex]
= [tex]\mathbf{8.90172 \times 10^{-14}}[/tex] moles
What is the core charge of helium and why?
Answer:
Formula for effective nuclear charge is as follows. So, for He atom value of S = 0.30 because the electrons are present in 1s orbital. Therefore, calculate the effective nuclear charge for helium as follows. Thus, we can conclude that the effective nuclear charge for helium is 1.7
Explanation:
The effective nuclear charge experienced by a 1s electron in helium is +1.70.
The melting point of sodium chloride is 801°C. The melting point of chlorine is -101°C. Explain, in terms of structure and bonding, the difference between the melting points of these two substances.
Answer:
It's harder to melt sodium chloride because of its density and stability.
Explanation:
The bond between Na+ and Cl- is an ionic bond, meaning its an ionic compound. Ionic compounds have more inter molecular forces(forces involving multiple molecules). Chlorine has much less of these forces than NaCl and isn't as dense.
Answer:
It's harder to melt sodium chloride because of its density
Explanation:
Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between CH3CH2CH2CH2CH3 and CH3CH2CH2CH2CH2CH3.
a. dispersion forces
b. dipole-dipole forces
c. hydrogen bonding
d. ion-dipole forces
2. Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between LiNO3 and H2O.
a. dispersion forces
b. dipole-dipole forces
c. hydrogen bonding
d. ion-dipole forces
Answer:
1) dispersion forces
2) ion-dipole forces
Explanation:
For the formation of a solution of the substances, CH3CH2CH2CH2CH3 and CH3CH2CH2CH2CH2CH3, dispersion forces are involved. Recall that the both are organic substances hence they are both molecular in nature. They are not only molecular, they are nonpolar molecules. This implies that only dispersion forces are the possible intermolecular forces.
For the formation of a solution of LiNO3 and H2O, the dipoles of water interacts strongly with the ions Li^+ and NO3^- thereby separating the ions in solution. The positive dipole of water interacts with NO3^- while the negative dipole of water interacts with Li^+.
Therefore, the interaction between nonpolar molecules is dispersion forces while between polar molecules is ion-dipole forces.
Dispersion forcesIon-dipole forcesDispersion Forces:
They are the weakest form of intermolecular force. The attraction between molecules is temporary.
it is due to temporary assymetric distribution of electrons in the molecules. It is found in the non-polar molecules.For example- Interaction between [tex]\bold { CH_3CH_2CH_2CH_2CH_3 }[/tex] and [tex]\bold { CH_3CH_2CH_2CH_2CH_2CH_3 }[/tex]
Ion-dipole forces:
The attraction between molecules is due to the interaction between opposite ions of molecules.
The distribution of electrons is asymmeric. This interaction is seen between polar molecules.For example- Interaction between [tex]\bold { LiNO_3 }[/tex] and [tex]\bold { H_2O }[/tex]
Therefore, the interaction between nonpolar molecules is dispersion forces while between polar molecules is ion- dipole forces.
To know more about molecular bonds, refer to the link:
https://brainly.com/question/4863547
A student followed the procedure of this experiment to determine the percent NaCl in a commercial bleaching solution that was found in the basement of an abandoned house. The student diluted 50.00 mL of the commercial bleaching solution to 250 mL in a volumetric flask, and titrated a 20-ml aliquot of the diluted bleaching solution. The titration required 35.46 mL of 0.1052M Na S,O, solution. A faded price label on the gallon bottle read $0.79. The density of the bleaching solution was 1.10 g ml.
(1) Calculate the mass of commercial bleaching solution titrated. 1.1 450=559
(2) Determine the percent NaOCl in the commercial bleaching solution.
(3) Calculate the mass of one gallon of the commercial bleaching solution.
llllllllalalalalallalalalallalallalalalalalallalalalallala pls I am really sorry for this I can't take it down
How fast are the atoms moving if the temperature of a gas is cold?
A. very, very slowly
B. they are stagnant
C. very, very quickly
Answer:
i think option a is correct answer because when there is low temperature then the kinetic enegry will be very less and the atoms moves very slowly.
Answer:
A. very, very slowly
Explanation:
A is the answer because atoms will move faster in hot gas than in cold gas.
4. 1.00 mole of Ca(NO3)2 contains the same mass of N as 1.00 mole of NaNO3. True or False
5. The theoretical yield of a reaction is generally less than the actual yield. True or False
6. Which of the following statements is/are TRUE concerning the "mole"? (a) One mole of a substance contains as many particles as exactly 12 amu of carbon-12. (b) One mole of a substance contains 6.022 x 1023 particles of that substance. (c) There are 6.022 x 1023 carbon atoms in 12.00 g of carbon-12. (d) Because it is heavier, a mole of iodine atoms contains more particles than a mole of bromine atoms.
7. The reaction of sulfuric acid with hematite (Fe2O3) , a common mineral, produces iron (III) sulfate and water, as follows: .
Fe2O3 + H2SO4 _________> Fe2(SO4)3 + H2O
When this equation is balanced, it will contain the following term(s) with the appropriate coefficient: (a) 3 H2SO4 (b) 2 Fe2O3 (c) Fe2(SO4)3 (d) 4 H2O
8. In a recent year, electric power plants in the US consumed 1.14 x 1011 kg of natural gas. Assume that natural gas is entirely methane, CH4, and calculate the number of hydrogen atoms in this amount. (a) 4.56 x 1011 atoms H (b) 1.71 x 1037 atoms H (c) 2.84 x 1013 atoms H (d) 4.28 x 1036 atoms H If you could also explain how you get the answer that would be really helpful
Answer:
4. False
5. False.
6. (b) One mole of a substance contains 6.022 x 10²³ particles of that substance
(c) There are 6.022 x 10²³ carbon atoms in 12.00 g of carbon-12.
7. The correct option is (A) 3H₂SO₄
8. (b) 1.71 * 10³⁷ atoms of hydrogen
Explanation:
4. 1.00 mole of Ca(NO3)2 contains the same mass of N as 1.00 mole of NaNO3 is False because 1 mole of Ca(NO3)2 contains 2 moles (28 g) of N atoms whereas 1 mole of NaNO3 contains 1 mole (14 g) of N atoms
5. The theoretical yield of a reaction is generally less than the actual yield is False because it is the actual yield of a reaction that is always less than the theoretical yield due to some incomplete reactions.
The actual yield is obtained from carrying out the actual reaction while the theoretical yield is calculated from the equation of the reaction.
6. A mole of a substance is defined as the amount of that substance which contains as many elementary particles as there are in 12 g of carbon-12.
From experiments, it was discovered that 12 g of carbon -12 contains 6.02 * 10²³ atoms, therefore, a mole of a substance can also be defined as the amount of that substance which contains 6.02 * 10²³ particles of that substance.
(a) One mole of a substance contains as many particles as exactly 12 amu of carbon-12 is false because 12 amu is the mass of 1 atom of carbon-12 and not a mole of carbon-12.
(b) One mole of a substance contains 6.022 x 1023 particles of that substance is true from the definitions above
(c) There are 6.022 x 1023 carbon atoms in 12.00 g of carbon-12 is true from the definitions above.
(d) Because it is heavier, a mole of iodine atoms contains more particles than a mole of bromine atoms is false because, irrespective of difference in their masses, a mole of all substances contain the same number of particles- 6.02 * 10²³.
7. The balanced chemical equation of the reaction of sulfuric acid with hematite (Fe2O3) to produce iron (III) sulfate and water is as follows: .
Fe₂O₃ + 3H₂SO₄ -----> Fe₂(SO₄)₃ + 3H2O
The correct option is (A) 3H₂SO₄
8. Mass of natural gas = 1.14 * 10¹¹ Kg.
Mass of natural gas in grams = 1.14 * 10¹¹ * 10³ g = 1.14 * 10¹⁴ g
Molar mass of CH₄ = 16g/mol
Number of moles of CH₄ in 1.14 * 10¹⁴ g = 1.14 * 10¹⁴ g/ 16 gmol⁻¹ = 7.125 * 10¹² moles
1 mole of CH₄ contains 4 moles of hydrogen atoms.
7.125 * 10¹² moles of CH₄ will contain 4 * 7.125 * 10¹² moles of hydrogen atoms = 2.85 * 10¹³ moles of hydrogen atoms
1 mole of hydrogen atoms contain 6.02 * 10²³ atoms of hydrogen
2.85 * 10¹³ moles of hydrogen atoms will contain 2.85 * 10¹³ * 6.02 * 10²³ atoms of hydrogen = 1.71 * 10³⁷ atoms of hydrogen
The equilibrium constant, K, for the following reaction is 2.44×10-2 at 518 K: PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 15.3 L container at 518 K contains 0.300 M PCl5, 8.55×10-2 M PCl3 and 8.55×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 8.64 L?
Answer:
[PCl₅] = 0.5646M
[PCl₃] = 0.1174M
[Cl₂] = 0.1174M
Explanation:
In the reaction:
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
K equilibrium is defined as:
K = 2.44x10⁻² = [PCl₃] [Cl₂] / [PCl₅]
The initial moles of each compound when volume is 15.3L are:
PCl₅ = 0.300mol/L×15.3L = 4.59mol
Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol
PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol
At 8.64L, the new concentrations are:
[PCl₅] = 4.59mol / 8.64L = 0.531M
[PCl₃] = 1.308mol / 8.64L = 0.151M
[Cl₂] = 1.308mol / 8.64L = 0.151M
At these conditions, reaction quotient, Q, is:
Q = [0.151M] [0.151M] / [0.531M]
Q = 4.29x10⁻²
As Q > K, the reaction will shift to the left producing more reactant, that means equilibrium concentrations are:
[PCl₅] = 0.531M + X
[PCl₃] = 0.151M - X
[Cl₂] = 0.151M - X
Where X is reaction coordinate.
Replacing in K expression:
2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]
1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²
0 = 9.84x10⁻³ - 0.3264X + X²
Solving for X:
X = 0.293 → False solution. Produce negative concentrations
X = 0.0336M → Right solution.
Replacing:
[PCl₅] = 0.531M + 0.0336
[PCl₃] = 0.151M - 0.0336
[Cl₂] = 0.151M - 0.0336
[PCl₅] = 0.5646M[PCl₃] = 0.1174M[Cl₂] = 0.1174MHow many moles of RNA are found in 250mL of a 0.0125 M solution? Group of answer choices 3.1 moles 0.031 moles 0.0031 moles 1.0 moles
Answer:
0.0031 moles
Explanation:[tex]Molarity=\frac{molSolute}{LitreSolution}\\ 0.0125M=\frac{molRNA}{0.25L} \\molRNA=0.0125*0.25=0.0031 mol[/tex]
What is the maximum amount of silver (in grams) that can be plated out of 4.7 L of an AgNO3 solution containing 6.3 % Ag by mass
Answer:
296.1g of Ag is the maximum amount of silver
Explanation:
A solution of 6.3% Ag by mass contains 6.3g of Ag per 100g of solution. Thus, you need to calculate the mass of the solution and then, the mass of Ag present in solution, thus:
Mass of solution:
Assuming a density of 1g/mL:
[tex]4.7L \frac{1000mL}{1L} \frac{1g}{mL} = 4700g[/tex]
If the solution contains 6.3g of Ag per 100g of solution, the mass of Ag in 4700L is:
4700L × (6.3g Ag / 100g) =
296.1g of Ag is the maximum amount of silverWhat molar ratio of sodium acetate to acetic acid should be used to prepare a buffer with pH = 4.5? Ka acetic acid = 1.8 x 10-5.
Answer: molar ratio: 0.58
Explanation:
This is a buffer problem. We would use the equation [tex]pH=pKa+log(\frac{base}{acid} )[/tex]. Since we were given Ka and pH, we can find the ratio.
pKa=-log(Ka)
pKa=-log(1.8×10⁻⁵)
pKa=4.74
Now that we have pKa, we can plug in our values and find the molar ratio. Instead of writing base/acid, let's use x.
4.5=4.74+log(x)
-0.24=log(x)
10⁻⁰⁻²⁴=x
x=0.58
What is the mass percent of vitamin C in a solution made by dissolving 5.20 g of vitamin C, C6H8O6, in 55.0 g of water
Answer:
The correct answer is 8.4 %
Explanation:
The mass percent of a compound in a solution is calculated as follows:
mass percent = mass of solute/mass of solution x 100
The solute is vitamin C, so its mass is:
mass of solute = 5.20 g
The solvent is water, and its mass is 55.0 g. The mass of the solution is given by the sum of solute + solvent:
mass of solution= 5.20 g + 55.0 g = 60.2 g
Finally we calculate the mass percent:
mass percent = 5.20 g/60.2 g x 100 = 8.64%
Explain why the following chemical equation represents a Lewis acid-base reaction. H+ + NH3 —>NH4+
Answer:
Due to an electron-pair acceptor and donor.
Explanations:
Lewis acid can be defined as an electron-pair acceptor. An example is Hydrogen ion(H+). This is because it is a proton and it distributes positive charge which means that it accepts electrons(negative charge).
Lewis base can be defined as an electron-pair donor. This is because it donates electrons to be accepted by the proton. An example is ammonia(NH3).
Calculate the pH of a solution that has [H3O+]=4.3 x 10^-5 M
Answer:
pH = 4.4
Explanation:
pH = -log[H₃O⁺]
= -log(4.3 × 10⁻⁵)
pH = 4.37 = 4.4
I'm actually learning this in my chemistry class right now lol. Hope this helps though. :)
Which statement is true: Mg -> Mg2+ + 2e-
(1) Mg gains 2 electrons (2) Mg2+ loses 2 electrons (3) mg loses 1 electron (4) mg loses 2 electrons
Answer:
(2) Mg²⁺ loses 2 electrons.
Explanation:
Let's consider the following half-reaction.
Mg ⇒ Mg²⁺ + 2 e⁻
Magnesium is a metal that loses 2 electrons to fulfill the octet rule. When magnesium loses electrons, the oxidation number increases from 0 to +2. This kind of half-reaction is known as oxidation, and has to be accompanied by a reduction of another species.
Two moles of copper (II) sulfate,CuSO4,contains blank moles of O
Answer:
8 mol
Explanation:
Step 1: Given data
Moles of copper (II) sulfate: 2 mol
Chemical formula of copper (II) sulfate: CuSO₄
Step 2: Establish the molar ratio of copper (II) sulfate to oxygen
According to the chemical formula, the molar ratio of copper (II) sulfate to oxygen is 1:4.
Step 3: Calculate the moles of O in 2 mol of CuSO₄
[tex]2molCuSO_4 \times \frac{4molO}{1molCuSO_4} = 8molO[/tex]
3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 mL of pure cyclohexene product. Calculate the student’s percent yield for this reaction. Show your work.
Answer:
[tex]49.45~%[/tex]
Explanation:
In this case, we have to start with the chemical reaction:
[tex]C_6H_1_2O~->~C_6H_1_0~+~H_2O[/tex]
So, if we start with 10 mol of cyclohexanol ([tex]C_6H_1_2O[/tex]) we will obtain 10 mol of cyclohexanol ([tex]C_6H_1_0[/tex]). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:
[tex](6*12)+(10*1)=82~g/mol[/tex]
With this value we can calculate the grams:
[tex]10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0[/tex]
Now, we have as a product 500 mL of [tex]C_6H_1_0[/tex]. If we use the density value (0.811 g/mL). We can calculate the grams of product:
[tex]500~mL\frac{0.811~g}{1~mL}=405.5~g[/tex]
Finally, with these values we can calculate the yield:
[tex]%~=~\frac{405.5}{820}x100~=~49.45%[/tex]%= (405.5/820)*100 = 49.45 %
See figure 1
I hope it helps!
Based on the data given, the percentage yield of the student's work is 49.45 %.
What is the equation of the reaction?The equation of the clay-catalyzed dehydration of cyclohexanol is given below:
C₆H₁₂O ----> C₆H₁₀ + H₂OFrom the equation of the reaction, 1 mole of cyclohexanol yields 1 mole of cyclohexene.
Therefore 10 moles of cyclohexanol should yield 10 moles of cyclohexene.
What is the moles of cyclohexene obtained?First we determine the mass of cyclohexene obtained.
Mass = density * volume
volume of cyclohexene = 500 mL
density = 0.811 g/mL
mass of cyclohexene = 500 * 0.811
mass of cyclohexene = 405.5 g
Number of moles of cyclohexene = mass/molar mass
molar mass of cyclohexene = 82 g
moles of cyclohexene = 405.5 g/82
moles of cyclohexene = 4.945 moles
What is the percentage yield?Percentage yield = actual yield /expected yield * 100%Percentage yield = 4.945/10 * 100%
Percentage yield = 49.45%
Therefore, the percentage yield of the student's work is 49.45 %.
learn more about percentage yield at: https://brainly.com/question/8638404
If 40.0 g of molten iron(II) oxide reacts with 10.0 g of mag-nesium, what is the mass of iron produced
Answer:
[tex]m_{Fe}=23.0gFe[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
[tex]FeO+Mg\rightarrow Fe+MgO[/tex]
Thus, for the given masses of reactants we should compute the limiting reactant for which we first compute the available moles of iron (II) oxide:
[tex]n_{FeO}=40.0gFeO*\frac{1molFeO}{72gFeO} =0.556molFeO[/tex]
Next, we compute the consumed moles of iron (II) oxide by the 10.0 g of magnesium, considering their 1:1 molar ratio in the chemical reaction:
[tex]n_{FeO}^{consumed}=10.0Mg*\frac{1molMg}{24.3gMg}*\frac{1molFeO}{1molMg}=0.412molFeO[/tex]
Therefore, we can notice there is less consumed iron (II) oxide than available for which it is in excess whereas magnesium is the limiting reactant. In such a way, the produced mass of iron turns out:
[tex]m_{Fe}=0.412molFeO*\frac{1molFe}{1molFeO}*\frac{56gFe}{1molFe}\\ \\m_{Fe}=23.0gFe[/tex]
Regards.
which conditions make snow
Answer:
It depends on the weather.
Explanation:
Like rain and hail, snow comes from the water vapor that forms the clouds, but obviously its formation is different: snow forms when the temperature is low in the atmosphere. In these conditions the water vapor drops freeze and when they collide form tiny crystals that join together to form snowflakes, which fall to Earth when they are heavy enough.
Calculate the pressure exerted by 0.5600 mole of in a 1.1000-L container at 25.0°C. (The gas constant is 0.08206 L·atm/mol·K. Take absolute zero to be –273.2°C.)
Use the ideal gas law.
(Enter your answer to four significant figures.)
Pressure =
atm
Use the van der Waals equation.
(For : a = 1.39 atm L2/mol2, and b = 0.0391 L/mol. Enter your answer to four significant figures.)
Pressure =
atm
Compare the results.
(Enter your answer to two significant figures.)
The
_________
is higher by
atm, or
%.
Answer:
using ideal gas equation =12.4576atm to 4.significant figure
using vander Waals equation = 12.3504
The differences is 0.10atm
an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m^3 while the temperature remains constant, what will be the new pressure in the gas.
Answer:
[tex]P_2=1.1x10^6Pa[/tex]
Explanation:
Hello.
In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:
[tex]P_1V_1=P_2V_2[/tex]
In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1V_1}{V_2}[/tex]
Consider that the given initial pressure is also equal to Pa:
[tex]P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa[/tex]
Which stands for a pressure increase when volume decreases.
Regards.
1. How many hydrogen atoms are in an alkane that has 7 carbon atoms?
2. An alkane contains 18 H atoms. Name the compound.
Answer:
1- there are 16 hydrogen atoms. ( heptane C7H16)
2- The compound is octane (C8H18)
explanation
to determine any atom in an alkane, this formula is used Cn H 2n +2, where n is the number of carbon atoms in the molecule.
to find the compound in Q2 we'll apply the numbers:
C nH₂n+2
The substance nitrogen has the following properties: normal melting point: 63.2 K normal boiling point: 77.4 K triple point: 0.127 atm, 63.1 K critical point: 33.5 atm, 126.0 K At temperatures above 126 K and pressures above 33.5 atm, N2 is a supercritical fluid . N2 does not exist as a liquid at pressures below atm. N2 is a _________ at 16.7 atm and 56.5 K. N2 is a _________ at 1.00 atm and 73.9 K. N2 is a _________ at 0.127 atm and 84.0 K.
Answer:
- N2 does not exist as a liquid at pressures below 0.127 atm.
- N2 is a solid at 16.7 atm and 56.5 K.
- N2 is a liquid at 1.00 atm and 73.9 K
- N2 is a gas at 0.127 atm and 84.0 K.
Explanation:
Hello,
At first, we organize the information:
- Normal melting point: 63.2 K.
- Normal boiling point: 77.4 K.
- Triple point: 0.127 atm and 63.1 K.
- Critical point: 33.5 atm and 126.0 K.
In such a way:
- N2 does not exist as a liquid at pressures below 0.127 atm: that is because below this point, solid N2 exists only (triple point).
- N2 is a solid at 16.7 atm and 56.5 K: that is because it is above the triple point, below the critical point and below the normal melting point.
- N2 is a liquid at 1.00 atm and 73.9 K: that is because it is above the triple point, below the critical point and below the normal boiling point.
- N2 is a gas at 0.127 atm and 84.0 K: that is because it is above the triple point temperature at the triple point pressure.
Best regards.
The following thermochemical equation is for the reaction of Fe 3 O 4 (s) with hydrogen (g) to form iron and water vapor Fe 3 O 4 (s)+4H 2 (g) 3Fe(s)+4H 2 O(g) When 64.6 grams of Fe 3 O 4 (s) react with excess hydrogenſe) how much heat is absorbed?
Answer:
41.3kJ of heat is absorbed
Explanation:
Based in the reaction:
Fe₃O₄(s) + 4H₂(g) → 3Fe(s) + 4H₂O(g) ΔH = 151kJ
1 mole of Fe3O4 reacts with 4 moles of H₂, 151kJ are absorbed.
63.4g of Fe₃O₄ (Molar mass: 231.533g/mol) are:
63.4g Fe₃O₄ × (1mol / 231.533g) = 0.274moles of Fe₃O₄
These are the moles of Fe₃O₄ that react. As 1 mole of Fe₃O₄ in reaction absorb 151kJ, 0.274moles absorb:
0.274moles of Fe₃O₄ × (151kJ / 1 mole Fe₃O₄) =
41.3kJ of heat is absorbed
which resonance form would be the most stable contributor to the intermediate arenium ion produced by electrophilic bromination of methoxybenzene
The question is incomplete as the options are missing, however, the correct complete question is attached.
Answer:
The correct answer is option A. ( check image)
Explanation:
The most stable contributor to the intermediate arenium ion produced by electrophilic bromination of methoxybenzene in given options is option a due to the fact that this resonating form follows the octet rule is satisfied for all atoms and additional π bond is present in between C-O that makes it more stable, while in other options there are positive charge which means they do not follows octet rule completely.
Thus, the correct answer is option A. ( check image)
One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (NaOCl) by mass. You may want to reference (Pages 552 - 557) Section 13.5 while completing this problem. Part A What is the molarity of this solution
Answer:
molarity of the solution = 0.548 mol/L
Note: Additional information about the question is given as follows;
One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (NaOCl) by mass
What is the molarity of this solution? (Assume a density of 1.02 g/mL .)
Explanation:
A 4.00 percentage by mass composition of sodium hypochlorite (NaOCl) solution means that 100 g of the solution contains 4.00 g NaOCl.
Thus, a 1000 g of the solution contains 40.0 g NaOCl
Density of solution = 1.02 g/mL
Therefore, the volume occupied by 1000 g solution = mass/density
volume of 1000 g solution = 1000 g/1.02 g/ml = 980.4 mL
Molar mass of NaOCl = 74.5 g/mol
Number of moles = mass/molar mass
Number of moles of NaOCl = 40.0 g/74.5 g/mol
Number of moles of NaOCl = 0.537 mole
Therefore, molarity = number of moles / volume(L)
volume of solution in litres = 980.4/1000 = 0.9804 L
Molarity = 0.537/0.9804 = 0.548 mol/L
Therefore, molarity of the solution = 0.548 mol/L
Consider the 1H NMR spectrum for the following compound:
CH3CH2CH3
Predict the first-order splitting patterns of the indicated proton. This question uses specific splitting patterns instead of the often used generic term "multiplet."
a. doublet of quartets
b. triplet of triplets
c. septet
d. quartet of quartets
e. quintet
Answer:
See explanation
Explanation:
In this case, we have to check the neighbors of each carbon in the molecule. In propane, we have two types of carbons (see figure 1) (blue and red ones). The red carbons are equivalent. (Both have the same neighbors). Now, we can analyze each carbon:
Blue carbon
In the blue carbon, we have 6 hydrogens neighbors (three on each methyl). If we follow the n+1 rule, we will have:
6+1= 7
For the blue carbon, we will have a Septet.
Red carbons
In the red carbon, we have only 2 neighbors (the carbon in the middle only have 2 hydrogens). If we follow the n+1 rule, we will have:
2+1=3
For the red carbon, we will have a triplet.
See figure 2
I hope it helps!
Select the correct answer
In an experiment, chemists heated a solid, red substance in a test tube. Vapors from the heated red substance condensed as a metallic liquid on
the side of the tube. The red substance eventually disappeared, leaving only the metallic liquid and producing a gas that escaped from the tube.
Which statement best describes what happened to the red substance in this experiment?
OA The experiment demonstrates the formation of plasma from the red substance.
B. The experiment demonstrates a physical property of the red substance.
OC The experiment shows that the red substance experienced a chemical change.
OD. The experiment shows that the red substance can be a solid, liquid, or gas.
CE. The experiment shows that the red substance is an element.
Answer:
C The experiment shows that the red substance experienced a chemical change.
Explanation:
Apparently, adding heat caused the red substance to decompose into a gas and a metallic liquid. If it were simply a phase change, the original red substance could be expected to return when the temperature cooled. Because the substance apparently decomposed, it is clearly not an element. At no point in the experiment is there any evidence of a plasma being formed.
The observed decomposition is a chemical change.
What is the value of ΔG at 25°C when the initial concentrations of A, B, and C are 1 M, 1 mM, and 1 μM, respectively?
Answer:
Explanation:
0,44
The rate at which two methyl radicals couple to form ethane is significantly faster than the rate at which two tert-butyl radicals couple. Offer two explanations for this observation.
Answer:
1. stability factor
2. steric hindrance factor
Explanation:
stability of ethane is lesser to that of two tert-butyl, so ethane will be more reactive and faster.
ethane is less hindered and more reactive, while two tert-butyl is more hindered and less reactive
Nitrosyl bromide, NOBr, is formed from NO and Br2.
2 NO(g) + Br2(g) 2 NOBr(g)
Experiments show the reaction is second order in NO and first order in Br2.
(a) What is the rate equation for the reaction?
rate = k[NO]2[Br2]
rate = k[NO][Br2]
rate = k[NO]2[Br2]2
rate = k[NO]2[Br]2
(b) How does the reaction rate change if the concentration of Br2 is changed from 0.0022 mol/L to 0.0066 mol/L?
the rate will double
the rate will remain unchanged
the rate will triple
(c) What is the change in the reaction rate if the concentration of NO is changed from 0.0024 mol/L to 0.0048 mol/L?
the rate will increase by a factor of 4
the rate will remain unchanged
the rate will also decrease by a factor of 1/2
Answer:
(a) What is the rate equation for the reaction?
rate = k[NO]2[Br2]
Explanation:
(b) How does the reaction rate change if the concentration of Br2 is changed from 0.0022 mol/L to 0.0066 mol/L?
the rate will doubleNitrosyl bromide, NOBr, is formed from NO and Br2.
(a) Rate = [tex]k[NO]2[Br2][/tex]
(b) The rate will triple Nitrosyl bromide, NOBr, is formed from NO and Br2.
(c) The rate will triple increase by a factor of 4
Calculation of Nitrosyl bromide
(a) The reaction is second order in NO ---> [tex]rate , r = k[NO]^2[/tex]
the reaction is first order in Br2 --> rate ,[tex]r = k[Br2]^1[/tex]
Therefore, from the above two total rate equation is , rate , [tex]r = k [NO]^2[/tex][tex][Br2]^1[/tex]
--> [tex]r = k[NO]^2 [Br2][/tex]
(b)The rate law is rate , [tex]r = k[NO]^2 [Br2][/tex]
------> rate , r is directly proportional to [Br2]
----->[tex]r / r’ = [Br2] / [Br2]’[/tex]
r = initial rate
r’ = final rate
[Br2] = initial conc = 0.0022 mol/L
[Br2]’ = final conc = 0.0066 mol/L
Plug the values we get[tex]r/r’ = 0.0022 / 0.0066[/tex]
r / r’ = 0.33
----> r’ = r / 0.33 = 3r
Therefore, the rate will triple
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(c) The rate law is rate ,[tex]r = k[NO]^2 [Br2][/tex]
------> rate , r is directly proportional to [tex][NO]^2[/tex]
-----> r / r’ =[tex][NO]^2 / [NO]’^2[/tex]
r = initial rate[tex]r / r’ = [NO]^2 / [NO]’^2[/tex]
r’ = final rate
[NO] = initial conc = 0.0024 mol/L
[NO]’ = final conc = 0.0048 mol/L
Plug the values we get [tex]r/r’ = 0.0024 / 0.0048[/tex]
[tex]r / r’ = (0.0024^2) / (0.0048)^2[/tex]
= [tex](0.5)^2[/tex]
=[tex]0.25[/tex]
----> r’ = [tex]r / 0.25 = 4r[/tex]
Therefore, the rate will triple increase by a factor of 4
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