In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts College, and 30% of the students were in the Education College. To see whether or not the proportions have changed, a sample of 300 students from the university was taken. Ninety of the sample students are in the Business College, 120 are in the Liberal Arts College, and 90 are in the Education College. Using α = .05, the conclusion of the test is that the a. proportions have not changed significantly. b. proportions follow normal distribution. c. Marascuilo procedure is more applicable. d. null hypothesis cannot be rejected.

Answers

Answer 1

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= [tex]\sqrt{npq\\}[/tex]

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= [tex]\sqrt{npq\\}[/tex]=[tex]\sqrt{0.3*0.7*300}[/tex]= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= [tex]\sqrt{npq\\}[/tex]=[tex]\sqrt{0.4*0.6*300}[/tex]=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= [tex]\sqrt{npq\\}[/tex]=[tex]\sqrt{0.3*0.7*300}[/tex]= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.


Related Questions

What is coefficient of the term of degree of degree 5 in the polynomial below 3x^6+5-x^2+4x^5-9 which one is the right answer A. 3 B. 4 C. 6 D. 5

Answers

Answer:

B. 4

Step-by-step explanation:

We are looking for the coefficient of the term x⁵. When we see it in the polynomial as 4x⁵, our coefficient and answer would then be 4.


The figure shows a person estimating the height of a tree by looking at the
top of the tree with a mirror. Assuming that both the person and the tree form
right angles with the ground, which of the following proportions can be used
to estimate the height of the tree

Answers

Answer:

[tex]\frac{6}{5} =\frac{x}{12}[/tex]

Step-by-step explanation:

Write a proportion in the form:

Height/side= height/side

The side lengths are 5 and 12.

The height (of the 5 side) is 6.

The proportion can be written as:

[tex]\frac{6}{5} =\frac{x}{12}[/tex]

Construct a confidence interval of the population proportion at the given level of confidence.
x equals =860​
n equals =1200​
94​% confidence
The lower bound of the confidence interval is __?

Answers

Answer:

The lower bound of the confidence interval is 0.6922.

Step-by-step explanation:

We have to calculate a 94% confidence interval for the proportion.

The sample proportion is p=0.7167.

[tex]p=X/n=860/1200=0.7167[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.7167*0.2833}{1200}}\\\\\\ \sigma_p=\sqrt{0.000169}=0.013[/tex]

The critical z-value for a 94% confidence interval is z=1.8808.

The margin of error (MOE) can be calculated as:

[tex]MOE=z\cdot \sigma_p=1.8808 \cdot 0.013=0.0245[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=p-z \cdot \sigma_p = 0.7167-0.0245=0.6922\\\\UL=p+z \cdot \sigma_p = 0.7167+0.0245=0.7412[/tex]

The 94% confidence interval for the population proportion is (0.6922, 0.7412).

solve for n n/5+0.6=2

Answers

Tip: use inverse operations
n/5 +.6 =2
n/5 = 1.4
n=7

Check:
7/5 + .6=2
1.4 + .6= 2
2=2

Final answer:
N=7

Answer:

N=7

Step-by-step explanation:

It is correct on Khan

What is the greatest common factor of 48 and 32?

Answers

Answer:

GCF - 16

Step-by-step explanation:

48 - 1, 2, 3, 4, 6, 8, 12, 16

32 - 1, 2, 4, 8, 16

Hope this helps! :)

Answer:

16

Step-by-step explanation:

48=3*16

32=2*16

URGENT!! Solve the triangle for all missing sides and angles. Part 2: Use the law of sines to find the length of side a. Part 3: Use any method to find the length of side c.

Answers

Answer:

B = 55°

a ≈ 143

c ≈ 212

Step-by-step explanation:

From the triangle above we are given a triangle with two known angles and a known side. The sum of angles in a triangle is 180°. Since we are given two angles, the last angle can be gotten when you subtract the two known angles from 180°. Therefore,

angle B = 180° - 42° - 83°

angle B = 55°

To find side a we can use law of sine

a/sin A = b/sin B

a/sin 42° = 175/sin  55°

a/0.66913060635  = 175/0.81915204428

cross multiply

0.81915204428 a  = 117.097856113

divide both sides by 0.81915204428

a =  117.097856113 /0.81915204428

a = 142.950087143

a ≈ 143

To find side c

b/sin B = c/sin C

175/sin 55 = c/sin 83°

cross multiply

c sin 55° = 175 sin 83°

divide both sides by sin 55°

c = (175 × 0.99254615164)/0.81915204428

c = 173.695576537 / 0.81915204428

c = 212.043146019

c ≈ 212

Find the midpoint of the line segment defined by the points (1/2, -5/2) and (-4/3, -1/6)

Answers

Answer:

-5/6 and -8/3

Step-by-step explanation:

To find the cordinates of the midpoint we must add the coordinates together and divide them by 2

let A be the midpoint of this line :

A (1/2-4/3 , -5/2-1/6)

A( -5/6, -8/3)

Answer:

(-5/12 , - 4/3)

Step-by-step explanation:

The midpoint of the points (1/2, -5/2) and (-4/3, -1/6) is

[tex] (\frac{ \frac{1}{2} - \frac{4}{3} }{2} \: \: \frac{ - \frac{ 5}{2} - \frac{1}{6} }{2} ) \\ \\ = ( \frac{ - \frac{5}{6} }{2} \: \: \frac{ - \frac{8}{3} }{2} ) \\ \\ = ( - \frac{5}{12} \: \: \: - \frac{4}{3} )[/tex]

(-5/12 , - 4/3)

Hope this helps you

Select the expression that is equivalent to (x - 1)2.
O A. x2 - 2x + 2
O B. x2 - x + 2
O C. x2 - x + 1
O D. x2 – 2x + 1

Answers

Answer:

D

Step-by-step explanation:

(x - 1)² = (x - 1)(x - 1)

x² - x- x + 1 = x² - 2x + 1

Dr. Hernandez is a conservation biologist studying the impacts a derelict pharmaceutical company is having on a native fish population in a nearby lake. The lake has been contaminated with bovine growth hormone and Dr. Hernandez wants to see if the fish reaching adulthood in the contaminated lake are larger than the fish in a pristine lake that is nearby. Dr. Hernandez has the weights of 30 fish from the contaminated lake and of 30 fish from the pristine lake.
Based on the experimental design of Dr. Hernandez's research and the kind of data collected, which statistical test should be used to determine whether the bovine growth hormone is increasing the growth of native fish?
A. Two-tailed two-sample t-test
B. One-tailed paired t-test
C. Two-tailed paired t-test
D. One-tailed two-sample t-test
E. One-Way ANOVA
F. Linear Regression with t-test for significance of slope

Answers

Answer:

C. Two-tailed paired t-test.

Step-by-step explanation:

Since Dr. Hernandez takes 30 samples from a contaminated lake and 30 fish from a pristine lake, he should use a two-tailed t-test.

Paired t-tests describe tests used to compare the means of two samples when each observation in one sample can be paired with an observation in the other sample. Dr. Hernandez can certainly pair the samples and observe the differences, so the answer is C. Two-tailed paired t-test.

Hope this helps!

Jimmy will be selling hot dogs at the football game. He bought hot dogs, buns, and condiments for a total of \$8$8dollar sign, 8 and now wants to calculate how many hot dogs he has to sell to make a profit. He graphs the profit he will make, (P)(P)left parenthesis, P, right parenthesis, as a function of the number

Answers

Answer:

the photo shows the answer ^D^ hope this helps~

Step-by-step explanation:

+also included the correct sign for confirmation xD

Answer:

up answer is correct :)

Step-by-step explanation:

Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1) (5 pts) Determine the constant c value such that the above joint PDF is valid. (2) (6 pts) Find P (X greater than 2 comma space Y less than 1 )(3) (9 pts) Determine the marginal PDF of X given Y

Answers

(1) Looks like the joint density is

[tex]f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0<y<x<4\\0&\text{otherwise}\end{cases}[/tex]

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

[tex]\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1[/tex]

[tex]\implies\boxed{c=\dfrac1{32}}[/tex]

(2) The region in which X > 2 and Y < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

[tex]P(X>2,Y<1)=\displaystyle\int_2^4\int_0^1\frac{xy}{32}\,\mathrm dy\,\mathrm dx=\boxed{\dfrac3{32}}[/tex]

(3) Are you supposed to find the marginal density of X, or the conditional density of X given Y?

In the first case, you simply integrate the joint density with respect to y:

[tex]f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0<x<4\\0&\text{otherwise}\end{cases}[/tex]

In the second case, we instead first find the marginal density of Y:

[tex]f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0<y<4\\0&\text{otherwise}\end{cases}[/tex]

Then use the marginal density to compute the conditional density of X given Y:

[tex]f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y<x<4\text{ where }0<y<4\\0&\text{otherwise}\end{cases}[/tex]

Consider the following function. f(x) = 2x + 5. Place the steps for finding f-1 (x) in the correct order. A. x-2/5= y B. y = 2x + 5 C. y-5 = 2x D. X-5/2=y E. f-1(x) = x-5/2 F.x= 2y+ 5 G. x-5= 2y H. f-1(x) = x-2/5

Answers

Answer:

[tex]\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-5}{2} \ \ }[/tex]

Step-by-step explanation:

hello,

the easiest way to understand what we have to do is the following in my opinion

we can write

[tex](fof^{-1})(x)=x\\<=>f(f^{-1}(x))=x\\<=>2f^{-1}(x)+5=x\\<=>2f^{-1}(x)+5-5=x-5 \ \ \ subtract \ \ 5\\<=> 2f^{-1}(x)=x-5 \\<=> f^{-1}(x)=\dfrac{x-5}{2} \ \ \ divide \ by \ 2\\[/tex]

so to follow the pattern of your question

y = 2x + 5

we need to find x as a function of y, so let's swap x and y

x = 2y + 5

then subtract 5

x - 5 = 2y

then divide by 2

[tex]\dfrac{x-5}{2}=y[/tex]

finally

[tex]f^{-1}(x)=\dfrac{x-5}{2} \\[/tex]

hope this helps

Answer:

1. y= 2x + 5

2. x = 2y + 5

3. x - 5 = 2y

4. (x-5)/2 =u

5. f^-1(x) = (x-5)/2

Step-by-step explanation:

:)

The shape on the left is transformed to the shape on the right. Figure A B C D is rotated to form figure A prime B prime C prime D prime. Which of the following statements describes the transformation? A B C D right-arrow A prime B prime C prime D prime A prime B prime C prime D prime right-arrow A B C D A B C D right-arrow D prime A prime C prime B prime D prime B prime C prime A prime right-arrow C A D B

Answers

Answer:

A

Step-by-step explanation:

I did the test and it is the only one that makes sense

Answer:

a

Step-by-step explanation:

Write your answer using only positive exponents

Answers

Answer:

Step-by-step explanation:

Hello

[tex](-4b^5c^{-6})^3\\\\=(-1)^34^3b^{15}v^{-18}\\=-64b^{15}c^{-18}\\\\=\dfrac{-64b^{15}}{c^{18}}\\[/tex]

hope this helps

The simplified form of the given exponential expression is -64b¹⁵/c¹⁸.

What is the exponent?

Exponent is defined as the method of expressing large numbers in terms of powers. That means, exponent refers to how many times a number multiplied by itself.

The given exponential expression is (-4b⁵c⁻⁶)³.

Here, the given expression can be written as -4³(b⁵)³(c⁻⁶)³

= -64b¹⁵c⁻¹⁸

= -64b¹⁵/c¹⁸

Therefore, the simplified form of the given exponential expression is -64b¹⁵/c¹⁸.

To learn more about an exponents visit:

https://brainly.com/question/15993626.

#SPJ2


Please help! Need Geometry help!!!!!

Answers

Answer:

938 feet

Step-by-step explanation:

b/c every angle of a rectangle is 90° u can u Pythagorean theroem to solve the question

a*a+ b*b=c*c

900*900+264*264=c*c

c=√879,696

c=938feet

Answer:

938 feet

Step-by-step explanation:

Well to solve this we need to use the Pythagorean Theorem,

[tex]a^2 + b^2 = c^2[/tex].

So we have a and b which are 900 and 264,

and we need to find c or the walking distance.

So we plug in 900 and 264 for a and b.

[tex](900)^2 + (264)^2 = c^2[/tex]

So, 900*900 = 810,000

264 * 264 = 69696

810000 + 69696 = 879696

So now we have,

879696 = c^2

To get the c by itself we do,

[tex]\sqrt{879696} = \sqrt{c}[/tex]

= c = 937.921105424

c = 938 rounded to the nearest foot

Thus,

the solution is 938.

Hope this helps :)

whats 1/2 + 2/4 - 5/8?

Answers

Answer:

3/8

Step-by-step explanation:

Step 1: Find common denominators

1/2 = 4/8

2/4 = 4/8

Step 2: Evaluate

4/8 + 4/8 - 5/8

8/8 - 5/8

3/8

Alternatively, you can just plug this into a calc to evaluate and get your answer.

Answer:

3/8

Step-by-step explanation:

Look at the denominator:

2, 4, 8. The LCM (Lowest Common Multiple) is 8.

So this equation becomes

4/8+4/8-5/8=3/8

Suppose a random variable X is best described by a uniform probability distribution with range 1 to 5. Find the value of that makes the following probability statements true.
a) P(X <-a)= 0.95
b) P(X c) P(X d) P(X ->a)= 0.89
e) P(X >a)= 0.31

Answers

Answer:

a) 4.8

b) 2.96

c) 4.4

d) 1.44

e) 3.76

Step-by-step explanation:

What we will do is solve point by point, knowing the following:

Fx (x) = P (X <= x) = (x - 1) / 4

a) P (X <-a) = 0.95

Fx (a) = 0.95

(a -1) / 4 = 0.95

a = 1 + 0.95 * 4

a = 4.8

b) P (X <a) = 0.49

Fx (a) = 0.49

(a -1) / 4 = 0.49

a = 1 + 0.49 * 4

a = 2.96

c) P (X <a) = 0.85

Fx (a) = 0.85

(a -1) / 4 = 0.55

a = 1 + 0.85 * 4

a = 4.4

d) P (X> a) = 0.89

P (X <a) = 1 - 0.89 = 0.11

Fx (a) = 0.11

(a -1) / 4 = 0.11

a = 1 + 0.11 * 4

a = 1.44

e) P (X> a) = 0.31

P (X <a) = 1 - 0.31 = 0.69

Fx (a) = 0.69

(a -1) / 4 = 0.69

a = 1 + 0.69 * 4

a = 3.76

Please Help! Select the correct answer. Simon used these steps to solve an equation:

Answers

Answer:

A.

Step-by-step explanation:

From Step 3 to Step 4, Simon added -42 to both sides.

This is the addition property of equality: as long as you add the same thing to both sides, the equation remains equal.

A.

The answer to this question is A

I NEED HELP ASAP,THANKS! :)
Roland’s Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 1 economy seats must be sold and at least 6 deluxe seats must be sold. The maximum number of passengers allowed on each boat is 30 Roland’s Boat Tours makes $40 profit for each economy seat sold and $35 profit for each deluxe seat sold. What is the maximum profit from one tour? Show work.

Answers

Answer:

  $1170

Step-by-step explanation:

Let x and y represent the numbers of economy and deluxe seats sold. The constraints are ...

x ≥ 1y ≥ 6x +y ≤ 30

And the objective function we want to maximize is ...

  p = 40x +35y

__

I find it convenient to graph the equations and locate the objective function line as far from the origin as possible. The graph is shown, along with the solution.

Here, it's even simpler than that. The profit per seat is the greatest for economy seats, so Roland's should sell as many of those as they can. The only limit is that 6 seats must be deluxe. The remaining 30-6=24 can be economy. So, the profit will be maximized for ...

  24 economy seats and 6 deluxe seats

The corresponding profit will be ...

  24(40) +6(35) = 1170

The maximum profit from one tour is $1170.

(09.06 HC)
The function H(t) = -16t2 + 90t + 75 shows the height H(t), in feet, of a projectile after t seconds. A
second object moves in the air along a path represented by g(t) = 31 + 32.2t, where g(t) is the height, in
feet, of the object from the ground at time t seconds.
Part A: Create a table using integers 2 through 5 for the 2 functions. Between what 2 seconds is the
solution to H(t) = g(t) located? How do you know? (6 points)
Part B: Explain what the solution from Part A means in the context of the problem.(4 points)

Answers

Answer: h(t) = g(t) between 4 and 5 seconds

Step-by-step explanation:

h(t) = -16t² + 90t + 75

g(t) = 31 + 32.2t

[tex]\begin{array}{c|c|c|c|c}\qquad&\underline{\quad t=2\quad }&\underline{\quad t=3\quad}&\underline{\quad t=4\quad }&\underline{\quad t=5\quad }\\h(t)&191&201&179&125\\g(t)&95.4&127.6&159.8&192\end{array}\right][/tex]

Notice that g(t) is increasing from t=2 to t=5, while h(t) is increasing from t=2 to t=3 and then decreasing.  

At t=4, h(t) > g(t)

At t = 5, g(t) > h(t)

therefore, the two lines must intersect at a point between t=4 and t=5.

You can graph this to verify the answer.

Beginning three months from now, you want to be able to withdraw $2,300 each quarter from your back account to cover college expenses over the next four years. If the account pays .45 percent interest per quarter, how much do you need to have in your bank account today to meet your expense needs over the next four years?

Answers

Answer:

  $36,450.46

Step-by-step explanation:

The amortization formula can be used to figure this. For quarterly payment A, the principal invested must be P for interest rate r and compounding n times per year for t years.

  A = P(r/n)/(1 -(1 +r/n)^(-nt))

  2300 = P(0.0045/4)/(1 -(1 +0.0045/4)^(-4·4))

  2300 = P·0.06309934

  P = 2300/0.06309934 = 36450.46

You need $36,450.46 in your account today so that you can withdraw $2300 quarterly for 4 years.

Arrange in ascending order. 8/13, 2/9,28/29

Answers

Step-by-step explanation:

he operation of sorting fractions in ascending order: 18/46, 28/41, 29/38, 29/44, 32/30 ... terms equivalents: 18/46=(2×3^2)/(2×23)=((2×3^2)÷2)/((2×23)÷2)=9/23; 28/41 already reduced to ... by the largest exponents: LCM (9, 28, 29)=2^2×3^2× 7×29=7308 Calculate LCM, the least ... /10 </13 </19

Find the volume V of the described solid S. The base of S is a circular disk with radius 4r. Parallel cross-sections perpendicular to the base are squares.

Answers

Answer:

(1024/3)r^3.

Step-by-step explanation:

Step one: So, we have that x^2 + y^2 = 4^2 × r^2(when z component = 0) . Hence, there is the need to make y^2 the subject of the formula.

Step two: 4y^2 = 16r^2 - x^2. Where 4 ×(16r^2 - x^2) is the the cross sectional area.

Step three: the next thing to do here is to integrate the cross sectional area making 4r and -4r the upper limit and lower limit for the integration.

Step four: the integration will then give a product (16 × 64)/3 A = (1024/3)r^3.

the twelve inch square tiles are shipped in boxes of sixteen pieces per box. each of the boxes weighs twenty four pounds. approximately how many ounces does each tile weigh?

Answers

Answer:

1.411764706

Step-by-step explanation:

24/17=1.411764706

Find the values of x and y in these equations. (x + yi) + (4 + 6i) = 7 − 2i (equation A) (x + yi) − (-8 + 11i) = 5 + 9i (equation B)

Answers

Answer:

Step-by-step explanation:

(x+yi)+4+6i=7-2i

x+yi=7-2i-4-6i

x+yi=3-8i

equating real and imaginary parts

x=3,y=-8

B.

x+yi=5+9i+(-8+11i)

x+yi=5+9i-8-11i

x+yi=-3-2i

equating real ,and imaginary parts

x=-3

y=-2

The value of x  and y for equation A is

[tex]x=3, y=-8[/tex]

The value of x  and y for equation B is

[tex]x=-3 , y=20[/tex]

Given :

[tex](x + yi) + (4 + 6i) = 7 - 2i[/tex]

find the value of x  and y in the given equation

Lets open the parenthesis and combine like terms

Equate the real and imaginary part to solve for x  and y

[tex]\left(x+4\right)+\left(y+6\right)i=7-2i\\x+4=7\\x=3\\\\y+6=-2\\y=-2-6\\y=-8[/tex]

The value of x=3  and y=-8

Now we do the same with second equation

[tex](x + yi) - (-8 + 11i) = 5 + 9i\\\\x+8+yi-11i=5+9i\\\left(x+8\right)+\left(y-11\right)i=5+9i\\x+8=5\\x=-3\\\\y-11=9\\y=9+11\\y=20[/tex]

The value of x  and y is x=-3 and y=20

Learn more : brainly.com/question/18552411

I flip a fair coin 17 times. Answer the following questions:
a. What is the probability of getting 9 heads?
b. What is the probability of getting 2 heads?
c.. What is the probability of getting 1 tail?
d. What is the probability of getting 14 or more heads?
e. What is the probability of getting 17 tails?

Answers

Answer:

A) 0.1855

B) 0.0010376

C) 0.0001297

D) 0.006363

E) 0.000007629

Step-by-step explanation:

In calculation of a probability, we normally take the ratio of the number of ways to meet a certain condition (i.e. the numerator) divided by the number of ways to pick from a pool (i.e. the denominator).

So what are the number of ways the flip of a coin 17 times can come out?

A coin has a head and tail, so each toss will have two possible results. If we toss once, we have 2 possible results. If we toss, twice we have 2² = 4 possible results.

If we toss thrice, we have 2³ = 8 possible results, etc.

Thus, for 17 tosses, we will have 2^(17) = 131072 possible results.

A) To achieve the probability of getting 9 heads, we will use combination formula;

C(n, k) = n! / (k!(n - k)!)

In this case, n = 17 and k = 9

So,

P(9 heads) = 17! / (9!(17 - 9)!) = 24310

Thus,

P(9 heads in 17 tosses of a fair coin) = 24310/131072 = 0.1855

B) Similar to A above;

P(2 heads) = 17! / (2!(17 - 2)!) = 136

Thus,

P(2 heads in 17 tosses of a fair coin) = 136/131072 = 0.0010376

C) Similar to A above;

P(1 tail) = 17! / (1!(17 - 1)!) = 17

Thus,

P(1 tail in 17 tosses of a fair coin) = 17/131072 = 0.0001297

D) probability of getting 14 or more heads?

Since, there are 17 tosses, this will be;

P(14 or more heads in 17 tosses) = P(14 heads in 17 tosses) + P(15 heads in 17 tosses) + P(16 heads in 17 tosses) + P(17 heads in 17 tosses)

P(14 heads) = 17! / (14!(17 - 14)!) = 680

P(15 heads) = 17! / (15!(17 - 15)!) = 136

P(16 heads) = 17! / (16!(17 - 16)!) = 17

P(17 heads) = 17! / (1!(17 - 17)!) = 1

Thus;

P(14 heads in 17 tosses) = 680/131072 = 0.005188

P(15 heads in 17 tosses) = 136/131072 = 0.0010376

P(16 heads in 17 tosses) = 17/131072 = 0.0001297

P(1 head in 17 tosses) = 1/131072 = 0.00000763

P(14 or more heads in 17 tosses) = 0.005188 + 0.0010376 + 0.0001297 + 0.00000763 = 0.006363

E) Similar to A above;

P(17 tails) = 17! / (17!(17 - 17)!) = 1

Thus,

P(17 tails in 17 tosses of a fair coin) = 1/131072 = 0.000007629

Box A contains 5green and 7 red balls. Box B contains 3green, 3 red and 6 yellow balls. A box is sleeted at random and a ball is drawn at random from it. What is the probability that the drawn ball is green?

Answers

Answer:

5/48

Step-by-step explanation:

Given

the sample space for box A

green balls = 5

red balls= 7

sample size= 5+7= 12

the sample space for box B

green balls = 3

red balls= 3

yellow balls= 6

sample size= 3+3+6= 12

The probability of drawing a green ball from box A= 5/12

The probability of drawing a green ball from box B= 3/12= 1/4

Therefore the probability of picking a green ball from either of the boxes at random is =[tex]=\frac{5}{12} *\frac{1}{4}[/tex][tex]=\frac{5}{48}[/tex]

Which equation, when solved, gives 8 for the value of x?
A: 5/2x+7/2x=3/4x+14

B: 5/4x-9=3/2x-12

C: 5/4x-2=3/2x-4

D: 5/2x-7=3/4x+14

Answers

Answer:

Step-by-step explanation:

C. 5x/4-2=3x/2-4

 

 5x/4 -2=6x/4-4

   +4       +4

5x/4+2=6x/4

-5x/4

2=x/4

*4

x=8

   

   

Answer:

your answer is C

Step-by-step explanation:

An airplane descends during the last hour of it's flight to prepare for landing. It's altitude changes at an average of -0.15 km per minute for those 60 minutes. Write an expression to represent the total change in the airplane's elevation. ( plz answer, will give brainliest )

Answers

Answer:

-.15 km/ minute * 60 minutes

-9 km

Step-by-step explanation:

The rate is -.15 km per minute

We have 60 minutes

distance = rate  times time

change in elevation is the same as the distance change

change in elevation = -.15 km/ minute * 60

   change in elevation =-9 km

Answer:

(0.15 km/min) * (60 min)

Step-by-step explanation:

We see that the plane descends 0.15 kilometres every minute over the span of 60 minutes.

Use the distance-rate-time formula: d = rt, where d is the distance, r is the rate, and t is the time.

Here, our rate is r = 0.15 km/min and our time is t = 60 minutes. Then the total change in elevation is:

d = rt

d = 0.15 * 60 = 9 km

Note that we disregard the negative sign from -0.15 km/min because the question is asking for the change in elevation. Change is never a negative value.

Hence, the expression will be: 0.15 * 60, which simplifies to 9 km.

~ an aesthetics lover

Solve the inequality a−32<1 and write the solution in interval notation, using improper fractions if necessary.

Answers

Answer:

( -∞ , 33 )

Step-by-step explanation:

To solve the inequation a-32 < 1, we need to sum on both sides 32, as:

a - 32 + 32 < 1 + 32

a < 33

It means that the solutions are all the number that are smaller than 33 or in interval notation it would be:

( -∞ , 33 )

Where 33 is not included in the interval.

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