In an experiment, a 88.11 mL sample of unknown silver nitrate solution was treated with 9.753 g of sodium chloride, resulting in 4.576 g of precipitate. Calculate the molarity of the silver nitrate solution

Answer:

Answer:

Explanation:

"Magnesium is an alkaline earth metal, and forms a Mg2+ ion. And carbonate ion, CO2−3 , has an equal an opposite charge. And thus the ionic species is MgCO3"

Ionic substances are composed of two or more ions. The compound MgCO3 is composed of  Mg²+ and CO₃²- ions.

The term ions refer to charged species that are present in a system. The compound MgCO₃ is an ionic substance and ionic substances are composed of ions.

As such, the compound MgCO₃ is composed of the ions  Mg²+ and CO₃²-.

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Answer:

Your body naturally gets rid of its waste and in your community/home also has sewers and gutters to also get rid of waste.

Answer:

these elements do not have the same masses.

Answer:

Explanation:

Slate is a fine-grained, foliated metamorphic rock that is created by the alteration of shale or mudstone by low-grade regional metamorphism. It is popular for a wide variety of uses such as roofing, flooring, and flagging because of its durability and attractive appearance.

Answer:

Deep within the Earth's crust rocks can be put under huge pressures and temperatures are very high. These conditions can cause the minerals in the rock to change. This process is called metamorphism. Limestone can change into marble, shale and mudstones into slate, and igneous rocks like granite can turn into gneiss.

Explanation:

Slate is a fine-grained, foliated metamorphic rock that is created by the alteration of shale or mudstone by low-grade regional metamorphism. It is popular for a wide variety of uses such as roofing, flooring, and flagging because of its durability and attractive appearance.

Answer:

what happened to it, have the gone extinct

Answer:

20000 Mg

Explanation:

Answer:

Temperature = 0.605°C

Total enthalpy at 300kpa = 545.2 kJ

Total enthalpy at 600kpa = 846.45 kJ.

Explanation:

Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.

Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.

The first thing to do is to determine the value for the specific volume of saturated liquid.

At 300 kpa, the specific volume of saturated liquid,n is given below as;

300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.

Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.

300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).

n = 0.0679 m^3/kg.

The second thing to do is to determine the value of the specific volume.

Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.

Determine the enthalpy of the mixture,b(I). This is given below as;

300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).

b(I) = 198.125 kJ/Kg.

Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.

b = 54.517 KJ/Kg.

Total enthalpy = 10 × 54.517 = 545.17 kJ.

Temperature can be Determine as below;

300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.

Temperature = 0.605°C.

Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10

Total enthalpy at 600kpa = 846.45 kJ.

Answer:

Oxygen sodium hydrogen iron potassium chlorine are elements

Water is a compound

And magnesium ion is cation.

Morever oxygen hydrogen and chlorine are gases

Water and magnesium ion are liquid

And sodium iron potassium are solids

Explanation:

Answer:

False, hope this helps!

Explanation:

Answer:

Think 12 units

Explanation:

Because it represents the hands of the clock

Answer:

4 digits that are 7,5,0,0

Explanation:

Answer:

yes it is true.

Ice floats on the surface of water because ice is less dense than liquid water

Explanation:

Answer:

Metal paper clips hope it helps

Answer:

C₂H₄O

Explanation:

In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.

Moles CO₂ = Moles C:

11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =

3.216g C

Moles H₂O = 1/2 moles H:

4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =

0.537 mol H * (1g/mol) = 0.537g H

Mass O to find moles O:

5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O

Ratio of atoms -Dividing in 0.134 moles-:

C = 0.268mol C / 0.134 mol O = 2

H = 0.537mol H / 0.134 mol O = 4

O = 0.134mol O / 0.134 mol O = 1

Empirical formula is:

Explanation:

first one because absolute dating is a thing for rock layers

Answer:

0.77 g

Explanation:

Step 1: Write the balanced equation

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Step 2: Calculate the moles corresponding to 0.91 g of AgNO₃

The molar mass of AgNO₃ is 169.87 g/mol.

0.91 g × 1 mol/169.87 g = 5.4 × 10⁻³ mol

Step 3: Calculate the moles of AgCl produced from 5.4 × 10⁻³ moles of AgNO₃

The molar ratio of AgNO₃ to AgCl is 1:1. The moles of AgCl produced are 1/1 × 5.4 × 10⁻³ mol = 5.4 × 10⁻³ mol.

Step 4: Calculate the mass corresponding to 5.4 × 10⁻³ moles of AgCl

The molar mass of AgCl is 143.32 g/mol.

5.4 × 10⁻³ mol × 143.32 g/mol = 0.77 g

Answer:

0.01875kg/m^3

Explanation:

mass=0.003kg

volume=0.16m

density=mass/volume

=0.003/0.16

=0.01875kg/m^3

Answer:

its b

Explanation:

just did the test on A P E X

If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.

A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.

The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

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Answer: The number of moles of [tex]O_2[/tex] are 6.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

Given mass = 192 g

Molar mass = 32 g/mol

[tex]\text{Number of moles}=\frac{192g}{32g/mol}=6mol[/tex]

The number of moles of [tex]O_2[/tex] are 6.

Answer:5.3 grams AgNO3

Explanation:

To solve your problem, take a look at the definition of molality (m):

moles of solute/kg of solvent

You are given the grams of solvent (water) to find the grams of silver nitrate.

First, convert 250 grams to kg:

250 g * 1 kg / 1000g = 0.250 kg

Now that you have the kg of solvent, you can solve for the moles of solute:

kg of solvent * molality = moles of solute

0.250 kg * 0.125 m = 0.03125 mol AgNO3

You can convert the number of moles to grams using the molar mass of AgNO3, which is 169.872 g/mol:

moles of solute * molar mass of solute = grams of solute

0.03125 mol AgNO3 * 169.872 g/mol = 5.3085 g

Because your question provides two significant digits, you must round this number to get the final answer:

5.3 grams AgNO3

I hope this helps!

Answer:

Work: 392400 J Power developer: 19620

Answer:

2 O atoms

hope it helps....

Answer:

2O is the correct answer

This question is incomplete, the complete question is;

The times of first sprinkler activation (in seconds) for a series of tests of fire-prevention sprinkler systems that use aqueous film-forming foam is as follows; 27 41 22 27 23 35 30 33 24 27 28 22 24

( see " use of AFFF in sprinkler systems," Fire technology, 1975: 5)

The system has been designed so that the true average activation time is supposed to be at most 25 seconds.

Does the data indicate the design specifications have not been met?

Test the relevant hypothesis at significance level 0.05 using the P-value approach  

Answer:

since p-value (0.042299) is lesser than the level of significance ( 0.05)

We Reject Null Hypothesis

Hence, There is no sufficient evidence that the true average activation time is at most 25 seconds

Explanation:

Given the data in the question;

lets consider Null and Alternative hypothesis;

Null hypothesis H₀ : There is sufficient evidence that the true average activation time is at most 25 seconds

Alternative hypothesis H₁ : There is no sufficient evidence that the true average activation time is at most 25 seconds

i.e

Null hypothesis H₀ : μ ≤ 25

Alternative hypothesis H₁ :  μ > 25

level of significance σ = 0.05

first we determine the sample mean;

[tex]x^{bar}[/tex] = [tex]\frac{1}{n}[/tex]∑[tex]x_{i}[/tex]

where n is sample size and ∑[tex]x_{i}[/tex] is summation of all the sample;

=  [tex]\frac{1}{13}[/tex]( 27 + 41 + 22 + 27 + 23 + 35 + 30 + 33 + 24 + 27 + 28 + 22 + 24 )

=   [tex]\frac{1}{13}[/tex]( 363

sample mean [tex]x^{bar}[/tex] = 27.9231

next we find the standard deviation

s = √( [tex]\frac{1}{n-1}[/tex]∑([tex]x_{i}-x^{bar}[/tex])²

x                    ([tex]x_{i}-x^{bar}[/tex])                       ([tex]x_{i}-x^{bar}[/tex])²

27                   -0.9231                          0.8521

41                    13.0769                        171.0053

22                  -5.9231                          35.0831  

27                  -0.9231                          0.8521

23                  -4.9231                          24.2369

35                  7.0769                          50.0825

30                  2.0769                          4.3135

33                  5.0769                          25.7749

24                  -3.9231                          15.3907

27                  -0.9231                          0.8521

28                  0.0769                          0.0059

22                 -5.9231                          35.0831  

24                 -3.9231                          15.3907

sum                                                    378.9229

so ∑([tex]x_{i}-x^{bar}[/tex])² = 378.9229

∴

s = √( [tex]\frac{1}{13-1}[/tex] ×378.9229 )

s = √31.5769

standard deviation s = 5.6193

now, the Test statistics

t = ( [tex]x^{bar}[/tex] - μ ) / [tex]\frac{s}{\sqrt{n} }[/tex]

we substitute

t = ( 27.9231 - 25 ) / [tex]\frac{5.6193}{\sqrt{13} }[/tex]

t = 2.9231 / 1.5585

t = 1.88

now degree of freedom df = n - 1 = 13 - 1 = 12

next we calculate p-value

p-value = 0.042299 ( using Execl's ( = TDIST(1.88,12,1)))

Here x=1.88, df=12, one tail

now we compare the p-value with the level of significance

since p-value (0.042299) is lesser than the level of significance ( 0.05)

We Reject Null Hypothesis

Hence, There is no sufficient evidence that the true average activation time is at most 25 seconds

Answer:

The correct answer is - the number of moles of solute per liter of solution.

Explanation:

The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:

M = n/v

Where n is the number of moles of the solute and,

v is the volume of solution (in liters normally)

It is worldwide used measurment for the concentration.

Answer: White or Black

Explanation: White is a blank color used for coloring so if you shine a certain color on it it'll show and along goes with black. :)