Answer:
Education –> Mortality –> Fertility rates
Education –> Fertility rates
Step-by-step explanation:
Education and fertility is a key role to grow a large population. But if the mortality rate is low families tend to have less children.
Ms. Guzman asked each of her homeroom students’ “What did you make on your Unit 6 science test”? She graphed the results on the line plot. Which is the best description of the data? (AKS 42) The range is 35, there is a peak at 90, and there are no outliers or gaps. The mode is 90, the data is skewed to the right, and there is a gap at 70 & 75. The mean is about 90, gaps at 70-75, mode at 85 and 100, and the data is skewed to the left. The median is 90, the distribution is asymmetrical, and there are gaps from 70- 75, and an outlier at 65. The median is 90, the distribution is asymmetrical, and there are gaps at 60, 70-75, and an outlier at 65.https://d3rqz33hmpm7kb.cloudfront.net/2021-03-08/5f50fc4b574c12225922587b/604618b510ed2dcf941eee43_rich-text-file-2021-03-08T12-2-46-770Z.imagepng
1. (10 points) Let f(x) = −cos(x). Compute ˆφ = c0π0 + c1π1 where π0 = 1 and π1 = x.
Compute the discrete approximation using
• x0 = π /2 and x1 = (3π)/4 .
• f( π/2 ) = 0 and f( (3π)/4 ) = √ 1 2 .
You may use the XT X|XT Y method or A⃗c = ⃗b method.
2. (10 points) Let f(x) = x 5 . Compute ˆφ = c0π0 + c1π1 for the domain 0 ≤ x ≤ 1. Let π0 = x and π1 = x 2 . • Compute the continuous approximation. • Do not round.
3. (10 points) Suppose you have just finished approximating f(x) = x 3 for 0 ≤ x ≤ α and ended up with φˆ(α, x) = 1 2 α 2x. (a) (8 points) Evaluate E2 (α, x) = ||f − φˆ||2 . (b) (2 points) After you have evaluated ||f − φˆ||2 for α, plug in α = 1 and simplify.
4. (10 points) Reconcile the XT X|XT Y and A| ⃗b methods for the discrete case. More specifically, show that the two are equivalent for n polynomial basis functions (π0, π1, . . . πn−1) and k points.
Topics Covered:
Least square Approximation
Reconcile the XTX|XTY and Ab Methods
Seven students volunteered for a comparison of study guides for an advanced course in mathematics. They were randomly assigned, four to study guide A and three to study guide B. All were instructed to study independently. Following a two-day study period, all students were given an examination about the material covered by the guides, with the following results:Study Guide A scores: 68; 77; 82; 85Study Guide B scores: 53; 64; 71Perform a randomization test by listing all possible ways that these students could have been randomized to two groups. There are 35 ways. For each outcome, calculate the difference between sample averages. Finally, calculate the two-sided p-value for the observed outcome
Answer:
Step-by-step explanation:
From the given question; we can use the R software to program the combination function that generates all the combinations.
options(digits =2(
scores<- c(68,77,82,85,53,64,71)
groupA <- combn(scores,4)
groupB <- apply(groupA,2, function(x) scores[! (scores %in% x) ] )
colnames(groupA) <- colnames(groupB) <- paste("G", 1:35, sep"")
The accompanying 35 groupings (G1 to G35) contain all potential ways these understudies can be randomized under the null hypothesis
Group A
[tex]\text{G1 \ G2 \ G3 \ G4 \ G5 \ G6 \ G7 \ G8 \ G9 \ G10\ G11\ G12 \ G13 \ G14}[/tex]
[tex]\text{68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68 \ \ 68}[/tex]
[tex]\text{77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 77 \ \ 82 \ \ 82 \ \ 82 \ \ 82}[/tex]
[tex]\text{82 \ \ 82 \ \ 82 \ \ 82 \ \ 85 \ \ 85 \ \ 85 \ \ 53 \ \ 53 \ \ 64 \ \ 85 \ \ 85 \ \ 85 \ \ 53}[/tex]
[tex]\text{85\ \ 53 \ \ 64 \ \ 71 \ \ 53 \ \ 64\ \ 71\ \ 64 \ \ 71 \ \ 71 \ \ \ 53 \ \ \ 64 \ \ 71 \ \ 64}[/tex]
[tex]\text{G15 G16 G17 G18 G19 G20 G21 G22 \ G23 \ G24 \ G25 \ G26 \ G27}[/tex]
[tex]\text{68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 68 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77 \ \ \ 77}[/tex]
[tex]\text{82 \ \ \ 82 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 53 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ 85}[/tex]
[tex]\text{53 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 64 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 53}[/tex]
[tex]\text{71\ \ \ \ 71\ \ \ \ 64\ \ \ \ \ 71\ \ \ \ 71\ \ \ \ 71\ \ \ \ 53\ \ \ \ 64\ \ \ \ 71\ \ \ 64\ \ \ \ 71\ \ \ \ 71\ \ \ \ 64}[/tex]
[tex]\text{G28 G29 G30 G31 G32 G33 G34 \ G35} \\ \\ 77 \ \ \ \ 77 \ \ 77 \ \ \ \ 82\ \ \ \ 82 \ \ \ 82 \ \ \ 82 \ \ \ \ \ 85 \\ \\ 85 \ \ \ 85 \ \ \ 53 \ \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ \ 53 \ \ \ 53 \\ \\ 53 \ \ \ 64 \ \ 64 \ \ \ 53 \ \ \ \ 53 \ \ \ 64 \ \ \ \ 64\ \ \ 64 \\ \\ 71 \ \ 71 \ \ \ 71 \ \ 64 \ \ \ 71 \ \ \ \ 71 \ \ \ \ 71 \ \ \ \ 71[/tex]
Group B
[tex]\text{G1 \ G2 \ G3\ G4\ \ G5\ \ G6\ \ G7\ \ G8 \ \ G9\ \ G10\ \ G11\ \ G12\ \ G13\ G14 \ G15}[/tex]
[tex]\tet{53 \ \ 85 \ \ \ \ 85 \ \ \ \ 85\ \ \ \ 82 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 77\ \ \ \ 77\ \ \ \ 77\ \ \ \ 77\ \ \ \ 77}[/tex]
[tex]\text{64 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 85 \ \ \ 85 \ \ \ 85 \ \ \ 64 \ \ \ 53 \ \ \ 53 \ \ \ 85 \ \ \ 85}[/tex]
[tex]\text{71 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 64 \ \ \ 53 \ \ \ 71 \ \ \ 71 \ \ \ 64 \ \ \ 71 \ \ \ 64}[/tex]
[tex]\text{G16 \ G17 \ G18 \ G19 \ G20 \ G21 \ G22\ \ G23\ \ G24\ \ G25 \ \ G26 \ \ G27\ \ G28}[/tex]
[tex]\text{77\ \ \ \ 77\ \ \ \ 77\ \ \ \ \ 77\ \ \ \ \ 77\ \ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ 68\ \ \ \ \ 68\ \ \ \ \ 68\ \ \ \ \ 68}[/tex]
[tex]\text{85 \ \ \ \ 82\ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 82 \ \ \ \ 64 \ \ \ \ 53 \ \ \ \ 53 \ \ \ \ 85 \ \ \ \ 85\ \ \ \ 85 \ \ \ \ 82\ \ \ \ 82}[/tex]
[tex]\text{53\ \ \ \ 71\ \ \ \ 64\ \ \ \ 53\ \ \ \ 85\ \ \ \ 71\ \ \ \ 71\ \ \ \ 64\ \ \ \ 71\ \ \ \ 64\ \ \ \ 53\ \ \ \ 71\ \ \ \ 64}[/tex]
[tex]\text{ G29 \ G30\ G31 \ G32 \ G33 \ G34 \ G35} \\ \\ \text{68 \ \ \ 68 \ \ \ 68 \ \ \ \ 68 \ \ \ \ 68 \ \ \ 68 \ \ \ \ \ 68} \\ \\ \text{82 \ \ \ 82 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77 \ \ \ \ 77} \\ \\ \text{53 \ \ \ 85 \ \ \ \ 71 \ \ \ \ 64 \ \ \ \ 53\ \ \ \ 85 \ \ \ \ 82} \\ \\[/tex]
The accompanying data below computes the distinctions for each group:
[tex]difference <- colMeans(groupA) - colMeans(groupB)[/tex]
[tex]\text{G1 G2 G3 G4 G5 G6 G7 G8 G9 \ G10 G11 G12 G13 G14 G15} \\ \\ \text{15 -3.3 3.1 7.2 -1.6 4.8 8.9 -14 -9.8 -3.3 1.3 \ 7.8 \ 12 \ -11 \ \ -6.8}[/tex]
[tex]\text{G16 G17 G18 G19 G20 G21 G22 G23 G24 G25 G26 G27 G28} \\ \\ \text{-0.42 \ -9.2\ -5.1\ 1.3 \ -17\ \ 6.6 \ \ 13 \ 17 \ \ -5.7\ -1.6 \ \ 4.8 \ \ -3.9 \ \ 0.17}[/tex]
[tex]\text{ G29\ \ G30 \ G31 \ G32 \ \ G33 \ G34 \ \ G35} \\ \\ \text{6.6 \ \ \ -12 \ \ \ -1 \ \ \ 3.1 \ \ \ 9.5 \ \ \ -9.2 \ \ \ -7.4}[/tex]
The two-sided p-value is the extent of contrasts between test midpoints as large or bigger in supreme value than the primary group. The cat function makes the outcomes simpler to peruse.
p <- sum (aba(difference)>=difference[1])/35
cat(p)
= 0.086
the truth table for the formula (X → Y ) ∨ (Z → ¬X)
Answer:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
Step-by-step explanation:
Let [tex]A[/tex] denote a Boolean variable.
The negation of [tex]A[/tex] ([tex]\lnot A[/tex]) is false if when [tex]\!A[/tex] is true, and true when [tex]A\![/tex] is false. In a truth table:
[tex]\begin{array}{c||c} A & \lnot A \\ \cline{1-2} \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c||c} A & \lnot A \\ \hline \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
Let [tex]B[/tex] denote another Boolean variable. The material implication "[tex]A[/tex] implies [tex]\!B[/tex]" ([tex]A \to B[/tex]) is true unless [tex]B\![/tex] is false when [tex]A\![/tex] is true.
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex]
The logical or "[tex]A[/tex] or [tex]B[/tex]" is true when either [tex]A\![/tex] or [tex]B\![/tex] is true (and also when both are true.)
[tex]\begin{array}{c|c||c} A & B & A \lor B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm T \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F\end{array}[/tex]
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
Start by finding the value of [tex]\lnot X[/tex], [tex](X \to Y)[/tex], and [tex](Z \to \lnot X)[/tex] for each of the [tex]2^3 = 8[/tex] possible combinations of [tex]X[/tex], [tex]Y[/tex], and [tex]Z[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \cline{1-6} \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \cline{1-6} \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
The value of [tex](X \to Y) \lor (Z \to \lnot X)[/tex] is true whenever either [tex](X \to Y)[/tex] or [tex](Z \to \lnot X)[/tex] is true (or both.) The combination [tex]X = \rm T[/tex], [tex]Y = \rm F[/tex], and [tex]Z = \rm T[/tex] is the only one among the eight where neither [tex](X \to Y)\![/tex] nor [tex](Z \to \lnot X)\![/tex] is true. [tex](X \to Y) \lor (Z \to \lnot X)\![/tex] would evaluate to true for all other combinations.
Hence, the truth table would be:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
An endangered species only has 350 animals left in the wild. If the species is decreasing by 7.5% each year, how many animals are left after 2 years?
Answer:
350 X 7.5 % = 26.25
26.25 + 2 = 52.5
350 - 53 = 297 answer
Step-by-step explanation:
What is the volume of a cone with a radius of 6 inches and a height of 15 inches? (Use 3.14 for π.)
188.4 in. 3
565.2 in. 3
726.8 in. 3
1,695.6 in. 3
Thx
Answer:
1,695.6 in. 3
Step-by-step explanation:
The sum of two numbers is less than 4. If we subtract the second number from
the first, the difference is greater than 1.
What is the inequality that would represent: The sum of two numbers is
less than 4?*
1 point
Your answer?
Answer:
x+y<4
Step-by-step explanation:
let the numbers be x and y
x+y<4
x-y>1
ayo boys, just remember, she aint it
Answer:
Imao
Step-by-step explanation:
Help me by please this is kinda hard for my child and I forgot it
a dog trainer has 104ft of fencing that will be used to create a retangular work area for dogs. If the trainer wants to enclosed an area of 532ft what will be the dimensions of the work area?
please help me i really need help please please
Answer:
it's D all of the above
Step-by-step explanation:
.......
Which statement is correct?
Thank you for anyone who answers
Answer:
I believe the correct answer is C
What is the area of the shaded region?
Answer:
65
Step-by-step explanation:
( (23 * 13) / 2 ) - ( (13 * 13) / 2 ) = ( 299 / 2 ) - ( 169 / 2 ) = 149.5 - 84.5 = 65
Numbers are slightly unclear but I think this is right.
What is the sum of the interior angles of nonregular hexagons?
Answer:
They add up to 720 degrees
Answer:
360 I think. Hope i helped! :)
Guys, this is important!! My assignment is worth 100 points. (not the question but the assignment!) Solve this graph for me and give an explanation and label everything.
Answer:
Step-by-step explanation:
From the given table, it can be deduced that;
scale factor = [tex]\frac{20}{4}[/tex]
= 5
Thus the values of Monsters were multiplied by 4 to determine that of the rooms.
1. When the value of room is 9, then that of Monsters is;
5 x 9 = 45
2. When the value of Monster is 30, then that of room is;
[tex]\frac{30}{5}[/tex] = 6
3. When the value of room is 13, then that of Monsters is;
13 x 5 = 65
4. When the value of Monster is 35, then that of room is;
[tex]\frac{35}{5}[/tex] = 7
The required table is attached to this answer for further clarifications.
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen at random from box A and placed in box B. Now, a poker chip is chosen at random from those now in box B. What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
Answer:
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Coin chosen from box B is red.
Event B: Blue poker chip transferred.
Probability of choosing a red coin:
7/10 of 4/9(red coin from box A)
6/10 of 5/9(blue coin from box A). So
[tex]P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444[/tex]
Blue chip transferred, red coin chosen:
6/10 of 5/9. So
[tex]P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333[/tex]
What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172[/tex]
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Help me outtttttt !!!!!!!!!
Answer:
i think its the one on the left. The blue one concine.
Step-by-step explanation:
7 points
Sue has a sticker collection with 36 red, 72 blue, and 18 red. She wants to
arrange the stickers in equal rows with only one type of sticker in each
row. Which of the following choices could Sue choose? *
18
4
12
8
how do you do this??
Answer: A. B. and C. are correct
Step-by-step explanation: It's easy when you realize that f(x) is really just y in disguise, because y is a secret agent. But really those are the correct answers.
Pls help Which algebraic rule describes the transformation?
Answer:
the answer will be B (x,y) --> (x,-y)
Answer:
I think the answer is B (x, y) ➡ (x, -y)
Step-by-step explanation:
five people were asked about the time in a week they spend in doing social work in their community they said 7,10,13,20,15 hours respectively.
which methametical concept is used in this question??
what value is depicted in this question??
Answer:
Mean time and 13
Step-by-step explanation:
Given that
here is a five people and they spend the work in 7,10,13,20,15 hours respectively
Therefore here the concept i.e. used is average time or the meantime
And, this can be determined below:
= Sum of observations ÷ number of observations
= (7 + 10 + 13 + 20 + 15) ÷ 5
= 13
Sammy's home has a value of $180,000. If the property tax rate where he lives is 1.245% how much does he pay in property taxes? Enter your answer rounded to the nearest dollar, such as: $3253.
Answer:
2241
180,000 x .01245= 2241
Which of the following temperatures is the COLDEST?
P: -13
Q: 59
R: -15
S: 32
Answer:
the temperature which is coldest is R.-15
Ms. Day drew a rectangle
on the board with a width
of 14 cm and a diagonal
length of 50 cm. Find the
length of this rectangle in
centimeters.
Answer:
700
Step-by-step explanation:
Find the positive of x that makes the equation true.
x^2 = 225
Answer:
x = 15
Step-by-step explanation:
15 * 15 = 225
Answer:
X = 15
Step-by-step explanation:
This is because if you square 15, you get 225.
Please help is for nowwww
Answer:
Draw a line going from 360 on the vertical line to 30 on the horizontal line.
Step-by-step explanation:
12 meters a minute. 30 minutes. 360 meters in total.
At noon, a tank contained 20 cm of water. After several hours, it contained 18 cm of water. What is the
percent decrease of water in the tank?
The percent decrease of water in the tank is
%.
Answer:
10%Step-by-step explanation:
Percentage decrease = Difference/Original value
So,
Percentage decrease
[tex] = \frac{2}{20} \times 100 \\ = 2 \times 5 \\ = 10[/tex]
So there fore the percentage decrease is 10%
A desk is on sale for $217, which is 38% less than the regular price. What is the regular price?
126 (x +77)
find x!!
Linear Functions Unit Portfolio Directions: Complete each of the tasks outlined below. Cab companies often charge a flat fee for picking someone up and then charge an additional fee per mile driven. Pick a U.S. city and research the rates of two different cab companies in that city. Find companies that charge different amounts per mile and have different flat fees. If you have trouble finding this information for two companies, you can make up what you think would be reasonable prices for a cab's flat rate and a cab's rate per mile. Task 1 a. For the first company, express in words the amount the cab company charges per ride and per mile. b. Write an equation in slope-intercept, point-slope, or standard form. Explain why you chose the form you did. C. What do the slope and y-intercept mean in the context of this problem? Hint: What do you pay when you step into the cab? Task 2 For the second company, express in a table the cost of the cab ride given the number of miles provided. A. Write and equation in slope-intercept, point-slope, or standard form. Explain why you chose the form you did. B. What does the slope mean in the context of the problem? Task 3 Cabs use a valuable commodity—gas! Research average gas prices from 2005-2015 for the city you chose. If you can't find this information for your specific city, you can research national gas price averages instead. A. Create a table showing the average gas price each year. B. Create a scatter plot of the data in your table. C. What equation models the data? What are the domain and range of the equation? Do you think your equation is a good fit for the data? Explain how you determined your answers. D. Is there a trend in the data? Does there seem to be a positive correlation, a negative correlation, or neither? How much do you expect gas to cost in 2020? Explain.
Answer:
Hope this helps you!!!
Have a great day!!!