Answer:
a. t>w
Step-by-step explanation:
Sin t= 0.29
t = sin^-1(0.29)
t= 16.86°
Sin w= 0.43
W = sin^-1(0.43)
W= 25.47°
Angles in the second quadrant are positive in sine and they are generally determined by subtracting the initial value from 180°
For t= 180°-16.86°
t = 163.14°
For w = 180°-25.47°
W= 154.53°
163.14°>154.53°
t>w
The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with 10-meter sides.
The heights of the pyramids are the same.
The volume of pyramid Als
y the volume of pyramid B. If the helght of pyramid B increases to twice that of pyramid A, the
new volume of pyramid B is
the volume of pyramid A.
Answer:
a. The volume of Pyramid A is double that of Pyramid B.
b. The new volume of B is equal to the volume of A.
Step-by-step explanation:
The base of pyramid A is a rectangle with length 10 meters and width 20 meters.
The base of pyramid B is a square of side length 10 meter.
Both pyramids have the same height, h.
The volume of a pyramid is given as:
V = lwh / 3
where l = length
w = width
h = height
The volume of Pyramid A is:
V = (10 * 20 * h) / 3 = 66.7h cubic metres
The volume of Pyramid B is:
V = (10 * 10 * h) / 3 = 33.3h cubic metres
By comparing their values, the volume of Pyramid A is double that of Pyramid B.
If the height of B increases to 2h, its new volume is:
V = (10 * 10 * 2h) / 3 = 66.7h cubic metres
The new volume of B is equal to the volume of A.
Don’t know this one
Answer:
B
Step-by-step explanation:
The answer is B because in order for the square root of a number to be equal to another number, the answer squared should be the number under the square root.
B. [tex](-4)^2\neq -16[/tex].
Hope this helps.
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFraction 8 Over 15 EndFraction of the same row left. How much wood did he burn over the winter?
Answer:
3/10
Step-by-step explanation:
We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:
Ambitious
First we have to do is that the denominator is the same.
in the case of 5/6 it would be 25/30
and for 8/15 it would be 16/30
Now if we can do the subtraction and it would be:
25/30 - 16/30 = 9/30 or what equals 3/10
3/10 was the amount of wood he burned in the winter
Answer:
D) 3/10 row
Step-by-step explanation:
You want to be able to withdraw $4000 a month for 30 years how much would you need to have in your account with an APR of 3.4% to accomplish this goal
Answer:
$904,510.28
Step-by-step explanation:
If we assume the withdrawals are at the beginning of the month, we can use the annuity-due formula.
P = A(1 +r/n)(1 -(1 +r/n)^(-nt))/(r/n)
where r is the APR, n is the number of times interest is compounded per year (12), A is the amount withdrawn, and t is the number of years.
Filling in your values, we have ...
P = $4000(1 +.034/12)(1 -(1 +.034/12)^(-12·30))/(.034/12)
P = $904,510.28
You need to have $904,510.28 in your account when you begin withdrawals.
Answer:
You need to have $904,510.28 in your account when you begin
Find the equation of a line perpendicular to 4x+2y=3 that contains the point (1,5)
Answer:
x -2y = -9
Step-by-step explanation:
We can start by swapping the coefficients of x and y, then negating one of them. We can finish by evaluating the expression at the given point to find the constant.
2x -4y = constant
2(1) -4(5) = -18 = constant
So, an equation could be ...
2x -4y = -18
We notice that all of the coefficients of this equation are divisible by 2, so we can remove a factor of 2 from the equation:
x -2y = -9
Find the value of x.
Answer:
[tex]\huge\boxed{x=\sqrt{66}}[/tex]
Step-by-step explanation:
ΔADC and ΔABD are similar (AAA)
Therefore the cooresponging sides are in proportion:
[tex]\dfrac{AD}{AC}=\dfrac{AB}{AD}[/tex]
Substitute
[tex]AD=x;\ AC=6+5=11;\ AB=6[/tex]
[tex]\dfrac{x}{11}=\dfrac{6}{x}[/tex] cross multiply
[tex](x)(x)=(11)(6)\\\\x^2=66\to x=\sqrt{66}[/tex]
Which of the following is false? Correlation coefficient and the slope always have the same sign (positive or negative). If the correlation coefficient is 1, then the slope must be 1 as well. If the correlation between two variables is close to 0.01, then there is a very weak linear relation between them. Correlation measures the strength of linear association between two numerical variables.
Answer:
If the correlation coefficient is 1, then the slope must be 1 as well.
Step-by-step explanation:
Coefficient of correlation is used in statistics to determine the relationship between two variables. Correlation coefficient and slope always have same sign. It measures the strength of linear relation between two variables. The values of correlation coefficient ranges between 0 to 1. where 0 determines that there is no relationship between two variables.
If the correlation coefficient is 1, then the slope must be 1 as well.
The correlation coefficient (ρ) is a measure that determines the degree to which the movement of two different variables is associated.
Correlation coefficient and the slope both quantify the direction and strength of the relationship between two numeric variables. When the correlation (r) is negative, the regression slope (b) will be negative. When the correlation is positive, the regression slope will be positive.If the correlation between two variables is close to 0.01, then there is a very weak linear relation between them.
So, the false statement is:
If the correlation coefficient is 1, then the slope must be 1 as well.
Learn more:https://brainly.com/question/16557696
In a random sample of 2,305 college students, 339 reported getting 8 or more hours of sleep per night. Create a 95% confidence interval for the proportion of college students who get 8 or more hours of sleep per night. Use a TI-83, TI-83 plus, or TI-84 calculator, rounding your answers to three decimal places.
Answer:
The 95% confidence interval for the proportion of college students who get 8 or more hours of sleep per night is (0.133, 0.161).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 2305, \pi = \frac{339}{2305} = 0.147[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.147 - 1.96\sqrt{\frac{0.147*0.853}{2305}} = 0.133[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.147 + 1.96\sqrt{\frac{0.147*0.853}{2305}} = 0.161[/tex]
The 95% confidence interval for the proportion of college students who get 8 or more hours of sleep per night is (0.133, 0.161).
–735 = 15(m + 929) m = _______
Answer:
-978
Step-by-step explanation:
1.) Use Distributive property (by multiplying 15 by the values in parentheses): -735=15m + 13935
2.) Subtract 13,935 on both sides, to move that value to the left side, to further isolate the variable m.
-735-13935=15m + 13935 - 13935
3.)-Simplify/Combine Like Terms
-14,670=15m
4.) Divide both sides by 15 to isolate and solve for m
-14,670/15=15m/15
5.) Simplify
-978=m
6.) Rearrange so m is on left side and value is on right side
m=-978
this circle is centered at the origin (0,0) the radius is 4, what is the equation?
Answer:
x^2 +y^2 = 16
Step-by-step explanation:
The equation of a circle is given by
(x-h) ^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
(x-0) ^2 + (y-0)^2 = 4^2
x^2 +y^2 = 16
A car travelling from Ibadan to Lagos at 90 km/hr
takes 1 hour 20 min. How fast must one travel to
cover the distance in one hour?
Answer:
A velocity of 120km/h is needed to cover the distance in one hour
Step-by-step explanation:
The velocity formula is:
[tex]v = \frac{d}{t}[/tex]
In which v is the velocity, d is the distance and t is the time.
A car travelling from Ibadan to Lagos at 90 km/hr takes 1 hour 20 min.
This means that [tex]v = 90, t = 1 + \frac{20}{60} = 1.3333[/tex]
We use this to find d.
[tex]v = \frac{d}{t}[/tex]
[tex]90 = \frac{d}{1.3333}[/tex]
[tex]d = 90*1.3333[/tex]
[tex]d = 120[/tex]
The distance is 120 km.
How fast must one travel to cover the distance in one hour?
Velocity for a distance of 120 km(d = 120) in 1 hour(t = 1). So
[tex]v = \frac{d}{t}[/tex]
[tex]v = \frac{120}{1}[/tex]
[tex]v = 120[/tex]
A velocity of 120km/h is needed to cover the distance in one hour
State the coordinates of the vertex for each of the following
Answer:
[a] y=x^2+3, vertex, V(0,3)
[b] y=2x^2, vertex, V(0,0)
[c] y=-x^2 + 4, vertex, V(0,4)
[d] y= (1/2)x^2 - 5, vertex, V(0,-5)
Step-by-step explanation:
The vertex, V, of a quadratic can be found as follows:
1. find the x-coordinate, x0, by completing the square
2. find the y-coordinate, y0, by substituting the x-value of the vertex.
[a] y=x^2+3, vertex, V(0,3)
y=(x-0)^2 + 3
x0=0, y0=0^2+3=3
vertex, V(0,3)
[b] y=2x^2, vertex, V(0,0)
y=2(x-0)^2+0
x0 = 0, y0=0^2 + 0 = 0
vertex, V(0,0)
[c] y=-x^2 + 4, vertex, V(0,4)
y=-(x^2-0)^2 + 4
x0 = 0, y0 = 0^2 + 4 = 4
vertex, V(0,4)
y = (1/2)(x-0)^2 -5
x0 = 0, y0=(1/2)0^2 -5 = -5
vertex, V(0,-5)
Conclusion:
When the linear term (term in x) is absent, the vertex is at (0,k)
where k is the constant term.
Suppose H is an ntimesn matrix. If the equation Hxequalsc is inconsistent for some c in set of real numbers R Superscript n, what can you say about the equation Hxequals0? Why?
Answer:
The answer is explained below
Step-by-step explanation:
Given that, the equation H*x = c is inconsistent for some c in R^n, we can say that the equation A*x = b has at least one solution for each b in R^n of IMT (Inverse Matrix Theorem) is not fulfilled.
Thanks to this we can say that by equivalence of theorem statement, the equation H*x = 0 will not have only the trivial solution. It will have non-trivial solutions too.
Please answer this correctly
Answer:
2/7
Step-by-step explanation:
The numbers greater than 7 or less than 3 are 2 and 8.
2 numbers out of 7.
P(greater than 7 or less than 3) = 2/7
Answer:
2/7
Step-by-step explanation:
There are a total of 7 sample spaces also known as 2,3,4,5,6,7,8. Now we have to find a number greater than 7 and less than 3. 2 is less than 3, and 8 is greater than 7, so two numbers are selected. This would become 2/7 because out of all of the 7 outcomes, only two are selected.
A positive integer is twice another. The sum of the reciprocals of the two positive integers is 3/14. Find the two integers.
Answer:
The integers are 7 and 14.
Step-by-step explanation:
y = 2x
1/y + 1/x = 3/14
1/(2x) + 1/x 3/14
1/(2x) + 2/(2x) = 3/14
3/(2x) = 3/14
1/2x = 1/14
2x = 14
x = 7
y = 2x = 2(7) = 14
Answer: The integers are 7 and 14.
The required two integers are 7 and 14
This is a question on word problems leading to the simultaneous equation:
Let the two unknown integers be x and y. If a positive integer is twice another, then x = 2y .......... 1
Also, if the sum of the reciprocals of the two positive integers is 3/14, then:
[tex]\frac{1}{x}+ \frac{1}{y} =\frac{3}{14}[/tex] ..........2
Substitute equation 1 into 2
[tex]\frac{1}{2y} +\frac{1}{y} =\frac{3}{14} \\[/tex]
Find the LCM of 2y and y
[tex]\frac{1+2}{2y} =\frac{3}{14} \\\frac{3}{2y} =\frac{3}{14} \\\\cross \ multiply\\2y \times 3=3 \times 14\\6y=42\\y=\frac{42}{6}\\y=7[/tex]
Substitute y = 7 into equation 1:
Recall that x = 2y
[tex]x = 2(7)\\x = 14[/tex]
Hence the required two integers are 7 and 14.
Learn more here: https://brainly.com/question/17671977
ga political candidate has asked you to conduct a poll to determine what percentage of people support her. if the candidate only wants a 8% margin of error at a 95% cnofidence level, what size of sample is needed
Answer: 151
Step-by-step explanation:
if prior population proportion is unknown , then the formula is used to find the sample size :
[tex]n=0.25(\frac{z_{\alpha/2}}{E})^2[/tex]
, where [tex]z_{\alpha/2}[/tex] = Two tailed critical value for significance level of [tex]\alpha.[/tex]
E = Margin of error.
Given : margin of error = 8%= .08
For 95% confidence level , two tailed critical value = 1.96
Now, the required sample size :
[tex]n=0.25(\frac{1.96}{0.08})^2\\\\=0.25(24.5)^2\\\\=150.0625\approx151[/tex]
Hence, the size of the sample needed = 151.
quanto e 500x6-51-5x50
Answer:
2699
Step-by-step explanation:
you do all the multiplication first
500×6= 3000
5 ×50 = 250
so it becomes
3000-51-250 = 2699
Answer:
2699
Step-by-step explanation:
How many gallons of fuel costing $1.15 a gallon must be mixed with a fuel costing $0.85 per gallon to get 40
gallons of a fuel that costs $1 per gallon? Formulate an equation and then solve it in order to determine how
many gallons of fuel costing $1.15.
Answer:
multiply 0.85x40
Step-by-step explanation:
What is 62 in expanded form?
A. 2 x 2 x 2 x 2 x 2 x 2
B. 6 x 6
C. 12
D. 36
Answer:
I think so you meant to write 62 as 6^2
If this is the question , then the answer is 6 x 6
HOPE THIS HELPS AND PLS MARK AS BRAINLIEST
THNXX :)
Answer:
B. 6 × 6
Step-by-step explanation:
6²
The square of a number means that the number is multiplied by itself.
6 × 6 (expanded form)
Compare the distributions using either the means and standard deviations or the five-number summaries. Justify your choice. Set A Set B The distributions are symmetric, so use the means and standard deviations. The mean for Set A is about 44.6 with standard deviation of about 6.2. The mean for Set B is about 42.8 with standard deviation of about 1.86. While the average low temperatures for the cities are approximately equal, the greater standard deviation for Set B means that Set A’s low temperatures have a greater variability than Set B temperatures. The distributions are symmetric, so use the means and standard deviations. The mean for Set B is about 41.56 with standard deviation of about 6.07. The mean for Set A is about 43.8 with standard deviation of about 14.8. While the average low temperatures for the cities are approximately equal, the greater standard deviation for Set A means that Set A’s low temperatures have a greater variability than Set B temperatures. The distributions are symmetric, so use the means and standard deviations. The mean for Set A is about 44.6 with standard deviation of about 6.4. The mean for Set B is about 41.5 with standard deviation of about 6.7. While the average low temperatures for the cities are approximately equal, the greater standard deviation for Set B means that Set B’s low temperatures have a greater variability than Set A temperatures. The distributions are symmetric, so use the means and standard deviations. The mean for Set A is about 44.6 with standard deviation of about 6.2. The mean for Set B is about 43.8 with standard deviation of about 14.8. While the average low temperatures for the cities are approximately equal, the greater standard deviation for Set B means that Set B’s low temperatures have a greater variability than Set A temperatures.
Answer:
Explained below.
Step-by-step explanation:
The question is:
Compare the distributions using either the means and standard deviations or the five-number summaries. Justify your choice.
Set A: {36, 51, 37, 42, 54, 39, 53, 42, 46, 38, 50, 47}
Set B: {22, 57, 46, 24, 31, 41, 64, 50, 28, 59, 65, 38}
The five-number summary is:
MinimumFirst Quartile Median Third Quartile MaximumThe five-number summary for set A is:
Variable Minimum Q₁ Median Q₃ Maximum
Set A 36.00 38.25 44.00 50.75 54.00
The five-number summary for set B is:
Variable Minimum Q₁ Median Q₃ Maximum
Set B 22.00 28.75 48.00 58.50 65.00
Compute the mean for both the data as follows:
[tex]Mean_{A}=\frac{1}{12}\times [36+51+37+...+47]=44.58\approx 44.6\\\\Mean_{B}=\frac{1}{12}\times [22+57+46+...+38]=44.58\approx 44.6[/tex]
Both the distribution has the same mean.Compare mean and median for the two data:
[tex]Mean_{A}>Median_{A}\\\\Mean_{B}>Median_{B}[/tex]
This implies that set A is positively skewed whereas set B is negatively skewed.Compute the standard deviation for both the set as follows:
[tex]SD_{A}=\sqrt{\frac{1}{12-1}\times [(36-44.6)^{2}+...+(47-44.6)^{2}]}=6.44\approx 6.4\\\\SD_{B}=\sqrt{\frac{1}{12-1}\times [(22-44.6)^{2}+...+(38-44.6)^{2}]}=15.56\approx 15.6[/tex]
The set B has a greater standard deviation that set A. Implying set B has a greater variability that set B.true or false? the circumcenter of a triangle is the center of the only circle that can be inscribed about it
Answer:
TRUE
Step-by-step explanation:
The circumcenter of a triangle is the center of the only circle that can be circumscribed about it
Answer:
False
Step-by-step explanation:
9(d − 93) = –36 d = _______
Steps to solve:
9(d - 93) = -36d
~Distribute
9d - 837 = -36d
~Subtract 9d to both sides
-837 = -45d
~Divide -45 to both sides
18.6 = d
Best of Luck!
find the value of x...
Answer:
x = 7
Step-by-step explanation:
This problem can be solved using angular bisector theorem.
It states that if any angle of triangle is bisected by a line , then that line
divides the opposite side of that angle in same proportion as that of two other sides which contain the angle.
__________________________________
Here one angle is is divided into parts theta
Thus,
using angular bisector theorem
14/21 = 6/3x-12
=> 14(3x-12) = 21*6
=> 3x-12 = 21*6/14 = 9
=> 3x = 12+9 = 21
=> x = 21/3 = 7
Thus, x = 7
Find the median of: 1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4
Answer:
4
Step-by-step explanation:
1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4
Arrange the numbers from smallest to largest
0,1, 1,2,2, 3,3, 4, 4,4,4,4,4 , 4, 5, 6, 6, 7, 8, 9,
There are 20 numbers
The middle number is between 10 and 11
0,1, 1,2,2, 3,3, 4, 4,4 ,4,4,4 , 4, 5, 6, 6, 7, 8, 9,
The median is 4
Solution,
Arranging the data in ascending order:
0,1,1,2,2,3,3,4,4,4,4,4,4,4,5,6,6,7,8,9
N(total number of items)= 20
Now,
Median:
[tex] (\frac{n + 1}{2)} ) ^{th \: item} \\ = (\frac{20 + 1}{2} ) ^{th \: item} \\ = \frac{21}{2} \\ = 10.5 \: th \: \: item[/tex]
Again,
Median:
[tex] \frac{10 \: th \: item + 11 \: th \: item}{2} \\ = \frac{4 + 4}{2} \\ = \frac{8}{2} \\ = 4[/tex]
An object is dropped from the top of a tower with a height of 1160 feet. Neglecting air resistance, the height of the object at time t seconds is given by the
polynomial - 16t square + 1160. Find the height of the object at t = 1 second.
The height of the object at 1 second is feet.
Answer:
Height at t = 1 sec is 1144 ft
Step-by-step explanation:
Given:
Initial height of object = 1160 feet
Height of object after t seconds is given by the polynomial:
[tex]- 16t ^2+ 1160[/tex]
Let [tex]h(t)=- 16t ^2+ 1160[/tex]
Let us analyze the given equation once.
[tex]t^2[/tex] will always be positive.
and coefficient of [tex]t^2[/tex] is [tex]-16[/tex] i.e. negative value.
It means something is subtracted from 1160 ft (i.e. the initial height).
So, height will keep on decreasing with increasing value of t.
Also, given that the object is dropped from the top of a tower.
To find:
Height of object at t = 1 sec.
OR
[tex]h (1)[/tex] = ?
Solution:
Let us put t = 1 in the given equation: [tex]h(t)=- 16t ^2+ 1160[/tex]
[tex]h(1)=- 16\times 1 ^2+ 1160\\\Rightarrow h(1) = -16 + 1160\\\Rightarrow h(1) = 1144\ ft[/tex]
So, height of object at t = 1 sec is 1144 ft.
helpppppppppp give bralienst
Answer:
1
Hope that helps.
Answer:
1
Step-by-step explanation:
16/16=1
Hope this helps, if you have any questions, feel free to ask
Have a good day! :)
I NEED HELP PLEASE, THANKS! :)
Answer:
D. No solution
Step-by-step explanation:
Instead of solving everything I just plugged the numbers on equations and saw that for some of them the numbers satisfied one or two equation but not all. Also for some I saw that a number set makes the equation have no solution. For eg, I plugged option B into equation 3 and got 1305=756 which is never true so it is no solution.
Hope you understand :)
Which shapes have the same volume as the given rectangular prism?
Gregoire sold 24 cars to his friend for $71.76. What was the price per car?
a. $47.76
b. $2.99
c. $17.22
d. $3.25
Answer:
2.99
Step-by-step explanation:
Take the total cost and divide by the number of cards
71.76/24 = 2.99
The cost per car is 2.99
Answer:
b. $2.99.
Step-by-step explanation:
To get the price per car, you get the total price divided by the total number of cars.
That would be 71.26 / 24 = 2.969166667, which is most close to b. $2.99. Those are some cheap cars!
Hope this helps!
The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 15 people is selected at random, and the number of hours worked per year per person is given below. Calculate the 98% confidence interval for the mean hours worked per year in this state. Round your answers to the nearest integer and use ascending order.Time205120612162216721692171218021832186219521962198220522102211
Answer:
[tex]2169.67-2.624\frac{48.72}{\sqrt{15}}=2136.66[/tex]
[tex]2169.67+2.624\frac{48.72}{\sqrt{15}}=2202.68[/tex]
And the confidence interval would be given by (2137, 2203)
Step-by-step explanation:
2051 ,2061 ,2162 ,2167 , 2169 ,2171 , 2180 , 2183 , 2186 , 2195 , 2196 , 2198 , 2205 , 2210 ,2211
We can calculate the mean and deviation with these formulas:
[tex]\bar X= \sum_{i=1}^n \frac{x_i}{n}[/tex] (2)
[tex]s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}[/tex] (3)
And we got:
[tex]\bar X=2169.67[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean
s=48.72 represent the sample standard deviation
n=15 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The degrees of freedom are given by:
[tex]df=n-1=15-1=14[/tex]
Since the Confidence is 0.98 or 98%, the significance is [tex]\alpha=0.02[/tex] and [tex]\alpha/2 =0.01[/tex], and using excel we calculate the critical value [tex]t_{\alpha/2}=2.624[/tex]
Now we have everything in order to replace into formula (1):
[tex]2169.67-2.624\frac{48.72}{\sqrt{15}}=2136.66[/tex]
[tex]2169.67+2.624\frac{48.72}{\sqrt{15}}=2202.68[/tex]
And the confidence interval would be given by (2137, 2203)