Physics High School

If energy is conserved, then:
O A. initial (PE + KE) = final (PE + KE).
O B. the initial KE must be zero.
O C. the momentum does not change.
O D. PE(before) = KE(before).

If Energy Is Conserved, Then:O A. Initial (PE + KE) = Final (PE + KE).O B. The Initial KE Must Be Zero.O

Answers

Answer 1
Answer is A mark me brainliest
Answer 2

If energy is conserved, then initial (PE + KE) = final (PE + KE). So, the correct option is A.

What is meant by Law of Conservation of Energy ?

The law of conservation of energy states that, energy can neither be created nor be destroyed, but can be transformed from one form to another.

Here,

According to law of conservation of energy,

The total energy of an isolated system remains constant. That means, the total energy of the system in the initial state will be same as that in the final state.

The total mechanical energy is the sum of kinetic energy and potential energy.

TE = KE + PE

Therefore, the energy to be conserved in the system,

Initial TE = Final TE

So, Initial (KE + PE) = Final (KE + PE)

Hence,

If energy is conserved, then initial (PE + KE) = final (PE + KE).

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Related Questions

What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N

Answers

Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
Σf = 2080 N
The net force acting of the object will be "2080 N".

Given values are:

Mass, m = 52 kgVelocity, v = 8.0 m/sRadius, r = 1.6 m

As we know the formula,

→ [tex]\Sigma f = ma[/tex]

or,

→ [tex]\Sigma f = \frac{mv^2}{r}[/tex]

By putting the values, we get

         [tex]= \frac{52\times 8^2}{1.6}[/tex]

         [tex]= \frac{52\times 64}{1.6}[/tex]

         [tex]= 2080 \ N[/tex]

Thus the response above is appropriate.

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