Answer:
90 N
Explanation:
m = 60 kg
a = 1.5 m/s^2
F = m × a = 1.5 × 60 = 90 N
What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N
Given values are:
Mass, m = 52 kgVelocity, v = 8.0 m/sRadius, r = 1.6 mAs we know the formula,
→ [tex]\Sigma f = ma[/tex]
or,
→ [tex]\Sigma f = \frac{mv^2}{r}[/tex]
By putting the values, we get
[tex]= \frac{52\times 8^2}{1.6}[/tex]
[tex]= \frac{52\times 64}{1.6}[/tex]
[tex]= 2080 \ N[/tex]
Thus the response above is appropriate.
Learn more about force here:
https://brainly.com/question/14109330