The glacier given in this picture is an example of which type?
Answer:
arctic glacier
Explanation:
Answer:
Explanation:
are there any choices to choose from?
if not a glacier is a type of frozen water compacted together...
if it doesnt have choices ill word it differently...
can u also tell me what is your unit about?
Arenediazoniums can undergo electrophilic aromatic substitutions with a wide variety of activated aromatic compounds to yield new azo dyes.
a. True
b. False
Which of the following is an ionization reaction?
a. H2SO4 (aq) + Ca(OH)2 (aq) → CaSO4 (s) + 2 H2O (l)
b. NH3 (aq) + H2O (l) ⇋ NH4+ (aq) + OH– (aq)
c. CH3COO– (aq) + H2O (l) ⇋ CH3COOH (aq) + OH– (aq)
d. None of these
e. H2O (l) + H2O (l) ⇋ H3O+ (aq) + OH– (aq
Answer:
d
Explanation:
What type of consumer eats only producers?
Answer: Primary consumers make up the second trophic level. They are also called herbivores. They eat primary producers—plants or algae—and nothing else. For example, a grasshopper living in the Everglades is a primary consumer
Answer:
primary consumer make up the second trophic level .they are also herbivores they eat primary consumer plants or alger and nothing else .for example a grasshopper living in the everglades is a primary consumer
What is the greatest concentration of pollution
Answer:
B
Explanation:The poisonous substances, present in the environment can easily get into the trophic level as living organism depends on each other and environment for food and nutrition. These poisonous substances may not be broken down in the body or excreted easily, efficiently and quickly. Instead, they accumulate in the tissues, and as the living organism eats more, the concentration of these substances increases and they pass from one trophic level to the next. The tertiary consumer being at the top of trophic levels receives the maximum pollutant. This phenomenon is known as biological magnification.
So, the correct answer is option B.
An alternating current complete 100 cycles in 0.1s. it's frequency is
Answer:
The frequency is 1000 cycles/s
Explanation:
An alternating current is an electrical current in which the current changes its magnitude and the sense cyclically. The frequency of this current is defined as the cycles that the current completes in one second.
As the current completes 100 cycles in 0.1 seconds, the frequency is:
100 cycles / 0.1s = 1000 cycles /s
The frequency is 1000 cycles/sElectrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of CuSO4, Sn(SO4)2 and Cr2(SO4)3 in separate electrolytic cells for the same amount of time. State and explain which cell would deposit the greatest amount (in mol) of metal. Identify the electrode at which the metal is deposited.
Answer:
CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode
Explanation:
The valence of the elements in this case is as follows -
Cu - 2e-
Sn - 4e-
Cr - 3e-
CuSO4 cell will have the greatest amount of deposit among all three
The atoms of copper metal will deposit at the cathode. At the cathode, the least number of moles of electrons needed .
Hence, more amount of copper can be extracted out by the electrolyte
Explain the difference between an exothermic and an endothermic reaction.
Answer:
Explanation:
Heat is a reactant.
If the equation requires heat to occur, the reaction is endothermic
The equation would have this model
A + B + heat =====> C + D
If the equation gives away heat, then it is exothermic
The equation would look like this. (I'll use a common reaction)
CH4 + 2O2 - heat ===> CO2 + 2H2O
The heat is minus when it has to be given away.
Calculate the pH when 64.0 mL of 0.150 M KOH is mixed with 20.0 mL of 0.300 M HBrO (Ka = 2.5 × 10⁻⁹)
Answer:
The answer is "12.06"
Explanation:
Given:
[tex]M(HBrO) = 0.3\ M\\\\V(HBrO) = 20 \ mL\\\\M(KOH) = 0.15 \ M\\\\V(KOH) = 64 \ mL[/tex]
[tex]\to mol(HBrO) = M(HBrO) \times V(HBrO) = 0.3 M \times 20 mL = 6 \ mmol\\\\\to mol(KOH) = M(KOH) \times V(KOH)= 0.15 M \times 64 mL = 9.6 mmol[/tex]
6 mmol of both will react
excess KOH remaining[tex]= 3.15 \ mmol[/tex]
Volume[tex]= 20 + 64 = 84 \ mL[/tex]
[tex][OH^{-}] = \frac{ 9.6 \ mmol}{84\ mL} = 0.01142\ M[/tex]
use:
[tex]pOH = -\log [OH^-][/tex]
[tex]= -\log (1.142\times 10^{-2})\\\\= 1.94[/tex]
use:
[tex]PH = 14 - pOH[/tex]
[tex]= 14 - 1.94\\\\= 12.06[/tex]
The pH of the resulting solution is 12.63.
The equation of the reaction is;
HBrO(aq) + KOH(aq) ------> KOBr(aq) + H2O(l)
Number of moles of KOH= 64/1000 × 0.150 M = 0.0096 moles
Number of moles of HBrO = 20/1000 × 0.300 M = 0.0060 moles
Number of moles of excess base = 0.0096 moles - 0.0060 moles = 0.0036 moles
Total volume of solution = 64.0 mL + 20.0 mL = 84 mL = 0.084 L
Molarity of excess base = 0.0036 moles/0.084 L = 0.043 M
pOH = -log[OH-]
pOH = -log[ 0.043 M]
pOH = 1.37
pH + pOH = 14
pH = 14 -pOH
pH = 14 - 1.37
pH = 12.63
Learn more: https://brainly.com/question/11897796
What is the Kc for the following reaction at equilibrium at 800∘C if [CO2]= 0.030 M ? CaCO3(s)⇌CaO(s)+CO2(g)
Answer:
0.030
Explanation:
Step 1: Write the balanced reaction at equilibrium
CaCO₃(s) ⇌ CaO(s) + CO₂(g)
Step 2: Calculate the concentration equilibrium constant
The concentration equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids or pure liquids.
Kc = [CO₂] = 0.030
temperature usually increase when water condenses which behavior of water is most directly responsible for this phenomenon?
Answer:
Temperature usually increases when water condenses. What behavior of water is most directly responsible for this phenomenon? The release of heat by the formation of hydrogen bonds. Hydrogen bonds stabilize and keep the of ice farther apart than the water molecules of liquid water.
oi oi oi oi ewin
.................
Which product is often derived from the natural environment?
Answer:
coal, cotton, chinese tradictional medicine
For the following exothermic reaction system at equilibrium:
H2O(g) CO(g) CO2(g) H2(g)
Choose the changes that will increase the value of K.
a. Decrease the volume (constant T)
b. Add H2O(g) (constant T)
c. Remove H2(g) (constant T)
d. Add a catalyst (constant T)
e. Add CO2(g) (constant T)
f. Increase the temperature
g. Decrease the temperature
Answer:
See explanation.
Explanation:
Hello there!
In this case, for the chemical reaction:
[tex]H_2O(g) CO(g)\rightleftharpoons CO_2(g) H_2(g)[/tex]
It is widely known that the the only factor altering the equilibrium constant is the temperature because of its thermodynamic definition:
[tex]K=exp(-\frac{\Delta G(T)}{RT} )[/tex]
Which is temperature dependent on the denominator and on the Gibbs free energy of reaction. In such a way, the answers can be just f and g, as the other factors modify Q (reaction quotient) rather than K. Thus, we can discuss about f and g:
f. This would increase K if the Gibbs free energy of reaction is positive (nonspontaneous).
g. This would increase K if the Gibbs free energy of reaction is negative (spontaneous).
It is important to discuss those two because the Gibbs free energy is not given.
Regards!
Combine terms: 12a + 26b -4b – 16a.
Answer:
= -4a+22b
Explanation:
i hope this helps :)
Answer:
12a-16a =-4a
26b -4b =22b
the final answer is-4a +22b
1 Write the chemical symbols for following elements: Nitrogen-
Phosphorus- bromine- Zinc-Potassium-Magnesium.
Answer:
Look below
Explanation:
Nitrogen: N
Phosphorus: P
Bromine: Br
Zinc: Zn
Potassium: K
Magnesium: Mg
Hope this helps(would be very grateful if you mark this answer branliest bc i need for lvl up)
A tree can be a _________________________ for insects in a schoolyard.
Answer:
habitat/shelter
Explanation:
What is the empirical formula for C6H12?
Answer:
The empirical formula of C6 H12,
Which is least likely to occur after an experiment is conducted to a test a hypothesis?
The data is analyzed to see if it supports or refutes the hypothesis.
• The same experiment is conducted again to see if the data are reliable.
The hypothesis becomes a theory if the results support it.
O A new experiment is designed to provide additional data about the hypothesis.
Answer:
4th one. (A new experiment is designed to provide additional data about the hypothesis.)
Answer:
The correct answer is C)The hypothesis becomes a theory if the results support it.
Explanation:
how many grams of ammonia produced from 1000 grams of N2?
Answer:
N2 + 3H2 ———> 2NH3
As we know 1000 grams ammonia is 58.82 moles so according to unitary method,
2 mole NH3 formed by 1 mole N2 hence 58.82 NH3 will be given by 29.41 moles N2.
No. Of moles = given mass/molar mass
Implies that
Mass of nitrogen required = 29.41*28 = 823.48 grams.
Explanation:
Pure gold has a density of 19.3 g/cm³. if it is made into a crown. what will be the density of the crown? how can you find out if the crown is indeed made of pure gold and nothing else?
Answer:
19.3g cm^3
If it deviates from the original 19.3g cm^3
witch are the two factors decrease as the kinetic energy of the particles in an object decreases
Answer:
mass and speed are the two factor
CHEMISTRY HELP ASAP
Use this balanced equation for the two questions below:
2KClO3(s) → 2KCl(s) + 3O2(g)
9. How many moles of KClO3 are used to produce 9.9 moles of O2?
10. How many moles of O2 are produced from 11.2 moles of KClO3?
PLS SHOW WORK TOO THX
Answer:
1 mole of KClO_3 contains 3 moles of O.
10 moles of O_2 contains 20 moles of O.
You need 20/3 moles of KClO_3 to produce 10 moles of O_2
Explanation:
sana makatulong
A(n) _________ is an atom or a group of atoms with either a positive or negative charge
O compound
O ion
O molecule
O nucleus
Answer:
the answer is ion..
hope it helps..
Use the following chemical equation, how many moles of ammonia (NH 3 ) produced when 3.15 moles of nitrogen (N 2 ) reacts with hydrogen (H 2 ) ? N 2(g) + 3H 2(g) 2NH 3(g)
Answer:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to use the 1:2 mole ratio of nitrogen to ammonia to calculate the moles of the latter that are produced when reacting 3.15 moles of the former with hydrogen as shown below:
[tex]n_{NH_3}^{produced}=3.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]
Thus, by solving the equation we obtain:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Best regards!
calculate the percentage of CL in AL(CLO3)3
Answer:
38.4%
Explanation:
We'll begin by calculating the molar mass of Al(ClO₃)₃. This can be obtained as follow:
Molar mass of Al(ClO₃)₃
= 27 + 3[35.5 + (16×3)]
= 27 + 3[35.5 + 48]
= 27 + 3[83.5]
= 27 + 250.5
= 277.5 g/mol
Next, we shall determine the mass of Cl in Al(ClO₃)₃. This can be obtained as follow:
Mass of Cl in Al(ClO₃)₃ = 3 × Cl
= 3 × 35.5
= 106.5 g
Finally, we shall determine the percentage of Cl in Al(ClO₃)₃. This can be obtained as follow:
Mass of Cl in Al(ClO₃)₃ = 106.5 g
Mass of Al(ClO₃)₃ = 277.5 g
Percentage of Cl =?
Percentage of Cl = mass of Cl / mass of Al(ClO₃)₃ × 100
Percentage of Cl = 106.5 / 277.5 × 100
Percentage of Cl = 38.4%
What is NaC2H3O2 coefficient
Answer:yes coefficient u mean??
Explanation:
Need help with this question please.
Answer:
12.8
Explanation:
14 = pOH + pH
pH = 14 - pOH
pH = 14 - 1.2
pH = 12.8
What is the formula mass of ZrF4?
Answer:
167.217g/mol
Explanation:
Formula mass is defined as the mass in grams that a mole of a molecule weighs. To solve the formula mass of ZrF₄ we require the molar mass of Zr and of F (Molar mass Zr: 91.225g/mol; F: 18.998g/mol)
In this molecule, there is 1 mole of Zr and 4 moles of F. The formula mass is:
Zr = 1*91.225g/mol = 91.225g/mol
F = 4*18.998g/mol = 75.992g/mol
Formula mass: 91.225g/mol + 75.992g/mol
167.217g/molHow many grams of H2SO4 will react 650.0 grams of NaOH?
Answer:
H2SO4 + 2NAOH➡NA2SO4+2H2O
H2SO4 = 1*2 +32+16*3= 98g
NAOH = (11+16+1)=28
Explanation:
To calculate the number of Mole = Mole *Molar Mass
To calculate for gram = Mole/ Molar Mass
20.5g NaoH/1 * 1 mole NaOH/28g NaoH = 0.73M NaoH
0.73M NaoH /1 * 1 M H2SO4 /2M NaoH = 0.37M H2SO4
0.37 M H2SO4 /1 * 98g H2SO4 /1M H2SO4 = 0.00367g H2SO4
:- 0.00367g of Sulphuric Acid will be needed to complete the reaction.